9 and 10 need help please

A real life example of an acute angle is the angle that's made in letter V.

It should be noted that an acute triangle simply means an angle that measures less than 90 degrees.

In this case, the real life example of an acute angle is the angle that's made in letter V. Other examples include slizing a pizza into different shapes.

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The physical layout of Alcoa Corporation's headquarters, with minimal traditional offices, open-air escalators, and low-walled cubicles, encourages an open and collaborative culture.

The physical layout of Alcoa Corporation's headquarters, characterized by the minimal number of traditional offices, open-air escalators, and low-walled cubicles, fosters an open and collaborative culture within the organization. The absence of traditional offices with four walls and a door eliminates physical barriers and promotes accessibility and visibility among employees. This layout encourages communication, interest, and collaboration, as employees are more likely to engage with one another in an open workspace.

The placement of elevators in out-of-the-way alcoves and the presence of an open-air escalator in the center of the building encourage employees to move around, interact with colleagues from different departments, and engage in impromptu conversations, fostering a sense of community and teamwork.

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Answer:

-3<x<5

Step-by-step explanation:

Given the inequality 2x-3<7 and 5-x<8

Solve 2x-3<7

Add 3 to both sides

2x-3+3 < 7+3

2x < 10

2x/2 < 10/2

x < 5

Solve 5-x<8

subtract 5 from both sides:

5-x-5<8-5

-x < 3

multiply both sides  by -1

-(-x) > -3

x > -3

-3<x

Combine both solutions x < 5 and -3<x

-3<x<5

The solution to the compound inequality is -3<x<5

The answer that describes the polygon RSTU is as follows:

A quadrilateral is a polygon with 4 sides. Therefore, let's use the properties to find the name of the shape  RSTU as follows:

The polygon has 4 sides therefore, it is a quadrilateral.

The quadrilateral has opposite side parallel to each other. The opposite sides are RS and TU.

A trapezoid is a quadrilateral with only one pair of opposite side parallel to each other.

Therefore, the shapes that defines the polygon are as follows:

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The average value of the function f(x)=cos(x) on the interval [0,π]=0 and c=pi/2.

The average value of a function is the height of the rectangle that has an area that is equivalent to the area under the curve of the function. If you look at the picture below, you know already that the integral of the function is all of the areas between the function and the x-axis

The average value of the function f(x)=cos(x) on the interval [0,π] and determine a number c in this interval for which f(x) is equal to the average value.

The average value of the function f(x) on interval [0,pi]

can be evaluated through the following expression:

\(A.V=\frac{1}{(b-a)}{\int_a^b f(x) dx\)

Here we have f(x)= cosx  and interval [0,pi]

\(A.V = \frac{2}{\pi}{\int_0^{\pi} cosx dx\\\\=2/\pi[sin\pi-sin0]\\=0.\)

Avarege value 0 and c=pi/2.

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The correct answer is option (b) No, the statement does not represent an exponential function, h(t) = -4.9t² + 18t + 40 is a quadratic function and not an exponential function.

An exponential function is a mathematical function in which the variable is in the exponent. Exponential functions follow the form f(x) = a^x, where a is the base and x is the exponent.

The given statement is h(t) = -4.9t² + 18t + 40, which does not represent an exponential function. The value of t is not in the exponent in this case. Instead, it's a quadratic equation, which is in the form of h(t) = at² + bt + c.

Therefore, the correct answer is option (b) No, the statement does not represent an exponential function.

Explanation:

An exponential function can also be represented by the general form y = ab^x, where b > 0 and b ≠ 1. When plotted on a graph, the curve of an exponential function rises or falls at an increasing rate, depending on whether b is greater than or less than 1, respectively.

A quadratic equation is an equation of the form ax² + bx + c = 0, where a ≠ 0, and x represents a variable. Quadratic equations are second-degree equations, which means the highest exponent of the variable is two.

Therefore, h(t) = -4.9t² + 18t + 40 is a quadratic function and not an exponential function.

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The truth values of the given statements in terms of q(x) are: q(0) is true, q(1) is false, q(-2) is false, and q(2) is true.

The statement q(x) is x² = 2x. Now, we will check the truth value of each statement in terms of q(x):

(i) q(0): \(0^2=2\times 0\)

   q(0): 0 = 0; so, the statement q(0) is true.

(ii) q(1): \(1^2=2\times 1\)

    q(1): 1 = 2; so, the statement q(1) is false.

(iii) q(-2): \((-2)^2=2\times (-2)\)

     q(-2): 4 = -4; so, the statement q(-2) is false.

(iv) q(2): \(2^2=2\times 2\)

     q(2): 4 = 4; so, the statement q(2) is true.

So, the truth values of the given statements in terms of q(x) are: q(0) is true, q(1) is false, q(-2) is false, and q(2) is true.

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The approximation of the integral using two-point Gauss integration is 8.30. The actual value of the integral is ∫ba (x^2 + 2x) dx = [x^3/3 + x^2]3 1 = 10. The error in the approximation is 1.7.

Sampling points and weights for two-point Gauss Integration:Two-point Gauss integration is used to approximate an integral. The following are the sampling points and weights for two-point Gauss integration:Sampling points xi = (a + b) / 2 - ((b - a) / 2) * (sqrt(3) / 3), (a + b) / 2 + ((b - a) / 2) * (sqrt(3) / 3)

Weights wi = 1, 1, where a and b are the lower and upper limits of the integral, respectively. Let's take an example to understand this better. Let's find the approximation for the integral of f(x) = x^2 + 2x over the range [1,3].

In this case, a = 1 and b = 3. We can use the following formula to calculate the approximation of the integral: ∫ba f(x)dx ≈ ((b-a)/2) [f(x1) + f(x2)] where x1 and x2 are the two sampling points. Calculation of the integral using two-point Gauss integration:

Let's calculate the integral ∫ba (x^2 + 2x) dx using two-point Gauss integration. a = 1 and b = 3. Using the formula, we get the following approximation: ∫ba f(x)dx ≈ ((b-a)/2) [f(x1) + f(x2)] = ((3-1)/2) [f(x1) + f(x2)] = (1/2) [(1.46) (f(1.46)) + (-0.46)(f(-0.46))] = (1/2) [(1.46)((1.46)^2 + 2(1.46)) + (-0.46)((-0.46)^2 + 2(-0.46))] = 8.30

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r = (sin theta + C)^(-1) where C is an arbitrary constant of integration.

Any equation with at least one ordinary or partial derivative of an unknown function is referred to as a differential equation. Assuming that a function's rate of change with regard to x is inversely proportional to y, we may write it down as dy/dx = k/y.

r = (cos(theta) - d/d(theta) of sec(theta)) / sec(theta)

The differential equation assists us in presenting a relationship between the changing quantity with respect to the change in another variable. The derivative represents nothing more than a rate of change. Be a function with the form: y=f(x), where x is an independent variable, f is an unknown function.

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Answer:

The correct option is The PLUS loan will have a higher balance by $34.10 at the time of repayment. Hence Option B is correct.

Step-by-step explanation:

Answer:

Exact Form:

49/4

Decimal Form:

12.25

Mixed Number Form:

12 1/4

Step-by-step explanation:

Isolate the radical, then raise each side of the equation to the power of its index.

√x-2=√x-10

x-4√x+4=x-10

-4√x+4=-10

-4√x=-10-4

-4√x=-14

√x=7

-

2

x= 49

---

44

In the triangle KRL, an interior angle that can be named with respect to KRE is the angle R.

When considering the triangle KRL, we can identify several interior angles within the triangle. An interior angle is an angle formed by two sides of a polygon that are adjacent to each other. In this case, we are specifically looking for an interior angle with respect to KRE, which means we are focusing on the relationship between the angle and the sides or vertices of the triangle.

In triangle KRL, the vertices are represented by the letters K, R, and L. The sides are represented by the segments KR, RL, and LK. To identify an interior angle with respect to KRE, we need to consider the relationship between angle KRE and the other angles in the triangle.

Angle KRE is formed by the segments KR and RE. The other angles in the triangle are angle KRL and angle LKR. Since angle R is formed by segments KR and RL, it is an interior angle that can be named with respect to KRE.

By considering the vertices and sides of the triangle, we can see that angle R is adjacent to angle KRE. It shares the side KR with angle KRE, making it an interior angle in relation to KRE within the triangle KRL.

In conclusion, when considering the triangle KRL, an interior angle that can be named with respect to KRE is the angle R. It is formed by the segments KR and RL, adjacent to angle KRE, and contributes to the overall geometry and relationships within the triangle.

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Step-by-step explanation:

43.5 miles per 1.25 gallons

= 34.8 miles per gallon.

Answer:

39 months later

Step-by-step explanation:

or it is very close to that

The solution to the ODE f'(t) + f(t) = 2 + e with the initial condition f(0) = 0 is given by f(t) = -1 + 2e^t.

To solve the given ordinary differential equation (ODE) f'(t) + f(t) = 2 + e using Laplace transforms, we first apply the Laplace transform to both sides of the equation. This transforms the ODE into an algebraic equation in the Laplace domain. After solving the algebraic equation for the Laplace transform of the function f(t), we then apply the inverse Laplace transform to obtain the solution in the time domain. By incorporating the initial condition f(0) = 0, we can determine the particular solution.

Let's solve the ODE f'(t) + f(t) = 2 + e using Laplace transforms. First, we take the Laplace transform of both sides of the equation. The Laplace transform of the derivative f'(t) can be expressed as sF(s) - f(0), where F(s) is the Laplace transform of f(t) and s is the Laplace variable.

Applying the Laplace transform to the ODE, we have sF(s) - f(0) + F(s) = 2/s + 1/(s - 1).

Since the initial condition is given as f(0) = 0, the equation becomes sF(s) = 2/s + 1/(s - 1).

Now, we can solve the algebraic equation for F(s):

sF(s) = 2/s + 1/(s - 1),

sF(s) = (2 + s - 1)/(s(s - 1)),

sF(s) = (s + 1)/(s(s - 1)),

F(s) = (s + 1)/(s(s - 1)).

Next, we need to find the inverse Laplace transform of F(s) to obtain the solution f(t) in the time domain. To achieve this, we can decompose the expression using partial fraction decomposition:

F(s) = A/s + B/(s - 1).

Multiplying both sides by s(s - 1), we have:

s + 1 = A(s - 1) + Bs.

Expanding and collecting like terms, we get:

s + 1 = As - A + Bs.

Equating coefficients of like terms, we find:

A + B = 1,   -A = 1.

Solving these equations, we obtain A = -1 and B = 2.

Therefore, F(s) = -1/s + 2/(s - 1).

Taking the inverse Laplace transform of F(s), we have:

f(t) = -1 + 2e^t.

Incorporating the initial condition f(0) = 0, we can determine the particular solution:

0 = -1 + 2e^0,

1 = 1.

Thus, the solution to the ODE f'(t) + f(t) = 2 + e with the initial condition f(0) = 0 is given by f(t) = -1 + 2e^t.


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Answer:

B = 10

I hope this helps!

Answer:

Step-by-step explanation:

25, i think

Answer:

The equation of the nth term of the sequence is 3n+9.

Step-by-step explanation:

The given problem is asking for a test to see if the sample mean is significantly different from 85 at the 0.05 level. To solve the problem, we can use the following formula:$$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$$where$\bar{x}$ = sample mean$\mu$ = population mean$s$ = sample standard deviation$n

$ = sample sizeTo calculate the t-value, we need to calculate the sample mean and the sample standard deviation. The sample mean is calculated as follows:$$\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}$$where $x_i$ is the score of the $i$th student and $n$ is the sample size.

Using the given data, we get:$$\bar

{x} = \frac{78+89+67+85+90+83+81+79}{8}

= 81.125$$The sample standard deviation is calculated as follows:$$

s = \sqrt{\frac{\sum_{i=1}^{n} (x_i - \bar{x})^2}{n-1}}$$Using the given data, we get:$$

s = \sqrt{\frac{(78-81.125)^2+(89-81.125)^2+(67-81.125)^2+(85-81.125)^2+(90-81.125)^2+(83-81.125)^2+(81-81.125)^2+(79-81.125)^2}{8-1}}

= 7.791$$Now we can calculate the t-value as follows:$$

t = \frac{\bar{x} - \mu}{\frac{s}

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Answer:

Step-by-step explanation:

yes

Answer:

⅔h – 5 = 11

Step-by-step explanation:

         h = babysitting hours last week

     ⅔h = two-thirds of those hours

⅔h - 5 = five hours fewer than two-thirds of those hours

⅔h – 5 = 11

The equation is ⅔h – 5 = 11.

Answer:

m = - 2

Step-by-step explanation:

( \(x_{1}\) , \(y_{1}\) )

( \(x_{2}\) , \(y_{2}\) )

m = \(\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\)

Answer:

true

Step-by-step explanation:

If $1.00 will buy 0.76 euros, then one euro will buy:

1 euro / 0.76 dollars/euro = 1.3158 dollars/euro

Rounded to the nearest cent, one euro will buy $1.32.

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Answer:

Samee

Step-by-step explanation:

Answer:

TIAGZ

and Billie Eilish

DABABY

Step-by-step explanation:

You are pushing a 40.0 kg crate across the floor. what force is needed to start the box moving from rest if the coefficient of static friction is 0.288?

The force needed to start the box moving from rest if the coefficient of static friction is 0.288 is 112.9 N.

Force is defined as an influence that causes an object to undergo a change in motion. Static friction: Static friction is a type of friction that must be overcome to start an object moving. The force needed to start the box moving from rest can be determined using the formula below:

Force of friction = Coefficient of friction × Normal force where: Coefficient of friction = 0.288

Normal force = Weight = mass × gravity (g) = 40.0 kg × 9.8 m/s² = 392 N

Force of friction = 0.288 × 392 N = 112.896 N (approx)

The force of friction is 112.896 N (approx) and since the crate is at rest, the force needed to start the box moving from rest is equal to the force of friction.

Force needed to start the box moving from rest = 112.896 N (approx) ≈ 112.9 N (rounded to one decimal place)

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Answer:

Milan puts 1/4 of her lawn-mowing money in savings and uses 1/2 of the remaining money to pay back her sister. If she has $15 left

Step-by-step explanation:

Step-by-step explanation:

Similar triangles

\( \frac{6}{uv } = \frac{8}{3} \)

uv=18/8

uv= 2.25