A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m as shown above. Question The magnitude of the net force on the block while it is sliding is most nearly

Answers

Answer 1

The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.

What is magnitude?Magnitude in physics typically refers to a size or quantity. Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. What is Frictionless plane?

The Plane by which no opposite force is applied on the sliding or moving object is termed as  Frictionless plane.

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Related Questions

Which statement accurately describes surface tension?

A.
Attractive forces between molecules at the surface cause a liquid to resist spreading out.
B.
A liquid with larger molecules resists movement more than a liquid with smaller molecules does.
C.
A material with relatively weak bonds between its particles can be shaped into a thin sheet.
D.
A material slows or completely blocks the flow of electrons through it.

Answers

Answer:

A. Attractive forces between molecules at the surface cause a liquid to resist spreading out.

Explanation:

Surface tension can be defined as a property of liquid which makes its surface to resist an external force, as a result of the cohesive nature of its molecules.

This ultimately implies that, the surface tension of a liquid is mainly caused by the cohesive forces existing between its molecules.

Hence, the statement which accurately describes surface tension is that, the attractive forces between molecules at the surface cause a liquid to resist spreading out. Also, the attractive force is due to electrostatic forces and it reduces the surface area of a liquid.

Mathematically, surface tension is given by the formula;

Surface tension = surface force)/length the force acts

γ = F /d

Where;

Γ is the Surface tension.

F is the force which applies to the liquid.

d is the length where the force acts

Answer:

Attractive forces between molecules at the surface cause a liquid to resist spreading out.

Explanation:

Imagine you want to watch a show, and an ad comes on beforehand. The ad is from Chic Shampoo. The voiceover says, “Shampoo Chic—we're unique!”

In this scenario, you are the:

Responses

message


stereotype

receiver


sender

Answers

In this scenario, you are the Receiver.

One possible scenario is moving to a city. The most likely scenario is he returns to school in the fall. In the best-case scenario, I'll finish the work by tomorrow. They looked at each other and weighed the situation. the sequence of events. chain of events. the course of the event. series of expansions. Your scenario is very similar to your situation, but it hasn't happened yet, and it may not happen at all.

The real world is where you actually have to live and the situations you actually have to deal with. Real-world examples are the life you are living now and the life you want to live someday. Almost any situation in which an unknown quantity exists can be described by a linear equation. To look at income over time, calculate mileage rates, and forecast profits. Many people use linear equations on a daily basis, even if they don't draw line graphs and do the calculations in their heads.

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Answer:

Receiver.

Explanation:


Activity A:
Surviving a crash
Get the Gizmo ready
• Click Reset (?).
. On the DESIGN tab, check that Sedan is selected
Introduction: Modern vehicles contain features designed to keep passengers safe in a crash.
The crumple zone in the front of the car slows the car gradually and increases stopping time.
The safety cell is a rigid cage that prevents passengers from being crushed. Inside, seat belts
and airbags prevent the driver from hitting the windshield, steering wheel, or dashboard.
Question: How does a crumple zone help protect a passenger?
1
Make a hypothesis: On the DESIGN tab, look at the parameters you can control. What
settings do you think will make the safest car? Set up the Gizmo, and then fill in below.
Crumple zone length:
Crumple zone rigidity:
Safety cell rigidity:
Seat belt present?
If present, seat belt stiffness:
Air bag present?
If present, air bag rigidity:

Answers

The crumple zone help protect a passenger from injury by converting some of the kinetic energy possessed by the car into a controlled deformation, or crumpling when there is a crash.

What is impact?

The term impact refers to a large force that acts for a short time. Passengers in a vehicles sustain injuries after an accident due to the high impact of the crash.

As such, the crumple zone help protect a passenger from injury by converting some of the kinetic energy possessed by the car into a controlled deformation, or crumpling when there is a crash.

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A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?​

Answers

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

A box puts a pressure of 50 N/m2 on an area of 0.25 m2. Find the force of the box on the floor.

Answers

A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)

What is pressure and types?

Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.

Using the formula Force = Pressure × Area

given Pressure = 50 N/\(m^{2}\)

area = 0.25 \(m^{2}\)

Substituting the values ,

Force = 12.5 Newton

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The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1.
Car 2
From the frame of reference of car 2, what is the velocity of car 1?
OA. 70 m/s east
B. 20 m/s west
OC. 70 m/s west
OD. 20 m/s east
SUBMIT

Answers

The velocity of the car 1 can be seen from the calculation as 20 m/s West

What is relative motion?

A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.

The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.

We can see that the velocity of the car 1 is;

45 m/s - 25 m/s

= 20 m/s West

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The three pairs of metal same-size spheres have different charges on their surfaces, as indicated. Each pair is brought together, allowed to touch, and then separated. Rank from greatest to least the total amount of charge on the pairs of spheres after separation.
A) +6 +2
B) +6 -2
C) +6

Answers

After separation, the pairs of spheres' total charges will be in the following order: Qa -> Qc -> Qb.

How to find The Calculation?

As specified in the query, here

Each pair is introduced, allowed to touch, and then separated.

which refers to payment via sharing.

The charge by sharing formula is Q = Q1 + Q2 / 2.

As a result, Pair A

Qa = +6+(+2)/2 = 4 represents the total charge for each pair.

Pair B

Qb = +6+(-2)/2 =2.

Pair C

Qc = +6+(0) / 2 =3.As a result, Qa -> Qc -> Qb will be the order of the total amount of charge on the pairs of spheres after separation, from greatest to least.

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There is a +1.0 mC charge at the origin and a +3.0 mC charge at (x, y) =(2.0 m, 0), a. Find the force on the +3.0 mC charge. b. Calculate the electric field at (x, y) = (1.00 m, 0.50 m). c. Find a point where the electric field is zero (other than at infinity). d. What is the potential at the point found in part c?

Answers

a.  The force on the +3.0 mC charge is 1.35 x 10^-6 N.

b.   The electric field at (x, y) = (1.00 m, 0.50 m) is  5.49 x 10^5 N/C

c. The point where the bc is zero (other than at infinity) is located on the line that connects the two charges and at the midpoint of the line segment connecting them.

d.  The potential at the point found in part c is at point zero

What is electric field?

An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

a.  we need to use Coulomb's law, which states that the force between two charges is given by:

F = k * (q1 * q2) / r^2

F = k * (q1 * q2) / r^2 = 8.99 x 10^9 Nm^2/C^2 * (1.0 x 10^-3 C * 3.0 x 10^-3 C) / (2.0 m)^2 = 1.35 x 10^-6 N

b. To calculate the electric field at (x, y) = (1.00 m, 0.50 m), we use the equation for the electric field due to a point charge:

E = k * q / r^2

The distance from the point charge is:

r = sqrt((1.00 m - 2.0 m)^2 + (0.50 m - 0 m)^2) = sqrt(3.25 m^2) = 1.8 m

Therefore, the electric field at (x, y) = (1.00 m, 0.50 m) is:

E = k * q / r^2 = 8.99 x 10^9 Nm^2/C^2 * (3.0 x 10^-3 C) / (1.8 m)^2 = 5.49 x 10^5 N/C

c. This point is located on the line that connects the two charges and at the midpoint of the line segment connecting them.

d.  At the point found in c, the electric field is zero, so the work done to move a test charge from infinity to that point is also zero.

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Give the SI base unit of each of these quantities Enter the abbreviation rather than the name of the unit: time: mass: Kg length:m

Answers

Time: s (second)

Mass: kg (kilogram)

Length: m (meter)

What are the SI units?

The SI units (International System of Units) are a standard system of measurement used in science, engineering, and many other fields. They provide a universal language for expressing and comparing measurements. The SI units are based on seven fundamental physical quantities, and each of these quantities is associated with a specific base unit, which is defined independently of any other unit.

Seven base units of the SI system are:

Length: meter (m)

Mass: kilogram (kg)

Time: second (s)

Electric current: ampere (A)

Temperature: kelvin (K)

Amount of substance: mole (mol)

Luminous intensity: candela (cd)

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A marble rolls with a speed of 15 m/s and has a momentum of 0.15 kg*m/s. What is its mass?

Answers

Answer:

m = 0.01 kg

Explanation:

Given that,

Momentum of the marble, p = 0.15 kg-m/s

Speed of the marble, v = 15 m/s

We need to find its mass. We know that,

Momentum, p = mv

Where

m is the mass

\(m=\dfrac{p}{v}\\\\m=\dfrac{0.15}{15}\\\\m=0.01\ kg\)

So, the mass of the marble is equal to 0.01 kg.

A pingpong ball has 2 kg/s of momentum when
thrown 8 m/s. Find the mass of the ball.

Answers

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

The drawing shows an arrangement in which a block (mass = 21.6 kg) is held in position on a frictionless incline by a cord (length = 0.700 m). The mass per unit length of the cord is 0.960 x 10-2 kg/m so the mass of the cord is negligible compared to the mass of the block. The cord is being vibrated at a frequency of 142 Hz (vibration source not shown in the drawing). What is the maximum value of the angle ?in degrees at which a standing wave pattern exists on the cord?

Answers

The value of θ does not exist for the given data in the above problem as the sin θ value is not in range.

Given that,

Frequency of the cord = 142 Hz

Mass of the block = 21.6 kg

Length of the cord = 0.7 m

Density μ = 0.96* 10⁻² kg/m

The tension opposing the movement of the block is given by,

T = W sinθ = m* g sin θ = 21.6* 9.81 sin θ = 211.9 sin θ ----(1)

We know the formula for the frequency of the stretched string as,

f = 1/(2L)* (√T/μ)

Substituting the values in the above equation, we have,

142 = 1/(2* 0.7)* [√(211.9*sin θ)/(0.96* 10⁻²)]

142 = 1/(1.4)* [148.57√sin θ]

(142* 1.4)/148.57 = √sin θ

√sin θ = 1.34

sin θ = 1.8

The range of sin θ -1 ≤ y ≤ 1.

So, the θ does not exist.

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Hello! Would you please help me with this physics problem?

Hello! Would you please help me with this physics problem?

Answers

We will have the following: since the collision is perfectly elastic then:

\(m_1v_1+m_2v_2=m_!v_3+m_2v_4\)

Now, we know that in an elastic collision the bodies won't have a net transfer of energy and the directions will be opposite but with the same magnitude:

So, the final velocities are:

10 kg object will have a final velocity of -2 m/s. And the 2 kg object will have a final velocity of 4m/s.

[We are assuming that the directions are positive for the initial direction of the 10 kg object and the 2kg mass initial velocity marks the opposite direction]

The same collision as in Question 5 takes place, only this time the car and the truck bounce off each other completely elastically What are the final velocities of the car and truck just after the collision?

Answers

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

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write any two physical hazard occuring in the late choldhood​

Answers

Answer:

Hazards during late childhood

Health Problems: Chronic health ailments like T.B., Pneumonia etc will hinder the child's motor abilities.Accidents: School age children are more adventurous in nature, they run fast, play hard, ride bicycles and scooters and engage in a variety of sports.

A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.

Figure 4.29
(a) Calculate the minimum force F he must exert to get the block moving.
40.873

(b) What is its acceleration once it starts to move, if that force is maintained?


m/s2

A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over

Answers

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

Minimum force to be applied

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

μ(s) is coefficient of static frictionm is mass of the blockg is acceleration due to gravity

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

Acceleration of the block

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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g A series circuit contains a 1.0-k Ω resistor, a 5.0-mH inductor, and an ideal 25-V power supply. What is the time constant for the circuit?

Answers

Hi there!

Recall the equation for an LR circuit time-constant:
\(\tau = \frac{L}{R}\)

L = Inductance (H)

R = Resistance (Ω)

Plug in the given values.

\(\tau = \frac{0.005}{1000} = 0.000005 s = \boxed{\text{5 } \mu s}\)

A rope pulls a 20 kg box up. If the tension in the rope is 275 N, what is the acceleration of the box?

Answers

Answer:

The answer is 13.75 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{275}{20} = \frac{55}{4} \\ \)

We have the final answer as

13.75 m/s²

Hope this helps you

A picture of a basketball on the left and a bowling ball on the right. The bowling ball is inside a white box.
Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?

Answers

The bowling ball requires more force to roll than the basketball. This is because the bowling ball has more mass than the basketball, and therefore more resistance to motion.

Why force is related to mass?

Force is related to mass because the force required to move an object is proportional to its mass. This relationship is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the force applied and inversely proportional to its mass. In mathematical form, this relationship is expressed as:

F = ma

The amount of force required to move an object is proportional to its mass and its velocity. Since the bowling ball has more mass, it requires more force to be applied in order to get it moving, and to keep it moving at a constant velocity. Additionally, because the bowling ball is inside a white box, its rolling friction is higher, further increasing the amount of force required to move it.

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A car travels from point A to B in 3 hours and returns back to point A in 5 hours. Points A and B are 150 miles apart along a straight highway. Calculate: a) Total distance and total displacement (in mile and meter) b) Average speed and Average velocity (in mile/hr and m/s​

Answers

The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

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sam exerts a force of 65 N on a lawn mower with a mass of 25 kg. which formula can be used to calculate the acceleration of a lawn mower

Answers

Answer:

F = ma - with this you will get 2.6 m/s^2

Explanation:

Use this formula to get the acceleration...

where F is force, M is mass and A is acceleration

by using this we get...

65 = 25 * a

so, a = 65/25

Therefore, the acceleration is 2.6 m/s^2

Hope that helped :)

The acceleration of a lawn mower will be 2.6 m/s². It is the ratio of force and the mass.

What is acceleration?

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The given data in the problem is;

The force act on a lawn mower,\(\rm F = 65 \ N\)

Mass of  lawn mower,\(\rm m = 25 kg\)

The acceleration of a lawn mower is,\(\rm a = ?\)

Acceleration, is found as the ratio of force and the mass.

\(\rm F= ma \\\\ a = \frac{F}{m} \\\\ a= \frac{65}{25} \\\\ a = 2.6 \ m/s^2\)

Hence, the acceleration of a lawn mower will be 2.6 m/s².

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_3) Which of the following is the unit for forces?

Answers

N(Newton) or Kgm/s^2

If the horizontal range and the max height of a body projected at an angle titre to the horizontal is K and Q respectively. Show that the muzzle velocity Vo is given by: Vo=√[2gQ + K²/8Q]​

Answers

Explanation:

Recall that

\(K = \dfrac{v_0^2\sin2\theta}{g}\:\:\:\:\:\:\:\:\:(1)\)

and

\(Q = \dfrac{v_0^2\sin^2\theta}{2g}\:\:\:\:\:\:\:\:\:(2)\)

From Eqn(2), we can write

\(\sin\theta = \sqrt{\dfrac{2gQ}{v_0^2}}\:\:\:\:\:\:\:\:\:(3)\)

Using the identity \(\sin\theta = 2\sin\theta \cos\theta\), we can rewrite Eqn(1) as

\(\dfrac{gK}{2v_0^2} = \sin\theta \cos\theta\)

Squaring the above equation, we get

\(\dfrac{g^2K^2}{4v_0^4} = \sin^2\theta \cos^2\theta\)

\(\:\:\:\:\:\:\:\:\:=\sin^2\theta(1 - \sin^2\theta)\:\:\:\:\:\:\:(4)\)

Use Eqn(3) on Eqn(4) and we will get the following:

\(\dfrac{g^2K^2}{4v_0^4} = \dfrac{2gQ}{v_0^2}(1 - \dfrac{2gQ}{v_0^2})\)

This simplifies to

\(\dfrac{gK^2}{8v_0^2Q} = 1 - \dfrac{2gQ}{v_0^2}\)

Rearranging this further, we get

\(1 = \dfrac{2gQ}{v_0^2} + \dfrac{gK^2}{8v_0^2Q}\)

Putting \(v_0^2\) to the left side, we get

\(v_0^2 = 2qQ + \dfrac{gK^2}{8Q}\)

Finally, taking the square root of the equation above, we get the expression for the muzzle velocity \(v_0\) as

\(v_0 = \sqrt{2gQ + \dfrac{gK^2}{8Q}}\)

Were is the computer located

Answers

Answer:

where u put it last time or retrace ur steps to where u last put it

In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.

Answers

The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.

This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point  in the sunlight is equal to the pressure at any other point not in the sunlight.

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Your washer has power of 450 watts, and your dryer has a power of 3000watts. How much energy do you use to clean a load of clothes in 1 hour ofwashing and 1.5 hours of drying?OA. 3.11 x 107 JOB. 1.78 x 107 JOC. 5.17 x 10³ JOD. 2.97 x 10³ J

Answers

ANSWER

B. 1.78 x 10⁷ J

EXPLANATION

Given:

• The power of the washer, P₁ = 450 W

,

• The power of the dryer, P₂ = 3000 W

,

• The time needed to wash one load of clothes, t₁ = 1 hour

,

• The time needed to dry those clothes, t₂ = 1.5 hours

Energy is the product of power and time,

\(E=P\cdot t\)

If the power is given in watts, we have to convert the time to seconds, so that the energy is in Joules. Knowing that 1 hour has 3600 seconds,

\(\begin{gathered} t_1=1hour\cdot\frac{3600s}{1hour}=3600s \\ \\ t_2=1.5hour\cdot\frac{3600s}{1hour}=5400s \end{gathered}\)

So the energy needed to wash the clothes is,

\(E_1=P_1\cdot t_1=450W\cdot3600s=1.62\cdot10^6J\)

And the energy needed to dry them,

\(E_2=P_2\cdot t_2=3000W\cdot5400s=16.2\cdot10^6J\)

So, the total energy needed for the whole cycle is,

\(E=E_1+E_2=1.62\cdot10^6J+16.2\cdot10^6J=(1.62+16.2)\cdot10^6J=17.82\cdot10^6J=1.78\cdot10^7J\)

Hence, the energy needed to wash the clothes for 1 hour and dry them for 1.5 hours is 1.78 x 10⁷ J.

(1) Thevelocity of a plantier is given by V(t) = 20t² - 100€ + 5got a, when will the accteration of a particle is zero by what the velocity of the Particles when its acceleration is zero​

Answers

Answer:

I really don't want to go out for a week and I deserve to be wit me she said that she would have been able even better then again this year moma and she was the one that was earlier than you and my parents are going through a tough time and it was broken down into the last time I was coming from but I see an feel a lot of hate

Explanation:

no exceptions

please help. ill make you BRAINLIEST

please help. ill make you BRAINLIEST

Answers

Answer:

because well I dont even know sorryy but you got this

in first equation of motion at denotes​

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Answer:

Names of the Equations of Motion

1 The First Equation of Motion is, v=u+at is known as velocity – time relation. 2 The Second Equation of Motion is, s=ut+12at2 is known as position – time relation.

A bat emits a sonar sound wave
(343 m/s) that bounces off a
mosquito 8.42 m away. How
much time elapses between
when the bat emits the sound
and when it hears the echo?
(Unit = s)

Please help I am very confused with this topic

Answers

The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

Learn more: https://brainly.com/question/10128949

Answer:

0.0491

Explanation:

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