Answer:
is this a mudder question
a torroidal solenoid has inner and outer radii of 6.06 cm and 16.6 cm and carries a current of 20.3 a. calculate the number of wire turns required to produce a 13.5 mt magnetic field inside the coil a distance of 10.5 cm from its center
We would need approximately 45,420 wire turns to produce a 13.5 mT magnetic field inside the toroidal solenoid at a distance of 10.5 cm from its center.
The magnetic field inside a toroidal solenoid is given by:
B = (μ0 * N * I) / (2 * π * r)
where B is the magnetic field, μ0 is the permeability of free space, N is the number of wire turns, I is the current, and r is the radial distance from the center of the toroid. In this case, we want to find N, so we can rearrange the equation to solve for it:
N = (2 * π * r * B) / (μ0 * I)
Plugging in the given values, we get:
N = (2 * π * 0.105 m * 13.5 T) / (4 * π * 10^-7 T·m/A * 20.3 A)
N ≈ 45,420 turns
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The area of a room that is 10 feet wide and 12 feet long is
13.3 square feet
14 square yards
120 square feet
12 squa2 yards
estimate how much energy per year is needed for 1 gigawatt (in j/yr).
An estimate of how much energy per year is needed for 1 gigawatt is approximately 31,536,000,000,000,000 joules (J) per year.
To estimate how much energy per year is needed for 1 gigawatt, we need to consider the unit of measurement for energy, which is joules (J).
A gigawatt is equivalent to 1 billion watts or 1,000,000,000 watts. To calculate the energy per year, we need to multiply this value by the number of seconds in a year.
There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 365 days in a year.
So, 1 gigawatt x 1 year = 1,000,000,000 watts x 60 seconds/min x 60 minutes/hour x 24 hours/day x 365 days/year
= 31,536,000,000,000,000 joules (J) per year
Therefore, approximately 31,536,000,000,000,000 joules (J) per year is an estimate of energy needed for 1 gigawatt.
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How is fat diet different from a low calorie diet
A trapezoidal channel is to be designed and constructed in a sandy loam with a longitudinal slope of 1 in 5000 to carry a discharge of 2.3 m3/s. Calculate suitable dimensions for the depth and bed width assuming Manning's n is 0.022 and the side slope is 1 in 2.
To calculate suitable dimensions for the depth and bed width of a trapezoidal channel, we can use the Manning's equation and the channel geometry relationships.
Given:
Discharge (Q) = 2.3 m^3/s
Manning's roughness coefficient (n) = 0.022
Slope (S) = 1 in 5000 = 0.0002 (dimensionless)
Side slope (Z) = 1 in 2 = 0.5 (dimensionless)
Let's denote:
y = Depth of flow (m)
B = Bed width (m)
Cross-sectional Area (A):
A = (y + Z*y) * B
A = (1 + 0.5) * B
A = 1.5B
Wetted Perimeter (P):
P = y + 2 * (y / sqrt(1 + Z^2))
P = y + 2 * (y / sqrt(1 + 0.5^2))
P = y + 2 * (y / sqrt(1.25))
P = y + 2 * (y / 1.118)
Hydraulic Radius (R):
R = A / P
R = (1.5B) / (y + 2 * (y / 1.118))
R = (1.5B) / ((1 + 2 / 1.118) * y)
R = (1.5B) / (1.795 * y)
R ≈ 0.835B / y
Manning's Equation:
Q = (1 / n) * A * R^(2/3) * S^(1/2)
Substituting the values:
2.3 = (1 / 0.022) * (1.5B) * (0.835B / y)^(2/3) * (0.0002)^(1/2)
Simplifying the equation:
y^(2/3) = (0.022 * 2.3) / (1.5 * 0.835 * B^(5/3) * 0.0002^(1/2))
Taking the cube of both sides:
y^2 = (0.022 * 2.3)^3 / (1.5 * 0.835 * B^(5/3) * 0.0002^(1/2))^2
Simplifying further:
y^2 ≈ 0.2048 / (B^(5/3))
Now, we need to make an assumption for the bed width (B) and solve for the depth (y). Let's assume B = 1 meter.
Substituting the value of B:
y^2 ≈ 0.2048 / (1^(5/3))
y^2 ≈ 0.2048
Taking the square root of both sides:
y ≈ sqrt(0.2048)
y ≈ 0.453 m
Therefore, with a bed width of 1 meter, a suitable depth for the trapezoidal channel is approximately 0.453 meters.
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What mass of lead has the same volume as 1600kg of petrol?
Answer:
The volume of 1600 kg of petrol is 1600/800 = 2 m^3. As the density of lead is 11400 kg/m^3, the mass of 2 m^3 is 11400*2 = 22800 kg. The mass of lead with the same volume as 1600 kg of petrol is 22800 kg.
]
If you use the same force to push a truck and push a car which one
will have more acceleration and why?
O The car because it has less mass
O The truck because it has more mass
O The truck because it has less mass
The car because it has more mass
Answer:
I think is the The truck because it has more mass
hey can yall help me out in dis
Answer:
Scientific method
Explanation:
Why are muscles an essential part of the circulatory system?
The circulatory system carries oxygen, nutrients, and hormones to cells they remove waste products, like carbon dioxide. These roadways travel in one direction only, to keep things going where they should. :)
Which material is a good conductor of electricity?.
COPPER
Because, copper
is just one of the more popular materials that is used for conductors
Dawn is trying to find out how much weight she can push across the room. She is really trying to find her __________. A. flexibility B. muscular endurance C. cardiovascular fitness D. muscular strength Please select the best answer from the choices provided. A B C D
Answer:
D. muscular strength
Explanation:
Lifting any weight requires force to lift it. This force is the result of the muscular strength of the body. It is the muscular strength that determines the weight that a body can lift without any exhaustion. Muscular strength depends on the size of the muscular fibers and the nerves' ability. They help in activating the strength of the muscle. Lifting the objects and the ability to lift it are the outcome of the strength muscles have.
In the given situation, Dawn is trying to find her muscular strength.
Answer:
d
Explanation:
d
An analyst wants to compare the cash flows of two United States companies, one that reports cash flow using the direct method and one that reports it using the indirect method. The analyst is most likely to:
The analyst is most likely to convert the cash flow statement from the indirect method to the direct method for accurate comparison.
When comparing the cash flows of two companies, it is essential to ensure that the cash flow statements are prepared using a consistent method. The direct method provides a more detailed and straightforward presentation of cash inflows and outflows, while the indirect method adjusts net income for non-cash items and changes in working capital.
To make a meaningful and accurate comparison, the analyst would likely convert the cash flow statement reported using the indirect method to the direct method. This conversion involves adjusting the indirect method statement by reconciling each line item to its cash inflow or outflow counterpart.
By converting both cash flow statements to the same method, the analyst can directly compare the cash flows of the two companies and assess their respective cash generation, operating activities, investing activities, and financing activities on a consistent basis.
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Which ecosystem in Southeast Asia has over 6,000 species of plants and 450 species of birds? A. Tropical savanna B. Tropical rainforest C. Grassland D. Deciduous forest Please select the best answer from the choices provided A B C D.
The tropical rainforests of Southeast Asia have over 6,000 species of plants and 450 species of birds.
What are tropical rain forests?
These are the forests that get the most of the year. They are the most diverse forest on the earth such as the amazon.
Tropical savana:These are the forests with very large grasses and occasional trees. They are found in Brazil and India.
Deciduous forests:These are the temperate forests in which trees shed all their leaves in one seson.
Therefore, the tropical rainforests of Southeast Asia have over 6,000 species of plants and 450 species of birds.
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Answer:
Its b. the tropical rainforest
Explanation:
A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is her acceleration? Is the acceleration higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds? How do you know?
Answer:
Acceleration of one cyclist=\(2.67m/s^2\)
Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.
Explanation:
We are given that
Initial velocity of one cyclist, u=0 m/s
Final velocity of one cyclist, v=8m/s
Time, t=3 s
Initial velocity of another cyclist, u'=0
Final velocity of another cyclist, v'=30m/s
Time, t'=8 s
We know that
Acceleration, \(a=\frac{v-u}{t}\)
Using the formula
\(a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2\)
Acceleration of one cyclist=\(2.67m/s^2\)
Acceleration of another cyclist, a'=\(\frac{30-0}{8}m/s^2\)
Acceleration of another cyclist, a'=\(3.75m/s^2\)
Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.
A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
This signal is reflected on the body of a submarine after a delay of 0.3 seconds.
Given: Speed of sound in water is 1500 m/s.
Calculate the period of this wave.
Answer:
0.000025s
Explanation:
Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s
No Attempt 50% Part (a) Write an expression for the largest distance he can stand from the center of the axis of rotation but not slide. Your expression will be in terms of ω
The expression for the largest distance he can stand from the center of the axis of rotation but not slide in terms of angular speed is found to be 6.07/w² m.
The man stands on the merry-go-round. The wheel rotates at an angular speed of 1.38Rad/s.
Now, the maximum distance that he can walk on the merry-go-round without sliding on the wheel will be at the point where the centrifugal and the frictional forces are equal,
uMg = Mw²/r, where, M is the Mass of the man, r is the distance that he w=can walk from the center of the wheel without sliding, w is the angular speed and g is gravity, u is the coefficient of friction.
r = ug/w²
Putting values of u and g.
r = 6.07/w²
So, the expression that we have derived is 6.07/w² m.
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Complete question - Problem 5: A Man Stands On A Merry-Go-Round That Is Rotating With An Angular Speed Of A = 1.38 Rad/S. The Coefficient of friction between his shoes and the merry-go-round is u = 0.62.
Part (a) Write an expression for the largest distance he can stand from the center of the axis of rotation but not slide. Your expression will be in terms of ω
a transverse wave of amplitude 3.0 cm , frequency 5.0 hz , and speed 3.0 m/s travels on an infinitely long slinky. part a how far apart are the two nearest points on the slinky that at one particular time both have the maximum magnitudes of displacements from their equilibrium positions? express your answer with the appropriate units.
Part A: 6.0 cm apart are the two nearest points on the slinky that at one particular time both have the maximum magnitudes of displacements from their equilibrium positions.
Part B: The period of the wave is 0.2 seconds.
A transverse wave of amplitude 3.0 cm, frequency 5.0 Hz, and speed 3.0 m/s travels on an infinitely long slinky. This question is a two-part question.
Let us solve each part of the question.
Part A:
We know that transverse waves move up and down perpendicular to the direction of the wave. It means that the maximum displacement of a particle from its equilibrium position is equal to the amplitude of the wave.
In one period (T), the wave completes one full cycle. The number of cycles completed in one second is called the frequency (f) of the wave.
The product of wavelength (λ) and frequency (f) of the wave is equal to its velocity (v).
The formula for a wave is given as follows:v = λf
Here, v is the velocity, λ is the wavelength and f is the frequency.
From the formula, we can calculate the wavelength of the wave. We are given the amplitude (A) and frequency (f) of the wave. We are to find the distance between two nearest points at maximum displacement.
To solve the problem, we use the formula for the wavelength of a wave.
λ = v/f
Substituting the values given:
λ = (3.0 m/s)/(5.0 Hz)
λ = 0.6 m
We know that for a transverse wave, maximum displacement is equal to the amplitude.
Therefore, the distance between two nearest points at maximum displacement is equal to two times the amplitude.
Substituting the value:
Distance between two nearest points at maximum displacement = 2 x amplitude= 2 x 3.0 cm = 6.0 cm
Part B:
The period of the wave is the time it takes for a complete cycle. The formula for the period is given as follows:
T = 1/f
Substituting the values:
T = 1/5.0 Hz
T = 0.2 seconds
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Submit Activity Log Week 2
Submit your completed Activity Log for this week here.
Please complete each area and make sure to include dates on your activity log.
Each activity log should include one week of physical activities.
A full week includes Monday - Sunday. Include at least 3 days of the same week. Full credit will only be given if all sections are completed.
Be sure to complete the heart rate section.
Please complete each area to receive full credit
Below is my activity log for for a week starting from Monday, February 20th, 2023 to Sunday, February 26th, 2023:
Monday, February 20th:
7:00am: 30-minute yoga session at home
12:00pm: 1-hour strength training at the gym
6:00pm: 30-minute jog around the neighborhood
What is the physical activities?Tuesday, February 21st:
8:00am: 45-minute indoor cycling class at the gym2:00pm: 30-minute walk during lunch break6:00pm: 45-minute hot yoga session at the studioWednesday, February 22nd:
7:00am: 30-minute HIIT workout at home1:00pm: 1-hour basketball game with friends at the park5:00pm: 30-minute jog around the parkThursday, February 23rd:
8:00am: 45-minute indoor rowing class at the gym2:00pm: 30-minute walk during lunch break6:00pm: 45-minute Pilates session at the studioFriday, February 24th:
7:00am: 30-minute strength training at home1:00pm: 1-hour Zumba class at the gym5:00pm: 30-minute jog around the neighborhoodSaturday, February 25th:
9:00am: 1-hour hike in the nearby nature reserve2:00pm: 30-minute swim at the community pool6:00pm: 45-minute kickboxing class at the gymSunday, February 26th:
10:00am: 1-hour yoga session at the park3:00pm: 30-minute walk around the lake7:00pm: 30-minute jog around the neighborhoodTherefore, this week consisted of a mix of cardio, strength training, and flexibility exercises. The activities varied between indoor and outdoor, as well as group and individual workouts. The inclusion of different activities helps to keep things interesting and maintain motivation.
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Kiko writes a roport to compare and contrast the code of plants and animals. Which of the following statements is accurato arvd bolony in Kiko's report?
The cell membrane of animals is much tickow than those in plants
Vaculos in plants are much larger than those in animals
Animal colls do not have chromosomos
Plant colls do not have chloroplasts
Answer:
Kiko writes a roport to compare and contrast the code of plants and animals. Which of the following statements is accurato arvd bolony in Kiko's report?
The cell membrane of animals is much tickow than those in plants
Vaculos in plants are much larger than those in animals
Animal colls do not have chromosomos
Plant colls do not have chloroplasts
The Moon has a mass of 7.35 * 1022 kg, and a radius of 1.737 * 106 m. Based on
these values, what is the acceleration due to gravity on the surface of the Moon?
Answer:
1.63 \(ms^{-2}\)
Explanation:
The equation \(g = \frac{G*M}{R^2}\) would be used where:
g = acceleration due to gravity
G = universal gravitational constant (6.67408 × \(10^{-11}\) \(m^{3} kg^{-1} s^{-2}\))
M = mass
R = radius.
assuming the values following both 10s of the mass and radius are their exponents, which is a little confusing, the values given would simply be substituted.
Anyone can correct me if I'm wrong.
The efficiency of a machine is always equal to or greater than 1 (True False)
Answer: False.Machine efficiency is a measure of how much work is produced by a machine compared to how much energy is required to operate the machine.
The ratio of useful output work divided by the total input work is known as machine efficiency. This number is frequently expressed as a percentage (100 x work output / work input).Example:
For example, if you lift a 50-pound weight 10 feet in the air using a pulley, the work done is 500 foot-pounds. However, if it took 600 foot-pounds of energy to lift the weight, the pulley system's efficiency would be calculated as follows: 500/600 = 0.83 or 83 percent.
The efficiency of a machine is always less than one, in general. It is defined as the ratio of output energy to input energy. Because of losses due to friction and other variables, the output energy is always less than the input energy. As a result, the efficiency of a machine is always less than one.Answer: False.
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Is this physically plausible?
Answer:
stop useing my awnsers just to deleate them
Explanation:
what should the magnitude of the force f be if the mass m is to have an upward acceleration of magnitude a?
Product of mass and acceleration is the magnitude of force.
A push or pull of an object is called force. Product of mass and acceleration is the magnitude of force. The S.I. unit of force is m/s². Unit can be represented by newton symbol is N.
F = m × a
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If the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet, then the mechanical advantage would be
Answer: 2
Explanation:
From the question, we are informed that the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet.
Based on the information given, the mechanical advantage would be calculated as:
= Force Arm / Resistance Arm
= 4 feet / 2 feet
= 2
Starting from rest, a boat increases its speed to 4.12 m/s with constant acceleration. (a)
What is the boat's overage speed? (b) If it takes the boat 4.77s to reach this speed, how far
has it travelled?
Answer:
initial velocity = 0 m/s
final velocity = 4.92 m/s
constant acceleration so,
(a) average velocity =
(initial velocity + final velocity)/2
(b) distance = average velocity x time
substitute and calculate
Explanation:
HOOE ITS HELP ;)
The initial velocity is zero. and the acceleration is constant. Thus the average velocity of the boat is 4.12 m/s. The boat will cover a distance of 19.6 m within 4.77 s.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
If the acceleration is constant, then the magnitude of velocity is constant.
Given initial velocity = 0 since the boat was in rest.
then the average speed of the boat = 4.12 m/s
Δt = 4.77 seconds.
The distance covered within this time can be determined using the equation as follows:
s = speed × time.
s = 4.12 m/s × 4.77 s = 19.6 m
Therefore, the boat will travel up to 19.6 m within 4.77 seconds.
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plzzzz help it for civics
Answer:
A : the colonists dumped tea in Boston Harbor
Calculate the wave speed of a wave that has a frequency of 12Hz and a wavelength of 6m.
Answer:
v=fxw v= 12x6=72 I think it hooefull
The mass of the train is 450000 kg.
Calculate the maximum possible speed of the train at the end of the first 4.0km of the
journey.
The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.
Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.
The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).
The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.
Since the potential energy is converted into kinetic energy, we can equate the two expressions:
PE = KE
\(mgh = (1/2)mv^2\)
Simplifying and canceling out the mass:
\(gh = (1/2)v^2\)
Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:
\((9.8 m/s^2)(0) = (1/2)v^2\)
Simplifying further:
\(0 = (1/2)v^2\)
This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
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8. Gravity pulls a skydiver down as air
friction (drag) pushes the skydiver up. Is
this an action-reaction pair?
Answer:
Air resistance is pushing up on the parachute and force of gravity is pulling down so she slows down. This increases friction which slows free fall down. So when the skydiver reaches terminal velocity, the force of gravity is balance by air resistance. But when the forces are balance, there is no acceleration.
A spherical, concave, shaving mirror has a radius of curvature of 32.1 cm. Part A What is the magnification of a person's face when it is 12.1 cm to the left of the vertex of the mirror? Where is the image? Express your answer in centimeters.
The magnification of a person's face when positioned 12.1 cm to the left of the vertex of a spherical, concave shaving mirror with a radius of curvature of 32.1 cm is -1. The image is formed at a distance of 12.1 cm to the left of the vertex of the mirror, and it is real, inverted, and the same size as the object.
A spherical, concave, shaving mirror with a radius of curvature of 32.1 cm is considered in the following question. In Part A, we need to determine the magnification of a person's face when it is positioned 12.1 cm to the left of the vertex of the mirror and also find the location of the image. The magnification formula is expressed as: \(\frac{h_0}{h_i} = - \frac{d_o}{d_i}\). Here, h₀ represents the height of the object, hᵢ refers to the height of the image, d₀ represents the distance between the object and the mirror, and dᵢ represents the distance between the image and the mirror. The negative sign in the formula pertains to real images, with the magnification being positive for a real image and negative for a virtual image.
Given the following values:
Radius of curvature, R = -32.1 cm (negative since it is a concave mirror)
Object distance, d₀ = -12.1 cm (negative as the object is on the left side of the mirror)
Image distance, dᵢ = ?
Using the rearranged equation:
\(d_i = - \frac{d_o * h_i}{h_0}\)
Since the height of the object, h₀, is equal to the height of the image, hᵢ (as it is a person's face), we can substitute this value into the equation:
\(d_i = -d_o\)
\(d_i = - (-12.1) = 12.1 cm\)
Therefore, the image is formed at a distance of 12.1 cm to the left of the vertex of the mirror.
The magnification of the person's face is given by:
\(M = -\frac{h_i}{h_0}\)
Since the height of the object, h₀, is equal to the height of the image, hᵢ (as it is a person's face), we can substitute this value into the equation:
\(M = -\frac{h_i}{h_0} = -1\)
Thus, the magnification of a person's face is -1, indicating that the image is real, inverted, and the same size.
In conclusion, the final image distance is 12.1 cm to the left of the vertex of the mirror.
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