80.8 is 40 2/5 % of (Simplify your answer) N

9514 1404 393

Answer:

  (b)  2×3

Step-by-step explanation:

You want to factor the number so that the factors are primes. Divisors of 6 are 1, 2, 3, 6, so we can factor the number as either of 1×6 or 2×3. The factors 2 and 3 are both prime. The factorization you want is ...

  6 = 2×3

_____

Additional comment

We know 1 is not a prime number, so we're not interested in any factorization that has 1 as a factor.

Answer:

True

Step-by-step explanation:

Answer: True

Step-by-step explanation:

Because its a 50/50 and

Hey there!

4 quarters = 1 dollar

To find how many quarters are in 20 dollars, we multiply 4 by 20

⇒ 4 × 20

⇒ 80

Therefore, 80 quarters are in 20 dollars

Answer:

1/10

Step-by-step explanation:

1/2= 5/10 - make it an equivalent fraction with the same denominator as the other fraction.

3/5= 6/10

5/10-6/10- subtract

=1/10

Angie decorates 8 cupcakes after putting 4 sugar flowers on each cupcake.

To find the number of cupcakes c Angie decorates, we can use the equation:4c = 32where 'c' is the number of cupcakes Angie decorates.

4 represents the number of sugar flowers Angie puts on each cupcake, and 32 is the total number of sugar flowers Angie puts on the cupcakes.

To solve this equation for c, we need to isolate c on one side of the equation. We can do this by dividing both sides of the equation by 4. This gives us:c = 8

Therefore, Angie decorates 8 cupcakes.Here's how we get to this answer:4c = 32Divide both sides by 4 to isolate c:c/4 = 32/4c = 8

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The value of length BC is 18.9

Cosine Rule states that the square of the length of any side of a given triangle is equal to the sum of the squares of the length of the other sides minus twice the product of the other two sides multiplied by the cosine of angle included between them.

Therefore,

c² = a² + b² - 2abcosC

To find the length BC we use cosine rule.

c² = 13² + 7² - 2(13)(7)cos140

c² = 218 - 182cos140

c² = 218-(-139.42)

c² = 218+139.2

c² = 357.2

c = √357.2

c = 18.9

Therefore, the length of BC is 18.9

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In the triangle, the value of the side BC is 18.9cm to 1 decimal place

The side BC can be found using the cosine formula, Remember that Cosine Rule states that the square of the length of any side of a given triangle is equal to the sum of the squares of the length of the other sides minus twice the product of the other two sides multiplied by the cosine of angle included between them.

The cosine formula states that

c² = a² + b² - 2abcosC

To find the length BC we use cosine rule.

c² = 13² + 7² - 2(13)(7)cos140

c² = 218 - 182cos140

c² = 218-(-139.42)

c² = 218+139.2

c² = 357.2

c = √357.2

c = 18.9

In conclusion, the value of  the length of BC is 18.9cm

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Given:

Mean,

\(\mu = 300,000\)

Standard deviation,

\(\sigma = 50,000\)

The Chebyshev theorem will be used for the solution of the given query,

i.e., \(P(|X - \mu| < k \sigma ) \geq 1-\frac{1}{k^2}\)

(i)

⇒ \(1-\frac{1}{k^2} = 0.75\)

            \(k = 2\)

The lower limit will be:

= \(\mu - k \sigma\)

= \(300000-2\times 50000\)

= \(200000\)

The upper limit will be:

= \(\mu + k \sigma\)

= \(300000+2\times 50000\)

= \(400000\)

hence,

The 75% houses sold are between:

⇒ (200000, 400000)

(ii)

⇒ \(\mu -k \sigma = Lower \ limit\)

By putting the values, we get

   \(300000-50000k = 150000\)

   \(300000-150000=50000k\)

                  \(150000=50000k\)

                           \(k=\frac{150000}{50000}\)

                              \(=3\)

now,

⇒ \(1-\frac{1}{k^2} = 1-\frac{1}{3^2}\)

              \(=\frac{8}{9}\)

              \(=0.8888\)

              \(=88.88\) (%)

hence,

88.88% houses sold between 150000 and 450000.      

(iii)

⇒ \(\mu - k \sigma = Lower \ limit\)

By putting the values, we get

   \(300000-50000k = 170000\)

   \(300000-170000=50000 k\)

                  \(130000= 50000 k\)

                          \(k = \frac{130000}{50000}\)

                             \(=2.6\)

now,

⇒ \(1-\frac{1}{k^2} = 1-\frac{1}{2.6^2}\)

              \(=0.8521\)

              \(=85.21\) (%)

hence,

85.21% houses are sold between 170000 and 430000.

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Consider the continuous random variable x that has a uniform distribution over the interval from 40 to 44. The variance of 'x' is approximately C: 1.155.

The variance of a continuous uniform distribution over the interval [a, b] is determined by the formula given as follows:

Var(x) = (b-a)^2 / 12

For the given distribution, a = 40 and b = 44, so the variance is calculated by putting these values into the above formula:

Var(x) = (44 - 40)^2 / 12 = 1.155

Therefore, the variance of 'x' is approximately 1.155

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Answer:

A prime number is a number with exactly two factors. A prime number is only divisible by 1 and itself. Another way to think of prime numbers is that they are only ever found as answers in their own times tables.

Step-by-step explanation:

Answer:

Prime no.

Step-by-step explanation:

A number that only has two factors [ 1 and itself] is called a prime no.

For ex:

The factors of 2 are: 1,2

The factors of 3 is : 1,3

But if you look at the factors of 6, there are; 1,2,3,6 [ 4 FACTORS]

Thus, 6 is a composite no. [Has more than 2 factors]

Answer:

Step-by-step explanation:

Answer:

you see

Step-by-step explanation:

The chemist uses 3.33 liters of 30% solution to make 5 liters of a 40% chemical solution

An equation is an expression composed of variables and numbers linked together by mathematical operations.

Let x represent amount of 60% solution and y represent the amount of 30% solution.

If a chemist wants to make 5 liters of a 40% chemical solution by mixing a 60% solution with a 30% solution. Hence:

x + y = 5    (1)

Also:

0.6x + 0.3y = 5(0.4)

0.6x + 0.3y = 2    (2)

From both equations:

x = 1.67, y = 3.33

The chemist uses 3.33 liters of 30% solution

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Answer:

1/5

Step-by-step explanation:

the two points are(7,5) and (2,4)

let,(x1,y1)=(7,5) and (x2,y2)=(2,4)

slope (m)=y2-y1/x2-x1

=4-5/2-7

=-1/-5

=1/5(minus ,minus are cut)

Answer:

y=2x+6

Step-by-step explanation:

Therefore, the solutions to the equation 0 = |3x + 3| + 3 are x = -2 and x = 0.

To solve the equation 0 = |3x + 3| + 3, we need to eliminate the absolute value. Remember that the absolute value of a number is always non-negative.

First, let's isolate the absolute value term on one side of the equation:

|3x + 3| = -3

Since the absolute value cannot be negative, there are no solutions to the equation as it stands. However, if we modify the equation to make the right side positive, we can find a solution.

To eliminate the absolute value, we can rewrite the equation as two separate equations, considering both the positive and negative cases:

   3x + 3 = -3

   -(3x + 3) = -3

Solving equation 1:

3x + 3 = -3

3x = -6

x = -2

Solving equation 2:

-(3x + 3) = -3

-3x - 3 = -3

-3x = 0

x = 0

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Answer:

Cooking., You either end up with great food because you measured the and use the right amount of ingredients or food that isn't the best because you used too little or too much ingredients.

Bonus) For Time Management, it involves math by scheduling activities and other things such things in life at certain times and some things should be met within certain time limits and such.

Answer: Hi!

Shopping! When you're shopping in a store, you have to calculate and estimate the prices of food and items in your head, (or on paper), so you know the total amount of money you are going to use. Many times the amount of money for an item is a fraction, too!

Hope this helps!

After answering the presented question, we can conclude that expressions Therefore, the population of the rural city in 2030 is approximately 11,014.18.

In mathematics, you can multiply, divide, add, or subtract. An expression is constructed as follows: Number, expression, and mathematical operator A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to contrast expressions and phrases. An expression or algebraic expression is any mathematical statement that has variables, integers, and an arithmetic operation between them. For example, the expression 4m + 5 has the terms 4m and 5, as well as the provided expression's variable m, all separated by the arithmetic sign +.

To approximate the population in 2030, we need to find the value of P(t) when t = 44, since 2030 is 44 years after 1986.

Using the given exponential growth model, we have:

\(P(t) = 3400^(0.0371t)\\P(44) = 3400^(0.0371*44)\\P(44) = 3400^1.6334\\P(44) = 11014.18\\\)

Therefore, the population of the rural city in 2030 is approximately 11,014.18.

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Based on the information provided, the missing number would be number 6.

When it comes to finding missing numbers, the first step is to decipher or identify the pattern. This can be either a sequence of numbers or the application of a specific mathematical operation such as subtraction or addition.

In this case, we can see there is a sequence of numbers that seems to go from 1 to 9. However, if you check carefully, the number 6 is missing, which is the number you need to add.

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Answer:

30 times three

Step-by-step explanation:

because all the bottom number are multiplying buy three.

Answer:

this is not belongs to mathematics

Step-by-step explanation:

Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

Answer:

A

Step-by-step explanation:

For a right triangle

\(A=\frac{ab}{2} \\\frac{(10.4)(15.3)}{2} =79.56\)

This is the same as the other triangle because they are the same size because of congruency

Area of the rectangle

\(a^2+b^2=c^2\\\)

\(\sqrt{(10.4^2+15.3^2} =c\)

\(c= 18.5\)

18.5 x 7 = 129.5

Add them all up

129.5+79.56+79.56= 288.62

Answer:

-18 is your answer

Step-by-step explanation:

To check is -18 is the right answer or not, you can just multiply -18 and -3.1 which should equal up to 55.8

The expression that is equivalent to StartRoot \(8 x^7 y^8\) EndRoot is (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2.

To understand why this is the case, let's break down each expression and simplify them step by step:

StartRoot \(8 x^7 y^8\) EndRoot:

We can rewrite 8 as \(2^3\), and since the square root can be split over multiplication, we have StartRoot \((2^3) x^7 y^8\) EndRoot. Applying the exponent rule for square roots, we get StartRoot \(2^3\) EndRoot StartRoot \(x^7\) EndRoot StartRoot \(y^8\) EndRoot.

Simplifying further, we have 2 StartRoot \(2 x^3 y^4\) EndRoot StartRoot \(2^2\) EndRoot StartRoot \(x^2\) EndRoot StartRoot \(y^4\) EndRoot. Finally, we obtain 2 \(x^3 y^4\) StartRoot 2 x EndRoot, which is the expression in question.

(\(2 x y^2\) StartRoot 8 x^3 EndRoot)^2:

Expanding the expression inside the parentheses, we have \(2 x y^2\)StartRoot \((2^3) x^3\) EndRoot. Applying the exponent rule for square roots, we get \(2 x y^2\) StartRoot \(2^3\) EndRoot StartRoot \(x^3\) EndRoot.

Simplifying further, we have \(2 x y^2\) StartRoot 2 x EndRoot. Squaring the entire expression, we obtain (\(2 x y^2\) StartRoot 2 x EndRoot)^2.

Therefore, the expression (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2 is equivalent to StartRoot \(8 x^7 y^8\) EndRoot.

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Answer:

Reject H0 ; and conclude that call length does not follow a normal distribution.

Step-by-step explanation:

Given :

The hypothesis :

H0: Call lengths outside normal customer roaming areas follows normal distribution

H1: Call lengths outside normal customer roaming areas do not follows normal distribution

Mean, μ = 14.3

Standard deviation, σ = 3.7

From the frequencies Given :

Expected values can be calculated :

Observed values :

16, 75, 139, 105, 37, 18 ; Total = 400

P(Z < (x - μ) / σ)) * total frequency

x = frequency

For x = 5 ;

P(Z < (5 - 14.3) / 3.7)) * 400 = 2.391

For x = 10;

P(Z < (10 - 14.3) / 3.7)) * 400 = 46.644

For x = 15;

P(Z < (15 - 14.3) / 3.7)) * 400 = 180.960

For x = 20;

P(Z < (20 - 14.3) / 3.7)) * 400 = 145.32

For x = 25;

P(Z < (25 - 14.3) / 3.7)) * 400 = 23.92

For x = 30;

P(Z < (30 - 14.3) / 3.7)) * 400 = 0.766

χ² = Σ(O - E)²/E

O = observed values

E = Expected values

χ² = (26-2.391)^2 / 2.391 + (75-46.644)^2 / 46.644 + (139-180.96)^2 / 180.96 + (105-145.32)^2 / 145.32 + (37-23.92)^2 / 23.92 + (18-0.766)^2 / 0.766 = 666.17

χ² = 666.17

The critical value "; df = n - 1= 6-1 = 5

α = 0.05

χ²critical(0.05 ; 5) = 11.07

χ²statistic > χ²critical ; Reject the Null, H0 ; and conclude that call length does not follow a normal distribution.

Answer:

\(y = - \frac{3}{2} x + 3\)

slope is -3/2, y-intercept is 3.

Step-by-step explanation:

\(m = \frac{ - 3 - 6}{4 - ( - 2)} = \frac{ - 9}{6} = - \frac{3}{2} \)

\(6 = - \frac{3}{2} ( - 2) + b\)

\(6 = 3 + b\)

\(b = 3\)

\(y = - \frac{3}{2} x + 3\)