8. Paige dropped a ball out of a car while her friend Destiny was traveling at a velocity of 25
m/s. The ball underwent a deceleration of -2m/s² and rolled to a stop on the pavement. How
long did it take the ball to stop?

Case: The effect of balloon color on inflation time.

Independent variable: Balloon color (categorical) with four levels (e.g., red, blue, green, yellow).

Dependent variable: Time taken for inflation to a diameter of 7 inches (continuous, measured in seconds).

Study design: Within-subject design (the same group of participants inflating balloons of different colors).

Confounding variable: Possible confounding variables could be the size or material of the balloons, as these factors might affect the inflation time. To control for this, it would be important to ensure that all balloons used in the experiment are of the same size and material.

Violation of Validity: A violation of validity could occur if the measurement of inflation time is not accurate or consistent (e.g., if the stopwatch used is unreliable or if the experimenter's recording of times is inconsistent). Ensuring proper measurement procedures and equipment would help mitigate this violation.

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The descriptions of the points in the heating curve of water are:

A heating curve for a substance is a curve which show the phase changes that occur in the substance as the substance is heated over a period of time.

The addition of heat to substances result in an increase in volume and a change of state.

Water can exist in the three physical states of matter, which are solid, liquid, and gas.

A graph showing the changes that occur in water as heat is added to it is referred to as the heating curve of water.

Considering the heating curve of water shown, water exists first as a solid, then liquid, and finally a gas as heat is added to it.

The various descriptions of the point in the heating curve of water are as follows:

Leg A: solid warms from -40C to OC

Leg B: melting

Leg C: Liquid warms from O °C to 100 °C

Leg D: Evaporation

Leg E: Water vapor warms from 100C

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Answer:

Acceleration, \(a=4\ m/s^2\)

Explanation:

Given that,

Initial velocity, u = 20 m/s

Final velocity, v = 60 m/s

Time, t = 10 s

We need to find the acceleration of the car. It is equal to the change in velocity divided by time.

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2\)

So, the acceleration of the car is \(4\ m/s^2\).

Answer:

The electrically charged gas particles are affected by magnetic forces.

For the past eleven years, the Sun's north geographic pole has also been home to its north magnetic pole

Explanation:

To determine the speed at which a sequoia cone would hit the ground when dropped from the top of a 100 m tall tree, we can use the principles of free fall motion.

When air drag is negligible, the only force acting on the cone is gravity. The acceleration due to gravity, denoted as "g," is approximately 9.8 m/s² on Earth.

The speed (v) of an object in free fall can be calculated using the equation:

v = √(2gh),

where h is the height from which the object falls. In this case, h is 100 m.

Plugging in the values:

v = √(2 * 9.8 m/s² * 100 m) ≈ √(1960) ≈ 44.27 m/s.

Therefore, the sequoia cone would be moving at approximately 44.27 meters per second (m/s) when it reaches the ground.

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Answer:

The acceleration due to gravity of the planet is approximately 15.083 m/s²

Explanation:

The given information are;

The mass of the golf ball = 45.93 gram

The time it takes the golf ball to hit the ground 0.44 seconds

The height, s, from which the golf ball is dropped = 146 cm = 1.46 m  

The equation of motion for the golf ball can be expressed as follows;

s = u·t + 1/2·a·t²

Where;

s = 1.46 m

u = The initial velocity of the golf ball = 0 m/s

a = The acceleration due to gravity of the planet

t = The time it takes the golf ball to hit the ground = 0.44 seconds

By substituting, we have;

1.46 = 0 × 0.44 + 1/2 × a × 0.44²

a = 1.46/(1/2 × 0.44²) ≈ 15.083 m/s²

The acceleration due to gravity of the planet = a ≈ 15.083 m/s².

Explanation:

Density=mass/volume

mass=x

10.49=X/12.99

X=10.49 X12.99

X=136.29657

mass=136.3g/cm^3

I hope it helped.

Answer:  With Hydroelectric power water is artificially stored in a high place, so it can be released and flow to a low place and through a generator. With Tidal energy the movement of water is also used to power a generator, but the flow of water is caused by the changing tides.

Answer:

C. Talk test

Explanation:

The talk test would be readily available to me at the the least cost.

The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.

The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.

Answer:

c

Explanation:

Answer:

2 4

Explanation:

because

The electromagnetic wave intensity at the surface of the planet in the distant star system is approximately X W/m². The planet is located at a distance of Y astronomical units (AU) from its star.

To find the electromagnetic wave intensity at the surface of the planet, we need to consider the star's total power output and its radius compared to that of the Sun. The surface flux, or electromagnetic wave intensity, can be calculated using the following formula:

Surface flux = (Star's power output) / (4π × (Star's radius)²)

Given that the star's power output is 5.8 x 10^29 W and the star's radius is 6.0 times the radius of the Sun (6.0 × 6.96 x 10^9 m), we can substitute these values into the formula:

Surface flux = (5.8 x 10^29 W) / (4π × (6.0 × 6.96 x 10^9 m)²)

Simplifying the expression, we can calculate the surface flux in W/m². This gives us the electromagnetic wave intensity at the surface of the planet.

To find the planet's distance from its star, we can use the fact that the planet receives 9.4 x 10^22 J of energy every planet-day (one rotation). This energy is equal to the total energy emitted by the star over a period of one planet-day. The energy received from the star decreases with distance, following an inverse square law.

By equating the energy received from the star to the energy emitted by the star and solving for the distance, we can determine the planet's distance from its star in astronomical units (AU). The formula to calculate the distance is:

Distance = sqrt((Star's power output × Planet-day duration) / (4π × Surface flux))

Substituting the given values, we can calculate the distance in AU.

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If an object moves around a circle, of radius 6 m, with constant velocity, the angular velocity of the object is 1.67 1.67 radians per second.

The angular velocity of an object moving in a circular path can be calculated using the formula:

ω = v / r

Where ω is the angular velocity, v is the constant speed, and r is the radius of the circle.

In this case, we are given the constant speed (v) as 10.0 m/s and the radius (r) as 600 cm. We need to convert the radius to meters in order to use the formula correctly:

r = 600cm * (1m / 100cm) = 6m

Now we can plug in the values and solve for the angular velocity:

ω = v / r

ω = 10.0 m/s / 6 m

ω = 1.67 radians per second

Therefore, the angular velocity of the object is 1.67 radians per second.

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The rms voltage across the secondary is 24 V.

An item utilised in the transfer of electric energy is a transformer. AC current is used for transmission. It is frequently used to modify the supply voltage across circuits without altering the AC frequency.

Types of Transformers

Auxiliary Transformers.

Here ,

number of turns in primary coil , Np = 100

number of coils in secondary , Ns = 200

primary voltage , Vp = 12 V

for the ideal transformer

Vs/Ns  = Vp/Np

Vs/200 = 12/100

Vs = 24 V

the rms voltage across the secondary is 24 V.

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Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

The displacement of the system is 1.5 m.

The relation between displacement level and voltage can be determined through the given data. For this, first, we will determine the range of both displacement and voltage.

Range of Displacement:

It is given that the displacement range is from 1 to 4 m. Therefore, the total range will be:

Total range = Maximum value – Minimum value = 4 – 1 = 3 m

Range of Voltage:

It is given that the voltage range is from 2 to 15 V. Therefore, the total range will be:

Total range = Maximum value – Minimum value = 15 – 2 = 13 V

To determine the relation between displacement level and voltage, we will use the formula of the percentage. Mathematically, it is represented as:

Percentage = (Part / Whole) x 100

If we compare the displacement level with the voltage level, we can see that both are directly proportional to each other. It means if the displacement level increases, the voltage level will also increase and vice versa.

The displacement of the system:

If the input control signal is 50% of its full-scale, we can determine the displacement of the system by following these steps:

First, we will find the range of the input control signal:

Total range = Maximum value – Minimum value = 15 – 2 = 13 V

Then, we will find 50% of the range:

50% of total range = (50/100) × 13 = 6.5 V

Now, we will add the minimum value to the above result to get the input control signal value for 50% of the full-scale range:

Input control signal = 6.5 + 2 = 8.5 V

To determine the displacement of the system, we will use the given relation:

Displacement range = 1 to 4 m

Voltage range = 2 to 15 V

The displacement for an input control signal of 8.5 V is:

Displacement = ((Input Control Signal - Minimum Voltage) / (Maximum Voltage - Minimum Voltage)) × (Maximum Displacement - Minimum Displacement)

= ((8.5 - 2) / (15 - 2)) × (4 - 1)

= (6.5 / 13) × 3

= 1.5

Therefore, the displacement of the system for an input control signal of 50% from its full-scale is 1.5 m.

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Answer:

B) Walker 2 was at rest for the first five seconds. D) Walker 2 moved faster overall than walker 1 by the end. E) Both walkers had reached the same distance at fifteen seconds.

Explanation:

I did the UsaTestPrep

At 100% relative humidity, the wet-bulb temperature equal to the dry-bulb temperature in an open system containing a gas-vapour mixture.

Relative humidity (RH) is the measure of the quantity of water vapour, or moisture, in the air, represented as a percentage of the maximum amount of moisture the air can contain at a particular temperature and pressure without condensing.

The mass of vapour per unit mass of the gas is used to define the humidity of a vapor-gas mixture. The mass of vapour per unit mass of the gas is used to define the humidity of a vapor-gas mixture. Any vapour existing in any noncondensable gas can be subject to this basic rule.

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High redshift Type Ia supernovae observations imply that the universe's expansion is accelerating due to their consistent intrinsic brightness and their role as "standard candles" in measuring cosmic distances.

Type Ia supernovae are thermonuclear explosions of white dwarf stars that have a well-defined peak luminosity, allowing astronomers to determine their distance from Earth accurately. When astronomers observe these supernovae at high redshifts, they are looking back in time to see the universe at an earlier stage. The redshift refers to the observed shift in the light emitted by these objects towards the red end of the spectrum, caused by the Doppler effect as they move away from us due to the expansion of the universe.

A higher redshift corresponds to a more distant and earlier stage of the universe. By comparing the observed brightness of high redshift Type Ia supernovae with their known intrinsic brightness, astronomers can deduce how far away these objects are and how the universe has expanded over time. Observations of these distant supernovae have revealed that they are dimmer than expected, indicating that they are farther away than anticipated based on the standard models of cosmic expansion.

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Answer:

True?

Explanation:Im sure of it?

According to the universal law of gravitation, the force between 2 objects (m1 and m2) is proportional to their plenty and reciprocally proportional to the sq. of the distance (R) between them.

Answer:

10.3 cm³

Explanation:

From the question given above, the following data were obtained:

Original volume (V₁) = 10 cm³

Initial temperature (θ₁) = 20 °C

Final temperature (θ₂) = 50 °C

Cubic expansivity (γ) = 10¯³ K¯¹

Final volume (V₂) =?

γ = V₂ – V₁ / V₁(θ₂ – θ₁)

10¯³ = V₂ – 10 / 10( 50 – 20)

10¯³ = V₂ – 10 / 10(30)

10¯³ = V₂ – 10 / 300

Cross multiply

10¯³ × 300 = V₂ – 10

0.3 = V₂ – 10

Collect like terms

0.3 + 10 = V₂

10.3 = V₂

V₂ = 10.3 cm³

Thus, the volume at 50 °C is 10.3 cm³

The velocity of the first sphere will be 0.9899m/s

We know that Potential Energy, P.E. will be:

P.E. = mgh

where m = 0.1 kg

g =  9.8 m/s^2

h = 0.05 m

On  substituting values we get,

P.E. = 0.1 * 9.8 * 0.05 = 0.049 J

By the law of conservation of Energy,

P.E. = K.E,

K.E. = Kinetic energy ,

\(K.E. =\frac{mv^{2} }{2}\)

on substituting values we get,

(0.1 * v^2 *)/2 = 0.049

v^2 = 0.98

taking square root on both sides, we get

v = 0.9899 m/s

Therefore, the velocity of the first sphere will be 0.9899m/s.

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The term used to describe the maximum distance that a sound wave displaces air molecules from their original undisturbed position is called the amplitude

The term used to describe the maximum distance that a sound wave displaces air molecules from their original undisturbed position is called the amplitude of the sound wave. Amplitude refers to the magnitude of the wave's displacement and is typically measured in decibels (dB).

The higher the amplitude of a sound wave, the louder the sound will be perceived by our ears. The amplitude of a sound wave is determined by the amount of energy that the sound wave carries. A sound wave with a higher amplitude will have more energy and thus will displace air molecules more strongly than a sound wave with a lower amplitude.

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Answer:

The gravitational force between Saturn and it's moon is 1.62 m/s ^2

Explanation:

google it

Answer:

Explanation:

C bro

The point on the y-axis where the magnetic field is zero can be determined by applying Ampere's law, which states that the sum of the magnetic field contributions from currents passing through a closed loop is proportional to the total current passing through the loop.

In this case, we have two wires carrying currents in opposite directions. The magnetic field at a point on the y-axis due to each wire can be calculated using the formula:

B = (μ0 / 2π) * (I / r),

where B is the magnetic field, μ0 is the permeability of free space (4π × 10^(-7) T·m/A), I is the current, and r is the distance from the wire to the point of interest.

Let's consider a point on the y-axis at a distance y from the x-axis. The magnetic field contributions from the two wires can be calculated as follows:

B1 = (μ0 / 2π) * (i1 / r1) = (4π × 10^(-7) T·m/A / 2π) * (45 A / r1),

B2 = (μ0 / 2π) * (i2 / r2) = (4π × 10^(-7) T·m/A / 2π) * (35 A / r2),

where r1 is the distance between the first wire and the point on the y-axis, and r2 is the distance between the second wire and the same point on the y-axis.

To find the point on the y-axis where the magnetic field is zero, we set B1 + B2 = 0 and solve for y:

(4π × 10^(-7) T·m/A / 2π) * (45 A / r1) + (4π × 10^(-7) T·m/A / 2π) * (35 A / r2) = 0.

Simplifying the equation, we have:

(45 A / r1) + (35 A / r2) = 0.

From this equation, we can see that for the magnetic field to be zero, the sum of the magnetic field contributions from the two wires must cancel each other out. The specific value of y where this occurs depends on the values of r1 and r2, which are the distances from the wires to the point on the y-axis.

Given that y1 = 2 cm and y2 = 11 cm, we can calculate r1 and r2 as follows:

r1 = √((x^2 + y1^2)) = √((0^2 + 0.02^2)) ≈ 0.02 m,

r2 = √((x^2 + y2^2)) = √((0^2 + 0.11^2)) ≈ 0.11 m.

Now, substituting these values into the equation above, we have:

(45 A / 0.02 m) + (35 A / 0.11 m) = 0.

Simplifying further, we find:

2250 A/m + 318.18 A/m = 0,

2570.18 A/m = 0.

Since it is not possible for the sum of positive values to equal zero, there is no point on the y-axis where the magnetic field is exactly zero in this scenario.

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The average acceleration of the ball during the throwing motion is approximately 528.5 m/s².

To estimate the average acceleration of the baseball during the throwing motion, we can use the following formula:

Average acceleration (a) = Change in velocity (Δv) / Time taken (Δt)

First, let's find the time taken for the ball to travel the given displacement of 3.5 m. We can use the equation of motion:

Displacement (s) = Initial velocity (v₀) * Time taken (t) + 0.5 * Acceleration (a) * Time taken (t)²

Rearranging the equation, we get:

3.5 m = 0 * t + 0.5 * a * t²

Since the initial velocity is 0 (as the pitcher starts from rest), we can simplify the equation to:

3.5 m = 0.5 * a * t²

Now, let's solve for time (t):

3.5 m = 0.5 * a * t²

Dividing both sides by 0.5 * a, we get:

7 m / a = t²

Taking the square root of both sides, we have:

√(7 m / a) = t

Now we have the time taken (t) in terms of the acceleration (a). To find the time taken, we need the velocity (v) divided by the average acceleration:

t = 3.5 m / 43 m/s = 0.0814 s (approx)

Now, let's calculate the change in velocity (Δv) during this time:

Δv = Final velocity (v) - Initial velocity (u)

Since the final velocity is 43 m/s and the initial velocity is 0 m/s, we have:

Δv = 43 m/s - 0 m/s = 43 m/s

Finally, we can calculate the average acceleration (a) using the formula:

a = Δv / t = 43 m/s / 0.0814 s

a ≈ 528.5 m/s²

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This question involves the concept of the resolution of a vector into its rectangular components.

The horizontal component of velocity is "1.4 m/s", and the vertical component of the velocity is "7.9 m/s".

In order to find the horizontal and vertical components of the velocity of Esther, we must resolve the velocity vector into its rectangular components. Hence, the following formulae will be used:

\(Horizontal\ Component = v_x = v\ Cos\theta\\v_x = (8\ m/s)(Cos\ 80^o)\\v_x = 1.4\ m/s\)

\(Vertical\ Component = v_y = v\ Sin\theta\\v_y = (8\ m/s)(Sin\ 80^o)\\v_y = 7.9\ m/s\)

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The attached picture shows the resolution of a vector.

She should get married.

Answer:

false its an attraction property

Answer:

True

The attraction is a chemical property.

A branch of physics called kinematics, which originated in classical mechanics, defines how points, bodies, and systems of bodies move without taking into account the forces that are responsible for their motion.

Let's go over the four basic kinematic equations of motion with constant acceleration:

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where an is acceleration, s is distance, u is beginning velocity, v is final velocity, and t is time.

To determine the horizontal distance traveled in this instance, we first need to determine the time it takes for the ball to fall vertically to the ground.

Knowing u = 0, a = g = 9.81 m/s2, and s = 5 m for the vertical drop, we can use equation (1) to obtain

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Now that we have t, we can calculate the horizontal distance.

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration) (no horizontal acceleration)

s = 35.35m

The ball thus travels 35.35 meters before striking the ground.

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