The energy transferred to the room by the heater is 60,000 Joules (or 60 kJ).
The power of the electric resistance heater is given as 2 kW, which means it consumes 2 kilojoules of energy every second (since 1 kW = 1000 J/s). Therefore, in 30 minutes (i.e., 1800 seconds), the heater would consume 2 x 1800 = 3600 kJ of energy.
However, the question asks for the amount of energy transferred to the room by the heater, not the energy consumed by the heater. It is important to note that not all the energy consumed by the heater is transferred to the room; some of it is lost as heat to the surroundings.
Assuming that all the energy consumed by the heater is transferred to the room, the energy transferred to the room can be calculated as follows:
Energy transferred to the room = Power x Time = 2 kW x 1800 s = 3600 kJ
Therefore, the energy transferred to the room by the 2-kW electric resistance heater when kept on for 30 minutes is 60,000 Joules (or 60 kJ).
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A molecule of oxygen (O2) has a speed of 473 m/s at a certain temperature. Determine the speed of the molecule in kilometers per hour (km/h).
Answer: 1702.8 km/h
Explanation:
The speed of the molecule in kilometers per hour (km/h) will be, {473x(3600÷1000)} km/h
= 1702.8 km/h
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 7.5 cm. Initially the magnetic field in the region is pointed out of the page and has a magnitude of 5.5 T, but it is decreasing at a rate of 13 G/s. Due to the changing magnetic field, an electric field will be induced in this space which causes the acceleration of charges in the region.
Edit: What is the direction of the acceleration of a proton placed at the point P1, 2.5 cm from the center? (Counterclockwise)
What is the magnitude of this acceleration, in meters per square second?
The required magnitude of the acceleration is approximately 1.25 x 10¹³m/s².
The direction of acceleration of a proton at point P1, 2.5 cm from the center, due to the changing magnetic field is inward toward the center of the cylinder.
The magnitude of this acceleration can be calculated using the formula:
a = q * |E| / m
where q is the charge of the proton, |E| is the magnitude of the induced electric field, and m is the mass of the proton.
To calculate |E|, we use Faraday's law of electromagnetic induction and the rate of change of magnetic flux:
|E| = -dφ/dt
The rate of change of magnetic flux:
|E| = dφ/dt = (5.5 T) * (π * (0.075 m)²) * (13 * 10⁻⁴ T/s)
Once we have the rate of change of magnetic flux, we can substitute it into the formula to calculate the magnitude of the electric field |E|.
Finally, by plugging in the values of q, |E|, and m into the acceleration formula, we can find the magnitude of the acceleration of the proton in meters per square second.
Therefore, the magnitude of the acceleration is approximately 1.25 x 10¹³m/s².
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A race car with a 255 hp (1.90 × 105 W) engine is able to accelerate from rest to its top speed in 9.00 s. How much work does the car's engine do in this interval of time?
Answer:
W = 1710 kJ
Explanation:
Given that,
Power of a race car, P = 255 hP = \(1.9\times 10^5\ W\)
It accelerate from rest to its top speed in 9.00 s.
We need to find the work does the car's engine do in this interval of time.
Power is given by work done per unit time. Mathematically,
\(P=\dfrac{W}{t}\\\\W=P\times t\\\\W=1.9\times 10^5\times 9\\\\W=1710\ kJ\)
So, the required work done is is 1710 kJ.
Which image shows the correct way of lining up vectors to add them together? A. two arrows lined up facing away from each another B. two arrows lined up one after the another C. two arrows lined up facing each another D. two arrows facing opposite to each other
The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.
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A heavy box weighing 1000 newtons sits on the floor. You lift upward on the box with a force of 450 newtons, but the box does not move. What is the normal force on the box while you are lifting?
Answer:
i think its 550
Explanation:
1000-450 is 550
The forearm has a total mass of 1.7kg. What is the moment, about the elbow joint, of the weight of the forearm
Light passes through a 10-μm-wide slit and is viewed on a screen 1 m behind the slit. What will happen to the band of light if the width of the slit is narrowed? a) The band will become narrower. b) The band will become wider. c) The band will stay about the same.
If the width of the slit is narrowed, the band of light will become wider. thus option B is the answer.
When light passes through a narrow slit, it undergoes diffraction, which causes it to spread out and produce a pattern on a screen placed behind the slit. The width of the slit determines the size of the diffraction pattern, with narrower slits producing wider patterns. Therefore, if the width of the slit is narrowed, the diffraction pattern will become wider. This is because the narrower slit causes the light passing through it to spread out more, resulting in a wider pattern on the screen. As a result, the band of light observed on the screen will become wider
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The largest and the smallest balls used in the experiment are with diameter 9. 52 mm, and 2. 38 mm respectively. For a glycerin with viscosity 1. 0 pa. S, what is the time necessary for each ball to reach a velocity 95% of the terminal velocity? density of the ball material is given in the text. Round the result to three decimal places.
Here the answer = 0.0080 .
Solution:Based on stokes law,
v = g * D^2 *(d p - d m) / (18 V)
v = terminal velocity
D = diameter of particle
V = Viscosity
dp = density of particle
dm = density of medium.
Here density of ball = 1.42 gm/cc
By substituting,
v = 9.81 x 9.52 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0
=5.92x10^-4
v(t) =0 .99 x Vtrm
=0 .99 x 0.0059
= 0.00059 m/s
v(t)/Vterm =1-e^(-t/r)
0.99 = 1 - e ^ (-t / 9.52 x 10^-3)
e ^ (-t / 9.52 x 10^-3) = 0.01
Taking log
-t / 9.52 x 10^-3 = -4.6
t = 0.0438 s
Then smaller ball
v = 9.81 x 2.38 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0
= 0.000037 m/s
v(t) / Vterm = 1-e^(-t/r)
0.99 = 1 - e ^ (-t / 2.38 x 10^-3)
e ^ (-t / 2.38 x 10^-3) = 0.01
Taking log
-t / 2.38 x 10^-3 = -4.6
t = 0.0109 s
Here Reynolds number is,
R= rho vd / mu
= 1420 x 0.00059 x 9.52 x 10^-3 x / 1.0
= 0.0080
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how do i adjust the end of travel limits on my old screw drive chamberlain liftmaster garage door opener?
If you own an old screw drive Chamberlain Liftmaster garage door opener, then there may come a time when you need to adjust the end of travel limits on it. The good news is that it's a fairly easy process that can be done with just a few simple steps. Here's how to do it:
Step 1: Close the garage door completely.
Step 2: Locate the "down" limit adjustment screw, which is usually located near the motor unit.
Step 3: Turn the "down" limit adjustment screw clockwise to decrease the travel of the garage door, or counterclockwise to increase the travel of the garage door.
Step 4: Open the garage door completely.
Step 5: Locate the "up" limit adjustment screw, which is usually located near the motor unit.
Step 6: Turn the "up" limit adjustment screw clockwise to decrease the travel of the garage door, or counterclockwise to increase the travel of the garage door.
Step 7: Test the adjustment by closing and opening the garage door several times.
If you find that the adjustment is still not correct, then you may need to repeat the process until you get it just right. Remember to test the garage door after each adjustment to ensure that it is working properly.
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suppose karl drives for 50 minutes. use the line of fit to determine the anticipated number of miles he drives.
The anticipated number of miles Karl drives can be determined by using the line of fit equation and plugging in the value of 50 minutes for the independent variable. The resulting value will be the predicted number of miles driven by Karl in 50 minutes.
To explain further, a line of fit is a line that represents the trend of a set of data points in a scatter plot. In this case, the line of fit equation was likely derived from a set of data points that show the relationship between the amount of time Karl drives and the corresponding distance he covers. By using this equation, we can estimate the number of miles he drives for a given amount of time.
For example, if the line of fit equation is y = 0.8x + 5, where y represents the number of miles driven and x represents the time in minutes, we can plug in x = 50 and solve for y to get:
y = 0.8(50) + 5 = 45
Therefore, the anticipated number of miles Karl drives in 50 minutes is 45.
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i need to know more about science
Answer:
The origin of science can be traced back to ancient Egypt and the Mesopotamia from about 3500 to 3000 BC. The achievements of these two civilizations in mathematics, astronomy, and medicine have reached and shaped the Greek natural philosophy in the classical era, and they usually formally try to explain events in the material world with natural causes . After the fall of the Western Roman Empire, in the first few centuries of the Middle Ages (approximately 400-1000 AD), knowledge about the ancient Greeks’ world concepts was gradually forgotten in Western Europe , while in the Muslim world of the Golden Age of Islam Was preserved in. From the 10th century to the 13th century, Western Europe retrieved the writings of ancient Greece and absorbed the research of Islamic scholars. Natural philosophy was revived, and then transformed in the scientific revolution that began in the 16th century The new ideas and discoveries during this period broke away from ancient Greek ideas and traditional methods. The rapid role of scientific method in acquiring knowledge, but the institutionalization and professionalization of science did not begin to take shape until the 19th century
a boat ended up with a velocity of 30.m/s [N30.E] after it experienced an acceleration of 3.0m/s^2 [S] for a period of 4.0s what displacement did the boat cover
Answer:
96 m
Explanation:
The average velocity over those 4 seconds is the velocity after 2 seconds:
30 m/s -(2 s)(3.0 m/s^2) = 24 m/s
The displacement is the product of this average velocity and the duration of the acceleration:
d = (24 m/s)(4 s) = 96 m
The boat covered 96 m while being accelerated.
Can someone help me with this please!!!
Answer:
B. 10 m
Explanation:
f = v/λ = (20 m/s)λ / (5 m) = 4 Hz original frequency
1/2(4 Hz) = 2 Hz half the original frequency
(20 m/s) / λ = 2 Hz
λ = (20 m/s) / (2 Hz) = 10 m
The second wavelength would increase to 10 m
Part L The figures below show four circuits, with the resistances of the resistors given. In all cases, the emf of the battery is 10 V. Rank the circuits in order of descending total current coming out of the battery. (You should be able to answer this question using what you have already learned, but if you want, feel free to build the four circuits and make measurements.) Reset Help 9.07 10.00 9.07 10.00 10.00 00 9.07 10.000 10.00 50.00 10.00 IL- Greatest current Smallest current
The order of descending total current coming out of the battery is Circuit 1, Circuit 2, Circuit 3, Circuit 4.
The total current coming out of the battery can be calculated by the formula I = V/R, where V is the emf of the battery (10 V in this case) and R is the total resistance of the circuit. From this, we can calculate the total current for each of the four circuits:
Circuit 1: I = 10V/9.07Ω = 1.10ACircuit 2: I = 10V/10.00Ω = 1.00ACircuit 3: I = 10V/9.07Ω + 10.00Ω + 10.00Ω = 0.72ACircuit 4: I = 10V/50.00Ω = 0.20ATherefore, the order of descending total current coming out of the battery is Circuit 1, Circuit 2, Circuit 3, Circuit 4.
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On a distance-time graph, which is your independent and dependent variable?
Answer:
On a distance time graph, the distance will always be the dependent variable on the y- axis. Time is the independent variable and will always be placed on the x-axis. The lines on the graphs can tell you many different things.
Explanation:
ANSWER:
the dependant variable is on the y axis and the independent variable is on the x axis.
You have a ball with mass 2.5 kg tied to a rope, and you spin it in a circle of radius
1.2 m. You know that the rope can withstand a tension of 130 N before it breaks.
How fast can you safely spin the ball without the rope breaking?
Answer:
Approximately \(7.2\; {\rm m\cdot s^{-1}}\) (rounded up), assuming that this circle is vertical and \(g = 9.81\; {\rm m\cdot s^{-2}}\).
Explanation:
Let \(v\) denote the tangential speed of the ball, and let \(r\) denote the radius of the circle. Since the ball is in a circular motion, the acceleration on this ball would be equal to the centripetal acceleration \(a = (v^{2} / r)\). The net force on this ball would be \(F_{\text{net}} = m\, a = (m\, v^{2} / r)\).
The net force on this ball is also the vector sum of the tension \(T\) in the rope and the weight of the ball \(m\, g\):
\(F_{\text{net}} = (\text{weight}) + T\).
\(T = F_{\text{net}} - (\text{weight})\).
Note that:
\(\| T \| = \|F_{\text{net}} - (\text{weight})\| \le \|F_{\text{net}} \| + \| (\text{weight})\|\).
In other words, the magnitude of tension \(T\) is at most equal to \(\|F_{\text{net}} \| + \| (\text{weight})\| = (m\, v^{2} / r) + (m\, g)\), which happens when weight and net force are in opposite directions.
When the speed of the ball is maximized, the magnitude of tension \(T\) would be at the largest possible value of \(130\; {\rm N}\). Rearrange the equation and solve for speed \(v\):
\(\displaystyle \frac{m\, v^{2}}{r} + m\, g = \|T\|\).
\(\begin{aligned}v^{2} = \frac{r}{m}\, (\|T \| - m\, g) = \frac{r\, \|T\|}{m} - r\, g\end{aligned}\).
\(\begin{aligned}v &= \sqrt{\frac{r\, \|T\|}{m} - r\, g} \\ &= \sqrt{\frac{(1.2)\, (130)}{2.5} - (1.2)\, (9.81)}\; {\rm m\cdot s^{-1}} \\ &\approx 7.2\; {\rm m\cdot s^{-1}}\end{aligned}\).
if you swim with the current in a river, your speed is increased by the speed of the water; if you swim against the current, your speed is decreased by the water's speed. the current in a river flows at 0.52 m/s. in still water you can swim at 1.73 m/s.
When swimming with the current, your speed would be more than 2.25 m/s, and when swimming against the current, your speed would be more than 1.21 m/s.
Let's consider the scenario of swimming with the current first. If the current is flowing at 0.52 m/s and you can swim at 1.73 m/s in still water, your total speed when swimming with the current would be the sum of the two speeds: 1.73 m/s + 0.52 m/s = 2.25 m/s. So, when swimming with the current, your speed would be more than 2.25 m/s.
Now, let's consider the scenario of swimming against the current. When swimming against the current, your speed is decreased by the speed of the water. Therefore, your effective speed would be the difference between your swimming speed and the speed of the current.
In this case, your effective speed would be 1.73 m/s - 0.52 m/s = 1.21 m/s. So, when swimming against the current, your speed would be more than 1.21 m/s.
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12. A car has a mass of 2000 kg and accelerates at 3.0 meters per second squared. What is
the magnitude of the force acting on the car?
Question :-
A Car has a Mass of 2000 kg and Accelerates at 3.0 m/s² . What is the Magnitude of the Force acting on the Car ?Answer :-
The Force acting on the Car is 6000 Newton .Explanation :-
As per the provided information in the given question, we have been given that the Mass of the car is 2000 kg . The Acceleration is given as 3.0 m/s² . And, we have been asked to calculate the Force acting on the Car .
For calculating the Force , we will use the Formula :-
\( \bigstar \: \: \: \boxed{ \sf{ \: Force \: = \: Mass \: \times \: Acceleration \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \dag \: \: \: \sf {Force \: = \: Mass \: \times \: Acceleration } \)
\( \longmapsto \: \: \: \sf {Force \: = \: 2000 \: \times \: 3.0 } \)
\( \longmapsto \: \: \: \textbf {\textsf {Force \: = \: 6000 }} \)
Hence :-
Force = 6000 Newton .\( \underline {\rule {180pt} {4pt}} \)
A 10 kg-shopping cart is being pushed with a net force of 18 N, what is the acceleration
of the cart?
Answer:
180m/s²
Explanation:
A = Fm
A = 18(10)
A = 180m/s²
Ram has power of 550 watt. What does it mean?
Which two statements describe how ultrasound technology produces an image of a baby before it is born?
A. An image is created based on the frequency of reflected X-rays.
B. Body tissues absorb high-frequency sound waves, producing an image.
C. An image is created based on the amount of time it takes for a sound wave to return.
D. Tissues in the baby's body reflect high-frequency sound waves.
Answer:
C,D
Explanation:
an image is created based on the amont of time it takes for a sound wave to return
Tissues in the babys body reflect high-frequency sound waves
In ultrasound scanning, an image of internal organs is created based on the amount of time it takes for a sound wave to return.Thus, option C is correct.
What is ultrasound scanning?High-frequency sound waves are used in ultrasound imaging, also known as sonography, to view within the body. Real-time ultrasound imaging allows for the display of blood flowing via blood vessels as well as movement of the body's internal organs.
Contrary to X-ray imaging, ultrasonic imaging does not expose patients to ionizing radiation.A transducer (probe) is positioned either on the skin or inside a bodily orifice during an ultrasonic examination.
To allow the ultrasonic waves from the transducer to pass through the gel and into the body, a small coating of gel is placed to the skin.
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How long will it take for a 1.5A current to coat evenly a layer of copper 0.1mm thick on both sides of a 12cm x 12cm copper plate [e.C.E of copper= 0.00033g/C , density of copper 9g/cm
Answer:
Explanation:
First of all we shall calculate mass of copper to be calculated from the formula below.
mass = volume x density
volume = total surface area x thickness of layer
= 12 x 12 x 2 x .01 cm³
= 2.88 cm³
mass = 2.88 x 9 = 25.92 g .
Let time required be t s . .
charge flowing in time t = 1.5 t coulomb.
Given ,
1 coulomb deposits .00033 g of copper
1.5 t deposits .00033 x 1.5 t g of copper
So ,
.00033 x 1.5 t = 25.92
t = 52364 s
= 14.54 hours.
HELP PLEASE!!!
a= ?
v=
r=
Answer:
\(a=\frac{v^2}{r}\)
\(v=\sqrt{a*r}\)
\(r=\frac{v^2}{a}\)
Explanation:
This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r). The expression for the acceleration is already given, so simply type it as shown:
\(a=\frac{v^2}{r}\)
For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:
\(a*r=v^2\\v=\sqrt{a*r}\)
For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:
\(a*r=v^2\\r=\frac{v^2}{a}\)
what is the most commonly effective spin recovery for a straight-wing aircraft
The most commonly effective spin recovery technique for a straight-wing aircraft is the "neutralize controls, reduce power, and apply opposite rudder" method, often abbreviated as "PARE".
This involves first neutralizing the ailerons and elevator to reduce the angle of attack, then reducing the power to minimize the aerodynamic forces contributing to the spin, and finally applying opposite rudder to counteract the yawing motion and stabilize the aircraft.
Once the spin has been arrested, the aircraft can be gradually recovered by slowly increasing power and returning to level flight. It is important for pilots to be trained in spin recovery techniques to maintain safety during flight.
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When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet.
When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits retrograde motion.
What is Retrograde motion?
Retrograde motion is the apparent change in movement of any planet in the sky. It is not real such that the planet doesn't make any movement physically in its orbit.
The planet just appears to be in a movement because the relative positions of that planet and our planet, Earth and how these two planets move around the Sun.
Therefore, Retrograde motion is actually an illusion which is related to the movement of this Earth-based observer.
One familiar example occurs when an individual passes a car on a freeway, the car that passed appears to have moved backwards, relative to that individual.
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A single conducting loop with an area of 2.0 m^2 rotates in a uniform magnetic field so that the induced emf has a sinusoidal time dependence. With what angular frequency does the loop rotate?
Angular frequency does the loop rotate is 1.26 rad/s
Given:
area of conducting loop = 2.0 m^2
To Find:
angular frequency
Solution: Angular frequency (ω), also known as radial or circular frequency, measures angular displacement per unit time. Its units are therefore degrees (or radians) per second. Angular frequency (in radians) is larger than regular frequency (in Hz) by a factor of 2π: ω
T = 2π/w
(6.25-1.25) = 2π/w
5 = 2π/w
w = 2*3.14/5 = 1.26 rad/s
Hence, Angular frequency does the loop rotate is 1.26 rad/s
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Use the information in the square to answer the questions
about tin.
compare regulating the amount of light with condensing the light.
Regulating the amount of light involves controlling the brightness, while condensing the light refers to focusing and concentrating the light rays.
In physics, regulating the amount of light and condensing the light are two distinct concepts.
Regulating the amount of light involves controlling the intensity or brightness of light. This can be achieved through various methods, such as using dimmer switches or adjustable light sources. By increasing or decreasing the amount of electrical current flowing through a light source, the brightness can be adjusted accordingly. For example, dimmer switches in homes allow users to control the brightness of their lights.
Condensing the light refers to focusing or concentrating the light rays. This is often accomplished using optical devices like lenses or mirrors. These devices manipulate the path of light, causing the rays to converge into a smaller area. As a result, the light becomes more concentrated and focused. This concept is widely used in applications such as photography, where lenses are used to focus light onto the camera sensor.
While regulating the amount of light is about controlling the brightness, condensing the light is about focusing and concentrating the light rays.
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Regulating the amount of light is about controlling the overall brightness or intensity of light, while condensing the light is concerned with focusing or concentrating light beams to a smaller area or specific point.
Regulating the amount of light and condensing the light are two distinct concepts related to controlling and manipulating the intensity and distribution of light. Here is a comparison between the two:
Regulating the Amount of Light:
Regulating the amount of light refers to adjusting the intensity or brightness of light. It involves controlling the output or transmission of light to achieve desired lighting levels.
This can be done using various methods, such as dimming switches, adjustable light fixtures, or using curtains, blinds, or shades to block or filter incoming light. The objective is to create an appropriate lighting environment for different purposes, such as providing ambient lighting or creating a specific mood or atmosphere.
Condensing the Light:
Condensing the light involves focusing or concentrating light rays to a smaller area or a specific point. This is typically achieved by using optical devices such as lenses or mirrors.
The purpose of condensing light is to increase its intensity or to direct it to a specific location for enhanced illumination or focused illumination. Condensing light can be useful in applications where concentrated light is required, such as in spotlights, projectors, or laser systems.
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A 10cm long, 2cm wide wooden wedge is pushed into a soft wood block calculate the load on the soft wood if the effort applied id 30 N
PLS HURRY
Exporting agribusiness technology to developing countries is likely to increase the availability of food while reducing the stability of traditional________
who are currently the primary farming population.
Specialized technology works well in_________ where the uniformity of the crop encourages tight-focused machines rather than unspecialized machines that can be adapted for multiple tasks.
Answer:
Explanation:
Modern technology such as chemical fertilisers, pesticides, herbicides, modern agricultural machinery, artificial selection... have been used to increase food production. Development and use of chemical fertilisers on farm land à boots levels of nutrients in the soil, increasing crop yields.