Answer:
F = 47.6 N
Explanation:
Newton's 2nd law can be expressed as the rate of change of the total momentum, respect of time, as follows:\(F = \frac{\Delta p}{\Delta t}\)
So, in order to find the average force exerted by the skater on the wall, we can find the change in momentum due to the force exerted by the wall (which is equal and opposite to the one exerted by the skater), and divide it by the time interval , as follows:\(F_{wall} = \frac{\Delta p}{\Delta t} =\frac{(48.0 kg*(-1.06m/s)}{1.07s} = -47.6 N\)
⇒ Fsk = 47.6 N (normal to the wall)
ANSWER ALL QUESTIONS and show your work ON THE ATTACHMENT AWARD 50 pts if you don’t know the answer to all of them I have posted them individually so I can still mark you brainlessly (however you spell the darn thing)
Answer:
the velocity is 210 - hq squared which equals to 14
How have humans
changed the area and how might this affect recovery after the flood?
Answer:
Explanation:
Loss of lives and property: Immediate impacts of flooding include loss of human life, damage to property, destruction of crops, loss of livestock, non-functioning of infrastructure facilities and deterioration of health condition owing to waterborne diseases. Flash floods, with little or no warning time, cause more deaths than slow-rising riverine floods.
Loss of livelihoods: As communication links and infrastructure such as power plants, roads and bridges are damaged and disrupted, economic activities come to a standstill, resulting in dislocation and the dysfunction of normal life for a period much beyond the duration of the flooding. Similarly, the direct effect on production assets, be it in agriculture or industry, can inhibit regularly activity and lead to loss of livelihoods. The spill over effects of the loss of livelihoods can be felt in business and commercial activities even in adjacent non-flooded areas.
Decreased purchasing and production power: Damage to infrastructure also causes long-term impacts, such as disruptions to clean water and electricity, transport, communication, education and health care. Loss of livelihoods, reduction in purchasing power and loss of land value in the flood plains lead to increased vulnerabilities of ties living in the area. The additional cost of rehabilitation, relocation of people and removal of property from flood-affected areas can divert the capital required for maintaining production.
Mass migration: Frequent flooding, resulting in loss of livelihoods, production and other prolonged economic impacts and types of suffering can trigger mass migration or population displacement. Migration to developed urban areas contributes to the overcrowding in the cities. These migrants swell the ranks of the urban poor and end up living in marginal lands in cities that are prone to floods or other risks. Selective out-migration of the workforce sometimes creates complex social problems.
Psychosocial effects: The huge psycho-social effects on flood victims and their families can traumatize them for long periods of time. The loss of loved ones can generate deep impacts, especially on children. Displacement from one’s home, loss of property and livelihoods and disruption to business and social affairs can cause continuing stress. The stress of overcoming these losses can be overwhelming and produce lasting psychological impacts.
Hindering economic growth and development: The high cost of relief and recovery may adversely impact investment in infrastructure and other development activities in the area and in certain cases may cripple the frail economy of the region. Recurrent flooding in a region may discourage long-term investments by the government and private sector alike. Lack of livelihoods, combined with migration of skilled labour and inflation may have a negative impact on a region’s economic growth. Loss of resources can lead to high costs of goods and services, delaying its development programmes.
Political implications: Ineffective response to relief operations during major flood events may lead to public discontent or loss of trust in the authorities or the state and national governments. Lack of development in flood-prone areas may cause social inequity and even social unrest posing threat to peace and stability in the region.
A postal worker on a bicycle travels at an average speed of 4 m/s for 3 minutes. Work out how far she travelled.d by the car in miles.
Answer:
Before we begin, first convert the minutes unit to seconds to match the unit for speed. Since there are 60 seconds in a minute, and there are 3 minutes, 3*60 = 180 seconds. Using the formula s = d/t, we can manipulate this formula to solve for d, the distance. So we isolate the d variable, to get d = st, and we can substitute the values of s and t into this formula. Now we have d = 4m/s*180s. Now we solve this to get d = 720m. Now we can convert meters to miles, to get approximately 0.45 miles.
Explanation:
compare the times of all sunsets during the same period what do you observe
Answer:
Theres no given?
Explanation:
Well, whatever.
I observed the shift of their sunset time.
Examples like:
January to June = their sunset time increased while
July to December = their sunset time decreased
who is the father of kinematics ?
explain +)
Answer:
FRANZ REULEAUX
Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.
A beam of light has a wavelength of 620 nm in vacuum.
a. What is the speed of this light in a liquid whose index of refraction at this wavelength is 1.56? (Use 3.00×108 m/s for the speed of light in a vacuum.)
b. What is the wavelength of these waves in the liquid?
Explanation:
It is given that,
Wavelength of a beam of light in vacuum, \(\lambda_o=620\ nm\)
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,
\(n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s\)
(b) The wavelength of light in material,
\(\lambda=\dfrac{\lambda_o}{n}\)
Let \(\lambda_1\) is the wavelength of these waves in the liquid. So,
\(\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m\)
Hence, this is the required solution.
500000000 in standard form
Answer:
5.0 x 10^8
Explanation:
because u moved it 8 times to it places
A spring is resting vertically on a table. A small box is dropped onto the top of the spring and compresses it. Suppose the spring has a
spring constant of 300 N/m and the box has a mass of 1.9 kg. The speed of the box just before it makes contact with the spring is 0.39
m/s.
(a) Determine the magnitude of the spring's displacement at an instant when the acceleration of the box is zero.
(b) What is the magnitude of the spring's displacement when the spring is fully compressed?
(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.
Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.
The gravitational potential energy is given by:
mgh = (1.9 kg)\((9.8 m/s^2)h\)
The elastic potential energy stored in the spring is given by:
1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.
The kinetic energy of the box just before it makes contact with the spring is given by:
\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.
Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.
mgh = 1/2 \(kx^2\)
Substituting the given values, we have:
\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)
Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.
(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.
At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.
mgh = 1/2 \(kx^2\)
Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.
It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.
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A 0.45 μF and a 0.67 μF capacitor are connected in series to a 15 V battery. a Calculate the potential difference across each capacitor.Express your answers using two significant figures. Enter your answers numerically separated by a comma.b Calculate the charge on each capacitor.Express your answers using two significant figures. Enter your answers numerically separated by a comma.c Repeat part A assuming the two capacitors are in parallel.Express your answers using two significant figures. Enter your answers numerically separated by a comma. dRepeat part B assuming the two capacitors are in parallel.Express your answers using two significant figures. Enter your answers numerically separated by a comma.
Given,
let C1 = 0.45 μF and C2 = 0.67 μF
And Voltage = 15 V.
Here both the capacitor are in series so the equivalent capacitor is,
\(\begin{gathered} \frac{1}{Ceq}=\frac{1}{C1}+\frac{1}{C2}=(\frac{1}{0.45}+\frac{1}{0.67})\times\frac{1}{10^{-6}}=(\frac{2.22+1.492}{10^{-6}})=\frac{3.712}{10^{-6}} \\ So,\text{ }Ceq=\frac{10^{-6}}{3.712}=0.2694\text{ }\mu F \end{gathered}\)As we know that,
\(\begin{gathered} C=\frac{Q}{V} \\ \therefore Q=CV=0.2694\times10^{-6}\times15=4.041\text{ }\mu C \end{gathered}\)So charge on each capacitor will be equal to 4.041 μC.
The capacitors are connected in series so the charge on both the sphere will be same but potential difference across each capacitor will be different.
The voltage across the capacitors are,
\(\begin{gathered} V1=\frac{Q}{C1}=\frac{4.041\times10^{-6}}{0.45\times10^{-6}}=8.98V \\ V2=\frac{Q}{C2}=\frac{4.041\times10^{-6}}{0.67\times10^{-6}}=6.031V \end{gathered}\)So potential difference across C1 is 8.98V and C2 is 6.031V.
If we connect both the capacitor in parallel connection then the equivalent capacitor will be,
\(Ceq=C1+C2=(0.45+0.67)\times10^{-6}=1.12\text{ }\mu F\)In parallel connection the voltage across the capacitor will be same but the charge will be different.
So the potential across each capacitor is 15 Volt.
The charge on each capacitor is,
\(\begin{gathered} Q1=(C1)V=0.45\times10^{-6}\times15=6.75\mu C \\ Q2=(C2)V=0.67\times10^{-6}\times15=10.05\mu C \end{gathered}\)So in parallel connection the charge on C1 = 6.75 μC and charge on C2 = 10.05 μC.
What is the displacement of a student who walks 12 m North, 5 m West, 3 m South,
and finally 6 m West to get to his next class?
When you draw all 4 of those moves, you see that he winds up 9m North and 11m West of where he started.
So the magnitude of his displacement is
D = √(9² + 11²) m²
D = √(81 + 121) m²
D = √(202) m²
D = 14.2 m
The direction is arctan(-11/9) = 50.7° west of North
Can a naturalized citizen serve as President/Vice President?
Answer:
No
Explanation:
I read a lesson about this yesterday, the president has to be naturally born in the US and has to live there for some years (30 I think?)
Answer:
The U.S. Constitution requires that a candidate for president or vice president must have been born in the United States or otherwise a “natural born citizen.” Controversies have arisen in U.S. history from time to time as to who is “natural born” and therefore eligible to be president. Furthermore, with so many foreign-born citizens living in the United States, many people believe this constitutional requirement itself should be changed.
Explanation:
NaCl solid is an example of a/an
A. Insulator
B. Conductor
OC. Nonmetal
D. Metalloid
Refer to the picture!
(a) The work done by the donkey on the cart is 59,721.9 J.
(b) The work done by the force of gravity on the cart is -48,434.87 J.
(c) The work done on the cart by friction during this time is 11,315.12 J.
What is the work done by the donkey on the cart?(a) The work done by the donkey on the cart is calculated as follows;
Wd = Fd cosθ
where;
F is the applied force by the donkeyd is the displacementθ is the angle of inclinationWd = 375 N x 163 m x cos(12.3)
Wd = 59,721.9 J
(b) The work done by the force of gravity on the cart is calculated as;
Wg = Fg x d x cosθ
Where;
Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacementθ = 90⁰ + 4.03⁰ = 94.03⁰
Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)
Wg = -48,434.87 J
(c) The work done on the cart by friction during this time is calculated as;
Wf = Ff x d x cosθ
where;
Ff is the force of friction;Ff = μmg cosθ
Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)
Ff = 69.59 N
Wf = 69.59 x 163 x cos (4.03)
Wf = 11,315.12 J
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The lines in the emission spectrum of hydrogen result from __________.
a. energy given off in the form of visible light when an electron moves from a higher energy state to a lower energy state
b. protons given off when hydrogen burns
c. electrons given off by hydrogen as it cools
d. electrons given off by hydrogen when it burns
e. decomposing hydrogen atoms.
Answer:
Option (a) is correct.
Explanation:
The lines in the emission spectrum of hydrogen is due to the transfer of electrons form higher energy levels to the lower energy levels.
When the electrons transfer from one level of energy that is higher level of energy to the other means to the lower level of energy then they emit some photons which having the frequency or the wavelength in the visible region.
A 60.6 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large piece of chocolate cake rated at 720 (food) Calories. How high must the person climb? The acceleration due to gravity is 9.8 m/s 2 and 1 food Calorie is 103 calories. Answer in units of km.
The height the weight-watcher needs to climb to work off the equivalent of the chocolate cake is 0.5225 km.
What is the height of the person?The height the weight-watcher needs to climb to work off the equivalent of the chocolate cake is calculated as follows;
P.E = mgh
Where;
m is the mass of the objectg is the acceleration due to gravityh is the height.720 Calories x 103 calories/1 food Calorie = 74,160 calories
74,160 calories = 310285.44 J
h = P.E/mg
h = (310285.44) / (60.6 x 9.8)
h = 522.5 m
h = 0.5225 km
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What forces are acting on the race car while it is in motion? (hint: there are 3
forces)
Answer:
the forces acting on the car while moving are - frictional force, applied force , air resistance and gravity.:
A ball is dropped from a height of 10m. At the same time, another ball is thrown
vertically upwards at an initial speed of 10m/sec. How high above the ground will the two balls
collide?
5.1 m
Explanation:
Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by
\(y_1 = 10 - \frac{1}{2}gt^2\) (1)
where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground \(y_2,\) is given by
\(y_2 = v_0t - \frac{1}{2}gt^2\) (2)
At the instant the two balls collide, they will have the same displacement, therefore
\(y_1 = y_2 \Rightarrow 10 - \frac{1}{2}gt^2 = v_0t - \frac{1}{2}gt^2\)
or
\(v_0t = 10\:\text{m}\)
Solving for t, we get
\(t = \dfrac{10\:\text{m}}{v_0} = \dfrac{10\:\text{m}}{10\:\text{m/s}} = 1\:\text{s}\)
We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):
\(y_1 = 10\:\text{m} - \frac{1}{2}(9.8\:\text{m/s}^2)(1\:\text{s})^2\)
\(\:\:\:\:\:\:\:= 5.1\:\text{m}\)
7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.
The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.
What is centrifugal force?when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.
It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.
The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.
To simulate gravity for the inhabitants, the concept of the centrifugal force is used.
Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.
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The diagram below shows two waves. At which letter (A-D) on the diagram is constructive interference going to occur?
A. A
B. B
C. C
D. D
At A and C, there is constructive interference occur.
constructive interference happens when two waves are in phase, right?Constructive interference happens when the maxima of two waves combine (the waves are in phase), resulting in a wave whose amplitude is equal to the total of the amplitudes of the separate waves. In a similar way, the wave minima would line up.
Where may one find constructive interference?The intersection of the lines (indicating peaks) is when constructive interference happens. To put it another way, when two waves are in phase, they interact positively. When two waves are fully out of phase (their peak is in the middle), destructive interference happens.
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A swimmer runs horizontally off a diving board with a speed of 3.04 m/s and hits the water a horizontal distance of 1.68 m from the end of the board.
With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.
What is velocity, for instance?The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.
We can use the kinematic equations of motion to solve this issue.
Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:
x=1.68 m and v0x=3.04 m/s
Δx = v0x * t
calculating t:
t = 1.68 m / 3.04 m/s because x / v0x.
t = 0.5526 s
Thus, the swimmer enters the water in 0.5526 seconds.
"y" equals "v0y*t" plus "(1/2)*a*t2"
replacing the values with:
Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²
Δy = -1.70 m
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A family is visiting the Statue of Liberty in New York City. One of the children accidentally drops her backpack from the top of the viewing platform which is 300 feet above the ground. At what height will the kinetic energy of the backpack be equal to it's potential energy?
In fact the actual height at which the two energies are equal can be determined only if there is a specified velocity. So by theoretically equating the energy equation we will arrive at the point that the height equal to 4.9 V².
What is kinetic energy?The kinetic energy of a body is the energy formed by virtue of its motion. It is directly proportional to the mass and velocity of the moving body and the equation is written as:
KE = 1/2 MV².
Potential energy is formed by virtue of the position of a body and it is equal to mgh. Where, g is gravitational acceleration equal to 9.8 m/s² and m is mass and h is the height from the ground.
The total of these two energy is called mechanical energy of a body and the total mechanical energy of a body is always conserved.
If the kinetic energy and potential energy are equal then the equations can be equated as:
1/2 mV² = mgh
V²/2 = gh.
=9.8 h
h = 4.9 V²
Therefore at a height of 4.9 V² the energies of the falling body will be equal where v is the velocity of the moving body.
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URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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EXTREMELY URGENT! DUE IN 15 MINUTES
Answer:
Antibiotics can only kill bacterial infections. they cant treat viruses because it's a viral infection that spreads through the body
They can't be used to treat infections caused by the Corona or any virus because antibiotics only kill bacterial infections. They can not treat Corona or any virus because it's a viral infection that spreads through out the body.
TOINETS
Assuming that distances are
equal, which of the following
objects would have the MOST
gravitational force with you?
A. Jupiter
NETTUNE
B. Earth
UNIVERSE
C. Sun
Answer:
The sun.
Explanation:
The sun has the most gravitational pull.
Convex lenses cause light rays to _____.
Answer:
to meet at a single point
(causing rays of light that are initially parallel to meet at a single point)
hope this helps:)
Explanation:
Answer:
focus
Explanation:
see more here
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What is a positive effect of increased carbon dioxide within the carbon cycle?
Answer:
The positive impact in the cycle is that CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.
Explanation:
Carbon cycle is the process by which carbon dioxide travels from the atmosphere to the earth and returns back to the atmosphere.
The negative impact of carbon dioxide in the carbon cycle is that it will cause green house effect. However, when it comes to the positive impact in the cycle, CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.
5. A capacitor is discharging through a resistor. The initial voltage across the capacitor is 3.2 V at t = 0. The voltage across the capacitor at time t = 20 ms is 0.8 V. The time it takes for the voltage across the capacitor to drop from 0.8 V to 0.2 V is
Hi there!
Recall the equation for the voltage of a discharging capacitor:
\(V_C(t) = V_0e^{-\frac{t}{\tau}}\)
V₀ = Initial voltage of the capacitor (V)
t = Time (s)
τ or RC = Time Constant (s)
With the given information, we can plug in the value for V₀:
\(V_C(t) = 3.2e^{-\frac{t}{\tau}}\)
We are given that at t = 20 ms (0.02 s), the voltage of the capacitor is 0.8V. We can use this to solve for the time constant (τ).
\(0.8 = 3.2e^{-\frac{0.02}{\tau}}\\\\0.25 = e^{-\frac{0.02}{\tau}}\)
Take the natural log of both sides and solve.
\(ln(0.25) = -\frac{0.02}{\tau}\\\\-1.3863 = -\frac{0.02}{\tau}\\\\\tau = \frac{0.02}{1.3863} = 0.0144 s\)
Now, we can use this time constant to solve for the time taken for the voltage to drop from 0.8 V to 0.2 V. Solve for the time taken for the capacitor's voltage to drop to 0.2 V:
\(0.2= 3.2e^{-\frac{t}{0.0144}}\\\\0.0625 = e^{-\frac{t}{0.0144}}\\\\ln(0.0625) = -\frac{t}{0.0144}\\\\t = (-2.773)(-0.0144) = 0.04 s\)
Now, subtract the times:
\(0.04 - 0.02 = 0.02 = \boxed{20 ms}\)
When do electromagnetic spectrum become beneficial and harmful?
Electromagnetic spectrum:
The orderly distribution (sequential arrangement) of E.M. waves according to their wavelengths or frequencies in form of distinct groups having different properties is called as E.M. spectrum.When first E.M. waves were discovered and researched the scientists coped up with a lots of benefits of it especially in the telecommunication industry. Later, when the E.M. spectrum was started using in industry the people came to know about its harmful disadvantages which it cause. They are as follows:
Advantages of E.M. spectrum:
E.M. spectrum was started using in telecommunication and IT sector at a high rate due to its communication properties. E.M. waves were used as a medium to serve as a transmitter and reciever at big stations for transferring and capturing signals, messages, data and much more. E.M. beam was also used in treatment of cancer and sterilization purposes for diseases like cancer, neuroskeletal abnormalities.Disadvantages of E.M. waves:
High frequencies of waves results into formation of high heat and temperature. Results into heat and burns on skin and skin diseases. U.V. rays result into damaging skin cells and increase of diseases such as cancer, tumor, etc.(PS: E.M. waves do become beneficial and harmful when it's usage is done. Basically, they come with both it's advantages (benefits) and disadvantages (harmfulness) when we use it. Especially it is commonly seen in industrial areas or communication sector)
A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
of 20 m along level ground (Figure 3). The total weight of sled and load is 14,700
2
N. The tractor exerts a constant 5000 N force at an of 36.9
◦ angle of above the
horizontal. A 3500 N friction force opposes the sled’s motion. Find the work
done by each force acting on the sled and the total work done by all the forces.
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
Work done by the applied forceThe work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
Work done by frictional forceW = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
Net work done by all the forces on the tractorW(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
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A car accelerates uniformly from rest to 23 m/s over .29 minutes.
What is the
acceleration of the car? (1 minute = 60 seconds)
* 5 poin
Answer:
1.322 m/s²
Explanation:
using the first equation of linear motion, we can calculate the acceleration
v = u +at
making a the subject of the formula
a = (v - u)/t
a= (23-0)/.29x60
= 1.322 m/s²