A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards across a friction-free surface. determine the acceleration.

Answers

Answer 1

Answer:

4.95 m/s/s

Explanation:

Upon neglecting air resistance, there are three forces acting upon the object. The up and downforce balance each other and the acceleration is caused by the applied force. The net force is 5.20 N, right (equal to the only rightward force - the applied force). So the acceleration of the object can be computed using Newton's second law.

a = Fnet / m = (5.20 N, right) / (1.05 kg) = 4.95 m/s/s, right

Answer 2

The acceleration of an object with the mass of 1.05 kg and force of 5.20 N is 4.95 m/s².

What is Force?

Force is an external agent which is capable of changing the state of rest or motion of an object. Force is a vector quantity as it has both the magnitude and direction. The SI unit of force is Newton (N). It is the product of mass of the object and acceleration.

F = m × a

where, F = Force of the object,

m = mass of the object,

a = acceleration of the object

Therefore, the acceleration of the object which moves rightwards across a friction-free surface is:

a = F/ m

a = 5.20 / 1.05

a = 4.95 m/s²

Therefore, the acceleration of the object is 4.95 m/s².

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Related Questions

What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact

Answers

Answer:

The characteristics that determine how easily two substances change temperature are:

specific heat of the material that makes up the substancesarea in contact between the two substances

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

true or false if the Ferris Wheel is not accelerating since the linear or tangential speed is constant.

Answers

Answer:

True

Explanation:

What is the definition of the half-life of a radioactive isotope?
answer: The time it takes for half the parent nuclei in a sample to become daughter nuclei.

Answers

Answer: The half-life is the amount of time it takes for a given isotope to lose half of its radioactivity. If a radioisotope has a half-life of 14 days, half of its atoms will have decayed within 14 days. In 14 more days, half of that remaining half will decay, and so on.

the weight of an object is measured in air to be 7N the object is then immersed in water and its apparent weight is measured to be 4N determined the buoyant force and state whether or not the object float

Answers

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Which of these would be a part of a force diagram for this image? Check all that apply.

Answers

The options that would be a part of a force diagram for the attached image are:

A; A dot that represents the box

B; A vector labeled Fg, pointing straight down

E; A vector labeled Fs, pointing parallel to and up the ramp.

What are the qualities of a force diagram?

This is a simple force diagram of an item lying on an inclined plane.

The first step is to draw a dot in the center of the box, as here is where we will draw the other forces operating on the box.

Second, we must recognize the force of gravity (F_g), which is a vertical vector line drawn from that dot and whose perpendicular component assures that the box is pressing against the inclined plane.

Third, we can see that the box is moving down the slope, but it will face some friction in the other direction. As a result, we will draw a vector line parallel to the inclined plane from the dot to the left of the box. Frictional force (F_fs) will be shown by this line.

Fourth, there would be a normal force attempting to counteract the perpendicular component of gravity (F_g). This normal force is perpendicular to the perpendicular component of F_g. This is referred to as F_g•sin. We will draw a vector line perpendicular to the inclined plane starting from the dot to represent this normal force. F_n represents this normal force.

Looking at the possibilities, only Options A, B, and E correlate to the forces stated above.

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Which of these would be a part of a force diagram for this image? Check all that apply.

Where does the force come from to make a windmill turn?

Answers

Answer:

When wind flows across the blade, the air pressure on one side of the blade decreases. The difference in air pressure across the two sides of the blade creates both lift and drag. The force of the lift is stronger than the drag and this causes the rotor to spin.

Explanation:

A car travel with a constant velocity of 45m/h for

20s.what distance does it cover?​

Answers

Answer:

15m

Explanation:

Distance = velocity x time

We neeed to convert the time to the same units that the velocity has (which is per hour)

20s = (60/60/3) hrs

20s = 1/3 hrs

distance = 45 x 1/3

distance = 15m

Find the Product or expression of: (4x-2)2​

Answers

Answer:

8x-4

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

\(\Longrightarrow: \boxed{\sf{8x-4}}\)

Hence, the final answer is 8x-4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4

You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.

Answers

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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HELP PLEASE THIS IS URGENT!!!

HELP PLEASE THIS IS URGENT!!!

Answers

The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.  

Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.

Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.

From the given,

X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two.  ₐ₋₂Xᵇ⁻⁴ ----->    ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.

When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay,  ₐ₋₅Xᵇ⁻⁸ ----->  ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.

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Where is the density of the material greater, at point B or point C?
Explain why.

Answers

Answer: The density is greater at point C

Explanation: At that point

The convention current slowly cools off

Why is Joshuas head so big?

Answers

Answer:

because he has a big brain and skull

Explanation:

well technically the bigger brain the bigger the head because the size of your skull determines the size of the brain so that concludes why Joshua's head is so big.

hope this helps

What is the unit of pressure
is it P=F/A?

Answers

The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2). This name for the unit was added in 1971; before that, pressure in SI was expressed simply in newtons per square metre.

Answer:

Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2

Explanation:

P = F/A is a formula for pressure not a unit.

Pa = Pascal

Bar = Bar

at = Technical Atmosphere

Torr = Torr

lbf/in^2 = pounds per square inch

A 0.750-m-long pulse is travelling at a speed of 6.12 m/s in a spring. How long does it take the pulse to pass any point on the spring?

Answers

Answer:

0.122secs

Explanation:

Speed  = Distance/Time

Given

Speed = 6.12m/s

Distance = 0.750m

Substitute

Time - Distance//Speed

Time = 0.75/6.12

Time = 0.122secs

Hence it takes the pulse 0.122secs

How does understanding what occurs at the various tectonic plate boundaries support our understanding of the past and current movement of rocks at earth's surface?

Answers

Answer:

Understanding what occurs at the various tectonic plate boundaries supports our understanding of the past and current movement of rocks at Earth's surface because the movement of the plates is responsible for shaping the planet's surface features, such as mountain ranges, ocean basins, and volcanoes. Different types of plate boundaries produce different geological features and events. For example, convergent plate boundaries, where two plates move towards each other, result in subduction zones, where one plate is forced beneath another, and can cause volcanic activity and earthquakes. Divergent plate boundaries, where two plates move away from each other, can cause seafloor spreading, mid-ocean ridges, and rift valleys. Transform plate boundaries, where two plates move past each other, can cause earthquakes. By studying the processes and features associated with these plate boundaries, scientists can gain insight into how the Earth's surface has changed over time and how it continues to change today.

Explanation:

Help me please I need it as soon as possible

Help me please I need it as soon as possible

Answers

Answer: B im sorry if its wrong

Explanation:

I think the answer would be D

Atoms are split at power plant to create electricity*
O A. Radiant to Mechanical
O B. Nuclear to Electrical
O C. Chemical to Radiant
D. Mechanical to Electrica;
help please I’m in a test that closes at 6

Answers

Answer:

B. Nuclear to Electrical

Explanation:

Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.

When atoms are split, nuclear energy is released. Some part of the mass of the atom is converted to energy. The nuclear energy released is expressed as heat energy. This energy is used to heat water in boilers when produces steam that are used to drive the movement of turbines. This in turn generates electricity.

2. A tennis ball machine launches balls horizontally with an initial speed of 5.3 m/s, from a height of 1.2 m.
a) What will the time of flight be for a tennis ball launched by the ball machine? (3)
b) What will the range of the tennis ball be? (2)
c) What will be the final velocity of the ball with which it reaches the ground? (3)

Answers

(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

Time of flight of tennis ball

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

Range of the tennis ball

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

Final velocity of the ball

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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A horizontal force of 15N is needed to keep a box sliding on a horizontal floor at a constant speed of 0.5m/s. The speed of the box is increased to 1.5m/s by some means (which is not the concern of this question). What horizontal force would be needed to keep the same box sliding on the same horizontal floor at a constant speed of 1.5m/s?

Answers

The horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.

Horizontal force

The horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is calculated as follows;

\(F= \frac{mv}{t} \\\\mv = Ft\\\\m = \frac{Ft}{v} \\\\\frac{F_1}{v_1} = \frac{F_2}{v_2}\)

where;

v1 is the initial velocityv2 is the final velocity

\(F_2 = \frac{F_1v_2}{v_1} \\\\F_2 = \frac{15 \times 1.5}{0.5} \\\\F_2 = 45 \ N\)

Thus, the horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.

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1. Two equally charged particles are held apart when they are released from rest, the initial acceleration of 1st particle is 7.22 m/s^2 and 2nd is 9.16 m/s^2. The mass of the 1st particle is 6.31×10^(-7) kg. Find the mass of 2nd particle and common charge.

Answers

The mass of 2nd particle  be 4.97×10⁻⁷ kg.

The common charge can not be determined.

What is force?

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given that: two equally charged particles are held apart when they are released from rest. So force acting on them is same.

For 1st particle:

Mass: m₁ =  6.31×10⁻⁷ kg.

Acceleration: a₁ =  7.22 m/s².

For 2nd particle:

Acceleration: a₂ =  9.16 m/s².

Mass: m₂ = ?

As force acting on both particle is same.

m₁a₁ = m₂a₂

⇒ m₂ = m₁a₁/a₂ = ( 6.31×10⁻⁷ kg)×( 7.22 m/s²)/( 9.16 m/s²) = 4.97×10⁻⁷ kg.

So,   the mass of 2nd particle  be 4.97×10⁻⁷ kg.

As there has no mention of distance between them and which type of particle it is, common charge can not be determined.

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The tension in a pulley belt is 31 N when stationary. Calculate power in watts transmitted when the belt is on the point of slipping on the smaller wheel. the wheel is 379 mm diameter and the coefficient of friction is 0.3. The angle of lap is 1610. The wheel speed is 1,547 rev/min.

Answers

Answer:

P = 756.84 Watts

Explanation:

As the tension is stationary or innitial, T₀ = 31 N, the mean would be:

T₁ + T₂ / 2 = T₀    (1)

T₁ + T₂ = 2 * 31 = 62 N

Now, with the following expression we can determine the linear speed:

V = πWD  (2)

W: angular speed of the wheel  (rev/s)

D: diameter of the wheel (in meters)

W = 1547 rev/min * (1 min/60 s) = 25.78 rev/s

V = π * 25.78 * 0.379 = 30.695 m/s

We also know that:

T₁ / T₂ = exp (μθ)

T₁ = T₂ exp(μθ)   (3)

We already have those values so replacing:

T₁ = T₂ exp(0.3 * 161 * π/180)

T₁ = 2.32T₂   (4)

We can now replace (4) in (1) like this:

T₁ + T₂ = 62 N

2.32T₂ + T₂ = 62

3.32T₂ = 62

T₂ = 18.67 N

Which means that T₁:

T₁ = 2.32(18.67)

T₁ = 43.33 N

Finally, the power can be determined using the following expression:

P = (T₁ - T₂)V  (5)       Replacing we have:

P = (43.33 - 18.67)*30.695

P = 756.84 Watts

Hope this helps

Find the torque t due to the spring. Assume that theta is small enough that the spring remains effectively horizontal and you can approximate sin(theta) = theta and cos(theta) =1.

Express the torque as a function of theta and other parameters of the problem. In this context, the torque will be a 1D vector; therefore, your equation must correctly express the relationship between the direction of torque and the direction of ant other 1D vectors within your equation.
Hints:

Deflecting the rod will stretch or compress the spring by a length L. The spring will react with a restoring force given by Hooke's law: F=-kL. What is L? Remember that the angle theta is assumed to be so small that sin(theta) = theta. express in terms of L and theta.

The torque τ about a point is defined as the product of the force F acting on a body times the moment arm (perpendicular distance d from the line of action of the force to the center point): T = Fd. What is d for the given situation? Remember that the angle θ is assumed to be so small that cos(θ)≈1.

Answers

Therefore, the frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.

How to solve

Since the rod is thin and uniform, its moment of inertia about the pivot point can be approximated as:

I = (1/3)ML^2

When the spring is connected 1/5 of the way from the pivot to the end of the rod, the effective length of the rod becomes:

l_eff = l/5 + (4/5)(l/2) = 9l/10

So, the frequency of oscillation is: 8.42 rad (after calculations)

The frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.


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A ball is thrown upward in the air with an initial velocity of 40 m/s. How long does it take to
reach back to the point it was thrown from?

Answers

Answer:

You need the definition of acceleration (a=Vf-Vi/t) and 1 equation of linear motion (deltaX = Vi×t + 1/2×a×t^2). Since you know a is constant (gravity) and you know your initial Vi to be 40 m/s and your final velocity Vf to be zero (maximum height), then you can use thhe definition of acceleration to find time.

-9.81m/s^2 = (0-40m/s)/t

t = (-40)/(-9.81) s

t = 4.077s

Now that you have time, you should know all but deltaX in the equation of linear motion.

dX = (40m/s)(4.077s) + (1/2)(-9.81m/s^2)(4.077s)^2

dX = (163.099m) — (81.549m)

dX = 81.55m

The cycling of the air is a natural phenomenon as shown above is the result of

The cycling of the air is a natural phenomenon as shown above is the result of

Answers

Answer:

natural convection

............

The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-N applied force. The uniform horizontal rod has a mass of 15 kg and is welded to the block at B. Friction in the guide is negligible.

Required:
Compute the bending moment M exerted by the weld on the rod at B. The bending moment is positive if counterclockwise, negative if clockwise.

Answers

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

\(\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2\)

Bending moment M:

From the second part of the diagram:

\(\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}\)

The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under

Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mile of tritium plus 1 mole of deuterium to be a mole of "reactions" ( total molar mass = 5 grams)

Answers

The energy released per kilogram of fuel used is 3.39 * 1014 J/Kg

Why is the energy released in a reaction?

Energy is released in a reaction because of  the breaking of bonds are well as formation of bonds.

The quantity of energy released in reactions differs according to the reaction type involved.

The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.

The energy, E released in nuclear reactions is given by the formula below:

Energy per kilogram of reactants (in joules) = Energy per mole of reactants (in joules) / Total molar mass of reactants (in kg)

Energy per kilogram of reactants (in joules)  = \(1.60218 x 10^-^1^3 joules\) /  5 grams

Energy per kilogram of reactants (in joules)   =  3.39 * 1014 J/Kg

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The energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

5 grammes, 0.005 kilogrammes, of reactants are provided.

Since 1 mile of tritium and 1 mile of deuterium are equal to 1 mole of "reactions," the sum of the "reactions" in 0.005 kilogrammes of reactants may be computed as follows:

Total moles of "reactions" in 0.005 kg of reactants = (0.005 kg / 5 g/mol)                            

                                                                                     = 0.001 mole.

The MeV per reaction must now be multiplied by the total number of "reactions" in order to get the total energy released by the "reactions."

Next, the energy must be converted from MeV to Joules.

MeV to Joules conversion factor is 1.6 10-13 J/MeV.

Total energy released = (MeV per reaction) x (number of reactions) x (conversion factor)

Total energy released = (17.6 MeV/reaction) x (0.001 mole) x (1.6 × 10^-13 J/MeV)

Total energy released = 2.816 × 10^-16 J

The total energy released by the "reactions" is 2.816 × 10^-16 J.

To determine the energy released per kilogram of fuel used, we need to divide the total energy by the mass of fuel used.

Total energy released per kilogram of fuel used = (total energy released) / (mass of fuel used)

Total energy released per kilogram of fuel used = (2.816 × 10^-16 J) / (0.005 kg)

Total energy released per kilogram of fuel used = 5.632 × 10^-14 J/kg

Therefore, the energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

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Help on this question ‼️

Help on this question

Answers

Answer:

I think the option b

Is the answer

Answer:

C

Explanation:

after a CCW rotation it would become a waning gibbous, so after a Clockwise rotation it would be a waxing gibbous (opposite)

How do people get energy from the food they eat

Answers

It is converted into different energy sources since it is not destroyed. You get protien from the energy

A 1200 kg car moving +13.7 m/s makes
an elastic collision with a 3200 kg truck,
initially at rest. What is the velocity of the
car after the collision?
(Unit = m/s)
Remember: right is +, left is -

Answers

When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.

The total momentum of the system before the collision is calculated as follows:P_initial = m_car x v_carP_initial = 1200 kg x 13.7 m/sP_initial = 16,440 kg*m/s Since the two cars stick together after the collision, their final velocity is the same. Let's suppose the final velocity of the cars after the collision is v_f. Then:P_final = (m_car + m_obstacle) x v_fwhere m_obstacle is the mass of the object the car collided with. Because the car is at rest after the collision, we can assume that the velocity of the object it collided with is zero. Therefore:P_final = m_car x v_fP_final = 1200 kg x v_fThe momentum of the system after the collision must be equal to the momentum of the system before the collision. That means:P_initial = P_final16,440 kg*m/s = 1200 kg x v_fv_f = 13.7 m/s - (16,440 kg*m/s / 1200 kg) v_f = 13.7 m/s - 13.7 m/s v_f = 0 m/sTherefore, the car will come to a stop after the collision.

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Which best describes the direction of heat?

Answers

the second law of thermodynamics
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Most people tend to be more free and spontaneous with their expenditures during a recession or crisis. Group of answer choices True False Please help me solve this. What is the percent of change from 22 to 11? HELP 2x+3=7 Substitute your solution for x into 2x+3 and evaluate. What do you get? do fungi live in warm environments If everybody disagrees about what is right and what is wrong, then it follows that:A) None of these.B)The majority is right.C)The minority must be wrong.D)There is no truth of the matter.E)There is only one truth of the matter.philosophy High Blood pressure has been identified as a risk factor for heart attacks and strokes. The proportion of U.S. adults with high blood pressure is 0.2. A sample of 37 U.S. adults is chosen. Round Answer to at least 4 decimal places. The United States controlled what canalwhen it opened in 1914?A. Colombian CanalB. Caribbean CanalC. Panama CanalD. American Canal You are considering a project in Bolivia that would generate 3 million dollars in cash flows per year going forever. The cost of the project is 10 million dollars. The discount rate for the project is 15%. You believe that there is some probability of expropriation prior to the 3rd year (after the 2nd cash flow). Which of the following statements is most correct? a. This is a good project if the probability of expropriation is larger than.33. b. This is a good project if the probability of expropriation is smaller than.33. c. This is a good project if the probability of expropriation is smaller than .d. This is a good project if the probability of expropriation is smaller than .66. Suppose a man is sitting on a chair and exerting 100 N of force downward, while a spring beneath the chair exerts 150 N of force upward. If you assign a negative value to the downward force, what is the net force of this system? management observed that the initial phase of a multiphase implementation was behind schedule and over budget. prior to commencing with the next phase, an is auditor's primary suggestion for a postimplementation focus should be to: what organization funded the 9/11 attacks Properties of protein is least likely to be affected by change in ph. You have put together a business plan to start up your own company supply devices for controling household devices through "The Internet of Things". Your technology company has been trading for 6 months and is gaining some traction in the market. Your sales are growing steadily and your investors need to check if your cash flow is sufficient for the next four months. They have asked you to prepare a cash flow projection to assess the funding requirements of your firm. You currently have overdraft facilities of 100,000 with your bank. Your account is 42,000 overdrawn. You have a start-up loan of 150,000, which has monthly repayments of 4,250. Your rent is 2,000 per month and your utility bills amount to 250 p/m. Your expected sales for the period are Sales Projections Feb Mar April 29000 43000 62000 74000 May Your projected purchases for the period are: Purchases for Resale Feb 26000 34000 Mar April 40000 May 48000 Advertising and website costs are normally 500 per month with a tradeshow in the UK costing 7,000 extra in March Based on the sales projections your freight costs are expected to vary monthly as follows: Feb Mar April May Freight 1,500 6 2,250 2,560 2,850 (0) Prepare a cash flow projection for the period Feb-May (20 marks) (ii) Examine your cash flow. Will you have enough funds to meet your commitments each month? (2 marks) (i) If you need an injection of funds to clear your overdraft and still have 100,000 cash available, how much would you need? (3 marks) (iv) Explain, briefly, the relevance and importance of a cash flow projection? (8 marks) which two statements are true for both compounds and mixturesA. Their particles are held together by chemical bondsB. Their particles all have the same chemical formulaC. They are made up of more than one type of atomD. They can be separated into two or more elements jackie is a 3-month-old infant participating in an experiment. she's lying in her crib with one end of a ribbon tied to her foot and the other end tied to a mobile dangling over her crib. she quickly learns that she controls the movement of the mobile with her kicking. one week later, the researchers return, tie the ribbon to her foot and hang the mobile above her crib. immediately, jackie starts vigorously kicking her leg. what does this experiment demonstrate? a. three-month-olds can remember actions for at least a week. b. three-month-olds can relearn the kicking strategy very quickly at the second test. c. mobiles are very interesting to 3-month-olds. d. kicking behavior is very easy to learn. Fast Delivery is the world's largest express transportation company. In addition to the world's largest fleet of all-cargo aircraft, the company has more than 661 aircraft and 66,000 vehicles and trailers that pick up and deliver packages. Assume that Fast Delivery sold a delivery truck that had been used in the business for three years. The records of the company reflected the following: Delivery truck cost Accumulated depreciation $ 49,000 34,200 Required: 1. Prepare the journal entry for the disposal of the truck, assuming that the truck sold for: (If no entry is required for a transaction/event, select "No journal entry required" in the first account field.) a. $14,800 cash b. $15,800 cash c. $14,100 cash Journal entry worksheet 1 2 3 Record the disposal of the truck, assuming the truck was sold for $14,800 cash. Note: Enter debits before credits. Transaction General Journal Debit Credit a. Record entry Clear entry View general journal Journal entry worksheet < 1 2 3 Record the disposal of the truck, assuming that the truck was sold for $15,800 cash. Note: Enter debits before credits. Transaction General Journal Debit Credit b. Record entry Clear entry View general journal Journal entry worksheet < 1 2 3 Record the disposal of the truck, assuming the truck was sold for $14,100 cash. Note: Enter debits before credits. Transaction General Journal Debit Credit C. Record entry Clear entry View general journal Order (-2.5,4,23,-1,5,-3,0.66) from least to greatest Find exact Valuelog4l=x You have two routers that should be configured for gateway redundancy. The following commands are entered for each router:A(config)#int fa 0/2A(config-if)#ip address 172.16.1.2A(config-if)#standby 2 priority 150A(config-if)#standby 2 ip 172.16.0.1B(config)#int fa 0/2B(config-if)#ip address 172.16.1.3B(config-if)#standby 2 priority 150Which of the following is true? (Select two.)