A 80 kg bicyclist is coasting down a long hill that has a 10 ∘ slope. His cross-section area is 0.35 m2, his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is 0.02, and the air temperature is 20∘C.

Answers

Answer 1

An 80 kg bicyclist is coasting down a long hill that has a 10° slope. The speed that a cyclist has eventually attained is mathematically given as

v = 26 meters per second. or v = 26 m/s

This is further explained below.

What is the speed?

Generally, the equation for balancing the equation of Force is  mathematically given as

F1 = F2 + F3

Therefore

F3 = F1 - F2

Where

sinθ = sin(10) = 0.1736

and

cosθ = cos(10) = 0.9848

F1 = m g sinθ

F1=80 x 9.81  x 0.1736

F1= 136.24 N

F2 = μ m g cosθ

F2= 0.02 x 80 kg x 9.81 m/s2 x 0.9848

F2 = 15.46 N

Hence

F3 = F1 - F2

F3= 136.24 N - 15.46 N

F3= 120.78 N

In conclusion, The equation for is  mathematically given as

v = speed reached by a bicyclist

v= ((2 x F3 / (ρ x CD x A)) 0.5

Therefore

v = ((2 x 120.78 N / (1.2041 kg/m3 x 0.85 x 0.35))1/2

v= 25.97 m/s

v = 26 m/s

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Complete Question

An 80 kg bicyclist is coasting down a long hill that has a 10 ∘ slope. His cross-section area is 0.35 m2, his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is 0.02, and the air temperature is 20∘C.

What speed those he eventually reach?


Related Questions

If I add 47014 J of energy to an ideal gas inside a balloon, causing the internal energy to increase by 6391 J, how much work is done on the environment by the gas as the balloon expands?

Answers

The first equation of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system on the environment, thus we can use this formula to calculate the work done on the environment by the gas as the balloon expands:

ΔU = Q - W

where:
U = Alteration in internal energy
Q is the heat added to the system, and W is the work the system does on the environment.

What we have here is

ΔU = 6391 J Q = 47014 J

Consequently, we may rewrite the equation to account for W:

W = 47014 J - 6391 J, where W = Q - U
W = 40623 J

Consequently, the amount of environmental damage caused by the gas as the balloon grows is 40623

A grinding wheel is a uniform cylinder with a radius of 8.50 cm and a mass of 0.380 kg. Calculate (a) its moment of inertia about its center, and (b) the applied torque needed to accelerate it from rest to 1750 rpm in 5.00 s. Take into account a frictional torque that has been measured to slow down the wheel from 1500 rpm to rest in 55.0 s.

Answers

Hi there!

(A)

A grinding wheel is the same as a disk, having moment of inertia of:

\(I = \frac{1}{2}MR^2\)

Plug in the given mass and radius (REMEMBER TO CONVERT) to find the moment of inertia:

\(I = \frac{1}{2}(0.380)(0.085)^2 = 0.00137 kgm^2\)

(B)

We can use the rotational equivalent of Newton's Second Law to calculate the needed torque:

Στ = Iα = τ₁ - τ₂

Begin by solving for the angular acceleration. Convert rpm to rad/sec:

\(\frac{1750r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 183.26 rad/sec\)

Now, we can use the following equation:

ωf = wi + αt (wi = 0 rad/sec, from rest)

183.26/5 = α = 36.65 rad/sec²

τ = Iα = 0.0503 Nm

Since there is a counter-acting torque on the system, we must begin by finding that acceleration:

\(\frac{1500r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 157.08 rad/sec\)

ωf = wi + αt

-157.08/55 = α = -2.856 rad/sec²

τ₂ = Iα = 0.0039 Nm

Now, calculate the appropriate torque using the above equation:

\(\Sigma\tau = \tau_1 - \tau_2\)

\(\Sigma\tau + \tau_2 = \tau_1\)

\(0.0503 + 0.0039 = \large\boxed{0.054 Nm}\)

5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?

Answers

The traffic cop needs 23.3 seconds to pass the automobile.

What is the acceleration of a car moving in a straight line at a constant speed?

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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Two objects are known to have the same momentum. Do these two objects necessarily have the same kinetic energy?

Answers

Answer:

No

Explanation:

Momentum is a measure of mass times velocity. But kinetic energy is one-half the mass times the square of the velocity, so it’s much more dependent on the velocity than on the mass. You could have two objects with the same momentum, one very massive but traveling slowly, and the other with only a little mass but traveling at a high velocity - and the latter one would have the higher kinetic energy.

Answer:

No

Explanation:

Kinetic energy equation

\(e = \frac{1}{2} m {v}^{2} \)

Momentum equation

\(p = mv\)

Therefore

\(e = pv\)

So, they should have same velocity and momentum

How do atomic and molecular interactions explano the properties of matter that we see and feel?

Answers

Answer:

The atomic and molecular interactions unveil the bulk properties of matter in our environment by ways of the fact that everything in the whole universe is made of either atoms, molecules or even ions

How matter is made up of atoms and molecules?

It has been proven practically everything in the whole universe is matter and everything which interact with matter is also matter. This explains to us the reasons why matter could be atoms, molecules or ions.

That being said, some substances (matter) is made up of atoms of elements, some made up of molecules or atoms and molecules and others ions or both. However, matter is anything which has mass and occupies space.

In conclusion, we can now conclude from the explanation above that the properties of matter are as a result of the interaction which exists between matter at the atomic and molecular level.

How much time does it take for a crate in a factory to move 10m with a force exerted on it of 450n and power output of 350 watts

Answers

The time it takes for a crate in a factory to move 10m with a force exerted on it of 450N and power output of 350 watts is 12.86s.

How to calculate time?

Power is the measure of the rate of doing work or transferring energy. It is the effectiveness that a force producing a physical effect has over time.

Power, in physics, can be calculated by dividing the work done on an object by the time taken as follows:

P = W/t

According to this question, factory moves an object 10m with a force exerted of 450N and power output of 350 watts. The time taken can be calculated as follows:

Work done = force × distance

Work done = 450N × 10m = 4500J

350W = 4500J ÷ X

X = 4500 ÷ 350

X = 12.86seconds.

Therefore, 12.86 seconds is the time for the object to be moved.

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Name the following compound:
CH2 = CH2
Ethyne
Ethane
Ethyl
ethane

Answers

Answer:

Ethene

Explanation:

although the correct term is Ethylene

Respond to all of the following in a minimum of 175 words
- Visualization is a powerful tool to have in your motivation toolbox. For this week’s My Vision Board and Reflection Worksheet assignment, you will take time to visualize your goals, not just the outcome, but each step to get there. Do you see a relationship between the process and practice of visualizing and maintaining motivation? Explain how you perceive the relationship or lack of it.

-Self-discipline is taking personal responsibility of your willingness and desire to finish tasks and reach your goals. The readings discussed several ways to increase your level of self-discipline. Which of the strategies discussed this week do you think you will use to increase your level of self-discipline in your life? Share a bit about why you think those strategies will work best for you.

Answers

Visualizing your objectives aids in sustaining inspiration by making your ambitions more perceptible and attainable.

Why is this important?

By contemplating the actions required to reach a desired outcome, individuals can foster lucidity and guidance, thereby pleasing them with determination for moving forward. Additionally, focusing on the process of accomplishment through visualization helps divide the steps needed to attain those objectives, thus reducing their complexity, making it less menacing, and rendering them easier to achieve.

Various strategies towards increasing self-discipline were also proposed: setting apparent goals, creating schedules, sidestepping enticement, and practicing mindfulness amongst others.

Personally, I find that determining clear-cut aims and scheduling activities are the most productive tactics to pursue. This approach establishes definite targets and creates an environment that favors concentration whereby dedicating time for working towards set purposes becomes convenient.

This system constructs accountability while instilling discipline as daily progression is made toward target achievements during scheduled times - this encourages further motivation and commitment.

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Note that this prompt has to do with Vision Setting, motivation and Self Discipline.

What is the explanation for the above?

The connection between maintaining motivation and visualization is undeniable. Visualization involves the creation of a mental image that represents your desired outcome, allowing you to keep your eyes on the prize, which helps increase motivation levels.

Note that, breaking down the steps needed to achieve your goals through visualization can make the process less daunting while ensuring consistent progress towards success. Mental checkpoints where achievements are recognized further strengthen one's resolve, thus fueling motivation for even greater accomplishments.

Developing self-discipline is crucial and comes with various techniques for improving it. Optimizing productivity can sometimes be challenging for individuals like myself who struggle with distractions while working.

Fortunately, creating a detailed schedule has always been an effective solution for managing such situations. By factoring-in designated time slots within this timetable per individual tasks, focusing intently can be achieved without succumbing to environmental disturbances experienced in regular work environments.

To additionally promote personal drive during these sessions of focus-creation we should endeavor attainable objectives which will boost our overarching mission amid these intentional work segments.

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To describe a position in more than one
dimension, you must use more than one______

Answers

Answer:

To describe a position in more than one dimension you must use more than one reference point. The reference point is a basis for evaluation, assessment or comparison; a criterion.

Explanation:

Hope this answer help :D

Answer:

reference point

Explanation:

PLEASE HELP please put you own deffinitions down

PLEASE HELP please put you own deffinitions down

Answers

Answer:

prototype - a first model of something

obsolete - out of date

Unintended Consequence - outcomes of actions that weren't predicted and intended

Feedback - reactions to something from someone like a customer

what’s the answer for this

whats the answer for this

Answers

Answer:4 m/s

Explanation:

How does the image make the message in the "Mummy, what happens to us if the bomb drops?" poster more clear?
A. The poster shows a clear picture of a girl having a serious talk with her parents.
B. The poster shows all the supplies needed to survive in picture format.
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
D. The poster shows the actual bomb attack.

Answers

Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

How does the image make the message in the "Mummy, what happens to us if the bomb drops?" poster more

A force directed 51.8° below the positive x-axis has an x component of 4.93 lb. Find its y component.

Answers

Answer:

y= 6.26 lb.

Explanation:

1. Draw the vector of the force to better visualize and understand the problem.

Check attached image 1.

2. Find an expression for the force in the y axis.

Using the trigonometric functions, we need to find a function that relates the angle, opposite side and adjacent side of the drawn triangle. The function that does this is the tangent.

Let theta (θ) be the angle given by the problem.

Let "y" be the missing y component.

Tangent (θ) = Opposite side (y) / Adjacent side (x)

\(Tan(tetha)=\frac{y}{x}\)

3. Solve the equation for y by multiplying both sides by x.

\(Tan(tetha)*x=y\)

4. Substitute the information given by the problem and calculate y.

\(Tan(51.8)*(4.93)=y\\ \\y=6.26\)

5. Express the result.

y= 6.26 lb.

A force directed 51.8 below the positive x-axis has an x component of 4.93 lb. Find its y component.

Help answer question in picture

Help answer question in picture

Answers

The answer is b :)) I’m pretty sure

A body of mass 2kg is suspended from the ceiling of a lift with a light inextensible string. If the lift moves upwards with acceleration of 2ms-2, what is the magnitude of the tension in the string (g = 1Oms-2)?​

Answers

Answer:

  24 N

Explanation:

The force on the body due to gravity is ...

  F = mg = (2 kg)(10 m/s²) = 20 N

in the downward direction.

The net force on the body required to accelerate it upward at 2 m/s² is ...

  F = ma = (2 kg)(2 m/s²) = 4 N

The tension in the string must be enough to overcome the force due to gravity and provide a net force upward.

  -20 N + T = 4 N

  T = 24 N

The tension in the string is 24 newtons.

_____

Additional comment

Here, "m" is used to represent both mass and meters. In the force formula, it is mass. In the units for acceleration, it is meters.

How to calculate distance with mass, friction, velocity, and drag force

Answers

Answer:then using equations of motion for constant acceleration, meaning the force providing the acceleration doesn't change throughout the motion. v^2 = u^2 +2as, v=final velocity, u = intial velocity=0, a=(f/m), s is distance over which the object is accelerated.

hope this helps! Brainlist?

The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?

Answers

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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5. Candance got $0.22 in change when she bought chips at the
store. What percent of a dollar does her change represent?

Answers

Answer:

22%

Explanation:

Given parameters:

The amount of change  = $0.22

Unknown

What percentage of a dollar the change represents  = ?

Solution:

A dollar is made up of 100cents;

        So;

 $0.22 represents 22cents

Percentage of dollar this represents  = \(\frac{22}{100}\)  x 100  = 22%

A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. m/s2 (b) Over what time interval does the proton reach this speed? s (c) How far does it move in this time interval? m (d) What is its kinetic energy at the end of this interval? J

Answers

Answer:

a)  a = 6.31 10¹⁰ m / s² , b) t = 2.06 10⁻⁵ s , c)  x = 13.39 m , d)  ΔK = 1.41 10⁻¹⁵ J

Explanation:

a) Since they indicate that the speeds are non-relativistic, we can use the kinematics relations and Newton's second law

                  F = m a

                 

The force in electrical is

                 F = qE

                qE = m a

                a = qE / m

we calculate

                a = 1.6 10⁻¹⁹ 660 / 1.673 10⁻²⁷

                a = 6.31 10¹⁰ m / s²

b) Let's use the one-dimensional kinematics relation

                 v = v₀ + a t

as part of rest its initial velocity is zero

                 v = a t

                 t = v / a

                 t = 1.30 10⁶ / 6.31 10¹⁰

                 t = 2.06 10⁻⁵ s

c) We use the kinematics displacement equation

                 x = v₀ t + ½ a t²

initial velocity is zero

                x = ½ a t²

                x = ½ 6.31 10¹⁰ (2.06 10⁻⁵)²

                x = 1,339 10¹ m

                x = 13.39 m

d) the kinetic energy is

            ΔK = Kf -K₀

            ΔK = ½ m v² - 0

            ΔK = ½ 1.673 10⁻²⁷ (1.30 10⁶) 2

            ΔK = 1.41 10⁻¹⁵ J

A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. What is the mass of this volume of water in kilograms

Answers

A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. The mass of this volume of water in kilograms is  60.4 kilograms (kg).

To calculate the mass of water in the rectangular container, we need to multiply the volume of water by the density of water.

1. Volume of water:

The volume of the rectangular container is given as:

Length (L) = 19 cm

Width (W) = 51 cm

Height (H) = 62 cm

The volume of water (V) is calculated as:

V = L × W × H

Converting the dimensions to meters:

L = 19 cm = 0.19 m

W = 51 cm = 0.51 m

H = 62 cm = 0.62 m

V = 0.19 m × 0.51 m × 0.62 m

V ≈ 0.0604 cubic meters (\(m^3\))

2. Density of water:

The density of water (ρ) is approximately 1000 kilograms per cubic meter (kg/\(m^3\)).

3. Mass of water:

Mass (m) = Volume × Density

m = 0.0604 m^3 × 1000 kg/\(m^3\)

m = 60.4 kilograms (kg)

Therefore, the mass of the volume of water in the rectangular container is approximately 60.4 kilograms (kg).

It's important to note that the density of water can vary slightly depending on temperature and impurities, but for most practical purposes, a density of 1000 kg/\(m^3\)is commonly used.

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Guys please help. I need this question

Guys please help. I need this question

Answers

I think it is 6!!!!!!!!!!!
6!!!!!!!!!!!!!!!!!!!!!!!!!!!!

I need this done pls

I need this done pls

Answers

Answer:

all the details are in the attached picture, the answers are marked with colour.

I need this done pls

Given three vectors A = 24i + 33j, B = 55i - 12j and C = 2i + 43j (a) Find the magnitude of each vector. (b) Write an expression for the vector difference A - C. (c) Find the magnitude and direction of the vector difference A-B. (d) In a vector diagram show vector A + B, and A - B, and also show that your diagram agrees qualitatively with your answer.

Answers

Answer:

(a) , .  and .

(b)\(\vec A - \vec C=22 \hat i -10 \hat j\).

(c)\(|\vec A - \vec B|=63.13\) and the direction \(\theta =\) 124.56°.

Explanation:

Given that,

,

and

\(\vec {C}=2 \hat i +43 \hat j\)

(a) The magnitude of a vector is the square root of the sum of the square of all the components of the vector, i.e. for a ,.

So, the magnitude of the is

\(|\vec A|=\sqrt {24^2+ 33^2}\)

\(\Rightarrow |\vec A|=\sqrt {1665}\)

.

The magnitude of the is

\(|\vec B|=\sqrt {55^2+ (-12)^2}\)

\(\Rightarrow |\vec B|=\sqrt {3169}\)

.

And, the magnitude of the is

\(|\vec C|=\sqrt {2^2+ 43^2}\)

\(\Rightarrow |\vec C|=\sqrt {1853}\)

.

(b) The difference between the two vectors is the difference between the corresponding components of the vectors. So, the required expression of is

\(\vec A - \vec C=(24 \hat i +33 \hat j) - (2 \hat i +43 \hat j)\)

\(\Rightarrow \vec A - \vec C=24 \hat i +33 \hat j - 2 \hat i -43 \hat j\)

\(\Rightarrow \vec A - \vec C=22 \hat i -10 \hat j\)

(c) The expression of is

\(\vec A - \vec N=(24 \hat i +33 \hat j) - (55 \hat i -12 \hat j)\)

\(\Rightarrow \vec A - \vec B=24 \hat i +33 \hat j - 55\hat i +12 \hat j\)

\(\Rightarrow \vec A - \vec B=-31 \hat i +45 \hat j\;\cdots (i)\)

The magnitude of is

\(|\vec A - \vec B|=\sqrt {(-31)^2+55^2}\)

\(\Rightarrow |\vec A - \vec B|=\sqrt {3986}\)

\(\Rightarrow |\vec A - \vec B|=63.13\)

Now, if a vector \(\vec V= -\alpha \hat i +\beta \hat j\) in 3rd quadrant having direction \(\theta\) with respect to \(\hat i\) direction, than

in the anti-clockwise direction.

Here, from equation (i), for the vector \(\vec A - \vec C\), \(\alpha=31\) and \(\beta=45\).

\(\Rightarrow \theta = \pi-\tan ^{-1}\left(\frac {45}{31}\right)\)

180°-55.44° [as \pi radian= 180°]

124.56° in the anti-clockwise direction.

(d) Vector diagrams for \(\vec A +\vec B\) and \(\vec A - \vec B\) has been shown  

in the figure(b) and figure(c) recpectively.

Vector \(\vec A - \vec B\) is in 3rd quadrant as calculated in part (c).

While Vector \(\vec A +\vec B=(24 \hat i +33 \hat j)+(55 \hat i -12 \hat j)\)

\(\Rightarrow \vec A +\vec B=79 \hat i +21 \hat j\), which is in 1st quadrant as both the components are position has been shown in figure(b).

Given three vectors A = 24i + 33j, B = 55i - 12j and C = 2i + 43j (a) Find the magnitude of each vector.

10) Allen was curious about dog interaction at the dog park. He wondered if big dogs liked to play with big dogs and if little dogs liked to play with little dogs. After gathering information through research, he followed the scientific method by stating a ____________. This educated guess refers back to the original questions and is stated in such a manner that the results can be measured. A) experiment B) hypothesis C) problem D) procedure

Answers

Answer: B) hypothesis

Explanation:

Answer: B) Hypothesis

Explanation:

I got it right

What is the tension in the string?
(I’m really having a hard time understanding this topic, and my professor isn’t helping much, so any extra explanation are greatly appreciated). The angles are 54.9205°.

What is the tension in the string?(Im really having a hard time understanding this topic, and my professor

Answers

If you look at the sketch I drew for the earlier part of this question, you'll see that, with respect to the positive horizontal (i.e. directly to the right), T₁ makes an angle of 180° - 54.9205° ≈ 125°, while T₂ makes an angle of 54.9205° ≈ 55°.

Split up the force acting on the block into vertical and horizontal components. We have

• net vertical force

F = T₁ sin(125°) + T₂ sin(55°) - mg = 0

where m = 0.56 kg, and

• net horizontal force

F = T₁ cos(125°) + T₂ cos(55°) = 0

Both net forces are 0 because the block is suspended in equilibrium.

Notice that cos(125°) = -cos(55°), so the second equation tells you that T₁ = T₂ and that the tensions in either string are the same. Also, sin(125°) = sin(55°).

Then in the first equation, we have

T₁ sin(125°) + T₂ sin(55°) - mg = 0

2 T₁ sin(55°) = mg

T₁ = mg/(2 sin(55°))

T₁ = (0.56 kg) (9.8 m/s²)/(2 sin(55°))

T₁ ≈ 3.35 N

Sound Wave A is moving through a medium that is
decreasing in temperature.
Sound Wave B is moving from a liquid to a gas medium.
Mark this and return
Which statement can be made about both waves?
O They will speed up.
O They will increase the density of their medium.
O They will slow down.
O They will decrease the density of their medium.
Save and Exit
28.2
Next
Submit

Answers

Explanation:

The satement that can be made about sound wave A and sound wave B is, they will slow down.

Relationship between sound wave and temperature

The relationship between sound waves and temperature is given by the following formula;

v= √γRT

The speed of sound wave increases with increase in temperature, and vice versa.

Speed of sound wave in liquid and gaseous medium

Sound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.

Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.

The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?

The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat

Answers

Answer:

it is double the temperature change of iron

4. The atmosphere is composed of about 78% nitrogen, 21% oxygen, and 1% argon. Typical atmospheric pressure in Boulder, Colorado is about 0.83 atm. What is the pressure contributed by each gas?​

Answers

ANS

Step 1 :Explanation of required formula.

According to Dalton's Law of Partial Pressures, the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture

i.e Pi=Xi × Ptotal,

Here we don't know exactly how many moles of the mixture we have,

but we know that 78.0% of all the molecules present in the mixture are nitrogen molecules, 21.0% are oxygen molecules, and 1% are molecules of Ar gas.

As we know, a mole is simply a very large collection of molecules. In order to have one mole of a substance, we need to have 6.022 × 1023 molecules of that substance.

This means that the actual number of moles is not important here, because the ratio that exists between the number of molecules is equivalent to the ratio that exists between the number of moles.

Hence,

Step 2 : Calculate of mole fraction of the mixture.

mole fraction of nitrogen = 78 /100 = 0.78

mole fraction of O2 =

21 /100 = 0.21

mole fraction of Argon =

1 /100 = 0.01.

Step 3 : Calculate the pressure contributed by each of the mixture.

The pressure contributed by N2 = mole fraction of N2 × Total pressure = 0.78 × 0.83 atm = 0.6474 atm

The pressure contributed by O2 = 0.21 × 0.83 atm = 0.1743 atm

The pressure contributed by N2 = 0.01 × 0.83 atm = 0.0083 atm.

Thank You !!!!!!

The pressure contributed by argon is 0.0083 atm, the pressure contributed by oxygen is  0.1743 atm and the pressure contributed by nitrogen is 0.6474 atm.

What is Pressure?

The perpendicular force per unit area, also known as the stress at a point within a confined fluid, is referred to as pressure in the physical sciences. A 42-pound box with a bottom area of 84 square inches will push down on a floor with a pressure of one-half pound per square inch, which is equal to the force divided by the area it is applied to. Atmospheric pressure, which at sea level is around 15 pounds per square inch, is the amount of weight that the atmosphere exerts on each unit area of the Earth's surface. Pascals are the units used to express pressure in SI.

Firstly calculate the mole fraction of the mixture :

Mole fraction of N₂ gas = 78 /100 = 0.78

Mole fraction of O₂ gas = 21 /100 = 0.21

Mole fraction of Argon gas =  1 /100 = 0.01.

Now, the pressure contributed by each gas will be :

Pressure contributed by N₂ = mole fraction of N₂ × Total amount of  pressure

So, the Pressure contributed by N₂ = 0.78 × 0.83 atm = 0.6474 atm

Similarly,

The pressure contributed by oxygen

O₂ = 0.21 × 0.83 atm = 0.1743 atm

The pressure contributed by Argon

Argon = 0.01 × 0.83 atm = 0.0083 atm.

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Which describes the magnetic field that forms when a wire carries an electric current?

Answers

The magnetic field that forms when a wire carries an electric current is a circular field that is strongest at the ends of the wire and weakest in the middle.

What does a current-carrying wire's magnetic field look like?

A current-carrying wire's magnetic field looks like a series of concentric circles that extend outward from the wire in both directions.

The magnitude of the magnetic field is greatest at the center of the wire and decreases as you move away from it.

The direction of the magnetic field is determined by the direction of the current flow: if the current is flowing clockwise around the wire, then the magnetic field will be pointing outward from the wire.

The magnetic field also has a north and south pole, so the direction of the field also depends on which direction around the wire the current is flowing.

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Determine the velocity of a car traveling 150 meters south for 15 seconds. Show your work.

Answers

Given data:

The distance traveled by car is d = 150 m.

The time taken by the car is t = 15 seconds.

Solution:

The velocity of the car is,

\(v=\frac{d}{t}\)

Substituting the known values,

\(\begin{gathered} v=\frac{150}{15} \\ v=10\text{ m/s} \end{gathered}\)

Thus, the velocity of the car is 10 meters per second towards the south.

Explanation:

velocity =distance÷time

v=d÷t

v=150÷15

v=10m/s

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