Answers
Refer to the photo attached. Let me know if it works out for you :)
Answer: 787 m/s & 0.0589s
Related Questions
How long has tension been building in the cascadia fault zone
Answers
Answer:
The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.
Explanation:
At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .
PLEASE HELP QUICK! i don’t know this one
Answers
Designed and developed by private companies: Commercial satellite.
Used to access electronic intelligence: Reconnaissance satellite.
Used to make strategic decisions in advance: Early warning satellite.
Used to assist in strike planning: Reconnaissance satellite.
Remote sensing: Commercial satellite.
How to explain the informationCommercial Satellite are designed and developed by private companies and are primarily used for commercial purposes. They can provide a wide range of services, including telecommunications, broadcasting, internet connectivity, and navigation. Commercial satellites are often operated by companies like SpaceX, OneWeb, or Iridium.
Reconnaissance satellites are used to gather information about a specific area or target. They are equipped with advanced imaging systems, such as high-resolution cameras or synthetic aperture radar (SAR), which allow them to capture detailed images or collect other types of data for military or intelligence purposes.
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The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather than an approximately constant value for the coefficient of volume expansion, the value for water changes drastically, as illustrated in the figure.
Below what temperature T
does water shrink when heated?
If the temperature of water at 30 ∘C
is raised by 1 ∘C
, the water will expand. At approximately what initial temperature T
will water expand by twice as much when raised by 1 ∘C
?
Answers
(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.
The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.
To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,
β = (1/V) (dV/dT)
where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.
At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.
Therefore, water will shrink when heated above 4°C.
To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:
β = (1/V) (dV/dT)
We want to find the initial temperature T such that
(dV/dT)T = 2 (dV/dT)30
where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.
Using the coefficient of volume expansion for water, we have
β = 3α
where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write
(dV/dT) = V × 3α
Substituting this into the equation above and simplifying, we get
T = 30 + 10/3 = 33.3°C
Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.
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Jeff was riding in a car with a textbook sitting on the seat beside him. When would the textbook demonstrate the GREATEST effect of inertia?
А
When the car makes a sudden stop,
B
When the car changes into another lane.
С
When the car slows down gradually.
D
When the car runs out of gas and rolls to a stop
Answers
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer distance
Please show working
Answers
Distance = (speed) x (time)
Car A: Distance = (8 m/s) x (43 s) = 344 meters
Car B: Distance = (7 m/s) x (50 s) = 350 meters
350 meters is a longer distance than 344 meters.
Car-B traveled a longer distance than Car-A did.
Answer:
\(\boxed {\boxed {\sf Car \ B : 350 \ meters }}\)
Explanation:
Distance is equal to the product of speed and time.
\(d=s*t\)
1. Car A
Car A has a speed of 8 meters per second and travels for 43 seconds.
\(s= 8 \ m/s \\t= 43 \ s\)
Substitute the values into the formula.
\(d= 8 \ m/s *43 \ s\)
Multiply and note that the seconds will cancel out.
\(d= 8 \ m*43= 344 \ m\)
2. Car B
Car B has a speed of 7 meters per second and travels for 50 seconds.
\(s= 7 \ m/s \\t= 50 \ s\)
Substitute the values in and multiply.
\(d= 7 \ m/s * 50 \ s\)
\(d= 7 \ m * 50 = 350 \ m\)
350 meters is a longer distance than 344 meters, so Car B traveled the longer distance.
A boat moves up and down as water waves pass under the boat. If the amplitude of the wave gets bigger, then
A)
the boat will rise up higher.
B)
the boat will not rise up as high.
C)
the boat will go up and down more often.
D)
the boat will continue to move the same way.
Answers
Answer: The Boat will rise
Explanation: Because high amplitude means high in heights.
what determines the size of a launch window? answer specifically and detail.
Answers
Explanation:
The size of a launch window is determined by a variety of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched.
One of the most important factors is the position of the launch site relative to the desired orbit. The launch site must be positioned in such a way that the rocket can achieve the required velocity and trajectory to reach the desired orbit. The angle and speed at which the rocket is launched are also crucial, as they affect the amount of fuel required and the trajectory of the rocket.
The position of the destination is another factor that affects the size of the launch window. For example, if the spacecraft is bound for a planet that is moving in its orbit, the launch window must be adjusted to account for the changing position of the planet.
In addition, the characteristics of the spacecraft being launched, such as its size, weight, and propulsion system, can also affect the size of the launch window. A larger spacecraft may require more fuel and a longer burn time, which may limit the available launch window.
Overall, the size of a launch window is determined by a complex set of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched. Launch planners use sophisticated computer models and simulations to calculate the optimal launch window based on these factors.
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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difference between rest and motion
Answers
motion - it is the state in which body moves from it’s place
Three identical charges QC, are placed in the vertices of a equilateral triangle of sides 10cm long calculate the force on each charge
Answers
The electric force acting on any of the given charges is Q × 1.8 × 10¹² Newton.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. One of the many forces that affect objects is the electric force.
the vertices of a equilateral triangle of sides 10cm long .
The electric force acting on any of the given charges is = 2k(Q/(0.1)²) cos60°
= 2 × 9 × 10⁹ × Q × 100
= Q × 1.8 × 10¹² Newton.
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please help me fast
_________ are the smallest plant, visible to our eyes .
Answers
I think I know that is the smallest flowering plant, but I don’t know about just the smallest plant.
If the horizontal range and the max height of a body projected at an angle titre to the horizontal is K and Q respectively. Show that the muzzle velocity Vo is given by: Vo=√[2gQ + K²/8Q]
Answers
Explanation:
Recall that
\(K = \dfrac{v_0^2\sin2\theta}{g}\:\:\:\:\:\:\:\:\:(1)\)
and
\(Q = \dfrac{v_0^2\sin^2\theta}{2g}\:\:\:\:\:\:\:\:\:(2)\)
From Eqn(2), we can write
\(\sin\theta = \sqrt{\dfrac{2gQ}{v_0^2}}\:\:\:\:\:\:\:\:\:(3)\)
Using the identity \(\sin\theta = 2\sin\theta \cos\theta\), we can rewrite Eqn(1) as
\(\dfrac{gK}{2v_0^2} = \sin\theta \cos\theta\)
Squaring the above equation, we get
\(\dfrac{g^2K^2}{4v_0^4} = \sin^2\theta \cos^2\theta\)
\(\:\:\:\:\:\:\:\:\:=\sin^2\theta(1 - \sin^2\theta)\:\:\:\:\:\:\:(4)\)
Use Eqn(3) on Eqn(4) and we will get the following:
\(\dfrac{g^2K^2}{4v_0^4} = \dfrac{2gQ}{v_0^2}(1 - \dfrac{2gQ}{v_0^2})\)
This simplifies to
\(\dfrac{gK^2}{8v_0^2Q} = 1 - \dfrac{2gQ}{v_0^2}\)
Rearranging this further, we get
\(1 = \dfrac{2gQ}{v_0^2} + \dfrac{gK^2}{8v_0^2Q}\)
Putting \(v_0^2\) to the left side, we get
\(v_0^2 = 2qQ + \dfrac{gK^2}{8Q}\)
Finally, taking the square root of the equation above, we get the expression for the muzzle velocity \(v_0\) as
\(v_0 = \sqrt{2gQ + \dfrac{gK^2}{8Q}}\)
Explain how a balloon is able to keep its shape?
Answers
Answer:
It depends on how they are made.
Explanation:
Rubber balloons are not always spherical in shape. When filled with air, the inflation forms a balance between the balloon material, including its shape and thickness and its elasticity and the pressure of the air. That’s what determines its shape. Although a sphere is often the shape, it could be tubular, offset, and most other shapes.
What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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A steam catapult applies a very large force to supplement the engine thrust of a jet fighter as it takes off from an
aircraft carrier. The jet has a mass of 4000 kg and must reach its take off speed of 70 m/s at the end of the 220
m flight deck. What is the combined force of the catapult and engines? (Use the work-energy theorem)
Answers
Answer:
The combined force of the catapult and engines is 44545.455 newtons.
Explanation:
Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:
\(K_{1}+W_{1\rightarrow 2} = K_{2}\) (1)
Where:
\(K_{1}\), \(K_{2}\) - Initial and final translational kinetic energies of the jet fighter, measured in joules.
\(W_{1\rightarrow 2}\) - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.
By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:
\(F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})\)
\(F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}\) (2)
Where:
\(F\) - Combined force of the catapult and engines, measured in newtons.
\(m\) - Mass of the jet fighter, measured in kilograms.
\(\Delta s\) - Length of the catapult, measured in meters.
\(v_{1}\), \(v_{2}\) - Initial and final speeds of the jet aircraft, measured in meters per second.
If we know that \(m = 4000\,kg\), \(v_{1} = 0\,\frac{m}{s}\), \(v_{2} = 70\,\frac{m}{s}\) and \(\Delta s = 220\,m\), then the combined force of the catapult and engines is:
\(F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}\)
\(F = 44545.455\,N\)
The combined force of the catapult and engines is 44545.455 newtons.
The combined force of the catapult and engines is 44,545.5 N.
The given parameters;
mass of the jet, = 4000 kgspeed of the jet, v = 70 m/slength of the deck, d = 220 mThe combined force of the catapult and engines is determined by applying work energy theorem as shown below;
\(W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N\)
Thus, the combined force of the catapult and engines is 44,545.5 N.
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Given the following nuclear reaction:
224/88 Ra → 4/2 He + A/Z X
Answers
(1) The atomic mass of the new atom is 220.
(2) The atomic number of the new atom is 86
(3) The symbol of the new atom is Rn
(4) The type of decay demonstrated is alpha decay.
What is nuclear reaction?
Nuclear Reactions are processes in which one or more nuclides are produced from a collision between two nuclei or one nucleus and a subatomic particle.
Alpha decay occurs in the nuclei of heavy elements, like radium, uranium, thorium.
When a nucleus of Ra (radium) decays, it emits an alpha particle and becomes an Rn (radon) nucleus.
The nuclear reaction equation is given as;
\(^{224}_{88}Ra ----- > ^4_2He \ +\ ^A_ZX\)
where;
X is the new atom formedA is the atomic mass of the new atomZ is the atomic number of the new atomThe atomic number of the new atom is calculated as;
Z = 88 - 2 = 86
The atomic mass of the new atom is calculated as;
A = 224 - 4 = 220
An atom corresponding to atomic number of 86 = radon
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The image below shows sound waves traveling through air.
Which point is the source of the sound?
Answers
The point on the image that is the source of the sound / sound waves travelling would be B. 2.
Where do sound waves originate ?When a sound is produced, such as a musical note or spoken word, it initiates a disturbance at the source, which sets the surrounding particles in motion. As these particles oscillate back and forth, they generate regions of compression and rarefaction, resulting in the formation of longitudinal waves.
The propagation of sound waves emanates from a central source, radiating outward in a spherical pattern, thereby creating an expanding wavefront. This fundamental principle of wave behavior stems from the point-source nature of sound waves, wherein they originate from a central locus and disperse in all directions.
This central source in the image is 2.
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Why is the earth Round
Answers
Answer:
because it has gravity in it . as it has more mass which can attract the things like we human are also attracted towards its centre and also mass is directly proportional to gravity which leads it to be round in shape.
hope u will get it..
Answer:
its round because of gravity
Explanation:
why is a mountain ? what is a animal ? what is love ?
Answers
Answer:
When we love someone we experience the same positive thoughts and experiences as when we like a person. But we also experience a deep sense of care and commitment towards that person. Being “in love” includes all the above but also involves feelings of sexual arousal and attraction.
Explanation:
Which one the answer to this question
Answers
Consider an electron confined in a region of nuclear dimensions (about 5 fm). Find its minimumpossible kinetic energy in MeV. Treat this problem as one-dimensional, and use the relativistic relationbetweenEandp. Give your answer to 2 significant figures. (The large value you will find is a strongargument against the presence of electrons inside nuclei, since no known mechanism could contain anelectron with this much energy.)
Answers
Answer:
39.40 MeV
Explanation:
Determine the minimum possible Kinetic energy
width of region = 5 fm
From Heisenberg's uncertainty relation below
ΔxΔp ≥ h/2 , where : 2Δx = 5fm , Δpc = hc/2Δx = 39.4 MeV
when we apply this values using the relativistic energy-momentum relation
E^2 = ( mc^2)^2 + ( pc )^2 = 39.4 MeV ( right answer ) because the energy grows quadratically in nonrelativistic approximation,
Also in a nuclear confinement ( E, P >> mc )
while The large value will portray a Non-relativistic limit as calculated below
K = h^2 / 2ma^2 = 1.52 GeV
A cyclist and his bicycle have a combined mass of 85 kg. If he is moving at
12 m/s, how much KE does he have?
Your nour
Answers
Answer:
211.2 kg:m/s
Explanation:
Mark brainily
Please help! This is due in 10 minutes
Answers
Answer:
Atom - the basic particle of matter
Density - calculated from measurements of mass and volume
Motion - calculated from measurements of distance and time
Energy - can change form and move matter
Matter - the scientific word for stuff
Hope this helps! Please mark brainliest if correct :D
Which layer of the atmosphere is most likely to protect life on Earth from ultraviolet radiation
Answers
Answer:
ozone layer
Explanation:
The ozone layer forms a thin shield in the upper atmosphere protecting life on earth from UV rays. Ozone is a naturally occurring gas that is found in two layers of the atmosphere
What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Answers
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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Helppppppppppppppppppppppppppppp
Answers
Answer:
Option #3 is your answer.
Explanation:
Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity
Answers
Answer:
Explanation:
The horizontal velocity is 1.61.
Calculate the power developed by a 68.0 kg athlete who, in 20.0 seconds. runs up stairs that have a vertical height of 8.00 m
Answers
Potential energy:-
mgh68(8)(10)680(8)5440JNow
time=t=20sSo
Power:-
PE/t5440/20272Wplease help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.
Row 1: Plate Boundary (Movement)
Write the type of plate boundary: convergent, divergent, transform.
Write the correct description for each in parentheses below the name: sliding, separating, or colliding.
Row 2: Diagram
Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.
Row 3: Lithosphere (Created or Destroyed)
Identify whether the Earth's crust is created or destroyed at this type of plate boundary.
Row 4: Geologic Process
Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.
Row 5: Real World Example
Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.
Row 6: References
This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.
Answers
Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.
Here are the steps to be followed:
Step 1: Understanding the Assignment Requirements
Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.
Step 2: Research
Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.
Step 3: Worksheet Setup
Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.
Step 4: Fill in Row 1 - Plate Boundary (Movement)
In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.
Step 5: Fill in Row 2 - Diagram
In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.
Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)
In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.
Step 7: Fill in Row 4 - Geologic Process
In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.
Step 8: Fill in Row 5 - Real World Example
In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.
Step 9: Fill in Row 6 - References
In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.
Step 10: Review and Proofread
Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.
Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.
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A light block of mass (m) and a heavy block of mass (M) are attached to the ends of a rope. A student holds the heavier block and lets the lighter block hang below it. Then she lets go. Air resistance can be neglected.
a. what is the tension in the rope while the blocks are falling, before either hits the ground?
b.would your answer be different if she had been holding the lighter block initially?
Answers
The tension in the rope while the blocks are falling, before either hits the ground is zero and it would be the same even if she had been holding the lighter block initially.
Given the mass of light block = m
The mass of heavy block = M
acceleration due to gravity = g
Let the tension in the rope be T
From Newtons second law of motion we know that F = ma where a is acceleration of the system.
In that situation, gravity is the sole external force that is important to us. Fnet = Fg = m(sys)a
The total mass of system = m+M. Then
(m+M)g = (m+M)a
Therefore, the blocks must be falling with the acceleration of free fall at a = g. Here, the lighter system is fastened to a heavy block. Gravity pulls it lower as it falls, so any strain would be upward.
Fnet = Fg - T = ma where m is the mass of the lighter block.
mg - T = ma. This is only accurate if T = 0. The string is therefore not under any tension.
Hence the tension will not change even if the order of blocks is reversed.
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