A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acceleration of the crate after it begins to move

Answer:

Explanation:

You didn't ask a question here, but I assume you want the pressure? You can use the ideal gas equation stating that:

PV = nRT

The 'P' is pressure, the 'V' is volume, the 'n is number of moles of gas, the 'R' is the ideal gas constant, and the 'T' is the temperature. First convert the Celsius degrees into Kelvin by using the following relation:

C + 273.15 = K

4 + 273.15 = 277.15K

Now, find the volume of a cylinder by using:

\(V=\pi r^2l\)

The 'l' is the length of the cylinder

Now just plug and chug everything into the ideal gas equation:

\(PV=nRT\)

\(P(\pi r^2l)=(5moles)(8.3145J/moles*K)(277.15K)P=\frac{11.52J}{\pi r^2l}\)

The value of equivalent resistance in the given parallel resistance circuit is 65.21 Ω.

Two resistors are connected in parallel when they are connected between the same two nodes.

Although parallel resistors have the same voltage drop, the currents passing through them may not be identical. Resistors that are electrically parallel don't necessarily have two parallel lines.

Resistance of the first resistor, R₁ = 75 Ω

Resistance of the second resistor, R₂ = 500 Ω

The expression for the equivalent resistance in the parallel resistance circuit is given by,

1/Req = 1/R₁ + 1/R₂

So,

Req = R₁R₂/(R₁ + R₂)

Req = 75 x 500/(75 + 500)

Req = 37500/575

Req = 65.21 Ω

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The ratio of maximum intensity to minimum intensity is -109/35.In interference, the intensity of the resulting light is given by the sum of the intensities of the individual sources, taking into account the phase difference between them.

Let's assume the intensities of the two coherent sources are I₁ and I₂, with a ratio of 36:1, respectively. So, we have I₁:I₂ = 36:1.

The resulting intensity, I, can be calculated using the formula for the sum of intensities:

I = I₁ + I₂ + 2√(I₁I₂)cos(Δφ)

where Δφ is the phase difference between the sources.

To determine the ratio of maximum intensity to minimum intensity, we need to consider the extreme cases of constructive and destructive interference.

For constructive interference, the phase difference Δφ is such that cos(Δφ) = 1, resulting in the maximum intensity.

For destructive interference, the phase difference Δφ is such that cos(Δφ) = -1, resulting in the minimum intensity.

Let's denote the maximum intensity as Imax and the minimum intensity as Imin.

For constructive interference: I = I₁ + I₂ + 2√(I₁I₂)cos(Δφ) = I₁ + I₂ + 2√(I₁I₂)(1) = I₁ + I₂ + 2√(I₁I₂)

For destructive interference: I = I₁ + I₂ + 2√(I₁I₂)cos(Δφ) = I₁ + I₂ + 2√(I₁I₂)(-1) = I₁ + I₂ - 2√(I₁I₂)

Taking the ratios of maximum and minimum intensities:

Imax/Imin = (I₁ + I₂ + 2√(I₁I₂))/(I₁ + I₂ - 2√(I₁I₂))

Substituting the given intensity ratio I₁:I₂ = 36:1:

Imax/Imin = (36 + 1 + 2√(36))(36 + 1 - 2√(36)) = (37 + 12√(36))/(37 - 12√(36))

Simplifying:

Imax/Imin = (37 + 12 * 6)/(37 - 12 * 6) = (37 + 72)/(37 - 72) = 109/(-35)

Therefore, the ratio of maximum intensity to minimum intensity is -109/35.

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Answer:En general, los semiconductores son materiales, inorgánicos u orgánicos, que tienen la capacidad de controlar su conducción dependiendo de ...

Explanation:

While the measure described in (a) may not directly apply to a test with binary, categorical, and numerical answers, the appropriate statistical measures and techniques would be determined based on the specific properties and analysis needs of each type of answer.

In the context of a test comprising binary, categorical, and numerical answers, the measure described for (a) may not be directly applicable. Binary and categorical answers fall under the nominal level of measurement, representing qualitative categories without inherent numerical value or order. Numerical answers may have either interval or ratio measurement, with varying mathematical properties.

When analyzing such a test, different statistical measures and techniques would be employed based on the specific nature of the data. This may involve analyzing frequencies and proportions for categorical responses and utilizing descriptive or inferential statistics for numerical answers. The appropriate statistical approaches would be determined by considering the distinct properties of each answer type.

Therefore, while the measure described in (a) may not directly apply to a test with binary, categorical, and numerical answers, the appropriate statistical measures and techniques would be determined based on the specific properties and analysis needs of each type of answer.

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The Sweden

___________

The composite figure is a combination of a rectangular pyramid and a rectangular prism, hence its volume is 140in³.

A rectangular prism is simply a three dimensional solid shape with six faces that are rectangles.

Volume of a rectangular prism is expressed as;

V = w × h × l

Where l is length, h is height and w is width

A rectangular pyramid is simply a three-dimentional object with a rectangular shaped base and triangular shaped faces that correspond to each side of the base.

The volume of rectangular pyramid is expressed as;

V = (1/3) × l × w × h

Where l is the base length, w is the base width and h is the height of the pyramid.

From the diagram below;

First we calculate the volume of a rectangular prism.

V = w × h × l

V = 3in × 4in × 7in

V = 84in³

Hence, the volume of the rectangular prism is 84in³.

Next, we calculate the volume of rectangular pyramid.

V = (1/3) × l × w × h

V = (1/3) × 7in × 3in × 8in

V = (1/3) × 168in³

V = 56in³

Hence, the volume of the rectangular pyramid is 56in³.

Volume of the composite figure = Volume of prism + Volume of pyramid

Volume of the composite figure = 84in³ + 56in³

Volume of the composite figure = 140in³

Therefore, the composite figure is a combination of a rectangular pyramid and rectangular prism, hence its volume is 140in³.

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The energy release when one atom of ^132Sb undergoes alpha decay to become one atom of ^97Nb is approximately 4.9503 × 10^-12 J.

The mass of the parent nucleus ^132Sb is greater than the mass of the daughter nucleus ^97Nb, so there is a release of energy when an alpha particle is emitted.

The mass lost during the decay process is:

mass lost = mass of parent - mass of daughter - mass of alpha particle

mass lost = 132.915250 u - 97.910328 u - 4.002603 u

mass lost = 30.002319 u

The energy released during the decay process can be calculated using Einstein's famous equation, E = mc^2:

E = (mass lost) × c^2

\(E = 30.002319 u \times (1.66054 \times10^-27 kg/u) \times (2.99792 \times 10^8 m/s)^2\)

E = 4.9503 × 10^-12 J

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To calculate the energy release from the atomic masses of Sb and Nb isotopes, we need to use Einstein's famous equation:

E = Δm * c^2

where E is the energy release, Δm is the change in mass, and c is the speed of light.

The change in mass, Δm, is given by the difference between the atomic masses of the products and reactants in the nuclear reaction. Assuming that the isotopes undergo a nuclear reaction that releases energy, we can use the atomic masses of the reactants and products to find Δm:

Δm = (mass of reactants) - (mass of products)

For example, if the reaction is:

A + B -> C + energy

then the Δm would be:

Δm = (mass of A + mass of B) - (mass of C)

In this case, we need to know the nuclear reaction that the isotopes undergo to release energy. Let's assume that both isotopes undergo nuclear fission, where they split into two smaller nuclei and release energy. We can write this as:

Sb-132 + n -> Ba-97 + Kr-36 + 3n

Nb-97 + n -> Sr-94 + Zr-42 + 2n

where n is a neutron.

Using the atomic masses of the isotopes, we can calculate the Δm for each reaction:

Δm(Sb) = (132.915250 u + 1.008665 u) - (96.949750 u + 35.967546 u + 3.026400 u) = -0.017671 u

Δm(Nb) = (97.910328 u + 1.008665 u) - (93.913730 u + 42.965630 u + 1.008665 u) = -0.028372 u

Now we can use Einstein's equation to calculate the energy release for each reaction:

E(Sb) = Δm(Sb) * c^2 = (-0.017671 u) * (931.5 MeV/u) = -16.449 MeV

E(Nb) = Δm(Nb) * c^2 = (-0.028372 u) * (931.5 MeV/u) = -26.444 MeV

Therefore, the energy release for the Sb-132 and Nb-97 isotopes undergoing nuclear fission reactions is approximately -16.449 MeV and -26.444 MeV, respectively. The negative sign indicates that energy is released in the reaction.

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The equation TC + or - WCA = TH is correct among the given equations. The option A is correct.

These given equations are regarding the magnetic compass errors.

Now, let us see the full form of the given above equation.

First Letter

T = concerning TRUE North (use plotter and latitude)

M = Regarding MAGNETIC North (True North +/- Deviation)

C = refers to the COMPASS North (Magnetic North +/- Compass card deviation) system

Second Letter

C = Plotted COURSE on the map (no wind correction applied)

H = Aircraft's HEADING after applying wind correction (Course +/- Wind Correction Angle)

Normal Order

TC = True course

VAR = Variation

MC = Magnetic course

WCA = Wind correction angle

MH = Magnetic heading

DEV = Deviation

CH = Compass heading

So, the above correct equation means that, True Course + or - Wind correction angle = True heading

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Answer:

2000

Explanation:

well it is just   20 * 100 = 2000 v

Answer:

approximately 5.76 × 10^−7 meters, or 576 nanometers

Explanation:

The location of bright fringes in a double slit experiment is given by the formula:

d * sin(θ) = m * λ

where:

d is the slit separation,

θ is the angle at which the fringe occurs,

m is the order of the fringe (m = 0 for the central maximum, m = 1 for the first bright fringe, m = 2 for the second bright fringe, and so on), and

λ is the wavelength of the light.

We're looking for the wavelength of the light, and we're given that d = 2.02 × 10^−6 m, θ = 16.5°, and m = 1 (since we're looking at the first bright fringe).

Rearranging the formula to solve for λ gives us:

λ = d * sin(θ) / m

We need to make sure that we're working in radians, as that's what the trigonometric functions in most programming and calculation tools expect. There are π radians in 180 degrees, so to convert from degrees to radians, we multiply by π/180. This gives us θ = 16.5° * π/180 = 0.2873 radians.

Substituting the given values into the formula gives us:

λ = (2.02 × 10^−6 m) * sin(0.2873) / 1

λ ≈ 5.76 * 10^-7 m

So the wavelength of the light is approximately 5.76 × 10^−7 meters, or 576 nanometers (since 1 m = 10^9 nm).

Answer:

R = 240 Ω

Explanation:

The resistance created by the light bulb can be calculated by using Ohm's Law:

\(V = IR\\\\R =\frac{V}{I}\)

where,

R = Resistance created by the light bulb = ?

V = Voltage across the bulb = 120 volts

I = current passing through the light bulb = 0.5 A

Therefore,

\(R = \frac{120\ volts}{0.5\ A}\)

R = 240 Ω

Answer:it is c i just did it and got it right. :3

Explanation:

The distance travelled by the car in the first 20 seconds of the motion is 130 m.

The area under the speed-time graph is the distance the particle travels.

The distance traveled by the car in the first 20 seconds is calculated as follows;

From the speed - time graph, at 20 seconds, the speed of the car is 13 m/s.

Distance = area of the graph = area of triangle formed from time, 0 s to 20 seconds.

Distance = ¹/₂bh

where;

Substitute the given parameters and solve for the distance traveled by the car.

Distance = ¹/₂bh

Distance = ¹/₂(20)(13)

Distance = 130 m

Thus, the distance travelled by the car in the first 20 seconds of the motion is 130 m.

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The missing graph is in the image attached.

The main cause of melting along subduction zones is the d. release of water from the subducting plate.

Subduction zones are areas where one tectonic plate moves beneath another, causing the denser plate to sink into the mantle. This process generates a significant amount of heat, which contributes to the melting of rocks in the mantle lithosphere.
As the subducting plate moves deeper into the mantle, it experiences increasing pressure and temperature. The minerals within the subducting plate contain water, which is released as the plate is subjected to these extreme conditions. This released water reduces the melting point of the surrounding mantle rocks, causing them to partially melt.

This partial melting creates magma, which can rise through the mantle lithosphere and eventually reach the Earth's surface, resulting in volcanic activity. The release of water from the subducting plate, therefore, plays a crucial role in generating the magma that leads to volcanic eruptions along subduction zones.
In summary, the main cause of melting along subduction zones is the d. release of water from the subducting plate, which lowers the melting point of surrounding mantle rocks and generates magma. This magma can rise through the mantle lithosphere, causing volcanic activity in these regions.

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The main cause of melting in subduction zones is the release of water from the subducting plate, which lowers the melting temperature of the surrounding rocks and causes them to melt.

The main cause of melting along subduction zones is primarily the release of water from the subducting plate (option d). When the oceanic lithosphere subducts, it carries with it water that has been trapped in the minerals of the crust and upper mantle. This water lowers the melting temperature of the surrounding rocks, causing them to melt and form magma. This is termed 'flux melting'. For example, the subduction of the Pacific Plate beneath the North American Plate in the Cascadia subduction zone causes intense volcanic activity in the Pacific Northwest.

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We must first determine the amount of force needed to lift the boxes against gravity. The weight of the boxes is calculated as follows: 30 boxes x 6 kg/box = 180 kg

Work = Force x Distance Work = 1765.8 N x 1.5 m Work = 2648.7 Joules Force = Weight x Gravitational Acceleration Force = 180 kg x 9.81 m/s2 Force = 1765.8 N

The total work required to raise thirty 6 kilogram boxes onto a 1.5 m high shelf is therefore 2648.7 Joules.

Hence, the gravitational pull between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two. To put it another way, the gravitational potential energy directly relates to how high an item is above the earth. Consequently, an item needs be elevated higher in order to enhance its gravitational potential energy. The gravitational potential energy increases with height.

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Answer:

Galaxy A is reported to be receding from us with a speed of 0.35c. Galaxy B, located in precisely the opposite direction, is also found

ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

To determine if an element is paramagnetic or diamagnetic, one can perform a magnetic susceptibility test.

Paramagnetic and diamagnetic elements refer to the magnetic properties of elements and molecules. Paramagnetic materials are attracted to a magnetic field, while diamagnetic materials are repelled by a magnetic field.

Paramagnetic substances have a positive magnetic susceptibility, meaning they are attracted to a magnetic field and experience an increase in magnetic polarization. Diamagnetic substances have a negative magnetic susceptibility, meaning they are repelled by a magnetic field and experience a decrease in magnetic polarization.

Another way to determine the magnetic properties of an element is to observe its behavior in a magnetic field. If an element experiences attraction to a magnetic field, it is paramagnetic, and if it experiences repulsion, it is diamagnetic.

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False. X-ray bursters are not similar to novae. They are phenomena that occur in binary systems containing a neutron star and a low-mass star. In these systems, the neutron star attracts material from its companion, and this material accumulates on its surface.

When enough material accumulates, it ignites and releases a burst of X-rays. This process is cyclical and can occur every few hours to every few weeks.

On the other hand, novae are phenomena that occur in binary systems containing a white dwarf and a companion star. In these systems, the white dwarf attracts material from its companion, and this material accumulates on its surface.

When enough material accumulates, it ignites in a thermonuclear explosion that causes a sudden increase in brightness. This process is also cyclical and can occur every few decades to every few centuries.

Therefore, it can be concluded that x-ray bursters are not similar to novae, and the collapsed star in x-ray bursters is a neutron star, not a white dwarf.

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The velocity of sound in air at STP (Standard Temperature and Pressure) is approximately 344 m/s. If the frequency of the sound wave is 200 Hz, then the wavelength of the sound wave can be calculated as follows:The formula that relates velocity, frequency, and wavelength of a wave is given as.

Where:

v = velocity of sound in air at STP, which is 344 m/sf = frequency of sound waveλ = wavelength of sound waveWe are given that f = 200 Hz. Substituting the values in the formula,v = fλ344 = 200 × λTherefore, the wavelength of the sound wave is:

λ = 344/200λ = 1.72 m.

Thus, the wavelength of the sound wave with a frequency of 200 Hz is 1.72 meters.

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Answer:

Explanation:

By being close to an atom that will gladly take the electrons being offered.

Suppose you are talking about Be. It is in the second column. It has two outer electrons that can be given away. It will not give away one of the two remaining electrons because they are too close to the + nucleus.

Along comes a Fluorine atom. It has 7 electrons in its outer ring. The chemistry of the situation allows it to take on one of the two electrons Be is offering. It is all a matter of charges and attractions.

Another Fluorine atom will take on the remaining electron from the Be. The outer ring cannot take on more than 1 electron, but that is enough

Answer:

car 4 i think

Explanation:

Answer:

car 3

Explanation:

car 1 - fastest - .5 seconds per meter

car 2- 2nd fastest - 1 second per meter

car 4 - 3rd fastest - 1.25 seconds per meter

car 3 - slowest - 1.5 seconds per meter

Answer:

a) 5.01 m/s

b) 3.28 m/s

c) 0.67 s

d) 0.45 m

e) 2.78 m

Explanation:

Answer:

a) 3.04 m/s

b) 3.7 m/s

c) 0.72 s

d) 0.36 m

e) 4.12 m

Explanation:

Answer:

Applied force

Normal force

Frictional force

Tension force

Wind force

Answer: Reaction force. An object at rest on a surface experiences reaction force .

Tension. An object that is being stretched experiences a tension force.

Friction. Two objects sliding past each other experience friction forces. ...

Air resistance. An object moving through the air experiences air resistance .

Gravitational Force.

Explanation:

Answer: She moves 5.616 meters in that second.

Explanation:

If we define t = 0s as the moment when she starts decelerating we can write the function of acceleration as:

a(t) = -(0.63 m/s^2)

where the negative sign is because she is slowing down.

The velocity equation can be found if we integrate over time:

v(t) = -(0.63m/s^2)*t + v0

Where v0 is the constant of integration, that represents the initial velocity, in this case is:

v0 = 32.7 km/h

Now, because the acceleration is in m/s^2, we should write this velocity in m/s.

in one km we have 1000 meters, and in one hour we have 3600 seconds, then we have that:

32.7 km/h = 32.7 *(1000/3600) m/s = 9.08 m/s

Then the velocity equation becomes:

v(t) = -(0.63m/s^2)*t  + 9.08 m/s

And for the position equation, we should integrate again to get:

p(t) = -(1/2)*(0.63m/s^2)*t^2 + (9.08m/s)*t + p0

Where p0 is the initial position.

For this problem, we want to find the distance that she moved between t = 5s and t = 6s, and that can be calculated as:

D = p(6s) - p(5s)

D = -(1/2)*(0.63m/s^2)*(6s)^2 + (9.08m/s)*6s + p0 +(1/2)*(0.63m/s^2)*(5s)^2 - (9.08m/s)*(5s) - p0

D = -(1/2)*(0.63m/s^2)*((6s)^2 - (5s)^2) + (9.08m/s)*(6s - 5s)

D = 5.615 m

She moves 5.616 meters in that second.

your answer is...

C. potassium