A 5.00 l container is filled with 0.300 atm acetylene and 0.800 atm hydrogen, which react according to:____.

Answer: A. The greater the pressure, the more of gas that will dissolve.

Explanation: Increasing pressure increases the solubility of gases. It has little effect on the solubility of liquids and solids.

Answer:

option 4 - it can have different compositions, and it has a set of characteristics that change.

Mixture is defined to have different compositions, and it has a set of characteristics that does change.There are 2 types of mixtures:1) homogenous mixtures 2)heterogenous mixtures

Heterogenous mixtures is defined as a type of mixture where in the composition is not uniform throughout the mixture.It consists as two or more phases. The phases are chemically distinct from each other.

As there are two or more phases present in heterogenous mixtures they can be separated by solvent extraction where in one phase is miscible with the solvent and the other phase is immiscible.

Components of a heterogenous mixtures are distinctly visible . There are two types of heterogenous mixtures, the colloids and the suspensions.These two vary with each other with respect to particle size.

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Answer:

molecular biology university of California

Explanation:

First find the mass of 1 mole of water (Molecular mass)

\( H_{2} O = 2H + O \)

\(

= 2(1) + 32 \)

\(

= 34 \: grams

\)

Hence 1 mole of water is 34 g

Compare

1 mole = 34 g

1.33 mole = x g

\( \frac{x}{34} = \frac{1.33}{1} \)

\(

x = 1.33 \times 34 \)

\(

\color{blue}{\boxed{x = 45.2}} \: \: \: \: to \: 3 \: s.f.

\)

Therefore 1.33 moles of water is 45.2 grams

The mass of the substances can be given by the molar mass and the moles of the substances. The mass of 1.33 mole of water is expressed in grams as, 23.94 grams.

The mass has been defined as the product of the moles of the substance and the molar mass in grams per mole. The mass is given in grams and has a formula,

Moles = mass ÷ molar mass

Mass = molar mass × moles

Given,

Moles = 1.33 moles

Molar mass of water (H₂O) is calculated as = 2 (1) + 16= 18 grams per mole

Using the formula of mole, mass is calculated as:

Mass = molar mass × moles

mass = 1.33 × 18

= 23.94 grams

The mass of the substance can be calculated if the value of the molar mass and the moles of the substance has been known. The molar mass of the substance can be calculated by adding the mass of the individual masses of the element in a molecule.

Therefore, 1.33 mol of water contains 23.94 grams.

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Answer:

V = 85.2

Explanation:

STP = 273K and 1 atm

Considering what we know about STP, we get the moles, temperature, and pressure. Using the ideal gas law we can find the volume (PV = nRT). Plug in our variables: (1 * V = 3.80 * R * 273). Since we are dealing with atm and not kPA or mmHg, we use the constant for atm (0.0821) which we use for R. (So.. now our equation is 1 * V = 3.80 * 0.0821 * 273). We now multiply the right side to get 85.17054. So... V = 85.2 considering sigificant figures (this is the part where I am the least sure of, since I havent done sig figs in a while)

A) In precipitation reaction when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.

B) After equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.

To answer the given questions about the precipitation reaction of calcium oxalate, let's break it down into two parts:

A) The concentration of calcium ions and oxalate ions in the saturated solution can be determined when an excess amount of calcium oxalate is added to 100.0 mL of pure water.

Since excess calcium oxalate is added, it means that the solution will contain more calcium oxalate than what can dissolve. At saturation, the solution is in equilibrium with the solid calcium oxalate.

Let's assume the concentration of calcium ions and oxalate ions in the saturated solution is represented by "x" (in mol/L).

The equilibrium expression for the reaction is:

Ks = [Ca²⁺][C₂O₄²⁻]

Given that the equilibrium constant Ks = 3.7 × 10⁻⁴, we can set up the equation:

3.7 × 10⁻⁴ = x * x

Solving for "x," we find:

x = √(3.7 × 10⁻⁴) ≈ 0.0192 mol/L

Therefore, when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.

B) If 1.00 mg of calcium chloride (CaCl2) were added to the mixture, what would be the expected concentrations of calcium ions and oxalate ions once equilibrium is reestablished?

Since calcium chloride (CaCl₂) dissociates completely into calcium ions (Ca²⁺) and chloride ions (Cl⁻) in solution, the addition of 1.00 mg of CaCl₂ will result in the addition of 1.00 mg of calcium ions.

First, we need to convert the mass of calcium ions from mg to mol:

1.00 mg = 0.001 g

0.001 g / (molar mass of Ca²⁺) = 0.001 g / 40.08 g/mol ≈ 2.498 × 10⁻⁵ mol

Since the solution volume is assumed to be unchanged, the concentrations of calcium ions and oxalate ions will change but not the molar amounts.

The concentration of calcium ions is the molar amount (2.498 × 10^(-5) mol) divided by the total solution volume (100.0 mL or 0.100 L):

Concentration of calcium ions = (2.498 × 10⁻⁵ mol) / 0.100 L ≈ 2.498 × 10⁻⁴ mol/L

The concentration of oxalate ions remains the same as in part A since the addition of calcium chloride does not affect the concentration of oxalate ions.

Therefore, after equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.

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The concentration of the HBr would be 0.09 M

First, let us look at the equation of the reaction:

\(HBr + NaOH --- > NaBr + H_2O\)

The mole ratio of HBr to NaOH is 1:1.

Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles

Equivalent mole of HBr - 0.0045 moles

Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M

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The mole fraction of hydrochloric acid (HCl) in the solution is approximately 0.460.

Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, the molality of HCl is given as 8.56 mol/kg. Mole fraction (X) is defined as the ratio of the moles of a component to the total moles of all components in the solution.

To calculate the mole fraction of HCl, we need to know the total number of moles in the solution. However, the information provided only gives the molality of HCl, which provides the moles of HCl per kilogram of solvent, but not the total moles of the solution. Without the total moles of the solution, it is not possible to directly calculate the mole fraction of HCl. Therefore, based on the given information, it is not possible to determine the mole fraction of HCl in the solution accurately.

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The given compound is better formed by the reaction of the ketonic compound with alkyl lithium. The organolithium reagent used here is (CH3)₂CHCH₂Li .

Organometallic compounds are compounds with one organic carbon -metal bond. These class of compounds are significantly important reagents in synthetic chemistry.

Organolithium compounds has the general formula R-Li. R can be any organic chain. They are used in the alkylation of other organic compounds.

The given initial compound is the benzyl ketone. Where the organolithium group is attaching through 1, 4 addition. The alkyl group is attached with the 4th carbon and the hydrogen from last step hydrolysis is attached to the first carbon of double bond.

Therefore, option a is correct.

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Your complete question is attached below:

Answer:

C

Explanation:

A neutral atom always has the same number of electrons and the total number of protons.

There are 0,419 moles of glucose in a sample that weights 75.5g.

To calculate the amount in moles of glucose in 75.5g, we first need the molar mass of this compound. To calculate that I'll be using the following atomic mass values:

C: 12

H: 1

O: 16

To calculate the molar mass, we multiply the number of atoms by the respective atomic mass:

(6 * 12) + (12 * 1) + (6 * 16) = 180 g/mol

Since the molar mass is 180 g/mol, we know that each mol has 180 g of glucose:

1 mol glucose ---------- 180g glucose

x --------------------------- 75.5g glucose

Solving for x, we have x = 0.419 moles of glucose

Photosynthesis is that plant process is affected most during this darkness because photosynthesis only occurs when there is sunlight.

Photosynthesis is a process in which water and carbondioxide combine in the presence of sunlight and produce glucose and oxygen. We know that Photosynthesis occurs only at daytime.

So we can conclude that Photosynthesis is affected during this darkness because photosynthesis only occurs when there is sunlight.

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Answer:

While alpha and beta rays have energy and mass, gamma rays are pure energy.

Answer:

2Fe + 3Cl2 --> 2 FeCl3

Explanation:

Fe + Cl2 -->  FeCl3

iron is balanced but chlorine isn't so we find what number can make each one equal

Fe +3Cl2 --> 2FeCl3

now we need to balance iron

2Fe + 3Cl2 --> 2 FeCl3

Among the options provided, \(AlCl_3\), is a Lewis acid.

The Lewis acid is a species that can accept a pair of electrons, forming a new covalent bond. The Lewis base is a species that can donate a pair of electrons to form a new covalent bond.

Among the options provided, \(CHBr_3\), \(NH_3\), and \(CBr_4\) are Lewis bases because they have electron-rich atoms that can donate a pair of electrons.

On the other hand, \(AlCl_3\) is a Lewis acid because it has an incomplete octet of electrons in its valence shell and can accept a pair of electrons to form a new covalent bond. Specifically, the aluminum atom has only six electrons in its valence shell, making it electron-deficient and prone to accepting a pair of electrons from a Lewis base to complete its octet.

Therefore, the correct answer is \(AlCl_3\), which is a Lewis acid. \(CHBr_3\), \(NH_3\), and \(CBr_4\) are Lewis bases because they have atoms with lone pairs of electrons that can donate to form new covalent bonds.

In summary, a Lewis acid is a species that can accept a pair of electrons to form a new covalent bond, while a Lewis base is a species that can donate a pair of electrons to form a new covalent bond.

Thus, Among the options provided, only \(AlCl_3\) is a Lewis acid because it has an incomplete octet of electrons in its valence shell and can accept a pair of electrons.

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Answer:

In a hydraulic lift system, the output force is greater than the input force because the pressure acting on the output piston is greater than the pressure acting on the input piston.

Explanation:

In order to calculate the average bond energy of the O−H bond, we need to consider the energy changes involved in breaking the bonds in H2 and O2 and the energy change in forming the bonds in H2O.

The reaction involves breaking two H−H bonds and one O=O bond in the reactants, and forming four O−H bonds in the product. The energy change (ΔH) for the reaction is -571 kJ. Given that the bond energy of H−H is 435 kJ and the bond energy of O=O is 498 kJ, we can calculate the total energy change in breaking the bonds in the reactants:

Energy change = 2 × (bond energy of H−H) + (bond energy of O=O)

                 = 2 × 435 kJ + 498 kJ

                 = 1368 kJ

Since the reaction is exothermic (ΔH < 0), the energy released in forming the bonds in the products will be equal to the magnitude of the energy change: Energy change in forming bonds = 571 kJ Now, we can calculate the average bond energy of the O−H bond:

Average bond energy of O−H = (Energy change in forming bonds) / (Number of O−H bonds formed)

                                         = 571 kJ / 4

                                          ≈ 142.75 kJ

Therefore, the average bond energy of the O−H bond is approximately 142.75 kJ.

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A n expression for ΔSmix: ΔSmix (x = 4/10, y = 2/10) = Nk [(4/10) ln (4/10) + (2/10) ln (2/10) + ln (10 / 6)]ΔSmix (x = 2/10, y = 3/10) = Nk [(2/10) ln (2/10) + (3/10) ln (3/10) + ln (10 / 5)]ΔSmix (x = 4/10, y = 3/10) = Nk [(4/10) ln (4/10) + (3/10) ln (3/10) + ln (10 / 7)]

When x = 1/3 and y = 2/3, we getΔSmix = Nk [(1/3) ln (1/3) + (2/3) ln (2/3) + ln (3)]

1. We have two gases of volume V1 and V2 before mixing. The final mixture has a volume V and the volume of the two gases together equals the volume of the mixture. Therefore,V = V1 + V2 .....(1)

Since both gases have the same temperature, they obey the ideal gas law. For an ideal gas, PV = nRT where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. Since the two gases have the same temperature, we can write

PV1 = n1RT and PV2 = n2RT where n1 = N1/

N is the number of moles of gas 1 and n2 = N2/

N is the number of moles of gas 2. Therefore, n1 + n2 = 1 and N1 + N2 = N.

Substituting for n1 and n2, we can write V1 = (N1 / N) RT / P and V2 = (N2 / N) RT / P. Therefore,V1 / V = N1 / (N1 + N2) and V2 / V = N2 / (N1 + N2).Therefore, V1 = V (N1 / (N1 + N2)) and V2 = V (N2 / (N1 + N2))2. We will find the entropy changes ΔS1 and ΔS2 in each gas when it expands from its initial volume to the final volume V. We use the fact that the entropy of an ideal gas is given by

S = Nk ln (V / N) + constant

where k is Boltzmann’s constant. The constant in the above equation is chosen such that the entropy is zero at zero temperature. Substituting for V1 and V2 in terms of V, we getS1 = N1k [ln (N / N1) - ln (N / (N1 + N2))] = Nk [N1 / N ln (N / N1) - (N1 + N2) / N ln (N / (N1 + N2))]ΔS1 = Nk [ln (N / N1) - ln (N / (N1 + N2))]S2 = N2k [ln (N / N2) - ln (N / (N1 + N2))] = Nk [N2 / N ln (N / N2) - (N1 + N2) / N ln (N / (N1 + N2))]ΔS2 = Nk [ln (N / N2) - ln (N / (N1 + N2))]The total entropy change due to the mixing process isΔSmix = ΔS1 + ΔS2 = Nk [N1 / N ln (N / N1) - (N1 + N2) / N ln (N / (N1 + N2))) + N2 / N ln (N / N2) - (N1 + N2) / N ln (N / (N1 + N2))]ΔSmix = Nk [(N1 / N) ln (N1 / N) + (N2 / N) ln (N2 / N) - ln (N / (N1 + N2)))]This is the expression for ΔSmix in terms of N, N1, and N2. In general, if the mixture contains a fraction x of gas 1 and a fraction y of gas 2, we can writeN1 = xN and N2 = yN where x + y = 1. Therefore,ΔSmix = Nk [(x ln x + y ln y) + ln (1 / (x + y))]Substituting x = 4/10 and y = 2/10, we getΔSmix = Nk [(4/10) ln (4/10) + (2/10) ln (2/10) + ln (10 / 6)]Substituting x = 2/10 and y = 3/10, we getΔSmix = Nk [(2/10) ln (2/10) + (3/10) ln (3/10) + ln (10 / 5)]

Substituting x = 4/10 and y = 3/10, we getΔSmix = Nk [(4/10) ln (4/10) + (3/10) ln (3/10) + ln (10 / 7)]

Therefore,ΔSmix (x = 4/10, y = 2/10) = Nk [(4/10) ln (4/10) + (2/10) ln (2/10) + ln (10 / 6)]ΔSmix (x = 2/10, y = 3/10) = Nk [(2/10) ln (2/10) + (3/10) ln (3/10) + ln (10 / 5)]ΔSmix (x = 4/10, y = 3/10) = Nk [(4/10) ln (4/10) + (3/10) ln (3/10) + ln (10 / 7)]

When x = 1/3 and y = 2/3, we getΔSmix = Nk [(1/3) ln (1/3) + (2/3) ln (2/3) + ln (3)]

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All matter is made up of substances called elements, which have specific chemical and physical properties and cannot be broken down into other substances through ordinary chemical reactions. Gold, for instance, is an element, and so is carbon. There are 118 elements, but only 92 occur naturally.

Answer:

Starch is a soft, white, tasteless powder that is insoluble in cold water, alcohol, or other solvents.

glycogen is a substance deposited in bodily tissues as a store of carbohydrates. It is a polysaccharide which forms glucose on hydrolysis.

Cellulose is a molecule, consisting of hundreds and sometimes even thousands of carbon, hydrogen and oxygen atoms.

The property of water that allows it to dissolve many substances is its polarity.

What is polarity?

Polarity refers to the distribution of electrical charge in a molecule. A polar molecule has an uneven distribution of electrons, resulting in a partial positive charge on one end of the molecule and a partial negative charge on the other end. This creates a dipole moment in the molecule.

Water molecules are polar, meaning that the electrons in the molecule are not distributed evenly, resulting in a partial positive charge on one end of the molecule and a partial negative charge on the other end.

This polarity allows water molecules to form hydrogen bonds with other polar or charged molecules, such as ions and polar compounds. This type of bonding allows many substances, such as salt and sugar, to dissolve in water.

Additionally, the polarity of water molecules also allows them to interact with nonpolar substances through London Dispersion Forces, which also allows some nonpolar substances to be dissolved in water.

Hence, the polarity of water allows it to dissolve many substances.

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Answer:

D

Explanation:

The air that we breathe in enters the nose or mouth, flows through the throat (pharynx) and voice box (larynx), and enters the windpipe (trachea). The trachea divides into two hollow tubes called bronchi.

Hamlet's portrayal shows that he believes himself to be unworthy of heroic action and full of self-deprecation. Ghost claims that by ingesting the waters of forgetfulness from the Underworld river.

Only Horatio and the readers discover the truth the about King's death in Hamlet, which creates dramatic irony. This kind of irony also emerges from his illusion of being angry. Others in the cast take him at his word when he lies to them.

When describing to Ophelia, Hamlet utilizes a simile to imply that it is both frigid and pure, or devoid of desire. Hamlet mocks Rosencrantz and Guildenstern by comparing playing a pipe to lying in this comparison (which they have been doing to him).

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Answer:

Joule is the SI unit of work. 1 Joule is amount of work done when a force of 1 Newton displaces a body through a distance of 1m in the direction of the force applied.

164 g of H₃PO₃ (phosphorus acid) would require 3 moles of H₂O for the reaction.

Given information,

Mass of H₃PO₃ = 164g

Moles of H₃PO₃ = 82 g/mol

The balanced chemical equation:

P₂O₃ + 3H₂O → 2H₃PO₃

For every 2 moles of H₃PO₃ produced, 3 moles of H₂O are required.

The number of moles of H₃PO₃:

Moles of H₃PO₃ = mass of H₃PO₃ / molar mass of H₃PO₃

Moles of H₃PO₃ = 164 g / 82 g/mol

Moles of H₃PO₃ = 2 mol

The number of moles of H₂O:

Moles of H₂O = (3/2) × moles of H₃PO₃

Moles of H₂O = (3/2) × 2 mol

Moles of H₂O = 3 mol

Therefore, 164 g of H₃PO₃ would require 3 moles of H₂O for the reaction.

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The actuation method triggered by a product-of-combustion detector in a CO2 system is typically referred to as "automatic actuation."

In this method, the product-of-combustion detector senses the presence of a fire or heat source and sends a signal to the CO2 system, causing it to automatically release CO2 to extinguish the fire.

This actuation method is commonly used in areas where fires may start unexpectedly, such as in server rooms, electrical substations, and other critical infrastructure facilities. It provides a fast and effective response to fires, helping to minimize damage and protect personnel.

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Answer:

there it is fella tried on ma own consciousness