Answer:
65.74 km/hr
Explanation:
KE = 1/2mv²
I'm assuming the KE is 1.1x10⁴ J ? It's hard to tell from what you wrote.
1.1x10⁴ J = 1/2(66 kg)v²
v² = 2(1.1x10⁴ J) / (66 kg) = 333.3 m²/s²
v = √333.3 m²/s² = 18.26 m/s
convert m/s to km/hr:
18.26 m/s x 1 km/1000 m x 3600 s/hr = 65.74 km/hr
In Hooke’s law what does k represent
A. Mass of the spring
B. Length of the spring
C. Force of the spring
D. Stiffness of the spring
E. Width of the spring
Bill Nye- Static Electricity Answer Key?
A box of mass m held in place by friction rides on the flatbed of a truck. The truck accelerates from rest. What is the minimum coefficient of static friction required to prevent the box from sliding?
a) μ > (g/2a) b) μ > (2a/g) c) μ > (g/a) d) μ > (a/g)
The minimum coefficient of static friction required to prevent the box from sliding is μ > (a/g), which is option d).
In this scenario, the box is in a state of rest before the truck accelerates. Once the truck starts accelerating, a pseudo-force acts on the box in the direction opposite to the acceleration of the truck. In order for the box to not slide, the force of friction between the box and the flatbed of the truck must be equal to the maximum value of the static friction. This maximum value of static friction can be calculated using the formula:
\(f_{max}\) = μ\(_s\) * N
where \(f_{max}\) is the maximum force of static friction, μ\(_s\) is the coefficient of static friction, and N is the normal force acting on the box.
In this case, the normal force acting on the box is equal to its weight, which is given by:
N = mg
where m is the mass of the box and g is the acceleration due to gravity.
Now, we can set up an equation for the net force acting on the box in the direction of the truck's acceleration:
\(f_{net}\) = \(f_{friction}\) - \(f_{pseudo}\)
where \(f_{friction}\) is the force of friction, and \(f_{pseudo}\) is the pseudo force acting on the box.
Since the box is not sliding, \(f_{friction}\) = \(f_{max}\), and \(f_{pseudo}\) = ma, where a is the acceleration of the truck.
Substituting the values, we get:
μ\(_s\) * mg = m * a
Simplifying, we get:
μ\(_s\) = a/g
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Drift velocity (v) of the charge carriers is given by the equation...
The drift velocity (v) of charge carriers in a conductor is given by the following equation: v = I / (n \(\times\) A \(\times\) q).
v = I / (n \(\times\) A \(\times\) q)
where:
v is the drift velocity, measured in meters per second (m/s)
I is the current flowing through the conductor, measured in amperes (A)
n is the number of charge carriers per unit volume of the conductor, measured in per cubic meter (\(m^(-3)\))
A is the cross-sectional area of the conductor, measured in square meters (m^2)
q is the charge of a single carrier, such as an electron, measured in coulombs (C)
This equation relates the drift velocity of the charge carriers to the current flowing through the conductor, the number of charge carriers per unit volume, the cross-sectional area of the conductor, and the charge of a single carrier. The drift velocity represents the average velocity of the charge carriers as they move through the conductor in response to an applied electric field.
The number of charge carriers per unit volume (n) depends on the material of the conductor and the temperature. In metals, the charge carriers are typically electrons, and the number density is on the order of 10^28 to 10^29 electrons per cubic meter.
The cross-sectional area (A) of the conductor is the area of the cross-section of the conductor perpendicular to the direction of the current flow, and is a measure of the amount of material available for the charge carriers to move through.
The charge of a single carrier (q) is typically the charge of an electron, which is approximately 1.6 x \(10^{-19\) coulombs.
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A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What is the speed of the 6.0 kg object after the collision? (A:3) Marking Scheme (A:3) 2A for showing your work 1A for final answer
A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What is the speed of the 6.0 kg object after the collision, the speed of the 6.0 kg object after the collision is 13 m/s.
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision, assuming there are no external forces acting on the system.
Let's denote the velocity of the 6.0 kg object after the collision as v.
Before the collision:
Momentum of the 1.2 kg ball = (mass of the ball) * (velocity of the ball) = (1.2 kg) * (40 m/s) = 48 kg·m/s
Momentum of the 6.0 kg object = 0 (since it is stationary)
After the collision:
Momentum of the 1.2 kg ball = (mass of the ball) * (velocity of the ball after the collision) = (1.2 kg) * (-25 m/s) = -30 kg·m/s
Momentum of the 6.0 kg object = (mass of the object) * (velocity of the object after the collision) = (6.0 kg) * v
According to the conservation of momentum:
Initial momentum = Final momentum
48 kg·m/s + 0 = -30 kg·m/s + (6.0 kg) * v
Simplifying the equation:
48 kg·m/s = -30 kg·m/s + (6.0 kg) * v
78 kg·m/s = (6.0 kg) * v
Dividing both sides by 6.0 kg:
v = 78 kg·m/s / 6.0 kg
v = 13 m/s
Therefore, the speed of the 6.0 kg object after the collision is 13 m/s.
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Which statement is true regarding the vectors?
A. G-> + H-> +Y->=X->
B. F->+G->+E->=Y->
C. X-> + F-> H->= G ->
D. Y-> + F-> +G ->=E->
Answer: D
Explanation:
I took the quiz and B was wrong
what is ccl4 compound name
Tetrachloromethane is the name given to the CCl4 chemical.
Structure of carbon tetrachloride chemically. The liquid CCl4 is transparent, nonflammable, and heavy. It evaporates quickly and has a distinctive sweet smell that is similar to that of chloroform. The term "volatile organic compound" refers to CCl4 (VOC).
The secondary prefix for four carbon atoms is tetra. The first prefix for chlorine is chloro. Meth represents the word's root, which is carbon. Tetrachloromethane, which may also be written as 1,1,1,1, is the name of the substance. a week ago With the chemical formula CCl4, carbon tetrachloride is an organochlorine chemical compound that goes by several different names.
covalent substance Since it has four non-polar covalent connections between carbon and chlorine, carbon tetrachloride (CCl4) is classified as a covalent molecule.
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Last Thursday, I went for a walk through my neighborhood. I started at my house. My smart watch told me that I walked a total of 3.5 miles. I started my walk at 5 pm and ended at 8 pm. At the end of my walk, I was 50 meters north of my house visiting a neighbor. I wanted to find my average velocity on the trip. My distance walked was 3.5 miles. My time was 3 hours. To find velocity, I used my calculator to find 3.5 miles divided by 3 hours which equaled 1.16 miles per hour. Did I accurately calculate my velocity? If not, what did I do wrong and what was my correct velocity?
Answer:
Yes, that is correct, although most velocity is calculated via m/s and therfore you would multiply your 3 hours by 60 twice. Much of the information given is irrelevant and just trying to confuse.
Explanation:
Compare the inner planets with the outer planets.
Inner Planets:
- Rocky
- Small
- Only 3 moons total
- Very close to each other (for space)
- Underweight
Outer Planets:
- Gassy oop-
- GIANT
- Over 200 moons total
- VERY far from each other
- Obese
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Good luck foe.
Lb.
Explain how electrostatic works on an atom level
At an atomic level, electrostatics is responsible for most of the physical phenomena that we encounter in our everyday life. Every object we see around us, such as chairs, buildings, and people, are made up of atoms, and every atom has electrons that are negatively charged, protons that are positively charged, and neutrons that have no charge.
Electrostatics is the study of electric charges at rest and of the forces and fields associated with these charges. Electrons are held in atoms by the attraction of the positive nucleus for the negative charge of the electrons. This attraction is known as electrostatic force. The protons in the nucleus are also held together by electrostatic forces, which are much stronger than those that bind electrons to the nucleus.
The forces between charged objects are governed by Coulomb's Law. This law states that the force between two charged objects is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges have the same sign, the force is repulsive; if they have opposite signs, the force is attractive.
Electrostatic forces play an important role in many physical phenomena, such as the attraction of dust particles to a TV screen, and the Van de Graaff generator, which uses electrostatic forces to build up very high voltages.
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Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec
Answer:
n =1.33 revolutions
Explanation:
Uniform Circular Motion
The angular speed can be calculated in two different ways:
\(\displaystyle \omega=\frac{v}{r}\)
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
\(\omega=2\pi f\)
Where:
f = frequency
Solving for f:
\(\displaystyle f=\frac{\omega}{2\pi}\)
Since the frequency is calculated when the number of revolutions n and the time t are known:
\(\displaystyle f=\frac{n}{t}\)
We can solve for n:
n=f.t
The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:
\(\displaystyle \omega=\frac{25}{90}\)
\(\displaystyle \omega=0.278\ rad/s\)
Now we calculate f:
\(\displaystyle f=\frac{0.278}{2\pi}\)
\(f=0.04421\ Hz\)
Calculating the number of revolutions:
n = 0.04421*30
n =1.33 revolutions
a light source with a frequency of 1.8 x 1015 s-1 is introduced to a metal which has a work function of 5.9 x 10-19 j. how much energy does the exiting electron have?
The exiting electron has an energy of 6.03 x 10⁻¹⁹J
The photoelectric effect is the emission of electrons while electromagnetic radiation, which includes light, hits a material. Electrons emitted in this way are referred to as photoelectrons.
In keeping with the well-known Einstein explanation of the photoelectric impact: The electricity of the photon could be sum total of electricity needed to put off the electron and kinetic energy of the emitted electron. consequently h nu= W + E.
The photoelectric effect is the manner wherein the electricity from electromagnetic radiation, together with visible light, gamma radiation or different hits an atomic electron wherein the power of the radiation is transferred in its entirety to the electron causing the electron to be ejected from the atom.
Calculation:-
KE = hv - work function
= 6.626 × 10⁻³⁴ ×1.8 x 10¹⁵ - 5.9 x 10⁻¹⁹
= 11.93 x 10⁻¹⁹ - 5.9 x 10⁻¹⁹
= 6.03 x 10⁻¹⁹ J
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What is matrix and what is its composition?
The matrix is the set of extracellular materials that will form a certain tissue. Through this there will be a physiological integration of the cells.
What is matrix and what is it's composition?In the matrix there will be different macromolecules, mainly collagen, enzymes, glycoproteins, among others which will give support to the cells that will be immersed in the matrix. It will also be involved in the process of cell multiplication and cell movement, since it will allow communication between the different cells to coordinate their cell functions.
The extracellular matrix is going to be composed, broadly speaking, of two components: interstitial matrix and the basal membrane. The interstitial matrix is one that will be formed by polysaccharides and fibrous proteins that gives it the characteristic to be able to cushion the compressions to which it may be subjected.
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how to make a brainliest questions Or how to Get them?
Answer:
Select the crown at the bottom of an answer where the speech bubble icon is.
How is conduction shown here:
Conduction Transfers Thermal Energy Through Direct Contact
Answer:
Conduction is the transfer of heat between substances that are in direct contact with each other. ... Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them.
Explanation:
the most critical component determining the kinetic energy of a projectile is:
The most critical component determining the kinetic energy of a projectile is its mass.
The kinetic energy (KE) of a projectile is determined by various factors, but the most critical component is its mass.
The formula for kinetic energy is given by:
KE = (1/2) * m * v^2
Where KE is the kinetic energy, m is the mass of the projectile, and v is its velocity.
Mass (m): The mass of the projectile plays a crucial role in determining its kinetic energy. The greater the mass of the projectile, the higher its kinetic energy will be for a given velocity. This is because kinetic energy is directly proportional to the mass of an object. A heavier projectile will have more mass, and hence, more kinetic energy.
Velocity (v): While velocity also contributes to the kinetic energy, it is the mass that has a more significant impact. The velocity is squared in the kinetic energy formula, meaning that doubling the velocity will result in four times the kinetic energy. However, doubling the mass will also double the kinetic energy.
Considering the relationship between mass and velocity in the kinetic energy formula, it becomes apparent that mass has a more critical effect on determining the kinetic energy of a projectile. Increasing the mass of the projectile will have a greater impact on its kinetic energy compared to increasing its velocity.
Therefore, the most critical component determining the kinetic energy of a projectile is its mass.
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A) The lunar excursion module has been modeled as a mass supported by four symmetrically located legs, each of which can be approximated as a spring-damper system with negligible mass. Design the spri
The Lunar Excursion Module (LEM) was designed to make a soft landing on the lunar surface, which required that the LEM must not bounce back into space upon impact. The LEM, therefore, was modeled as a mass that was supported by four symmetrically located legs.
Each of these legs could be approximated as a spring-damper system with negligible mass.The design of the springs had to be such that the total energy of the system was dissipated during the landing without causing any structural damage to the LEM. This is because the energy of the landing must not cause the spacecraft to bounce back into space.The design of the springs was also affected by the nature of the lunar surface. The lunar surface was not homogeneous and, therefore, the spacecraft had to be designed to deal with different types of soil and rocks.
This meant that the springs had to be able to adjust to different soil types and absorb the energy of the impact.In addition, the design of the springs was also affected by the lunar environment. The temperature on the moon fluctuates widely between day and night. Therefore, the springs had to be designed to withstand extreme temperatures without losing their resilience.
Finally, the design of the springs was affected by the mass of the spacecraft. The springs had to be able to support the weight of the spacecraft without collapsing while also being light enough to not add too much weight to the spacecraft. This meant that the springs had to be designed using lightweight and strong materials such as titanium alloys.
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Q1. Explain the conservation of energy in terms of the energy transformation(s) that occur when you strike (light) a match.
Q2. When you turn on a lamp at home you are using electricity generated by a power company or public utility. Assume the electricity powering the lamp was generated at a coal burning power plant and explain the conservation of energy in terms of the energy transformations that occur when you turn on the lamp.
Q3. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Q4. Does a pendulum swing forever? Why or why not?
Q5. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Q6. Describe the transformations between potential and kinetic energy when you drop a 15000 gram television from a height of 0.8 meters.
Q7. A car with a mass of 860 kg sits at the top of a 32 meter high hill. Describe the transformations between potential and kinetic energy that occur when the car rolls to the bottom of the hill and continues rolling.
Q8. How is the previous problem different from ones where the object comes to a stop at the end of moving/falling? Discuss what happens to the energy in each case and how they are different.
Q9. Describe the transformations between potential and kinetic energy that occur when a 1000 kg rock falls from the top of a 18 meter cliff.
Q10. How much kinetic energy does a 2000 gram ball have the instant before it hits the ground after falling from a height of 6 meters?
Q11. Assume the collision in problem 10 is perfectly elastic (no energy is lost) and there is no air friction. How high should the ball bounce? Describe the transformations between potential and kinetic energy that will occur from when the ball is dropped till it reaches the top of it's first bounce.
1) when we light a matchstick,the energy which got consumed in while rubbing the matchstick against the surface,turns into heat and hence ,it lights , therefore,the energy gets transferred from one type to another which proves the law of conservation of energy.
2) The coal gets burn and generate into electricity which further used by us for various purposes like lighting lamp and since the energy gets transferred from one source to another instead of ceasing, it proves the statement of conservation of energy.
3) As the pendulum swings in air , it continues to move from one point to another, changing potential energy to kinetic energy due to the motion that's taking place and unless an external force interferes, it's speed won't increase as at some point due to the friction by air will resist the movement resulting in decresement of kinetic energy and increased potential energy, thus ,at some point it will come to rest .
4) No ,it doesn't , because due to the force of friction,the disturbance in the movement of it ,takes place, making it stop at a specific point after some time.
5) As the pendulum swings in air , it continues to move from one point to another, changing potential energy to kinetic energy due to the motion that's taking place and unless an external force interferes, it's speed won't increase as at some point due to the friction by air will resist the movement resulting in decresement of kinetic energy and increased potential energy, thus ,at some point it will eventually come to rest .
6)
Mass (m)⇢15000 gram = 15 kgHeight(h)⇢0.8 metersAcceleration due to gravity(g)⇢9.8m/s²Potential energy ⇢mghPotential energy ⇢(15 x 9.8 x 0.8 )JPotential energy ⇢117.6 J7)
Mass (m)⇢15000 gram = 860 kgHeight(h)⇢32metersAcceleration due to gravity(g)⇢9.8m/s²kinetic energy ⇢mghkinetic energy ⇢(860 x 9.8 x 32 )Jkinetic energy ⇢269,696 J8) In the previous problem ,the kinetic energy increases as continues rolling and the potential energy decreases in this process of prolongation of the movement ,while ,when an object comes to rest after the process of moving or falling, it's potential energy is at the highest while the kinetic energy is just the opposite .
9)
Mass (m)⇢ 1000kgHeight(h)⇢18 metersAcceleration due to gravity(g)⇢9.8m/s²Kinetic energy ⇢mghKinetic energy ⇢(1000x 9.8 x 18 )JKinetic energy ⇢176,400 J10)
Mass (m)⇢ 2000 gm = 2kgHeight(h)⇢6metersAcceleration due to gravity(g)⇢9.8m/s²Kinetic energy ⇢mghKinetic energy ⇢(2x 9.8 x 6 )JKinetic energy ⇢117.6 J11)
In perfectly elastic collision, there's no loss of energy, hence ,the energy that got used up in the starting to bounce the ball ,will remain the same throughout the whole collision and the height would be the same 6 meters and kinteic energy would be 117.6J
which list is in order from smallest to biggest
Answer:
b
Explanation:
the solar system is smaller then nebula nebula is smaller then a galaxie and a galaxie is smaller then a universe
Rosalinda wants to calculate the mass of Earth using Kepler's laws or Newton's universal law of gravitation.Which
data would allow her to find the mass of Earth?
the mass of the Sun and the orbital period of the moon
the moon's orbital period and distance from Earth
Earth's distance from the Sun and the moon's orbital period
Earth's orbital perigd and distance from the Sun
Answer:
On Edg 2021, the answer was "B = The moon's orbital period and distance from Earth"
Explanation:
I hope this is correct for you, if it isn't I am very sorry. Good luck! :)
Newton's principles of motion and the universal law of gravitation can be used to derive Kepler's third law. Make the centripetal force equal to the force of gravity. The following expression, which may also be written as P2=42a3GM, can be obtained by inserting an expression for the planet's velocity: GMr=4r2P2. Thus, option B is correct.
What Kepler's laws or Newton's universal law of gravitation?Newton demonstrated that the force that causes something to fall toward the ground, like an apple, is the same force that causes the moon to orbit the Earth. The Sun, as well as any other star and its satellites, are affected by this universal force.
Newtonian physics and Kepler's laws serve as the foundation for planetary motion and orbital laws. Because these fundamental rules govern everything in the cosmos, they also govern how planets and artificial satellites move.
Therefore, If two things experience the same acceleration when the same force is applied to them, then they have the same inertial mass. Newton's second law makes use of the same mass.
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A CAR ACCElerates FROM REST To
50 M/S iN 7.5 S ; If its MASS = 2,000kg
HOW MUCH POWER is THE ENGINE Delivering
how do we know the sun within our solar system is not a first generation star born right after the big bang?
We know that the Sun within our solar system is not a first-generation star born after the Big Bang because the Sun contains heavier elements.
What is a first-generation star?A first-generation star is a star made of essentially only hydrogen and helium. First-generation stars are predicted to be enormous in size. They also live fast and die young.
An important component of stars is hydrogen gas. The nuclear fusion of hydrogen atoms produces the energy that sustains a star throughout its life. The nuclear fusion of hydrogen atoms also produces other elements including helium, carbon and oxygen.
Elements that the stars produce and that are heavier than hydrogen and helium are labeled metals. The Sun has been found to be metal-rich. This means it is at least a second-generation star.
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A slope of length 50 m rises to a height of 10 m above the ground. An effort of 100 N is needed to push a 250 N object up the ramp. Calculate: 1. AMA 2. VR 3. efficiency
1.) The AMA is 2.5
2.) The VR is 5.
3.) The efficiency is 50%.
Given that the object has a weight of 250 N and the effort needed to push it up the ramp is 100 N, we can calculate the AMA as follows:
AMA = Load / Effort
AMA = 250 N / 100 N
AMA = 2.5
Therefore, the AMA is 2.5.
To calculate the VR, we need to find the distance moved by the effort and the distance moved by the load. The distance moved by the effort is the length of the ramp, which is 50 m. The distance moved by the load is the height it is raised, which is 10 m. Therefore, we have:
VR = Distance moved by effort / Distance moved by load
VR = 50 m / 10 m
VR = 5
Therefore, the VR is 5.
To calculate the efficiency, we need to find the work done by the load and the work done by the effort. The work done by the load is:
Work done by load = Load x Distance moved by load
Work done by load = 250 N x 10 m
Work done by load = 2,500 J
The work done by the effort is:
Work done by effort = Effort x Distance moved by effort
Work done by effort = 100 N x 50 m
Work done by effort = 5,000 J
Therefore, the efficiency is:
Efficiency = (Load x Distance moved by load) / (Effort x Distance moved by effort)
Efficiency = (2,500 J) / (5,000 J)
Efficiency = 0.5 or 50%
Therefore, the efficiency is 50%.
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a) Find the moment of inertia of a point mass of 0.005 g at a perpendicular distance of 3 m from its axis of rotation. b) Find the moment of inertia of a sphere of mass 0.3 kg and radius 0.6 m. c) Find the kinetic energy of a rotating body with moment of inertia 0.003 kg m² and angular velocity of 0.6 rad s-¹.
Answer:
A. 4.5 x 10^-5 kg.m2
B. 108 x 10^-3 kg.m2
C. 54 x 10^-5
Explanation:
A. I = m(r^2)
point mass m = 0.005 g = 5 x 10^-6 kg
I = (5 x 10^-6 kg) x (3 m)^2 = (5 x 10^-6 kg) x 9 m^2 = 4.5 x 10^-5 kg.m2
B. I = m(r^2)
point mass m = 0.3 kg = 3 x 10^-1 kg
I = (3 x 10^-1 kg) x (0.6 m)^2 = (3 x 10^-1 kg) x 0.36 m^2 = 108 x 10^-3 kg.m2
C. KE = 1/2I(w^2)
KE = 1/2(3 x 10^-2 kg.m^2)(0.6 rad/s)^2 = 54 x 10^-5
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm.
Determine the horizontal distance travelled by the electron when it hits the plate.
Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=\(1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}\)=\(7*10^{14}\) m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
\(X=u[2y/a]^{1/2}\)
=\(4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}\)
=\(3*10^{-2}\)= 3 cm
if you have an electromagnet, how can you make its magnetic field stronger?
The magnetic field of an electromagnet can be strengthened in the following ways.
Increasing the current through the coil. The magnetic field's strength is inversely proportional to the current through the coil. The magnetic field of electromagnet will get stronger as the current increases.
Increase the number of wire turns in the coil to increase the magnetic field's strength.
By inserting a ferromagnetic core, such as iron, inside the coil, the magnetic field's intensity can be greatly increased.
Reducing the space between the coil and the core. The magnetic field gets stronger as the space between the coil and the core gets smaller.
Expanding the coil's surface.
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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
Answer:
Explanation:
is this marked??
(a). The car's average velocity between t = 1.0s to t = 1.5s will be - \(1\;m/s\)
(b). The car's acceleration at t = 1.5s will be - \(0.4\;m/s^{2}\)
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
The car's average velocity (in m/s) in the interval between -t = 1.0 s to t = 1.5 s.
The car's acceleration at t = 1.5 s.Determining whether car's speed increasing or decreasing with time.What is Acceleration?The rate of change of velocity with respect to time is called Acceleration. Mathematically -
\($a=\frac{dv}{dt}\)
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
\($v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s\)
PART - B
Velocity at t = 1.5 s will be -
\($v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s\)
The car's acceleration at t = 1.5s will be -
\($a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}\)
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words (pls dont just take my points :( )
Answer:
Gravity creates stars and planets by pulling together the material from which they are made.
Explanation: Thats the only thing i have im stuck on the tga quiz
5- A 2.0 kg block of aluminum (specific heat = 897 J/kg·K) is at an initial temperature of 300 K. What will its final temperature be if (3.35 × 105 J )of thermal energy is transferred to the block?
Answer:
T = 486.6 K
Explanation:
The final temperature of the block can be found using the following formula:
\(Q = mC\Delta T\\\)
where,
Q = Thermal Energy Transferred = 3.35 x 10⁵ J
m = mass of aluminum block = 2 kg
C = Specific Heat = 897 J/kg.K
ΔT = Change in Temperature = T - 300 K
T = Final Temperature of the Block = ?
Therefore,
\(3.35\ x\ 10^5\ J = (2\ kg)(897\ J/kg.K)(T-300\ K)\\\\5.38\ x\ 10^5\ J + 3.35\ x\ 10^5\ J = (1794 J/K)(T)\\\\T = \frac{8.73\ x\ 10^5\ J}{1794\ J/K}\)
T = 486.6 K
Shelley's cup of tea cooled down
1
2
of a degree in 10 minutes. At what rate is her tea cooling down
If Shelley's cup of tea cools 1/2 of a degree in 10 minutes, the rate of her tea cooling down is 0.05 degrees per minute.
10 minutes = 1 / 2 degrees
1 minute = 1 / 2 / 10 degrees
1 minute = 1 / 20 degrees
1 minute = 0.05 degrees
If a value is given for x amount of a factor, to calculate for unit amount of the factor, divide the value by the value of x. Similarly, if a value is given for unit amount of a factor, to calculate for x amount of factor, multiply the value by x.
Therefore, the rate of her tea cooling down is 0.05 degrees / minute.
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