a 140.0 ml sample of 0.10 m ba(oh)2 is titrated with 0.10 m hbr. determine the ph of the solution after the addition of 560.0 ml hbr.

The following H atom transitions, that would emit the photon of the light with the greatest energy is n = 2 to n = 1. The correct option is c.

The largest energy is given as :

ΔE = 13.6 ( 1/nf² - 1/ ni²)

a) n = 5 to n = 3

ΔE = 13.6 ( 1/3² - 1/ 5²)

ΔE = 0.97 eV

b) n = 4 to n = 2

ΔE = 13.6 ( 1/2² - 1/ 4²)

ΔE = 2.4 eV

c) n = 2 to n = 1

ΔE = 13.6 ( 1/1² - 1/ 2²)

ΔE = 10.2 eV

d) n = 5 to n = 4

ΔE = 13.6 ( 1/4² - 1/ 5²)

ΔE = 0.7 eV

Thus, the transition would emit the photon of light with the greatest energy is n= 2 to n= 1. The correct option is c.

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Answer: 2.94x10^22 atoms of O2

Explanation:

To determine the number of atoms in a given volume of a gas, you need to know the molar volume of the gas and the number of moles of the gas present.

The molar volume of a gas at standard temperature and pressure (STP) is 24.45 L/mol. At STP, the pressure is 1 atm and the temperature is 0°C (273.15 K).

So, to find the number of moles of a gas present in a container, you can use the Ideal Gas Law: PV = nRT.

Where:

P = pressure (atm)

V = volume (L)

n = number of moles

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (K)

So we can rearrange the formula to find n = PV/RT

n = (2.44 atm * 2.54 L) / (0.0821 L·atm/mol·K * 275 K) = 0.049 moles

To find the number of atoms of O2, we just multiply the number of moles by Avogadro's number which is 6.022x10^23 atoms/mol.

So the number of atoms of O2 in 2.54 L at 2.44 atm and 275 K is:

6.022x10^23 atoms/mol * 0.049 moles = 2.94x10^22 atoms of O2

This is the number of atoms of O2 present in the container.

The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.

Case 1: HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​
Ha​ : Not all proportions are equal.

Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\)  where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.  
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)

We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)

Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)

Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)

The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)

From the above percentages, we can see that Friday has the highest percentage of traffic accidents.

Case 2:
HD​: Not all proportions are equal.

Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71

Test Statistic

\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)

We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic can be computed as:

\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

Case 3:

All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic is,

\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)

The p-value is 0.1664.

Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

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The mass defect of the oxygen nucleus is 16 8o 816o. the mass of neutral 16 8o 816o is equal to 15.994914 atomic mass units

8(1.008665)+8(1.007825)

=16.13192

16.13192-15.994914

=.13701 amu

The atomic nucleus is a small, dense region made up of protons and neutrons at the center of an atom, discovered by Ernest Rutherford in 1911, based on Geiger-Marsden's gold leaf experiment in 1909. After the discovery of the neutron in 1932, models of the nucleus composed of protons and neutrons were rapidly developed by Dmitri Ivanenko[1] and Werner Heisenberg. I was.

The cell nucleus carries genes, structures that control and regulate cell activity (such as growth and metabolism) and contain genetic information. Nucleoli are small bodies commonly found within the nucleus. The nucleoplasm is the gel-like matrix in which the core components are suspended.

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Answer: lysocline

Explanation:

Lysocline is the depth in the ocean at which calcareous skeletal material first begins to dissolve. It is the depth of the ocean whereby the dissolution rate of calcite has a dramatic rise.

Lysocline is also referred to as the transition zone upper bound where the CaCO3 content drops.

Answer:

\( \huge{\boxed{\boxed{1.27 \: M}}} \)

Explanation:

The final molarity or concentration of HCl can be found by using the formula

\( C_1V_1 = C_2V_2 \)

where

c is the concentration in M , mol/dm³ or mol/L

v is the volume

C1 is the initial molarity or concentration

V1 is the initial volume

C2 is the final molarity

V2 is the final molarity

From the question

C1 = 6 M

V1 = 5.3 ml

V2 = 25 ml

\( C_2 = \dfrac{C_1V_1}{V_2} \)

We have

\( C_2 = \dfrac{5.3 \times 6}{25} = \dfrac{31.8}{25} \\ = 1.272 \)

We have the final answer as

Given data:Initial volume of HCl solution = 5.30 mlInitial molarity of HCl solution = 6.00 MTotal volume after dilution = 25.0 mlThe final molarity of HCl solution can be calculated using the following formula;

M1V1 = M2V2 where,M1 = Initial molarity of HCl solutionV1 = Initial volume of HCl solutionM2 = Final molarity of HCl solutionV2 = Total volume after dilutionFirst, calculate the final volume of HCl solution after dilution:Final volume = Total volume after dilution - Initial volume of HCl solution= 25.0 ml - 5.30 ml= 19.70 mlNow, substitute the values in the formula:M1V1 = M2V2(6.00 M)(5.30 ml) = M2(19.70 ml)M2 = (6.00 M × 5.30 ml) / 19.70 ml= 1.62 MTherefore, the final molarity of HCl solution is 1.62 M.Hence, the correct option is,Final molarity = 1.62 M.

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When they talk about items found, they refer to molecules. According to Avogadro, one mole of any substance, regardless of its type, contains the same amount of molecules equal to 6.022x10^23.

Now they tell us about a molecule of silver and a mole of calcium. In one mole of calcium, there will be 6.023x10^23 molecules, which is different from one molecule of silver, so the answer will be false

Answer:

a buffalo

Explanation: if its north America it needs to be native from here none of the other are from north America

Newtons laws of motion:  For the planetary motion puzzle, Newton correctly identified the variables force and momentum. I hypothesize that momenta and forces are the appropriate variables to characterize the motion of the planets, as stated in Newton's grant request.

Do you think Newton believed in hypothesis?

Newton vehemently resisted the hypothesis-based approach, insisting that theories regarding the origins and characteristics of appearances, such as the laws of motion, be deduced from the facts instead.

A fundamental formulation for a hypothesis is "If this happens, then this will happen." Specifying what will happen to the dependent variable if you change the independent variable is one technique to formulate your hypothesis.

There are six forms of hypothesis and they are:

Simple hypothesis.

Complex hypothesis.

Directional hypothesis.

Non-directional hypothesis.

Null hypothesis.

Associative and casual hypothesis.

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The volume of insulation material required is approximately 0.003606 cubic meters (m³).

To calculate the volume of insulation material, we can subtract the volume of the inner pipe (original pipe) from the volume of the outer pipe (original pipe + insulation).

Given:

Length of the pipe, L = 10 m

Radius of the pipe, r = 7 cm = 0.07 m

Thickness of the insulation, dr = 2 mm = 0.002 m

The outer radius of the larger pipe is R = r + dr.

Using the formula for the volume of a cylinder, V = π(R² - r²)L, we can substitute the values and calculate:

V = π((0.07 + 0.002)² - 0.07²) × 10

V ≈ 3.606 × 10⁻³ m³

Therefore, the volume of insulation material required is approximately 0.003606 m³ (cubic meters).

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Answer:

alligators protect their offspring by digging a hole where they bury their eggs and stay all the meanwhile on top of the hole protecting their offspring. baby alligators can be eaten by birds and snakes. they for short periods of time take a break to hunt for food. when their hatchling hatch they keep them in their mouth until they're in the water. alligators are good protecting their offspring.

seahorses make the males take care of their baby's till they are born and male seahorses join together in groups to help protect eachother. once the babies are born male seahorses are still together helping raise their pups

Alligators bury their eggs in a hole that they have dug, and they then spend the entire time on top of the hole guarding their young. Therefore, by below given ways animals take care of their offspring.

Offspring refers to the new organism that an organism creates via the act of reproduction. Both birds and snakes can consume young alligators. They stop for brief periods of time to go food hunting. They hold their hatchlings in their mouths until they are in the water after they hatch. Alligators do a superb job of safeguarding their young.

Male seahorses form groups to assist defend one another, and they are required to care for their young until they are born. Male seahorses continue to work together to nurture their young after the babies are born.

Therefore, by above ways animals take care of their offspring.

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Omega-3 fatty acids are a type of zoochemical that can be found in fatty fish. Zoochemicals are compounds that are naturally present in animal-based foods and have beneficial effects on human health.

These fatty acids are important for maintaining a healthy heart and brain, and they have anti-inflammatory properties. Eating fatty fish such as salmon, tuna, and mackerel is a good way to increase your intake of omega-3 fatty acids.Omega-3 fatty acids are essential for maintaining various bodily functions, and they are particularly vital for brain health. Studies have shown that omega-3s can help improve cognitive function and reduce the risk of developing dementia and Alzheimer's disease. Additionally, these fatty acids can help lower the risk of heart disease by reducing inflammation and improving cholesterol levels. In addition to fatty fish, other foods that are high in omega-3s include chia seeds, flaxseeds, and walnuts.

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Omega-3 fatty acids are a group of essential nutrients that are crucial for maintaining overall health and well-being. They are a type of zoochemical that are primarily found in fatty fish like salmon, mackerel, and sardines.

These fatty acids have been shown to have numerous health benefits, such as reducing inflammation, improving heart health, and supporting brain function. Additionally, they may play a role in preventing chronic diseases like cancer and diabetes. While omega-3 fatty acids can be obtained through diet, some people may choose to take supplements to ensure they are getting enough of this important nutrient. Fatty fish such as salmon, mackerel, and sardines are rich sources of omega-3 fatty acids. It's important to include these fatty fish in our diet to maintain overall well-being.

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rate is directly propotional to \([concentration]^{[order]}\)

orders of the reactants in the rate law determined by diong an experiment

It is an experimental concept

option 1 correct

kinetics tells you speed of the reaction , kinetics tells you how fast you how fast the reaction is occurring

A rate term expresses the response in terms of changes in reactant or product concentrations over time. Reaction rates can be expressed in terms of either reactants or products in a reaction.

There are several rules for writing rate equations:

1) Reaction equations have a negative sign. This is because reactants are depleted or diminished.

2) The product description is positive. It's because you gain weight.

3) All rate equations for different reactants and products must be the same to be accurate. (This means that the equation must be corrected for reaction stoichiometry)  

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The hydrogen chloride is a gas at room temperature due to the presence of weak intermolecular forces.

Hydrogen chloride (HCl) is a chemical compound in which polar covalent bond is present between hydrogen atom and chlorine atom.

This bond is not so strong enough to maintain the stability in the liquid phase, else they are weak intermolecular forces and easily gets break through small amount of energy and having low boiling point. That's why HCl is present in gaseous state at room temperature.

Hence due to weak intermolecular force, HCl is present in gaseous state.

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Answer:

To find the least soluble substance at a given temperature we follow the temperature line up and the first substance curve we hit is the least soluble. For most soluble it is the same procedure except the last substance curve hit is the most soluble.

To determine if a substance is more soluble or less soluble based on a solubility curve, you need to compare the solubility values at different temperatures. Here's how you can interpret a solubility curve:

1. Higher Points on the Curve: If a point on the curve is higher, it indicates that the substance is more soluble at that temperature. In other words, at higher temperatures, the substance can dissolve in a greater amount.

2. Lower Points on the Curve: If a point on the curve is lower, it means that the substance is less soluble at that temperature. In this case, at lower temperatures, the substance can dissolve in a smaller amount.

3. Comparing Points: By comparing the solubility values at different temperatures, you can determine which temperature has a higher solubility and which has a lower solubility. The steeper the slope of the curve, the faster the increase or decrease in solubility with temperature.

Solubility curves provide a graphical representation of the relationship between temperature and solubility. They allow you to determine the solubility characteristics of a substance and how it changes with temperature.

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The elements in the same column of the periodic table was having a same amount of valence electrons.

define valence electrons ?

A valence electron is an electron connected with an atom in the outer shell that can participate in the production of a chemical bond if the outer shell is not closed. A shared pair originates in a single covalent connection, with both atoms donating one valence electron.

The existence of valence electrons can influence an element's chemical characteristics, such as its valence—whether it can connect with other elements and, if so, how easily and how many times. In this approach, the reactivity of a particular element is strongly reliant on its electrical arrangement. A valence electron can only reside in the outermost electron shell of a main-group element; a valence electron can also exist in the innermost electron shell of a transition metal.

The elements in the same column of the periodic table was having a same amount of valence electrons.

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The true volume of the flask at 20°C is 10.00 mL.

The volume of a volumetric flask is determined by filling it to the mark with a liquid of known density and measuring the mass. The difference between the mass of the empty flask and the mass of the filled flask is equal to the mass of the liquid, which can then be used to calculate the volume of the liquid. In this case, the mass of the distilled water is

20.214 g - 10.2634 g = 9.9506 g.

The density of water at 20°C is approximately 0.9970 g/mL, so the volume of the water is given by:

This is the true volume of the flask at 20°C, which is equal to the volume indicated on the flask. The volumetric flask is designed to be used at a specific temperature (usually 20°C), and the volume indicated on the flask is calibrated to be the true volume at that temperature. It is important to measure the temperature of the liquid and the flask before using a volumetric flask to ensure accurate results.

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log 12 can be written in four different ways as log(12), ln(12)/ln(10), log(12)/log(e), and log₁₀(12).

1. Using the logarithm base 10 (common logarithm): log(12)

This notation implies that the logarithm of 12 is taken with base 10, which is the default base for logarithms when no base is specified.

2. Using the change of base formula: ln(12)/ln(10)

The change of base formula allows us to express the logarithm of 12 in terms of natural logarithm (base e) and base 10 logarithm. It states that log_b(x) = ln(x)/ln(b), where ln denotes the natural logarithm.

3. Using logarithm base e (natural logarithm): log(12)/log(e)

This notation represents the logarithm of 12 with base e (Euler's number). It utilizes the property that log_b(x) = log(x)/log(b), where log denotes the common logarithm.

4. Using the logarithm function with base 10: log₁₀(12)

This notation explicitly specifies the base of the logarithm function as 10, indicating that the logarithm of 12 is taken with base 10.

By utilizing the properties of logarithms and different bases, we can express log 12 in various forms, each offering a different perspective on the logarithm of 12.

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If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .

Using the ideal gas law equation:

PV = nRT

n = (PV) / (RT)

= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)

= 42.71 moles

the balanced equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl -> \(ZnCl_{2}\)  + \(H_{2}\)

1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.

The molar mass of zinc is 65.38 g/mol.

Mass of zinc = moles of zinc * molar mass of zinc

= 42.71 moles * 65.38 g/mol

= 2796.96 g

Therefore, the mass of the zinc is 2796.96 grams.

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Answer:

Ethanamine (also known as ethylamine)

Explanation:

The compound that is requested by the question is ethanamine. Its trivial name is ethylamine.

It is a compound that contained the ethyl moiety (CH3CH2-) as well as the amine moiety (-NH2).

Ethanamine has a structure that can easily be determined by the statements in the question.

The structure of ethanamine is shown in the image attached.

Answer:

What is the name of this compound?

                                                                                    H       H

                                                                                    │       │

                                                               H ── N ── C ── C ── H

                                                                          │       │        │

                                                                          H      H        H

❌ A) ethanal

❌ C) ethanoic acid

❌ D) methyl ethanoate

I Took Question Test And Have Day.

Answer:

the equation is balanced

The cell’s pressure potential or ψp is 2.44 bars if the cell contains 0.6M glucose at 20°c with its surrounding solution containing 0.5M glucose.

As;

ψoutside = ψcell ( here ψ represents water potential)

Therefore;

ψp outside + ψs outside = ψp cell + ψs cell ( Since, ψ = ψp + ψs)

As ψs = -iCRT, therefore

0 + (-iCRT outside) = ψp cell + (-iCRT cell)

In iCRT, i represents the ionization constant

C represents the Molar concentration

R represents the Pressure constant 0.0831 liter bars/mole at degrees Kelvin

T represents temperature (degree kelvin)

Substituting the values;

(-1)(0.5M)(0.0831)(20 + 273) = ψp - (1)(0.6M)(0.0831)(20 +273)

-12.17 = ψp cell - 14.61

ψp cell = (-12.17) + 14.61

ψp cell = 2.44 bars

Therefore, the cell’s pressure potential (ψp) is calculated to be 2.44 bars if the cell contains 0.6M glucose at 20°c with its surrounding solution containing 0.5M glucose.

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Answer:

749 grams CO₂

Explanation:

To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.

Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)

Molar Mass (C₃H₈): 44.094 g/mol

1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O

Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)

Molar Mass (CO₂): 44.01 g/mol

250. g C₃H₈         1 mole C₃H₈           3 moles CO₂              44.01 g
------------------  x  ----------------------  x  ----------------------  x  --------------------  =
                               44.094 g              1 mole C₃H₈            1 mole CO₂

= 749 grams CO₂

Arginine is more likely to be found on the outside of a globular protein, while Tryptophan and Isoleucine are more likely to be found on the inside.

The location of amino acids within a globular protein depends on their physicochemical properties. Amino acids with polar or charged side chains tend to be found on the protein's surface, exposed to the surrounding aqueous environment, while amino acids with nonpolar side chains tend to be buried in the protein's interior.

Arginine (Arg) has a positively charged side chain, making it hydrophilic. It readily interacts with water molecules, and therefore, it is more likely to be found on the protein's surface.

Tryptophan (Trp) and Isoleucine (Ile) have nonpolar side chains. Nonpolar amino acids are hydrophobic and tend to avoid contact with water. Therefore, they are more likely to be buried in the protein's interior away from the aqueous environment.

Based on their side chain properties, Arginine is more likely to be found on the outside of a globular protein, while Tryptophan and Isoleucine are more likely to be found on the inside.

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Answer:

A. Almost all of the mass is concentrated in the nucleus.

Explanation:

Because when he shot the alpha particles towards the atoms, most passed through (which meant atom is mostly empty space), but some bounced back and such (which meant mass is concentrated in the nucleus.)

The reason they bounced is because alpha particles are postive and nucleus is positive as well, and we know positives don't attract, rather they repel thus they bounced.

Answer:

Liquid from a solid

Explanation:

Answer:

its FALSE

Explanation:

FAKE   ITS NOT REAL

i) The concentration of G in mol/dm3 is also 0.003416 mol/dm³.

ii) Molar mass of YOH is 204.49 g/mol

iii) The concentration of G is 0.003416 mol/dm³, the molar mass of YOH is 204.49 g/mol, and the percentage by mass of Y in YOH is 91.63%.

To solve this problem, we'll use the given information and the equation for the reaction: HCl + YOH → YCl + H2O

i. Concentration of G in mol/dm³:

From the given information, we know that 28.00 cm³ of the acid (F) neutralizes 25.00 cm³ of the base (G). This means the stoichiometric ratio between HCl and YOH is 1:1. Therefore, the number of moles of HCl neutralized by 28.00 cm³ of F is:

n(HCl) = concentration of F × volume of F in dm³

       = 0.122 mol/dm³ × 28.00 cm³ / 1000 cm3/dm³

       = 0.003416 mol

Since the stoichiometric ratio is 1:1, the concentration of G in mol/dm³ is also 0.003416 mol/dm3.

ii. Molar mass of YOH:

To calculate the molar mass of YOH, we need to know the mass of YOH used in the reaction. From the given information, we know that 7.0 g of YOH is present in 1 dm3 of G. Therefore, the molar mass of YOH can be calculated as:

Molar mass of YOH = Mass of YOH / Number of moles of YOH

                 = 7.0 g / 0.003416 mol

                 = 204.49 g/mol (rounded to two decimal places)

iii. Percentage by mass of Y in YOH:

The molar mass of Y in YOH can be calculated by subtracting the molar mass of OH from the molar mass of YOH:

Molar mass of Y = Molar mass of YOH - Molar mass of OH

              = 204.49 g/mol - 17.01 g/mol

              = 187.48 g/mol

The percentage by mass of Y in YOH can be calculated as:

Percentage by mass of Y = (Molar mass of Y / Molar mass of YOH) × 100%

                       = (187.48 g/mol / 204.49 g/mol) × 100%

                       = 91.63% (rounded to two decimal places)

Therefore, the concentration of G is 0.003416 mol/dm3, the molar mass of YOH is 204.49 g/mol, and the percentage by mass of Y in YOH is 91.63%.

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