#8- please help i suck at this, ill mark brainliest

Answer:

The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid.

Answer:

The dirty dozen.

Explanation:

This is mainly seen in the control of hazardous waste and its regulations through treaty in the control of persistent organic pollutant(POPs). This regulation is seen to occur in 12 widely used persistent organic pollutants; these are seen to have the ability to absorb and store tissues that make them fatty especially in humans and also animals found in the higher trophic levels or in the food web. That being said, it can be noted that the dirty dozen can move or even attain hundreds, or thousands of levels towards the environ and also in other cases, transporting them through air or water as the case may be.

The hydronium ion concentration of the solution is 3.16 x 10^(-5) M. To determine the hydronium ion concentration of a solution with a pH of 4.5, we need to use the equation pH = -log[H+].  

To determine the hydroxide ion concentration of a solution with a pOH of 10.5, we need to use the equation pOH = -log[OH-]. Rearranging this equation, we get [OH-] = 10^(-pOH). Plugging in the pOH of 10.5, we get [OH-] = 3.16 x 10^(-11) M. Therefore, the hydroxide ion concentration of the solution is 3.16 x 10^(-11) M.

Note that the hydronium ion and hydroxide ion concentrations of a solution are related by the equation [H+][OH-] = 1.0 x 10^(-14) at 25°C. Using this equation, we can see that if the hydronium ion concentration is 3.16 x 10^(-5) M, the hydroxide ion concentration must be 3.16 x 10^(-10) M. Conversely, if the hydroxide ion concentration is 3.16 x 10^(-11) M, the hydronium ion concentration must be 3.16 x 10^(-4) M.

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Answer:

When the forest burns we will lose a huge amount of oxygen and animals will lose their home.

Explanation:

Answer:

86.45 g

Explanation:

Given data:

Percent abundance of Fa - 85 = 31%

Percent abundance of Fa - 86 = 12%

Percent abundance of Fa - 87 = 38%

Percent abundance of Fa - 88 = 19%

Average atomic mass of Fa = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+ (abundance of 3rd isotope × its atomic mass) + (abundance of 4th isotope × its atomic mass)   / 100

Average atomic mass = (31×85)+(12×86) +(38×87)+(19×88) /100

Average atomic mass =  2635 +1032 +3306 +1672 / 100

Average atomic mass  = 8645 / 100

Average atomic mass = 86.45

Answer:

gain electrons

Explanation:

"atoms gain electrons, they acquire a negative charge "

(a) The number of moles of **bismuth (Bi)** formed when 681 g of Bi2O3 reacts with excess carbon is **X mol**.

To determine the number of moles of Bi formed, we need to use the balanced chemical equation and the molar mass of Bi2O3. From the balanced equation, we can see that 1 mole of Bi2O3 reacts to form 2 moles of Bi. Therefore, we need to convert the mass of Bi2O3 to moles and then apply the stoichiometric ratio.

The molar mass of Bi2O3 is calculated as follows:

Bi2O3: Bi (2 * 208.98 g/mol) + O (3 * 16.00 g/mol) = 465.96 g/mol

Now, we can calculate the number of moles of Bi formed:

moles of Bi = (mass of Bi2O3) / (molar mass of Bi2O3)

moles of Bi = 681 g / 465.96 g/mol = X mol

Therefore, X mol of Bi form during the reaction.

(b) The number of grams of carbon monoxide (CO)** formed when 681 g of Bi2O3 reacts with excess carbon is Y g.

To determine the mass of CO formed, we again need to use the balanced chemical equation and the stoichiometry.

From the balanced equation, we can see that 1 mole of Bi2O3 reacts to form 3 moles of CO. Therefore, we need to convert the moles of Bi2O3 to moles of CO using the stoichiometric ratio and then convert moles to grams. First, calculate the moles of Bi2O3:

moles of Bi2O3 = (mass of Bi2O3) / (molar mass of Bi2O3)

moles of Bi2O3 = 681 g / 465.96 g/mol = Z mol

Next, use the stoichiometry to find the moles of CO formed:

moles of CO = 3 * moles of Bi2O3 = 3 * Z mol Finally, calculate the mass of CO formed: mass of CO = (moles of CO) * (molar mass of CO)

mass of CO = (3 * Z mol) * (molar mass of CO)

Therefore, Y g of CO form during the reaction.

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Answer:

6) 225.8 g

7) 1.01 g

8) 21.624 g

Explanation:

6) Molar Mass of Lithium Bromine: 86.845

86.845 * 2.6 = 225.8 g

7) Molar Mass of Neon: 20.180

20.180 * 0.05 = 1.01 g

8) Molar Mass of Water Vapor: 18.02

18.02 * 1.2 = 21.624 g

Omega-3 acid ethyl esters are a type of medication that is used to lower blood triglyceride levels in people with high levels of triglycerides in their blood.

Triglycerides are a type of fat that is found in the blood and elevated levels of triglycerides are associated with an increased risk of heart disease.

Omega-3 acid ethyl esters are a concentrated form of omega-3 fatty acids, which are essential fats that are found in certain types of fish, such as salmon, mackerel, and sardines.

Omega-3 fatty acids are known to have several health benefits, including reducing inflammation, improving brain function, and lowering triglyceride levels.

Omega-3 acid ethyl esters work by reducing the liver's production of triglycerides, which in turn lowers the amount of triglycerides in the blood.

The medication is taken orally, usually once or twice daily, with food.

In summary, omega-3 acid ethyl esters are used to lower blood triglyceride levels in people with high levels of triglycerides in their blood, reducing the risk of heart disease.

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Answer:

False

Explanation:

Always add acid to the water, it dilutes the acid the other way around.

The non-phosphorylated proteins from the non-diseased samples will move further to the anode without the bulky phosphate group attached to a tyrosine. The correct option is C.

Isoelectric focusing (IEF) is a technique used to separate proteins based on their isoelectric points (pI), which is the pH at which a protein has a net neutral charge. During IEF, proteins migrate in an electric field through a pH gradient until they reach a region of the gel where the pH matches their individual pI, resulting in immobilization.

In the context of chronic myelogenous leukemia (CML), where the hyperactive tyrosine protein kinase ABL is involved, the phosphorylation of proteins plays a significant role. Phosphorylation refers to the addition of a phosphate group to a protein. Phosphorylated proteins generally have a different charge distribution compared to non-phosphorylated proteins.

In this scenario, it is likely that protein X, which is suspected to be a target of the hyperactive ABL kinase, would be phosphorylated in the samples with CML. The addition of a phosphate group to the protein alters its charge distribution, leading to a change in its pI. Therefore, the phosphorylated protein X would have a different pI compared to the non-phosphorylated form.

Given this information, we can deduce that the non-phosphorylated proteins from the non-diseased samples would have a lower pI compared to the phosphorylated protein X from the CML samples. Consequently, the non-phosphorylated proteins would migrate further toward the anode in the isoelectric focusing process, as they would be attracted to the region of the gel with a higher positive charge.

This aligns with option C, which states that non-phosphorylated proteins from the non-diseased samples would move further to the anode without the bulky phosphate group attached to a tyrosine.

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The answer of this question is True.

About 20 percent of your daily energy needs is determined by your BMR.

BMR stands for basal metabolic rate.What is Basal Metabolic Rate (BMR)?

BMR is the amount of energy, in calories, used by your body when at rest.

It is an estimation of the number of calories required to keep your body functioning while at rest.

In other words, it is the minimum amount of calories your body requires to carry out its everyday processes, such as breathing and circulating blood, while at rest.

There are several factors that affect BMR, including age, gender, height, weight, and body composition.

A higher BMR implies that the body requires more calories to maintain its energy requirements.

Hence, about 20 percent of your daily energy needs is determined by your BMR.

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Answer:

96 m/s.

Explanation:

Distance equals speed x time,

12 x 8, so the distance is 96 m/s.

The weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ is 9.5294 x 10²⁶ g

To calculate the weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ (glucose), we need to determine the molecular weight of glucose and then multiply it by the given number of molecules.

The molecular formula of glucose (C₆H₁₂O₆ ) indicates that it consists of 6 carbon (C) atoms, 12 hydrogens (H) atoms, and 6 oxygen (O) atoms.

Using the atomic weights of carbon (12.01 g/mol), hydrogen (1.01 g/mol), and oxygen (16.00 g/mol), we can calculate the molecular weight of glucose:

To find the molecular weight of glucose, we add up the atomic weights of all the constituent atoms:

(6 x atomic weight of carbon) + (12 x atomic weight of hydrogen) + (6 x atomic weight of oxygen)

(6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol

The molecular weight of glucose (C₆H₁₂O₆ ) is 180.18 g/mol.

To find the weight of 5.3 x 10²⁴ molecules of glucose, we can use the following equation:

Weight = Number of molecules x Molecular weight

Weight = (5.3 x 10²⁴ molecules) x (180.18 g/mol)

Calculating this expression:

Weight = 9.5294 x 10²⁶ g

Therefore, the weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ (glucose) is approximately 9.5294 x 10²⁶ grams.

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We must first determine the molar mass of the compound to convert it to grams, which we use to calculate the molecular weight.

It is possible to determine the molar mass of \(C_6H_1_2O_6\) (glucose), by adding the atomic masses of its constituent parts:

C: 6 atoms x atomic mass of carbon (12.01 g/mol) = 72.06 g/mol

H: 12 atoms x atomic mass of hydrogen (1.01 g/mol) = 12.12 g/mol

O: 6 atoms x atomic mass of oxygen (16.00 g/mol) = 96.00 g/mol

Total molar mass of \(C_6H_1_2O_6\) = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol

Now we can find the weight of \(5.3 * 10^2^4\) C6H12O6 molecules using this molar mass:

(number of molecules) x (molar mass) = weight (in grams).

(5.3 x \(10^2^4\) molecules) x (180.18 g/mol) = weight

Weight = 9.00 x \(10^2^6\) grams

Therefore, the weight of 5.3 x \(10^2^4\) molecules of C6H12O6 is approximately 9.00 x\(10^2^6\) grams.

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Answer:

its B

Explanation:i took the test

Answer:

I believe the answer is ; explains natural phenomena.

Explanation:

As a pollutant such as methylmercury works its way through the food chain, Biomagnification occurs, resulting in top-level food chain members ingesting even higher concentrations of the pollutant.

Biomagnification is the process by which pollutants such as methylmercury become increasingly concentrated as they move up the food chain. This occurs because organisms at lower levels of the food chain ingest small amounts of the pollutant, which then accumulates in their bodies. As larger organisms consume these smaller organisms, they take in a higher concentration of the pollutant. This process continues as the pollutant moves up the food chain, resulting in top-level predators ingesting even higher concentrations of the pollutant. Biomagnification can have serious consequences for the health of these top-level predators, as well as for human populations that consume them.

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When aqueous solutions of sodium phosphate and copper (II) nitrate are combined, solid copper (II) phosphate and a solution of sodium nitrate are formed.

The net ionic equation for this reaction is written as follows:

Cu²⁺(aq) + PO₄³⁻(aq) → Cu₃(PO₄)₂(s)

It is important to note that the net ionic equation shows only the species (atoms, ions, or molecules) that undergo changes during the chemical reaction.

The complete balanced chemical equation for the reaction is:

Na₃PO₄(aq) + 3Cu(NO₃)₂(aq) → Cu₃(PO₄)₂(s) + 6NaNO₃(aq)

Let's write the ionic equation. Na₃PO₄ dissociates into Na⁺ and PO₄³⁻ in an aqueous solution while Cu(NO₃)₂ dissociates into Cu²⁺ and 2NO₃⁻ in an aqueous solution.

Ionic equation:

3Cu²⁺(aq) + 2PO₄³⁻(aq) → Cu₃(PO₄)₂(s)

We can see that the Na⁺ and NO₃⁻ ions are spectator ions in the reaction, that is why we call it a net ionic equation. This equation shows only the ions that participate in the reaction.

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The enthalpy of reaction (ΔH) of the above chemical reaction is equal to -143 kJ/mol.

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

Next, we would write the properly balanced chemical equation for this chemical reaction:

                                    3/2O₂ -----> 2/2O₃

Therefore, the enthalpy of reaction (ΔH) of the above chemical reaction is half the enthalpy of reaction (ΔH) of the initial chemical reaction:

Enthalpy of reaction (ΔH) = ½ × -286 kJ/mol

Enthalpy of reaction (ΔH) = -143 kJ/mol.

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Answer:

= konstanta produk kelarutan

= kation dalam larutan berair

= anion dalam larutan berair

= konsentrasi relatif a dan b

DARI WEB

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g . Solubility of NaNO3=21.9g or NaNO3 x 100 g/ 25 g =87.6. Calculate the molar mass of the dissolved compound as the sum of mass of all atoms in the molecule.

Answer:

K_{sp} = [A^+]^a [B^-]^b

K_{sp} = solubility product constant

A^+ = cation in an aquious solution

B^- = anion in an aqueous solution

a, b = relative concentrations of a and b

Explanation:

To determine the limiting reagent, we need to compare the amount of moles of each reactant used in the chemical reaction. The reactant that produces the least amount of product is the limiting reagent.

First, let's calculate the number of moles of each reactant:

- Moles of Ca3(PO4)2 = (155 g) / (310.18 g/mol) = 0.5 mol

- Moles of H2SO4 = (155 g) / (98.08 g/mol) = 1.58 mol

- Moles of H3PO4 = (88 g) / (97.99 g/mol) = 0.898 mol

According to the balanced chemical equation, 1 mole of Ca3(PO4)2 reacts with 3 moles of H2SO4 to produce 2 moles of H3PO4. Therefore, if we use 0.5 moles of Ca3(PO4)2, we need 1.5 moles of H2SO4 to react completely.

Since we only have 1.58 moles of H2SO4, this means that H2SO4 is not the limiting reagent. However, if we use 0.5 moles of Ca3(PO4)2, we will only produce 1 mole of H3PO4. Since we need 0.898 moles of H3PO4 to use up all of the available phosphoric acid, Ca3(PO4)2 is the limiting reagent.

Therefore, the limiting reagent in this reaction is Ca3(PO4)2.

Note: It is important to check the calculation for each reactant to ensure that we have the correct limiting reagent. In this case, we found that H2SO4 was not the limiting reagent because we had more moles of H2SO4 than what was needed to react with all of the Ca3(PO4)2. If we had found that H2SO4 was the limiting reagent, we would have needed to recalculate the amount of product produced using the moles of H2SO4 instead of Ca3(PO4)2.

The board of examiners in each state is responsible for granting licensure to individuals seeking to work in certain professions. This licensure is typically granted through one of three methods: examination, endorsement, or reciprocity.

Examination involves taking a test to demonstrate one's knowledge and proficiency in the field. This is often the most common method of licensure, as it ensures that individuals have a certain level of competence before being allowed to practice. Endorsement allows individuals who have already been licensed in another state to apply for licensure in a new state without having to take another examination. This is often an option for individuals who have already demonstrated their competence and don't want to go through the entire examination process again. Reciprocity is similar to endorsement, but it involves states recognizing each other's licensing requirements and granting licensure to individuals who have met those requirements in another state. In short, the board of examiners in each state can grant licensure through any of these methods, depending on the individual's situation and the requirements of the profession.

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Answer:

D

Explanation:

cracks from temperature changes is a type of physical weathering often known as freezing and thawing

False. Not all chemical compounds have isomers, which are molecules with the same molecular formula but different structural arrangements. Isomers only occur in certain cases where a molecule's atoms can be rearranged to create different structures with distinct properties.

The same molecular formula applies to structural isomers and other types of isomers, which are also chemical substances. It follows that these substances have the same molar mass because they share the same molecular formula.

When a substance has the same molecular formula but a different structural makeup, it is an isomer. They make up the group known as stereoisomers, or spatial isomers, which also includes optical isomers where isomers only differ in the spatial arrangement of their atoms.

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Answer:

Explanation:

a )

Zn = Zn²⁺ + 2e   ( oxidation reaction )

Fe³⁺ + 3e = Fe( s ) ( reduction reaction )

b )

[ Zn = Zn²⁺ + 2e ] x 3

[ Fe³⁺ + 3e = Fe( s ) ] x 2

-------------------------------------------------------------------

3 Zn + 2 Fe³⁺ + 6e = 3 Zn²⁺ + 2 Fe ( s ) + 6e

3 Zn + 2 Fe³⁺  = 3 Zn²⁺ + 2 Fe ( s )

Answer:

hi there !!

B) Water evaporates into steam.

this is correct because only physical state changes, steam can be cooled down to get water again.

Answer:

A

Explanation:

Have a nice day

Answer:

3.38 x 10⁴cm³

Explanation:

Given that:

      Volume of the substance  = 3.83 x 10⁷mm³

The problem entails use to convert from mm³ to cm³;

                    1000mm³   = 1cm³

So;

          3.83 x 10⁷mm³ will produce \(\frac{ 3.83 x 10^{7} }{1000}\)    = 3.38 x 10⁴cm³

Answer:

mass cannot be created nor destroyed just moved around

Explanation:

The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed so it can only be moved around during a chemical reaction