A 500-N box is at rest on the floor. Dennis Elbo makes several
attempts to move the box, pushing against the box with varying
amounts of horizontal force. Yet the box never does move. In this
situation, the amount of static friction force experienced by the box
Select all that apply.
-
0 is 500 N
O is equal to the force with which Dennis exerts on the
box
has an upper limit and Dennis O has not yet exceeded the upper limit
Ois always the coefficient of friction multiplied by the normal force value

Answers

Answer 1

Answer:

Select the second and the third options you listed.

Explanation:

Select the answer options:

"is equal to the force with which Dennis exerts on the  box."

and

"has an upper limit and Dennis has not yet exceeded the upper limit."

In fact, this upper limit of the static friction force is the product of the coefficient of static friction (\(\mu\)) times the weight of the box.


Related Questions

What is the largest known star?

Answers

Answer:

UY Scuti is slightly larger than VY Canis Majoris

Explanation:

These stars are millions of miles away and cannot be seen by the naked eye.

Beetlejuice is another large star that can be seen by the eye.

The acceleration of positive performing SHM is 12cm/sec at distance of 3cm from the mean position its time period is?​

Answers

The angular acceleration of the object can be obtained from the solution as  432 cm^2/sec from the mean position.

What is the simple harmonic motion?

We know that the simple harmonic motion is the kind of motion that the acceleration of the motion is such that the motion is directed towards the center of the motion. The implication of this is that the motion of the object would always tend towards the center of the motion of the object.

Then we would have to apply the formula that involves the angular velocity and the distance that is covered and thus we have to write the formula as follows;

α =  ω^2y

α = acceleration

ω = angular velocity

y = distance covered

Then we have;

α =  (12)^2 * 3

= 432 cm^2/sec

Thus the acceleration directed to the center is  432 cm^2/sec.

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what is the electric force between 2 forces .0042c and -0.0050c and are .0030m apart

Answers

To calculate the electric force between two charges, we can use Coulomb's law:

F = k * |q1 * q2| / r^2

where F is the electric force, k is the electrostatic constant (k ≈ 8.99 × 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

In this case, q1 = 0.0042 C, q2 = -0.0050 C, and r = 0.0030 m.

Substituting these values into the equation:

F = (8.99 × 10^9 N m^2/C^2) * |0.0042 C * (-0.0050 C)| / (0.0030 m)^2

F = (8.99 × 10^9 N m^2/C^2) * 0.000021 C^2 / 0.000009 m^2

F ≈ 1977.78 N

Therefore, the electric force between the two charges is approximately 1977.78 Newtons.

If the parallel circuit had 23 amps with the same resistance, what will be the voltage

Answers

If the parallel circuit had 23 amps with the same resistance, the voltage will be V = 23 amps * R.

To determine the voltage in a parallel circuit with a given current and resistance, we can use Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R).

In this case, if the parallel circuit has a current of 23 amps and the same resistance as before, we can use the same resistance value as before to calculate the voltage.

Ohm's Law equation: V = I * R

Given:

Current, I = 23 amps

Resistance, R (same as before)

Substituting the values into the equation, we have:

V = 23 amps * R

Therefore, The specific value of resistance (R) is not provided in the question, so the voltage (V) cannot be determined without knowing the resistance value. If the resistance value is provided, you can substitute it into the equation to calculate the voltage.

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8. How do you think the biodiversity of a large forest compares to a small forest?

Answers

Answer:

A large forest has more toes than the smaller forest

Explanation:

If the dog barks twice, but the cat doesn't, then it states that I caw can ring 5 times.

You have a 6.00 V power supply, and
a 30.0 ohm and a 75.0 ohm resistor.
Find the current flowing out of the
battery if the resistors are connected
in parallel.

You have a 6.00 V power supply, anda 30.0 ohm and a 75.0 ohm resistor.Find the current flowing out of

Answers

Answer: 0.28 A

Explanation:

Answer:

.28

Explanation:

Acellus

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPP

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

right answer is death valley

Explanation:

because it is close to surface gravitational field

mexico

cus its the farthest

A person standing on the roof of a building drops a 0.125 Kg ball on the ground. A

child on eight floor saw the ball passing with a speed of 33.1 m/s. The first floor of the building

is 12.0 m high and each successive floor is 8.00 m high. Determine the total numbers of floors

in the building. How fast was the ball falling just before it hit the ground? What was its kinetic

energy just before it hit the ground?

Answers

Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?

Answers

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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How do your results from ray tracing compare to your results from using the thin-lens equation?
What is the focal length of a convex lens that produces an image 10 cm away with a magnification of -0.5? Show all calculations in your answer.
Hint: Use the definition of magnification and the thin-lens equation.

Answers

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image (image distance can be negative or positive depending on the nature of the image).

According to the lens equation

\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\) where;

f is the focal length  of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm\)

Hence the focal length of the convex lens is 20cm

Pete is driving down 7th street. He drives 0.150km in 18 seconds. Assuming he does not speed up or slow down, what is his speed in meters per second?​

Answers

Answer:

150m/s

Explanation:

0.150km to m is multiplying by 1000.

The mass of an object on the Earth is 100. kg.
What is the weight of the object on the Earth?
What is the mass of the object on the moon?
Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is the weight of the object on the moon?
PLEASE HELPPPPPPPPPPPP

Answers

Answer:

163n

Explanation:

Weight is force due to gravity, weight of object is 980 N

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

Weight = mass.gravity

Weight = 100*9.8

Weight = 980 N

Weight is force due to gravity, weight of object is 980 N

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How is the pressure of a gas related to its concentration of particles?

Answers

Increasing the pressure of gas is like exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume.
Hope this helps!

Answer:

Explanation:

Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.

Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.

Please help me!!

1 a) Compare the speed that light waves travel in air to the speed that sound waves travel in the air. (Show results in meters/second)


1 b) How many times faster do light waves travel in the air in comparison to sound waves in air? (show working out)


2) Compare the speed of light in water to the speed of sound in water. (Show results in meters/second)

Please help me!!1 a) Compare the speed that light waves travel in air to the speed that sound waves travel

Answers

Answer:A sound wave is a pressure disturbance that travels through a medium by means of particle-to-particle interaction.As one particle becomes disturbed,it exerts a force on the next adjacent particle, disturbing that particle from rest and transporting the energy through the medium.Like any wave,the speed of a sound wave refers to how fast the disturbance is passed from particle to particle.While frequency refers to the number of vibrations that an individual particle makes per unit of time, speed refers to the distance that the disturbance travels per unit of time.

Since the speed of a wave is defined as the distance that a point on a wave (such as a compression or a rarefaction)travels per unit of time,it is often expressed in units of meters/second (abbreviated m/s). In equation form, this is speed = distance/time

The faster a sound wave travels,the more distance it will cover in the same period of time.If a sound wave were observed to travel a distance of 700 meters in 2 seconds,then the speed of the wave would be 350 m/s. A slower wave would cover less distance - perhaps 660 meters - in the same time period of 2 seconds and thus have a speed of 330 m/s.Faster waves cover more distance in the same period of time.

The speed of any wave depends upon the properties of the medium through which the wave is traveling.Typically there are two essential types of properties that affect wave speed - inertial properties and elastic properties.Elastic properties are those properties related to the tendency of a material to maintain its shape and not deform whenever a force or stress is applied to it.A material such as steel will experience a very small deformation of shape and dimension when a stress is applied to it.Steel is a rigid material with a high elasticity.On the other hand,a material such as a rubber band is highly flexible;when a force is applied to stretch the rubber band,it deforms or changes its shape readily.A small stress on the rubber band causes a large deformation.Steel is considered to be a stiff or rigid material,whereas a rubber band is considered a flexible material. At the particle level,a stiff or rigid material is characterized by atoms and/or molecules with strong attractions for each other.The phase of matter has a tremendous impact upon the elastic properties of the medium.For this reason,longitudinal sound waves travel faster in solids than they do in liquids than they do in gases.Even though the inertial factor may favor gases,the elastic factor has a greater influence on the speed (v) of a wave,thus yielding this general pattern:solids > liquids > gases The density of a medium is an example of an inertial property.The greater the inertia (i.e.mass density) of individual particles of the medium,the less responsive they will be to the interactions between neighboring particles and the slower that the wave will be. However,within a single phase of matter,the inertial property of density tends to be the property that has a greatest impact upon the speed of sound.Like any liquid,water has a tendency to evaporate.As it does,particles of gaseous water become mixed in the air.The temperature will affect the strength of the particle interactions an elastic property.At normal atmospheric pressure,the temperature dependence of the speed of a sound wave through dry air is approximated by the following equation:

v = 331 m/s + (0.6 m/s/C)•T

where T is the temperature of the air in degrees Celsius.Using this equation to determine the speed of a sound wave in air at a temperature of 20 degrees Celsius yields the following solution.

v = 343 m/s

(The equation itself does not have any theoretical basis;it is simply the result of inspecting temperature-speed data for this temperature range.Other equations do exist that are based upon theoretical reasoning and provide accurate data for all temperatures.The speed of light as it travels through air and space is much faster than that of sound;it travels at 300 million meters per second or 273,400 miles per hour.Visible light can also travel through other things besides through air and through space.The speed of light in water is approximately 2.26×108 2.26 × 10 8 meters per second.

A car travels 100 m while decelerating to 8 m/s in 5 s.
a) What was its initial speed?

Answers

Answer:

Vi = 32 [m/s]

Explanation:

In order to solve this problem we must use the following the two following kinematics equations.

\(v_{f} =v_{i} - (a*t)\\\)

The negative sign of the second term of the equation means that the velocity decreases, as indicated in the problem.

where:

Vf = final velocity = 8[m/s]

Vi = initial velocity [m/s]

a = acceleration = [m/s^2]

t = time = 5 [s]

Now replacing:

8 = Vi - 5*a

Vi = (8 + 5*a)

As we can see we have two unknowns the initial velocity and the acceleration, so we must use a second kinematics equation.

\(v_{f}^{2} = v_{i}^{2} - (2*a*d)\)

where:

d = distance = 100[m]

(8^2) = (8 + 5*a)^2 - (2*a*100)

64 = (64 + 80*a + 25*a^2) - 200*a

0 = 80*a - 200*a + 25*a^2

0 = - 120*a + 25*a^2

0 = 25*a(a - 4.8)

therefore:

a = 0 or a = 4.8 [m/s^2]

We choose the value of 4.8 as the acceleration value, since the zero value would not apply.

Returning to the first equation:

8 = Vi - (4.8*5)

Vi = 32 [m/s]

RADIOWAVES of constant amplitude can be generated with
1) FET
2) filter
3)rectifier
4)oscillator​

Answers

Answer:

4) oscillator

Explanation:

4) oscillator

A toy car is given an initial velocity of 0.0 m/s and experiences a constant acceleration of 2.0 m/s2. What is the final velocity after 12.0 s?​

Answers

Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

An electric field is associated with every:____.
a. position-dependent magnetic field.
b. time-dependent magnetic field.
c. conductor moving in a magnetic field.
d. object moving in a magnetic field.
e. magnetic field.

Answers

Answer:

b. time-dependent magnetic field.

An electric field is associated with every time-dependent magnetic field.

What is electric field?

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field. The magnetic impact on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field.

An electric field is produced by a time-varying magnetic field. The first law of Faraday states that an electromotive force is always produced when a conductor is exposed to a changing magnetic field. Induced current is the term for the current that results when the conductor circuit is closed.

An electric field is associated with every time-dependent magnetic field.

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1.
Ramon decided to open his own software
business. He borrowed money from a bank
to buy computers and office equipment,
and he hired one assistant. What is a
DISADVANTAGE of Ramon's
type of
business organization?
A. ease of organization
B. flexibility
C. limited liability
D. unlimited liability

Answers

Ramon is starting the software business by borrowing money as well as he hired a personal assistant also. So he have unlimited liabilities on these. He have to find the sources to return the borrowed money and have to give the salary for the assistant.

What are liabilities in business ?

Liabilities are the legitimate debts that a business owes to other creditors. Accounts payable, notes payable, and bank debt are just a few examples. Liabilities are a necessary component of operation and expansion for every business. A company's foundation is secure when liabilities and equity are properly balanced.

Here, Ramon borrowed money to buy the computers and other equipments. He must refund the money within the limited duration. It would be more better if he could by the things on his own at the time when he is able.

He hire a personal assistant in the starting. So he has to pay the salary and facilities to the person. But he could manage the things in starting himself  so could have less liabilities. Therefore, here, Ramon have unlimited liabilities.

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The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.​

Answers

The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).

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The 243000-lb space-shuttle orbiter touches down at about 236 mi/hr. The drag chute is deployed at 189 mi/hr, the wheel brakes are applied at 101 mi/hr until wheelstop, and the drag chute is jettisoned at 35 mi/hr. If the drag chute results in a deceleration of -0.000200v2 (in feet per second squared when the speed v is in feet per second) and the wheel brakes cause a constant deceleration of 3.5 ft/sec2, determine the distance s traveled from 189 mi/hr to wheelstop.

Answers

Answer:

5156.37 ft

Explanation:

Given data:

weight ( W ) = 243,000 Ib

Motion of shuttle ; from 189 mi/hr to 101 mi/hr

dv/dt = -0.0002 V^2

I/v * dv/dt = -0.0002 ds

Convert mi/hr to ft/s ( 1 mi/hr = 1.467 ft/s)

189 mi/hr = 277.263 ft/s

101 mi/hr = 148.167 ft/s

After Integrating

In ( 148.167 / 277.263 ) = -0.0002 ( S1 - S2 )

S1 - S2 = -0.627 / -0.0002

S1 - S2 = 3135 ft/s

Now from 101 mi/hr to 35 mi/hr

dv/dt = ( - 0.0002 V^2 + 3.5 )

ds =  V*dv / ( -0.0002 v^2 - 3.5 )

given :  35 mi/hr = 51.345 ft/s

             101 mi/hr = 148.167 ft/s

Integrate

S3 - S2 = - In( 0.0002 v^2 + 3.5 ) / 0.0002 * 2 ]

            = 1644.75 ft/s

S4 - S3 = 376.62 ft/s

attached below is the remaining part of the solution

Total distance travelled = 3135 + 1644.75 + 376.62 = 5156.37 ft

The 243000-lb space-shuttle orbiter touches down at about 236 mi/hr. The drag chute is deployed at 189

1. What is the speed of light in a vacuum? (1 point)
Responses

a. c=3⋅108 m/s
b. c=2⋅108 m/s
c. v=2⋅108 m/s
d. v=3⋅108 m/s

2. Why is a polarized filter helpful to a photographer?(1 point)
Responses
a.It transmits all light.
b.It scatters all light.
c.It blocks all light.
d.It blocks some light but not all

3. When a sound wave propagates through air, how do the air molecules move?(1 point)
Responses

a.The air molecules move randomly.
b.The air molecules vibrate forward and back along the wave’s direction of travel.
c.The energy is transferred without physical motion.
d.The air molecules vibrate side to side, perpendicular to the wave’s direction of travel.

Answers

1. The speed of light in vacuum is 3x108 m/s

2. Polarized filter is helpful to a photographer because, it blocks some light but not all.

3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.

What is meant by polarization of light ?

Polarization of light is defined as the phenomenon by which the vibrations of light gets restricted to a particular direction that is perpendicular to the direction of wave motion.

Here,

1. The speed of light in the vacuum, c = 3x108 m/s

2. Photographers use the polarized filters for photography to improve the landscape photographs. This is because, using polarized filters in the camera can reduce unwanted reflections and glares from the external light. This could help to improve the contrast in landscape photography.

3. When a sound wave is propagated through air, the air molecules also move along with it. This is because, when the wave passes through the air, it pushes the air molecule, leading to the bouncing of air molecules with the surrounding molecules. Thus exerts a high pressure in air and when the the peak of the wave is passed, the pressure gets lower. This causes the movement of air molecules in a direction perpendicular to the direction of propagation of the wave.

Hence,

1. The speed of light in vacuum is 3x108 m/s

2. Polarized filter is helpful to a photographer because, it blocks some light but not all.

3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.

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Assuming barber wants to setup a saloon in a measuring length of 3m by 3m. He has a simple wooden chairs,3 large mirror and one bulb. Using the knowledge of shadows and reflection, advice the barber on how to arrange a good saloon using the only item he has. Without adding more source of light, how can he enhance the lighting system in his saloon?​

Answers

The best way to arrange the salon to best use what he has is:

Place the bulb in the middle of the wallDirectly face the chair and mirror in front of the bulb for proper lighting and reflectionPlace the chairs side by side of each otherEach mirror should be facing each chai

What is Reflection?

This refers to the change in direction of a wavefront between two different media so that the wavefront returns to its originating medium.

Hence, we can see that from our knowledge of shadows and reflection, we can note that mirrors reflect and light helps to bring detail in a dark area and the chairs should be facing the mirrors directly so the customer can see his hair and how it is being cut by the barber.

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Assuming barber wants to setup a saloon in a measuring length of 3m by 3m. He has a simple wooden chairs,3

A wooden block floats in water, and a solid steel object is attached to the bottom of the block by a string as in the figure below. If the block remains floating, which of the following statements is valid? (Choose all correct statements.)The tension in the string is less than the weight of the steel object.The buoyant force on the block is equal to the weight of the volume of water it displaces.The buoyant force on the steel object is equal to its weight.The buoyant force on the block is equal to its weight.The tension in the string is equal to the weight of the steel object.

Answers

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

In the figure, (FB)block is buoyant force on block, (FB)steel is buoyant force on steel object, Wsteel is weight of the steel object, Wblock is weight of the steel block, and 7 is tension in the string. is

Weight of an object acts always in downwards.

Buoyant force on an object which is placed in a fluid is always upward direction. When the buoyant force is equal to the weight of the object, then the object floats in the fluid.

From the Archimedes principle, the buoyant force exerted by a fluid on an object which is placed in it is equal to the weight of the fluid displaced by the object.

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

When the block is floating, the buoyance force supported by the water is equal to the total weight of the block and steel object. Thus, the statement the buoyant force on the block is equal to its weight is not correct.

As the steel object is at rest in the water, then the net force acting on it is zero.

(F ret )steel  =0

T+(F B ) steel -W steel =0 W steel =T+(F B ) steel

Therefore,

T<W steel

Thus, the statement tension in the string is less than weight of the steel object is correct.

If the weight of the steel object is equal to the buoyant force, then the tension in the string should be zero. But the steel object is hanging with the string, so tension never is zero.

Thus, the statement 'the buoyant force on the steel object is equal to its weight' is not correct.

If the tension in the string is equal to the weight of the steel object, then the buoyant force on the steel object should be zero. But any object in a fluid should experiences the buoyant force.

Thus, the statement 'the tension in the string is equal to the weight of the steel object' is not correct.

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I have to make a presentation about ultrasound diagnostic (it's for physics). Does someone know more about that topic? I need to explain how does ultrasound show insides of human body.
*sorry if my english isn't that good, im from Cro​

Answers

Answer: Okay so I don't know much but from what I do know

Ultrasound emits sound waves into the body and what bounces back is what they can see the grey shape is what is closest. It's all micro sound waves and cannot hurt an unborn baby.

Explanation:

Not sure if this is correct but it is what I remember being told.

Hope this helps!

Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 10^5 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.

Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 10^5 m/s in the

Answers

Therefore, the magnetic force on an electron is 1.175 x 10⁻¹⁴N in the positive y-direction.

The force experienced by a moving charge in a magnetic field is given by the Lorentz force law. Since the charge on a proton is positive and that on an electron is negative, the direction of the magnetic force experienced by each is different.In this question, we need to find the magnitude and direction of the magnetic force on a proton and an electron as they travel from the Sun to the Earth.

Let's first calculate the magnetic force on a proton:

F = qvBsinθ

where q = charge of the particle

v = velocity of the particle

B = magnetic field strength

θ = angle between the velocity of the particle and the magnetic field = 90° (since the proton is moving perpendicular to the magnetic field)

Therefore,

F = qvBsinθ

= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°

= 1.175 x 10⁻¹⁴ N

Direction of magnetic force on a proton:The direction of the magnetic force on a proton can be found using the right-hand rule. According to this rule, if we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the negative y-direction.

Therefore, the magnetic force on a proton is 1.175 x 10^-14 N in the negative y-direction.

- Now, let's calculate the magnetic force on an electron:

Again using the Lorentz force law,

F = qvBsinθ

= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°

= -1.175 x 10⁻¹⁴ N (the negative sign indicates that the direction of the magnetic force is opposite to that of the proton)

Direction of magnetic force on an electron:Again using the right-hand rule, we can find the direction of the magnetic force on an electron. If we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the positive y-direction.

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define Brownian motion​

Answers

Answer:

Brownian motion, or pedesis, is the random motion of particles suspended in a medium.

Explanation:

of motion typically consists of random fluctuations in a particle's position inside a fluid sub-domain,

Answer:

The erratic random movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium is called Brownian motion. Hope it helps you.

Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.

Answers

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

How to solve for the  total distance

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-28 kg, and that of the other is 1.86 10-27 kg. If the lighter fragment has a speed of 0.844c after the breakup, what is the speed of the heavier fragment

Answers

Answer: Speed = \(3.10^{-31}\) m/s

Explanation: Like in classical physics, when external net force is zero, relativistic momentum is conserved, i.e.:

\(p_{f} = p_{i}\)

Relativistic momentum is calculated as:

p = \(\frac{mu}{\sqrt{1-\frac{u^{2}}{c^{2}} } }\)

where:

m is rest mass

u is velocity relative to an observer

c is light speed, which is constant (c=\(3.10^{8}\)m/s)

Initial momentum is zero, then:

\(p_{f}\) = 0

\(p_{1}-p_{2}\) = 0

\(p_{1} = p_{2}\)

To find speed of the heavier fragment:

\(\frac{mu_{1}}{\sqrt{1-\frac{u^{2}_{1}}{c^{2}} } }=\frac{mu_{2}}{\sqrt{1-\frac{u^{2}_{2}}{c^{2}} } }\)

\(\frac{1.86.10^{-27}u_{1}}{\sqrt{1-\frac{u^{2}_{1}}{(3.10^{8})^{2}} } }=\frac{3.10^{-28}.0.844.3.10^{8}}{\sqrt{1-\frac{(0.844c)^{2}}{c^{2}} } }\)

\(\frac{1.86.10^{-27}u_{1}}{\sqrt{1-\frac{u^{2}_{1}}{(3.10^{8})^{2}} } }=1.42.10^{-19}\)

\(1.86.10^{-27}u_{1} = 1.42.10^{-19}.{\sqrt{1-\frac{u^{2}_{1}}{(3.10^{8})^{2}} } }\)

\((1.86.10^{-27}u_{1})^{2} = (1.42.10^{-19}.{\sqrt{1-\frac{u^{2}_{1}}{(3.10^{8})^{2}} } })^{2}\)

\(3.46.10^{-54}.u_{1}^{2} = 2.02.10^{-38}.(1-\frac{u_{1}^{2}}{9.10^{16}} )\)

\(3.46.10^{-54}.u_{1}^{2} = 2.02.10^{-38} -[2.02.10^{-38}(\frac{u_{1}^{2}}{9.10^{16}} )]\)

\(3.46.10^{-54}.u_{1}^{2} = 2.02.10^{-38} -2.24.10^{-23}.u^{2}_{1}\)

\(3.46.10^{-54}.u_{1}^{2}+2.24.10^{-23}.u^{2}_{1} = 2.02.10^{-38}\)

\(2.24.10^{-23}.u^{2}_{1} = 2.02.10^{-38}\)

\(u^{2}_{1} = \frac{2.02.10^{-38}}{2.24.10^{-23}}\)

\(u_{1} = \sqrt{9.02.10^{-62}}\)

\(u_{1} = 3.10^{-31}\)

The speed of the heavier fragment is \(u_{1} = 3.10^{-31}\)m/s.

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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