9(k+12)+4k2 when k= 3 the 2 is small

Freya should budget a maximum of $472.50 for housing expenses based on the guideline of spending 30% of her monthly income.

When budgeting for housing, it is generally recommended to allocate a certain percentage of your income towards housing expenses. The recommended percentage varies depending on factors such as location, personal financial goals, and individual circumstances.

A common guideline is to spend no more than 30% of your monthly income on housing expenses. To determine the maximum amount Freya should budget for housing, we can calculate 30% of her monthly income:

Maximum housing budget = 30% of $1575

Maximum housing budget = 0.30 × $1575

Maximum housing budget = $472.50

Therefore, Freya should budget a maximum of $472.50 for housing expenses based on the guideline of spending 30% of her monthly income.

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Step-by-step explanation:

54

is the correct answer

Answer:

54

Step-by-step explanation:

multiply the exponents

-1 does not equal 0, the equation is not true for any value of "a". This means that there is no value of "a" for which the function f(x) is continuous at x = 1.

To determine the value of "a" for which the function f(x) is continuous at x = 1, we need to check if the left-hand limit and the right-hand limit of f(x) as x approaches 1 are equal, and if the value of f(x) at x = 1 is equal to these limits.

First, let's calculate the left-hand limit of f(x) as x approaches 1. For x < 1, the function is given by f(x) = (ax² - 1). To find the left-hand limit, we substitute x = 1 into this expression:

lim(x→1-) f(x) = lim(x→1-) (ax² - 1) = a(1²) - 1 = a - 1.

Next, let's calculate the right-hand limit of f(x) as x approaches 1. For x > 1, the function is given by f(x) = (a(x² - 2x + 1)). Substituting x = 1 into this expression, we have:

lim(x→1+) f(x) = lim(x→1+) (a(x² - 2x + 1)) = a(1² - 2(1) + 1) = a(1 - 2 + 1) = a.

For the function f(x) to be continuous at x = 1, the left-hand limit and the right-hand limit should be equal. Therefore, we have:

a - 1 = a.

To solve this equation for "a," we subtract "a" from both sides:

-1 = 0.

Since -1 does not equal 0, the equation is not true for any value of "a". This means that there is no value of "a" for which the function f(x) is continuous at x = 1.

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Answer:

ithink C dahil yuhn nga aking suggest.

Answer:

Hi

Please mark brainliest ❣️

Step-by-step explanation:

-3 1/4 ÷ 2 1/3

Change to improper fraction

-13/4 ÷ 7/3

-13/4 × 3/7

-39/28 or -1 11/28

Answer:

It would be a diagnol line.

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\( \boxed{ \mathsf{ \red{y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1}) }}}\)

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is (0, -1.5) which lies on the y axis(the point where the dotted line touches the y axis)

other point is (2.5, 0) and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\(\mathsf{\implies y - ( - 1.5) = \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )} \)

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\(\mathsf{\implies (y + 1.5) = \frac{0 + 1.5}{2.5 } (x )} \)

\(\mathsf{\implies y + 1.5 = \frac{ 1.5}{2.5 } x } \)

\(\mathsf{\implies y + 1.5 = \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x } \)

\(\mathsf{\implies y + 1.5 = \frac{ 3}{5 } x } \)

multiplying both sides by 5

\(\mathsf{5y + 7.5 = 3x}\)

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\(\mathsf{\implies5(0) + 7.5 = 3(0)}\)

\(\mathsf{\implies0 + 7.5 = 0}\)

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\(\mathsf{\implies7.5 > 0}\)

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\(\mathsf{5y + 7.5 > 3x}\)

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

that is the last option

Answer:

...............................

Answer: 68y+106=36-y

Answer:

\(\sqrt{5}\)

Step-by-step explanation:

\(a^{2} + b^{2} = c^{2}\)

In this situation a = 1, b = 2

\(1^{2} + 2^{2} = c^{2}\)

1 + 4 = \(c^{2}\)

5 = \(c^{2}\)

c = \(\sqrt{5}\)

This is an important mathematical theorem to know. It's called the Pythagorean Theorem.

Answer:

Below.

Step-by-step explanation:

(-3, 9) - Quadrant II.

(6, -6) - Quadrant IV.

(0, -1 1/2) -  x-axis 0, y-axis -1/1/2

Answer:

∠ GJK = 102°

Step-by-step explanation:

(2x + 92) and (3x + 63) are same- side interior angles and sum to 180° , so

2x + 92 + 3x + 63 = 180

5x + 155 = 180 ( subtract 155 from both sides )

5x = 25 ( divide both sides by 5 )

x = 5

Then

∠ GJK = 2x + 92 = 2(5) + 92 = 10 + 92 = 102°

Cramer's rule states that the solution to a system of equations can be determined by taking the determinant of the coefficient matrix, which in this case is 4, and then dividing each equation's determinant of the corresponding matrix by the determinant of the coefficient matrix. This allows us to solve for the variable y.

Cramer's Rule is a method used to solve systems of linear equations. It states that the solution to a system of equations can be determined by taking the determinant of the coefficient matrix and then dividing each equation's determinant of the corresponding matrix by the determinant of the coefficient matrix. This gives us the solution for the variable y. To calculate the determinant of the coefficient matrix, we take the product of the diagonal elements and subtract the product of the elements that are not on the diagonal The determinant is calculated by taking the product of a and d, and then subtracting the product of b and c. Once we have the determinant of the coefficient matrix, we can calculate the determinants of each equation's corresponding matrix by replacing the y in the equation with 1 and the other coefficients with the original coefficients of the equation. We then divide each equation's determinant by the determinant of the coefficient matrix to solve for y. This method is useful as it allows us to solve a system of equations with multiple variables in a quick and efficient manner.

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As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

It is possible either multiply, distribute, add, or negate in mathematics. The trying to follow is how a expression is put together: Number, expression, and scientific operator The ingredients of a mathematical expression include numbers, variables, and operations (such as addition, subtraction, multiplication or division etc.) It is possible to combine expressions and phrases. An expressions, often known as an arithmetic operation, is any mathematical statement that contains variables, numerals, and a numerical operation between them. That instance, the word m there in given equation is separated from the terms 4m and 5 by the arithmetic symbol +, as is the variable m in the phrase 4m + 5.

given

To address this issue, we just need to determine the total or difference that yields 2x2 + 2x + 2

Option A: ( x2 + 4x -2) + (x2 - 2x - 4) = 2x2 + 2x - 6

Option B: ( x2 + 4x - 2 ) + ( x2 + 2x + 4 ) = 2x2 + 6x + 2

Option C: ( x2 + 4x - 2) - ( -x2 + 2x - 4)= x2 + 4x - 2 + x2 - 2x + 4

= 2x2 + 2x + 2

As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

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The complete question is:-

Select the correct answer.

Which sum or difference is modeled by the algebra tiles?

A. (-x2 + 2x + 3) − (x2 − 2x − 1) = -2x2 + 2

B. (-x2 + 2x + 3) − (-x2 + 2x + 1) = -2x2 + 2

C. (-x2 + 2x + 3) + (-x2 + 2x + 1) = -2x2 + 2

D. (-x2 + 2x + 3) + (-x2 − 2x − 1) = -2x2 + 2

Answer:

  4

Step-by-step explanation:

Put 2 where x is and do the arithmetic.

  f(2) = 10 -3∙2 = 10 -6

  f(2) = 4

Answer:  It will not create a perpendicular bisector.

Explanation:

If the compass is the same setting as the first arc and drawn from point B, the points of intersection of the arcs will pass through the midpoint of AB (thus creating a perpendicular bisector).

If you change the setting of the compass and draw an arc from point B, the points of intersection of the arcs will still create a perpendicular line but will not pass through the midpoint of AB (creating a perpendicular line but not a perpendicular bisector).

A perpendicular bisector divides a line segment into two equal segments.

If the compass setting is changed, the line will not be bisected.

To bisect a line, the positioning of the compass must be done as follows:

The above points are what is being done in the given construction.

Any step or setting other than that, would not create a perpendicular bisector.

Hence, if the compass setting is changed, the perpendicular bisector of the line would not be drawn.

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cot (-859°) can be expressed as cot 41° an acute angle which is less than 45°

Trigonometry is used in navigation directions. Estimate the direction you need to place your compass to get a straight line. With the help of a compass and navigation trigonometric functions, it's easy to find a place or find the distance to see the horizon. 

A  Mathematical Statement which contains numbers and variables.

Angle: The two straight lines meeting at the vertex(a common point)

According to the question:

cot (-859) can be expressed as:

cot (-859 + 360x2)= cot (-859 +720)= cot (139)= cot (180 -139)= cot 41°(or)cot(-859) = cot(-859 + 180°x5)= cot (859 +900)= cot (41)°

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The variables 8 observations have x2 values of 2 or greater.

Two variables, x1 and x2, are present in the supplementary data set. There are a total of 20 observations in this data set. The x2 values for 8 of these 20 observations are equal to 2. Thus, x2 values of two were present in eight out of twenty observations, or 40%. The following 12 observations' x2 values do not add up to 2. Thus, 8 of the 20 observations in the data set have x2 values of 2 or higher.8 of these 20 observations have x2 values that are equal to 2. Thus, eight out of twenty observations, or 40 percent, had x2 values equal to two. The x2 values for the next 12 observations are not equal to 2. Consequently, 8 of the data set's 20 observations have x2 values of 2 or above.

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The ways to elect the candidates from the total is 462

From the question, we have

The number of ways of selection could be drawn is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 11 and r = 6

Substitute the known values in the above equation

Total = ¹¹C₆

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 11!/5!6!

Evaluate

Total = 462

Hence, the number of ways is 462

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Answer:

9.88888888889 or rather, 8 8/9

Step-by-step explanation:

Answer:

The answer is below.

Step-by-step explanation:

Two option.

1st. Take the derivative of f(x) and make f'(x)=0.

2nd. Graph it.

For more elaborate explanation, please ask another fellow student.

Answer:

B? I think its b. Im not completely sure tho

Step-by-step explanation:

The expected number of investigators who will report that 3, 4, or 5 people are consumers of rice is 57 investigators.

The binomial distribution B(n, p) describes the behavior of a count X of successes in n independent trials, each with its own boolean-valued outcome: success (with probability p) or failure (with probability q = 1-p).

We want to find the probability that an investigator reports 3, 4, or 5 people are consumers of rice. The probability P(X=k) for a binomial distribution is given by the formula:

P(X=k) = C(n, k) * p^k * q^(n-k)

So we want to find P(X=3) + P(X=4) + P(X=5) :

P(X=3) = C(10, 3) * (0.5)^3 * (0.5)^(10-3)

= 0.117

P(X=4) = C(10, 4) * (0.5)^4 * (0.5)^(10-4)

= 0.205

P(X=5) = C(10, 5) * (0.5)^5 * (0.5)^(10-5)

= 0.246

The expected number of investigators who will report three or less of the people interviewed consumed is :

= P(X=3) + P(X=4) + P(X=5)

= 0.117 + 0.205 + 0.246

= 0.568

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Full question is:

Suppose that half the population of a town are consumers of rice. Each of 100 investigators interviews 10 individualas to see wheather they are consumers of rice. How many investigators do you expert to report that three or more but less than six people are consumers of rice?

If a five - card poker hand is dealt to you such that all of them were hearts, the probability of this is 0.000495.

First find the number of ways the 52 cards in a standard deck of cards can be dealt in 5 ways:
= 52! / (5! x 47!)

= 2, 598, 960 ways

In a standard deck of cards, there are a total of 13 cards that are hearts. You therefore need to find the number of ways that 5 cards are dealt such that they are all hearts:

= 13! / (5! x 8!)

= 1, 287 ways

The probability that all the cards in a five - card poker hand dealt to you are hearts is:

= Number of ways to give all hearts / Number of possible ways

= 1, 287 / 2, 598, 960

= 0.000495

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Answer:

9

Step-by-step explanation:

9

9x9 = 81

Therefore, 81 ÷ 9 is 9

Step-by-step explanation:

Let the number Noah is thinking of be x,

=> x - 19 * 4 = 16

=> x - 19 = 16/4

=> x = 16/4 + 19

=> x = 4 + 19

=> x = 23

If my answer helped , please mark me as brainliest,

Thank you

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

\(x^2-2x + y^2 - 6y = 26\)

Typically, the equation of a circle would be in the form \((x-h)^2+(y-k)^2=r^2\) where \((h,k)\) is the center and \(r\) is the radius.

To get the given equation \(x^2-2x + y^2 - 6y = 26\) into this form, we must complete the square for both x and y.

1) Complete the square for x

Let's take a look at this part of the equation:

\(x^2-2x\)

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

\(x^2-2x+1\)

Great! Now, let's add this to our original equation:

\(x^2-2x+1+y^2-6y = 26\)

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

\(x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27\)

Complete the square:

\((x-1)^2+y^2-6y = 27\)

2) Complete the square for y

Let's take a look at this part of the equation \((x-1)^2+y^2-6y = 27\):

\(y^2-6y\)

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

\(y^2-6y+9\)

Great! Now, back to our original equation:

\((x-1)^2+y^2-6y+9= 27\)

Remember to add 9 on the other side as well:

\((x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36\)

Complete the square:

\((x-1)^2+(y-3)^2= 36\)

3) Determine the center and the radius

\((x-1)^2+(y-3)^2= 36\)

\((x-h)^2+(y-k)^2=r^2\)

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

Answer:

\(\sqrt{g^2+f^2-c}\)

\(g=-1,f=-3,c=-26\)

so, the Center of the equation is \((1,3)\)

\(\sqrt{(-1)^2+(-3)^2-(-26})\)

\(=\sqrt{1+9+26}\)

\(=\sqrt{36}\)

\(=6\)

OAmalOHopeO

Answer:

I think you can go with:

The margin of error is equal to half the width of the entire confidence interval.

so  try .74 ± \(\frac{.032}{2}\)  =   [ .724 , .756] as the confidence interval

Step-by-step explanation:

Answer:

HCF of 72 and 96 is 24

Step-by-step explanation:

What is the highest common factor (HCF) of 72 and 96

HCF

Highest Common factor(HCF) is the biggest number that is divisible by both numbers.

First we will write prime factors of both 72 and 96

72: 2x2x2x3x3

96: 2x2x2x2x2x3

Now, writing the common factors: 2x2x2x3

Multiplying them we get:  24

So, HCF of 72 and 96 is 24

The correct answer is Option C. The graph represents the function f (x) = StartFraction 1 Over x EndFraction minus 1 is On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = 0.

On a coordinate plane, the graph of a hyperbola is shown.

In quadrant 1, one curve opens up and to the right, while in quadrant 3, the other curve opens down and to the left.

The vertical asymptote is at x = -1, and the horizontal asymptote is at y = 0. This hyperbola is symmetrical across both the x and y axes.

The function f(x) = 1/x - 1 has a vertical asymptote at x = 0 because the denominator approaches zero as x approaches zero.

A fraction with a denominator of zero cannot exist.

The horizontal asymptote of this function is y = -1 because as x approaches infinity or negative infinity, f(x) approaches -1.

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