a 50 kg laboratory worker is exposed to 20 mj of neutron radiation with an rbe of 10. What is the dose in mSv?

Answer:

Ver explicacion

Explanation:

Como se mencionó en la pregunta, un catalizador aumenta la velocidad de una reacción pero él mismo no participa en la reacción.

La descomposición del peróxido de hidrógeno se muestra mediante la ecuación;

2H2O2 (l) ------> 2H2O (l) + O2 (g)

La enzima involucrada en el proceso es la catalasa.

Answer:

Mechanical weathering

A. does not change rock composition

C. abrasion

F. ice wedging

Chemical weathering

B. oxidabon

D. changes rock composition

E. acid rain

Explanation:

In the column of mechanical weathering folowing points came does not change rock composition, ice wedging and abrasion.

Weathering is a phenomenon in which break down or cracking of rocks takes place due to various reasons.

Abrason is a kind of mechanical weathering as in this proces due to rubbing of a rack againt abother object causes weathering. And ice wedging is also a mechanical weathering because of the expansion of water it takes place.

Acid rain and oxidabon is a process in which rock changes its structure due to chemical reaction.

Hence division of weathering is done above properly.

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Charge flowed : 240 Coulombs

Given

t = time = 60 s

I = current = 4 A

Required

Charge

Solution

General formula :

Q = I x t

Q = charge (electricity), C

Input the value :

Q = 4 x 60

Q = 240 Coulombs

The equilibrium expression for the solid calcium hydroxide (Ca(OH)2) and the dissolved ions can be written as follows: K = [Ca2+][OH-]²

The equilibrium expression represents the relationship between the concentrations of the reactants and products at equilibrium for a given chemical reaction. In the case of solid calcium hydroxide dissolving in water, the equilibrium expression involves the concentration of the dissolved ions, calcium (Ca2+) and hydroxide (OH-). When calcium hydroxide dissolves in water, it undergoes a dissociation process where the solid dissociates into its constituent ions: Ca(OH)2(s) ⇌ Ca2+(aq) + 2OH-(aq). The equilibrium expression is derived based on the law of mass action and allows us to quantify the extent of the reaction at equilibrium. The concentration of each species is represented within square brackets, and the stoichiometric coefficients from the balanced equation are used as exponents.

In the case of calcium hydroxide, the equilibrium expression is given by K = [Ca2+][OH-]². This expression indicates that the equilibrium constant (K) is equal to the concentration of the calcium ions ([Ca2+]) multiplied by the square of the concentration of the hydroxide ions ([OH-]). The equilibrium constant, K, is a constant value at a given temperature and provides information about the extent of the reaction. For the dissolution of calcium hydroxide, the value of K will depend on the temperature and can be used to determine the equilibrium concentrations of the ions based on the initial conditions.

In summary, the equilibrium expression for the solid calcium hydroxide and the dissolved ions is K = [Ca2+][OH-]². This expression allows us to quantitatively describe the equilibrium concentrations of the calcium and hydroxide ions in the solution resulting from the dissolution of calcium hydroxide in water.

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The balanced chemical equation for reaction equation for the bromination of stilbene using pyridinium the limiting reagent in the following procedure is given as:

2 C₁₄H₁₂ + 3 Br₂ + 2 C₅H₅NHBr → 2 C₁₄H₁₁Br₂ + 2 C₅H₅N + 2 HBr

The bromination of stilbene using pyridinium bromide as the limiting reagent can be represented by the following balanced reaction equation:

2 C₁₄H₁₂ + 3 Br₂ + 2 C₅H₅NHBr → 2 C₁₄H₁₁Br₂ + 2 C₅H₅N + 2 HBr

In this reaction, stilbene (C₁₄H₁₂) reacts with bromine (Br₂) in the presence of pyridinium bromide (C₅H₅NHBr) as a catalyst. The products formed are 1,2-dibromo-1,2-diphenylethane (C₁₄H₁₁Br₂), pyridine (C₅H₅N), and hydrogen bromide (HBr).

The given question is incomplete and the complete question is given as,

Write a balanced reaction equation for the bromination of stilbene using pyridinium when the limiting reagent in the following procedure is given.

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A solution of CuSO₄ might be irradiated with a current of 12 A for 45 minutes and yield about 3.37 grams of copper (Cu).

Consider Faraday's law of electrolysis, which states that the amount of substance deposited or liberated at an electrode is directly proportional to the amount of electricity passed through the solution, when calculating the amount of copper (Cu) obtained by passing a current through a solution of CuSO₄.

To determine the amount of material (in grams), use the following formula: The formula for calculating substance amount (in grams) is current (in amperes) * time (in seconds) * molar mass / faraday's constant.

Let's first convert the values to the proper units: 12 A of current

45 minutes divided by 60 seconds equals 2700 seconds.

The next step is to calculate the molar mass of copper. Copper has a molar mass of about 63.55 g/mol.

The Faraday constant, which is equal to 96,485 C/mol, must also be used.

The formula can be used to determine how much copper was obtained:

(12 A * 2700 s * 63.55 g/mol) / (96,485 C/mol) equals (325,080 Asg) / 96,485 Cmol for the substance's mass in grams.

Simplifying even more = 3.37 g

Therefore, 3.37 grams of copper (Cu) would be produced by running a current of 12 A through a solution of CuSO₄ for 45 minutes.

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Answer:

Desk

Water

Cloud

Helium

Explanation:

Answer:

Soil permeability

Explanation:

Soil permeability is the ease with which gases, liquids or plant roots can penetrate or pas through the soil.

It is an important factor when considering soil property for agricultural purposes.

Answer:

Soil permeability

Explanation:

When the dry ingredients of a cake are combined, the result is a mixture. Option 3.

In chemistry, mixtures are substances that are obtained by mixing two or more chemically different substances together with each substance maintaining its chemical identity. In other words, the components of a mixture are still chemically unique and can be separated by physical means.

Mixtures can be homogeneous or heterogeneous. Homogenous mixtures are mixtures in which the components are uniformly dispersed throughout the entire mixture. For heterogeneous mixtures, the components are not uniform throughout the mixture.

Thus, when the dry ingredients of a cake, such as flour, sugar, etc., are combined, what we are going to have is a mixture. Whether this mixture would be homogenous or heterogeneous will depend on the level of mixing. Whatever the case may be, the components can still be separated by physical means.

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Answer:

1) The standard enthalpy change of neutralization is the enthalpy change when solutions of an acid and an alkali react together under standard conditions to produce 1 mole of water. Notice that enthalpy change of neutralization is always measured per mole of water formed. Enthalpy changes of neutralization are always negative - heat is released when an acid and and alkali react. For reactions involving strong acids and alkalis, the values are always very closely similar, with values between -57 and -58 kJ mol-1. That varies slightly depending on the acid-alkali combination (and also on what source you look it up in!).

2)same of n1

Answer:

Number one is f 2 is c number 3 is c

Explanation:

Those are the answers

Answer:xmnjjnnnnnnnnnnnnnnnnnnnnnnxxxxxxxxxxxxxxxxxxxxxhn cfghjnbvghjmnbvghmkjhbnmjhb mjhgvbnmkjyokonownndjnxjnjdndlnjbkxnlknsjcnldx bExplanation:

Answer:

military time

Explanation:

military time

Determining whether a functional group is acidic or basic depends on its ability to either donate or accept a proton (H+). Here are some general guidelines to help you assess the acidity or basicity of a functional group:

1. Acidity:

  a. Look for functional groups that have an acidic hydrogen directly bonded to an electronegative atom, such as oxygen or a halogen. Examples include carboxylic acids (–COOH) and phenols (–OH on an aromatic ring).

  b. Consider the stability of the resulting conjugate base. If the conjugate base is stabilized through resonance or delocalization of the negative charge, the functional group is more acidic. For example, the carboxylate ion (–COO-) is stabilized through resonance.

2. Basicity:

  a. Look for functional groups that contain lone pairs of electrons, which can readily accept a proton. Common examples include amines (–NH2) and amides (–CONH2).

  b. Consider the availability of lone pairs. The more accessible the lone pairs are, the more basic the functional group. For example, primary amines have more available lone pairs than tertiary amines and are, therefore, more basic.

It's important to note that the acidity or basicity of a functional group can also be influenced by its environment, neighboring groups, and other factors. These guidelines provide a general starting point, but there may be exceptions and variations based on specific compounds and circumstances.

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Taking into account the definition of dilution, if you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, you need to add more solvent until you get a final volume of 500 mL.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

1 M× 100 mL= 0.2 M× Vf

Solving:

(1 M× 100 mL)÷ 0.2 M= Vf

500 mL= Vf

In summary, if you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, you need to add more solvent until you get a final volume of 500 mL.

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The empirical formula of the compound is CH2O.

To find the empirical formula of the compound, we need to determine the ratios of the atoms in the compound. To do this, we need to find the number of moles of each element present in the compound.

The molar mass of carbon is 12.01 g/mol, the molar mass of hydrogen is 1.008 g/mol, and the molar mass of oxygen is 16.00 g/mol. The number of moles of carbon in the sample is:0.1565 g × 1 mol/12.01 g ≈ 0.0130 mol. The number of moles of hydrogen in the sample is:0.02627 g × 1 mol/1.008 g ≈ 0.0261 molThe number of moles of oxygen in the sample is:

0.4170 g × 1 mol/16.00 g ≈ 0.0261 mol

Now that we know the number of moles of each element, we can determine the simplest whole number ratio of the elements in the compound. We can do this by dividing each number of moles by the smallest number of moles. In this case, the smallest number of moles is 0.0130 mol.

We get:

Carbon: 0.0130 mol ÷ 0.0130 mol = 1

Hydrogen: 0.0261 mol ÷ 0.0130 mol = 2

Oxygen: 0.0261 mol ÷ 0.0130 mol = 2

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The Fischer esterification is a reaction between a carboxylic acid and an alcohol to form an ester, typically in the presence of an acid catalyst. The reaction proceeds via a nucleophilic acyl substitution mechanism.

The first step is protonation of the carboxylic acid by the acid catalyst, which makes it more electrophilic and facilitates attack by the alcohol. The alcohol then attacks the carbonyl carbon of the protonated carboxylic acid, forming a tetrahedral intermediate.

Next, a proton from the protonated alcohol is transferred to a nearby water molecule, generating an oxonium ion intermediate. This intermediate is then deprotonated by a base, such as the conjugate base of the acid catalyst, to form the ester product and regenerate the acid catalyst.

The overall reaction can be represented as:

Carboxylic acid + Alcohol → Ester + Water

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Answer:

Strong

Explanation:

You're holding it over a fire

so it's a strong force

Answer:

v = 1130 cm³

Explanation:

Given data:

Volume of sample = ?

Mass of Al sample = 3.057 Kg (3.057 Kg× 1000g/1 Kg = 3057g)

Density of Al sample = 2.70 g/cm³

Solution:

Formula:

d = m/v

d = density

m = mass

v= volume

by putting values

2.70 g/cm³ = 3057g /v

v = 3057g /2.70 g/cm³

v = 1130 cm³

Answer:

F

Cl

Br

I

Explanation:

Br=11.81...

Cl=12.96...

F=17.42...

Iodine=10.45

The crucible heated before the hydrate was added is to remove the moisture.

What is crucible and its uses?

Crucible is a type of container that is used to heat substances to very high temperatures. It is typically made of a heat-resistant material such as porcelain, metal, or graphite. It is used in a variety of laboratory and industrial processes such as metal smelting, distillation, and synthesis. Crucibles are often used to separate components of a sample by melting them away from the sample and then cooling the remained material for further analysis.

Heating the crucible before adding the hydrate serves two purposes. First, it ensures that any residual moisture in the crucible is removed.  Second, heating the crucible helps to ensure that the hydrate is completely dehydrated.  The crucible is typically heated before adding a hydrate because hydrates are compounds that contain water molecules, which can be chemically bound to the other components of the compound. When the hydrate is heated, the water molecules can be driven off through a process called dehydration, leaving behind the anhydrous compound.

Therefore, in order to remove the moisture the is crucible heated.

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Answer:

Approximately \(0.08\; \rm mol\), assuming that this gas is an ideal gas.

Explanation:

Look up the standard room temperature and pressure:\(25\; \rm ^{\circ}C\) and \(P = 101.325 \; \rm kPa\).

The question states that the volume of this gas is \(V = 2\; \rm dm^{3}\).

Convert the unit of all three measures to standard units:

\(\begin{aligned} T &= 25\; \rm ^{\circ}C \\ &= (25 + 273.15)\; \rm K \\ &= 293.15\; \rm K\end{aligned}\).

\(\begin{aligned}P &= 101.325\; \rm kPa \\ &= 101.325 \; \rm kPa \times \frac{10^{3}\; \rm Pa}{1\; \rm kPa} \\ &= 1.01325 \times 10^{5}\; \rm Pa\end{aligned}\).

\(\begin{aligned}V &= 2\; \rm dm^{3} \\ &= 2 \; \rm dm^{3} \times \frac{1\; \rm m^{3}}{10^{3}\; \rm dm^{3}} \\ &= 2 \times 10^{-3}\; \rm m^{3}\end{aligned}\).

Look up the ideal gas constant in the corresponding units: \(R \approx 8.31\; \rm m^{3}\cdot Pa \cdot mol^{-1} \cdot K^{-1}\).

Let \(n\) denote the number of moles of this gas in that \(V = 2\; \rm dm^{3}\). By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:

\(P \cdot V = n \cdot R \cdot T\).

Rearrange this equation and solve for \(n\):

\(\begin{aligned}n &= \frac{P \cdot V}{R \cdot T} \\ &\approx \frac{1.01325 \times 10^{5}\; {\rm Pa} \times 2 \times 10^{-3}\; {\rm m^{3}}}{8.31 \; {\rm m^{3} \cdot Pa \cdot mol^{-1} \cdot K^{-1}} \times 293.15\; {\rm K}} \\ &\approx 0.08\; \rm mol\end{aligned}\).

In other words, there is approximately \(2\; \rm mol\) of this gas in that \(V = 2\; \rm dm^{3}\).

Answer:

A: sink

Explanation: If an object's density is:

GREATER than \(1gcm^{3}\), it will SINK in water.

LESS than \(1gcm^{3}\), it will FLOAT in water.

hope this helps

The probability that the woman does not have cancer is approximately 98.53%.

Calculate the probability of having cancer given a positive test result.

Given an overall cancer prevalence of 2%, we can assume that the probability of having cancer is 0.02. To calculate the probability of having a positive test result, we need to determine the false positive rate (1 - specificity) of the test. The specificity of the test can be calculated by subtracting the false positive rate from 1. However, the false positive rate is not provided in the given information, so we cannot calculate the exact specificity of the test. Therefore, we cannot determine the probability of having cancer given a positive test result.

Calculate the probability of not having cancer given a negative test result.

To calculate the probability of not having cancer given a negative test result, we need to determine the false negative rate (1 - sensitivity) of the test. The sensitivity of the test can be calculated by subtracting the false negative rate from 1. Again, the false negative rate is not provided, so we cannot calculate the exact sensitivity of the test. However, since we know the cutpoint for defining a positive test result is ≥ 20 pg/mL, and the woman's serum-estradiol measurement is 13.5 pg/mL, which is below the cutpoint, we can assume that she would have a negative test result. Therefore, the probability of not having cancer given a negative test result would be close to 100%.

Calculate the probability that she does not have cancer.

The probability that she does not have cancer can be approximated by multiplying the probability of not having cancer given a negative test result with the probability of having a negative test result. Assuming the sensitivity and specificity of the test are reasonably high, we can estimate that the probability of not having cancer given a negative test result is close to 100%, and the probability of having a negative test result is close to 100%. Therefore, the probability that she does not have cancer is approximately 98.53%.

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Answer:

add a substace devider

Explanation:

i forgot what it was called but there is a chemical that allows the substances to seperste and than you can test the substaces ph and what it is

Answer:

Explanation:

Transparent and translucent materials transmit most of the light that strikes them, but not all of it. Light can also

reflect off these materials. When light reflects, it is bouncing off something. Windows transmit most of the light that strikes them, but they also reflect light. If you have a lamp turned on near a window at night, you can see the reflection of the lamp in the window.

Transparent and translucent materials also absorb some of the light that strikes them. When something absorbs light, it is soaking up the light. When light is absorbed by an object, the light energy changes to heat energy and the object heats up. If you touch a window that has been in the sunlight, you will notice that it is warm.

Opaque materials do not transmit any light. All of the light that strikes an opaque material is reflected or absorbe

125 ml of ethanol contain, of ethanol is \(2.44 moles\)

Moles are a unit of measurement used to quantify the amount of a substance. One mole of a substance is equal to 6.02 x 10^23 particles, also known as Avogadro's number. This number is used in many equations to describe the amount of a substance, such as the ideal gas law, which is PV = nRT, where n is the number of moles. Another equation used to describe moles is the mass-molarity equation, which states that the molarity of a solution is equal to the mass of the solute divided by the molar mass multiplied by the volume of the solution.The moles of ethanol present in 125 ml of ethanol can be calculated using the density and the molar mass of ethanol. The molar mass of ethanol is 46 g/mol.

Therefore, the number of moles of ethanol present in 125 ml of ethanol can be calculated using the following equation:

\(Moles=\frac{ (Density * Volume) }{ Molar Mass}\)

Moles = \(\frac{(0.789 g/ml x 125 ml) }{ 46 g/mol}\)

Moles = \(2.44 moles\)

Therefore ,125 ml of ethanol contain, of ethanol \(2.44 moles\) .

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3.4 moles of carbon tetrachloride is equivalent to 523.6g.

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

mass = no. of moles × molar mass

According to this question, 3.4 moles of carbon tetrachloride is given. The mass can be calculated thus;

molar mass of carbon tetrachloride = 154g/mol

mass = 3.4 moles × 154g/mol

mass = 523.6g

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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The final volume of the gas at 89 KPa and 120 °C, given that it occupies 1.75 L at 675 °C and 1.45 atm, is 1.20 L

First, we shall list out the given parameters from the question:

The final volume of the gas can be obtained by using the combined gas equation states as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

(1.45 × 1.75) / 948 = (0.878 × V₂) / 393

Cross multiply

948 × 0.878 × V₂ = 1.45 × 1.75 × 393

Divide both side by (948 × 0.878)

V₂ = (1.45 × 1.75 × 393) / (948 × 0.878)

= 1.20 L

Thus, from the above calculation, we can conclude that the final volume of the gas is 1.20 L

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