The magnitude of the force that the object exerts on the child is 100 N.
option C is the correct answer.
What is Newton's third law of motion?
Newton's third law of motion states that for every action there is an equal and opposite reaction. In other words, action and reaction are equal and opposite.
Mathematically, Newton's third is given as;
Fa = Fb
where;
Fa is the applied forceFb is the reaction experienced by the objectIf the child exerts 100 N force on the object, the reaction of the object or the upward force exerted on the child by the object is 100 N in opposite direction.
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Which space rock is easiest to study and what do we typically learn from
them?
explore how archemides principle is applied in building a ship and submarine
Answer:
Principle Archimedes is applied in building a ship and submarine using the manipulating that buoyancy, is controlled the ballast tank system.
Explanation:
Submarine is rather had they focused on main parts of the submarine,he is complex and long process implementation,the most submarine design like submarine stability.
Submarine stability is complete and the fundamental Archimedes principle to arrive the weight of submarine is equal to buoyancy force.
Submarine into the parts and components of ballast tank the sequence in diving and surfacing,there two vital parts:- flood parts and air vents
flood parts:- at the bottom position and allow water to enter or leave that tank.
air vents:- air vents at the top of the pressure hall,and that they submarine dive.
this time submarine is most modern system is depth is 300 to 450 meters,high pressure air is 15 bar is tank air valve.
submarine is basic of the effective volume of all the submarine surfaced condition,submarine minus to the free water flood is equal to the fully pressure hull,submarine is the surfaced condition.
Find the direction of the sum of
these two vectors:
3.14 m,
30.0°
60.0°
2.71 m
The magnitude of the resultant vector is 4.14m and the direction is 50°.
What is the magnitude of the forces?The resultant magnitude of the vector is the sum of the algebraic forces acting at the point.
The magnitude of the resultant vector, F is calculated below:
\(F = \sqrt{3.14^{2} + 2.71^{2}} = 4.14m\)
The direction is given below as follows:
\(x = tan^{-1} × \frac{3.14}{2.71} = 50\)
Therefore, the magnitude of the resultant vector is 4.14m and the direction is 50°.
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How many force vectors would be shown on a free-body diagram of an elevator suspended by a cable descending at constant velocity.?
There would be a total of 2 force vectors on a free-body diagram of an elevator suspended by a cable descending at constant velocity.
What is a free-body diagram?FBDs are valuable tools for describing the relative magnitude and direction of all forces operating on an object in a given condition. The meticulous drafting of a free-body diagram is the initial step in evaluating and describing most physical processes. In a free-body diagram, the size of the arrow denotes the magnitude of the force while the direction of the arrow denotes the direction in which the force acts.
A free-body diagram often includes the following elements:
A streamlined form of the body (most commonly a box)A system of coordinatesForces are depicted as arrows indicating the direction in which they act on the body.Moments are depicted as curving arrows pointing in the direction in which they affect the body.The quantity of forces acting on a body is determined by the nature of the problem and the assumptions made. Air resistance and friction are frequently overlooked.
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What happens when a star can no longer fuse hydrogen to helium in its core?
-the core cools off
-the core shrinks and heats up
-the core expands and heats up
-helium fusion immediately begins
When a star can no longer fuse hydrogen to helium in its core, the core shrinks and heats up. This is because the core is no longer able to generate enough energy through hydrogen fusion to support its own weight against the force of gravity. So the correct option is B .
As a result, the core contracts and becomes denser, which causes an increase in temperature and pressure. This increased temperature and pressure eventually become high enough to ignite hydrogen fusion in a shell surrounding the core, and the star begins to expand and brighten. This phase of a star's life is called the subgiant or red giant branch, depending on its initial mass. Helium fusion does not begin until the core temperature and pressure are high enough to fuse helium, which occurs later in the star's evolution.
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What is the atomic mass of N2-
Answer: 28.0134 g/mol
Explanation:
For a molecule (for example, nitrogen, N2) the mass of molecule is the sum of the atomic masses of the two nitrogen atoms. For nitrogen, the mass of the N2 molecule is simply (14.01 + 14.01) = 28.02 amu.
Question 11 of 30A satellite with a mass of 100 kg fires its engines to increase velocity, therebyincreasing the size of its orbit about Earth. As a result, it moves from acircular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What isthe approximate change in gravitational force from Earth as a result of thischange in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kgand G = 6.67 x 10- 11 N·m2/kg)O A. -8NB. -36 NC. -24 ND. -16 NSUBMIT
Given:
The mass of the satellite is m = 100 kg
The radius of the lower orbit is
\(R_l=\text{ 7.5}\times10^6\text{ m}\)The radius of the higher orbit is
\(R_h=7.7\times10^6\text{ m}\)The mass of the earth is
\(M\text{ = 5.97}\times10^{24}\text{ kg}\)The universal gravitational constant is
\(G\text{ = 6.67}\times10^{-11}\text{ Nm}^2\text{ /kg}^2\)To find the approximate change in gravitational force.
Explanation:
The gravitational force due to the lower orbit is
\(\begin{gathered} F_l=\frac{GMm}{(R_l)^2} \\ =\frac{6.67\times10^{-11}\times5.97\times10^{24}\times100}{(7.5\times10^6)^2} \\ =\text{ 707.9 N} \end{gathered}\)\(\begin{gathered} F_l=\frac{GMm}{(R_l)^2} \\ =\frac{6.67\times10^{-11}\times5.97\times10^{24}\times100}{(7.5\times10^6)^2} \\ =\text{ 707.9 N} \end{gathered}\)\(\begin{gathered} F_l=\frac{GMm}{(R_l)^2} \\ =\frac{6.67\times10^{-11}\times5.97\times10^{24}\times100}{(7.5\times10^6)^2} \\ \approx\text{ 707.9 N} \end{gathered}\)The gravitational force due to the higher orbit is
\(\begin{gathered} F_h=\frac{GMm}{(R_h)^2} \\ \approx671.61\text{ N} \end{gathered}\)The approximate change in gravitational force is
\(\begin{gathered} \Delta F=F_h-F_l \\ =671.61-707.9 \\ =-36.29\text{ N} \end{gathered}\)The approximate change in gravitational force is 36.29 N
the gazelle travels 2 km in a half hour.The gazelle's average speed is:
1/2 kmh
1km/h
4km/h
Answer:
distance =2km
time =1/2hour
speed =distance /time =2/1/2=4km/h
The average speed of the gazelle is equal to 4 Km/h. Therefore, option (C) is correct.
What is the average speed?The average speed can be defined as the total distance traveled in a fixed interval of time. It can be determined by dividing the total distance traveled by the total time.
The average velocity of the object is a single value if the object moves uniformly, it will travel the same distance in the same interval of time.
The mathematical expression for the average speed is as follows:
The average speed = Total distance covered/Total time taken
Given, the distance traveled by gazelle = 2 Km
The time taken by the gazelle to travel this distance = 1/2 hr = 0.5 hr
The average speed = 2Km/ 0.5 hr = 4 Km/hr
Therefore, the gazelle's average speed is equal to 4 Km/hr.
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What might be some explanations for Earth's apparent
"luck" in not being hit by more space debris?
The International Space Station moves about once a year to get out of the way of dangerous debris. Critical parts of the station can withstand impact of objects as large as 1 cm, according to NASA. The agency didn't specify the size of the Cosmos 1408 fragment that posed a danger.
Take my pointssssss please
Answer:
thanksssssssssssssssssssss
Answer:
thank yoooooooooooooooooooooooooooooooooooooooooooooouuuuuuuuuuuuuuu
Explanation:
Scenarios that demonstrate the Motion of objects in Space! PLEASEEEE!!!!
There are several objects that move in space.
What are the Scenarios that demonstrate the Motion of objects in Space?There are many scenarios that demonstrate the motion of objects in space. Here are some examples:
Planetary motion: The motion of planets in the solar system is a classic example of objects in space in motion. The planets orbit around the sun in elliptical paths, with their motion governed by the gravitational pull of the sun.
Satellites: Satellites are artificial objects that are launched into space to perform various tasks, such as communication, navigation, and weather monitoring. The motion of satellites is determined by the gravitational forces of the Earth and other celestial bodies.
Asteroids and comets: Asteroids and comets are small, rocky or icy objects that orbit the sun. Their motion is also governed by the gravitational forces of the sun and other celestial bodies, and their orbits can be highly elliptical.
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help please
A vector in the xy plane has components \( -14.0 \) units in the \( x \)-direction and 5 units in the \( y \)-direction. (a) What is the magnitude of the vector?
The magnitude of the vector with components -14.0 units in the x-direction and 5 units in the y-direction can be calculated using the Pythagorean theorem.
The magnitude of a vector represents its length or size. In the xy plane, the magnitude of a vector with components in the x-direction (horizontal) and y-direction (vertical) can be found using the Pythagorean theorem. The theorem states that the square of the magnitude of a vector is equal to the sum of the squares of its components.
For the given vector with components -14.0 units in the x-direction and 5 units in the y-direction, we can calculate its magnitude as follows:
Magnitude = sqrt(\(14^{2} } +5^{2}\))
Magnitude = sqrt(196 + 25)
Magnitude = sqrt(221)
Magnitude ≈ 14.87 units
Therefore, the magnitude of the vector is approximately 14.87 units. This represents the length or size of the vector in the xy plane, taking into account its components in the x and y directions.
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A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s^2. The friction experienced by the swimmer is 100 N. How many N of force does the swimmer applies a force of
Answer:
490N
Explanation:
According Newton's second law!
\sum Force = mass × acceleration
Fm - Ff = ma
Fm is the moving force
Ff s the frictional force = 100N
mass = 65kg
acceleration = 6m/s²
Required
Moving force Fm
Substitute the given force into thr expression and get Fm
Fm -100 = 65(6)
Fm -100 = 390
Fm = 390+100
Fm = 490N
Hence the force that will cause two cart to move is 490N
The force the swimmer applied when he pushes on the pool wall is 490 N.
The given parameters;
mass of the swimmer, m = 65 kgacceleration of the swimmer, a = 6 m/s²frictional force experienced by the swimmer, Fk = 100 NThe force applied by the swimmer is calculated by applying Newton's second law of motion as shown below;
F = ma
∑F = 0
F - Fk = ma
F = Fk + ma
F = 100 + (65 x 6)
F = 490 N
Thus, the force the swimmer applied when he pushes on the pool wall is 490 N.
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Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at the various marked positions along the roller coaster track below: KE= ME PER KE PE=20 000J KE=25 000J PE= mgh PE=_ KE= KE KE=OJ PE-7 500J PE=5 000J PE- D Ε. Voc KE=/m 12 KE- PEN KE=_ PE=__ KE=40 000J PE=OJ What is the total mechanical energy of the roller coaster throughout the ride? Explain how you determined ME.
Answer:
Part A
1) At the starting point, we have;
PE = 40,000 J
2) PE = 0 J, KE = 40,000 J
3) KE = 20,000 J
4) PE = 15,000 J
5) KE = 32,500 J
6) KE = 40,000 J, PE = 0 J
7) KE = 35,000 J
8) KE = 40,000 J, PE = 0 J
Part B
The total Mechanical Energy = ME = 40,000 J
At the final point, we have;
ME = KE + PE = 40,000 J + 0 J = 40,000 J
Explanation:
Part A
By the law of conservation of energy, we have;
ME = PE + KE
Where;
ME = The total Mechanical Energy of the system
PE = The Potential Energy of the system
KE = The Kinetic Energy of the system
Where there is no friction, we have;
At the final stage, KE = 40,000 J. PE = 0 J
Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J
1) At the starting point, we have;
KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J
2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;
PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J
3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J
4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J
5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J
6) At the bottom KE = 40,000 J, PE = 0 J
7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J
8) KE = 40,000 J, PE = 0 J
Part B
The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;
ME = KE + PE
At the final point, we have;
ME = 40,000 J + 0 J = 40,000 J
The total Mechanical Energy = ME = 40,000 J
What is the electric potential 3. 0×10−11 m from a proton (charge +e )? Let V=0 at r=[infinity]
This question involves the concepts of electric potential, charge, and distance.
The electric potential is "48 V".
ELECTRIC POTENTIALThe electric potential of a point in the vicinity of a charge is given by the following formula:
\(V=\frac{kq}{r}\)
where,
V = electric potential = ?k = Colomb's constant = 9 x 10⁹ N.m²/C²q = magnitude of charge = 1.6 x 10⁻¹⁹ Cr = distance from charge = 3 x 10⁻¹¹ mTherefore,
\(V = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1.6\ x\ 10^{-19}\ C)}{3\ x\ 10^{-11}\ m}\)
V = 48 volts
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A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s² until it stops. What distance does the train travel while slowing down?
A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s² until it stops the distance does the train travel while slowing down are 4430.75 m.
What is distance?Distance measures length. For example, the gap of a street is how lengthy the street is. In the metric gadget of size, the maximum not unusualplace devices of distance are millimeters, centimeters, meters, and kilometers.
It takes 24/.065 = 369.23 sec to slow down to zero.In that point it travels s = half of at^2 = half of (.065)(369.23^2) = 4430.75m.Read more about distance:
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01
Question 4
What is an atom's nucleus made of?
X a. protons only
b. only neutrons
c. electrons and protons
d. protons and neutrons
Answer:
D i think
Explanation:
dont need a explanation it's just D
. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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Dos personas aplican sendas fuerzas de 50N sobre una mesa, en direcciones horizontales perpendiculares entre sí. ¿Cuanto vale el módulo e la resultante de estas dos fuerzas? Ilustra tu respuesta con un dibujo.
Answer:
|Fr| = 50*√2 [N]
Explanation: (See Annex )
En el diagrama de cuerpo libre ( mostrado en el anexo) se ve que, al ser las dos fuerzas iguales (50 N) el paralelogramo formado para encontrar la resultante de las fuerzas (Fr) es un cuadrado, y la diagonal de ese cuadrado ( que es al mismo tiempo la hipotenusa del triangulo recto OPA ) es igual a:
Hipotenusa = |Fr| = √ (50)² + (50)²
|Fr| = √2* (50)²
|Fr| = 50*√2 [N]
Each color that we see corresponds to a different _____ of light.
a. speed
b. phase
c. amplitude
d. wavelength
Answer:
D wavelength
Explanation:
The different wavelengths determine the color.
Question 1. Change in the shape or volume of rocks is
Group of answer choices Faulting Stress Folding Deformation
2.
Stress is ________ . Strain is ________ .
Group of answer choices
The deformation;
1) Change in the shape or volume of rocks is Deformation
2) Stress is the deforming force. Strain is the deformation.
What is the change called?
Deformation is the term denoting a change in a rock's volume or shape. Geological processes including tectonic forces, compression, tension, and shearing are just a few that can cause it. Rocks may fold, fault, or fracture as a result of deformation, resulting in the production of geological features as mountains, valleys, and fault lines.
Stress is the term used to describe the internal pressure or force that external pressures apply to a material. It is the force acting on the substance per unit area. The distortion that takes place in a material when it is stressed is measured by strain.
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What are the latitude and longitude coordinates for Location C? 1) 50N, 68S 2) 50N, 68W 3) 50S, 68E 4) 50S, 68W Which is farther- the distance between Location B and the Equator or the distance between Location C and the Equator? 1) Location B and the Equator 2) Location C and the Equator 3) Locations B and C are the same distance from the Equator 4) Cannot discern from the information provided
The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.
Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.
However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.
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how to find upper force and normal force of a rod physics
Answer:
When you lift only one end of the 5 m uniform rod you are effectively raising its center of mass located at its geometric center. The center of mass of this uniform rod is at the 2.5 m point. So instead of using the full weight of 10 N weight the needed force is only one-half of the weight which is 5 newtons.
The work done by lifting the full rod to a height of h is
weight * h = 10 N * h but in this condition h is only 1/2 * h so the work done is one-half of the work. 1/2 * weight * h = 1/2 * 10 N * h
Work done = 5 N * h which makes the force needed equal to 5 newtons
If you put something like a piece of cardboard between a magnet and an iron nail, the magnet still holds the nail in place, even though the magnet is not touching the nail.
Explain how that happens.
Answer:
Hiiii
Explanation:
Helllooooooo
Solids in which the atoms have no particular order or pattern are called
Answer:
Amorphous solids are composed of atoms or molecules that are in no particular order. Each particle is in a particular spot, but the particles are in no organized pattern. Examples include rubber and wax. Crystalline solids have a very orderly, three-dimensional arrangement of atoms or molecules
Explanation:
describe a situation when you might travel a high velocity but with low acceleration
What is the range on the pH scale for strong bases (extreme delay basics ) ?
Answer:
Bases are present to the right of the pH scale after the value of 7 which is the neutral state (example: pure water). Bases go up from 8 to 14. The strong bases are usually from 11 - 14 (example: conc. NaOH).
Which of these is true for both natural and artificial selection?
A. They both occur randomly and spontaneously.
B. They both involve the extinction of unfit species.
C. They both result in the enrichment of certain alleles over others.
D. They both require human involvement to choose the most desirable traits
Answer:
c is answer
Explanation:
Humans allow only organisms with favorable traits to reproduce. Is this true of natural selection, artificial selection or both? Competition for resources determines reproductive success.
If a ceramic cup is placed on top of a lit franklin stove, it will gradually heat up. what is the mode of heat transfer from the stove to the ceramic cup?
The mode of heat transfer from the stove to the ceramic cup is conduction.
Conduction can be described as the process by which heat energy is transmitted through collisions between neighboring atoms or molecules and resulting in the transfer of heat from the hotter end to the colder end.
For conduction to take place, it is necessary that the particles are in contact with each other.
Therefore; when the ceramic cup is placed on top of a lit franklin stove, the particles are in contact with each other resulting in the transfer of heat energy from the stove to the ceramic cup due to collisions between the particles resulting in the heating of the ceramic cup.
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Which vehicle will have more kinetic energy, a parked
semitruck or a car moving at 50 km/h?
Answer:
a semi truck
Explanation: