a 0.350 kg block at -27.5 (degree C) is added to 0.217 kg of water at 25.0 (degree Celsius). they come to equilibrium at 16.4 (degree Celsius). what is the specific heat of the block?

Answer:

true

Explanation:

they can cause skin damage

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + (13 x 2)

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

Finally, they rely on a variety of environmental cues such as the length of the day, the Sun's position and angle in the sky, water salinity and temperature gradients, and the Earth's magnetic field. They do this to navigate effectively.

Animal navigation refers to the ability of many animals to find their way around without the use of maps or instruments.

Birds like the Arctic tern, insects like the monarch butterfly, and fish like salmon migrate thousands of miles to and from their breeding grounds on a regular basis, and many other species navigate effectively over shorter distances.

Several animal species can use a variety of cues to help them orient and navigate effectively. Insects and birds can identify where they are and navigate by combining learned landmarks with sensed direction (from the earth's magnetic field or from the sky).

Thus, this is why an animal might use more than one type of clue to find its way.

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i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

M.A = Load/Effort

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

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Pption d. flow does not independently influence the speed of water in a stream. Instead, it is an outcome determined by the combined effects of gradient, discharge, and channel geometry.

The flow itself, or the rate at which water moves in a stream, is not an independent factor that influences the speed of water in a stream. Instead, it is a result of other factors such as gradient, discharge, and channel geometry.

a. Gradient: The gradient, or slope, of the stream affects the speed of water. Steeper gradients generally lead to faster-flowing water.

b. Discharge: The discharge of a stream, which refers to the volume of water passing through a given point in a specified amount of time, directly affects the speed of water. Higher discharge results in faster flow.

c. Channel geometry: The shape and dimensions of the stream channel also influence the speed of water. Wider and deeper channels tend to have slower flow, while narrower and shallower channels often lead to faster flow.

Therefore, option d. flow does not independently influence the speed of water in a stream. Instead, it is an outcome determined by the combined effects of gradient, discharge, and channel geometry.

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Answer:

whats the question lol

Explanation:

Answer:d

Explanation:

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

What is a drag force?

Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.

Here,

mass of the water, m1 = 3.0 kg

mass of the squid, m2 = 36 kg

initial speed, v2 = 3.5 m/s

(a)

According to the conservation of momentum:

m1*v1 = m2*v2

3 * v1 = 36 * 3.5

v1 = 42 m/s

It is the speed at which the squid rejects the water.

(b)

The maximum range:

R(max) = (v2) ^2 / g

where,

g=9.8 m/s^2 and launch angle is 45°

R(max) = 3.5^2 / 9.8

R(max) =  1.25 m

Hence,

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

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Your question is incomplete, but most probably the full question was:

We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.

a. At what speed does the squid eject the water?

b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

Answer:

Distance cover in 2  hour = 6 kilometer

Explanation:

Given equation:

x = 2t - 10

where

x = kilometer

t = hour

Find:

Distance cover in 2  hour

Computation:

T = 2

So,

x = 2t - 10

x = 2(2) - 10

x = 4 - 10

x = -6

Distance cover in 2  hour = 6 kilometer

Answer:

The distance is 6 km.

Explanation:

The equation of uniform linear motion of a particle has the form: x = 2t – 10. (x: km, t: h). What is the distance traveled by the particle after 2 hours?

x = 2t - 10

distance traveled after t = 2 hours

Substitute t = 2 in the given expression

x = 2 x 2 - 10

x = 4 - 10

x = - 6 km

So, the distance is 6 km.

The Zeeman effect on the 5461 Å line with a gyromagnetic ratio of 1 instead of 2.001 would result in different energy level splitting and spectral lines.

To understand this effect, follow these steps:
1. Recall that the Zeeman effect refers to the splitting of spectral lines in the presence of an external magnetic field.

2. The energy shift due to the Zeeman effect is given by the formula: ΔE = \(m_j * g_j * \mu_B * B\), where \(m_j\) is the magnetic quantum number, \(g_j\) is the gyromagnetic ratio, \(\mu_B\) is the Bohr magneton, and B is the magnetic field strength.

3. Note that the original gyromagnetic ratio is 2.001. If the gyromagnetic ratio were 1 instead, the energy shift would be smaller, given that \(g_j\) is now smaller.

4. With a smaller energy shift, the splitting of the spectral lines in the presence of a magnetic field would be different than when the gyromagnetic ratio is 2.001.

5. This change in the gyromagnetic ratio would result in a different pattern of spectral lines and energy level splitting for the 5461 Å line due to the modified Zeeman effect.

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Split F₁ into its horizontal and vertical components:

F₁ = F₁ cos(θ) i + F₁ sin(θ) j

(boldface = vector; regular font = magnitude)

By Newton's second law, if the object is in equilibrium, then

• the net horizontal force on the block is

∑ F = F₁ cos(θ) - F₃ = 0   →   F₁ cos(θ) = 70 N

• the net vertical force is

∑ F = F₁ sin(θ) + F₂ - W = 0   →   F₁ sin(θ) = 65 N

Recall that cos²(θ) + sin²(θ) = 1 for any θ, so we have

(F₁ cos(θ))² + (F₁ sin(θ))² = (70 N)² + (65 N)²

F₁² = 9125 N²

F₁ = √(9125 N²) ≈ 95.5 N

Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.

Explanation:

Answer:

Hello! your answer is C. I did this. got 100%. Have a nice day!

Explanation:

Answer:

D Predicting the volume of a gas by its Temp and preasure

Explanation:

1: not C, took the Plato test and it was wrong

C DOES seem like the answer, but determining if an element is a metal or non-metal deals with the molecular structure of said element as well as the different components meaning its more of a chemistry based task

2: the answer choice D refers to the measurement of volume and temp, these are tied to physical traits and therefore, is a task based on the understanding of physics

*SIDENOTE* a good way to tell in this case is process of elimination, we know that option A involves a more chemical style task, referring to the measurement of the acidity of said substance, same goes for option C for it deals with the molecular structure of a solution

Answer: Practice Makes Perfect

Explanation:

First, you would want to exercise:

Warmups:

Stretch:

Do these every day:

Then:

Do these in a month, and you will improve a lot in basketball.

Hope This Helps

The adiabatic process refers to a thermodynamic process in which there is no heat transfer involved between the system and the surroundings. During an adiabatic process, the change in the internal energy of the system is achieved by the transfer of energy from or to the system, which results in a change in temperature.

Argon gas is initially at a pressure of 100 kPa and a temperature of 300 K and expands adiabatically from 0.01 m3 to 0.027 m3 while doing work on a piston. The work done by the gas on the piston during the adiabatic expansion can be calculated using the formula for the work done by the gas: W = (γ / (γ - 1)) * p * (V2 - V1)where,γ = Cp / Cv is the ratio of specific heats of the gas.

Cp = Specific heat at constant pressure, Cv = Specific heat at constant volume, p = Initial pressure of the gasV1 = Initial volume of the gasV2 = Final volume of the gas.

Initial pressure, p1 = 100 kPa, Initial temperature, T1 = 300 K, Initial volume, V1 = 0.01 m3, Final volume, V2 = 0.027 m3. The specific heat at constant pressure and constant volume of argon gas is constant. The value of γ can be calculated as follows:γ = Cp / Cv = 1.67 / 1.40 = 1.193Therefore,γ / (γ - 1) = 3.77.

Work done by the gas can be calculated as W = 3.77 * 100 kPa * (0.027 m3 - 0.01 m3)W = 95.44 kJHence, the work done by the argon gas during the adiabatic expansion is 95.44 kJ.

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The resistance is 15 ohms.

Also, it's dissipating 960 watts whenever it's turned on. So it's almost as hot as a toaster, and Minh no longer has hands.

Since a rotating comet is an isolated system, all of its mechanical energy (motion + potential) and angular momentum are conserved (constant).

Angular momentum is the quantity rotation of a body which is the product of its moment.

The angular momentum is given by,

L = mvr

where v= velocity of comet ,

r= distance of comet from sun ,

m= mass of comet,  

At position 1, r is smaller therefore v (speed) increases to keep the angular momentum constant, similarly at position r be comes large do the  speed v decreases again to keep the angular  momentum to the constant , therefore at position 1 speed of the and it  is greater than at 2. As speed is larger at 1 , therefore kinetic energy ( K=1/2mv² ) will also be greater at the  position 1 compared of   position 2 .

Now mechanical energy is the  same at both positions of  due to energy conservation law .

As mechanical energy is equal =KE+GPE , since it is  kinetic energy is greater at the  position 1 therefore GPE will be greater at position 2 .

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To minimize the side loads placed on the landing gear during touchdown, the pilot should keep the longitudinal axis of the aircraft parallel to the direction of its motion. This means that the aircraft should be aligned with the runway, allowing for a smooth and controlled touchdown.

When the aircraft is not aligned with the runway, side loads can be placed on the landing gear, which can cause damage to the gear or even lead to a runway excursion. Keeping the aircraft aligned with the runway also ensures that the main wheels make contact with the ground simultaneously, reducing the risk of a nose-wheel touchdown,

which can also cause damage to the landing gear. Therefore, it is essential for pilots to maintain proper alignment with the runway during touchdown to ensure safe and efficient landings.

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The pit, from the initial dropping point, will hit the ground after traveling a horizontal distance of approximately 18.4 meters.

To find the time it takes for the pit to hit the ground, we use the equation that relates the initial vertical velocity, acceleration due to gravity, and displacement. h = (1/2) * g * t^2. Where h is the initial height (1.0 m) and g is the acceleration due to gravity (approximately 9.8 m/s^2). Solving for t, we find: t = sqrt((2 * h) / g). Next, we calculate the horizontal distance using the horizontal velocity and the time. distance = horizontal velocity * time. By substituting the given horizontal velocity of 18 m/s, we get the horizontal distance traveled by the cherry pit from its initial dropping point.

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The force is 3.84 N, and it is attracting if the currents are flowing in the same direction, while it is repulsive if they are going in the opposite direction ( force is same).

The magnetic force, which is defined as the product between the currents multiplied by the length where they are transferred and inversely proportionate to the distance that separates them, is used to solve this problem by taking into account the costs listed below. We'll just swap out the values to get the required value.

F = μoI1I2l / 2πd

Here,

F = force

μo= Free space permeability

I = current in every state

l =  length

d = Distant from one another

F = 4π×\(10^{-7}\)×130×130×250 / 2π×0.22

The force is therefore 3.84 N, and it is attracting if the currents are flowing in the same direction, while it is repulsive if they are going in the opposite direction ( force is same).

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The negative plate is the one facing us because the electric field between the plates is zero, which can only happen if the two plates have the same magnitude and opposite sign of charge density.

Charge density is the amount of electric charge per unit area or per unit volume of a material or object. It is usually denoted by the symbol ρ and is measured in units of coulombs per square meter (C/m²) or coulombs per cubic meter (C/m³).

In the case of a charged plate, the charge density is the total charge on the plate divided by its surface area. For example, if a plate has a charge of 60 µC and an area of 2 m², then the charge density is:

Charge density = 60 µC / 2 m² = 30 µC/m²

Charge density is an important concept in electrostatics, as it is used to describe the distribution of electric charge over a surface or within a volume. It is also used in the calculation of electric fields and forces in electrostatics, as the electric field depends on the charge density of the objects producing the field.

Two large, charged plates with charge density ±30µC/m² facing each other with a separation of 5.0 mm.

One of the plates has a negative charge density.

We want to find out which plate is negative

1. Calculate the total charge on one of the plates using the charge density and the area of the plate:

Q = ±30 µC/m² * A

Here, A is the area of one of the plates.

2. Calculate the electric field due to each plate using Coulomb's law:

E = (1/4πε₀) * (Q / r²)

Here, r is the distance between the plates, which is 5.0 mm or 0.005 m.

ε₀ is the permittivity of free space, which is a constant and has a value of 8.85 x 10⁻¹² F/m.

Since there are two plates, calculate the electric field due to each plate and then take the difference between them to get the net electric field between the plates.

3. Substitute the values and calculate the electric field due to each plate:

E1 = (1/4πε₀) * (Q / r²)

E2 = (1/4πε₀) * (Q / r²)

Here, E1 is the electric field due to one plate, and E2 is the electric field due to the other plate. Since the plates have the same magnitude of charge density, their charges will have the same magnitude too, so we can drop the absolute value sign in Coulomb's law.

4. Subtract the electric field due to one plate from the electric field due to the other plate to get the net electric field:

E = E1 - E2

E = 0

Since, the net electric field is zero, this means that the electric field due to one plate is equal in magnitude and opposite in direction to the electric field due to the other plate. Therefore, the plates must have the same magnitude of charge and opposite signs of charge density.

5. Since, one of the plates has a negative charge density is known, this means that the negative plate is the one facing us. Therefore, the negative plate is the one that we were asked to identify.

Therefore, the negative plate is the one facing us.

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Answer:east

Explanation:Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.

Answer:

it rises east and moves west through out the day and sets west

When two identical conducting spheres, one initially charged with Q and the other uncharged, are brought into contact, the final charge on each sphere will be Q/2.

When two identical conducting spheres are brought into contact, they will share their charge until they reach an equilibrium state. In this case, one sphere has an initial charge Q, while the other is initially uncharged.

When the spheres touch, the charges redistribute themselves in order to minimize the overall electrostatic potential energy. Since the spheres are identical, they will share the charge equally.

Thus, after the spheres come into contact, the total charge Q will be divided equally between the two spheres. Therefore, each sphere will end up with a charge of Q/2.

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Option A. The absolute brightness of a star depends on its size and temperature

The absolute brightness of a star is the amount of light it emits at a standard distance from Earth, regardless of how far away it actually is.

The size and temperature of a star are the primary factors that determine its absolute brightness. The size of the star affects the amount of light it emits, with larger stars emitting more light. The temperature of a star affects the color of the light it emits, with hotter stars emitting bluer light and cooler stars emitting redder light. Both of these factors play a significant role in determining a star's absolute brightness.

Distance and color can also affect a star's brightness, but in different ways. The distance of a star affects its apparent brightness as seen from Earth, but not its absolute brightness. The color of a star can provide information about its temperature and composition, but does not directly determine its absolute brightness.

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Answer:

stress tension tensile strength

Explanation:

The maximum stress which a material can withstand when it is pulled apart is its: stress tension tensile strength.

Given parameters:

Mass of load = 20kg

Height of man = 1.4m

Unknown:

Work done by man = ?

Work done is the force applied to move a body in a particular direction.

Often times, it is mathematically expressed as;

           Work done  = Force x distance

In this problem, we use the formula of potential energy to find the work done;

     Work done  = Potential energy  = mgh

where m is the mass of the load

            g is the acceleration due to gravity  = 9.8m/s²

            h is the height of the body

Now, input the parameters, and solve for work done;

        Work done = 20 x 9.8 x 1.4  = 274.4J

The work done by man is  274.4J