The direction of the magnetic force on the wire between the poles is into the page.
The magnitude and direction of the magnetic force on the wire between the poles can be calculated as follows:
F = BIL sinθWhere,F is the magnetic force on the wire between the poles.
B is the magnetic field strength. I is the current flowing through the wire.θ is the angle between the direction of the current and that of the magnetic field.
Substitute the given values in the above formula to get the magnitude of magnetic force as follows:
F = 0.845 × 9.5 × 0.0150 × sin 25°F = 0.0197 N (approx)
Therefore, the magnitude of the magnetic force on the wire between the poles is 0.0197 N (approx).
The direction of the magnetic force on the wire between the poles is given by the right-hand rule.
It can be determined as follows:
Curl the fingers of the right hand in the direction of the current flow.
The thumb points in the direction of the magnetic force. In this case, the magnetic force is directed into the page.
Therefore, the direction of the magnetic force on the wire between the poles is into the page.
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a set of related measures or activities with a particular long term aim
Answer:
program explanation
Explanation:
program explanation
The set of activities having a long-term aim should be a program.
What is the program?A program refers to a set of instructions that a computer follows in order to perform a specific task. At the time When you program a computer, you provide it a set of instructions to make it able to perform a particular task.
So here the program should be considered.
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A 55.0-kg person consumes a small order of french fries
(241.0 Cal)
and
wishes to
"work off"
the
energy by climbing a
11.0 m
stairway.
How many vertical climbs are needed to use all the
energy?
To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 17.0 times.
The energy content of the small order of french fries is given as 241.0 Cal. We can convert this value to joules since the unit of energy in the metric system is the joule (J). 1 calorie (Cal) is equal to 4.184 joules (J). To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 57 times.
Energy content of the small order of french fries:
241.0 Cal × 4.184 J/Cal = 1007.144 J
Work done to climb the stairway:
(55.0 kg) × (11.0 m) × (9.8 m/s²) = 59294 J
Number of climbs needed to use all the energy:
1007.144 J ÷ 59294 J ≈ 17.0
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two students will be working together diluting concentrated acid for their experiment. before beginning, they think about the ramp acronym and quickly assess the risk of their planned procedure. choose the best assessment for each letter.
By using the RAMP acronym, the students can examine and manage the risks connected with their diluting concentrated acid approach, resulting in a safer and more regulated experimental process.
To assess the risk of their planned procedure using the RAMP acronym, the best assessment for each letter would be as follows:
R - Recognize hazards: The students should identify and acknowledge any potential hazards associated with diluting concentrated acid.
A - Assess risks: The students should evaluate the risks associated with the procedure. This involves considering the probability and potential consequences of accidents or mishaps, such as acid splashes, improper handling, or inhalation of fumes.
M - Minimize risks: The students should take measures to minimize the identified risks. This includes implementing safety protocols and precautions.
P - Prepare for emergencies: The students should be prepared to respond to any potential emergencies or accidents that may occur during the procedure.
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When developing a model of the cycling of water between the land, the ocean, and the atmosphere, one must include the forces that propel the water. For the model, these forces would be-
Answer: gl
Explanation:
When developing a model of the cycling of water between the land, the ocean, and the atmosphere. For the model, these forces would be gravity and sunlight( evaporation).
Sunlight causes evaporation and propels oceanic and atmospheric circulation, which transports water around the globe. Gravity causes precipitation to fall from clouds and water to flow downward on the land through watersheds. Energy from the sun and the force of gravity drive the continual cycling of water.
What is gravity ?"Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun."
What is energy ?"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.”
What is water cycle ?"The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow."
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5. Ocean temperatures are increasing under climate change. What effect do you think this might have on the biological pump?
If ocean temperatures are increasing under climate change, then it might alter the carbon cycle and therefore it may have negative outcomes on the biological pump.
What does the biological pump mean?The term biological pump makes reference to the mechanism by which inorganic carbon atoms can be fixed into organisms due to photosynthetic processes, which is key to maintaining the homeostasis of the biosphere.
Therefore, with this data, we can see that the increase in ocean temperature may impact on the state of equilibrium of the biosphere by altering the carbon cycle and consequently affecting the biological pump.
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Differentiate between rest and motion.
Answer:
1. A body is said to be at rest if its position does not change with respect to its surroundings.
10. If the mass of the Earth is... increased by a factor of 2, then the Fgrav is ______________ by a factor of _______. ... increased by a factor of 3, then the Fgrav is ______________ by a factor of _______. ... decreased by a factor of 4, then the Fgrav is ______________ by a factor of _______.
Answer:
If the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.
If the mass of the earth is increased by a factor of 3, then Fgrav is increased by a factor of 3.
If the mass of the earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4
Explanation:
In order to solve this question, we must take into account that the force of gravity is given by the following formula:
\(F_{g0}=G \frac{mM_{E0}}{r^{2}}\)
So if the mass of the earth is increased by a factor of 2, this means that:
\(M_{Ef}=2M_{E0}\)
so:
\(F_{gf}=G \frac{2mM_{E0}}{r^{2}}\)
Therefore:
\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{2mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)
When simplifying we end up with:
\(\frac{F_{gf}}{F_{g0}}=2\)
so if the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.
If the mass of the earth is increased by a factor of 3
So if the mass of the earth is increased by a factor of 2, this means that:
\(M_{Ef}=3M_{E0}\)
so:
\(F_{gf}=G \frac{3mM_{E0}}{r^{2}}\)
Therefore:
\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{3mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)
When simplifying we end up with:
\(\frac{F_{gf}}{F_{g0}}=3\)
so if the mass of the Earth is increased by a factor of 3, then the Fgrav is increased by a factor of 3.
If the mass of the earth is decreased by a factor of 4
So if the mass of the earth is decreased by a factor of 4, this means that:
\(M_{Ef}=\frac{M_{E0}}{4}\)
so:
\(F_{gf}=G \frac{mM_{E0}}{4r^{2}}\)
Therefore:
\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{mM_{E0}}{4r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)
When simplifying we end up with:
\(\frac{F_{gf}}{F_{g0}}=\frac{1}{4}\)
so if the mass of the Earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4.
which element of a speech is used to link the introduction, body, and conclusion?please choose the correct answer from the following choices, and then select the submit answer button.subordinate pointssupporting materialsthesis statementstransition statements
Transition statements are used to link the introduction, body, and conclusion of a speech.
These statements serve as bridges between different sections or ideas within a speech, helping the speaker guide the audience smoothly from one point to another. Transition statements can be words, phrases, or sentences that indicate a shift in topic, introduce new information, provide examples, summarize key points, or signal the conclusion of one part and the beginning of another.
Transitions play a crucial role in maintaining the coherence and flow of a speech. They help the audience understand the logical progression of ideas and follow the speaker's train of thought. By using effective transition statements, speakers can create a seamless connection between the introduction, body, and conclusion, enhancing the overall clarity and organization of their speech.
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a projectile of 1.32 kg mass approaches a stationary body of 5.30kg at 12.5 m/s and, after colliding, rebounds in the inverse direction along the same line with a speed of 5 m/s. what is the speed of the 5.30kg body after the collision? g
The speed of the 5.30 kg body after the collision is approximately 4.358 m/s.
To solve this problem, we can apply the principle of conservation of momentum. The total momentum before the collision should be equal to the total momentum after the collision.
Let's denote the initial velocity of the 5.30 kg body as v2 and the final velocity as v2f. The initial velocity of the 1.32 kg projectile is 12.5 m/s, and its final velocity is -5 m/s (opposite direction).
Before the collision:
Total momentum = m1 * v1 + m2 * v2
= (1.32 kg) * (12.5 m/s) + (5.30 kg) * (0 m/s) (since the 5.30 kg body is stationary initially)
After the collision:
Total momentum = m1 * v1f + m2 * v2f
= (1.32 kg) * (-5 m/s) + (5.30 kg) * v2f
Since momentum is conserved, the total momentum before the collision should be equal to the total momentum after the collision:
(1.32 kg) * (12.5 m/s) + (5.30 kg) * (0 m/s) = (1.32 kg) * (-5 m/s) + (5.30 kg) * v2f
Solving for v2f:
(1.32 kg) * (12.5 m/s) = (1.32 kg) * (-5 m/s) + (5.30 kg) * v2f
16.5 kg·m/s = -6.6 kg·m/s + (5.30 kg) * v2f
23.1 kg·m/s = (5.30 kg) * v2f
Dividing both sides by 5.30 kg:
v2f = 23.1 kg·m/s / 5.30 kg
v2f ≈ 4.358 m/s
Therefore, the speed of the 5.30 kg body after the collision is approximately 4.358 m/s.
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A diagram of an electrical process. A steady wave enters an unlabeled device. Simultaneously, a signal is captured by a microphone, which is relayed to the unlabeled device by a squiggly line. The device generates a wave where the waves are of different heights.
What kind of modulator is used in this scenario?
modulator
Answer:
amplitude
Explanation:
tell me if i am wrong or right
Answer:
Amplitude <3
Explanation:
Suppose that the ultrasound source placed on the mother's abdomen produces sound at a frequency 2 MHz (a megahertz is 10^610 6 Hz). Sound travels through tissue at roughly the same speed as in water (v\approx 1500v≈1500m/s). Find the maximum change in frequency between the sound that is emitted by the device and the sound that is observed at the wall of the baby's heart. Treat the heart wall as a moving observer. Hint: you will need to use your answer from part (a). Give your answer as a positive number in Hz.
Answer:
the maximum frequency observed is 2.0044 10⁶ Hz
Explanation:
This is a Doppler effect exercise. Where the emitter is still and the receiver is mobile, therefore the expression that describes the process is
f ’= \(f_o \ ( \frac{v \pm v_o}{v} )\)
the + sign is used when the observer approaches the source
typical speeds of a baby's heart stop are around 200 m / min
let's reduce to SI units
v₀ = 200 m / min (1 min / 60 s) = 3.33 m / s
let's calculate
f ’= 2 10⁶ (\(\frac{1500 \ \pm 3.33}{1500}\))
f ’= 2.0044 10⁶ Hz
f ’= 1,9956 10⁶ Hz
therefore the maximum frequency observed is 2.0044 10⁶ Hz
Comparison of rarefraction and compression
Answer:
In a longitudinal wave, a compression is a region when the particles are closest together. A rarefaction is an area in a longitudinal wave where the particles are the furthest distant from one another. A compression is a zone where the medium is compressed, while a rarefaction is a region where the medium is spread out.
2 pts
The energy and penetrating power of nuclear radiation in decreasing order is:
Alpha > beta > gamma
Beta > alpha > gamma
Gamma > beta > alpha
Answer:
I think the answer 1
Explanation:
im probably wrong too i dont know
19,792,000,000 in scientific notation will have how many significant figures
Answer:
= 1.9792 × 10^10
Significant Figures= 5
Explanation:
Look at the attachment below
Hope this helps (:
a motor drives a shaft of radius r/8 that is attached to the center of a wheel of radius r. the motor is turned off, and the force that the motor exerts on the shaft, fmotor, varies with time, as shown. there is also a constant friction force of 0.4n applied to the rim of the wheel in the opposite direction of the motion. during which time interval does the rotational kinetic energy increase and then decrease?
The time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n and decreases is when fmotor is less than 0.4n.
What is rotational kinetic energy?
Rotational kinetic energy is the kinetic energy associated with the rotation of an object. It is equal to the work done in rotating an object (a moment of force multiplied by the angular displacement) and is equal to one-half the moment of inertia of the object multiplied by the angular velocity squared.
The rotational kinetic energy of the wheel is given by the equation:
K.E. = 1/2 Iω2
where I is the moment of inertia and ω is the angular velocity.
The moment of inertia is given by I = mr2, where m is the mass of the wheel and r is the radius of the wheel.
The angular velocity is given by ω = v/r, where v is the linear velocity of the wheel.
The linear velocity of the wheel is given by v = 2πfr, where f is the frequency of rotation.
The frequency of rotation is given by f = (fmotor - 0.4n)/(2πr).
The rotational kinetic energy can therefore be written as:
K.E. = 1/2 m(2πfr)2r2
Time interval where the rotational kinetic energy increases:
The rotational kinetic energy increases when the linear velocity of the wheel (v) increases. This happens when the frequency of rotation (f) increases. This is when fmotor is greater than 0.4n.
Hence, the time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n.
Time interval where the rotational kinetic energy decreases:
The rotational kinetic energy decreases when the linear velocity of the wheel (v) decreases. This happens when the frequency of rotation (f) decreases. This is when fmotor is less than 0.4n.
hence, the time interval where the rotational kinetic energy decreases is when fmotor is less than 0.4n.
Therefore, The time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n and decreases is when fmotor is less than 0.4n.
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2. What is the distance to a star, in parsecs, if its measured parallax (p) is 1/30 of an
arc second (use equation below)? What is its distance in light years? Show your
work!
Dist. (in pc) = 1/ Parallax (in arc sec)
The distance to the star, in parsecs, is 30 pc.
The distance to the star, in light years, can be calculated using the conversion factor of 3.26 light years per parsec. Therefore, the distance to the star in light years is approximately 97.8 light years.
The distance to a star can be determined using its measured parallax angle. Parallax is the apparent shift in the position of an object when viewed from two different points. It is measured in units of arc seconds.
The formula to calculate the distance to a star in parsecs is:
Distance (in pc) = 1 / Parallax (in arc sec)
Given that the measured parallax is 1/30 of an arc second, we can substitute this value into the formula:
Distance (in pc) = 1 / (1/30) = 30 pc
This gives us the distance to the star in parsecs.
To convert the distance to light years, we use the conversion factor of 3.26 light years per parsec. Multiplying the distance in parsecs by this conversion factor gives us the distance in light years:
Distance (in light years) = 30 pc × 3.26 light years/pc = 97.8 light years
Therefore, the distance to the star is approximately 30 parsecs or 97.8 light years.
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Calculate the force needed to give a car of mass 800 kg an acceleration of 2.0 ms−2. plss quick
The force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.
How to calculate force?The force needed to push an object can be calculated by multiplying the mass of the object by its acceleration as follows:
Force = mass × acceleration
According to this question, a car of mass 800 kg has an acceleration of 2.0 ms−². The force is calculated as follows:
Force = 800kg × 2m/s²
Force = 1600N
Therefore, the force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.
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Where is the furthest humans have sent probes in space?
To the nearest star to our Sun
To the Moon
Outside the edges of the solar system
To Mars
Answer:
Outside the edges of the solar system.
That's not a simple question, and it doesn't have a simple answer.
The two Voyager spacecraft have been flying for about 43 years now.
They left the "heliosphere" about 2 years ago (in November 2018), and are now about 10.9 billion miles from Earth.
Mission controllers can still communicate with them, but it takes radio signals almost 17 hours to reach either one of the spacecraft from Earth.
(And another 17 hours if it has anything to answer back. That's a day and a half to do a "How are you ?" . . . . . "I'm OK.".)
But wait !
The boundary of the solar system is considered to be beyond the outer edge of the "Oort Cloud", a collection of small objects that are still under the influence of the Sun's gravity. The thickness of the Oort Cloud is not exactly known, but it's estimated to begin at about 93 billion miles from the Sun, and to extend maybe as far as 9,300 billion miles from the sun. It will take about 300 years for Voyager 2 to reach the inner edge of the Oort Cloud and possibly 30,000 years to fly beyond it.
So even though the Voyager spacecraft are the farthest man-made objects away from Earth, and have been sailing along for 43 years, neither of them is anywhere near leaving the solar system yet.
Yes, we've sent artificial probes past the Sun, the Moon, Mercury, Venus, Mars, Jupiter, Saturn, Uranus, Neptune, Pluto, several asteroids, several comets, and past the Kuiper belt, we're still thousands of years from leaving the solar system, and millions of years from reaching the next nearest star ... even if the Voyagers don't get pulverized into dust by meteoroids and radiation before they get there.
true or false Oxygen atoms bond together, but this is not because of an atomic force.”
Answer:
this is false not correct no FALSE
8. What is the total mechanical energy of a penny dropped off of the top of the Empire
State Building if it has a potential energy of 47 J, and a kinetic energy of 23 J?
A.18J
B.24 J
C.70 J
D.667 J
Answer:
C 70 Joules because all of the energy of converted to potential energy.
calculate the force required to give a mass of 71 kg an acceleration of 6.4 m/s²
The force of 454.4 N is required to give a mass of 71 kg and an acceleration of 6.4 m/s².
What is force?Force can be explained as the influence that is capable of changing the state of the body of motion or rest. The S.I. unit of measurement of force is Newton and force is a vector parameter. Force exerted on a body can change the direction as well as the speed of the moving body.
The force exerted on a system can be calculated from the product of the mass (m) and acceleration. The mathematical expression of the 2nd law of motion for force can be represented as:
F = ma
Given, the mass of the acting on an object, m = 71 Kg
The acceleration acting on an object, a = 6.4 m/s²
The force acting on the given mass can be calculated as:
F = ma = 71 × 6.4
F = 454.4 N
Therefore, the force required on an object is equal to 454.4 N.
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A parallel-plate capacitor with circular plates and a capacitance of 11.0 μF is connected to a battery which provides a voltage of 12.6 V .Part AWhat is the charge on each plate?Part BHow much charge would be on the plates if their separation were doubled while the capacitor remained connected to the battery?Part CHow much charge would be on the plates if the capacitor were connected to the battery after the radius of each plate was doubled without changing their separation?
A- the charge on each plate is 2.45 x\(10^{-7}\) C. B- the charge on each plate would be 69.3 μC , C- the charge on each plate would be 554 μC.
Part A: The capacitance of a parallel-plate capacitor is given by:
C = εA/d
where ε is the permittivity of free space, A is the area of each plate, and d is the distance between the plates.
Q = CV = (εA/d)V
Substituting the given values, we get:
Q = (8.85 x \(10^{-12}\) F/m)(π\(r^{2}\))(12.6 V)/(2d) = (5.56 x \(10^{-9}\)C/\(m^{2}\))/d
Q = (5.56 x \(10^{-9}\)C/\(m^{2}\))/d = ( (5.56 x \(10^{-9}\)C/\(m^{2}\))(π(0.05 )/(4.5 x \(10^{3}\) m) = 2.45 x\(10^{-7}\) C
Therefore, the charge on each plate is 2.45 x 10^-7 C.
Part B:
the voltage across the plates will remain the same, so the charge on each plate will be:
Q' = CV = (C/2)V = (11.0 μF/2)(12.6 V) = 69.3 μC
Therefore, the charge on each plate would be 69.3 μC if the separation between the plates were doubled while the capacitor remained connected to the battery.
Part C:
The voltage across the plates will remain the same, so the charge on each plate will be:
Q'' = CV = (4C)V = (4)(11.0 μF)(12.6 V) = 554 μC
Therefore, the charge on each plate would be 554 μC if the radius of each plate were doubled without changing their separation and the capacitor remained connected to the battery.
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the quantity with the same units as force times time, ft, with dimensions mlt−1 is what?
The quantity with the same units as force times time (ft) and dimensions of MLT^(-1) is momentum.
Momentum is defined as the product of an object's mass and its velocity. Its units in the SI system are kilogram meters per second (kg m/s).
To see why momentum has the same units as force times time, we can use the definition of force, which is the rate of change of momentum.
F = dp/dt
where F is force, p is momentum, and t is time. Rearranging this equation, we get:
F * t = dp
where F * t is force times time (ft) and dp is the change in momentum. Therefore, force times time has the same units as momentum, which is MLT^(-1).
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A tsunami of wavelength 225km and velocity 575km/h travels across the Pacific Ocean. As it approaches Hawaii, people observe an unusual decrease of sea level in the harbors.
Approximately how much time do they have to run to safety? (In the absence of knowledge and warning, people have died during tsunamis, some of them attracted to the shore to see stranded fishes and boats.)
Under the given scenario, the people in Hawaii would have approximately 47 minutes (0.78 x 60 minutes) from observing the unusual sea level decrease to when the tsunami reaches their location.
A tsunami of wavelength 225km and velocity 575km/h travels across the Pacific Ocean. As it approaches Hawaii, people observe an unusual decrease in sea level in the harbors. To determine how much time people have to run to safety, we need to calculate the time it takes for the tsunami to reach Hawaii.
We can use the formula: time = distance/velocity.
In this case, the distance is unknown, but we can use the wavelength as a proxy. Since the wavelength is 225km, we can assume that the distance between each crest and trough of the wave is 225km. Therefore, the distance traveled by the wave in one wavelength is 2 x 225km = 450km.
Now we can calculate the time it takes for the wave to travel this distance using the given velocity of 575km/h:
time = distance/velocity
time = 450km / 575km/h
time = 0.78 hours
So the people in Hawaii would have approximately 47 minutes (0.78 x 60 minutes) from observing the unusual sea level decrease to when the tsunami reaches their location. It's important to note that this is just an estimate and the actual time may vary depending on factors such as the ocean's depth and the coastline's shape.
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Starting from rest an object accelerates on a straight line at rate of 2ms‐² for 10 seconds. what is the speed of the object at the end of the 10 seconds
Answer:
20 meters/sec
Explanation:
See attachment.
2m/s^2 = (v - 0)/10s
v = 20 m/s
suppose you place 3.31mL of a substance into a graduated cylinder. The graduated cylinder has a mass of 12.55 g when empty and a mass of 15.5 7 g after adding the substance. what is the density of the substance (in g/ml)
The density of the substance is 0.913 grams per milliliter (g/mL).
Density is a measure of how much mass is contained in a certain volume of a substance. It is defined as the mass of a substance divided by its volume. In this problem, we need to calculate the density of a substance given its volume and the mass of the substance and the container it is placed in.
To calculate the density of the substance, we need to first determine the mass of the substance alone. We can do this by subtracting the mass of the empty graduated cylinder from the mass of the cylinder with the substance in it.
The mass of the substance can be calculated as follows:
Mass of substance = Mass of cylinder with substance - Mass of empty cylinder
Mass of substance = 15.57 g - 12.55 g
Mass of substance = 3.02 g
Now that we know the mass of the substance, we can calculate its density using the formula:
Density = Mass / Volume
We were given the volume of the substance as 3.31 mL, so we can plug this into the formula:
Density = 3.02 g / 3.31 mL
Simplifying this expression gives us the density of the substance:
Density = 0.913 g/mL
Therefore, the density of the substance is 0.913 grams per milliliter (g/mL). This means that for every milliliter of the substance, there is 0.913 grams of mass. Density is a fundamental property of a substance that can help us identify or classify it.
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If the puppies in the experimental group gain, on average, 3 pounds more than those in the control group over a 4-month period and seem healthier and more energetic, then ________.
If the puppies in the experimental group gain, on average, 3 pounds more than those in the control group over a 4-month period and seem healthier and more energetic.
The given statement suggests that the researchers conducted an experiment on two groups of puppies, with one being a control group and the other an experimental group. The researchers were testing the impact of an independent variable on the puppies over a 4-month period. Based on the results of the experiment, the puppies in the experimental group gained an average of 3 pounds more than those in the control group. Additionally, these puppies also appeared healthier and more energetic than their counterparts in the control group. This implies that the independent variable of the study resulted in positive effects on the dependent variable in the experimental group. The researchers would, therefore, consider their hypothesis to be supported.
The experimental group appeared to benefit from the independent variable, which resulted in the observed differences between the two groups.
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A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is 2.4 N. The free-body diagram shows the forces acting on the sled.
What is the acceleration of the sled and the normal force acting on it, to the nearest tenth?
Answer:
a = 1.3 m/s2; fn = 63.1 n :)
Which is one use of lasers
A. reproducing images to make them clearer
B. Producing a magnified image of the moon
C. Cutting an iron bar into two pieces
D. Making a leaf appear larger so it’s veins are visible
Answer:
c
Explanation:
because what else can the laser be used for
In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the current through the inductor, I, when energy is shared equally between the electric and magnetic fields. Express your answers in terms of qm, L, and C.
Answer:
a. q = qm/√2 b. qm/√(2LC)
Explanation:
a. Charge on the capacitor
Let U₁ = energy in inductor and U₂ = energy in capacitor and U = total energy in circuit.
So, U₁ + U₂ = U.
Since the energy is shared equally between the capacitor and inductor, U₁= U₂,so
2U₂ = U
and U₂ = U/2
Now U₂ = q²/2C where q is the charge on the capacitor with capacitance C and
U = (qm)²/2C where qm is the maximum charge on the capacitor.
Since U₂ = U/2,
Substituting the values for U₂ and U, we have
q²/2C = [(qm)²/2C]/2
q² = (qm)²/2
taking square-root of both sides, we have
q = qm/√2
b. The current in the inductor
Since the energy in the capacitor equals the energy in the inductor,
1/2LI² = 1/2q²/C where L is the inductance of the inductor and I the current through it.
I² = q²/LC
taking square-root of both sides, we have
I = q/√LC
substituting the value of q from above, we have
I = qm/√2 ÷ √LC
I = qm/√(2LC)