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Answer:

Arc BC = 117°

Step-by-step explanation:

Angle D is an inscribed angle that intercepts arc ABC. According to the Inscribed angle theorem of a circle, m<D = ½ of arc ABC.

Thus,

104° = ½(AB + BC)

104° = ½(91° + BC)

Multiply both sides by 2

104*2 = 91 + BC

208 = 91 + BC

Subtract both sides by 91

208 - 91 = BC

117 = BC

Arc BC = 117°

As the interest rate increases from 10 percent to 11 percent, the present value of the bond decreases from $1,074.47 to $1,058.31. Conversely, when the interest rate decreases to 9 percent, the present value increases to $1,091.19. This is because the discount rate used to calculate the present value is inversely related to the interest rate, meaning that as the interest rate increases, the present value decreases, and vice versa.

To compute the present value of a five-year, 10 percent coupon bond with a face value of $1,000, we need to discount the future cash flows (coupon payments and face value) by the appropriate interest rate.

Step 1: Calculate the present value of each coupon payment.
Since the bond has a 10 percent coupon rate, it pays $100 (10% of $1,000) annually. To calculate the present value of each coupon payment, we need to discount it by the interest rate.

Using the formula: PV = C / (1+r)^n
Where PV is the present value,

C is the cash flow,

r is the interest rate, and

n is the number of periods.

At an interest rate of 10 percent, the present value of each coupon payment is:
PV1 = $100 / (1+0.10)^1 = $90.91

Step 2: Calculate the present value of the face value.
The face value of the bond is $1,000, which will be received at the end of the fifth year. We need to discount it to its present value using the interest rate.

At an interest rate of 10 percent, the present value of the face value is:
PV2 = $1,000 / (1+0.10)^5 = $620.92

Step 3: Calculate the total present value.
To find the present value of the bond, we need to sum up the present values of each coupon payment and the present value of the face value.
Total present value at an interest rate of 10 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,074.47

When the interest rate goes to 11 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 11 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,058.31

When the interest rate goes to 9 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 9 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,091.19

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Answer:

B

Step-by-step explanation:

(hx)(gx)

(2x+5)(3x+2)

6\(x^{2}\)+4x+15x+10

6\(x^{2}\)+19x+10

Answer B

Answer:

a) Option A is correct.

b) Option B is correct.

Step-by-step explanation:

\(a) \: \: 5 \times a \\ = 5a\)

\(b) \: \: b \times b \\ = {b}^{2} \)

Answer:

thats crazy man

Step-by-step explanation:

False. The expected cell frequency in statistical analysis, specifically in the context of contingency tables and chi-square tests, is not based on the researcher's opinion. Instead, it is determined through mathematical calculations and statistical assumptions.

In contingency tables, the expected cell frequency refers to the expected number of observations that would fall into a particular cell if the null hypothesis of independence is true (i.e., if there is no relationship between the variables being studied). The expected cell frequency is calculated based on the marginal totals (row totals and column totals) and the overall sample size.

The expected cell frequency is computed using statistical formulas and is not influenced by the researcher's opinion or subjective judgment. It is a crucial component in determining whether the observed frequencies in the cells significantly deviate from what would be expected under the null hypothesis.

By comparing the observed cell frequencies with the expected cell frequencies, statistical tests like the chi-square test can assess the association or independence between categorical variables in a data set.

Thus, the statement "the expected cell frequency is based on the researcher's opinion" is false. The expected cell frequency is derived through statistical calculations and is not subject to the researcher's subjective input.

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The equation of the line that passes through the point (2, 1) and has a slope of -5/2 is y=(-5/2)*x+6.

An equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=3x+4. Where:

m= the slope.

b= the constant term that represents the y-intercept.

For the given example: m=3 and b=4.

The question gives:

Point : (2,1) , where x=2 and y=1

Slope= -5/2

From the  standard form of the linear equation ( y= mx+b) and the given point and the slope, you can write:

y=mx+b

1=-5/2*(2)+b , thus you can find b.

1=-5+b

-b=-5-1

-b=-6

b=6

If b=6 and m=-5/2, you can write the linear equation:

y=mx+b

y=(-5/2)*x+6

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The equation of line that models this is y = -5/2x + 6

The equation of a line is typically written in slope-intercept form, which is y = mx + b, where m is the slope of the line, and b is the y-intercept.

The slope (m) is a measure of how steep the line is, and it can be calculated using the formula:

y = mx + c

In the given question, the slope is -5/2 and the points are (2, 1)

Substituting the values into the formula of equation of line;

y = mx + c

1 = -5/2(2) + c

1 = -5 + c

c = 1 + 5

c = 6

The equation is y = -5/2 + 6

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Answer:

90% correct

Step-by-step explanation:

You want to make calculating easy and to do this, you multiply write out 18 out of 20 like a fraction, 18/20, and multiply both the numerator and the denominator by 5 because 20*5 = 100. 18*5 = 90. 90/100 is the same thing as 90%. Hope this helps!

The forward premium on the dollar based on the indirect quotation is -1.91%.

Given that the spot rate is 0.9574 €/$ and the 2-month forward rate is 0.9391 €/$.

We are to determine the forward premium on the dollar based on the indirect quotation.

Let's calculate the forward premium on the dollar below;

Forward premium on dollar = (Forward rate - Spot rate)/Spot rate× 100%.

Substitute the known values in the above formula:

Forward premium on dollar = (0.9391 - 0.9574)/0.9574× 100%.

Forward premium on dollar = (-0.0183)/0.9574× 100%.

Forward premium on dollar = -0.0191× 100%.

Forward premium on dollar = -1.91%.

Therefore, the forward premium on the dollar based on the indirect quotation is -1.91%.

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Answer:

21 miles

Step-by-step explanation:

she rod 3.5 hours total,

3.5 * 6

Answer:

Step-by-step explanation:

Given:

Total distance during weekend:

1. The speed-density relationship given by U = 60(1 - 0.007k) allows us to determine the free flow speed and jam density. In this equation, U represents the speed, and k represents the density.

Substituting k = 0 into the equation, we get U = 60(1 - 0.007(0)) = 60 units. Hence, the free flow speed is 60 units. To determine the jam density, we set the speed, U, to zero and solve for k. Setting U = 0 in the equation, we have 0 = 60(1 - 0.007k). Simplifying, we find 1 - 0.007k = 0. Dividing both sides by 0.007, we obtain k = 1/0.007 ≈ 142.86 units. Thus, the jam density is approximately 142.86 units.

2. The relationship describing flow (Q) versus speed (U) and density (k) can be derived from the speed-density relationship and is given by Q = U * k. Substituting the expression for U from the given equation, we have Q = (60(1 - 0.007k)) * k. Simplifying further, we get Q = 60k - 0.007k^2. This equation represents the flow as a function of both speed and density, describing how the flow varies with changes in speed and density.

3. The capacity of the road can be determined by finding the maximum flow rate, which occurs at the critical density. The critical density is the point where the flow starts decreasing due to congestion. To find the critical density, we differentiate the flow equation with respect to density and set it equal to zero. Taking the derivative of Q = 60k - 0.007k^2 with respect to k, we obtain 60 - 0.014k = 0. Solving for k, we find k = 60/0.014 ≈ 4285.7 units. Thus, the capacity of the road is approximately 4285.7 units, representing the maximum flow rate that can be sustained before congestion occurs.

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If Sin F = 3/5 , then the value of Cos D is 4/5 (option a)

Let us consider the triangle in the given question. Since we are given that Sin F = 3/5, we know that the side opposite angle F is 3 and the hypotenuse is 5. Using Pythagoras theorem, we can find the length of the adjacent side as follows:

Opposite² + Adjacent² = Hypotenuse²

3² + Adjacent² = 5²

9 + Adjacent² = 25

Adjacent² = 16

Adjacent = 4

So we have found that the length of the adjacent side is 4. Now we can use the definition of cosine to find Cos D.

Cosine is defined as the ratio of the adjacent side to the hypotenuse. Therefore,

Cos D = Adjacent/Hypotenuse = 4/5

Hence, the answer is option A) 4/5.

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You can take LCM and then can add to see what's the sum.

The sum result of given expressions is given by: \(\dfrac{5}{y+5}\)

You can take LCM and then can add to see whats the sum.

\(\begin{aligned}\dfrac{3y}{y^2 + 7y + 10} + \dfrac{2}{y+2} &= \dfrac{3y}{(y+2)(y+5)} + \dfrac{2}{y+2}\\&= \dfrac{3y + 2(y+5)}{(y+2)(y+5)}\\&= \dfrac{5y+10}{(y+2)(y+5)}\\&= \dfrac{5(y+2)}{(y+2)(y+5)}\\&= \dfrac{5}{y+5}\\\end{aligned}\)

Thus, the sum of given expressions is given by:

\(\dfrac{5}{y+5}\)

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Answer: 3:2

Step-by-step explanation:

If 3/5 of the marbles are blue, then the last 2/5 will be yellow.

Answer:

Hey there! So as you know, 3 out of 5 marbles are blue, which can be written as 3/5. To find the ratio of blue to yellow marbles, we need to find the number of yellow marbles.

We know that 5 marbles are blue and yellow combined, and 3 of them are blue, so that leaves 5-3 = 2 yellow marbles.

So the ratio of blue marbles to yellow marbles is 3:2, or 3/2. It means that for every 3 blue marbles, there are 2 yellow marbles.

The graph of the equation given is mentioned below.

What is plot point in graph ?

Whenever we draw a point on our grid, we'll call it "plotting a point." The grid is really called a "graph" and the points we plot are called "coordinates." These are really locations on a plane -- we're just finding and labeling them.

Equation given,

y = 3/5x - 1    ----eq(i)

y = 2/5x        -----eq(ii)      

Now, for this two equation we infinite points for real numbers.

Now, take some points to plot the graph.

First for the eq(i)

Put x = 0, so y = -1

Put x = 5, so y = 2

Points for eq(i) is (0, -1) and (5, 2)

Now, for eq(ii)

Put x = 0, so y = 0

Put x = 5, so y = 2

Points for eq(ii) is (0, 0) and (5, 2)

Common point is (5, 2)

Now, plot this point on graph.

Hence, for more clarity graph of the equation given is mentioned below.

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Answer:

False: A function is a rule that assigns each vale of the independent variable to exactly one vale of the dependent variable.

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

The correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are given below.Option A. V = -(0.25)x - 4 Option B. V = − (0.25)x+4

A function can be defined as a special relation where each input has exactly one output. The set of values that a function takes as input is known as the domain of the function. The set of all output values that are obtained by evaluating a function is known as the range of the function.

From the given options, only option A and option B are the functions that satisfy the condition.Both of the options are linear equations and graph of linear equation is always a straight line. By solving both of the given options, we will get the range as (-∞, 4) and domain as (-∞, 0).Hence, the correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are option A and option B.

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The error made in subtracting the two rational expressions 1/(x - 2) - 1/x is that the common denominator is not correctly identified and applied.

To subtract rational expressions, we need to find a common denominator and then subtract the numerators. In this case, the common denominator should be (x - 2) * x. However, the error lies in neglecting the parentheses in the first expression, leading to a miscalculation of the common denominator.

The correct subtraction of the given expressions should be: (x - 2)/(x - 2) - 1/(x * (x - 2)). Simplifying this expression further would result in (x - 2 - 1)/(x * (x - 2)), which can be simplified as (x - 3)/(x * (x - 2)).

Therefore, the error made in the subtraction lies in incorrectly identifying and applying the common denominator, which resulted in an inaccurate calculation of the expression.

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Answer: 6 chocolates

Step-by-step explanation:

Keilantra had 24 chocolates to begin with, and she ate six lots of three. so the first step is 6 x 3 = 18. Now that we know how many chocolates Keilantra ate, we need to figure out how many chocolates she has left. So we take our product (18) and we subtract it from the total (24). So we end up with 24 - 18 = 6.

Answer:

1. No

2. Right triangle

3. No

4. Right triangle

Step-by-step explanation:

A, B = two smallest sides

C = hypotenuse, largest side

Pythagorean theorem. If A^2 + B^2 = C^2, then you have a right triangle.

The standard deviation (σ) of this discrete random variable X is 6 dollars.

In Mathematics and statistics, an expected value is sometimes referred to as the long-term mean (average) of a discrete random variable, E(X) and it can be calculated by taking the weighted average of all the outcomes of the discrete random variable with respect to their probabilities.

In this context, we can logically deduce that the expected value (mean) is given by µₓ is equal to $6.

Based on the probability distribution table (see attachment), we would determine the variance of this discrete random variable X as follows;

Variance (X) = (-12 - 6)²(0.1) + (8 - 6)²(0.9)

Variance (X) = 36

Now, we can determine the standard deviation (σ) of this discrete random variable X is;

Variance (X) = σ²

σX = √36

σX = $6

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The chi-square goodness-of-fit test can provide information on categorical data match an expected distribution and which categories are contributing to any deviation from that distribution.

The chi-square goodness-of-fit test is a statistical test used to determine whether a set of observed categorical data matches an expected distribution. Specifically, the test compares the observed frequencies of each category to the expected frequencies based on a hypothesized distribution, and calculates a chi-square statistic. This statistic measures the degree of difference between the observed and expected frequencies, with larger values indicating greater deviation from the expected distribution. If the chi-square statistic is large enough to reject the null hypothesis (i.e., the observed data do not match the expected distribution), the test can provide information on which categories are contributing the most to the discrepancy. This can help identify which categories are over-represented or under-represented in the observed data, and can inform further investigation into potential causes of the deviation. In summary, the chi-square goodness-of-fit test can provide information on whether observed categorical data match an expected distribution and which categories are contributing to any deviation from that distribution.

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The distance that she runs from one corner of the field to another is given as follows:

147.1 yards.

The Pythagorean Theorem states that for a right triangle, the length of the hypotenuse squared is equals to the sum of the squared lengths of the sides of the triangle.

The distance in this problem is the diagonal of a rectangle, which is the hypotenuse of a right triangle in which the length and the width are the sides, hence:

d² = 85² + 120²

d = sqrt(85² + 120²)

d = 147.1 yards.

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The predictor variable is normally distributed is not required for the validity of standard linear regression modeling.

The assumptions that the residuals are normally distributed, the response variable is linearly related to the predictor variable, the response variable is normally distributed, and the variance in the residuals is the same for all values of the predictor variable are required assumptions for the validity of standard linear regression modeling. Additionally, the assumption that the intercept is not zero is not a required assumption, but rather a consideration for the interpretation of the model. In standard linear regression modeling, the following are not required assumptions for validity:
1. The predictor variable is normally distributed.
2. The intercept is not zero.
3. The response variable is normally distributed.
Required assumptions include:
1. The residuals are normally distributed.
2. The response variable is linearly related to the predictor variable.
3. The variance in the residuals is the same for all values of the predictor variable (homoscedasticity).

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Answer:

  (a)  0.0062

Step-by-step explanation:

You want the probability P(X > 14.5) given that X has a normal distribution with mean 2 and variance 25.

This probability can be found using a suitable calculator or spreadsheet. The calculator in the attachment specifies the normal distribution using mean and standard deviation, so we need to find the square root of the variance.

  P(X > 14.4) ≈ 0.0062

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a)The derivative of y with respect to x is (24x² - 2x)/(8x³ - x²)

b) The derivative of f(x) = ln(x) is f'(x) = 1/x

a) The derivative of the given functions, I'll use the standard rules of differentiation. Here are the derivatives:

y = ln(8x³ - x²)

To find the derivative of this function, we'll use the chain rule. Let's denote the inner function as u = 8x³ - x². The derivative of u with respect to x is du/dx = 24x² - 2x. Now, applying the chain rule:

dy/dx = (1/u) × du/dx

= (1/(8x³ - x²)) × (24x² - 2x)

= (24x² - 2x)/(8x³ - x²)

Therefore, the derivative of y with respect to x is (24x² - 2x)/(8x³ - x²).

b) f(x) = ln(x)

The derivative of ln(x) is given by the formula:

d/dx [ln(x)] = 1/x

Therefore, the derivative of f(x) = ln(x) is f'(x) = 1/x.

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Answer:

3 stamps

Step-by-step explanation: 42 stamps in equal groups would be 6 stickers/group.

6+3 = 9 stickers in each pile

there was 7 piles so multiply 7 by the 9 stickers in each pile

7· 9 = 63  

5 · 12 = 60, so she gave her friends 60 stickers

63-60 = 3