A 50 kg sprinter, starting from rest, runs 50m in 7.0s at constant acceleration.a. What is the magnitude of the horizontal force acting on the sprinter?b. What is the sprinter’s power output at 2.0 s, 4.0 s, and 6.0s?

There are three types of lunar eclipses: total, partial, and penumbral.

During a total lunar eclipse, the moon is completely shadowed by the Earth, resulting in a reddish-brown color. In a partial lunar eclipse, only a portion of the moon is shadowed, while in a penumbral lunar eclipse, the moon passes through the Earth's outer shadow, resulting in a subtle darkening of the moon's surface. These classifications are based on the degree to which the moon passes through the Earth's shadow during the eclipse.

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The motor vessel tows a small dinghy, the tension in the rope is the force that is being applied to the dinghy. In this case, the tension in the rope is given as 150 newtons and the angle that the rope makes with the horizontal is 20 degrees.

The force which effectively pulls the dinghy forward, we need to resolve the tension force into its horizontal and vertical components. The horizontal component of the tension force is given by 150 * cos (20) = 139.7 N This is the force that effectively pulls the dinghy forward. To find the force which lifts the bows of the dinghy out of the water, we need to find the vertical component of the tension force. This force is given by 150 * sin (20) = 51.4 N This force lifts the bows of the dinghy out of the water. Therefore, the force which effectively pulls the dinghy forward is 139.7 N and the force which lifts its bows out of the water is 51.4 N. It's worth noting that the actual force required to lift the bows of the dinghy out of the water may be greater than this calculated value, as there are many other factors that can affect the buoyancy of the dinghy, such as its weight, shape, and the speed at which it is being towed.

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The stopping time will be 0.13 second required in order to safely stop a CEV .

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

The average force acting on CEV is = 426000 N.

Mass of the  CEV is = 7250 kg.

Initial speed of the CEV  is =  7.65 m/s

Hence, deceleration of the CEV is = ( 426000 N ÷ 7250 kg) = 58.75 m/s²

Hence, required stopping time = 7.65 m/s ÷ 58.75 m/s² = 0.13 second.

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u=0

a=10.9m/s^2

s=226m

v^2-u^2=2as

v^2=2 (10.9)(226)

v^2=49268

v=70.2m/s^2

v=u+at

70.2=0+10.9 (t)

70.2/10.9=t

t=6.44s

Answer:

Pangea is a supercontinent(one giant landmass) that existed around 300-200 years ago and was discovered by Alex Wegener. Take some time to research Pangea to understand the reasoning behind it.

Hope this helps :)

After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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Therefore, this reaction's internal energy change is -2850 J. This indicates a loss of 2850 J in the system's internal energy.

The definition defined energy as that of the "power to accomplish work" refers to the capacity to apply a force that moves an object. Kinetic energy and potential energy are the two categories of energy. The quantitative characteristic that is transferred to the a body or into a physical process in physics is energy, which is visible in the performance of labor as well as in form of heat and light. Energy is a resource that is conserved; it can only be changed through one form to another and it cannot be produced or destroyed, according to the law of conservation of energy.

According to the formula E = mc2, a body's mass (m) will vary by an amount equal to E/c2 if its energy increases by an amount E (in any form). This equation was developed by Albert Einstein.

Thomas Young coined the term "energy" for the first time in the realm of physics in 1800, but it didn't catch on. Later, Young utilized interference tests to demonstrate that light is indeed a wave.

The equation: can be used to determine the internal energy change for a reaction.

ΔU = Q - W

where U represents the change in internal energy, Q represents heat added to or released from the system, and W represents work performed by or on the system.

Since it is being released into the environment, the heat contributed to the system in this instance is -2290 J, and the work performed by the system is 560 J. Consequently, the internal energy change can be determined as follows:

ΔU = Q - W

ΔU = -2290 J - 560 J

ΔU = -2850 J

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Answer:

686.7

Explanation:

weight = mass x gravity

686.7 = 70 x 9.81

The correct answer for how the albedo of polar regions affect insolation is: Low temperatures are maintained because of the high amount of reflection.

The albedo of a surface refers to its ability to reflect sunlight. Higher albedo means more sunlight is reflected, while lower albedo means more sunlight is absorbed. Polar regions, such as the Arctic and Antarctic, have high albedo due to the presence of ice and snow, which reflect a significant portion of incoming sunlight.

When sunlight hits the polar regions with high albedo, a large portion of it is reflected back into space rather than being absorbed by the surface. As a result, less solar energy is available to heat the surface, leading to lower temperatures in these regions.

Therefore, low temperatures are maintained in polar regions because of the high amount of reflection caused by their high albedo.

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Answer:

59F

Explanation:

Given parameters:

Temperature in °C  = 15°C

Unknown:

Temperature in Fahrenheit scale  = ?

Solution:

To solve this, we use the conversion equation below;

       F  = (C x 1.8)  + 32

C is the temperature in celcius;

    F = (15 x 1.8) + 32  = 59F

The magnetic flux through the coil is given by:

Φ = BAcosθ

where B is the magnetic field, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the plane of the coil. Since the axis of the coil is parallel to the field, θ = 0 and the equation simplifies to:

Φ = BA

The rate of change of magnetic flux is given by:

dΦ/dt = d(BA)/dt = A(dB/dt)

Plugging in the given values, we get:

A = πr^2 = π(1.0 cm)^2 = 3.14 × 10^-4 m^2

dB/dt = (0.30 T - 0.00 T)/(20 ms) = 1.5 × 10^4 T/s

Therefore, the emf induced in the coil is:

emf = -N(dΦ/dt) = -500 × 3.14 × 10^-4 m^2 × 1.5 × 10^4 T/s = -0.235 V

Note that the negative sign indicates that the emf is induced in a direction that opposes the change in magnetic flux.

The correct option is a. There is only work done on the system, so there will be an increase in the internal energy of the gas that will appear as an increase in temperature.

When an ideal gas is compressed without allowing any heat to flow into or out of the gas, the temperature of the gas will increase. The correct option is a. There is only work done on the system, so there will be an increase in the internal energy of the gas that will appear as an increase in temperature.

In the process of compressing an ideal gas without allowing any heat to flow into or out of the gas, the internal energy of the gas increases as work is done on the system. This increase in internal energy appears as an increase in temperature.

Since the heat exchange is prohibited, all the work done is used to increase the internal energy of the gas as pressure is exerted on it by the surroundings.

Therefore, the correct option is a.

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Answer:

i dont know this is hard for me

According to Freud's theory of psychosexual development, identification refers to a process in which a child models their behavior, attitudes, and personality characteristics after someone of the same sex, usually a parent or caregiver.

In other words, the child identifies with and internalizes the traits and values of the person they see as a role model. Identification plays a crucial role in the formation of gender identity, as the child learns what it means to be a boy or girl based on the behaviors and attitudes they observe from their same-sex parent or caregiver.

This process is believed to occur during the phallic stage of psychosexual development, which occurs between the ages of 3 and 6 years old.During this stage, the child's focus is on their genitalia and they begin to develop a sense of gender identity.

They also experience the Oedipus or Electra complex, which is a desire to possess the opposite-sex parent and a fear of retaliation from the same-sex parent. The child resolves this conflict by identifying with the same-sex parent and adopting their gender role as their own.

This process is essential for the child's development of a healthy sense of self and their ability to navigate relationships with others.

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To find the missing values in the table, we can use the formula:

Q = I² * R * t

where Q is the energy in joules, I is the current in amperes, R is the resistance in ohms, and t is the time in seconds.

Eil. nr.      I            R             t           Q

1             5A        200Ω      10s     10000J

2            2A        500Ω       5s      10000J

3            40A      50Ω        10s      20000J

4            0.1A      300Ω      1.0s      30J

Here are the calculations for each missing value:

What is an energy?

Energy is a fundamental concept in physics that describes the ability of a system to do work or cause a change. In other words, energy is the capacity of a system to perform a task or produce an effect. energy can take many different forms.

What is resistance?

In physics, resistance refers to the opposition of a material or device to the flow of electrical current. In other words, resistance is a measure of how much a material or device hinders the flow of electric charge through it.

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a. The force acting on the astronaut by the moon is approximately 2.54 × 10^3 Newtons.

b. The speed of the astronaut orbiting the moon is approximately 1.54 × 10^3 meters per second.

a. To calculate the force acting on the astronaut by the moon, we can use Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

where:

F is the force,

G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2),

m1 is the mass of the astronaut (75 kg),

m2 is the mass of the moon (7.35 × 10^22 kg), and

r is the distance between the astronaut and the moon's center (2.5 × 10^6 m).

Let's plug in the values and calculate the force:

F = (6.67430 × 10^-11 m^3 kg^-1 s^-2) * (75 kg) * (7.35 × 10^22 kg) / (2.5 × 10^6 m)^2

F ≈ 2.54 × 10^3 N

Therefore, the force acting on the astronaut by the moon is approximately 2.54 × 10^3 Newtons.

b. To find the speed of the astronaut, we can use the centripetal force equation:

F = (m * v^2) / r

where:

F is the force (calculated in part a, approximately 2.54 × 10^3 N),

m is the mass of the astronaut (75 kg),

v is the speed of the astronaut (what we need to find), and

r is the distance between the astronaut and the moon's center (2.5 × 10^6 m).

Let's rearrange the equation to solve for v:

v^2 = (F * r) / m

v = √((2.54 × 10^3 N * 2.5 × 10^6 m) / 75 kg)

v ≈ 1.54 × 10^3 m/s

Therefore, the speed of the astronaut orbiting the moon is approximately 1.54 × 10^3 meters per second.

a. The force acting on the astronaut by the moon is approximately 2.54 × 10^3 Newtons.

b. The speed of the astronaut orbiting the moon is approximately 1.54 × 10^3 meters per second.

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Answer:

A. Trade winds

Explanation:

Answer:

b

Explanation:

Thx to random guy I know this

If a laboratory fire erupts, you should immediately notify your instructor and then proceed to use the fire extinguisher to put out the fire. It is important to follow proper safety procedures in such situations.

If a laboratory fire erupts, the first thing to do is to immediately notify your instructor. This is important because they are trained to handle emergencies like this and will know the best course of action to take. They may tell you to grab the fire extinguisher if it is safe to do so, but it is important to follow their instructions. In some cases, throwing water on the fire may actually make it worse, so it is best to let the instructor handle the situation. Opening windows can also help to provide ventilation and remove smoke from the room, but again, this should be done under the direction of the instructor. Remember, safety always comes first in an emergency situation.

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In the event of a laboratory fire, the first step is to use a fire extinguisher. Throwing water on the fire should be avoided. Notifying the instructor and opening windows are important safety measures.

In the event of a laboratory fire, it is important to follow proper safety protocols. Running for the fire extinguisher should be the first step, as it is the most effective way to put out a fire in the lab. Throwing water on the fire should be avoided, as it can potentially spread the flames or cause a chemical reaction. Notifying your instructor and opening the windows are also crucial steps to ensure everyone's safety and allow for proper ventilation.

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Answer:

Living thing

Explanation:

Nonliving things do not move by themselves, grow, or reproduce.

Answer:

Living

Explanation:

Unless you cut the tree, making that thang dead- its living

Mangrove root cells have higher solute concentrations than bald cypress roots. Mangroves are peculiar trees that grow in coastal or estuarine saltwater or brackish water.

They have specialised physiological and anatomical adaptations to live in certain settings.

Mangroves can handle high salt levels. Mangrove roots have salt glands that actively exude salt. This keeps their cell salt concentration low despite the high salt content of their surroundings.

However, freshwater swamp-dwelling bald cypress root cells have lower solute concentrations. Bald cypress tree root cells do not need to control or expel salts in freshwater environments since salt concentrations are significantly lower.

Mangrove trees adapt to saline surroundings, therefore their root cells have a higher solute concentration than bald cypress trees.

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Answer:

60m/s

Explanation:

Whenever two objects are moving in opposite direction the relative speed is obtained by adding the speeds of the two objects.

Here the two vehicles are moving with speed 20m/s and 40m/s .

So the relative speed of the car relative to that of the truck will be,

(40 + 20 ) m/s

60m/s

hope this helps!

The work done by a stock boy in 15 minutes to lift 60 boxes is 4.5kJ and the power to do this work is 300 W.

Work done in lifting the boxes = mgh

m =mass of the box

g = acceleration due to gravity

h = height

From the given,

m = 5 kg

g = 10m/s²

h = 1.5 m

Workdone = m×g×h

                  = 5×10×1.5

                  = 75 J

The work done by the boy to lift 4 boxes in a minute is 75 joule.

In 15 minutes, the boy can lift the box = 4×15 = 60 boxes

The work done to lift 60 boxes = 60 × 75 = 4500 J

Hence, the work done in lifing the 60 boxes in 15 minutes is 4.5 kJ.

Power is obtained by the ratio of workdone and time and the unit of power is watt (W)

Power = workdone/time

          = 4500 / 15

          = 300 W

The power for this job is 300 W.

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Answer:

40.1 m/s or 144.36 km/h

Explanation:

The equation is (v=∆ f/f) x (c/2)

V is velocity

delta f is returned frequency minus intial frequency divided by the initial frequency

c is the speed of light in m/s divided by 2

v= (400,000,109 Hz - 400,000,002 Hz)/400,000,002Hz x (299,792,458 m/s)/2

Hi there!

For a straight wire, we can use Ampère's Law to find its magnetic field at various distances from the wire.

Using the equation:
\(\oint B\cdot dl = B \cdot l = \mu_0 i\)

B = Magnetic field strength (T)
l = length of path of integration (m)

μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
i = Enclosed current (2.24 A)

This is a dot-product, so the cosine of the angle between the magnetic field and the path of integration is considered. However, since we are always tangential to the magnetic field, cos(0) = 1. We can simplify to B * l.

The length of the path of integration is equivalent to the circumference of a circle produced with a radius 'r' as a straight, long wire creates circular magnetic fields around the wire.

Therefore:
\(C = 2\pi r\\\\B \cdot 2\pi r = \mu_0 i\)

Solve for 'B'.

\(B = \frac{\mu_0i}{2\pi r}\)

1.

Plug in the given values and solve for the strength of the magnetic field at r = 0.022m.

\(B = \frac{(4\pi \times 10^{-7})(2.24)}{2\pi (0.022)} = \boxed{20.364 \mu T}\)

Using magnetic hand rules, a left-flowing (-x axis) current will result in a magnetic field of this strength INTO THE PAGE (or +y-axis if we assign the +/- z-axis to be up/down respectively) above the wire.

2.

Since B ∝ 1/R, if we double 'R', B will be halved.

Therefore:
\(B_{2R} = \frac{B_R}{2} = \frac{20.364 \mu T}{2} = \boxed{10.182 \mu T}\)

3.

The same logic applies. If we increase 'R' by 10x, B will decrease by 10x.

\(B_{10R} = \frac{B_R}{10} = \frac{20.364\mu T}{10} = \boxed{2.0364 \mu T}\)

However, since this point is BELOW the wire, the direction of the magnetic field differs. Using hand rules, the field would point OUT OF THE PAGE, or to the -y-axis.

The definition of eccentricity allows us to find that the answer for the distance to the focus is

             c = 4.6 10⁶ km

The orbit of the plants without ellipses, where the eccentricity is the ratio between the distance to the focus and the major axis  

                e = \(\frac{c}{a}\)

Where e is the eccentricity, c the distance to the focus and a the major axis

In this case they indicate the value of the eccentricity e = 0.92 and the value of the major axis a = 5 10⁶ km

              c = e a

Let's calculate

              c = 0.92 5 10⁶

              c = 4.6 10⁶ km

In conclusion using the definition of eccentricity we can calculate the distance to the focus is

             c = 4.6 10⁶ km

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Answer:

4,600,000 km

Explanation:

Answer:

a)  y_total = 575.4 m , b)   t_total = 22.56 s , c)  v = 106.20 m

Explanation:

a) We can solve this exercise using the scientific relations

Let's find the height reached while the engines are running

         v₁ = v₀ + a t

         v₁ = 62.3 + 4.30 3.73

         v₁ = 78.339 m / s

in this time it rose

        y₁ = v₀ t₁ + ½ a t₁²

        y₁ = 62.3 3.73 + ½ 4.30 3.73²

         y₁ = 262.29 m

At this moment the engines are turned off and the rocket continues in a vertical launch, suppose that the acceleration of gravity is constant in this path

        v₂ = v₁ 2 - 2 g y₂

at maximum height the velocity is zero (v₂ = 0)

        y₂ = v₁ 2 / 2g

        y₂ = 78.339 2/2 9.8

        y₂ = 313.11 m

the total height is

       y_total = y₁ + y₂

       y_total = 262.29 + 313.11

       y_total = 575.4 m

b) the time the rocket is in the air is

       t_total = t₁ + t₂

where t₂ is the time after the engines have shut down

       y = y₁ + v₁ t₂ - ½ g t₂²

      y = 0

      0 = 262.29 + 78.339 t₂ - ½ 9.8 t₂²

      t₂² - 15.99 t₂ - 53.53 = 0

      t₂ = [15.99 ±√ (15.99² +4  53.53)] / 2

      t₂ = [15.99 ± 21.67] / 2

      t₂´ = 18.83 s

      t₂´´ = -2.84 s

since the time must be a positive quantity the correct result is t2 = 18.83 s, the total time in the air is

      t_total = 3.73 + 18.83

      t_total = 22.56 s

c) the speed when it hits the ground

We can perform this calculation starting with the maximum height y = 575.4 m where it has zero initial velocity (vo = 0)

      v² = v₀² + 2 g y

      v = √ 2gy

       v = √ (2 9.8 575.4)

       v = 106.20 m

Answer:

25s

Explanation:

To find the amount of seconds it takes, you divide 100 (the meters) by 4 (the meters per second) the meters then cancel out, and you are left with 25 s

The force required to accelerate the block is 28 N.

The acceleration of a cart with a mass of 25 kg and applied force of 50 N is 2 m/s².

The mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is 0.5kg.

A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.

The force required to accelerate the block is calculated as follows;

F = ma

F = 3.5 kg x 8 m/s²

F = 28 N

The acceleration of a cart with a mass of 25 kg and applied force of 50 N is calculated as follows;

a = F/m

a = 50/25

a = 2 m/s²

The mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is calculated as follows;

m = F/a

m = 3 N / 6 m/s²

m = 0.5 kg

A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.

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The question involves a company that produces 3D-printed venturi valves for ventilators and assesses the quality of these valves based on three measures: product length, tube diameter, and tube wall thickness. A dataset containing information about these measures is provided. The task is to determine the quality of a new product with specific measure values using the K-nearest neighbors (KNN) approach, considering K values of 1 and 3.

The K-nearest neighbors (KNN) algorithm is a machine-learning technique used for classification or regression tasks. In this case, we want to predict the quality of a new product based on its three measures by comparing it to the existing dataset.

For K=1, we find the nearest neighbor to the new product in the dataset based on the Euclidean distance between their measure values. The quality of the new product would then be determined by the quality of this nearest neighbor.

For K=3, we find the three nearest neighbors to the new product and consider their qualities. One approach to determine the quality could be to take the average of the qualities of these three nearest neighbors.

By applying the KNN approach with K=1 and K=3 to the given dataset and the new product's measure values (2, -3, 0.1), we can determine the quality of the new product based on the qualities of the nearest neighbors.

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