a 0.1 kg arrow is shot at 120 m/s, a 4 kg cannonball is fired at 50 m/s, and a 1.2 kg model rocket launches with a velocity of 75 m/s. determine which has the greatest momentum.

The moon’s orbit is closer to Earth is the event which occurs during high tide.

This occurs once in a month and is the phenomenon in which the moon is

closest to the Earth. This brings about an increase in the tide levels of the

water bodies.

This is the reason why the option B is the most appropriate option as the

moon’s orbit being closer to Earth also signifies a close proximity between

the moon and the earth

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Answer: The answer is: b) The moon’s orbit is closer to Earth.

Explanation: I have my ways :>

Have a great day!

-Sunny

Answer:

thx sa points

Explanation:

Answer:

D,E,F

Explanation:

Explanation:

For example, a uniform electric field E is produced by placing a potential difference (or voltage) ΔV across two parallel metal plates, labeled A and B. ... The relationship between ΔV and E is revealed by calculating the work done by the force in moving a charge from point A to point B.

A roller coaster starts from rest at its highest point and then descends on it ( frictionless) track. Its speed is 30 m/s when it reaches ground level. We have to find its speed when its height was half of its starting point.

To solve this problem, we can use the conservation of energy principle.

At the highest point, the roller coaster has only potential energy, which is equal to its initial potential energy when it is at half of its starting point, it will have lost some potential energy and gained an equal amount of kinetic energy. Since there is no friction, the total mechanical energy of the roller coaster is conserved. Therefore, we can set the initial potential energy equal to the final kinetic energy and solve for the final velocity.

Initial potential energy = Final kinetic energy
mgh = \(\frac{1}{2} mv^{2}\)

where m is the mass of the roller coaster, g is the acceleration due to gravity, h is the initial height of the roller coaster, and v is the final velocity.

We can simplify this equation by canceling out the mass and rearranging:

gh = \(\frac{1}{2} v^{2}\)

When the roller coaster is at half of its starting point, its initial height (h) is divided by 2. Therefore, we can plug in the given values and solve for the final velocity:

g(h/2) = \(\frac{1}{2} v^{2}\)
(9.8 m/s^2)(h/2) = \(\frac{1}{2} v^{2}\)
(9.8 m/s^2)(50 m/2) = \(\frac{1}{2} v^{2}\)
v = 21 m/s

Therefore, the answer is (C) 21 m/s.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 80 × 4

We have the final answer as

Hope this helps you

Answer:

0.645 kg

Explanation:

because 1 kg = 1000 g

so 1 g = 1/1000 kg = 0.001 kg

645 g = (645 x 0.001) kg = 0.645 kg

The net force acting on the mass along the incline is equal to 16 Newton.

Given the following data:

To determine the net force acting on the mass along the incline:

First of all, we would find the acceleration of the mass by using the second equation of motion:

\(S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4\)

Acceleration, a = 8 \(m/s^2\)

For the net force, we would apply Newton's Second Law of Motion:

\(F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8\)

Net force = 16 Newton.

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1. The tension on a rope suspending a 15.0 kg box from the ceiling is 147 N, acting in the opposite direction to counterbalance the weight of the box.

2. To overcome the friction force from the road and maintain a constant velocity, an applied force of 2650 N must be exerted on the car.

1. To determine the tension on the rope when a 15.0 kg box is suspended from the ceiling, we analyze the forces at play. When the box is stationary, the net force acting on it is zero.

Let's consider the tension in the rope as T. The weight of the box can be calculated using the equation W = mg, where m represents the mass of the box, and g is the acceleration due to gravity.

Weight of the box = 15.0 kg * 9.8 m/s² = 147 N

Since the box is in equilibrium, the tension in the rope must balance the weight of the box. Therefore:

T - 147 N = 0

Solving for T:

T = 147 N

2. When a 1510 kg car experiences a 2650 N friction force from the road, we need to find the force that must be applied to the car to overcome this friction and maintain constant velocity.

The force of friction is given by the equation \(F_f_r_i_c_t_i_o_n\) = μ * N, where μ is the coefficient of friction and N is the normal force. In this case, we assume the friction force is the maximum static friction force, which is μ * N.

Since the car is experiencing a friction force of 2650 N, we have:

\(F_f_r_i_c_t_i_o_n\) = 2650 N

The normal force (N) is equal to the weight of the car (mg), where g is the acceleration due to gravity.

Weight of the car = 1510 kg * 9.8 m/s² = 14818 N

Since the car is at constant velocity, the applied force must balance the friction force:

Applied force - 2650 N = 0

Solving for the applied force:

Applied force = 2650 N

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Answer:

both

Explanation:

You'll use less water....less hot water   so water and energy are saved

The law that governs the conservation of electric charge in a closed system is known as the law of conservation of charge.

According to this law, the total amount of electric charge in a closed system remains constant and cannot be created or destroyed. As for how objects can change their charges in a closed system, it is because the distribution of electric charge can change.

For example, when two objects with different electric charges are brought into contact, electrons can flow from one object to the other until both objects have the same electric potential. This transfer of electrons results in a change in the charge of each object, but the total charge remains the same.

Another way objects can change their charges is through the process of ionization, where an atom loses or gains electrons, resulting in a change in the electric charge of the atom. Again, the total charge remains constant, as the lost or gained electrons must go somewhere.

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Explanation:

Nasa picture po ang answer

Answer:

As its speed increases.......

The kinetic energy of an object increases as its speed increases. So, option B.

The type of energy that an object possesses as a result of its motion is called kinetic energy.

The kinetic energy of an object is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity.

The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed.

When slowing down from its current pace to a condition of rest, the body expends the same amount of energy.

A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

The kinetic energy of the object,

KE = 1/mv²

where m is the mass and v is the speed of the object.

Since, the mass is a constant, the increase in speed can increase the kinetic energy of the object.

Hence,

The kinetic energy of an object increases as its speed increases.

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Factors influencing incoming solar radiation include solar angle, atmospheric conditions, and surface characteristics.

Several factors influence the amount of solar radiation reaching Earth's surface. The solar angle, determined by the Earth's tilt and position in its orbit, affects the intensity of radiation. Atmospheric conditions such as cloud cover, aerosols, and pollution can scatter or absorb radiation. Surface characteristics, such as albedo (reflectivity) and vegetation, also influence the amount of incoming radiation.

The composition of incoming solar radiation consists primarily of visible light, ultraviolet (UV) radiation, and infrared (IR) radiation. Visible light is the range of wavelengths perceived by human eyes. UV radiation has shorter wavelengths and can be harmful to living organisms. IR radiation has longer wavelengths and carries heat energy.

Once solar radiation enters the atmosphere, several processes occur. Approximately 30% of incoming radiation is reflected back into space by clouds, atmospheric particles, and the Earth's surface. About 20% is absorbed by the atmosphere, including gases like ozone and water vapor. The remaining 50% reaches the Earth's surface, where it is absorbed by land, water, and vegetation, contributing to various physical and biological processes such as heating the Earth's surface, driving weather patterns, and supporting photosynthesis.

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To estimate the energy expenditure during horizontal treadmill walking, we can use the Metabolic Equivalent of Task (MET) method.

MET is a unit that represents the metabolic rate, where 1 MET is equivalent to the energy expenditure at rest. The formula to estimate energy expenditure in METs is:

Energy Expenditure (METs) = Treadmill Speed (m/min) / 3.5

To convert the energy expenditure to ml ⋅ kg^(-1) ⋅ min^(-1), we multiply the MET value by 3.5.

Let's calculate the estimated energy expenditure for the given examples:

a) Treadmill speed = 50 m ⋅ min^(-1), Subject's weight = 62 kg

Energy Expenditure (METs) = 50 / 3.5 ≈ 14.29 METs

Estimated Energy Expenditure = 14.29 METs * 3.5 ml ⋅ kg^(-1) ⋅ min^(-1) ≈ 50 ml ⋅ kg^(-1) ⋅ min^(-1)

b) Treadmill speed = 80 m ⋅ min^(-1), Subject's weight = 75 kg

Energy Expenditure (METs) = 80 / 3.5 ≈ 22.86 METs

Estimated Energy Expenditure = 22.86 METs * 3.5 ml ⋅ kg^(-1) ⋅ min^(-1) ≈ 80 ml ⋅ kg^(-1) ⋅ min^(-1)

Therefore, the estimated energy expenditure during horizontal treadmill walking is approximately 50 ml ⋅ kg^(-1) ⋅ min^(-1) for a treadmill speed of 50 m ⋅ min^(-1) and a subject's weight of 62 kg, and approximately 80 ml ⋅ kg^(-1) ⋅ min^(-1) for a treadmill speed of 80 m ⋅ min^(-1) and a subject's weight of 75 kg.

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The total revenue, on the other hand, rises as a result of the higher price and constant quantity demanded for an inelastic good when the price is raised and the demand remains the same.

Inelastic demand is when consumer preferences do not change as much as changes in the price of a good. When the price increases by 20% while the decrease in demand is only 1%, the demand is said to be inelastic. Elastic items are usually required when appropriate substitutes are not available. The items with the most prevalent inelastic demand are utilities, prescription drugs, and tobacco products. Businesses that sell these items may be more tolerant of price changes because demand for them never ceases, regardless of price changes. The amount of a good that is purchased has no effect on price changes when the price elasticity of demand for that good is completely inelastic; rather, higher prices will always lead to higher overall income. whenever the cost of a thing or service changes, the demand for such items remains mostly stable.

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The temperature of 1.00 L of gasoline rises from 30°C to 50°C, the volume of the gasoline will increase by (50 - 30) x 950 x 10-6 cm³ = 12 cm³.

Temperature is a measure of the average kinetic energy of the particles in a system. It is measured in degrees Celsius (°C), Fahrenheit (°F) or Kelvin (K) and is used to describe the intensity of heat in an object or environment. Temperature is an important factor in determining the state of a system and the properties of its components.

The volume coefficient of thermal expansion for gasoline is 950 x 10-6 K-1, which means that the volume of 1.00 L of gasoline will increase by 950 x 10-6 cm³ for every 1 degree Celsius increase in temperature.

Therefore, when the temperature of 1.00 L of gasoline rises from 30°C to 50°C, the volume of the gasoline will increase by (50 - 30) x 950 x 10-6 cm3 = 12 cm³.

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The principle involved is the conservation of momentum, where the boat moves in the opposite direction to maintain total momentum zero.

The physics principle involved in the movement of the boat as the man jumps onto the jetty is the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant if no external forces act on it.

In this scenario, the boat and the man can be considered as an isolated system since there are no external forces acting on them. Initially, when the man is standing on the boat, the system is at rest, and the total momentum is zero.

When the man jumps off the boat and onto the jetty, he exerts a force on the boat in one direction. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. As the man pushes off the boat, the boat experiences an equal and opposite force that propels it in the opposite direction.

Due to the conservation of momentum, the momentum gained by the boat in one direction is equal to the momentum lost by the man in the opposite direction. As a result, the boat moves away from the jetty, exhibiting a backward motion.

This principle can be mathematically expressed as:

Initial momentum of the system = Final momentum of the system

Since the initial momentum is zero, the final momentum of the system (including the man and the boat) must also be zero. The momentum gained by the boat ensures that the total momentum of the system remains conserved.

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The minimum power must the motor deliver to lift the fully loaded elevator at a constant speed 2. 10 m/s is 19.1 kW.

Speed is the rate an object or person is moving in a given direction. It is measured as distance (meters, feet, miles, etc.) per unit of time (seconds, minutes, hours, etc.). It is an important and fundamental characteristic of matter, as it determines the kinetic energy of an object. Speed is also a vector quantity, as it describes both magnitude and direction. Speed has general and special relativity implications as well, as relative motion affects the propagation of light and space-time.

Step 1: Calculate the net force on the elevator:

Fnet = Ffr – mg

Fnet = 4.0 x 103 N – (2.5 x 103 kg)(9.81 m/s²)

Fnet = 9.10 x 103 N

Step 2: Calculate the power required to lift the elevator:

P = Fnet x v

P = (9.10 x 103 N) (2.10 m/s)

P = 19.1 kW

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Arctic winds are stronger when the Arctic Oscillation (AO) is in its negative phase. The AO is a large-scale atmospheric circulation pattern that affects weather patterns in the Northern Hemisphere, particularly in the Arctic region. The correct option is b) negative

The AO can be positive, negative, or neutral, depending on the pressure patterns in the Arctic and mid-latitude regions.
When the AO is in its negative phase, there is a stronger pressure difference between the Arctic and mid-latitudes, which leads to stronger winds. This negative phase is characterized by a weakening of the polar vortex, a large-scale low-pressure system over the Arctic.

As a result, cold air from the Arctic is more likely to be displaced southward, bringing colder temperatures and stronger winds to the mid-latitudes. In contrast, when the AO is positive or in a neutral phase, the pressure difference between the Arctic and mid-latitudes is weaker, resulting in weaker winds.

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a) The ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them is used to express capacitance.

b) The area of the plates, the spacing between them, and the type of insulating material or dielectric between them are the three variables that have an impact on a parallel-plate capacitor's capacitance.

c) The area of each plate, the dielectric material separating the plates, and the distance between the plates all affect the capacitance of a parallel plate capacitor.

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Answer: I think the answer is d

Explanation: sry if wrong

A constant force of 1.25N

Explanation:

This is a kinematics problem.

First find acceleration,

then use F = ma to find force.

Given:

mass = .5kg

delta x = 20m

t = 4s

a = ?

Friction = 0

From the kinematics equations:

delta x = Vi + (1/2)at^2

Plug in terms that are given:

20m = 0 + (1/2)a(4^2)

(2*20m)/(16s^2) = a

40m/(16s^2)= 2.5m/s^2

Now use F = ma to find force exerted on object.

F = (0.5kg)*(2.5m/s^2)

F = 1.25N

The ratio u₁/u₂ is equal to (m₁/m₂)×(r₁/r₂). The potential energy of a planet-satellite system is given by the formula U = -G(m₁m₂)/r, where G is the gravitational constant, m₁ and m₂ are the masses of the planet and satellite, and r is the distance between their centers.

In circular orbits, the kinetic  of the satellite is equal to half of its potential energy, so the total energy of the system is negative and equal in magnitude to the potential energy.

Using this formula, we can write u₁ = -G(mm₁)/r₁ and u₂ = -G(m×m₂)/r₂.

Dividing u₁ by u₂, we get:

u₁/u₂ = (-G(m m₁)/r₁) / (-G(m m₂)/r₂)
u₁/u₂ = (m₁ r₂) / (m₂ r₁)
u₁/u₂ = (m₁/m₂) (r₂/r₁)

Since the satellites are in circular orbits, their speeds are given by the formula v = √(Gm/r),

where v is the speed, G is the gravitational constant, m is the mass of the planet, and r is the radius of the orbit.

Therefore, we can write r₂/r₁ = (v₁/v₂)².

Substituting this into the previous equation, we get:

u₁/u₂ = (m₁/m₂) ((v₁/v₂)²)

The ratio u₁/u₂ is equal to (m₁/m₂) (v₁/v₂)², where m₁ and m₂ are the masses of the two satellites, v₁ and v₂ are their speeds, and r₁ and r₂ are their orbital radii.

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Newton’s second law of motion states that the force F acting on an object of mass m produces an acceleration a in the object, and is given by, F = ma. The law s invariant under Galilean transformation.

The Galilean transformation is a set of equations that describe the relationship between two reference frames that are in relative motion with constant velocity. It has no effect on the form of Newton’s second law because it only involves a change of coordinates and time, which do not affect the physical laws.

To see this, consider two reference frames S and S', where S' moves with constant velocity v with respect to S. Let an object of mass m be at rest in S, and let F be the net force acting on it in S. According to Newton’s second law in S, we have:

F = ma

Now, let us apply the Galilean transformation to the equation. The position of the object in S' is given by:

x' = x - vt

where x is the position of the object in S, and t is time. Taking the derivative of x' with respect to t, we get:

v' = dx'/dt

= dx/dt - v

= v - v

= 0

This means that the velocity of the object is the same in both reference frames. Similarly, the acceleration is also the same in both reference frames, since it is the derivative of velocity,

a' = dv'/dt = da/dt = a

Therefore, we can write Newton’s second law in S' as,

F' = ma'

where F' is the net force acting on the object in S'. Substituting a' = a, we get:

F' = ma

which is the same form as in S. Thus, we see that the form of Newton’s second law is invariant under the Galilean transformation.

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Answer:

radiation!

Explanation:

Answer: Radiation is the thermal transmission of heat energy across space.

Explanation:

Answer:

0.84m

Explanation:

0.51+0.43=0.93

πr can be 22/7 or 3.14

radius is 2x2= 4

3.14 divide0.93divide 4

=0.84m/s

Answer:

0.605 m (approx.)

Explanation:

We know, given the radius and the circular velocity we can yield the centripetal acceleration using this equation,

\(a = \frac{v^2}{r}\)

From this equation, we can solve for \($r$\) like this,

\(r = \frac{v^2}{a}\\r = \frac{0.51^2}{0.43} m \\ = 0.605 m\)

Answer:

An electrically polarized object can have zero net charge, while a charged object cannot have zero net charge.

I hope this helps :D

Answer:

we have to apply force to move something things wants to save their position and if we want to change it

we have too apply force

Answer:

we have to apply

them to have a answer