a 200lb cable is 1000 long and hangs vertically from a building. how much work is required to lift the cable to the top of the building?

Answer:

The equation for wave speed can be used to calculate the speed of a wave when both wavelength and wave frequency are known. Consider an ocean wave with a wavelength of 3 meters and a frequency of 1 hertz. The speed of the wave is: Speed = 3 m x 1 wave/s = 3 m/s.

Explanation:

Answer:

A

Explanation:

if its wronge im so sorry

Answer:

B

Explanation:

Answer:

B

Explanation:

Answer:

4200 Newtons

Explanation:

Force = mass x acceleration

1200 x 3.5 = 4200

Answer:

Explanation:

They traveled this distance in 2 parts, essentially. Part 1 had an average speed for a certain number of hours, part 2 had an average speed for a certain number of hours, and those 2 parts taken together took them a distance of 364 km. In equation form, that looks like this:

km/hr part 1 + km/hr part 2 = 364 km

Now we need to find each part on the left side of that equation. Part 1 first:

We traveled 65 km/hr for 2 hours, so that took us

\(65\frac{km}{hr}*2hr\) and canceling out the hour label, we have that in part 1 we got

65(2) = 130 km. Good. Now onto the second part, where our unknown is.

We traveled 78 km/hr the second part for x hours, so that took us

\(78\frac{km}{hr}*xhr\) and canceling out the hour label, we have that in part 2 we got

78x km. Now we can fill in the main equation (the one in bold print)

130 km + 78x km = 364 km and subtracting 130 km from both sides:

78x km = 234 km and dividing by 78 km:

x = 3 hours. Part 2 took 3 hours. Part 1 took 2 hours, so the whole trip took 5 hours.

Hi, to answer your question regarding the comparison of the magnitudes of kinetic energy (K_A and K_B) of puck A and puck B when they reach the finish line, we need to consider the following steps:

1. Kinetic energy is defined as KE = 0.5 * m * v^2, where m is the mass of the object, and v is its velocity.

2. In order to compare K_A and K_B, we need to know the masses and velocities of both pucks A and B at the instant they reach the finish line.

Since the question does not provide any information about the masses and velocities of the pucks, we cannot determine whether K_A is equal to, greater than, or less than K_B. Therefore, the correct answer is: "You need more information to decide."

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The tension in the string is 3.51 x 10^-8 N.

The equation for the gravitational force between two masses m1 and m2 separated by a distance r is given as:

Fg = Gm1m2/r²

where G is the gravitational constant equal to 6.67 x 10^-11 N m²/kg²

To find the tension in the string, we need to find the gravitational force between the two boxes.

Since each box has 1.00 g of protons, the mass of each box is equal to the mass of the protons in each box, which is equal to 1.00 g or 0.001 kg.

The total mass of the system is 2m = 0.002 kg, where m is the mass of one box.

The distance between the two boxes is the sum of their distances from the center of the earth, which is

3.84 x 10^8 m + 384,400 m = 3.84 x 10^8 m + 3.844 x 10^5 m = 3.84 x 10^8 m (to three significant figures).

Therefore, the tension in the string is given as:

T = Fg = Gm1m2/r² = (6.67 x 10^-11 N m²/kg²)(0.001 kg)(0.001 kg)/(3.84 x 10^8 m)²= 3.51 x 10^-8 N (to three significant figures)

Therefore, the tension in the string is 3.51 x 10^-8 N.

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a. Just Noticeable Difference (JND) refers to the smallest difference in stimuli that can be detected by a person. It is also known as the difference threshold. Weber's Law states that the JND is proportional to the magnitude of the stimulus.

In simpler terms, the JND is relative to the initial stimulus. For example, if you have a 10 kg weight and you add 1 kg, you will notice the difference. However, if you have a 100 kg weight and you add 1 kg, you may not notice the difference. Weber's Law helps us understand how our perception changes as the magnitude of the stimulus changes.

b. To suggest a discount using the principle of JND, we need to consider the income range and the prices of the pressure cooker. Let's assume the JND for families earning Rs. 10,000 per month is Rs. 200 and for families earning Rs. 15,000 per month is Rs. 300. Based on these values, we can calculate the discounts that would make them notice and be motivated to buy the pressure cooker.

For families earning Rs. 10,000 per month, the JND is Rs. 200. So, if we offer a discount of Rs. 200 on the 3 Litre pressure cooker priced at Rs. 1800, the new price would be Rs. 1600. This discount would be noticeable to them and may motivate them to purchase.

For families earning Rs. 15,000 per month, the JND is Rs. 300. So, if we offer a discount of Rs. 300 on the 5 Litre pressure cooker priced at Rs. 2400, the new price would be Rs. 2100. This discount would be noticeable to them and may encourage them to buy.

The justification for these discounts is that they are based on the JND principle, which ensures that the discounts are noticeable to the target audience. By offering discounts within their perception range, we can attract their attention and motivate them to make a purchase.

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In a gym the students raced with each other and teacher is recording everyone's speed than the second graph is representing correctly.

A graph is a visual depiction of statistical data or a logical relationship between variables. Graphs serve a predictive purpose because they have the virtue of displaying broad trends in the mathematical behavior of data. However, as just approximations, they may be incorrect and occasionally deceptive.

Most graphs have two axes, with the axis denoting a set of independent variables and the vertical axis denoting a set of dependent variables. The most typical graph is indeed a broken-line chart, where the regression coefficient is typically a factor of duration.

In the second graph the speed of every student is represented accurately, therefore the second graph is correct.

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If the optical depth for blue light in the atmosphere is 0.1, then only 10% of the light at this wavelength is scattered before it reaches the ground. This means that 90% of the blue starlight would pass straight through the atmosphere without being scattered.

The cross section for scattering of blue light by air molecules can be determined using the formula:

σ ≈ σ_T(λ_0/λ)^4
where σ_T is the Thomson cross section,
λ_0 is the characteristic wavelength of the scatterer, and
λ is the wavelength of the incident light.

Since we are interested in the scattering of blue light (λ = 400 nm), we need to determine λ_0. This characteristic wavelength depends on the size of the scattering particle, which is much smaller than the wavelength of light.

For air molecules, λ_0 is typically on the order of 1 nm. Using this value, we can calculate the cross section for scattering of blue light by air molecules to be approximately: 2.3 × 10^-31 m^2.

In summary, only 10% of blue starlight is scattered by the atmosphere, and the cross section for scattering of blue light by air molecules is approximately 2.3 × 10^-31 m^2, with a characteristic wavelength λ_0 of approximately 1 nm.

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Answer:

I think true..... :))))))))))

Answer:

The speed the car must travel to experience no friction is approximately 16.9 m/s

Explanation:

The car and road data are;

The mass of the car, m = 1,200 kg

The radius of the road, r = 80 meters

Given that the angled at which the road is banked, θ = 20°

The friction between the tires and the road, at the required speed, \(\mu_s\) = 0, No friction

We have;

\(\dfrac{v^2}{r \cdot g} = \dfrac{\left( sin \, \theta + \mu_s \cdot cos \, \theta \right)}{\left( cos\, \theta + \mu_s \cdot sin\, \theta \right)}\)

Where \(\mu_s\) = 0, we get;

\(\dfrac{v^2}{r \cdot g} = \dfrac{ sin}{ cos} = tan \, \theta\)

∴ v² = r·g·tan(θ)

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

v = The speed at which the car travels

∴ v² = 80 m × 9.81 m/s² × tan(20°) = 285.64384 m²/s²

v = √(285.64384 m²/s²) ≈ 16.9 m/s

The speed with which the car must travel to experience no friction, v ≈ 16.9 m/s

To find the wavelength, use the formula: wavelength = speed of light / frequency. Wavelength ≈ 6.22 x 10⁻² meters.


To calculate the wavelength of a photon with a frequency of 4.81 x 10⁶ Hz, you need to use the equation that relates wavelength (λ), frequency (f), and the speed of light (c):
wavelength (λ) = speed of light (c) / frequency (f)
The speed of light is approximately 3 x 10⁸ meters per second (m/s). Now plug in the given frequency:
λ = (3 x 10⁸ m/s) / (4.81 x 10⁶ Hz)
Divide 3 x 10⁸ by 4.81 x 10⁶:
λ ≈ 6.22 x 10⁻² meters
So, the wavelength of the photon is approximately 6.22 x 10⁻² meters.

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Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 4000 × 9.8 × 20 = 784,000

We have the final answer as

Hope this helps you

The magnitude of the electric field at point 'P' is given by E = (9 x 10⁹N m²/C²)) x Q / R².

To find the electric field at point 'P', we can use the formula:

E = kQ / R²

where 'k' is the Coulomb constant (k = 9 x 10⁹ N m²/C²).

In this case, since the charge 'Q' is uniformly distributed throughout the ring, we can treat it as a point charge located at the center of the ring. Therefore, the distance from the center of the ring to point 'P' is simply 'R'. Plugging in these values, we get:

E = kQ / R²

E = (9 x 10⁹ N m²/C²) x Q / R²

The electric field at a point in space is a vector quantity that describes the force that would be exerted on a positive test charge placed at that point. The direction of the electric field is the direction of the force that the test charge would experience.

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Answer:

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed.

Explanation:

Hope this helps :)

Answer:

Examples of Uniform Motions.

The hr. ...

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed

The available options are:

A. bartenders serving alcohol

B. students identifying their professors.

C. Doctors diagnosing cases of schizophrenia.

D. eyewitnesses identifying suspects from a lineup.

Answer:

A.  bartenders serving alcohol

Explanation:

This is because of the underage rule concerning sale of alcohol. Thus, there are occasional period in which underage person or a minor will want to buy alcohol, and without necessarily asking for the birth certificate or ID card that contains Age information, it is therefore, necessary for bartenders to be able to tell the age of their unfamiliar customers, by mere looking at them, so as not to sell to a minor.

Hemce, Rhodes research in guessing the age of unfamiliar person has important implications for BARTENDERS SERVING ALCOHOL, because it will guide them to determine Underage or Minor, that want to buy alcohol from them.

Hi there!

A neutral metal sphere is comprised of both ELECTRONS and PROTONS.

Recall that electrons have a NEGATIVE (-) charge, and protons have a POSITIVE (+) charge.

Opposite charges attract, and like charges repel.

In this instance, the positively-charged rod will cause the electrons in the neutral metal sphere to move towards the side facing the rod (opposite charges attract), which causes the two to be attracted to one another.

The breakdown electric field of polyethylene foam alone cannot be used to estimate the highest voltage that can be applied to the wire before it breaks down.

The biggest electrical potential difference that a system can withstand without experiencing harm or failure is known as the maximum voltage. As exceeding the maximum voltage can lead to electrical failure, fire, or even harm, it is crucial in the design and operation of electrical and electronic devices. The design, manufacturing method, and material properties of the device, as well as the environment in which it will be utilised, all influence the maximum voltage. It is crucial to follow the manufacturer's recommendations for maximum voltage and to routinely test and maintain equipment to make sure it is operating within its limitations in order to ensure safe operation.

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For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.

The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.

When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.

\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)

Substituting the known values:

\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)

Solving for m₂:

\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)

The mass of the right block must be 7.9 kg for the two blocks to remain stationary.

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The question is -

Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg

Answer:

apply more energy to the object with more mass

Explanation:

An artificial satellite can be called a celestial body as it orbits around a planet.

Objects in space such as the sun, moon, planets, and stars are known as celestial bodies or heavenly bodies. Satellites are revolving bodies that orbit planets. They are the fundamental component of celestial bodies. These could be transmitted by humans or be of natural origin.

The moon orbits the earth as a natural satellite because it is held in place by the gravity of the planet. Additionally, man has positioned artificial or man-made satellites in orbit around the earth and other planets for communication and scientific research.

As a artificial satellite also orbits around a natural celestial body, it can be called as a celestial body.

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Answer:

what is the number

Explanation:

The average velocity of the pirates is 1.44 miles/hr.

A vector quantity is an average velocity. The change in position or displacement (x) divided by the time intervals (t) in which the displacement happens yields the average velocity. Depending on the sign of the displacement, the average velocity can be positive or negative. Meters per second (m/s or ms-1) is the SI measure of average velocity.

total time = t₁ + 1 + t₂

T = 1 + 1 + 3

T = 5hr

Displacement = AC = √(4² + 6²)

S = √16+36

S = √52

Average velocity = Displacement/ Time

v = S/t

substituting the value in the above equation, we get

v = 7.2/5

v = 1.44 mile/hr

Thus, the average velocity of the pirates is 1.44 miles/hr.

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The magnitude of the average force exerted on the passenger during the collision is 9321.9 N.

The magnitude of the average force exerted on the 47 kg passenger can be calculated using the formula for force: F = m * a, where m is the mass of the passenger and a is the acceleration experienced during the collision. Since the passenger is brought to rest, the final velocity is 0 m/s. Therefore, the acceleration can be calculated using the equation: a = (v_f - v_i) / t, where v_f is the final velocity (0 m/s), v_i is the initial velocity (11.9 m/s), and t is the time interval (0.06 s).
Substituting the values, we get a = (0 - 11.9) / 0.06 = -198.3.
Finally, we can calculate the magnitude of the average force by multiplying the mass of the passenger and the acceleration: F = m * a = 47 kg * (-198.3) = -9321.9 N.
Since force is a vector quantity, the negative sign indicates that the force is in the opposite direction to the passenger's initial velocity.

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Answer:

Knees to Chest

Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..

Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.

A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

–8 = 100 × a

Divide both side by 1000

\(a = \frac{-8}{100}\)

Therefore, the deceleration of the box is –0.08 ms¯²

Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:

Deceleration (a) = –0.08 ms¯²

Initial velocity (u) = 21 ms¯¹

Final velocity (v) = 0 ms¯¹

0 = 21 + (–0.08×t)

0 = 21 – 0.08t

Collect like terms

0 – 21 = –0.08t

–21 = –0.08t

Divide both side by –0.08

\(t = \frac{-21}{-0.08}\\\\\)

Therefore, it will take 262.5 s for the box to come to rest.

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If the temperature of a star doubles while all other properties remain constant, its spectrum shifts towards shorter wavelengths (bluer) and its flux increases by a factor of 16.

When the temperature of a star doubles while other properties remain constant, its spectrum undergoes a shift towards shorter wavelengths, meaning it becomes bluer. This shift is due to the relationship between temperature and the peak wavelength of radiation emitted by a black body, known as Wien's displacement law. Additionally, the star's flux, which is the amount of energy emitted per unit area, increases by a factor of 16. This increase is a result of the Stefan-Boltzmann law, which states that the total energy radiated by a black body is proportional to the fourth power of its temperature. Thus, doubling the temperature leads to a 16-fold increase in the star's flux.

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The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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Gamma rays are not deflected by magnetic fields.

Gamma rays are electromagnetic waves and are not affected by magnetic fields. Therefore, gamma rays would not be deflected by the uniform magnetic field as shown in the diagram.

However, if the emitted particle is a charged particle, such as an alpha particle or a beta particle, then it would be affected by the magnetic field.

The direction of deflection would depend on the charge and velocity of the particle and the direction and strength of the magnetic field.

The redirection of charged particles in an attractive field is depicted by the Lorentz force condition, which expresses that the power on a charged molecule because of an attractive field is opposite to both the speed of the molecule and the course of the attractive field.

The heading of the power is given by the right-hand rule, where the thumb focuses toward the speed, the fingers point toward the attractive field, and the palm provides the guidance of the power.

In summary, gamma rays are not deflected by magnetic fields, while charged particles are deflected according to the Lorentz force equation, with the direction of deflection depending on the charge and velocity of the particle and the direction and strength of the magnetic field.

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