a 120 nf capacitor is used in a standard 120 volt ac circuit with a frequency of 60 hz what is the cpaacitive resistance

Abby volunteers at the planetarium at the museum of natural history. she is putting together a presentation about the solar system in which she will describe the shape of the solar system. she uses the term orbital plane when she discusses the plane in which the planets orbit.

The space that connects the centers of the orbiting objects and the object being orbited is known as an orbital plane and is formed like a flat, disk. Planets in our solar system avoid colliding with one another because their orbital planes are similar.

A rotating body's orbit is located in a geometric plane called the orbital plane. An orbital plane can be identified using just three non-collinear points in space. The locations of the centers of an orbiting celestial body and a large body (the host) at two different times or points in its orbit are typical examples.

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Answer:

The first component of the cell theory says that all living things are made of cells. The second component of the cell theory states that cells are the basic structure and function of living things. The last component of the cell theory says that cells come from other cells.

Explanation:

Srry this took so long but hope this helps this is also the right answer have a good day

(P.S please mark the helpfull )

The correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

To find the tight asymptotic bound of T(n), we will use the Master Theorem. So, let's take a look at each recurrence relation:

1. T(n) = 10T(n/10)+100nApplying the Master Theorem: a = 10, b = 10, f(n) = 100nlogb a = log10 10 = 1 Since f(n) = Θ(n) = Θ(n1), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(n log n).

2. T(n) = T(n/10)+100n Here, a = 1, b = 10, f(n) = 100nlogb a = log10 1 = 0 Since f(n) = Θ(n0) = Θ(1), Case 1 of the Master Theorem applies. The solution, therefore, is Θ(n).

3. T(n) = T(n/10)+100 Here, a = 1, b = 10, f(n) = 100logb a = log10 1 = 0 Since f(n) = Θ(1) = Θ(n0), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(log n).Therefore, the correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

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Let's use the Master Theorem to find the asymptotic tight bound for each of the three recurrence relations given in the problem statement.

1. T(n) = 10T(n/10) + 100n Here, a = 10, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 10 = 1 Since f(n) = Θ(n1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(n log n)Therefore, the correct tight asymptotic bound for T(n) in the first case is Θ(n log n).

2. T(n) = T(n/10) + 100n Here, a = 1, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(n1), we can apply Case 1 of the Master Theorem and get: T(n) = Θ(n)Therefore, the correct tight asymptotic bound for T(n) in the second case is Θ(n).

3. T(n) = T(n/10) + 100 Here, a = 1, b = 10, and f(n) = 100. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(log n) Therefore, the correct tight asymptotic bound for T(n) in the third case is Θ(log n). Hence, the three asymptotic tight bounds for T(n) are Θ(n log n), Θ(n), and Θ(log n), respectively.

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Answer:

Due to the direction of force due to pressure.

Explanation:

Let there be two small holes having area, \(a\) , at points A and B in the bottle filled with water as shown in the figure \((i)\). Water comes out at the right angles to the wall of the bottle as shown in figure \((ii)\).

From Newton's second law, the acceleration of an object is always in the direction of net applied force.

We know that pressure, \(P\), on any surface due to fluid acts perpendicular to the surface, so, the force due to pressure,\(F=Pa\), will also be perpendicular to the surface as shown in the diagram\((iii)\).

So, the direction of the acceleration of the water element at that point will be perpendicular to the bottle surface which leads to the change in velocity of the water element in the same direction.

That's why water comes out at right angles to the surface of the bottle.

Answer:

Actually, there is  no force (felt by the object) acting on the object.

It is similar to an  object in orbit around the earth (weightlessness)

F = M a    describes the motion of the particle where

M a = M g    where the acceleration of the particle is equal to the force of gravity acting on the particle

From an external view the only force acting on the particle is M g and it produces an acceleration of M g

There is no force felt by the freely falling body. The cause of free fall is gravitational pull. Where Acceleration is equal to the gravitational acceleration. According to Newton's Law of Gravitation , two bodies attract each other due to their masses and separation , since earth is a very big body therefore the lit body falls towards the earth . Thus the graph plotted is a straight line.

What is Newton's law of Gravitation?

"The force acting between two bodies is directly proportional to product of masses and inversely proportional to the square of the separation ."

F= G.{m_{1} . m_{2} }/r^{2}.

Hence the only force by which the object is falling is gravitational pull.

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The simplified expression for Q using De Morgan's laws is Q = A . (A' . C')'.

a) Truth tables for the NAND gate and NOR gate with two inputs:

NAND gate:

| A | B | Q |

|---|---|---|

| 0 | 0 | 1 |

| 0 | 1 | 1 |

| 1 | 0 | 1 |

| 1 | 1 | 0 |

NOR gate:

| A | B | Q |

|---|---|---|

| 0 | 0 | 1 |

| 0 | 1 | 0 |

| 1 | 0 | 0 |

| 1 | 1 | 0 |

b) Truth table and logic expression for Z in terms of inputs A, B, and C:

| A | B | C | Z |

|---|---|---|---|

| 0 | 0 | 0 | 1 |

| 0 | 0 | 1 | 0 |

| 0 | 1 | 0 | 1 |

| 0 | 1 | 1 | 0 |

| 1 | 0 | 0 | 1 |

| 1 | 0 | 1 | 0 |

| 1 | 1 | 0 | 0 |

| 1 | 1 | 1 | 0 |

Logic expression for Z: Z = (A' AND B' AND C) OR (A' AND B AND C')

c) Simplification of the Boolean expression Q = (A. (A + C))' using De Morgan's laws:

Q = (A. (A + C))'

Apply De Morgan's law: (AB)' = A' + B'

Q = (A' + (A + C)')'

Apply De Morgan's law again: (A + B)' = A' . B'

Q = ((A')' . (A + C)')'

Simplifying the double negations: (A')' = A and (A + C)' = A' . C'

Q = (A . (A' . C'))'

Final simplified expression: Q = A . (A' . C')'

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Answer:

Because Star A and Star B have identical luminosities, the difference in their apparent brightness is due solely to distance. Star B is twice as far from Earth as Star A.

Explanation:

Answer:

 its not long dummy, its your imagination

Explanation:

Answer:

the charges get closer together

Answer:

B; the time needed to travel from W to X is the same as the time needed to travel from Y to Z.

Explanation:

According to Kepler's Second Law, the time it takes to travel each sweep of area is equal, the same way the area of each section is also equal. Also, this answer is correct on Edge.

Answer:

The answer is B !

Explanation:

I took the test and got it correct

Answer:

73 neutrons.

Explanation:

Data obtained from the question:

Mass number of Xenon = 127.

Neutron number =...?

We can obtain the number of neutron present as follow:

Atomic number of Xenon = 54

Recall:

Atomic number = proton number = 54

Mass number = proton + neutron

127 = 54 + Neutron

Neutron = 127 – 54

Neutron = 73.

Therefore, 73 neutrons are present in the Xenon atom.

Answer:

1298.5watt

Explanation:

Power is defined as the rate at which work is done

Expressed mathematically as;

P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered

Hence for 1 person the power consumption is ;

Note weight =mass× acceleration of free fall due to gravity,g

g is known as 9.8m/S2

Time taken is 1min which is 60 sec

60 ×9.8 × 5.3/60 = 51.94 watt

Hence for 25 persons we have

25 × 51.94 =1298.5watt

1.3kilo watt( kilo is 1000)

The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

The Work Done is calculated as:

Force (F) = 60 × 9.8

Distance (d) = 5.30 meters

Work (W) = F × d

Work (W) = (60 × 9.8) × 5.30

Work (W) = 3,080.4 joules

The Power is calculated as:

Time (t) = 1 minute

Power (P) = Work / Tim (t)

Power (P) = 3,080.4 / 60

Power (P) = 51.34 watts

Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

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Answer:

Hey mate....

Explanation:

This is ur answer....

Hope it helps!

Brainliest pls!

Follow me! ◇

International system of units.French système international d'Unitès, international decimal system of weights and measures derived from and extending the metric system of units.Adopted by the 11th General conference on weights and measures (CGPM) in 1960, It is abbreviated SI in all languages.

(a) To determine the force constant (k) of the spring, we will use Hooke's Law, which states that the force exerted by a spring (F) is proportional to the displacement (x) from its equilibrium position:

F = -kx

First, we need to calculate the gravitational force (weight) acting on the 2.40 kg object:

F = mg
F = (2.40 kg)(9.81 m/s²)
F ≈ 23.544 N

Now, we can use Hooke's Law to find the force constant (k):

23.544 N = k(0.0228 m)
k ≈ 1032 N/m

(b) To find the distance the spring stretches with a 1.20 kg object, we'll use the same formula:

F = (1.20 kg)(9.81 m/s²)
F ≈ 11.772 N

Now, rearrange Hooke's Law to solve for x:

x = F/k
x ≈ 11.772 N / 1032 N/m
x ≈ 0.0114 m or 1.14 cm

(c) To calculate the work (W) done by an external agent to stretch the spring 8.70 cm, we'll use the formula for the work done on a spring:

W = (1/2)kx²

First, convert the distance to meters:

x = 8.70 cm = 0.087 m

Now, calculate the work:

W = (1/2)(1032 N/m)(0.087 m)²
W ≈ 3.918 J

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Answer:

133m/s

Explanation:

b/c 250÷2.2÷0.85=133

Explanation:

I hope it helped U

stay safe stay happy

The kinetic energy of the baseball with a mass of 0.14 Kg and 30 m/s speed is 63 J.

Kinetic energy of an object is generated by virtue of its motion. It is dependant on the mass and speed of the object. Thus as mass or speed increases, kinetic energy increases.

The equation connecting the kinetic energy with the mass and speed , v is given as follows:

Ke = 1/2 m v²

Given that the mass = 0.14 kg

speed = 30 m/s.

kinetic energy = 1/2 0.14 × 30² = 63 J.

Therefore, the kinetic energy of the baseball is 63 J.

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Answer:

7 seconds

Explanation:

please see paper!

vf² = vo²+2ad

vf=vo+at

vf²=3.5²+2.2.75

vf²=312.25

vf=17.67 m/s

vf=vo+at

17.67 = 3.5 +2t

t=7.085 s

Answer:

a. Dugan's average speed for the entire race was 2.47 m/s.

b. Dugan's average speed for the first 25.00 m leg of the race was 2.48 m/s.

c. Since the starting and ending points are the same, the displacement is zero. Therefore, the average velocity is also zero.

Explanation:

To solve this problem, we'll need to use the formula:

average speed = total distance / total time

where total distance is the distance covered in the entire race (50 meters), and total time is the time it took Dugan to cover that distance.

a. To find Dugan's average speed for the entire race, we'll need to add up the times for both legs of the race:

total time = 10.08 seconds + 10.17 seconds = 20.25 seconds

Now we can plug in the values:

average speed = 50 meters / 20.25 seconds = 2.47 m/s

So Dugan's average speed for the entire race was 2.47 m/s.

b. To find Dugan's average speed for the first 25.00 m leg of the race, we'll need to use the formula again, but this time we'll only consider the first leg of the race:

average speed = 25 meters / 10.08 seconds = 2.48 m/s

So Dugan's average speed for the first 25.00 m leg of the race was 2.48 m/s.

c. Average velocity is the displacement (change in position) divided by the time taken. Since the starting and ending points are the same, the displacement is zero. Therefore, the average velocity is also zero.

Answer:

the guy above is actually right :)

Explanation:

The net force on an object is zero that is pulled with forces of 80 newtons to the right and 80 newtons to the left.

Net force is equal to sum of all the force acting on a body.

The formula for net force if n force are acting on it:

                       \(F_{net}=F_{1}+ F_{2}+F_{3}.....F_{n}\)

In this case the two forces are equal but opposite in direction.

Putting the values in the formula

\(F_{net} = 80+(-80)\) (since forces are equal but opposite)

\(F_{net}= 0\)

So the net force acting on the object is zero because the forces are equal and opposite.

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The net force on an object that is pulled with forces of 80 newtons to the right and 80 newtons to the left is: 0 newtons

To solve this problem the formula of net force and the procedure that we have to use is:

Fr = ∑F

Where:

Information about the problem:

Applying the resultant force formula we get:

Fr = ∑F

Fr = F1 + F2

Fr = 80 newtons - 80 newtons

Fr= 0 newtons

We can say that the resultant force is the algebraic sum of all the forces acting on a body.

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The work done by the electrostatic force on the moving point charge is 1.014 J.

d = √[(0.23 - 0.17)² + (0.27 - 0)²] = 0.277 m

F = kq₁q₂/r²

where;

F = (9 x 10⁹ x 2.4 x 10⁻⁶ x 4.9 x 10⁻⁶)/(0.17)²

F = 3.66 N

W = Fd

W = 3.66 x 0.277

W = 1.014 J

Thus, the work done by the electrostatic force on the moving point charge is 1.014 J.

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Answer:

False

Explanation:

A Larger pulse with more energy means that the wave has a large amplitude. As in the given question, both the waves are travelling in the same medium, hence their speeds will remain the same and therefore the larger pulse will not overtake the smaller pulse. Remember the amplitude of a wave does not affect the speed at which the wave travels.

Let's first resolve the two forces into their components as shown in the diagram below: The larger force (617 N) makes an angle of 46° with the horizontal axis.

Therefore, the horizontal component will be given by:

H = 617 cos 46°H = 617 × 0.69H = 425.73 N

The vertical component will be given by:V = 617 sin 46°V = 617 × 0.73V = 450.66 NOn the other hand, the smaller force (411 N) makes an angle of (90° - 46°) = 44° with the horizontal axis. Therefore, the horizontal component will be given by:H = 411 cos 44°H = 411 × 0.72H

= 296.52 N

The vertical component will be given by:V = 411 sin 44°V = 411 × 0.67V = 274.47 N The resultant horizontal component, R will be given by:R = 425.73 + 296.52R = 722.25 N The resultant vertical component, R will be given by:R = 450.66 + 274.47R = 725.13 N The magnitude of the resultant, R will be given by:R² = (722.25)² + (725.13)²R = √(522198.06)R = 722.82 N The angle that R makes with the larger force (617 N) will be given by:θ = tan⁻¹(725.13/722.25)θ = 45.23° Therefore, the magnitude of the resultant is 722.82 N and it makes an angle of 45.23° with the larger force.

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The kinetic energy of the baseball when thrown by a major-league pitcher at 95.0 mph is approximately 136.22 Joules.

The kinetic energy (KE) of an object can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass in kilograms, and v is the velocity in meters per second.

First, we need to convert the mass from ounces to kilograms and the velocity from miles per hour to meters per second.

1 oz = 0.0283495 kg

5.13 oz * 0.0283495 = 0.14515 kg

1 mph = 0.44704 m/s

95.0 mph * 0.44704 = 42.4698 m/s

Now, we can calculate the kinetic energy:

KE = 0.5 * 0.14515 kg * (42.4698 m/s)^2

KE ≈ 136.22 Joules

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The instantaneous velocity of the ball is when $t=2$ is 32 ft/s so the average velocity: 32 ft/s.

The given function is $y=60t-16t^2$. We need to find the average velocity of the ball for the time period beginning when $t=2$ seconds and lasting. The average velocity is calculated by dividing the distance travelled by the time taken. The average velocity for the time period beginning when $t=2$ seconds and lasting 0.5 seconds is calculated as follows:

Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Here, $y_2$ is the value of the function when $t=2.5$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.5)-16(2.5)^2=45$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.5$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{45-32}{0.5}]$Average velocity = $[\frac{13}{0.5}]$Average velocity = $26$ ft/sNow, for the time period beginning when $t=2$ seconds and lasting(ii) 0.1 seconds. Here, $y_2$ is the value of the function when $t=2.1$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.1)-16(2.1)^2=31.84$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.1$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.84-32}{0.1}]$Average velocity = $[-1.6]$ ft/s(iii) 0.01 seconds. Here, $y_2$ is the value of the function when $t=2.01$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.01)-16(2.01)^2=31.9364$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.01$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.9364-32}{0.01}]$Average velocity = $[-6.36]$ ft/s

Finally based on the above results, we can guess that the instantaneous velocity of the ball is when $t=2$ is 32 ft/s. hence, Average velocity: 32 ft/s.

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Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.