7x - y = 4
Slope-Intercept Form:

The representation which is most appropriate for showing the change in the average hourly wage is: A. scatter plot with the title average hourly wage and the x axis labeled years since 2016 and the y axis labeled hourly wage in dollars, with points at 0 comma 9, 1 comma 9 and a half, 2 comma 10, 3 comma 11, 4 comma 12, 5 comma 13, and 6 comma 14.

In this scenario, the years would be plotted on the x-axis (x-coordinate) of the scatter plot while the hourly wage would be plotted on the y-axis (y-coordinate) of the scatter plot through the use of Microsoft Excel.

On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the line of best fit (trend line) on the scatter plot.

From the scatter plot (see attachment) which models the relationship between the years and hourly wage, an equation for the line of best fit is given by:

y = 0.8571x + 8.6429

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Answer:

$4.50

Step-by-step explanation:

If 8 pounds is 9 dollars, then each pound is $1.125, times 4 is $4.50.  Hope this helps :)

A pint = a pound = 0.4536L hence, both are true and Jules is right.

Given that,

Jules reads that 1 pint is a equivalent to 0. 473 liters. He asks his teachers how many liters there are in a pint. His teacher responds that there are about 0. 47 liters in a pint. He ask his parent, and they say there are about 0. 5 liters in a pint.

According to the given conditions;

The teacher rounded to the near hundredths and the parents rounded to the near tenths.

All of them rounded correctly.

A pint = a pound (if it's water) = 453.6 g = 0.4536 L

So, according to this scenario both the cases are true and Jules is right.

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The cartesian equation of the plane passing through point P =(1,0,2) and orthogonal to the vector <1,2,-1> is x + 2y - z = 3.

To find the cartesian equation of the plane, we first need to find the normal vector of the plane using the given vector.
The normal vector of the plane is the vector perpendicular to the plane. Since we are given that the plane is orthogonal to <1,2,-1>, we know that the normal vector is parallel to this vector.

Therefore, the normal vector of the plane is <1,2,-1>.Next, we use the point-normal form of the equation of a plane to find the equation of the plane. The point-normal form is given by: (x - x1)·n = 0 where (x1) is a point on the plane and n is the normal vector of the plane.

In this case, we have a point P = (1,0,2) on the plane and a normal vector n = <1,2,-1>. So the equation of the plane is:

(x - 1) + 2(y - 0) - (z - 2) = 0

which simplifies to:

x + 2y - z = 3

This is the cartesian equation of the plane passing through P = (1,0,2) and orthogonal to the vector <1,2,-1>.

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False. It is not optimal for Anil to give Bala one-third of the lottery money (£33.33). According to Anil's preferences, his utility function is given by u(A,B) = min{2A, B}.

This function implies that Anil values his own money (A) more than the money he gives to Bala (B). By giving Bala one-third of the money, Anil would keep only £66.67 for himself, which is less than what he could potentially keep if he gave Bala a smaller amount. To maximize his own utility, Anil should give Bala the minimum amount possible, which in this case would be zero.

Anil's utility function indicates that he values his own money (A) twice as much as the money he gives to Bala (B). By maximizing his utility, Anil would want to keep as much money for himself as possible, while still giving Bala some amount of money. In this case, Anil can keep £100 for himself, which is the maximum amount possible, while giving Bala £0.

This division of money maximizes Anil's utility according to his preferences. Therefore, it is not optimal for Anil to give Bala one-third of the lottery money; instead, he should give Bala the minimum amount of £0 to maximize his own utility.

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a) Bar chart for the distribution:

Amount (in cedis)     |  No of Students

-------------------------------------

1.00                  |     1

2.00                  |     3

3.00                  |     2

4.00                  |     5

5.00                  |     1

b) i) The mean is 3.17 cedis (corrected to the nearest pesewa).

ii) The median is 4.00 cedis.

iii) The mode is 4.00 cedis.

a)For the distribution, a bar graph

Amount (in cedis)     |  No of Students

-------------------------------------

1.00                  |     1

2.00                  |     3

3.00                  |     2

4.00                  |     5

5.00                  |     1

-------------------------------------

b) i) Mean: To find the mean, we need to calculate the sum of the products of each amount and its corresponding frequency, and then divide it by the total number of students.

Sum of products = (1.00 * 1) + (2.00 * 3) + (3.00 * 2) + (4.00 * 5) + (5.00 * 1) = 1.00 + 6.00 + 6.00 + 20.00 + 5.00 = 38.00

Total number of students = 1 + 3 + 2 + 5 + 1 = 12

Mean = Sum of products / Total number of students = 38.00 / 12 = 3.17 cedis (corrected to the nearest pesewa)

ii) Median: To find the median, we need to arrange the amounts in ascending order and determine the middle value. Since the total number of students is 12, the middle value would be the 6th value.

Arranging the amounts in ascending order: 1.00, 2.00, 3.00, 3.00, 4.00, 4.00, 4.00, 4.00, 4.00, 5.00, 5.00, 5.00

The 6th value is 4.00, so the median is 4.00 cedis.

iii) Mode: The mode is the value that appears most frequently. In this case, the mode is 4.00 cedis since it appears the most number of times (5 times).

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Answer:

19,27 cm^2

Step-by-step explanation:

area of triangle = (6 x 3)/ 2 = 9 cm^2

circle area : 3^2 x 3,14 = 28,27 cm^2

area of shaped region = 28,27 - 9 = 19,27 cm^2

The ratio test can be used to determine the radius of convergence. To the specified series,

an = (-1)^n-1 * (3x - 8)^n / (n - 8^n)

How to determine the radius of convergence and the interval

The ratio of successive terms is

a_n+1 / a_n = (3x - 8)/(n - 8^n) * (n - 8^n)/(3x - 8) = n - 8^n

By the Ratio Test, the series converges when \(lim_n- > ∞ |a_n+1 / a_n| < 1.\)This is equivalent to

\(lim_n- > ∞ |n - 8^n| < 1\)

The absolute value on the left-hand side can be factored as

\(|n - 8^n| = |n - 8| * |1 - 8^(n-1)|\)

Since 0 < 8 < 1, we know that |1 - 8^(n-1)| < 1 for all n. Therefore, the series converges when

|n - 8| < 1

This is the same as 7 + n + 9. Thus, R = is the radius of convergence.

1.

The interval of convergence is (7, 9). To see this, we can check the endpoints, x = 7 and x = 9.

If x = 7, the series becomes

SUM(n=1,n=[infinity]) \((−1)^n−1 * (21)^n / n - 8^n\)

This is a multiple of the known convergent geometric series 1/(1 - 21).

If x = 9, the series becomes

SUM(n=1,n=[infinity]) \((−1)^n−1 * (27)^n / n - 8^n\)

This is a multiple of the geometric series 1/(1 - 27), which is known to diverge.

As a result, the convergence interval is (7, 9).

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Answer: 14x^5 + 17x^4 - 87x^3 + 60x^2 + 15x - 18

Step-by-step explanation: You would need to simplify the expression by using distributive property.

Answer:

Step-by-step explanation:

x + 12 = y

x = y - 12

Answer:

B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Step-by-step explanation:

P1: 12^2+15^2=20^2  144+225=400  369=400

P2: 16^2+30^2=34^2  256+900=1156  1156=1156

P3: 20^2+21^2=29^2  400+441=841  841=841

P4: 18^2+20^2=26^2  324+400=676  724=676

So the answers are B and E

Answer:

b and e

Step-by-step explanation:

According to ASC 420 Exit or Disposal Cost Obligations, exit or disposal cost obligations are liabilities that arise from one-time termination benefits provided to employees, costs associated with closing a facility, and other expenses incurred as a result of an exit or disposal activity.

These obligations are recognized and measured based on the principles of other applicable GAAP.

The relevant topic number for exit or disposal cost obligations is Topic 420. The specific eight-digit codification citation (XXX-XXXXX) that addresses the initial measurement of these obligations is 420-10-25-1. This paragraph notes that the fair value of the liability at the initial recognition date is the amount for which these obligations and related costs are measured.

The amount for which these obligations and related costs are measured is determined based on the fair value of the liability at the initial recognition date. This amount includes the estimated costs associated with employee severance arrangements, lease termination fees, and other direct costs associated with the exit or disposal activity.

The specific eight-digit codification citation (XXX-XX-XX-X) that describes the disclosure requirements in the notes to the financial statements for exit or disposal obligations is 420-10-50-2. This paragraph requires entities to disclose information about the nature and scope of the exit or disposal activity, including its timing, the expected completion date, the associated costs, and any significant uncertainties or risks that could affect the outcome or timing of the activity.

In summary, under ASC 420, exit or disposal cost obligations are recognized and measured based on their fair value at the initial recognition date. Entities are required to disclose information about the nature and scope of the exit or disposal activity, as well as any significant uncertainties or risks that could affect the outcome or timing of the activity.

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Answer:

Pretty sure it is Product of Powers Property

Step-by-step explanation:

Answer: x=33/5

Step-by-step explanation:

5x-28=5

5x=33

x=33/5

Answer:

p=13

Step-by-step explanation:

Answer:

\(\boxed{\bold{\huge{\boxed{x = 26}}}}\)

Step-by-step explanation:

\(70 = \frac{4x+36}{2}\)

Multiplying both sides by 2

\(70 * 2 = 4x+36\)

\(140 = 4x+36\)

Subtracting 36 to both sides

\(140 - 36 = 4x\)

\(104 = 4x\)

Dividing both sides by 4

\(26 = x\)

OR

\(x = 26\)

Answer:

x=26

Step-by-step explanation:

\(70=\frac{4x+36}{2}\\ 70*2=4x+36\\140=4x+36\\4x=140-36\\4x=104\\\frac{4x}{4}=\frac{104}{4}\\ x=26\)

check

70=(4x+36)/2

70=(4*26+36)/2

70=(104+36)/2

70=140/2

70=70

a. 80% of 90 is the same as of 90 - False

b. 45% of 60 is 27 - True

c. 20% of 90 is the same as as of 90- True

d. 25 is 35% of 80 -False

a. 80% of 90 is not the same as 90. To find 80% of 90, we multiply 90 by 0.8, which gives us 72. Therefore, the statement is false.

b. To find 45% of 60, we multiply 60 by 0.45, which gives us 27. Therefore, the statement is true.

c. 20% of 90 is the same as of 90. To find 20% of 90, we multiply 90 by 0.2, which gives us 18. Therefore, the statement is true.

Lastly, for question d. 25 is not 35% of 80. To find 35% of 80, we multiply 80 by 0.35, which gives us 28. Therefore, the statement is false.

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Answer:

?

Step-by-step explanation:

54,675+33,548,000x^1+a^2=

get rid of ^1 cuz that doesn't change the value

a^2 can be written as 2a because a^2= a*a and 2a= a*a

54,675+33,548,000x+2a

54,675+33,548,000x= -2a-54675

33,548,000x=-2a-54675

16774000x=-a-27337.5

x=-a - 27337.5

x=-a-27337.5/ 16774000

I obviously know this isn't a real question but here

Answer:

Step-by-step explanation:hey Karlie

The required fraction of chicken,whose are laying eggs irregularly.

Multiply the numerators and denominators independently to track down the item. At the point when you need to duplicate divisions, increase the 2 numerators together first and compose it on top. Then duplicate the denominators together and compose it on the lower part of the portion. Work on your response in the event that you would be able so it is in the least terms.

9/15 chickens are laying eggs regularly and 2/15 chickens never lay eggs.

Then,fraction of chicken

1 - 9/15 - 2/15

15 - 9 - 2/15

4/15

Thus, the fraction of chicken are 4/15

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Correct question:

9/15 of David's chickens lay

eggs every day. 2/15 of the chickens never lay any eggs. What fraction of the chickens lay eggs irregularly.

Answer:

The answer is A.

Step-by-step explanation:

It is a 9 to 1 ratio because as you see on the graph, for each lemon-lime cup, there are 9 peach juice cups. And as you keeping going up, the ratio is the same.

Answer: A

Step-by-step explanation: I'm totally a smart 8-year-old.

Answer:

  (w -3)(w +10)

Step-by-step explanation:

The product of two binomial factors looks like ...

  (x +a)(x +b) = x² +(a+b)x +ab

This means you want to find values 'a' and 'b' such that ...

You can do this by looking at factor pairs of -30 that have positive sums:

  -30 = (-1)(30) = (-2)(15) = (-3)(10) = (-5)(6)

The sums of these factor pairs are 29, 13, 7, 1. You want the factor pair with a sum of 7, so 'a' = -3 and 'b' = 10.

  w^2 +7w -30 = (w -3)(w +10)

Answer: Michaela's answer

Step-by-step explanation:

Dema added the numbers together

Answer: 3.333333333

Step-by-step explanation:

Put 5 divided by 1.5 (1 1/2) in a calculator.

A two-sided confidence interval is appropriate because the research question is about whether the average mileage is significantly different from 300 miles.

(a) To determine if a one-sided or two-sided confidence interval is appropriate for this situation, we need to consider the research question and the nature of the hypothesis being tested. If the research question is specifically focused on whether the average mileage is less than or greater than 300 miles, then a one-sided confidence interval would be appropriate. On the other hand, if the research question is broader and seeks to determine whether the average mileage is significantly different from 300 miles (i.e., it could be less or greater), then a two-sided confidence interval would be appropriate.

(b) To compute a 95% confidence interval, we can use the formula:

CI =X ± (Z * (σ/√n))

Where X is the sample mean, Z is the z-value corresponding to the desired confidence level (in this case, 95% corresponds to Z = 1.96 for a large enough sample), σ is the population standard deviation (unknown, so we use the sample standard deviation), and n is the sample size.

Plugging in the given values:

CI = 285 ± (1.96 * (50/√226))

Simplifying the expression:

CI = 285 ± (1.96 * 3.322)

CI = [278.15, 291.85]

Interpretation: The 95% confidence interval for the average mileage from Pullman to home is [278.15, 291.85]. This means that we are 95% confident that the true average mileage of all Washington State University students falls within this interval. It suggests that based on the sample data, the average mileage is likely to be between 278.15 and 291.85 miles.

(c) If the confidence level is decreased to 90%, the new confidence interval will be narrower since a smaller confidence level requires less certainty, resulting in a narrower interval. Conversely, if the confidence level is increased to 99%, the new confidence interval will be wider as a higher confidence level demands greater certainty, leading to a wider interval to capture a larger range of potential values. Therefore, the answer is D. narrower for a confidence level of 90% and A. wider for a confidence level of 99%.

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The diver's velocity during the first 2 sec of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

Given data: Initial velocity, u = 0 ft/sec

Acceleration, a = g = 32.2 ft/sec²

The maximum rate of fall, vmax = 80 mph

Time, t = 2 seconds

Air resistance constant, Ar = 0.2

We are supposed to determine the sky diver's velocity during the first 2 seconds of fall using the modified Euler method.

The governing equation for the velocity of the skydiver is given by the following:

ma = -m * g + k * v²

where, m = mass of the skydive

r, g = acceleration due to gravity, k = air resistance constant, and v = velocity of the skydiver.

The equation can be written as,

v' = -g + (k / m) * v²

Here, v' = dv/dt = acceleration

Hence, the modified Euler's formula for the velocity can be written as

v1 = v0 + h * v'0.5 * (v'0 + v'1)

where, v0 = 0 ft/sec, h = 2 sec, and v'0 = -g + (k / m) * v0² = -g = -32.2 ft/sec²

As the initial velocity of the skydiver is zero, we can write

v1 = 0 + 2 * (-32.2 + (0.2 / 68.956) * 0²)0.5 * (-32.2 + (-32.2 + (0.2 / 68.956) * 0.5² * (-32.2 + (-32.2 + (0.2 / 68.956) * 0²)))

v1 = 62.732 mph

Therefore, the skydiver's velocity during the first 2 seconds of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

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The value of the expression is simplified to x = 6/5

Algebraic expressions are defined as expressions composed of terms, variables, constants, coefficients and factors.

They are also identified with the presence of arithmetic operations, such as;

From the information given, we have;

25x² - 14 = 22

collect the like terms

25x² = 36

Find the square root of both sides

5x = 6

Make 'x' the subject

x = 6/5

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The number of triangles for every 3 circles is given as follows:

C. 5.

The number of triangles for every 3 circles is obtained applying the proportions in the context of the problem.

From the figure, we have that:

Hence the number of triangles per circle is given as follows:

10/6 = 5/3.

Hence the number of triangles for 3 circles is given as follows:

3 x 5/3 = 5.

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Answer:

I think the answer would be D. 20 hope it helps

Step-by-step explanation: