Answer:
122.5m
Explanation:
Δy=1/2gt^2
1/2(9.8*5^2)= 122.5
*this does not take into account direction or friction forces such as air resistance*
Sandy wants to know whether an item dropped into a fluid will sink or float. What is true for any item that floats?
A.
The force of gravity is equal to the force of mass.
B.
The force of gravity is stronger than the buoyant force.
C.
The buoyant force is stronger than the force of gravity.
D.
The object has no density.
Answer:
A, I think but I'm sureExplanation:
ur welcomeee ♥️♥️
Answer: C.
The buoyant force is stronger than the force of gravity.
Explanation:because I did it
An electric lamp is marked 100w 220v. What do you
understand by this? what current is taken by the lamp when it is connected to a 220v main supply. What is the resistance
of the lamp.
Answer:
The current is "\(\frac{5}{11} \ A\)" and resistance is "484 ohm".
Explanation:
The given values are:
Potential difference,
V = 220 v
Power,
P = 100 w
Now,
The current will be:
⇒ \(P=VI\)
On putting the values, we get
⇒ \(100=220\times I\)
⇒ \(I=\frac{100}{220}\)
⇒ \(= \frac{5}{11}\) A
then,
Resistance will be:
⇒ \(V=IR\)
⇒ \(220=\frac{5}{11}\times R\)
⇒ \(R=44\times 11\)
⇒ \(=484\) ohm
who was the first president of the united states
Answer:
George Washington
Explanation:
Answer:
well for me
Explanation:
It was George Washington
If a ball is rolling at a velocity of 1.5 m/s and has a momentum of 10.0 kg times m/s, what is the mass of the ball?
Answer:
Mass of the ball, M = 6.667 kg
Explanation:
Given data:
Momentum, Mo = 10.0 kgm/s
Velocity of the rolling ball, V = 1.5 m/s
Mass of the body, M = ?
Momentum, Mo = Mass, M x Velocity, V
10.0 kgm/s = M x 1.5 m/s
Divide each side by 1.5 m/s
M = 10.0 kgm/s / 1.5 m/s
M = (6⅔) kg
:. Mass of the ball, M = 6.667 kg
An elephant pushes with 2000 N on a load of trees. If it takes the elephant 45 seconds to move trees 15 meters, how much power did the elephant generate?
Answer:
Power generate by elephant = 666.67 W
Explanation:
Given:
Force = 2,000 N
Change in time = 45 Seconds
Distance = 15 meter
Find:
Power generate by elephant ?
Computation:
⇒ Work Done = Force × Distance
⇒ Work Done = 2,000 × 15
⇒ Work Done = 30,000
⇒ Power = Work Done / Time taken
⇒ Power generate by elephant = 30,000 / 45 seconds
⇒ Power generate by elephant = 666.67 W
A woman does 236 J of work
dragging her trash can 24. 4 m to
the curb, using a force of 18. 9 N.
At what angle was her force
directed?
(Unit = degrees)
According to the given statement is the 59.21° angle was her force directed.
What is a force?The word "force" has a specific meaning in science. At this level, calling a force a shove or a pull is entirely appropriate. A charge is not really something an object "has in it" or that it "contains." One thing experiences a force from another. Living organisms or inanimate objects are not the only things that can be considered forces. Every time two items interact, a force is exerted on every one of the objects. The force is no longer felt by the two objects when the interaction ends.
Briefing:Work done = force × distance
236J = 18.9cos(o) × 24.4
236/24.4 = 18.9cos(o)
(0.5117)cos^-1 = (o)
59.21°
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A proton is located at x = 1.0 nm, y=0 nm and an electron is located at x=0 nm, y=4.0 nm. Find the attractive Coulombic force between them.
The attractive Coulombic force between the proton and electron is approximately 2.3 x 10^-8 N.
To calculate this force, we can use Coulomb's law: F = (kq1q2)/r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between them. Plugging in the values, we get F = (9x10^9 Nm^2/C^2)(1.6x10^-19 C)*(-1.6x10^-19 C)/(4x10^-18 m^2) = -2.3x10^-8 N. The negative sign indicates that the force is attractive.
In summary, the attractive Coulombic force between the proton and electron is -2.3 x 10^-8 N, which is found using Coulomb's law and the charges and distances given in the problem.
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Distributive shock is the result of which of the following? - Pump failure - Poor vessel function - Low fluid volume - Rapid deoxygenation
Distributive shock is the result of poor vessel function.
Shock is a life-threatening medical condition that occurs when the body is not getting enough blood flow. Shock is a result of many underlying conditions that damage the circulatory system, decrease blood volume, or reduce the heart's pumping capacity. Distributive shock is one of the four types of shock.
Distributive shock is a type of shock that occurs as a result of poor blood vessel function. Distributive shock is characterized by a sudden drop in blood pressure, which results in a lack of oxygen and nutrients to vital organs and tissues.
The following three types of distributive shock are common:
Anaphylactic shockSeptic shockNeurogenic shockIn the body, the capillaries are responsible for delivering nutrients and oxygen to the cells while also removing waste materials. In distributive shock, the capillaries are dilated, causing blood to pool in the small veins and venules and leading to a sudden drop in blood pressure. This drop in blood pressure lowers oxygen and nutrient delivery to organs and tissues, resulting in organ failure, brain damage, and death.
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What would the velocity of an object be if it was on a 1.75m
rope and took 4 seconds to go around 2 revolutions?
Answer:
T = 4 sec / 2 = 2 sec period of revolution
S = 2 pi R = 2 * pi * 1.75 m = 11 m
V = S / T = 11 m / 2 sec = 5.5 m/s speed of object
Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities. Determine the radius of their circular path.
Answer:
r = 0.0548 m
Explanation:
Given that,
Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.
We need to find the radius of their circular path. The formula for the radius of path is given by :
\(r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}\)
m is mass of Singly charged uranium-238 ion, \(m=3.95\times 10^{-25}\ kg\)
q is charge
So,
\(r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m\)
So, the radius of their circular path is equal to 0.0548 m.
What is the difference between FIR AND IIR filter?
Digital filters are important in digital signal processing. FIR and IIR filters are two types of digital filters. The main difference between FIR and IIR filters is that FIR filters are known as non-recursive filters, while IIR filters are recursive filters. In this answer, we will explore more about the differences between FIR and IIR filters.
FIR Filters FIR stands for finite impulse response. FIR filters are also called non-recursive filters. In an FIR filter, the output depends only on the current input and the previous inputs. FIR filters are also known as moving average filters. FIR filters have a linear phase response, which makes them useful in audio and image processing. FIR filters have more stable responses compared to IIR filters, which means they are more predictable.
IIR filters are more efficient than FIR filters because they use feedback loops. IIR filters have nonlinear phase responses, which make them useful in signal processing and control systems. IIR filters are less stable than FIR filters, which means they are less predictable.
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which of these lists has all pure substances
a) milk water copper
b) gold oxygen nickel
c) tea sale concrete
d) orange juice with pulp silver soda water
Melissa tells her little brother that she has rice that can dance to music. melissa takes an aluminum pie pan and places a shallow layer of rice in the pan. she holds the pan of rice over a speaker on the radio and turns the radio volume up. the rice begins to dance and her little brother is amazed! she shares this during science class the next day. her teacher asks: "melissa, can you explain using the concept of sound waves what really happened to make the rice dance?
Melissa observed with the rice dancing is an interesting phenomenon called the Chladni effect.
When she placed the aluminum pie pan with a shallow layer of rice over the speaker on the radio and turned up the volume, the sound waves produced by the speaker caused the pan and the rice to vibrate.Sound waves are actually vibrations that travel through a medium, in this case, the air. When the speaker emits sound waves, they hit the pan, causing it to vibrate. These vibrations are then transferred to the rice, making it move and dance on the pan's surface.
The reason the rice gathers into patterns is due to the specific frequencies of the sound waves. Each frequency creates a unique standing wave pattern on the pan's surface. These patterns form areas of high and low vibrations, causing the rice to gather in the areas of least vibration, resulting in visible patterns.So, in simple terms, the rice dances due to the vibrations caused by the sound waves produced by the speaker. The Chladni effect helps us visualize and understand how sound waves interact with different objects and create patterns. I hope this explanation helps! Let me know if you have any further questions.
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Realiza la siguiente conversión de unidades: 340 N a Kgf
Answer:
The answer is 34.67 kilograms force
A 1. 25 kg block is attached to a spring with spring constant 17. 5 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46. 0 cm/s. What are
The maximum displacement of the block from its equilibrium position is 0.063 meters.
To solve this problem, we can first find the initial potential energy stored in the spring by using the formula: PE = 0.5kx^2, where k is the spring constant and x is the initial displacement from equilibrium (which is zero). Thus, the initial potential energy is 0 J. Then, we can use the principle of conservation of energy to find the maximum displacement of the block from its equilibrium position. Since there is no external work done on the block-spring system, the initial kinetic energy of the block is converted entirely into potential energy stored in the spring when the block reaches its maximum displacement. Using the formula for kinetic energy, KE = 0.5mv^2, where m is the mass of the block and v is the initial velocity, we can find the initial kinetic energy to be 1.44 J. Setting the initial kinetic energy equal to the final potential energy, we can solve for x to find the maximum displacement of the block from its equilibrium position to be 0.063 meters.
It is important to note that the almost instantaneous hit with the hammer means that we can assume the time interval over which the force is applied to be very short and thus the impulse of the force can be treated as an instantaneous change in momentum of the block. Therefore, the conservation of momentum principle can be ignored in the problem.
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Solve the science problem
explain how a syringe dra
ws blood from a patient's body
Answer:
You first push in then when the syringe is full push the out
Explanation:
1. in
2. out
but u should watch a You-tube video just in case
I hoped this helped!
Calculate the force of kinetic friction on a 12.3 kg mass if its coefficient of kinetic friction is 0.137
Answer:
Explanation:
All we need here is the equation for frictional force, which is
f = μ\(F_n\) where \(F_n=mg\) That's normal force which is the same thing as weight.
Therefore,
\(F_n=(12.3)(9.8)\) to 2 sig figs so
\(F_n=120\) and
f = (.137)(12) to 2 sig figs as well so
f = 16N
1.
X, Y and Z are the weights of three objects
suspended by pulleys as shown.
Assuming the pulleys in this system are frictionless
and weightless and that Z= 12 N, what are the
values of X and Y?
24°
50°
Х
Y
Z
Answer:
The weight of the object X is approximately 3.262 N (Acting downwards)
The weight of the object Y is approximately 8.733 N (Acting downwards)
Explanation:
The question can be answered based on the principle of equilibrium of forces
The given parameters are;
The weight of Z = 12 N (Acting downwards)
The weight of the pulleys = Negligible
From the diagram;
The tension in the in the string attached to object Z = The weight of object Z = 12 N
The tension in the in the string attached to object X = The weight of the object X
The tension in the in the string attached to object Y = The weight of the object Y
Given that the forces are in equilibrium, we have;
The sum of vertical forces acting at a point, \(\Sigma F_y\) = 0
Therefore;
\(T_{1y} + T_{2y} + T_{3y} = 0\)
\(T_{1y} = -( T_{2y} + T_{3y} )\)
Where;
\(T_{1y}\) = The weight of object Z = 12 N
\(T_{1y}\) = 12 N
\(T_{2y}\) = The vertical component of tension, T₂ = T₂ × sin(24°)
∴ \(T_{2y}\) = T₂ × sin(156°)
Similarly;
\(T_{3y}\) = T₃ × sin(50°)
From \(T_{1y} = -( T_{2y} + T_{3y} )\), and \(T_{1y}\) = 12 N, we have;
12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)
Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0
Therefore at point B, we have;
T₁ₓ + T₂ₓ + T₃ₓ = 0
The tension force, T₁, only has a vertical component, therefore;
∴ T₁ₓ = 0
∴ T₂ₓ + T₃ₓ = 0
T₂ₓ = -T₃ₓ
T₂ₓ = T₂ × cos(156°)
T₃ₓ = T₃ × cos(50°)
From T₂ₓ = -T₃ₓ, we have;
T₂ × cos(156°) = - T₃ × cos(50°)...(2)
Making T₃ the subject of equation (1) and (2) gives;
Making T₃ the subject of equation in equation (1), we get;
12 = -(T₂ × sin(156°) + T₃ × sin(50°))
∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))
Making T₃ the subject of equation in equation (2), we get;
T₂ × cos(156°) = - T₃ × cos(50°)
∴ T₃ = T₂ × cos(156°)/(-cos(50°))
Equating both values of T₃ gives;
(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))
-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))
∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283
∴ T₂ ≈ -8.02 N
From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;
T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717
∴ T₃ ≈ -11.4 N
The weight of the object X = -T₂ × sin(156°)
∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N
The weight of the object X ≈ 3.262 N (Acting downwards)
The weight of the object Y = -(T₃ × sin(50°))
∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N
The weight of the object Y ≈ 8.733 N (Acting downwards)
what is the investigative question when comes to internal resistance
When there is current flowing through the apparatus or electrical circuit and the source voltage or source battery experiences a voltage drop, internal resistance is present.
The voltage across the ideal voltage source is equal to the voltage at the terminals when there is no current flowing to an external resistance. However, there will be a voltage drop across the internal resistance when current leaves the cell, which will reduce the voltage at the cell's terminals.
The electromotive force within a cell is always greater than the potential difference between neighboring cells. Thus, variables like the distance between the electrodes, their effective area, temperature, and solution concentration affect a cell's internal resistance.
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a car goes a distance of 40 m in 5.25 seconds. What is it’s average velocity?
Answer:
I believe it is about 7.6 spm
Explanation:
40÷ 5.26 = 7.61904761904
The car's average speed is 7.62 m/s.
It's velocity can't be determined without knowing anything about it's position or direction.
What is the wavelength of the microwave?
The wavelength of the microwave, given that it is moving at a speed of 3.6×10⁸ m/s is 3 m (last option)
How do i determine the wavelength of the microwave?From the question given above, the following data were obtained:
Speed of microwave (v) = 3.6×10⁸ m/sFrequency of microwave (f) = 1.2×10⁸ HzWavelength of microwave (λ) = ?The wavelength of the microwave can be obtained as shown below:
Velocity (v) = wavelength (λ) × frequency (f)
3.6×10⁸ = wavelength × 1.2×10⁸
Divide both sides by 1.2×10⁸
Wavelength = 3.6×10⁸ / 1.2×10⁸
Wavelength = 3 m
Thus, from the above calculation, we can conclude that the wavelength of the microwave is 3 m (last option)
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The illumination lights in an operating room use a converging mirror to focus an image of a bright lamp onto the surgical site. One such light has a mirror with a focal length of 15 cm. If the patient is 1.0m from the mirror, where should the lamp be placed relative to the mirror?
According to the question: The lamp should be placed 11 cm from the mirror.
What is mirror?Mirror is an object which reflects light in such a way that images of nearby objects are visible. It is a surface which can reflect light in an exact way. Mirrors are used for various purposes like for making up, for decorating a room, for security purposes, and also for various scientific experiments. Mirrors are usually made up of two pieces of glass which are either flat or curved with a reflective coating on one side.
This coating is usually made up of metal, such as silver, and is highly reflective. Mirrors can also be made up of other materials such as plastic and other metals. By reflecting light, mirrors can help to create illusions and also create an optical illusion.
This is because the distance between the mirror and the lamp should be equal to the sum of the focal length of the mirror (15 cm) and the distance between the patient and the mirror (1.0 m). Therefore, the distance between the mirror and the lamp should be 1.0 + 15/100 = 2.15 m.
Use the thin lens equation to solve this
(1/s)+(1/s prime)=(1/f)
You are looking for the s value, which is the lamps distance from the mirror. s prime is the distance to the patient, and f is 10 cm.
(1/s)+(1/1.1)= (1/0.1)
= 11.000001 cm
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Q3.
Name the type of relationship shown in the graph below?
<<<<
A.Linear
B.Non-linear
C.Quadratic
D.Non-quadratic
Answer:
Linear
Explanation:
The slope is constant.
Answer:
A. Linear
Explanation:
hope I help you
A rock is dropped from a bridge and hits the water 1.5 seconds later. How high is the bridge?
An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?
Answer:
The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.
Tan theta = 9 / 90 = .1 so theta = 5.71 deg
The time for the monkey to reach the ground is
t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec
So the horizontal speed of the dart must be at least
Vx = 90 m / 1.36 sec = 66.4 m/s
Vx = V cos theta
V = 66.4 m/s / cos 5.71 = 66.7 m/s
The angle of projection of the tranquilizer dart is 5.7⁰
The horizontal speed of the tranquilizer dart is 66.5 m/s
The given parameters;
vertical position of the monkey, y = 9 mhorizontal position of the veterinarian, x = 90The angle of projection of the tranquilizer dart is calculated as;
\(tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0\)
The speed of the tranquilizer dart is calculated as;
X = v₀ₓt
where;
t is the time to reach maximum height
X is the horizontal displacement = 90 m
The time to reach maximum height is calculated as;
\(h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s\)
The horizontal speed of the tranquilizer dart is calculated as;
\(X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s\)
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where the reference cutting velocity is 0 =75 /min and reference feed per tooth is 0 = 0.1 /tooth .
The reference cutting velocity is 0 =75 /min and reference feed per tooth is 0 = 0.1 /tooth, F = f₀ * z * N.
The reference cutting velocity (V₀) is 75 m/min and the reference feed per tooth (f₀) is 0.1 mm/tooth, you can use these values to calculate various machining parameters, such as material removal rate or spindle speed, depending on the specific machining operation you're performing.
For example, if you want to calculate the spindle speed (N) in revolutions per minute (RPM), you can use the following formula:
N = (1000 * V₀) / (π * D)
Where N is the spindle speed in RPM, V₀ is the reference cutting velocity (75 m/min), D is the tool diameter in mm, and π is a constant approximately equal to 3.14159.
Similarly, you can calculate the feed rate (F) in mm/min using the reference feed per tooth (f₀) and the number of teeth (z) on the cutting tool:
F = f₀ * z * N
Where F is the feed rate in mm/min, f₀ is the reference feed per tooth (0.1 mm/tooth), z is the number of teeth on the cutting tool, and N is the spindle speed in RPM, which we calculated earlier.
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a body is thrown down from a tower of height 192 m with initial velocity 2m/s. find the time taken to hit the ground, velocity just before it hits the ground
Answer:
t = 6.47 s
v = 61.38 m/s
Explanation:
List out the variables we have/are given:
Δx = -192 mv₀ = 2 m/sv = ?t = ? a = -9.8 m/s²We can use this constant acceleration equation that contains Δx, v₀, a, and v to solve for v, the final velocity:
v² = v₀² + 2aΔxPlug in known values:
v² = (2)² + 2(-9.8)(-192)Simplify the equation.
v² = 4 +2(1881.6) v² = 3767.2Take the square root of both sides.
v = 61.37752031The velocity just before the body hits the ground is 61.38 m/s.
Let's find another equation that contains Δx, v₀, a, t to solve for t, the time:
Δx = v₀t + 1/2at²Plug in known values:
-192 = (2)t + 1/2(-9.8)t²Simplify this equation.
-192 = 2t - 4.9t²Set this equation equal to 0.
0 = -4.9t² + 2t + 192Factor this equation. You should get:
t = 6.46709390, t = -6.05893064Since time can't be negative, we will use the positive t value.
The time taken to hit the ground is 6.47 seconds.
2.1 The sketch below shows a large suitcase with a mass of 32 kg rests on a rough incline at an angle of 30 to the ground. 2.1.1 Define normal force in words. 2.1.2 Draw a labelled free-body diagram of all the forces acting on the suitcase. 2.1.3 Calculate the magnitude of the force of friction that keeps the suitcase stationery on the incline. (2) (3) (3) 2.1.4 Calculate the coefficient of static friction between the suitcase and the incline, if the suitcase is just about to move on the incline. (3)
Answer:
Explanation:
1) Normal force is the upward force applied by the ramp (incline) on the suitcase as the reaction to the downward force of the Weight (Fg) of the suitcase
2) sorry, can't supply a FBD. Brainly doesn't have drawing tools available.
3) Fg = mg = (32 kg)(9.8 m/s²) = 313.6 N
N= y-component of Fg = cos30(313.6 N) = 271.6 N
Ff = (coeff. friction)(N)
3) Ff = x-component of Fg = sin30(313.6) = 156.8 N
4) coeff. friction = Ff/N = 156.8N/271.6N = 0.58
Research by Goodale and colleagues indicates that the primary function of the dorsal stream of the visual cortex is to.
Research conducted by Goodale and colleagues suggests that the primary function of the dorsal stream of the visual cortex is to process visual information for guiding actions and motor control, rather than conscious perception.
Goodale and his colleagues have proposed a theory known as the two-stream hypothesis, which suggests that the visual processing in the brain is divided into two distinct streams: the ventral stream and the dorsal stream.
On the other hand, the dorsal stream, referred to as the "where" or "how" pathway, is primarily involved in processing visual information for the purpose of guiding actions and motor control. This stream is responsible for extracting spatial information, motion perception, and the perception of depth and location of objects in the visual field.
Goodale and his colleagues have provided substantial evidence for this hypothesis through various studies, including patient studies with individuals who have damage to the dorsal stream. These patients often experience impairments in their ability to interact with objects in their visual field, even though their conscious perception of those objects remains intact.
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