An electron-positron pair has 12800eV of Ex then the photon frequency that produced the electron-positron pair with 12800 eV of energy is approximately 3.10 x \(10^1^8\) Hz.
To determine the photon frequency that produced an electron-positron pair with 12800eV of energy, we can use the relationship between energy and frequency given by the equation:
E = hf
Where:
E is the energy of the photon,
h is Planck's constant (6.626 x J·s), and
f is the frequency of the photon.
First, we need to convert the energy from electron volts (eV) to joules (J). We know that 1 eV is equal to 1.602 x \(10^-^1^9\) J, so:
E = 12800 eV * (1.602 x\(10^-^1^9\) J/eV)
E = 2.05 x \(10^-^1^5\) J
Now, we can rearrange the equation to solve for the frequency:
f = E / h
f = (2.05 x \(10^-^1^5\)J) / (6.626 x \(10^-^3^4^\) J·s)
f ≈ 3.10 x \(10^1^8\) Hz
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c) An identical spring is pulled with a force or 75 N The elastie limit of the spring is 72N
Suate and explain whether or not the spring will return to its original shape.
Answer:
Spring cannot return to its original, since a part of its deformation is plastic, not elastic.
Explanation:
Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in elastic region, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.
Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is plastic, not elastic.
If a car has traveled 24 km in 2 hours, what is its average speed?
Answer:
12km per hour
Explanation:
The formula is distance/time.
24km/2 hours = 12km/1 hour
Explanation:
average speed = distance / time
= 24km/ 2 hr
= 12 km/ hr
Hope this will be helpful to you .
Assume the motions and currents mentioned are along the x axis and fields are in the y direction.(a) Does an electric field exert a force on a stationary charged object? Yes/No(b) Does a magnetic field do so? Yes/No
Yes, an electric field exerts a force on a stationary charged object. This is because the electric field is composed of electric lines of force that travel in a straight line and exert a force upon the stationary charged object.
The magnitude of the force depends on the strength of the electric field and the charge on the object. No, a magnetic field does not exert a force on a stationary charged object. This is because a magnetic field is composed of magnetic lines of force that travel in circles and therefore do not exert a force on a stationary object.
However, a magnetic field does exert a force on a moving charged object, such as a current-carrying wire. This force is known as the Lorentz force, which is a combination of both electric and magnetic forces.
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A cyclist bikes in a straight line at an average velocity of 22 miles/hour east and I’m finishing a 100 mile race how much time did it take her
Answer:
Below
Explanation:
To calculate the time it took for the cyclist to finish their race, you can you this equation :
time = displacement / velocity
Plug in your values....
time = (100 mi) / (22 mi/h)
= 4.54545454.... hours
As for sig figs in this question you would need to round this answer to 1 sig fig because 100 only has 1 sig fig. (you round to the lowest # of sig figs in the question)
= 5 hours
It took the cyclist 5 hours to complete their race
Hope this helps! Best of luck <3
A physics student spins a bucket of water over her head in a circular path in order to demonstrate centripetal force. She fills the bucket half-full with water first, and then empties out half of its contents (so that the bucket is a quarter-full) for her next trial. In which case is more force required to spin the bucket, and why? Explain using relevant force equation(s).
Answer:
The first case requires more force to spin de bucket.
Explanation:
As we know, the centripetal force is directly proportional to the mass, the equation is given by:
\(F_{c}=ma_{c}\)
The first case has a quarter more water than the second case, therefore the first case requires more force to spin de bucket.
I hope it helps you!
A box of books weighing 325 N is shoved across the floor by a force of 475 N exerted downward at an angle of 35° below the horizontal. (a) If ????k between the box and the floor is 0. 55, how long does it take to move the box 5. 80 m starting from rest? s (b) What is the maximum coefficient of friction between the box and the floor that allows the box to move from this applied force.
The net forces on the box acting perpendicular and parallel to the floor are
∑ F[perp] = F[normal] - 325 N + (475 N) sin(-35°) = 0
∑ F[perp] = (475 N) cos(-35°) - F[friction] = ma
where m is the mass of the box and a is its acceleration.
Solve for F[normal] :
F[normal] = 325 N + (475 N) sin(35°) ≈ 597 N
Then the frictional force has magnitude
F[friction] = 0.55 F[normal] ≈ 329 N
and so
60.5 N ≈ (325 N) a/g
(note that sin(-35°) = -sin(35°), cos(-35°) = cos(35°), and mg = 325 N so m = (325 N)/g)
Solve for a :
a = (60.5 N) / (325 N) g ≈ 1.82 m/s²
(a) Assuming this acceleration is constant, starting from rest, the box achieves a final velocity v such that
v² = 2a∆x
v² = 2 (1.82 m/s²) (5.80 m)
⇒ v ≈ 4.60 m/s
which happens in time t such that
v = at
4.60 m/s = (1.82 m/s²) t
⇒ t ≈ 0.177 s
(b) Let µ be the coefficient of static friction. The box just begins to slide if the magnitude of the parallel component of the applied force matches the magnitude of friction, i.e.
∑ F[para] = (475 N) cos(-35°) - F[friction] = 0
We have
F[friction] = µ F[normal] = (597 N) µ
so that
(597 N) µ = (475 N) cos(35°)
⇒ µ ≈ 0.651
Date: 09/10/2022
What is the equation to finding time using acceleration..
Is it:
T = V - U / A
——————————
Answer:
yes it's the right answer...............
Which table is it I’ll mark brainlest
Answer:
we need the graph to answer the question.
The work function for platinum is 6.35 eV . Ultraviolet light of wavelength 150 nm is incident on the clean surface of a platinum sample. We wish to predict the stopping voltage we will need for electrons ejected from the surface. (d) What stopping voltage would be required to arrest the current of photoelectrons?
we can conclude that a stopping voltage of -6.26183 eV is not applicable in this case.
To predict the stopping voltage required to arrest the current of photoelectrons, we can use the equation:
stopping voltage = energy of incident photons - work function
1. First, let's convert the wavelength of the incident light from nanometers (nm) to meters (m). We have a wavelength of 150 nm, which is equivalent to 150 × 10^-9 meters.
2. Next, we need to calculate the energy of the incident photons using the equation:
energy = (Planck's constant × speed of light) / wavelength
Substituting the given values:
energy = (6.626 × 10^-34 J·s × 3 × 10^8 m/s) / (150 × 10^-9 m)
3. Calculate the energy of the incident photons.
energy = 0.08817 eV
4. Now, we can determine the stopping voltage using the formula:
stopping voltage = energy of incident photons - work function
Substituting the values:
stopping voltage = 0.08817 eV - 6.35 eV
5. Calculate the stopping voltage.
stopping voltage = -6.26183 eV
Since a negative voltage value doesn't make physical sense in this context, we can conclude that a stopping voltage of -6.26183 eV is not applicable in this case.
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WHATS THE ANSWER HELP!!
5m I think,maybe, not a 100% sure die
Answer:
5m i think
Explanation:
WHATS THE ANSWER HELP!!
how does the current through a wire change if the wires resistance is increased? Explain why this is so?
The current through a wire change if the wires resistance is increased in the following ways;
The length of the wires will affect the amount of resistance. The longer the wire, the more resistance.The cross-sectional area of the wires also affects the amount of resistance. Wider wires have a greater cross-sectional area which affects the resistance.The material of the wire also affect the resistance to charge flow. The measurement of the conducting ability of a material is called resistivity.Relationship between Resistance and cross section of wireThe relationship between resistance and the area of the cross section of a wire is inversely proportional. Resistance also depends on the material of the conductor.
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024 (part 1 of 3) 10.0 points
A 2.0 kg block is pushed 3.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 29.0° with the horizon-
tal, as shown in the figure.
The acceleration of gravity is 9.81 m/s².
2 kg
3 m
29°
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
Answer in units of J.
The work was done by the force on the block of 2 kg with an acceleration gravity of 9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.
What is work done?When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.
To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.
Given:
The mass, m = 2 kg,
The acceleration, g = 9.81 \(m/s^2\),
θ = angle between block and surface kinetic friction = μ
Calculate the work done by the formula given below,
\(W_{fy}\) = F sinθ
\(W_{fy}\) = (\(mgsin\)θ)/ (sinθ - μ * cosθ)
Substitute the values
\(W_{fy}\) = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)
\(W_{fy}\) = 42.83 J
Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of 9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.
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a rock has a mass of 14,826 grams. what is the rocks mass in kilograms
Answer:
14.826 kg
Explanation:
move the decimal at the end over to the left 3 times
Answer: 14.826
Explanation: Because if you It also means 1 kilogram and 1000 grams are defined as being equal.Stephanie did 55 Joules of work when she lifted her cat 5 meters up a flight of stairs. How much force did she use to lift her cat?
A yacht can sail at a maximum speed of 150 kilometersperhour. It is sailing from Key West toward the Bahamas at half of its top speed. If its velocity remains constant, how far will the yacht sail in 2hours?
Answer:
150 km
Explanation:
It has a maximum speed of 150 km/h, and it sails at half its top speed, so it sails at 75 km/h. If it remains constant for 2 hours, it will have gone 150km.
how far from the mirror must an object be placed to create an upright image three times the height of the object?
The object must be placed at a distance of one-third (1/3) of the focal length from the mirror to create an upright image three times the height of the object.
The distance between the mirror and the object is determined by the magnification of the image formed. It is possible to determine the distance between the object and the mirror by using the formula for magnification.
Formula to calculate the distance between the object and the mirror:
Magnification = -Image distance / Object distance
Magnification, m = 3 (upright image)
Object distance, u = ?
Image distance, v = negative (-v)
Therefore, the formula for magnification can be rearranged as follows:
u = -v / m
To find the distance between the mirror and the object, substitute the given values into the formula. The solution is as follows:
u = -v / mu = -v / 3
Hence, if the magnification is 3, and the object is placed at a distance of 'u' from the mirror, then the image would be formed at a distance of 'v' = -3u (negative sign implies virtual image).
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1. Why are the outer planets called “gas planets?”
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Explanation:
i hope this helps :)
Which slider makes the height of the wave decrease at it travels?
The slider that controls the height of the wave is typically labeled as "amplitude" or "height".
Adjusting this slider will either increase or decrease the height of the wave. If you want the height of the wave to decrease as it travels, you may need to use a more advanced tool or software that allows you to adjust the shape of the wave. This can be done by manipulating the wave's frequency, wavelength, and phase, among other properties.
amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
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A 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. Answer the following questions. In your explanations, address the fact that the marbles have different masses and. different speeds. [1] (a) Which marble hits the ground first and why? (b) Which marble travels farther and why?
(a) It can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) Both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
According to the given statement, a 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. The questions to answer are as follows:
(a) The acceleration due to gravity is constant at 9.8 m/s², according to Newton's Law of Gravitation.
According to the law of physics, heavier objects fall faster than lighter ones, but since the 10-gram marble has a speed that is five times faster than the 100-gram marble, it implies that the 10-gram marble covers more ground in less time than the 100-gram marble as acceleration is directly proportional to the force applied.
The time taken by both marbles to reach the ground is given byt = √(2h/g)where h is the height from which the marbles were dropped, and g is the acceleration due to gravity.
The height from which the marbles were dropped is the same in both cases, so it can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) The range traveled by both marbles is determined by the horizontal component of their velocity. It's worth noting that the horizontal components of their velocities are identical since they were launched from the same height, so there's no advantage for either marble.
The range of a projectile is determined by the formula:
R = u²sin(2θ)/g where R is the range, u is the velocity of the object, θ is the angle of the initial velocity with the horizontal, and g is the acceleration due to gravity.
Since the angle of the initial velocity with the horizontal is the same for both marbles, and their initial velocity is also the same, it can be stated that both marbles travel the same distance.
Therefore, both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
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When 18(O)is struck by a proton, 18(F) and another particle
are produced. The reaction has a Q value of -2.453 MeV, and the atomic mass of 18(O) is 17.999 160 u. What is the atomic mass of 18(F)
Answer:
Explanation:
As per the given information, 18(O) is struck by a proton, and 18(F) and another particle are produced. The reaction has a Q value of -2.453 MeV, and the atomic mass of 18(O) is 17.999 160 u.
We have to find the atomic mass of 18(F). The Q value of a nuclear reaction can be given as Q = (Mi - Mf - Mp) × c²WhereQ = Q
value of the nuclear reaction = initial massMf = final massMp = mass of the projectile = speed of light
The Q value of the given nuclear reaction is -2.453 MeV. Since we know the initial mass (Mi) and the mass of the projectile (Mp), we can calculate the final mass (Mf) as follows: Mf = Mi - Mp - (Q / c²)Now, let's calculate the final mass of 18(F).
Initial mass (Mi) = mass of 18(O) = 17.999 160 UMass of the projectile (Mp) = mass of a proton = 1.007 825 uQ value (Q) = -2.453 MeVSpeed of light (c) = 2.998 × 10⁸ m/sMf = 17.999 160 u - 1.007 825 u - (-2.453 MeV / (2.998 × 10⁸ m/s)²)Mf = 18.000 674 therefore, the atomic mass of 18(F) is 18.000 674 u.
A bus starts from rest.if the acceleration is 2m/s square, find
i.the distance travelled
ii.the velocity after 2 seconds.
Answer:
The velocity after 2 seconds can be found through:
V = u +a*t
Where V is final velocity, u is initial velocity, a is acceleration and t is time.
V = 0 + 2* 2= 4 meters/second
The distance (s) can be found through:
V^2= u^2 +2*a* s
Where V is final velocity, u is initial velocity, a is acceleration.
4^2= 0^2 + 2 *2*s
16= 0 + 4s
s= 4 meters
Distance (s) can also be found through:
s= ut + 1/2 at^2
s= 0+ 1/2 *2*2^2= 1 *2*2
s= 4 meters
Explanation:
Measure the value of the radius of curvature and deduce the value of the focal length.
The radius of curvature is observed to be equal to twice the focal length for spherical mirrors with small apertures. Hence R = 2f.
Does focal length increase with a radius of curvature?As the radius of curvature for a lens grow (R2 > R1), the curvature of the lens decreases, and the focal length of the lens expands (f2 > f1) We can say clearly that the main focus of a spherical mirror lies at the core between the center of curvature and the pole.
the radius of curvature becomes longer the circle gets larger. As the circle gets larger, its curve gets praised, as the curve gets admired on a clear material Focal length of a lens depends on the deform index of the glass from which it is built, and on the curvature of its two surfaces.
So we can conclude that the result of a radius of curvature on the focal length of a convex lens.
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A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
car travel 3km due north then 5km east represent these displacement graphically and determine the resultant displacement
5.83 N-E will be displacement when car travel 3km due north then 5km east.
the resultant displacement =\(\sqrt{3^2+5^2}\)
= 5.83 N-E
Being a vector quantity, displacement has both a magnitude and a direction. The vector (or straight line) distance between an initial and final position is what is meant by this term. Knowing these two places is consequently all that is necessary to determine the resultant displacement.
Calculate the inverse tangent of the ratio of the displacement components in the y- and x-directions to determine the direction of the displacement vector.
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the above graph shows______
A. changing acceleration
B. direction and speed
C. speed and distance traveled
D.speed and velocity
the reason a moving object slows down is that its force of motion gradually runs out. true false
The reason a moving object slows down is that its force of motion gradually runs out is false.
If no unbalanced force applies to an object, its momentum stays constant. According to Newton's Second Law, if an object is subjected to an unbalanced force, it will move with a constant speed.
What does momentum actually mean?
The product of a particle's mass and velocity is momentum. Momentum is a vector quantity that has both magnitude and direction. The force exerted on a particle is equated to the time rate of change of momentum by Isaac Newton's second equation of motion.
What does the word "momentum" mean?
illustration of momentum
whenever you throw a ball at a person and it hits him in the face. It shows how challenging it would have been to put a stop to the situation. In the air, a baseball is swooping. There is a big truck moving. a gun of this type shot a bullet.
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A particular light source gives off light waves with a measured wavelength of
2. 0 X 10-7 m. What is the frequency of the light source?
a. ) 6. 67 X 10-15 Hz
b. ) 6. 0 X 1011 Hz
c. ) 1. 5 X 1015 Hz
d. ) Not enough information
The frequency of the light source is 1.5 x 10¹⁵ Hz.
Frequency of the light sourceThe frequency of the light source is determined using the following equations;
c = fλ
where;
c is speed of light
f is the frequency
λ is the wavelength
f = (3 x 10⁸) / (2 x 10⁻⁷)
f = 1.5 x 10¹⁵ Hz
Thus, the frequency of the light source is 1.5 x 10¹⁵ Hz.
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Which of these neutron stars must have had its angular momentum changed by a binary companion? (a) a pulsar that pulses 30 times per second (b) a pulsar that pulses 600 times per second (c) a neutron star that does not pulse at all.
The neutron star that pulses 600 times per second must have had its angular momentum changed by a binary companion.
Neutron stars that pulse are known as pulsars and their pulses are caused by their rotation. The rate of pulsation is directly related to the neutron star's angular momentum. A pulsar that pulses faster must have a smaller radius and higher angular velocity than a pulsar that pulses slower.
Therefore, a pulsar that pulses 600 times per second must have a very small radius and high angular velocity, which can only be achieved by a change in its angular momentum. The most likely cause of this change in angular momentum is a binary companion transferring angular momentum to the pulsar.
In conclusion, a neutron star that pulses 600 times per second is the one that must have had its angular momentum changed by a binary companion.
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c. If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, what is the net force on the box?
According to the data given in the question the net force on the box is of 5 N.
What does net force mean?All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.
Given data :
Force on box to the left side (F1) = 15 N
Force on box to the right side (F2) = 20 N
Because both forces are in opposite direction
Hence,
Net force = F2 - F1
Net force = 20 - 15
Net force = 5 N.
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A mother is helping her children, of unequal weight, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child simply sinking to the ground. Given that her heavier child of weight W is sitting a distance L to the left of the pivot, at what distance L1 must she place her second child of weight w on the right side of the pivot to balance the seesaw?
Express your answer in terms of L, W, and w.
L1= ?
Now consider this problem as a more formal introduction to torque. The torque of each child about the pivot point is the product of the child's weight and the distance of the child (strictly speaking, the child's center of mass) from the pivot. The sign of the torque is positive if it would cause a counterclockwise rotation of the seesaw. The distance is measured perpendicular to the line of force and is called the moment arm.
The concept of torque requires both a force and a specification of the pivot point, emphasized by the first subscript on the torque.
Part B
Find ?p,w, the torque about the pivot due to the weight w of the smaller child on the seesaw.
Express your answer in terms of L1 and w.
Tp,w???
The children's mother wants the seesaw to balance, which means that there can be no angular acceleration about the pivot. The balanced seesaw will then be in equilibrium since it has neither linear acceleration nor rotational acceleration.
For the linear acceleration to be zero, the vector sum of forces acting on the seesaw and children must equal zero.
For the angular acceleration to be zero, the sum of the torques about the pivot must equal zero. This can be written
?i?p,i=0,
where ?p,i is the torque about the pivot due to the i th force.
Part C
Determine ?i?p,i, the sum of the torques on the seesaw. Consider only the torques exerted by the children.
Express your answer in terms of W, w, L, and L1.
The child with weight w has an identical twin also of weight w. The two twins now sit on the same side of the seesaw, with one twin a distance L2 from the pivot and the other a distance L3. (Figure 2)
Part D
Where should the mother position the child of weight W to balance the seesaw now?
Express your answer in terms of L2, L3, W, and w. L=????
Bad news! When the mother finds the distance L from the previous part it turns out to be greater than Lend, the distance from the pivot to the end of the seesaw. Hence, even with the child of weight W at the very end of the seesaw the twins exert more torque than the heavier child does. The mother now elects to balance the seesaw by pushing sideways on an ornament (shown in red) that is a height h above the pivot. (Figure 3)
Part E
With what force in the rightwards direction, Fx, should the mother push? Note that if you think the force exerted by the mother should be toward the left, your final answer Fx should be negative.
Express your answer in terms of W, Lend, w, L2, L3, and h.
Fx= ????
The distance L1 that the mother must place her second child of weight w on the right side of the pivot to balance the seesaw is (WL)/(W+w).
To balance the seesaw, the torques on both sides of the pivot must be equal. The torque due to the heavier child is W*L, and the torque due to the smaller child is w*L1. Therefore, to balance the seesaw, we need to have W*L = w*L1, which gives us L1 = (W*L)/(W+w).
For part B, the torque about the pivot due to the weight w of the smaller child is w*(Lend-L1), since the moment arm is the distance between the pivot and the child's position.
For part C, the sum of the torques on the seesaw is given by W*L - w*L1, since the torque due to the heavier child is positive and the torque due to the smaller child is negative.
For part D, the mother should position the child of weight W at a distance L from the pivot, where L = (w*L2 + w*L3)/(W+2w).
For part E, the mother should push with a force of Fx = (W+w)*g*h/(Lend - L1), where g is the acceleration due to gravity.
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