A 75 kg man stands in an elevator. What will be the force that the elevator exerts on him when
a) the elevator is at rest? ;
b) the elevator is moving upwards with a uniform acceleration of 3.2 m/s"?
c) moving downwards with an acceleration of 2.0 m/s ?

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

Resistance is proportional to length and inversely proportional to area.

L1 =  5 cm

L2 = 10 cm

L3 = 15 cm

A1 = k * (.50 cm)^2

A2 = k * (.25 cm)^2 = 1/4 A1

A3 = k * (.05 cm)^2= 1/100 A1

R1 = 1 * 1 = 1

R2 = 2 * 4 = 8 R1

R3 = 3 * 100 = 300 R1

R3 has greatest resistance

A is pulling the block straight down toward the center of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

A is pulling the block straight down toward the centre of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

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Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s

The magnification is the ratio of the image size to the object size. If the image and object are in the same medium, it is just the image distance divided by the object distance:

On the other hand:

Where h' is the size of the image and h is the size of the object.

Therefore:

Substitute h'=4.58m, h=0.86m and o=3.35m to find i, the distance from the lens at which the image is produced:

Therefore, the image is produced 17.84m away from the lens.

An orbital projectile should be launched with such a horizontal speed exceeding 8000 m/s. Determine the speed of the a satellite inside an orbit 1000 km, M is 5.98x1024 kg, and R is 6.4x10m. [Ans x 10 = 7.34 m/s].

At 328,084 feet, the barrier between earth and space is the highest point you have probably ever gone and is around 11 times greater than Mount Everest. Consider that for a second. If looking at this image doesn't inspire awe in you, perhaps contemplating it in a different way would.

A: At low earth orbit, an object must travel at a speed of roughly 28,000 km/h (17,500 mph) in order to orbit the Earth. At this speed, the object would be able to leave Earth's atmosphere and keep a steady orbit around it at a height of about  325 km (200 km).

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Answer:

Skeletal muscle cells

Explanation:

Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.

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The x component of the force is -8.03 N.

The y component of the force is -11.47 N.

The parallel components of the force is resolved into x and y components as follows;

The x component of the force is calculated as follows;

Fx = F cosθ

where;

Fx = 14 N x cos (235)

Fx = -8.03 N

The y component of the force is calculated as follows;

Fy = F sinθ

where;

Fy = 14 N x sin (235)

Fy = -11.47 N

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Answer:

Tolerance: \(\pm 10\%\)

Explanation:

Resistor Color Codes

Resistor Color Coding uses colored bands to quickly identify the resistive value or resistors and its percentage of tolerance.

Since the question does not provide a specific color table, we'll use the table attached below.

The colors of the resistor shown in the question are:

First band: orange

Second band: blue

Third band: brown

Fourth band: silver

The colors relate to the following numbers respectively:

3, 6, 10Ω, \(\pm 1\%\)

The first two colors form the number 36

The third color is the multiplier: 36*10Ω = 360Ω

And the fourth color is the tolerance or the possible variation of the resistance \(\pm 1\%\)

Resistance: 360Ω

Tolerance: \(\pm 10\%\)

Answer: Tidal range

Explanation:

Tides are considering the rise and fall of sea levels and there are two types of it which are called high tide and low tide. The difference between high tide and low tide is called the tidal range.

The tidal range is not constant and it is considering height difference. It can change and it is depending on the locations of the Sun or the Moon.

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

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The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.

To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).

Saturn's density can be computed using the following formula:

density equals mass divided by volume

Saturn's mass and volume may be computed given its mass and radius.

The volume of Saturn can be determined using the sphere volume formula:

volume =\((4/3) \pi (r^3)\)

where r is Saturn's radius.

Filling in the blanks:

volume = \((4/3) \pi (5.6 \times 107) m^3\)

8.27 x 1023 \(m^3\)volume

Saturn's mass is given as \(5.68 \times 10^{26} kg.\)

We can now compute Saturn's density:

density equals mass divided by volume

density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)

This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.

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Hello,

I hope you and your family are doing well!

To find the angle of the applied force (α), you can rearrange the equation for the net force to solve for α. The equation for the net force is:

F_net = F * cos(α + β) - m * g * sin(β) - u * N

To solve for α, you can start by isolating the term containing α. You can do this by subtracting the other terms from both sides of the equation, which gives you:

F_net - F * cos(β) + m * g * sin(β) + u * N = F * cos(α + β)

Then, you can divide both sides of the equation by F * cos(β) to get:

[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α + β)

Next, you can use the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) to rewrite the right side of the equation:

[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α)cos(β) - sin(α)sin(β)

Finally, you can rearrange this equation to solve for α:

α = atan2(sin(α) * cos(β) + cos(α) * sin(β), cos(α) * cos(β) - sin(α) * sin(β))

This equation gives the angle of the applied force (α) in terms of the other variables in the equation for the net force.

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The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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Answer: d. Between 1 and infinity

Explanation:

The correct answer is Between 1 and infinity This is so because Eair/Eoil = Kair/koil.

Basically a capacitor is a device which is used or utilized in storing electricity in an electric field. They are found in electrical devices and appliances where they are used in applications.

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion

Explanation:

Answer:

43200 J

Explanation:

(1/2(mass)) (speed)^2

Answer:

A stone is thrown up wards with an initial velocity of 25 m/s at an angle of 30 to the ground.

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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The value of Current I​ is  I =1320.".

Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles. Electrons flowing over a wire are frequently used as charge carriers in electric circuits.

V = IR,

  =  R=ρ A/1

​l= RA/ρ

V= IR, I= R/V 5.5

R= ρ l/A, = 5.5* 10 3 20/2 * 24

 I =1320.

The passage of electric charge across a surface at a rate measured in amperes, or amps, is the SI unit of electric current.

Therefore, The value of Current I​ is  I =1320."

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The acceleration of the box being pulled by the given force is 2.03 m/s².

The given parameters;

The normal force on the box is calculated as follows;

\(F_n = mg- Fsin(\theta)\\\\F_n = 15\times 9.8\ - \ 75\times sin(20)\\\\F_n = 121.35 \ N\)

The frictional force experienced by the box is calculated as follows;

\(F_k = \mu F_n\\\\F_k = 0.33 \times 121.35 \\\\F_k = 40 \ N\)

The net horizontal force on the box is calculated as follows;

\(\Sigma F _x = 0\\\\Fcos(\theta) - F_k = ma\\\\\)

where;

\(75 \times cos(20) \ - \ 40 = 15a\\\\30.425 = 15a\\\\a = \frac{30.425}{15} \\\\a = 2.03 \ m/s^2\)

Thus, the acceleration of the box being pulled by the given force is 2.03 m/s².

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Answer:

amplitude

frequency

wave

transition

transverse waves

Nearby jet airplane

Fast train

Siren

Lawn move

Answer:

tough

ques

Explanation:

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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Answer:

the light is reflected, because light is white when the spectrum is combined, and white reflects white. that's why wearing a white shirt outside feels cooler than wearing a black shirt, since it doesn't absorb light.

Answer:

All the light is reflected, so the shirt appears white.

Explanation:

The velocity of the ball just before it hits the ground is 14.0 m/s

Let's solve the problem using the given equation:

\(v^2 = u^2 + 2as\)

We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.

Plugging in the given values, we get:

v^2 = 0 + 2(9.81)(10)

v^2 = 196.2

Taking the square root of both sides, we get:

v = sqrt(196.2)

v = 14.0 m/s

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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)

Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--

Answer:

Explanation:

Given data

initial speed ,u= o m/s

final speed v= 25 m/s

time t= 3.11 seconds

Applying the first equation of motion we have

\(v= u+at\\\\v-u=at\\\\a= \frac{v-u}{t} \\\\a= \frac{25-0}{6.22} \\\\a= 4.02 m/s^2\)

Also applying \(v=u+at\) with initial speed set at 0, we can also find speed at 3.11 seconds

\(v=0+4.02*3.11\\v= 12.50 m/s\)

Hence the average speed in the first 3.11 seconds is

\(\bar v= \frac{v}{2} \\\\\bar v=\frac{ 12.50}{2} \\\\ \bar v= 6.25 m/s\)

Applying the expression \(\bar v=\bar u+at\)  we can now fing the average speed in the second 3.11 second

\(\bar v=\bar u+at\\\\ \bar v=6.25+4.02*3.11\\\\ \bar v=18.75m/s\)

The velocity of the car along east direction  must be 34.94 m/s.

In physics momentum of any object can be defined as product of velocity and mass. As velocity is a vector quantity, momentum is also a vector quantity. So, to define momentum both magnitude and direction are required.  SI unit of momentum is kg-m/s.

Mass of the car = 1370 kg.

Mass of the   pickup truck a = 2280 kg

Momentum of the  pickup truck along east = 2280 kg × 21 m/s

= 47880 kg-m/s.

Hence, velocity of the car along east direction = (47880/1370) m/s

= 34.94 m/s.

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