A 25.1 kg boy climbs to the top of a 11.08 m tall water slide at an amusement park. He carries a 2.94 kg rubber ball with him. Taking the bottom of the slide to be the zero point, what is the gravitational potential of just the boy in joules? (do not include units)

Answer:

use the formula above it's easy

Force = gravity x mass1 x mass2 / distance^2

Force = (6.67x10 ^-11) x (75) x (2100) / 1^2

Force = 1.050525 x 10 ^-5 Newtons

Answer

  96mph

Explanation:

You are given "144 miles in 90 minutes" and what you need to figure out is "144 km in X hours." To go from 90 min to hours, you can do 90 min * 1hr/60min = 1.5 hrs or 144 km in 1.5 hrs or 144 km per 1.5 hours. 144/1.5 = 96.

Answer:

Explanation:

According to ohm's law, we know that:

Where,

Substituting the values, we get:

→ 2000 = 200 × R

→ 2000/200 = R

→ 10 = R

Hence,

The maximum temperature is -320.44 and the minimum temperature is -333.22.

In this case, there was an increase of 50 °C in the temperature of this object. We say that the temperature variation suffered by the body was 50°C, and this can be determined mathematically through the difference between the final value and the initial temperature value (60 – 10 = 50).

In this case, we have:

\(x+ 333.22 = 12.78\\x=12.78-333.22\\x=-320.44\)

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-320.44 is the maximum temperature at which nitrogen is a liquid.

-346 is the minimum temperature at which nitrogen is a liquid

Answer: The Energy Change

Explanation: change for a chemical reaction can either be exothermic if it gives off heat or endothermic if it requires heat to proceed.  in a chemical reaction is due to the difference in the amounts of stored chemical energy between the products and the reactants. This stored chemical energy, or heat content, of the system is known as its enthalpy. energy changes that occur during a chemical reaction can be shown in a diagram called a potential energy diagram, or sometimes called a reaction progress curve. A potential energy diagram shows the change in potential energy of a system as reactants are converted into products.

Answer:

Baseball is commonly expressed in English units - we'll use that

(Rubber to home plate is 60' 6 '' but the ball is probably released at about 60 ft)

t = S / v      time of fall and time to reach plate

H = 1/2 g t^2

t = (2 H / g)^1/2     we'll use 32.,2 ft / sec^2    for g

t = (2 * 2.81 / 32.2)^1/2 = .418 sec

v = 60 ft / .418 sec = 144 ft/sec

Since 60 mph = 88 ft/sec

v = 144 / 88 * 60 = 98 mph

Answer:

Explanation:

How did media attention affect Barack Obama's presidential performance?(A)(B)(C)(D)He made a concerted effort to listen to Congress' concerns about his policies.He decided to go on Fox News in an attempt to win over Republican voters.He started traveling the country to give speeches about his policy goals.He began meeting in private with Speaker of the House Nancy Pelosi.

Two athletes are competing in upcoming competitions, a weightlifting meet and a marathon. phosphagen and oxidative energy systems will each be primarily used, respectively.

As it is in charge of high-intensity, brief-duration activity, the phosphagen energy systems generate energy for jumping and sprinting. The quickest and most effective energy producer in muscle activity. Phosphagen metabolism is demonstrated by this system. It uses creatine phosphate to produce ATP (adenosine triphosphate, the chemical which provides energy for all body processes).

Energy is produced by the oxidative energy systems using 30% and 70% of carbs and lipids, respectively. When done for at least 150 minutes a week, aerobic exercise enables the body to experience physiological and health benefits.

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Answer:

Na⁺

Explanation:

In the given atom:

  Number of protons  = 11

  Number of neutrons  = 12

So, the number of electrons  = 10

The number of protons within an atom is used to determine the kind of atom we have been given.

Since the number of protons is the same as the atomic number, here the atomic number is 11 and this is Sodium .

 In this sodium atom, the number of protons is more than the number of electrons;

 Charge = number of protons  - number of electrons  = 11 - 10  = +1

So, we have a Na⁺

Answer:

KE = KE (incidental) - KE of emitted photons

or KE = h * f - Wf

So   h * f = KE + Wf = 1.2 + 1.88 = 3.08    incident energy

If you double the frequency then h * f = 6.16

KE = 6.16 - 1.2 = 4.96 eV

The wave speed is c = sqrt(1/b) = sqrt(0.1) = 0.3162 and  the argument of the exponential function is negative, the wave is moving in the positive x direction.

The one-dimensional wave equation is given by:

∂²v/∂t² = c²∂²v/∂x²

where v is the wave function, t is time, x is position, and c is the wave speed.

Let's consider the Gaussian wave function:

v(x, t) = a * exp(-b(x - ct)²)

where a, b, and c are constants.

Taking the first partial derivative of v with respect to t:

∂v/∂t = -2abc(x - ct) * exp(-b(x - ct)²)

Taking the second partial derivative of v with respect to t:

∂²v/∂t² = 2ab(c(x - ct)² - 1) * exp(-b(x - ct)²)

Taking the first partial derivative of v with respect to x:

∂v/∂x = -2ab(x - ct) * exp(-b(x - ct)²)

Taking the second partial derivative of v with respect to x:

∂²v/∂x² = 2ab(1 - 2b(x - ct)²) * exp(-b(x - ct)²)

Now, plugging these partial derivatives into the wave equation:

∂²v/∂t² = c²∂²v/∂x²

2ab(c(x - ct)² - 1) * exp(-b(x - ct)²) = c² * 2ab(1 - 2b(x - ct)²) * exp(-b(x - ct)²)

Simplifying the equation:

c² = 1 / b

So the wave speed is c = sqrt(1/b) = sqrt(0.1) = 0.3162.

To determine the direction of the wave, we can look at the argument of the exponential function in the wave equation, which is:

-b(x - ct)²

If x > ct, then the argument is negative, meaning the wave is moving in the positive x direction. If x < ct, then the argument is positive, meaning the wave is moving in the negative x direction.

In our case, a = 5.00, b = 10.00, and c = 100, so the wave function is:

v(x, t) = 5.00 * exp(-10.00(x - 100t)²)

Since the argument of the exponential function is negative, the wave is moving in the positive x direction.

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Answer:

1025meter

Explanation:Distance is speed times time.so 3hx115km/h=345km

                                                                              5hx136km/h=680km

                                                                              345km+680km=1025km

Answer:

1025

Explanation:

Answer:

9.81 m/s   ( or 32.2 ft/s )

Explanation:

At ONE second your velocity

 v = at     = 9.81 * 1 = 9.81 m/s

Answer:

40

Explanation:

because his increasing speed

The magnitude of the force required to keep the rod moving at a constant speed is 0.9065 N.

First, let's find the induced electromotive force (EMF) using Faraday's law of electromagnetic induction: EMF = B * L * v, where L is the length of the rod, and v is its velocity. Converting the length to meters: L = 0.25 m.

EMF = 1.4 T * 0.25 m * 3.7 m/s = 1.295 V

Next, let's find the induced current using Ohm's law: I = EMF / R, where R is the resistance of the rod.

I = 1.295 V / 0.50 Ω = 2.59 A

The current induced in the rod is 2.59 A.

Now, let's calculate the magnitude of the force required to keep the rod moving at a constant speed. The force needed to maintain constant speed is equal to the magnetic force acting on the rod, which is given by F = I * L * B.

F = 2.59 A * 0.25 m * 1.4 T = 0.9065 N

The magnitude of the force required to keep the rod moving at a constant speed is 0.9065 N.

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Complete question:

The figure shows a 25 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.7 m/s . The rails have negligible resistance, but the rod has a resistance of 0.50 Ω .

B=1.4T

What is the current induced in the rod?

What is the magnitude of the force is required to keep the rod moving at a constant speed?

Answer:

distance and the amount of the force

Explanation:

moment = f x d

This question involves the concepts of electric field strength and distance.

The strength of the electric field is "215760 N/C".

The electric field strength due to a charge is given by the following formula:

\(E = \frac{kq}{r^2}\)

where,

Therefore,

\(E=\frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)}{(0.5\ m)^2}\)

E = 215760 N/C

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This question involves the concepts of electric field strength and distance.The strength of the electric field is "215760 N/C".

The electric field strength due to a charge is given by the following formula:

\(E=\dfrac{kq}{r^2}\)

where,

E = Electric Field Strength = ?

k = Colomb's constant = 8.99 x 10⁹ N.m²/C²

q = magnitude of charge = 6 μC = 6 x 10⁻⁶ C

r = distance = 0.5 m

Therefore, putting the values in the formula;

\(E=\dfrac{(8.99\times 10^9)(6\times 10^{-6})}{0.5}\)

E = 215760 N/C

Thus the strength of the electric field is "215760 N/C".

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In summary, the first sample has a per cent error of 2.0% from the theoretical boiling point of 100.0°C, while the second sample has a per cent error of 0.8%.

The per cent error represents the deviation of the experimental value from the theoretical value, expressed as a percentage of the theoretical value. It provides a measure of the accuracy of the experimental measurements. The per cent error for the first sample, which boils at 102.0°C, can be calculated as follows:

\(\[\text{{Percent error}} = \left|\frac{{\text{{Experimental value}} - \text{{Theoretical value}}}}{{\text{{Theoretical value}}}}\right| \times 100 = \left|\frac{{102.0 - 100.0}}{{100.0}}\right| \times 100 = 2.0\%\]\)

Therefore, the per cent error for the first sample is 2.0%. Similarly, the per cent error for the second sample, which boils at 99.2°C, can be calculated as:

\(\[\text{{Percent error}} = \left|\frac{{\text{{Experimental value}} - \text{{Theoretical value}}}}{{\text{{Theoretical value}}}}\right| \times 100 = \left|\frac{{99.2 - 100.0}}{{100.0}}\right| \times 100 = 0.8\%\]$\)

Thus, the per cent error for the second sample is 0.8%.

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Answer:

see below

Explanation:

voltage = current * resistance

Communication is the act of conveying information from one person to another. .'Good communication makes it difficult to express wants and needs.'These statement is not true about good communication.

Communication is the act of conveying information from one location, person, or organization to another. There is a sender, a message, and a recipient for every message.

Communication, while it may appear to be a simple notion, is actually a very complex topic. The message's path from sender to the destination might be influenced by a multitude of circumstances.

Hence the option 'A' is right. 'Good communication makes it difficult to express wants and needs this statement is not true about good communication.

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the answer is A

Explanation : took the quiz on edge 2020

The pressure difference needed to drain the shake in 3.0 minutes is approximately 346.67 cP cm^3/min / cm^2.

To find the pressure difference needed to drain the shake in 3.0 minutes, we can use the equation for flow rate:
Flow Rate = Volume / Time
Given that the volume is 520 ml and the time is 3.0 minutes, we can calculate the flow rate:
Flow Rate = 520 ml / 3.0 minutes = 173.33 ml/min

Now, to find the pressure difference, we can use the equation:
Pressure Difference = (Flow Rate * Viscosity) / Area
The viscosity of a shake is similar to that of water, which is about 1.0 cP (centipoise). The area of a typical straw is about 0.5 cm^2.
Plugging in the values:
Pressure Difference = (173.33 ml/min * 1.0 cP) / 0.5 cm^2
Converting ml to cm^3 (1 ml = 1 cm^3):
Pressure Difference = (173.33 cm^3/min * 1.0 cP) / 0.5 cm^2
Simplifying:
Pressure Difference = 346.67 cP cm^3/min / cm^2

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Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

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The rubber is stretched and firmly gripped by the nail due to the pressure inside the tire, which prevents air leakage.

The force of all gas particle/wall collisions divided by the surface area of the wall is the definition of pressure (P): One of the fundamental measurable quantities of this phase of matter, pressure is a property shared by all gases. The amount of force applied to a given area is referred to as pressure.

For instance, the weight of the snow divided by the area of the roof would represent the pressure from snow on a roof. Gases are typically where pressure in chemistry comes from. Gas is added to a balloon before it is inflated. Gas molecules collide with one another and the balloon's walls.

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The disk's final rotation rate (in rev/s) is  2.55 rev/s.

To calculate this, we must use the angular momentum of the disk. The angular momentum of the disk before the mass dropped onto it is equal to 2.3 rev/s x (3.5 kg x (80 cm)2). After the mass drops onto the disk, the angular momentum will be equal to (3.5 kg x (80 cm)2) x (2.55 rev/s). We can calculate the change in angular momentum by subtracting the two equations. The change in angular momentum is equal to 0.06 kg x (80 cm)2 x (2.55 rev/s - 2.3 rev/s). Thus, the final rotation rate is equal to 2.55 rev/s. This is the new angular momentum divided by the mass of the disk multiplied by the radius of the disk squared.

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According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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Electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ hertz would be classified as radio waves.

Electromagnetic waves are a form of energy that propagate through space in the form of oscillating electric and magnetic fields. These waves are generated by the acceleration or oscillation of charged particles, such as electrons.

The frequency of an electromagnetic wave refers to the number of oscillations or cycles it completes per unit of time. It is usually measured in hertz (Hz), which represents cycles per second. In the given scenario, the electrons are oscillating with a frequency of 2.0 x 10¹⁰ Hz.

Now, let's discuss the classification of electromagnetic waves based on their frequency and wavelength. The electromagnetic spectrum encompasses a wide range of waves, including radio waves, microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays.

Radio waves have the longest wavelengths and lowest frequencies among the electromagnetic waves. They typically range from a few centimeters to several kilometers in wavelength. These waves are commonly used for various forms of communication, such as radio and television broadcasting, as well as wireless communication technologies like Wi-Fi and cellular networks.

As the frequency of electromagnetic waves increases, we move through the spectrum, encountering microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays in that order. Each segment of the spectrum has distinct properties and applications.

In summary, the electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ Hz would be classified as radio waves. These waves have longer wavelengths and lower frequencies compared to other regions of the electromagnetic spectrum and are widely used for communication purposes.

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Answer:

For smooth surface:The light rays bounce off the table and all move in the same direction.

Question 1-9: Yes, it does seem to take more effort to move the cart when the force was inclined at an angle to the ramp's surface.

Question 1-10: if your choice in Prediction 1-1 was that it would take more effort to move the cart when the force was inclined at an angle, then yes, it was the best choice.

Explanation:

Question 1-9: Yes, it does seem to take more effort to move the cart when the force was inclined at an angle to the ramp's surface. This is because only the force component parallel to the displacement is included in the calculation of work.

The equation W = F × d × (cos A) supports this observation as a reasonable way to calculate the work. When the force is applied at an angle, the cosine of the angle is taken into account, which reduces the effective force used in the work calculation.

Question 1-10: Based on all of your observations in this investigation, if your choice in Prediction 1-1 was that it would take more effort to move the cart when the force was inclined at an angle, then yes, it was the best choice.

The observations support the fact that more physical work was done to move the cart over the same distance at the same slow constant speed when the force was applied at an angle to the ramp's surface.

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Here's the fact that you need to know:

"The AREA under a speed/time graph is the distance traveled during the time covered by the graph."

Now ... What's the area of that nice trapezoid on the graph ?

Hint: Area of a trapezoid is

(1/2) • (height) • (base-1 + base-2)