72pts
What is the mechanical advantage of the wheel and axle shown below?

0.8 cm 26 cm​

Answer:

kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case =  4 m/s when m = 0.125 kg KE = (0.5) m v² =  (0.5) (0.125) (4)²

Explanation:

Answer:

1. 0.5    2.  2    3. 3.75    4.  5

Explanation:

a. The student's final position is 100.5 meters at an angle of 25.2° north of east from her initial position and b. The student would have to head in the direction of 334.8° south of east to return to her initial position.

a. To find the student's final position, we can use vector addition. We can start by breaking each displacement vector into its x- and y-components. First displacement (70 m at 37° north of east),

x-component = 70 cos(37°) = 56.02 m

y-component = 70 sin(37°) = 42.49 m

Second displacement (82 m at 20° south of east),

x-component = 82 cos(-20°) = 78.72 m

y-component = 82 sin(-20°) = -28.12 m

Third displacement (28 m at 30° west of north),

x-component = 28 sin(30°) = 14 m

y-component = 28 cos(30°) = 24.24 m

We can add the x-components and y-components separately to get the total displacement,

x-displacement = 56.02 m + 78.72 m - 14 m = 120.74 m

y-displacement = 42.49 m - 28.12 m + 24.24 m = 38.61 m

The magnitude of the total displacement is,

|d| = √(x-displacement² + y-displacement²)

|d| = √(120.74² + 38.61²)

|d| = 126.0 m.

The direction of the total displacement can be found using the inverse tangent function,

θ = atan(y-displacement/x-displacement)

θ = atan(38.61/120.74)

θ = 17.4° north of east. Therefore, the student's final position is 126.0 m at 17.4° north of east.

b. To return to her initial position, the student would need to walk the same distance and direction as her total displacement but in the opposite direction. The opposite direction of 17.4° north of east is 162.6° south of west. Therefore, she would need to walk 126.0 m at 162.6° south of west to return to her initial position.

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The height that will illustrate the distance will be d = 6.36m

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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For a longitudinal wave, the compression region, is the one represented by the densely packed particles with high pressure and the region with loosely packed particles is called rarefaction. Hence, the first part is C he dense region and the second one with some space between the dots is labeled as R.

Longitudinal waves are a type of mechanical waves passing through a medium. Unlike electromagnetic waves, they cannot be passed through vacuum.

In a longitudinal wave, the oscillation of particles is along the direction of wave propagation. The wave is composed of high pressure regions and low pressure regions called compressions and rarefactions respectively.

The regions where, particles are densely packed and shows the thick dote are labelled as compressions and the regions where, some space between particles are labeled as rarefactions.

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Answer:

Option C.

Explanation:

To know which velocity-time graph best describes the motion of the ball, let us calculate the velocity of the ball and the time taken for the ball to get the ground. This can be obtained as follow:

1. Determination of the velocity.

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 100 m

Final velocity (v) =.?

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 100)

v² = 0 + 1960

v² = 1960

Take the square root of both side.

v = √(1960)

v = 44.27 m/s

2. Determination of the time taken.

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 100 m

Time (t) =.?

h = ½gt²

100 = ½ × 9.8 × t²

100 = 4.9 × t²

Divide both side by 4.9

t² = 100 / 4.9

Take the square root of both side

t = √(100 / 4.9)

t = 4.52 s

From the above illustration,

Initial time (t1) = 0 s

Final time (t2) = 4.52 s

Initial velocity (u) = 0 m/s

Final velocity (v) = 44.27 m/s

Thus, we can see that as the time increase, the velocity also increase. Therefore, option C gives the correct answer to the question.

Answer:

matter

Explanation:

Hope I helped :)

Answer:

a)A-B =(1,0,-3) +(2,-5,-1) =(3, -5, -4);    

b)B-C =(-2-3, 5-1, 1-1) = (-5,4,0);  

c)-A +(B –C) = (-1,0,3) +(-5,4,0) =(-6,4,3);  

d) =(3,0,-9) –(6,2,2) = (-3, -2, -11);  

e) = (-2,0,6) +(-6,15,3) +(-3,-1,-1) =

d) = (2,0,-6) –(-5*3, 4*3, 0) =  

Explanation:

1)C=k*A = (k*a1, k*a2, k*a3);

2)C=-A = -1*A;

3)C= A+B = (a1+b1, a2+b2, c2+c2);

4)C=A-B =A +(-B);  

5)A+B=B+A;  

6)A+B+C =(A+B)+C =A+(B+C

Answer:

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Explanation:

Answer:

As you go talk to her or even before you go talk to her. If that's the case however, start talking to everyone you meet both boys and girls. See, improving your communication with women is easy. Just get a few books on social skills and then go over to talk to all the ladies you see without any hidden agenda.

Explanation:

I really hope this helps your question  ^_^

Answer:

The difference in angle of refraction between the red and blue light is 0.2°

Explanation:

Here is the complete question

Sunlight strikes a piece of crown glass at an angle of incidence of 37.4°. Calculate the difference in the angle of refraction between a red (660 nm) and a blue (470 nm) ray within the glass. The index of refraction is n=1.520 for red and n=1.531 for blue light.

Solution

From Snell's law refractive index n = sini/sinr where i = angle of incidence and r = angle of refraction.

Now for the red light n₁ = 1.520, i = 37.4° and r₁ = angle of refraction of red light

So, n₁ = sini/sinr₁

n₁sinr₁ = sini

sinr₁ = sini/n₁

r₁ = sin⁻¹(sini/n₁) = sin⁻¹(sin37.4°/1.52) = sin⁻¹(0.6074/1.52) = sin⁻¹(0.3996) = 23.55°

Now for the blue light n₂ = 1.531, i = 37.4° and r₂ = angle of refraction of blue light

So, n₂ = sini/sinr₂

n₂sinr₂ = sini

sinr₂ = sini/n₂

r₂ = sin⁻¹(sini/n₂) = sin⁻¹(sin37.4°/1.531) = sin⁻¹(0.6074/1.531) = sin⁻¹(0.3967) = 23.37°

So the difference in angle of refraction between the red and blue light is r₁ - r₂ = 23.55° - 23.37° = 0.18° ≅ 0.2°

Kinetic energy is the energy an object has due to its Motion.

Kinetic energy is a characteristic of a moving particle. It is a type of energy that a matter or particle possesses due to its motion.

It is expressed:

\(K_E = \frac{1}{2}mv^2\)

Where m is the mass of the particle and v is velocity.

Hence, Kinetic energy is the energy an object has due to its Motion.

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Answer:

(4,5) and (8,10) what is the slope

Explanation:

After school, a student rides his bike back home. The student lives 750 meters from the school. If it takes the student 3 minutes to get home, what is his average speed?

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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In this scenario, the cat sliding down the rubber rod and falling into metal pail "a" caused the transfer of charge to pail "a". This transfer of charge caused pail "a" to become charged and the metal pails "b" and "c" that were in contact with it, were also charged by induction.

When the shelf broke, the metal pails fell separated to the non-conducting floor, resulting in the charge being separated and no longer being able to move from one metal pail to another.

After the cat ran away, the charged metal pails likely remained charged, as there was no conductor available for the charge to flow through and neutralize.

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Hi there!

1.

Since the two resistors are in series, we can simply add:
\(R_T = R_1 + R_2 + ... R_n\)

\(R_T = 20 + 5 = \boxed{25 \Omega}\)

2.

In series, the potential difference of each resistor (lamp) ADDS UP. We can begin by finding the current through the circuit using Ohm's law:
\(V = IR\\\\I = \frac{V}{R_T}\)

Plug in the values:
\(I = \frac{50}{25} = 2 A\)

Now,

we can use Ohm's law to find the individual voltage for each lamp.

20 Ohm lamp:
\(V = 2 * 20 = \boxed{40 V}\)

5 Ohm lamp:
\(V = 2 * 5 = \boxed{10 V}\)

3.

To solve, we can use the power equation.

\(P (\text{Watts})= IV\)

Plug in the values for each.

20 Ohm lamp:
\(P = 2 * 40 = \boxed{80 W}\)

5 Ohm lamp:
\(P = 2 * 10 = \boxed{100 W}\)

Answer:

C

Explanation:

trust me

D. Fixed position ,mean position , Equilibrium position.

Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.

The particles of the medium vibrate about their equilibrium position in a direction parallel to the direction of propagation of the wave is called a longitudinal waves.

Characteristics of Wave Motion

In wave motion, the disturbance travels through the medium due to repeated periodic oscillations of the particles of the medium about their mean position (or) Equilibrium position.

Energy and momentum are transferred from one point to another without any actual transfer of the particles of the medium.

There is a regular phase difference between the particles of the medium because each particle receives disturbance little later than its preceding particle.

Therefore,

In a wave, each particle of the medium vibrates, or oscillates, around a fixed position.

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Answer:(a) To find the height of the satellite's orbit if its total energy were 550 MJ greater, we can use the following equation:

K2 + U2 = K1 + U1 + 550 MJ

Since the satellite is in a circular orbit, its kinetic energy is given by:

K = (1/2)mv^2

where m is the mass of the satellite, and v is its velocity.

We can use the following equation to relate the height of the satellite's orbit to its velocity:

v = sqrt(GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth plus the height of the satellite's orbit.

Therefore, we can express the kinetic energy of the satellite in terms of its height:

K = (1/2)m(GM/R)

Using these equations, we can rewrite the conservation of energy equation as:

(1/2)m(GM/(R1+h1)) - GMm/(R1+h1) = (1/2)m(GM/(R2+h2)) - GMm/(R2+h2) + 550 MJ

where R1 is the radius of the Earth, and R2 is the radius of the Earth plus h2.

Simplifying and solving for h2, we get:

h2 = [(GMm/(R1+h1)) - (GMm/(R2+h2)) - 550 MJ/(GM/(R2+h2))]^(-1) - R2

Plugging in the given values, we get:

h2 = 931 km

Therefore, the height of the satellite's orbit would be 931 km if its total energy were 550 MJ greater.

(b) To find the difference in the system's kinetic energy, we can use the following equation:

Delta K = K2 - K1

Substituting the expressions for K1 and K2, we get:

Delta K = (1/2)m(GM/(R2+h2)) - (1/2)m(GM/(R1+h1))

Plugging in the given values, we get:

Delta K = -7.5 x 10^9 J

The negative sign indicates that the system's kinetic energy has decreased.

(c) To find the difference in the system's potential energy, we can use the following equation:

Delta U = U2 - U1

Substituting the expressions for U1 and U2, we get:

Delta U = -GMm/(R2+h2) + GMm/(R1+h1)

Plugging in the given values, we get:

Delta U = 5.9 x 10^9 J

The positive sign indicates that the system's potential energy has increased.

Explanation:

Given,

The initial velocity of the projectile, u=128 ft/s

The acceleration due to gravity, g=-32 ft/s²

After reaching the maximum height the velocity of the projectile will be v=0 m/s

The time(t₁) required for the projectile to reach the maximum height is given by,

On substituting the known values,

The maximum height (h) reached by the projectile is given by,

On substituting the known values,

The time (t₂) required for the projectile to come back to the ground from its maximum height is calculated using the formula,

Here the value of the height will take a negative value because the projectile will be covering that distance when it is falling downwards

On substituting the known values,

Thus the total time in which the projectile returns to the ground is

A) Thus the projectile will return to the ground in 8 s

B) The maximum height reached by the projectile is 256 ft

C)

The height, h=240 ft

The time(t₃) required to reach this height is given by,

On substituting the known values,

On solving the above equation,

And

Thus the projectile will reach the height at 3s when going up and again at 5s when coming down.

According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.

The formula for the specific heat capacity (C) = Q/ m × ΔT

Q is energy added and the value, which is 334J

m is the mass of the lemonade, which is 300g = 0.3 kg

Δ T is the change in temperature, which is 19°C =(273+19)= 292 K

So, C = 334/ 0.3 × 292

         = 3.81 J/kg/k

So the specific heat capacity of the lemonade is 3.81 J/kg/k.

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In a tree if the same rock is placed in four different locations, the rock will have the most potential energy.

Potential energy is a form of energy stored that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised just above ground as opposed to falling to the ground, it has more potential energy. An object has potential energy as a result of its position in relation to other objects. Potential energy is so named because it has the ability to transform into other types of energy, like kinetic energy.

Potential energy is the energy that is held within a material or an object. Energy in an object held vertically is known as gravitational potential energy. Potential energy that can be stretched or compressed is known as elastic potential energy.

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Answer:

Explanation:

Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:

v_f^2 = v_i^2 + 2ad

where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)

and

d = v_i t + (1/2)at^2

where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.

First, we need to resolve the initial velocity into its vertical and horizontal components:

v_i_x = v_i cos(30°) = 121.1 m/s

v_i_y = v_i sin(30°) = 70.0 m/s

Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:

v_f = v_i_y + at

0 m/s = 70.0 m/s + (-9.8 m/s^2)t

t = 7.14 s

Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:

d = v_i_y t + (1/2)at^2

d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2

d = 247.5 m

Therefore, the peak height of the football is 247.5 meters.

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 Goodluck

Explanation:

Nuclear power plants have backup generators to ensure that essential equipment, such as cooling systems, can continue to function in the event of a power outage or other emergency.

Nuclear power plants rely on a constant supply of electricity to operate the equipment that controls the nuclear reaction and cools the reactor. If the power supply is interrupted, the reactor can overheat and damage can occur. Backup generators provide power to essential equipment, such as cooling systems, that keep the reactor and spent fuel pools from overheating.  If the backup generators fail, there is a risk of a nuclear accident, as was seen in the disaster in 2011, where the failure of backup generators led to a loss of cooling and a major nuclear incident.

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The effort required to compress an ideal gas is therefore given by W = -1/2 nRT ln(V2/V1) during an isothermal process.

When an ideal gas is subjected to isothermal expansion (T = 0) in a vacuum, the work done is equal to zero as pex=zero. Joule established q = 0 empirically; hence, U = 0. Equation 1 can be written as: for both reversible and irreversible isothermal changes. Reversible isothermal change q = -w = pex (Vf-Vi)

nRT = ln(V2/V1) - W

If we solve for W, we obtain:

W = ln(V1/V2)nRT (v) If we condense this phrase, we get:

W=-nRT ln(V2/V1).

W=-RT ln(V2/V1).

W=-1/2nRT ln(V2/V1)

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Answer:

Explanation:

Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.

Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.

As the mass of the central star increases, the distance to the habitable zone increases and the size (width) of the habitable zone also increases.

The habitable zone is the distance from a star at which the liquid water could exist on the orbiting planet's surfaces. Habitable zone is also known as Goldilocks' zones, where the environmental conditions might be just right neither too hot nor too cold for life.

A star is a large luminous object which is found in space that produces heat and light energy as well as electromagnetic radiations. The habitable zone of a star is the zone where liquid water can be found. The distance to the habitable zone of a star increases with the increase in mass of the star.

Therefore, as the mass of the central star increases, the distance to the habitable zone also increases.

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Answer: Z

Explanation: I took the quiz!! :3

During a solar eclipse as seen from Earth, the moon will be at the position Z.

When the Moon moves in front of the Sun, obstructing the Sun's view for a small portion of the Earth either completely or partially, this is known as a solar eclipse.

Here,

When the Moon is in its new moon phase, when its orbital plane is closest to that of the Earth's, and during eclipse season, such an alignment takes place roughly every six months. The Sun's disc is completely covered by the Moon during a total eclipse. The Sun is only partially covered by annular and partial eclipses. A solar eclipse can only be seen from a relatively restricted area of the earth, in contrast to a lunar eclipse, which can be seen from anyplace on the night side of Earth.

The Moon is parallel to the line connecting the Earth and the Sun at its first and final quarters. Only one-half of the Moon is visible to us as being illuminated by the Sun; the other one-half is hidden in shadow.

Hence,

During a solar eclipse as seen from Earth, the moon will be at the position Z.

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