The length of the sides of the cube that has twice the mass of gold would be approximately 1.26 cm.
The density of gold is 19.3 g/cm³. Therefore, the volume of the gold cube is:
Volume = mass/density = 19.3 g / 19.3 g/cm³ = 1 cm³
Since the cube is 1 cm long on each side, the volume is equal to the length cubed:
1 cm³ = (1 cm)³
To find the length of a cube that has twice the mass of gold, we can use the relationship between mass, density, and volume:
mass = density x volume
If the mass is doubled, then we have:
2 x mass = density x volume
We know the density of gold, and we know that the volume of the new cube must be twice the volume of the original cube.
2 x mass = density x 2 x (1 cm)³
Solving for the length of the sides of the new cube,
(Length of sides)³ = 2 x (1 cm)³
Length of sides = (2 x (1 cm)³)^(1/3) = 1.26 cm (approx.)
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When velocity is negative and acceleration is negative, what happens to the object's motion?
Answer:
Speeds up at a negative direction
Explanation:
El peso normal de un estudiante de secundaria es 725 N y el área de los dos zapatos que usa es de 412 cm2 . La presión medida que sus zapatos ejercen en el suelo es
Answer:
Presión = 175,97 N/m²
Explanation:
Dados los siguientes datos;
Peso del alumno (fuerza) = 725N
Área de zapatos = 412 cm² a metros cuadrados = 412/100 = 4.12 metros
Para encontrar la presión, usaríamos la siguiente fórmula;
Presión = fuerza / área
Presión = 725 / 4.12
Presión = 175,97 N/m²
An equal amount of a gas is held in two identical containers. The temperature of container 1 is 15°C and the temperature of container 2 is 30°C. In which container will the pressure be lowest? (Assume there is nothing else inside the containers.)
Answer:
Container 1
Explanation:
The reason why there will be less pressure in container 1 is that it's colder than container 2. You must have learned right, that a colder thing has its molecules less moving, and they don't expand, instead they actually decrease in volume? In the same way, it's applied to gas also. So that's why, because container 1 has 15C temperature, which is half less than container 2's 30C, that's why, container 1 has less pressure than Container 2.
So hence, container 1 has less pressure than container 2 because of its a lower temperature, which doesn't make the molecules expand, and move around that much.
THANKS!
A car has a mass of 1000 kg. It is driving to the right.
Draw a free body diagram showing the forces acting on it.
Find it’s weight on Earth.
How do I even draw a body diagram? Please help.
Answer:
Explanation:
What is a free body diagram?
Answer: a force diagram is a graphical illustration used to visualize the applied forces and resulting reactions on a body in a given condition
Drawing a free-body diagram for this problem
Answer: Look at the attached picture, ask me any questions if you are still confused. It is a little messy since I didn't have my pen.
Find its weight on Earth
Answer: The weight is dependent on the mass of the object and the gravitational constant on the planet. The gravitational constant, in this case, is 9.8.
so the weight = mass * gravitational constant = m * g = 1000 * 9.8
= 9800 N
Hope that helps!
A coffee maker has a power rating of 1.4 kW. How much energy will this coffee maker transfer every second?
Answer:
The power rating of the coffee maker is 1.4 kW, which means that it uses 1.4 kilowatts of power when it is in operation. To find out how much energy it will transfer every second, we can use the formula:
Energy transferred = Power × Time
Since we want to know the energy transferred every second, we can set the time to 1 second. Therefore:
Energy transferred per second = Power × 1 second
Energy transferred per second = 1.4 kW × 1 second
We can simplify this by converting the unit of power from kilowatts to watts:
Energy transferred per second = 1,400 watts × 1 second
Energy transferred per second = 1,400 joules
Therefore, the coffee maker will transfer 1,400 joules of energy every second.
Please help !!
Which of the following statements regarding orbits is true?
A. A satellite moves in an elliptical orbit with the central body at one
focus
B. The Sun and a planet are at the two foci of an orbit.
c. In an orbit, the satellite and the central body are the two foci of the
ellipse.
D. In an elliptical orbit, there is one focus and the satellite is located
there.
The true statement about an orbit is that the sun and a planet are at the two foci of an orbit. Hence, option B is correct.
What is an orbit?An orbit is a curved path taken by an object in celestial mechanics, such as the path taken by a planet around a star, a natural satellite around a planet, or an artificial satellite around an object or location in space, such as a planet, moon, asteroid, or Lagrange point.
Ordinarily, the term "orbit" refers to a trajectory that repeats itself periodically, though it can also apply to a non-repeating trajectory. Kepler's principles of planetary motion roughly predict that planets and satellites have elliptic orbits, with the center of mass orbiting at a focal point of the ellipse.
Hence, this concludes that option B is correct.
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Scientist Jordan makes a discovery and publishes the results for other scientists to read. Scientist Leesha tries to repeat the experiment and cannot make it work. Her results are also published. Scientist Jordan looks at his data again and finds that the discovery only works under certain conditions. He publishes the change. Now scientist Leesha repeats the new method and finds the same results as Jordan, but another scientist, Winslow, gets different results. What does this story demonstrate? A. that scientific knowledge is impossible to obtain B. that scientific knowledge results from a lot of debate and confirmation C. that scientific knowledge is developed by individual scientists in isolation D. that scientists are really good at arguing
Answer:
Answer choice B!
Explanation:
Study Island work
Answer:A
I DID THIS ON STUDYILSLAND
Please write in complete sentences.
How does density affect refraction?
Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from the air through a diamond.
answer both questions
(1.) The Phenomena of Refraction Occurs when a Ray (Here Light) enters a Relatively Denser or Rarer Medium and Due to the Change in Density, the Speed of the Incident Ray Decreases or Increases Respectively.
(2.) If a light ray projected through a diamond, the light would refract drastically.
If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?
Which has more momentum a 100 kg kid riding a bike 10m/s or a 5000 kg truck barley rolling at 0.1 m/s
Answer:
The momentum of bike is more.
Explanation:
Given that,
Mass of the kid, m = 100 kg
Speed of the bike, v = 10 m/s
The momentum of the kid is given by :
p = mv
So,
p = 100 kg × 10 m/s
p = 1000 kg-m/s
Mass of the truck, m = 5000 kg
Speed of the truck, v = 0.1 m/s
The momentum of the truck is given by :
p = 5000 kg × 0.1 m/s
= 500 kg-m/s
So, the momentum of the kid riding a bike is more than that of the truck.
What do you mean by electromagnetic induction?
What do you mean by electromagnetic induction ?
Well Explained Answer : -Discovery : -
A British scientist Michael Faraday and an American scientist Joseph Henry discovered the phenomenon of electromagnetic induction in 1831 independently.
Definition / Meaning : -
The production of electricity from magnetism is called electromagnetic induction.
Or ,
Electromagnetic induction is the phenomenon of the production of an induced current in a coil placed in a region where the magnet field changes with time
For Example : -
(i) If a bar magnet is moved in and out of coil of wire , even then an electric current is produced. This is an example of electromagnetic induction.
(ii) Another example , when a straight wire is moved up and down rapidly between the two poles of a horseshoe magnet , then an electric current is produced in the wire. This is also an example of electromagnetic induction .
#\( \rm{ \bold{Keep \: Learning}}\)Electromagnetic induction denotes to producing electricity using magnetic field or magnetism.
This is the process or phenomenon of production of induced induced current in a region where magnetism changes with respect to the time.
It was discovered by great scientist Michael Faraday.
calculate the distance travelled by a car moving with 40 m/s velocity in 2 hours
Answer:
14,400m
Explanation:
The formula for calculating speed is S=D/T.
S=speed( in meters per second- m/s)
D=distance(in meters)
T=time( in seconds)
For our case:
S=40m/s
D=?
Time=2 hours=60min x 60 sec=3600seconds
Now make D the subject.
D=S x T
D=4m/s x 3600s=14,400m
Therefore our answer is
14 400 m or 14.4 km
in a michelson interferometer, light of wavelength 632.8 nm from a he-ne laser is used. when one of the mirrors is moved by a distance d, 8 fringes move past the field of view. what is the value of the distance d?
In a Michelson interferometer, light of wavelength 632.8 nm from a He-Ne laser is used. When one of the mirrors is moved by a distance d, 8 fringes move past the field of view.
The electric field in a parallel plate capacitor has a magnitude of 1.40 x 10^4 V/m.
The electric field in a parallel plate capacitor is given by the formula
E = σ / ε0where E is the electric field, σ is the surface charge density, and ε0 is the permittivity of free space.
σ = ε0 x E
E = 1.40 x 10^4 V/m (given)
ε0 = 8.85 x 10^-12 C^2/Nm^2 (given)
σ = ?Plugging in the values we get,
σ = ε0 x E
= 8.85 x 10^-12 x 1.40 x 10^4
= 1.239 x 10^-7 C/m^2
Therefore, the surface charge density on the positive plate is 1.239 x 10^-7 C/m^2.
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Air was mixed with small quantity of iodine and made to flow with a velocity of 5. 25m/s2, 3cm diameter. Determine the mass transfer
The mass transfer rate of iodine in this flow is approximately 0.0052 kg/s.
Assuming that the concentration of iodine in the air is constant and uniform, we can use Fick's law of diffusion to calculate the mass flux:
J = -D (dC/dx)
where J is the mass flux in kg/(m²·s), D is the diffusion coefficient in m²/s, C is the concentration of iodine in kg/m³, and x is the distance in meters.
The diffusion coefficient for iodine in air at room temperature is approximately 1.16 × 10^-5 m²/s.
Assuming that the flow is fully developed and laminar, we can use the Hagen-Poiseuille equation to calculate the volumetric flow rate:
Q = (π/4)D²v
where Q is the volumetric flow rate in m³/s, D is the diameter of the pipe in meters, and v is the velocity of the flow in m/s.
Substituting the given values,
Q = (π/4)(0.03 m)²(5.25 m/s) ≈ 0.0043 m³/s
To convert the volumetric flow rate to a mass flow rate, we need to multiply by the density of the air. Assuming that the air is at room temperature and atmospheric pressure, we can use the ideal gas law to calculate the density:
ρ = P/(RT)
where ρ is the density in kg/m³, P is the pressure in Pa, R is the gas constant, and T is the temperature in Kelvin.
Substituting the values for room temperature and atmospheric pressure, we get:
ρ = (101325 Pa)/[(8.314 J/(mol·K))(293 K)] ≈ 1.20 kg/m³
Multiplying the volumetric flow rate by the density, we get:
ṁ = Qρ ≈ 0.0052 kg/s
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An object is 25.0 cm away from a concave lens of focal length -5.0cm If the height of the object is 2.7 cm, what is the image height?
The height of the image is 0.54cm
To solve this problem, we employ the thin lens equation:
1/f = 1/do + 1/di
where f denotes focal length, di denotes image distance, and do denote object distance.
We begin by solving for di, which gives us the image distance and height:
1/di = 1/f - 1/do
Substituting the values from the problem yields:
1/di = 1/-5 - 1/25
1/di = -0.2
di = -5 cm
The image is virtual and vertical, as indicated by the negative sign above.
The magnification formula can then be used to get the image height:
m = -di/do
Substituting the values yields:
m = -(-5)/25 = 0.2
Because the image is virtual, we ignore the negative sign above and take the absolute value of magnification:
|m| = 0.2
Lastly, the image height is calculated by multiplying the object height by the magnification:
|m| x object height = image height
height of image = 0.2 x 2.7 cm
Height of image = 0.54 cm
As a result, the image height is 0.54 cm.
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obtain expression for effective ressistence of three resistors R1,R2,AND R3 are conected in series to 6v battery through voltmeter and ammeter
Explanation:
If they are in a series circuit they just add together
Rtotal = R1 + R2 + R3
there is some small resistance in the ammeter and the battery too (these would add to the total ) if you want to be totally correct.
Using the Position vs. time Graph below, showing the motion of two cyclists (Cyclist A and Cyclist B) answer the following question.Do the two cyclists have the same velocity at t = 3 seconds?
Using the information depicted on the distance - time graph, the slope of the graph is could be used to infer the velocity of each cyclist. Hence, cyclist A and B do not have the same velocity at 3 seconds.
The steepness of slope on the distance - time graph gives the velocity of the cyclist. At time, t = 0 ; the cyclist A has a greater slope than cyclist B. Hence, the velocity of the cyclists is different.
Therefore, the cyclists do not have the same velocity at time, t = 3 seconds.
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Explain what happen to pressure exerted by air in the tyre if the temperature of tyre increases
Answer:
See the answer below
Explanation:
According to Amonton's law, the pressure of a gas is directly proportional to the temperature of its molecules given that the volume remains constant.
Hence, if the temperature of a tyre increases, heat is transferred to the air molecules within the tyre leading to an increase in the air temperature. The air thus exerts more pressure on the tyre in agreement with Amonton's law.
the energy of an object as it is in motion is defined as
The energy of an object in motion is called kinetic energy
Kinetic energy is defined as the energy possessed by an object due to its motion. The amount of kinetic energy an object has is directly proportional to its mass and the square of its velocity. Mathematically, the formula for kinetic energy is:
Kinetic energy = 1/2 x mass x velocity^2
Where:
Mass (m) is the mass of the object in kilograms (kg)
Velocity (v) is the velocity of the object in meters per second (m/s)
Kinetic energy is a scalar quantity, which means it has only magnitude and no direction. It is measured in joules (J) in the SI unit system.
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Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
a sim,ple elctrical ciurucuiot contains a battery a light bulb and a properly copnnected ammeter the ammeter has a very low internal resistance because it is connected in
In a simple electrical circuit, if it contains a battery, a light bulb, and a properly connected ammeter, the ammeter has a very low internal resistance because it is connected in series with the circuit.
An electrical circuit is made up of a combination of resistors, voltage sources, and current sources that are interconnected in a closed loop. It is used to generate an electric current in a complete circuit and can be as straightforward as a battery connected to a bulb or as complicated as a full-scale electronic circuit.
Ammeters are measuring devices that are used to measure current in a circuit. The ammeter should be connected in series with the circuit to allow current to flow through it. An ammeter with a very low internal resistance should be used since any extra resistance in the ammeter can change the current being measured.
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Mr. Seifert needs to push a cardboard box down the hallway for Ms. Wang. The box has a mass of 40 kg and he is pushing it with an acceleration of 2 m/s/s. Because the cardboard does not slide easily, there is a friction force of 25 Newtons acting on the box to the LEFT. How much force is Mr. Seifert applying to the box to move it forward to the RIGHT?
Answer:
105N
Explanation:
force = mass x acceleration
force without the 25N = 40 x 2
= 80N
On top of this, he has to counteract the 25N so the actual force is 80N + 25N which is 105N
What is the focal length of a lens if an object placed 3.28 cm from the lens produces an image that is 1.91 cm in front of the lens?0.828cm-4.57cm-0.219cm1.21cm
Using lens equation:
\(\begin{gathered} \frac{1}{f}=\frac{1}{d_i}+\frac{1}{d_o} \\ where: \\ di=1.91 \\ d_o=3.28 \\ so: \\ \frac{1}{f}=\frac{1}{1.91}+\frac{1}{3.28} \\ so: \\ f\approx1.21cm \end{gathered}\)Answer:
1.21 cm
Can prolonged exposure to highly intense infrared light cause electrons to be ejected from a clean metal surface?
Infrared light doesn't have enough energy
electrons do not eject until the threshold frequency is reached, even after prolonged exposure; once the threshold frequency is reached, ejections take place immediately - supports a one to one relationship between the electrons and other particle
hypothesized that the energy radiated from a heated object, such as stove element or a light bulb filament, is emitted in discrete units, or quanta
No, prolonged exposure to highly intense cannot infrared light cause electrons to be ejected from a clean metal surface because Infrared light doesn't have enough energy. Option A is correct.
According to Einstein's photoelectric effect, prolonged exposure to highly intense infrared light cannot cause electrons to be ejected from a clean metal surface. The electrons do not eject until the threshold frequency is reached, even after prolonged exposure; once the threshold frequency is reached, ejections take place immediately and support a one to one relationship between the electrons and other particle.
The photoelectric effect is based on the hypothesis that the energy radiated from a heated object, such as a stove element or a light bulb filament, is emitted in discrete units, or quanta. The minimum energy required to eject an electron is determined by the threshold frequency. Infrared radiation is of lower frequency and cannot provide sufficient energy to overcome the threshold frequency.
Therefore, even if infrared radiation is exposed for a longer duration, electrons will not be ejected out of a clean metal surface. Thus, prolonged exposure to highly intense infrared light cannot cause electrons to be ejected from a clean metal surface.
Hence, Option A is correct.
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In a food chain, the flow of energy and matter are depicted with an _____
Answer:
flujo de energia
Explanation:
Identify the conditions for an inelastic collision in a closed system. Check all that apply. a. Energy is conserved. b. Momentum is conserved Kinetic energy is conserved. c. Objects always stick together after an inelastic collision. d. One object may be stationary before an inelastic collision.
b. Momentum is conserved.
c. Objects always stick together after an inelastic collision.
d. One object may be stationary before an inelastic collision.
In an inelastic collision, there are certain conditions that apply to the collision itself and the behavior of the objects involved. Let's examine each option in detail:
a. Energy is conserved: In an inelastic collision, energy is not conserved. Some energy is typically lost in the form of heat, sound, or deformation of the objects involved. This loss of energy is due to the internal forces and interactions within the objects during the collision.
b. Momentum is conserved: Conservation of momentum is a key characteristic of an inelastic collision. In an inelastic collision, the total momentum of the system before the collision is equal to the total momentum after the collision. This means that the sum of the individual momenta of the objects involved remains constant.
c. Kinetic energy is conserved: Kinetic energy is not conserved in an inelastic collision. As mentioned earlier, some of the initial kinetic energy is transformed into other forms of energy, such as heat or deformation. The total kinetic energy after the collision is generally less than the total kinetic energy before the collision.
d. Objects always stick together after an inelastic collision: In an inelastic collision, the objects involved may stick together or deform upon impact. However, it is not a universal rule that objects always stick together after an inelastic collision. The degree of stickiness or deformation depends on the specific properties of the objects and the nature of the collision.
Therefore, the correct conditions for an inelastic collision in a closed system are:
- Momentum is conserved.
- Objects may stick together or deform after the collision.
- One object may be stationary before the collision.
It's important to note that these conditions may vary depending on the specific scenario and the nature of the objects involved in the collision.
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Answer:
Energy is conserved.
Momentum is conserved
One object may be stationary before an inelastic collision.
Explanation:
Are carbon compounds rigid and strong
A ball rolls off the top of the roof of a building that is 13 meters tall. Calculate the amount of time it takes for it to hit the ground.
Answer:
The ball takes \($t=1 \cdot 917sec$\) to hit the ground.
Explanation:
• The second equation of motion represents the total distances travelled by an object in a time interval of \($\Delta t$\) with an initial speed of \($u$\) and acceleration \($a$\).
• To find the time, ball takes to hit the ground, use the formula: \($$s = ut + \frac{1}{2}a{t^2}$$\)
Where, \($t$\) is time, \($u$\) is initial velocity, \($a$\) is acceleration and\($s$\) is displacement.
• In this case, \($a = g = 9 \cdot 8m/se{c^2}$\).
• Placing the value of the given initial velocity, \($u=0cm/s$\) and displacement,\($s = 13m$\) in the above formula.
\(& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\\)
\(& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]\)
• Hence, ball takes \($t=1 \cdot 917sec$\) to hit the ground.
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A lever of length 1m has been used to lift a load of 600N by applying an effort of 200N. If load is at 20cm from fulcrum, calculate mechanical advantages, velocity ratio and efficiency
solve numerical problem
Answer:
1) The Mechanical Advantage of the lever is 3
2) The velocity ratio of the lever is 4
3) The efficiency of the lever is 75%
Explanation:
A lever is a simple machine that is used to lift a heavy load with a little effort or force
The mechanical advantage is the ratio of the force output to the force input
The given parameters of the lever are;
The length of the lever = 1 m
The weight of the load (force output), \(F_r\) = 600 N
The effort applied (force input), \(F_e\) = 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
\(MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3\)
The Mechanical Advantage, MA of the lever = 3
2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, \(L_e\), to the distance moved by the load, \(L_r\)
For the lever, we have;
The distance of the load from the fulcrum, \(L_r\) = 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from the fulcrum, \(L_e\) = 1 m - 0.2 m = 0.8 m
From which we have;
\(V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8 \ m}{0.2 \ m} = 4\)
The velocity ratio of the lever = 4
3) The efficiency, η, is given as follow;
\(\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%\)
The efficiency of the lever is 0.75 or 75%.
Explanation:
The length of the lever = 1 m
The weight of the load (force output), F_rF
r
= 600 N
The effort applied (force input), F_eF
e
= 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
MA = \dfrac{F_r}{F_e} = \dfrac{600 \ N}{200 \ N} = 3MA=
F
e
F
r
The length of the lever = 1 m
The weight of the load (force output), F_rF
r
= 600 N
The effort applied (force input), F_eF
e
= 200 N
1) The Mechanical Advantage, MA of the lever is given as follows;
MA = \dfrac{F_r}{F_e} = \dfra
=
200 N
600 N
=3
The Mechanical Advantage, MA of the lever = 3
2) The velocity ratio, V.R., is the ratio of the distance moved by the effort, L_eL
e
, to the distance moved by the load, L_rL
r
For the lever, we have;
The distance of the load from the fulcrum, L_rL
r
= 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from the fulcrum, L_eL
e
= 1 m - 0.2 m = 0.8 m
From which we have;
V.R.= \dfrac{L_e}{L_r} = \dfra
The distance of the load from the fulcrum, L_rL
r
= 20 cm = 0.2 m
Therefore, we have;
The distance of the effort from t
V.R.= \dfrac{L_e}{L_r} = \dfrac{0.8
L
e
=
0.2 m
0.8 m
=4
The velocity ratio of the lever = 4
3) The efficiency, η, is given as follow;
\%Efficiency, \, \eta = \dfrac{M.A.}{V.R.} \times 100 = \dfrac{3}{4} \times 100 = 75\%%Efficiency,η=
V.R.
M.A.
×100=
4
3
×100=75%
The efficiency of the lever is 0.75 or 75
A 3.00 kg crate is pulled along a frictionless surface with a force of 55.0 N at 25.00 to the
horizontal so that it accelerates directly to the right. What is the crate's acceleration?