A 15.75-g piece of iron absorbs 1,086.75 joules of heat energy and its temperature changes from 25.0°C to 175.0°C. Calculate the specific heat capacity of iron.

Answers

Answer 1

Answer

0.46 J/g°C

Explanation

Given:

Mass of iron, m = 15.75 g

Quantity of heat, q = 1086.75 J

Initial temperature, T₁ = 25.0 °C

Final temperature, T₂ = 1750 °C

What to find:

The specific heat capacity, c of the iron.

Step-by-step solution:

The specific heat capacity of the iron can be calculated using the formula below:

\(q=mc(T_2-T_1)\)

Put the values of the given parameters into the formula:

\(\begin{gathered} 1086.75=15.75\times c\times(175.0-25.0) \\ \\ 1086.75=15.75\times c\times150 \\ \\ 1086.75=2362.5c \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }2362.5 \\ \\ \frac{1086.75}{1362.5}=\frac{2362.5c}{2362.5} \\ \\ c=0.46\text{ }J\text{/}g^0C \end{gathered}\)

The specific heat capacity, c of the iron = 0.46 J/g°C


Related Questions

What quality of a drop of water increases as it gets closer to the earth surface I’m thinking it’s velocity but I don’t know

What quality of a drop of water increases as it gets closer to the earth surface Im thinking its velocity

Answers

Answer: the correct answer is C velocity.

Explanation: I just got the answer wrong on the exam.

Answer:The Anwser is C; velocity

Explanation:

What is the difference between the grassland and savanna biomes?
A)Grassland biomes are closer to the equator and receive more rain.

B)Savanna biomes are closer to the equator and receive more rain.

C)Grassland biomes contain mostly grasses.

D)Savanna biomes contain mostly grasses.

Answers

Answer:

C)Grassland biomes contain mostly grasses.

Explanation:

The main differences between a savanna biome and a grassland is that grasslands biomes contain mostly grasses.

Savanna are made up of both grasses and shrubs.

Savanna are a mix of grasslands with some scattered trees in the area. Grasslands are open grass fields. They do not contain much trees as such. The savanna and grasslands are renowned for their fauna diversity of beasts.  

Calculate the pH of the buffer that results from mixing 60.0 mL of 0.25 M HCHO2(pKa= 3.74) and 15.0 mL of 0.500 M NaCHO

Answers

Answer:

\(pH=3.44\)

Explanation:

Hello.

In this case, since the formic acid (HCHO2) is a weak acid and it is mixed with its conjugate base (CHO2⁻) in the form of NaCHO2, we can compute the pH via the Henderson-Hasselbach equation:

\(pH=pKa+log(\frac{[Base]}{[Acid]} )\)

Whereas the concentration of both acid and base are computed considering final total volume of 75.0 mL after adding the volume of each solution as shown below:

\(n_{base}=0.500mol/L*0.0150L=7.50x10^{-3}mol\\\\n_{acid}=0.25mol/L*0.0600L=1.5x10^{-2}mol\)

And the resulting concentrations upon the final volume:

\([Base]=\frac{7.50x10^{-3}mol}{0.0750L}=0.1M\)

\([Acid]=\frac{1.5x10^{-2}mol}{0.0750L}=0.20M\)

Thus, the pH is:

\(pH=3.74+log(\frac{0.10M}{0.20M} )\\\\pH=3.44\)

Best regards.

how to get pure alumina? explain with the reactions​

Answers

Okay I will explain you friend...

To get pure alumina, you should follow these below steps.

Step (1):- Impurity alumina is treated with conc. NaOH solution to form sodium aluminate.

\({ \green{ \tt{Al2O3 + 2NaOH + 3H2O → 2Na[Al(OH)4]}}}\)

Step (2):- sodium aluminate is treated with carbon dioxide gas to form precipitated Al2O3

\({ \purple{ \tt{2Na[Al(OH)4] + CO2 → Al2O3.xH2O + NaHCO3}}}\)

Step (3):- Precipitated Al2O3 separated by filtration and heated at 1470K to give pure alumina.

\({ \blue{ \tt{Al2O3.xH2O \: \: —(1470K)→ Al2O3 + xH2O}}}\)

In a double replacement reaction, the ions of two compounds exchange places in an aqueous solution to form two new compounds.

True

False

Answers

Answer:

true

Explanation:

Answer:

True

Explanation:

In a displacement reaction, more reactive element displaces less reactive element. Whereas in a double displacement reaction there is exchange of ions of two compounds.

I’ll give you THE BRAINLIEST
please answer ASAP

1. 4 Al + 3 O2 -> 2 Al2 O3
a. How many moles of Aluminum would be needed to react completely
with 8.0 moles of oxygen gas?
b. How many moles of aluminum oxide would be produced if 5.0 moles of
aluminum were reacted with an excess of oxygen?

2. CS2 + 3 O2 -> CO2 + 2 S02
If 85.5 grams of carbon disulfide are reacted with an excess of oxygen, how
many grams of sulfur dioxide would be produced?

3. 2 Br + 7 O2 -> 2 Br2 O7
If 425 grams of oxygen gas reacted with 350 grams of bromine, what should be the theoretical yield of dibromine heptoxide? Limiting reagent? Grams of Br2O7 produced?

Answers

hope you understand everything , (AD).

Ill give you THE BRAINLIEST please answer ASAP 1. 4 Al + 3 O2 -> 2 Al2 O3a. How many moles of Aluminum
Ill give you THE BRAINLIEST please answer ASAP 1. 4 Al + 3 O2 -> 2 Al2 O3a. How many moles of Aluminum

Which characteristic of the elements increases as you move across a period
from left to right?

A. Magnetic attraction
B. Atomic number
C. Year discovered
D. Metallic nature

Answers

Answer: THE ANSWER SHOULD BE Atomic number

Sry if wrong

Explanation:

Assume the trials listed below with Equilibrium constants!

Need help with the table graphing questions (in answers b, c, d, I need to explain my answer which I'm a little confused about -> how do you actually go about solving?)

Assume the trials listed below with Equilibrium constants!Need help with the table graphing questions
Assume the trials listed below with Equilibrium constants!Need help with the table graphing questions

Answers

The value of Kc for the reaction at 25°C is 11.25.

The equilibrium constant expression for the reaction:

2NO(g) + \(Cl_2\)(g) ⇌ 2NOCl(g)

is Kc = \(([NOCl]^2)/([NO]^2[Cl_2])\), where [NO], [\(Cl_2\)], and [NOCl] are the molar concentrations of NO, \(Cl_2\), and NOCl, respectively, at equilibrium.

At 25°C, if the concentration of NO and \(Cl_2\) are 0.2 M and the concentration of NOCl is 0.3 M, then we can substitute these values into the equilibrium constant expression to find the value of Kc:

Kc =\(([NOCl]^2)/([NO]^2[Cl_2])\)

Kc = \((0.3^2)/(0.2^2*0.2)\)

Kc = 11.25

Therefore, the value of Kc for the reaction at 25°C is 11.25.

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--The complete Question is, Assuming trials with equilibrium constants, what is the equilibrium constant expression for the reaction:

2NO(g) + Cl2(g) ⇌ 2NOCl(g)

and what is the value of Kc at 25°C if the concentration of NO and Cl2 are 0.2 M and the concentration of NOCl is 0.3 M? --

CuI2 (light brown solid) name copper compounds

Answers

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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Balance the equation AgCO3—> Ag+C+O2 and what type of reaction is it

Answers

Answer:

Decomposition Reaction

2 AgCO₃ -----> 2 Ag + 2 C + 3 O₂

Explanation:

During the reaction, the reactant breaks down into smaller elements/compounds. As such, this is a decomposition reaction.

An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, you can add coefficients to modify the quantities of particular elements/compounds. These coefficients must be as small as they can be while remaining whole numbers.

The unbalanced equation:

AgCO₃ -----> Ag + C + O₂

Reactants: 1 silver, 1 carbon, 3 oxygen

Products: 1 silver, 1 carbon, 2 oxygen

The balanced equation:

2 AgCO₃ -----> 2 Ag + 2 C + 3 O₂

Reactants: 2 silver, 2 carbon, 6 oxygen

Products: 2 silver, 2 carbon, 6 oxygen

When heated, calcium carbonate, CaCO3(s) , decomposes to calcium oxide, CaO(s) , and carbon dioxide, CO2 . Using relevant data from your book's appendices, calculate the heat evolved or consumed when 15.0 g of calcium carbonate are decomposed. answer: kJ

Answers

As per the standard data, the heat evolved during one mole of calcium carbonate decomposes is 177.8 KJ. Thus 15 g or 0.15 moles of calcium carbonate when decomposed will produce 26.67 KJ of heat.

What is reaction enthalpy?

Reaction enthalpy of a substance is the heat evolved or absorbed during a reaction. Reaction enthalpy is negative for an exothermic reaction and positive for an endothermic reaction.

Molar mass of calcium carbonate = 100 g.

no.of moles in 15 g = 15 /100 = 0.15 moles.

One mole or 100 g of calcium carbonate decompose to evolve 177.8 KJ according to the scientific record.

Thus, heat evolved by the decomposition of 0.15 moles is 0.15 × 177.8 KJ = 26.67 KJ.

Hence, the heat evolved during the decomposition of 15 g of calcium carbonate is 26.67 KJ.

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A population of plants has a mixture of individuals with short, wide flowers and long, narrow flowers. Short, wide flowers are more easily pollinated by bees while long, narrow flowers are more easily pollinated by hummingbirds. Over time, the population becomes dominated by long, narrow flowers.Which statement ,begin emphasis,best,end emphasis, explains the increase in number of plants with long, narrow flowers over time?Answer options with 4 options.The environment favors short, wide flowers instead of long, narrow flowers.B.The gene for short, wide flowers is mutated into a gene for long, narrow flowers.C.Individuals with long, narrow flowers are stronger than individuals with short, wide flowers.D.Individuals with long, narrow flowers produce more seeds than individuals with short, wide flowers.

Answers

The best explanation for the increase in the number of plants with long, narrow flowers over time is option D: Individuals with long, narrow flowers produce more seeds than individuals with short, wide flowers.

In this population, short, wide flowers are better suited for bee pollination, while long, narrow flowers are more suitable for hummingbird pollination. Over time, the plants with long, narrow flowers produce more seeds compared to those with short, wide flowers.

This happens because the hummingbirds, which are the main pollinators for long, narrow flowers, are more effective in transferring pollen between these flowers. As a result, the long, narrow flower individuals have a higher reproductive success and pass on their traits to the next generation

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How many 14C atoms are in a charcoal sample that has a decay rate of 3500 per min? (For 14C, t1/2= 5730yr)

Answers

There are approximately 2.89 × 10^7 14C atoms in the charcoal sample.

The radioactive decay law and the sample's decay rate can be used to calculate the quantity of 14C atoms present in a sample. According to the radioactive decay law, a radioactive substance's rate of decay is proportional to the quantity of radioactive atoms it contains. In this instance, we are informed that the sample of charcoal degrades at a rate of 3500 per minute. By multiplying the half-life of 14C by the amount of minutes in a year (525,600 min/yr), we may convert the 5730 years to minutes. Therefore, 5730 years x 525,600 min/yr = 3.01 109 minutes is the half-life of 14C. The number of 14C atoms in the sample can be determined using the decay law equation as follows: R = λN

where N is the number of radioactive atoms in the sample, R is the decay rate, and is the decay constant. From the half-life (t1/2), the decay constant () can be computed as follows: λ = ln(2)/t1/2

With the values from the issue substituted, we get:

1.21 x 10-4 min-1 = ln(2)/5730 year

We can now solve for N using the decay law equation: N = R/λ

If we substitute the values provided, we get: N = 3500 per minute / (1.21 10-4 min-1), multiplied by 2.89 107.

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Which indicator would be the best to use if 0. 050 m benzoic acid ( k a = 6. 6 × 10 –5) is titrated with 0. 050 m naoh?

Answers

I would say Phenolphthalein

1. What does the atomic number of an element represent? What does the mass number of an
atom represent?

Answers

The atomic number represents or stand for the distinction identity of a chemical element. It is usually defined as the number of protons present number in an atom of an element, which is also equal to the number of electrons

This table shows data collected about four different landforms. Landform What Is Its Landmass? What Is Its Shape? Is There Water? W Large Has steep sides No X Large Goes down and comes back up No Y Small A circle Filled with water Z Small Rises up in the middle then goes back down Surrounded by water Question Which landform is an island?

A.
W because it has steep sides.

B.
X because it dips in the middle.

C.
Y because it is small and a circle.

D.
Z because it is surrounded by water

Answers

Answer:

answer is d

Explanation:

because it is surrounded by water

Why is the same type of nail used in all test tubes? ​in every experiment done to show how rusting works and in what conditions.

Answers

in test tube 1 iron nail gets both air and moisture which is required for rusting. ... in the test tube 3 iron nail is not rusted because of the calcium chloride which is moisture absorber. hence nail would not get moisture for the rusting.

Given the following equation: Mg + 2HCI → MgCl₂ + H₂
How many moles of H₂ can be produced by reacting 2 moles
of HCI?

Answers

Taking into account the reaction stoichiometry, 1 mole of H₂ can be produced by reacting 2 moles of HCI.

Reaction stoichiometry

In first place, the balanced reaction is:

Mg + 2 HCl  → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Mg: 1 moleHCl: 2 molesMgCl₂: 1 moleH₂: 1 mole

Moles of H₂ produced

By reaction stoichiometry 2 moles of HCl form 1 mole of H₂.

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If 70.0g of manganese (IV) fluoride reacts with 70.0g ammonium sulfide, which reactant is
the limiting reactant and how many grams of the excess reactant is left over?
MnF_4(aq)+2(NH_4)_2S(aq)-> MnS_2(s)+4NH_4F(aq)

Answers

The limiting reactant would be the ammonium sulfide and the amount of the excess manganese (IV) fluoride would be 1.96 grams

Limiting reactants

From the equation of the reaction:

\(MnF_4(aq)+2(NH_4)_2S(aq)- > MnS_2(s)+4NH_4F(aq)\)

The mole ratio of \(MnF_4\) to \((NH_4)_2S\) is 1:2

Mole of 70 g \(MnF_4\) = 70/130.93

                                 = 0.53 moles

Mole of 70 g  \((NH_4)_2S\) = 70/68.154

                                       = 1.03 moles

Equivalent mole of   \((NH_4)_2S\) = 0.53 x 2

                                                = 1.06 moles

Thus,   \((NH_4)_2S\) seems to be limiting while \(MnF_4\) is in excess.

Excess \(MnF_4\) = 0.53 - 1.03/2

                          = 0.015 mole

Mass of 0.015 mole \(MnF_4\) = 0.015 x 130.93

                                             = 1.96 grams

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How do I do this ? What was AMU again?

How do I do this ? What was AMU again?

Answers

Answer

n=4

Procedure

Data

Sulfur has an atomic mass of 32.065 u

Fluorine has an atomic mass of 18.9984 u

To solve this problem we need to find the number of atoms of fluorine, this can be done using an equation as follows

\(108.01=32.065+18.9984x\)

Solving for x we have

\(x=\frac{108.01-32.065}{18.9984}=3.99\approx4\)

Hence as we can't have a decimal atom we consider 4 atoms of fluorine.

choose the hydration shells that form around a potassium ion when potassium chloride ( kcl ) dissolves. notice the positive, negative, and partial charges.

Answers

When KCl dissolves in water, the K⁺ ion forms a positive hydration shell surrounded by water molecules with partial negative charges, while the Cl⁻ ion forms a negative hydration shell surrounded by water molecules with partial positive charges.

When potassium chloride (KCl) dissolves in water, the potassium (K⁺) ion is surrounded by water molecules with partial negative charges on the oxygen atoms. This creates a hydration shell with a net positive charge, as the positive charge of the potassium ion is balanced by the partial negative charges of the surrounding water molecules.

On the other hand, the chloride (Cl⁻) ion is surrounded by water molecules with partial positive charges on the hydrogen atoms, creating an hydration shell with a net negative charge.

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what was the open-range system ​

Answers

Answer: In the Western United States and Canada, open range is rangeland where cattle roam freely regardless of land ownership. ... Land in open range that is designated as part of a "herd district" reverses liabilities, requiring an animal's owner to fence it in or otherwise keep it on the person's own property.

Explanation: Mark me as brainliest

Cl2(g)→Cl−(aq)+ClO−(aq)

Answers

Cl₂   ----->     Cl⁻  +  OCl⁻

The balance equation is :

Cl₂   +   2OH⁻   ----->     Cl⁻  +  OCl⁻  +    H₂O

The unbalanced chemical equation is give as :

Cl₂   ----->     Cl⁻  +  OCl⁻

the medium is basic , so add OH⁻ in the left side to balnace the given equation.

Cl₂   +   OH⁻   ----->     Cl⁻  +  OCl⁻

now, to balance OH⁻ ion add water H₂O to the right side of equation to balance the given equation, we get

Cl₂   +   OH⁻   ----->     Cl⁻  +  OCl⁻  +    H₂O

now to balance H  multiply 2 in  OH⁻ , we get

Cl₂   +   2OH⁻   ----->     Cl⁻  +  OCl⁻  +    H₂O

Now, the given chemical equation is balanced .

Thus, Cl₂   ----->     Cl⁻  +  OCl⁻

The balance equation is :

Cl₂   +   2OH⁻   ----->     Cl⁻  +  OCl⁻  +    H₂O

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I need help finding arm

I need help finding arm

Answers

Answer:

line 15 is were you can find the a then you look around for the r but as a heads up the m thats supposed to be there was actually inverted into a w in theory it must have been misprinted.

Explanation:

Are pressure and volume directly or inversely proportional

Answers

Pressure and volume can be regarded as the entity that is inversely proportional.

What is the relationship between Pressure and volume?

It should be noted that this explanatin an be done using the law in chemistry which is the Boyle's law which states that, for a given amount of gas and constant temperature, the volume is inversely proportional to the pressure.

However the Equal quantities of all gases can be seen to have same number of molecules when subjected to the same temperature and pressure (Avogadro's law).

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Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate the compound with the lowest boiling point. A carbon chain with 5 central carbons, with C H 3 bonded to the first, second, and last carbons in the chain. 2 central carbons with C H 3 bonded to the outside, and C H 3 bonded to the leftmost inside carbon. 2 central carbons, each with C H 3 bonded to them. A central C has H bonded left, above, behind to the right, and in front to the right.

Answers

The ranking of boiling point is based on the molecular weight and intermolecular forces between molecules.

2 central carbons, each with CH3 bonded to them. A central C has H bonded left, above, behind to the right, and in front to the right. A carbon chain with 5 central carbons, with CH3 bonded to the first, second, and last carbons in the chain. 2 central carbons with CH3 bonded to the outside, and CH3 bonded to the leftmost inside carbon.

In this case, all compounds are hydrocarbons, meaning they are non-polar molecules and exhibit van der Waals forces. However, the length of the carbon chain and the arrangement of atoms in the molecule affect the magnitude of these forces.

The first compound has only two carbons and exhibits weak intermolecular forces, so it has the lowest boiling point. The second compound has three carbons and a more complex arrangement of atoms, resulting in slightly stronger van der Waals forces and a higher boiling point.

The third compound has a longer carbon chain, which increases the molecular weight and results in stronger intermolecular forces, giving it a higher boiling point than the previous two. The fourth compound has the longest carbon chain and has multiple branches, which increases the surface area of the molecule and the strength of the intermolecular forces, giving it the highest boiling point.

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Answer:

The answers are 4, 2, 3, 1

Explanation:

Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate

GROUP NUMBER
ELEMENT
Potassium
Fluorine
Silicon
Radon
Gold
Beryllium
Oxygen
Neon
Rubidium
Tungsten
Arsenic
Calcium
Sodium
Aluminum
Chromium
Iodine
Helium
Nitrogen
Iron
Zinc

GROUP NUMBERELEMENTPotassiumFluorineSiliconRadonGoldBerylliumOxygenNeonRubidiumTungstenArsenicCalciumSodiumAluminumChromiumIodineHeliumNitrogenIronZinc

Answers

Answer:

Jet ğıpep2pep2p2pp3oroe88r82

Which event is an example of sexual reproduction in plants?
A. Pine trees produce seeds in cones.
B. Mosses form spores in capsules.
C. A kalanchoe produces plantlets on its leaves.
D. A potato has buds that can grow into new stems.

Answers

Answer:

the correct answer to your question is b

The correct answer is B

(a) using principles of atomic structure, explain why the first ionization energy of rn is less than that of xe.

Answers

The difference in first ionization energy between Xe and Rn can be explained by the combination of differences in electron configuration and shielding effect.

The energy needed to remove one electron from an atom or ion is known as the initial ionization energy. The number of electrons in the atom and the arrangement of those electrons are two parameters that affect an element's ionization energy.

The electron configurations of the elements Rn (Radon) and Xe (Xenon) are similar, although Radon contains more electrons than Xenon. In contrast to the outermost electrons of Xenon, the outermost electrons of Radon are bound by the nucleus more securely and are therefore more difficult to remove. Because Xe has a lower initial ionization energy than Rn, it is simpler to remove one electron from Xe than from Rn.

Additionally, the shielding effect of inner electrons also affects the ionization energy. The shielding effect refers to the ability of inner electrons to screen or reduce the attraction between the nucleus and outer electrons. In Xe, there are more inner electrons than in Rn, which provides a stronger shielding effect, further reducing the ionization energy of Xe.

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What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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