The complete question is;
A 1.15-kg mass oscillates according to the equation x = 0.650 cos(8.40t) where x is in meters and t in seconds. Determine (a) the amplitude, (b) the frequency, (c) the total energy, and (d) the kinetic energy and potential energy when x = 0.360 m.
Answer:
A) Amplitude; A = 0.650 m
B) Frequency; f = 1.337 Hz
C) total energy = 17.142 J
D) Kinetic energy = 11.884 J
Potential Energy = 5.258 J
Explanation:
We are given;
Mass;m = 1.15 kg
Equation; x = 0.650 cos (8.40t)
(a) The standard form of a wave function is in the form y(x,t) = Asin(kx−ωt+ϕ)
So, comparing terms in our equation in the question to this, the amplitude is;
A = 0.650 m
(b) we know that formula for frequency is;
f = ω/2π
Again, comparing terms in the standard equation and our question, we can see that ω = 8.4
Thus;
f = 8.4/(2π)
f = 1.337 Hz
(c) Formula for the total energy is given by;
E = m•ω²•A²/2
Plugging in the relevant values, we have;
E = (1.15)(8.40)²(0.650)²/2
E = 17.142 J
(d) we want to find the kinetic energy and potential energy when x = 0.360 m.
The formula for kinetic energy in this case is given by;
K = (1/2)•m•ω²•(A² - x²)
Thus;
K = (1/2) × (1.15) × (8.40)² × ((0.650)² - (0.360)²)
K = 11.884 J
Also, the formula for the potential energy in this case is given by;
U = (1/2)•m•ω²•x²
Thus;
U = (1/2) × (1.15) × (8.40)² × (0.360)²
U = 5.258 J
importance of states of matter
Answer:
STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.
Explanation:
A student puts a besker of warm water next to a besker of cold water so that they fough which two statements are true? DA Thermal energy will move from the warm water to the cold water Thermal energy will move from the air to the cold water. Thermal energy utill move from the air to the warm water Thermal energy till move from the cold water to the warm water
Explanation:
so sorry
don't know but please mark me as brainliest please
what is a Lever?
what is wedge
what is a inclined Plane/screw
what is a wheel and axle
what is a Pulley?
Answer:lever
Explanation:
You launch a model rocket from ground level. It moves directly upward with a constant acceleration of 71.0 m/s2 for 1.45 seconds, at which point it runs out of fuel. Assuming air resistance on the rocket is negligible, what is the maximum altitude (above the ground) achieved by the rocket?
m
Answer:
74.0 meters
Explanation:
We can use the kinematic equation for displacement with constant acceleration to solve this problem:
Δy = v0t + 1/2at^2
where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.
Plugging in the given values, we get:
Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2
Δy = 74.0 m
Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.
Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds
The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].
The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.
The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.
To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]
Y = 4.95sin[π(3.80x - 1180t - 0.206)]
The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.
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-- The given question is incomplete, the complete question is
"Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --
Why is there always plastic coverings around wires? Explain using terms like insulators and conductors.
Explanation:
as there is plastic covering around the wires because at the copper when we cover with like a insulators that can flow current are called insulators for when we when we touch the wire then we get current that's conductor orchid covering of fire so we can't be get a current
A 33.0-kg child starting from rest slides down a water slide with a vertical height of 15.0 m. (Neglect friction.)
(a) What is the child's speed halfway down the slide's vertical distance?
m/s
(b) What is the child's speed three-fourths of the way down?
m/s
Show My Work (Optional)
This question involves the concept of the conservation of energy.
(a) The child's speed halfway will be "12.13 m/s".
(b) The child's speed three-fourth way will be "14.86 m/s".
(a)
Using the law of conservation of energy:
Potential Energy Lost = Kinetic Energy Gained
\(mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}\)
where,
v = speed = ?
g = acceleration due to gravity = 9.81 m/s²
h = height lost = halfway = height/2 = 15 m/2 = 7.5 m
Therefore,
\(v = \sqrt{(2)(9.81\ m/s^2)(7.5\ m)}\)
v = 12.13 m/s
(b)
Using the law of conservation of energy:
Potential Energy Lost = Kinetic Energy Gained
\(mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}\)
where,
v = speed = ?
g = acceleration due to gravity = 9.81 m/s²
h = height lost = three-fourth way down = \(\frac{3}{4}height = \frac{3}{4}(15\ m) = 11.25\ m\)
Therefore,
\(v = \sqrt{(2)(9.81\ m/s^2)(11.25\ m)}\)
v = 14.86 m/s
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The attached picture shows the law of conservation of energy.
What is Energy in physics?
Answer:
Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.
Explanation:
Hope this helps!
Which part of a road vehicle must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency?
The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.
What is Friction?This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.
When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.
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if the mass of the paper is 0.003 kg, what force does the boxer except on it?
Answer:
1.15 N
Explanation:
You want to know the force exerted on a mass of 0.003 kg to accelerate it from 0 to 23 m/s in a period of 0.06 s.
AccelerationThe acceleration of the mass is the change in velocity divided by the change in time:
a = ∆v/∆t
a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²
ForceThe force applied is the product of mass and acceleration:
F = ma
F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N
The applied force is 1.15 newtons.
If a ball leaves the ground with a velocity of 4.67 m/s,
how high does the ball travel?
Answer:
\(Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\\)
according to Newton's law of motion, when we shake a mango tree, mangoes fall down explain.
A long, straight, vertical wire carries a current upward. Due east of this wire, in what direction does the magnetic field point
The magnetic field of the wire will be directed towards west. Using right thumb rule one can get the direction of field lines.
What is the field outside the capacitor plates in a parallel capacitor?
Answer is zero
Plz mark me brainlist
Explanation:
Outside two infinite parallel plates with opposite charge the electric field is zero, and that can be proved with Gauss's law using any possible Gaussian surface imaginable
2. Gerard is riding his bicycle directly east. His maximum
instantaneous velocity was 8 meters per second and his
minimum instantaneous velocity was 0 meters per second. He
covered 7.20 kilometers in 20.0 minutes. What is his average
velocity for the ride?
Gerard's average velocity for the ride is 6 meters per second.
To find Gerard's average velocity for the ride, we can use the formula:
Average velocity = Total displacement / Total time
First, we need to convert the distance traveled from kilometers to meters:
7.20 kilometers * 1000 = 7200 meters
Next, we convert the time from minutes to seconds:
20.0 minutes * 60 = 1200 seconds
Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:
Total displacement = 7200 meters
Finally, we substitute the values into the average velocity formula:
Average velocity = 7200 meters / 1200 seconds
Average velocity = 6 meters per second
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in fig. 9-21, suppose that the projectile has an initial momentum of 6 kg m/s, a final x component of momentum of 4 kg m/s, and a final y component of momentum of 3 kg m/s. for the target, what then are (a) the final x component of momentum and (b) the final y component of momentum?
The formula used by the momentum calculator is p=mv, or momentum (p) equals mass (m) equals velocity (v).
What is the initial and ultimate momentum formula?The Momentum-Impulse Theorem for just a single item yields the final momentum by adding the beginning momentum and the impulse: pi + p Equals p f p I Plus p. Impulse is measured in the same units as momentum, which are kgms=Ns s n g m s =0 N s.
What is an object's final momentum?The mass of the both balls multiplied by the final velocity, or (4+6), would give the final momentum (vf). The conservation of momentum allows us to find vf; the final momentum must equal the sum of the original momentum values. As a result of their opposing directions, ball B's velocity was negative.
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3. What is the acceleration of a cart with a F = 80 N and m = 32 kg? *
2.0 m/s^2
O 2.5 m/s^2
2.8 m/s^2
2.7 m/s^2
Answer:
2.5 m/s^2
Explanation:
Given the following data;
Force = 80N
Mass = 32kg
To find acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
\( F = ma\)
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
\(Acceleration (a) = \frac{F}{m}\)
Substituting into the equation;
\(Acceleration (a) = \frac{80}{32}\)
Acceleration = 2.5m/s²
The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.
Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.
Plugging in the values, we get:
F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2
Simplifying this, we get:
F = 1.98 x 10^27 N
Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.
The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)
The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)For more questions on gravitational force
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what is difference between heat engine and carnot engine
Answer: A heat engine uses temperature differences which cause pressure changes to exert force on a moving part. A Carnot Process is a theoretical explanation of a process involving pressure and temperature changes during ,amongst other things, phase changes.
Explanation:
Answer: The difference is a heat engine uses temperature differences which cause pressure changes to exert force on a moving part, A Carnot engine is only a theoretical explanation of a process involving pressure and temperature changes during or amongst other things.
Explanation:
When a 2kg metal is exposed to 2MJ of
heat it dissolves into liquid at 500K
Calculate the latent heat of fusion for
the metal. Betty went in to get you metal is exposed to to megajoules of heat
Answer:
1×10⁶ J/Kg
Explanation:
From the question given above, the following data were obtained:
Mass (m) of metal = 2 Kg
Heat (Q) = 2 MJ
Latent heat of Fusion (Hf) =?
Next, we shall convert 2 MJ to J. This can be obtained as follow:
1 MJ = 1×10⁶ J
Therefore,
2 MJ = 2 MJ × 1×10⁶ J / 1 MJ
2 MJ = 2×10⁶ J
Finally, we shall determine the latent heat of fusion. This can be obtained as follow:
Mass (m) of metal = 2 Kg
Heat (Q) = 2×10⁶ J
Latent heat of Fusion (Hf) =?
Q = m•Hf
2×10⁶ = 2 × Hf
Divide both side by 2
Hf = 2×10⁶ / 2
Hf = 1×10⁶ J/Kg
Thus, the latent heat of fusion for the metal is 1×10⁶ J/Kg
Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]
What is the difference between vector and velocity?
Answer:
Is the vector is(mathematics) a directed quantity, one with both magnitude and direction, the (soplink) between two points while velocity is (physics) a vector quant that denotes the rate of change of position with respect to time or a speed with the directional component.
need help with problem 24 part b and c if possible
For b)
We will use the formula of Newton's second law
\(F=ma\)where F is the force, m is the mass and a is the acceleration. In this case we have
F=85N
m=75 kg
a=?
We will isolate the a
\(a=\frac{F}{m}\)we substitute the values
\(a=\frac{85}{75}=1.13m/s^2\)c)
We will use the same formula that we use previously but in this case, we have the next data
F=-85N
m=55 kg
\(a=\frac{-85}{55}=-1.55m/s^2\)ANSWER
b) 1.13 m/s^2
c)-1.55 m/s^2
A roller coaster has a mass of 450 kgIt sits at the top of a hill with height 49 m. If it drops from this hill, how fast is it going when it reaches the bottom? Assume there is no air resistance or friction.)
The speed of the roller coater at the bottom of the hill is 31 m/s.
Speed of the roller coater at the bottom of the hill
Apply the principle of conservation of mechanical energy as follows;
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v is the speed of the coater at bottom hillh is the height of the hillg is acceleration due to gravityv = √(2 x 9.8 x 49)
v = 31 m/s
Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.
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The diagram shows part of a spring that is shaken from side to side to produce a wave.
0.60m
The distance between successive peaks is 0.60 m and the frequency is 2.5 Hz.
How long does it take for a wave to travel 3.0 m along the spring?
A 0.20 s
B 0.50s
C 2.0s
D 5.0 s
It takes 5.0 s for a wave to travel 3.0 m along the spring.
The time it takes for a wave to travel 3.0 m along the spring is 5.0 s. This can be calculated by dividing the distance (3.0 m) by the wave speed, which is equal to the frequency (2.5 Hz) multiplied by the distance between successive peaks (0.60 m).
3.0 m / (2.5 Hz x 0.60 m) = 5.0 s
What is frequency?
Frequency is a measure of the number of times a particular event or phenomenon occurs within a given period of time. It is usually expressed as an oscillations per second (Hertz). Frequency is an important measure in many fields, including physics, engineering, electronics, and music.
Therefore, It takes 5.0 s for a wave to travel 3.0 m along the spring.
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An 82kg male and 48kg female pari figure starting team are gliding across the ice of 7.4m/s preparing for a throw jump maneuver. The male starter tosses the female starter forward with a speed of 8.6n/s. Determine the speed of the male starter immediately after the throw.
Answer:
Explanation:
(m1 + m2)*V1 = m2*V2 + m1*Vx
Vx = ((m1 + m2)*V1 - m2*V2) / m1
Vx = ((82 + 48)*7.4 - 48*8.6) /82 = 6.7 m/s
4. A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Planet X as on Earth. If the escape velocity for the rocket taking off from Earth is v0, then its escape velocity on Planet X is
(A) 2v0
(B) sqrt(2)v0
(C) v0
(D) v0/2
(E) v0/4
The escape velocity for the rocket taking off from Earth is v0, then its escape velocity on Planet X is (A) 2v0.
The surface gravity of a planet is given by:
g = \(GM/R^2,\)
where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.
Let's assume that the mass of the astronaut is m. On Earth, the weight of the astronaut is given by:
mg = \(GMearth/Rearth^2,\)
where Mearth and Rearth are the mass and radius of the Earth, respectively.
On Planet X, the weight of the astronaut is given by:
mgx =
Since the astronaut weighs twice as much on Planet X as on Earth, we have:
mgx = 2mg.
Combining these equations, we get:
\(GMx/Rx^2 = 2GMearth/Rearth^2.\)
Since Planet X has half the radius of Earth, we have:
Rx = Rearth/2.
Substituting this into the above equation, we get:
GMx/\((Rearth/4)^2\) = 2GMearth/\(Rearth^2,\)
or
GMx = 8GMearth.
The escape velocity of a planet is given by:
v_escape = sqrt(2GM/R),
where R is the radius of the planet.
On Earth, the escape velocity is:
v_escape,earth = sqrt(2GMearth/Rearth).
On Planet X, the escape velocity is:
v_escape,x = sqrt(2GMx/Rx).
Substituting the expressions for GMx and Rx, we get:
v_escape,x = sqrt(2(8GMearth)/(Rearth/2)),
or
v_escape,x = sqrt(32) * sqrt(GMearth/Rearth).
Since sqrt(32) is approximately equal to 5.66, we have:
v_escape,x = 5.66 * v_escape,earth.
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Water flows through a valve with inlet and outlet velocities of 3 m/s. If the loss coefficient of the valve is 2.0, and the specific weight of water is 9800 N/m3, the pressure drop across the valve is most nearly:
Answer:
The value is \(\delta P = 9000 \ Pa\)
Explanation:
From the question we are told that
The inlet and outlet velocity is \(v = 3 \ m/s\)
The loss coefficient is \(k = 2\)
Th specific weight of water is \(w = 9800 \ N/m^3\)
Generally the pressure drop across the valve is mathematically represented as
\(\delta P = \frac{1}{2} * k * \rho * v^2\)
Here \(\rho\) is the density which is mathematically represented as
\(\rho = \frac{w}{g}\)
=> \(\rho = \frac{9800}{9.8}\)
=> \(\rho = 1000 \ kg/m^3\)
So
\(\delta P = \frac{1}{2} * 2* 1000 * 3^2\)
\(\delta P = 9000 \ Pa\)
How does thermal energy play a role in particle motion and changes of state?
Answer:
Increasing an object's thermal energy increases particle motion and can cause a change of state. Decreasing an object's thermal energy increases particle motion and can cause a change of state.
What technology do researchers use today to help gather data
Answer:
Researchers use a wide range of technologies today to help gather data, depending on the field of study and the type of data they need to collect. Here are some examples:
Sensors: Sensors are devices that can detect and measure physical quantities such as temperature, pressure, and motion. Researchers use sensors to collect data on the environment, human behavior, and other phenomena.
Drones: Drones or unmanned aerial vehicles (UAVs) are aircraft that are remotely controlled or can fly autonomously. Researchers use drones to collect data from hard-to-reach or dangerous areas, such as remote forests, volcanoes, or disaster zones.
Satellites: Satellites are spacecraft that orbit the Earth and can collect data on a wide range of environmental and climatic factors, such as temperature, rainfall, and ocean currents. Researchers use satellite data to study climate change, natural disasters, and other global phenomena.
Imaging technologies: Imaging technologies such as magnetic resonance imaging (MRI) and computed tomography (CT) scans are used to collect detailed images of the body's internal structures. Researchers use these images to study the human brain, diagnose diseases, and develop new medical treatments.
Social media and online platforms: Social media and online platforms provide researchers with access to large amounts of data on human behavior, opinions, and attitudes. Researchers use this data to study social trends, political movements, and public opinion.
Wearable technology: Wearable technology such as fitness trackers and smartwatches collect data on physical activity, heart rate, and other health metrics. Researchers use this data to study human health and behavior.
These are just a few examples of the many technologies researchers use today to help gather data. The use of advanced technology has revolutionized the way researchers collect and analyze data, allowing them to make new discoveries and gain a deeper understanding of the world around us.