Mass of the balloon is 45.5 kg.
Mass is the intrinsic property of any object.
Radius of balloon, r = 5.45 m
Distance moved by the balloon, d = 106 m
Time spent in moving, t = 21.5 s
Density of air, ρ = 1.2 kg/m³
Volume of the balloon = 4/3πr³
Volume = 4/3 * 3.142 * 5.45³
Volume = 4/3 * 3.142 * 161.87
Volume = 4/3 * 508.76
Volume = 678.35 m³
Density = mass / volume
Mass = Density * volume
Mass = 1.2 * 678.35
Mass = 814.02 kg
Velocity = distance / time
Velocity = 106 / 21.5
Velocity = 4.93 m/s
If it starts from rest, 0 m/s, then the final velocity is 9.86 m/s
acceleration = velocity / time
acceleration = 9.86 / 17 m/s²
acceleration = 0.58 m/s²
The mass dropped from the balloon decreases Mb and increases buoyancy
F = ma
mg = (Mb - m) * a
9.8 * m = (814.02 - m) * 0.58
9.8m * (1/0.58) = 814.02 - m
16.89m = 814.02 - m
16.89m + m = 814.02
17.89m = 814.02
m = 814.02 / 17.89
m = 45.50 kg
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pt 1
Question 4 (1 point)
How much current would flow in a closed circuit that has a 9.0V
battery and 5.00 total resistance?
HELP PLEASE GIVING BRIANLESS
To calculate the current in a circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). So, in this case, the current would be:
I = V / R
I = 9.0V / 5.00 ohms
I = 1.8 A
So, 1.8 A of current would flow in a closed circuit that has a 9.0V battery and 5.00 total resistance.
A ball is thrown down vertically with an initial speed of v0 from a height of h. (a) What is its speed just before it strikes the ground? (b) How long does the ball take to reach the ground? What would be the answers to (c) part a and (d) part b if the ball were thrown upward from the same height and with the same initial speed? Before solving any equations, decide whether the answers to (c) and (d) should be greater than, less than, or the same as in (a) and (b).
Answer:
a) v² = v₀² + 2 g h, b) t = v₀/g (1+ √ (1 + 2gh/ v₀²))
Explanation:
a) This is an exercise that we can solve using conservation of energy.
Starting point. High point
Em₀ = K + U = ½ m v₀² + m gh
Final point. Soil
\(Em_{f}\) = K = ½ m v²
energy is conserved because there is no friction
Emo = Em_{f}
½ m v₀² + m g h = ½ m v²
v² = v₀² + 2 g h
b) the time it takes to reach the ground can be calculated with kinematics
let's create a reference frame with positive upward direction
v = vo - g t
when it reaches the ground it has a velocity v, the initial velocity is downwards v₀ = -v₀
v = -v₀ - gt
t = - (v + v₀) / g
we substitute the velocity values calculated in the previous part
t = - (√(v₀² + 2 g h) + vo) / g
we will simplify the equation a bit
t = - v₀/g (1+ √ (1 + 2gh/ v₀²))
c) is now thrown vertically upward with the same initial velocity vo.
To find the final velocity we use the conservation of energy where the velocity is squared, so it does not matter if it is positive or negative, therefore in this section the value should be the same as in part a
v = √ (v₀² + 2gh)
d) for this part if there is change since the speed is not squared
v₀ = v₀
v = v₀ - gt
t = (v₀ - v) / g
t = (v₀ - √(v₀² + 2 g h)) / g
t = v₀/g (1 - √(1 + 2gh / v₀²))
During a picnic, you and two of your friends decide to have a three-way-tug-of-war, with three ropes in the middle tied into a knot. Roberta pulls to the west with 277 N of force; Michael pulls to the south with 603 N. a) With what force should you pull to keep the knot from moving
Answer:
Explanation:
I'm not 10% sure but i think that if you were to do:
603 + 277 = 880
1000 - 880 = 120
So to keep it from moving, i think you would need to pull with a force of 120N
The force with which it should be pulled to keep the knot from moving is 663.58 N.
What is Newton's third law ?Newton's third law states that, for every action, there is an equal and opposite reaction.
Here,
Force exerted by Roberta, F₁ = 277 N
Force exerted by Michael, F₂ = 603 N
Since, Roberta is pulling to the west and Michael is pulling towards the south, the angle between the forces applied by them is 90°.
The force needed to keep the knot from moving is the resultant force of these two forces.
Therefore, the resultant force,
Fₙ = √F₁² + F₂²
Fₙ = √(277)² + (603)²
Fₙ = 663.58 N
Hence,
The force with which it should be pulled to keep the knot from moving is 663.58 N.
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_____ is a force which is applied to an object by another object or a person. __________ is a force that always opposes the motion of an object and is frequently ignored. a. Tensional force, friction c. Applied force, air resistance b. Friction, applied force d. None of the above. Please select the best answer from the choices provided A B C D
Answer:
Fritional force
Explanation:
Fritional force is a force that always opposes the motion of an object and is frequently ignored
C
Explanation:
Applied force, air resistance
Theoretically, in an infinite 100% vacuum, how much of it's kinetic energy does an object flying 100 m/s lose after 5 seconds?
1. What were enron failure issue ? What were corporate Governance isues in Enron.
The Enron scandal drew attention to accounting and corporate fraud as its shareholders lost $74 billion in the four years leading up to its bankruptcy, and its employees lost billions in pension benefits.
What were Enron failure issue ?Enron's Board of Directors failed to fulfil its fiduciary duties towards the corporation's shareholders. Secondly, the top executives of Enron were greedy and acted in their own self-interest.
Enron's downfall was attributed to its reckless use of derivatives and special purpose entities. By hedging its risks with special purpose entities which it owned, Enron retained the risks associated with the transactions. This arrangement had Enron implementing hedges with itself.
Enron raised fundamental issues about corporate fraud, accounting transparency, and investor protection.
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A lorry of mass 2000kg moving with a speed of 50kmh' collides with a drum of mass 25kg at a police checkpoint. The velocity of the lorry after the impact is 34kmh'. What is the velocity of the drum?
The velocity of the drum after the collision with a lorry of 2000 kg mass is determined as 1,280 km/h.
What is the velocity of the drum?The velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the lorrym₂ is the mass of the drumu₁ and u₂ are the initial velocitiesv₁ and v₂ are the final velocitiesThe velocity of the drum after the collision is calculated as;
2000 (50) + 25(0) = 2000(34) + 25v₂
100,000 = 68,000 + 25v₂
25v₂ = 32,000
v₂ = 32,000/25
v₂ = 1,280 km/h
Thus, the final velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum.
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The velocity of the drum after the collision, given that a 2000 kg lorry moving with a speed of 50 Km/h collides with it, is 1280 Km/h
How do I determine the velocity of the drum after collision?The following data were obtained from the question given above:
Mass of lorry (m₁) = 2000 KgInitial velocity of car (u₁) = 50 Km/hMass of drum (m₂) = 25 KgInitial velocity of truck (u₂) = 0 Km/hFinal velocity of lorry (v₁) = 34 Km/hFinal velocity of drum (v₂) = ?The law of conservation of linear momentum states as follow:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Inputting the given parameters, the velocity of the drum after the collision can be obtain as follow:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2000 × 50) + (25 × 0) = (2000 × 34) + (25 × v₂)
100000 + 0 = 68000 + 25v₂
Collect like terms
25v₂ = 100000 - 68000
25v₂ = 32000
Divide both sides by 25
v₂ = 32000 / 25
v₂ = 1280 Km/h
Thus, the velocity of the drum after collision is 1280 Km/h
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I want to know about the inventions caused due to rain. Like the Benjamin Franklin's Lightning Conductor. I have to make a chart.
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33.1 ◦C . In an attempt to cool the liquid, which has a mass of 185 g , 90.3 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.(2 significant digits pls)
90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .
How do you calculate the amount of heat needed to melt ice?Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.
In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.
Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.
Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J
We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:
m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg
Finally, we round the mass to two significant digits and convert it to grammes:
m2 = 90.1 g
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A 12 V automobile battery is connected to an electric starter motor. The current
through the motor is 250 A.
a) How much power does the motor dissipate?
b) How much energy does the battery deliver to the motor during the 26 s period?
PLEASE HELP QUICK
Answer: \(3000\ W,\ 78,000\ J\)
Explanation:
Given
The voltage of the battery is \(V=12\ V\)
Current through the battery is \(I=250\ A\)
(a) Power is the product of voltage and current
Power dissipates is given by
\(P=VI\\P=12\times 250\\P=3000\ W\)
(b) Energy delivered
\(E=P\times t\)
\(E=3000\times 26\\E=78,000\ J\)
In the United States, about _________ % of females and ________ % of males smoke.
a. 15; 30
b. 18; 24
c. 26; 21
d. 30; 30
Approximately 18% of girls and 24% of males in the United States smoke as of 2019, according to the Centers for Disease Control and Prevention (CDC).
Do both men and women smoke in the US?In general, men are more likely than women to use any type of tobacco product. 15.6% of adult females and 16.7% of adult males smoked cigarettes in 2015. These variations could be attributed to a mix of biological (especially ovarian hormones), cultural, and behavioural elements.
In India, how many males smoke?India is the nation with the second-highest number of tobacco smokers in the world with 267 million users (behind China). There are about 100 million smokers in the world today who are over the age of 15. (cigarettes and bidis).
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Question:
"In the United States, about what percentage of females and what percentage of males smoke?
a. 15%; 30%
b. 18%; 24%
c. 26%; 21%
d. 30%; 30%"
ASAP pls answer right and I will mark brainiest
Answer: question one: i cannot tell Question 2: waxing crescent Question 3: waxing gibbous Question 4: B
Explanation
PLS HELP! Answer these questions pls. I will mark BRAINLIEST, FIVE STARS AND THANKS. The second question in the pic has three answers. *50 POINTS!*
Answer:
First one is hydrogen and oxygen
Second one is color change, solid dissolves, and temperature increases
Explanation:
Electrolysis is the process of using electricity to decompose water into hydrogen and oxygen.
Odors and change of states are physical changes while the rest are chemical changes.
Hope this helped!
which is the product of cellular respiration? A. ATTP B. light C. oxygen D.sugar
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
A fireplace arch is to be constructed in the shape of a semi ellipse. The opening is to have a height of 2 feet at the center and a width of 6 feet along the base (see figure). The contractor draws the outline of the ellipse using tacks as described at the beginning of this section. Determine the required positions of the tacks and the length of the string.
To construct a semi-ellipse fireplace arch with a height of 2 feet and a base width of 6 feet, the contractor can use the following steps:
Determine the center point of the arch. Mark this point on the floor and call it point C.Measure the height of the arch, which is 2 feet. Mark this point above point C and call it point A.Measure the base width of the arch, which is 6 feet. Mark two points on either side of point C at a distance of 3 feet each. Call these points B and D.
Tie a string to a tack at point A, and loop it around two more tacks at points B and D.Adjust the length of the string until it is taut, but not too tight.Using a pencil, trace the curve of the string from point B to point D. This will create the semi-ellipse shape.
The required positions of the tacks and the length of the string will depend on the specific measurements and dimensions of the fireplace arch. By following these steps, the contractor can ensure that the semi-ellipse fireplace arch is constructed accurately and meets the desired specifications.
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A piece of irregularly shaped metal weighs 300N in air. When the metal is completely submerged in water, it weighs 232.5N. Find the volume and specific gravity of the metal.
Answer:
Volume of metal piece = 0.0069 m³ (Approx.)
Explanation:
Given:
Weight of metal in air = 300 N
Weight of metal in water = 232.5 N
Find:
Volume of metal piece
Specific gravity of metal
Computation:
We know that;
Density of water = 1,000 kg/m³
Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water
Buoyant force applied on metal piece = 300 N - 232.5 N
Buoyant force applied on metal piece = 67.5 N
Buoyant force = Volume of metal x Density of water x Gravitational force
67.5 = Volume of metal x 1,000 x 9.8
Volume of metal piece = 0.0069 m³ (Approx.)
A 100 kg block slides down a frictionless ramp which is at an angle of 26.6 ∘ with the horizontal. Find the magnitude of the velocity of the block when it gets to the bottom of the ramp if the length of the incline is 50 meters. V=_____m/s
The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude
(100 kg) g sin(26.6°) ≈ 438 N
(Note that the positive sign here means we take "down the ramp" to be the positive direction.)
Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that
438 N ≈ (100 kg) a ⇒ a ≈ 4.38 m/s²
The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that
v² = 2a (50 m)
Solve for v :
v = √(2a (50 m)) ≈ 20.9 m/s
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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What is the kinetic energy of a car with a mass of 1200 kg and is traveling at 40 m/s?
Answer:
9,600,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 1200 \times {40}^{2} \\ = 600 \times 1600\)
We have the final answer as
9,600,000 JHope this helps you
how to calculate the end point on a wave when x is greater than zero
Answer:
get good
Explanation:
get good
djhdhdhdjdusigxig 9gc
help on this asap please
Answer:
I think A is correct.
Explanation:
If it's not I'm sorry probably my fault but I hope this helps:)
The path of a projectile fired at an angle above the horizontal is best described as
Water from a river or reservoir enters a hydroelectric power plant through a.....????
The most common type of hydroelectric power plant is an impoundment facility. An impoundment facility, typically a large hydropower system, uses a dam to store river water in a reservoir. Water released from the reservoir flows through a turbine, spinning it, which in turn activates a generator to produce electricity.
What is turbine ?
"A turbine is a rotary mechanical device that extracts energy from a fluid flow and converts it into useful work." The work produced by a turbine can be used for generating electrical power when combined with a generator.
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Photons of infrared radiation with wavelengths longer than those of visible light will have what kind of energy compared to that of visisble light?
Answer:
Infrared photons carry lower radiation energy than the visible light.
Explanation:
Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.So, we can write the energy of a single photon as follows:\(E = h*\nu (1)\)
Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.So, an infrared photon carries less energy that one of the visible light.Infrared photons carry lower radiation energy than the visible light.
What are visible and infrared radiation?
Visible light is the section of the spectrum of electromagnetic radiation which are visible to human eyes. The wavelength range of this light varies from 400 nm to 700 nm .
Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
So, we can write the energy of a single photon as follows:
\(E=h\nu\)
Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
So, an infrared photon carries less energy than one of the visible light.
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A train travels 8.81 m/s in a -51.0° direction.
The train accelerates for 2.23 s, changing its
velocity to 9.66 m/s in a 37.0° direction.
What is [delta]x?
The displacement of the train after 2.23 seconds is 25.4 m.
Resultant velocity of the trainThe resultant velocity of the train is calculated as follows;
R² = vi² + vf² - 2vivf cos(θ)
where;
θ is the angle between the velocity = (90 - 51) + 37 = 76⁰R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)
R² = 129.75
R = √129.75
R = 11.39 m/s
Displacement of the trainThe displacement is calculated as follows;
Δx = vt
Δx = 11.39 m/s x 2.23 s
Δx = 25.4 m
Thus, the displacement of the train after 2.23 seconds is 25.4 m.
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I need help with this
The required volume of the plastic bin with the respective unit would be 619.65 cubic cm.
What is the volume of the cuboid?The volume of a cuboid is equal to the product of the length, width, and height of a cuboid.
The volume of a cuboid is length × width× height
Width (W) = 9.0 cm
Length (L) = 15.3 cm
Height (H) = 4.5 cm
As it is 3D geometry
The equation of volume will be L×W×H
The volume of the plastic bin = 15.3 ×9.0 × 4.5
The volume of the plastic bin = 619.65 cubic cm.
Therefore, the volume of the plastic bin would be 619.65 cubic cm.
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A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey
i) The initial deceleration of the car is -1.6 m/s² and the time taken is 5 seconds
ii) The final deceleration is -1 m/s²
iii) The total dispalcement = 1016 m
What is the initial deceleration of the car?The initial deceleration of the car is given by the formula below:
v² = u² + 2as
where;
v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacementSolving for a;
12² = 20² + 2 * a * 80
a = -1.6 m/s²
Time taken, t = v - u / a
t = 12 - 20 / (-1.6)
t = 5 seconds
Final deceleration:
a = v - u / t
a = 0 - 12 / 12
a = -1 m/s²
iii) Displacement at constant velocity = 12 * 1 * 60
Displacement at constant velocity = 720 m
Final displacement, s = ut + 0.5at²
s = 12 * 12 + 0.5 * 1 * 12²
s = 216 m
Total dispalcement = 80 + 720 + 216
Total dispalcement = 1016 m
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Question 5 (10 points)
When a large amount of groundwater is extracted, what type of effects can occur
due to this large amount of water extraction? (*select all that apply)
Select 3 correct answer(s)
water table decrease
no change to water table
salt water intrusion
sinkholes
PLEASE HELP
Answer:
sink hole, water table decrease ,and salt water intrusion
Answer:
pls give brainliest
Explanation:
sink hole,water table descrese and salt water intrusion
Most nitrogen atoms have a mass of 14u (hence 28u for N2), but a small
percentage of nitrogen atoms have an extra neutron and thus an atomic mass of 15u. (We
refer to atoms of the same element but with different masses as isotopes of that element.)
Recently, scientists studying isotope data from the Cassini spacecraft have noticed that
the ratio of 15u nitrogen to 14u nitrogen is much larger than it is here on earth. Assuming
that Titan and the earth originally had the same isotope ratios, explain why the ratios
might be different today.
Answer:
itan it is much further from the sun, so the transformation of Carbon into 14 carbon is very small, so there is no process that changes the relationship between ¹⁵N/¹⁴N,
Explanation:
If the relationship between ¹⁵N and ¹⁴N is different on Earth and titan, they indicate that the relationship is higher in casino.
The first thing to clarify that this transformational is due to changes at the nuclear level.
Specifically carbon by incidence of cosmic rays from the sun forming ¹⁴C, this atom is unstable and decays after its life span of 5730 years in ¹⁴N, on Earth it is much closer to the Sun so the amount of cosmic rays is much greater therefore the amount of nitrogen atom 14 increases whereby the ratio between the two isotopes of nitrogen decreases.
In the case of Titan it is much further from the sun, so the transformation of Carbon into 14 carbon is very small, so there is no process that changes the relationship between ¹⁵N/¹⁴N, The reactionary from Saturn is fundamentally in infrared that does not have energy to change the nuclear structure of the coal.
For which the most likely explanation is the absence of means to transform carbon into carbon 14 by the remoteness of Titan from the Sun