#8. Benny pushes Betty on her skateboard with a force of 150 N. If she accelerates at 3.0 m/s? what is her
mass? Type the formula and answer.

Answers

Answer 1

Answer:

50 kg

Explanation:

Force = Mass x Acceleration

150 = Mass x 3

150 = 50 x 3


Related Questions

The temperature of a cup of coffee varies according to Newton's Law of Cooling: dT dt equals negative k times the quantity T minus A, where T is the temperature of the coffee, A is the room temperature, and k is a positive constant. If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C, find the temperature, to the nearest degree Celsius of the coffee after 4 minutes.

74
67
60
42

Answers

Answer:

Explanation:

Writing out the Newton's Law pf Cooling:

dT/dt = -k * (T - A),

where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.

If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C,

T = 100

A = 25

dT = 100 - 90 = 10

dt = 1

Putting the figures into the equation:

10/1 = -k * (100 - 25)

k = -10/75°C

After 4 minutes, dT/4 = 10/75 (100 - 25) = 10

dT = 40

Temperature after 4 minutes = 100 - 40 = 60°C

The temperature of a cup of coffee varies according to Newton's Law of Cooling, the temperature of the coffee after 4 minutes is approximately 67°C.

To tackle this problem, we can apply Newton's Law of Cooling's differential equation and solve it using variable separation.

dT/dt = -k(T - A)

At t = 0 (initial condition): T = 100°C

At t = 1 minute: T = 90°C

dT/dt = -k(T - A)

At t = 0: dT/dt = -k(100 - 25)

So,

-10 = -k(75)

k = 10/75

Separating variables and integrating, we have:

1/(T - A) dT = -k dt

∫(1/(T - A)) dT = ∫(-k) dt

ln|T - A| = -kt + C

ln|100 - 25| = 0 + C

ln|75| = C

So, the equation will be:

ln|T - A| = -kt + ln|75|

ln|(T - 25)/(75)| = -kt

Now,

ln|((T - 25)/(75))| = -(10/75)(4)

|((T - 25)/(75))| = \(e^{(-40/75)\)

T - 25 = ± 75 *  \(e^{(-40/75)\)

T = 25 ± 75 *  \(e^{(-40/75)\)

T ≈ 25 ± 42.42

Therefore, the temperature of the coffee after 4 minutes is approximately:

T ≈ 25 + 42.42 = 67.42°C

Thus, the temperature of the coffee after 4 minutes is approximately 67°C.

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Which of these results in kinetic energy of an object? position motion mass volume

Answers

Answer:

Motion

Explanation:

I just took the test :)

P.S. Can I please get a brainliest (look at my account to see what i do with the points :p)

Kinetic energy is the energy that set an object or body in motion. Motion result in kinetic energy.

What is kinetic energy?

Kinetic energy is the energy required to set an object in motion.

It is the energy present in a moving body. This involve the movement of an object from one place to another as it is found in a moving ball or car.

Therefore, motion result in kinetic energy.

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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s

Answers

ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

An object with a mass of 10 kg accelerates 16 m/s2 when an unknown force is applied to it what is the amount of force

Answers

Answer:

\( \huge{ \boxed {\bold{ \tt{160 \: N}}}}\)

Explanation:

Given :Mass ( m ) = 10 kgAcceleration ( a ) = 16 m / s²To find :Force = ?We know,

\( \boxed{ \sf{Force = Mass \: \times \: Acceleration}}\)

\( \sf{➛ force \: = 10\: \times 16}\)

\( \sf{➛ force = 160 \: Newton}\)

The amount of force is 160 N

Hope I helped!

Best regards! :D

~TheAnimeGirl

Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!

Answers

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

an example of a household appliance with a low and high power rating​

Answers

Answer:

Explanation:

There are countless household appliances in every single house. One appliance with a low power rating would be a ceiling fan. On average ceiling fans consume roughly 60w and are found in the majority of houses. On the other side of the spectrum, we have a high power-rating appliance such as a microwave. Microwaves use anywhere between 1000w to 1800w of power in order to function correctly. This is very large power consumption and one of the highest power ratings found for appliances in a household.

Estimate the maximum centripetal acceleration of the moon around the sun. For this estimate, you may assume that the earth and moon are both and circular orbits around their parent body.

Estimate the maximum centripetal acceleration of the moon around the sun. For this estimate, you may

Answers

Using Newton's second law and the universal gravitation law we find that the maximum acceleration response is

the acceleration around the sun is twice the acceleration around the EarthAcceleration around the Sun 6 10⁻³ m/s²Acceleration around the Earth 3 10⁻³ m/s²

The universal law of Gravitation states that the force between two bodies is proportional to their masses and inversely proportional to the square of their distance

           F = \(G \frac{M m}{r^2}\)  

Where G is the universal gravitation constant (G = 6.67 10-11 N m²/kg²), M and m the mass of the bodies and r the distance between them

Newton's second law indicates that the force is proportional to the masses and the acceleration of the bodies

        F = m a

Where F is the force, m and a the mass and acceleration of the body     

let's substitute

         \(G \frac{Mm}{r^2}\)  = m a

         a = \(G \frac{M}{r^2}\)

In this case the acceleration is called centripetal since it corresponds to a circular motion of the Moon and the Earth.

In tables we can find the values:

The mass of the Earth is 5.98 10²⁴ kgThe distance between the Moon and the Earth is 3.84 10⁸ mMass of the sun 1,991 10³⁰ kgEarth - Sun Distance 1,496 10¹¹m

Let's calculate the acceleration of the Moon around the Earth

      a₁ = 6.67 10⁻¹¹ \(\frac{5.98 \ 10^{24}}{ (3.84 \ 10^8 )^2 }\)

      a₁ = 2.71 10⁻³ m / s²

The acceleration of the Earth around the Sun  

      a₂ = 6.67 10⁻¹¹  \(\frac{1.991 \ 10^{30} }{(1.496 \ 10^{11})^2 }\)  

      a₂ = 5.93 10⁻³ m / s²

We can see that the acceleration around the Sun is twice the acceleration of the moon around the Earth

In conclusion they use Newton's second law and the universal gravitation law, we find that the maximum acceleration response is

the acceleration around the sun is twice the acceleration around the EarthAcceleration around the Sun     6 10°³ m/s²Aacceleration around the Earth 3 10°³ m/s²

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A ball weighing 3.4 N is thrown with a velocity of 52 m/s. What is the momentum?

Answers

Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

A heat engine operates between 200 K and 100 K. In each cycle it takes 100 J from the hot reservoir, loses 25 J to the cold reservoir, and does 75 J of work. This heat engine violates the second law but not the first law of thermodynamics. Why is this true?

Answers

Answer:

It does not violate the first law because the total energy taken is what is used 100J = 25J + 75J

But violates 2nd lawbecause the engine has a higher energy after doing work than the initial for e.g A cold object in contact with a hot one never gets colder, transferring heat to the hot object and making it hotter confirming the second law

Rita raises a 10kg package to a height of 2.5 m in 2.0 s.
(a) How much work did she do on the package?
(b) How much power was expended on the package?
(c) It she were to raise the package in 1.0 s rather than 2.0 s, how do the work and power change?

Answers

Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s

why do astronauts weigh less on the moon than on earth

Answers

Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

2. When you increase your speed from 35 mph to 70 mph, the force of impact you experience will be increased: A. 2 times B. 4 times C. 5 times D. 7 times​

Answers

you just have to divide 35 and 70, the answer is A. 2 times

When you increase your speed from 35 mph to 70 mph, the force of impact you experience will be increased 4 times.

Hence, the correct option is B.

The force of impact in a collision is directly proportional to the square of the velocity. When the speed is doubled (increased from 35 mph to 70 mph), the force of impact will increase by a factor of four (\(2^2\)). This is a fundamental concept in physics known as the kinetic energy formula, which is given by:

Kinetic Energy = (1/2) * mass * \(velocity^2\)

Since kinetic energy is directly proportional to the square of velocity, doubling the speed results in four times the kinetic energy and, consequently, four times the force of impact.

Therefore, When you increase your speed from 35 mph to 70 mph, the force of impact you experience will be increased 4 times.

Hence, the correct option is B.

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When an object levitates, the magnetic force causes the object to repel. Without this magnetic force, ________ would pull the object down. ​

Answers

Answer:

gravity

Explanation:

I don't know what the explanations would be

A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.

When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e

Answers

Answer:

e

Explanation:

One car is traveling with a speed of 40 miles per hour. A second car is traveling with a speed of 50 miles per hour. They crash into each other. It is a very different accident if they crash into each other head on, or if the faster one hits the slower one from behind. What does this have to do with the word velocity?

Answers

Answer:

Velocity is a vector whose magnitude is called speed. Collision study needs to analyse the transfer of momentum, which is another vector quantity associated with the velocity vector of each object

Explanation:

The important concept to recall is that velocity is a vector quantity, which has direction apart from just magnitude (as speed is). So in the transfer of momentum (another vector quantity) that takes place in a collision, it is extremely important to know the direction of the velocity vector, since there is much larger transfer of momentum if the cars collide heads on, than if the cars collide from behind while going in the same direction.

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?

Answers

Answer:

 α = 5 rad / s²

Explanation:

This is a rotational kinematics exercise.

They indicate the initial velocity wo = 10 rad / s

             w = w₀ + α t

             α = \(\frac{w-w_o }{t}\)

let's calculate

             α = \(\frac{30-10}{4}\)

             α = 5 rad / s²

The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change

            a = α r

            v = w r

A 7 N force and a 10 N force act on an object in opposite directions. What is the net force on the object?
70 N
17 N
3 N
1.43 N
0 N

Answers

Answer: 70N

Explanation:

'and'= multiply

7N*10N=70N

A large boulder falls from an underwater ledge and crashes on the floor of the ocean. A pod of dolphins is 800 meters away. Determine how long it takes for the sound of the crash to reach the dolphins.

0.5 sec
0.3 sec
2.3 sec
1.9 sec

Answers

Answer:

0.5

Explanation:

Answer:

0.539

Explanation:

Violet light of 425 nm is reflected from a thin film of air between two glass plates. The thickness of the film is 1.70 x 10^-6 m.

(a) How much farther does the light reflected from the bottom surface of the film travel than that reflected from the top surface?

(b) How many wavelengths of light does this present?

Answers

a) The path length difference between the light reflected from the bottom and top surfaces of the film is 3.4 x 10⁻⁶ m

b) It is equivalent to 8 wavelengths of violet light with a wavelength of 425 nm.

a) When light reflects off a thin film of air between two glass plates, interference between the reflected waves can result in constructive or destructive interference, depending on the thickness of the film and the wavelength of the light. This can lead to a range of optical phenomena, including coloration, reflection, and transmission.

In this scenario, violet light of 425 nm is reflected from a thin film of air with a thickness of 1.70 x 10⁻⁶ m. To find the difference in path length between the light reflected from the bottom surface of the film and the light reflected from the top surface, we can use the formula:

path length difference = 2 x thickness of the film

= 2 x 1.70 x 10⁻⁶ m

= 3.4 x 10⁻⁶ m

b) To find the number of wavelengths of light this presents, we can divide the path length difference by the wavelength of the light:

number of wavelengths = path length difference / wavelength

= (3.4 x 10⁻⁶ m) / (425 x 10⁻⁹ m)

= 8 wavelengths

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/ Assignment 01 Science teachers think practical science is a good thing. a. Agree b. Disagree c. Uncertain​

Answers

It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.

Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.

Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.

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A bar has a 20 N weight at one end, as shown in Figure 7.22. You have a weight of 15 N to hang somewhere on the bar so that the bar is in equilibrium. Where would you hang the 15 N weight on each of these bars? Consider the bar to have no mass.​

Answers

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electric field falls off as 1/r2 of the distance r from the charge. How does the surface area change with r ?

Answers

The change in surface area of Gaussian surface with radius (r) is 8πr.

Electric field from Coulomb's law

The electric field experienced by a charge is calculated as follows;

\(E = \frac{Q}{4\pi \varepsilon_o r^2}\)

where;

E is the electric fieldQ is the charger is the radius

The electric field reduces by a factor of \(\frac{1}{r^2}\)

Surface area of a Gaussian surface;

The surface area of a sphere is given as;

\(A = 4\pi r^2\)

Change in area with r

\(\frac{dA}{dr} = 8\pi r\)

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

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Two identical objects A and B of mass M move on a one-dimensional, horizontal air track. Object B initially moves to the left with speed vo. Object A initially moves to the right with speed 3vo, so that it collides with object B. Friction is negligible. Express your answers to the following in terms of M and vo.
(a) Determine the total momentum of the system of two objects.
(b) A student predicts that collision will be totally inelastic (the objects stick together on collision). Assuming this is true, determine the following for the two objects immediately after the collision. i. the speed ii. the direction of motion.
I 'm having trouble in how to approach the problem, specifically when to use inelastic or elastic.

Answers

a) Total momentum before collision is: \(\mathrm{\rho = M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

b) Immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, as A was moving to right before collision.

What is momentum?

Momentum may be defined as the product of mass and velocity of any object.

(a) Before the collision, total momentum of the system is :

\(\mathrm{\rho = m_A \times v_A + m_B \times v_B}\)

\(\mathrm{m_A = m_B = M, v_A = 3v_0, \ and \ vB = -v_0}\) (since B is moving to the left).

Therefore, total momentum before the collision is:

\(\mathrm{\rho= M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

(b) Immediately after the collision, the two objects move with the same velocity v. Total momentum of the system is: p' = (mA + mB)  ×  v = 2M  ×  v

As total momentum is conserved: p' = p

\(\mathrm{2M \times v = 2M \times v_0}\)

\(\mathrm{v = v_0}\)

Therefore, immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, since A was moving to the right before collision.

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Sound waves will travel faster on a dry day than on a humid day of the same temperature. Is this true or false?

Answers

The speed of a sound wave depends on the density of the medium on which it propagates. Then, it is affected by temperature and humidity.

The speed of sound in dry air is lower than in moist air.

Then, it is not true that sound waves will travel faster on a dry day.

Therefore, the answer is:

\(\text{False}\)

The average 8-18 year old spends how many hours per day average in front of a screen doing little physical activity

Answers

Nearly four hours every day, doing little to no physical activity.

Which dog has the most kinetic energy? A. A dog of mass 10 kg running with speed 6 m/s B. A dog of mass 8 kg running with speed 4 m/s C. A dog of mass 12 kg running with speed 5 m/s D. A dog of mass 15 kg running with speed 3 m/s​

Answers

Answer:

J stands for Joules.

A has the most KE

Explanation:

Dog A

En = 1/2 m * v^2m = 10 kgv = 6 m/sEn = 1/2 10 * 6^2En = 5 * 36En = 180 J

Dog B

En = 1/2 m * v^2m = 8 kgv = 4 m/sEn = 1/2 8 * 4^2En =   4 * 16En = 64 J

Dog C

En = 1/2 m * v^2m = 12 kgv = 5 m/sEn = 1/2 12 * 5^2En =   6 * 25En = 150 J

Dog D

En = 1/2 m * v^2m = 15 kgv = 3 m/sEn = 1/2 3 * 3^2En =   1.5 * 9En = 13.5 J

A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2

Answers

Refer to the photo taken.
Answer: Option D, 9.1 m/s^2
A 750 kg race car accelerates to the right. The engine applies a force of+7000 N to the car. The total

part 1 of 2
A runner is jogging in a straight line at a
steady u, 2.2 km/hr. When the runner is
L 4 km from the finish line, a bird begins
flying straight from the runner to the finish
line at v= 6.6 km/hr (3 times as fast as the
runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner.
24
finish
line
L
What cumulative distance does the bird
travel? Even though the bird is a dodo, as-
sume that it occupies only one point in space
(a "zero" length bird), travels in a straight
line, and that it can turn without loss of
speed.
Answer in units of km.
Answer in units of km

Answers

After the given information and solving it the cumulative distance the bird travel is 6 km.

Equation :

The given parameters of the motion are;

The velocity of the runner,

vr  = 2.2 km/hr

The distance from the finish line and the bird begins to fly from the runner to the finish line,

L = 4 km

The direction and speed of the runner = 6.6 km/hr in a straight line to the finish line and back to the runner

The speed of the bird = 4 × The speed of the runner

Given,

The length of the bird = 0

The bird turns without loss of speed

The time it takes the bird to reach the finish line,

t₁ = 4 km / (6.6 km/hr) = 0.606 hr

The distance the runner runs in time t₁,

d = 2.2 km/hr × 0.606 hr

d = 1.3332 km

The distance runner and  bird combined travel before they meet,

X, is given as follows;

X = L - d

X = 4 km - 1.3332 km

X = 2.667 km

We get; X = (vr + vb) x t

Which gives;

2.667 = ( 2.2 + 6.6) × t

t = 2.667/( 2.2 + 6.6 )

t =  2.667/(8.8)

t = 0.303

The time it take for the bird and the runner to meet,

t = 0.303 hour

The distance the bird travels before reaching the runner,

d₂ = vb x t

So,

d₂ = 6.6 km/hr × 0.303 hr = 2 km

The cumulative distance the bird travels dt = L + d2

dt = 4 km + 2km

dt = 6 km

The cumulative distance the bird travels by the time it reaches the runner dt = 6 km

Alternatively, we have;

db = d₁ + d₃

dr = d₂

d₁ + d₃ + d₂ = 2·L

So, dr + db = 2·L

dr = The distance runner runs before meeting with the bird

db = The distance bird travels before meeting with the runner

db = 4dr

So,

dr +  db = 3 × 4 = 12

dr + 4· dr = 4 · dr = 12

dr = 12 /4 = 3

db =3 × dr

db = 3 × 2

db = 6 km

The distance bird travels before meeting with the runner,

db = 6 km

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what is the kinetic energy of a 1,719.44kg car that travels at 9.22 m/s?

Answers

Given data:

* The mass of the car is 1719.44 kg.

* The velocity of the car is 9.22 m/s.

Solution:

The kinetic energy of the car in terms of mass and velocity is,

\(K=\frac{1}{2}mv^2\)

where m is the mass of the car, v is the velocity of the car, and K is the kinetic energy,

Substituting the known values,

\(\begin{gathered} K=\frac{1}{2}\times1719.44\times(9.22)^2 \\ K=73083.42\text{ J} \\ K=73.08\times10^3\text{ J} \\ K=73.08\text{ kJ} \end{gathered}\)

Thus, the kinetic energy of the car is 73083.42 J or 73.08 kJ.

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