A 47.0 kg cheetah can run with a speed of 31.0 m/s. What is the cheetah's kinetic energy?​

The centripetal force affecting the body has to be doubled.

1. The centripetal force acting on a body moving in a circular path of radius r with speed v is given by F = mv²/r, where m is the mass of the body.

2. If the speed of the body increases to √2v while moving in the same circular path, the new centripetal force acting on the body can be calculated as follows:

  F' = m(√2v)²/r = 2mv²/r

3. Comparing the new centripetal force F' with the initial centripetal force F, we get:

  F' = 2F

4. As a result, the centripetal force acting on the body must be twice in order for the body to proceed in the same circular direction at 2v.

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Answer:

Power is the rate at which work is done or energy is transferred in a unit of time. Power is increased if work is done faster or energy is transferred in less time.

Answer:An element cannot be broken down into any other substance. ... Compounds are substances made from atoms of different elements joined by chemical bonds. They can only be separated by a chemical reaction. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).

Explanation:I hope this helps

Answer:

Mixture is a substance that is formed when two or more compounds or elements are mixed in any ratio. For example- sherbet, air. sand, etc.

Explanation:

An element cannot be broken down into any other substance. ... Compounds are substances made from atoms of different elements joined by chemical bonds. They can only be separated by a chemical reaction. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).

;-; sorry hopes this helps a little

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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The distinction in top among the pinnacle floor of glycerin and the pinnacle floor of ethyl alcohol is 0.0432 meter or 4.32 centimeter the difference in height between the top surface of glycerin and the top surface of alcohol is 4.32 centimeter.

Given the subsequent data:

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An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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Answer:

The right answer is "0.273 m".

Explanation:

Given:

Power (P),

\(\frac{1}{f} = 2D\)

Near point,

u = 0.6 m

As we know,

⇒ \(\frac{1}{v} -\frac{1}{u}=\frac{1}{f} = 2\)

By substituting the values, we get

⇒ \(\frac{1}{v} -\frac{1}{0.6} =2\)

            \(\frac{1}{v}=2+\frac{1}{0.6}\)

            \(\frac{1}{v} =\frac{1.2+1}{0.6}\)

            \(\frac{1}{v}=\frac{2.2}{0.6}\)    

By applying cross-multiplication, we get

          \(0.6=2.2 \ v\)

            \(v = \frac{0.6}{2.2}\)

      \(S_{near} = 0.273 \ m\)

A jet of water squirts out horizontally from a hole near the bottom of the tank shown in the figure. If the hole has a diameter of 3.80 mm, the height h of the water level in the tank is 44.1 cm

The height of the water level can be calculate as follows:

According to kinematics, if the water's initial velocity when it exits the tank is, its horizontal range is given by

d = v√(2y/y)

where, y is the acceleration caused by gravity and is the vertical distance from the ground to the hole.

Torricelli's law provides the velocity of the fluid flowing out of the hole. the velocity  of water coming out of the hole is

v=√(2gh)

where,h is the tank's top-to-bottom distance, as depicted in the picture.

The horizontal range equation is used to calculate the water's exit velocity from the hole:

d= v√(2y/g)

v= d x √(g/2y)

and since d= 0.600 m an y= 1 m

v= 0.600  x √(9.8/2(1))

v= 0.600 x 4.9

v= 2.94 m/s

Now, we can  use Torricelli's theorem to find the height

v=√(2gh)

h = v²/2g

h = (2.94)² / 2 (9.8)

h = 0.441 m = 44.1 cm

Your question is incomplete because of missing picture but most probably your full question attached below

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Answer: C. Ask a question that can be answered by making observations.

Explanation: Just did it

Answer:

Iodine is most similar  to the other non- metals in the Halogen Family, such as Fluorine, Chlorine, Bromine, Astatine .

Explanation:

Given,

The mass of the ball, m=16 g=16×10⁻³ kg

The length of the string, r=1.4 m

The period of revolution of the ball, T=1.09 s

The angular velocity of the ball is given by,

On substituting the known values,

The tension on the string will be equal to the centrifugal force that acts on the ball.

And it is given by,

On substituting the known values,

Thus the magnitude of the tension of the string is 0.74 m

The luminosity of this star in units of the solar luminosity would be: 483.7L.

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

b) We cannot calculate the work done by the friction force.

c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:

Work_gravity = force_gravity * displacement * cos(theta),

where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).

The weight of the block is given by:

force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.

Plugging in the values, we get:

Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.

The work done on the 6.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.

The negative sign indicates that the tension is in the opposite direction of the displacement.

Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:

Work_net = change_in_kinetic_energy.

Since the block starts from rest, its initial kinetic energy is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.

Solving for velocity, we get:

velocity = sqrt(2 * Work_net / mass).

The net work done on the block is the sum of the work done by gravity and the tension:

Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.

Plugging in the values, we get:

velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.

Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.

The work done on the 8.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.

The work done on the 8.00 kg block by the friction force can be calculated using the formula:

Work_friction = force_friction * displacement * cos(theta),

where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.

(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.

Simplifying, we get:

Work_net = 1/2 * 14.00 kg * velocity^2.

Using the value of velocity calculated in part (a), we get:

Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.

The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:

Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.

The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:

Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.

Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.

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Answer:

1. 125N

2. 200N

3. 280N

Explanation:

Force= mass × acceleration

1. force= 25×5

= 125N

2. Force= 50×4

=200N

3. Force=70×4

=280N

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

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(a) The work done by the applied force is 32.6 J.

(b) The work done by gravity on the block is 29.4 J.

(c) The magnitude of the normal force is 29.4 N.

The force applied to the block is determined by applying the formula for the net force on the block.

F(net) = 0

Fcosθ - mg - Fsinθμ = 0

Fcosθ - Fsinθμ = mg

F(cosθ - sinθμ) = mg

F = (mg) / (cosθ - sinθμ)

F = (3 x 9.8) / (cos26  -  0.2 x sin26)

F = 36.25 N

The work done by the applied force is calculated as;

W = Fd cosθ

W = (36.25 x 1) x cos(26)

W = 32.6 J

The work done by gravity on the block is calculated as follows;

W = mgd

W = 3 x 9.8 x 1

W = 29.4 J

The magnitude of the normal force is calculated as follows;

N = mg

N = 3 x 9.8

N = 29.4 N

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Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

The statement which does not describe energy within an ecosystem is that Energy is always fully contained and is denoted as option A.

This is referred to as all the organisms and the physical environment with which they interact. Energy on the other hand is referred to as the ability to do work and examples include potential energy, kinetic energy, mechanical energy etc.

Energy can neither be created nor destroyed but can be converted from one form or type to another. it also have various types which are mentioned in the previous paragraph.

It is not always fully contained as a result of other factors which influences its presence because some are lost to heat energy while some percentage is used for the metabolism in organisms.

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The options are:

Answer:

Tension

Explanation:

Answer:

The temperature rises because for a given volume of gas, a rise pressure of the gas in pressure results in a proportionate rise in the temperature of the gas

Similarly when the handle is raised to draw air causes a fall in pressure that results in proportionate fall in temperature, for a given volume of gas

Explanation:

From Gay-Lussac's law, states that the pressure of a given mass of gas is directly proportional to its Kelvin temperature, provided that the volume is held constant

Mathematically, the law states that Pressure ∝  Temperature, at constant Volume

Therefore;

P₁/T₁ = P₂/T₂

Similarly, by kinetic theory of gases, we have;

The

\(P = \dfrac{n \cdot MW \cdot v_{rms}^2}{3 \cdot V}\)

\(v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }\)

Therefore, as in order for the hand pump to inflate the bicycle tires, the air in the pump has to be compressed to force it into the tire, thereby increasing the pressure, of the air in a given volume of the pump which results in the raising of the temperature of the air in the pump, which raises the temperature of the wall of the pump.

The temperature of the air in the pump also falls as the pressure in the pump is reduced by raising the pump handle, to reduce the air pressure inside the pump and and allow air to be taken into the pump.

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

The acceleration of the bicyclist on the hill is 1.32 m/s².

The acceleration of the bicyclist on the hill is calculated by applying the following kinematic equation as shown below.

vf² = vi² + 2ah

where;

make a the subject of the formula and solve for the acceleration;

2ah = vf² - vi²

a = (vf² - vi²) / (2h)

a = (15.9² - 2.59²) / (2 x 46.6)

a = 1.32 m/s²

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The following statement is not a scientific hypothesis:

C. Halle Berry is attractive.

A scientific hypothesis is a proposed explanation for an observation or pattern in nature that can be tested through further investigation and experimentation. It should be testable, falsifiable, and based on evidence.

Neon atoms emit red light. This is a scientific hypothesis that can be tested and confirmed by looking at the spectrum of light emitted by neon atoms.

B. There is an attractive force between the earth and moon. This is a scientific hypothesis that can be tested and confirmed by measuring the force of gravity between the earth and moon.

D. Summer days are the hottest of the year. This is a scientific hypothesis that can be tested and confirmed by collecting temperature data during the summer months.

E. The sky is blue. This is a scientific hypothesis that can be tested and confirmed by observing the sky under different atmospheric conditions.

The statement "Halle Berry is attractive" is a subjective opinion that cannot be tested or confirmed through scientific investigation, hence it is not a scientific hypothesis. Attractiveness, as a concept, can vary widely based on personal, cultural, and social factors.

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The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

On Mars:

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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We multiply the magnitude of the vector even by the cosine angle referenced towards the horizontal. The horizontal force defines as the force exerted inside a direction parallel to the horizon. Acceleration is merely the rate during which velocity changes. As a result, the magnitude indicates how rapidly velocity varies, and the further calculation can be defined as follows:

For option a:

\(\to F_{foot}= 13 \ N\\\\\to m_1= 64 \ kg\\\\\to m_2=2.9 \ kg\\\\\)

Please find the graph for the direction:

\(\to |F_{ground}|= |F_{foot}| \\\\ \to F_{ground}= -F_{foot}= - 13 \ N\\\\\)

For option b:  

\(F_{ground}=(m_1+m_2)a\\\\a=\frac{F_{ground}}{m_1+m_2}\\\\\)

For option c:  

\(\bold{a=\frac{13}{64+2.9}}\\\\\)

  \(\bold{=\frac{13}{66.9}}\\\\\bold{=0.194 \ \frac{m}{s^2}}\\\\\)

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Answer:

right

Explanation: