72 pointsWhat postulate or theorem can you use to prove the pair of triangles are congruent? Name the missing congruence statement.DCA ABC A type your answer...by type your answer...

The value of the total area of the shaded region are,

⇒ 42 units²

We have to given that;

Sides of rectangle are,

AB = 9

BC = 6

Hence, The area of rectangle is,

⇒ 9 x 6

⇒ 54 units²

And, Area of triangle is,

A = 1/2 × 4 × 6

A = 12 units²

Thus, The value of the total area of the shaded region are,

⇒ 54 - 12

⇒ 42 units²

So, The value of the total area of the shaded region are,

⇒ 42 units²

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If you have a trend then the process is non-stationary, but if you account for the time trend, it's still stationary around the line.

What is Null hypothesis?

The null hypothesis in inferential statistics is that two possibilities are equal. The underlying assumption is that the observed difference is just the result of chance. It is feasible to determine the probability that the null hypothesis is correct using statistical testing.

Consider the given process:

      \(x_{t} = c+\alpha x_{t-1}+\beta _{t} \\E[\beta _{t}]=0\\\)

Obtain mean,

     \(E[x _{t}]=\frac{c}{1-\alpha }\)

This works only when |α|<1. If α=1 this doesn't work, it blows up, because , \(E[x _{t}]\neq E[x _{t-1}]\) i.e. the process is not stationary.

The constant refers to the term c.

The trend is easy too:

    \(x_{t} +c+\alpha t+\alpha x_{t-1} +\beta_{t}\)

In this case,

  \(E[x _{t}]=\frac{c+\alpha t}{1-\alpha }\)

So, if you have a trend then the process is non-stationary, but if you account for the time trend, it's still stationary around the line.

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Answer:

b Huda found the product of –3 and 9 as positive.

yeah-

Answer:

The second dealer is better.

Step-by-step explanation:

3.8/2=   2.7/1.5=

3.8/2=1.9 (first vendor)   2.7/1.5=1.8 (second vendor) 1.8 is less than 1.9.

Answer:

24

Step-by-step explanation:

yur welcome

Assuming the track is straight, the distance at which they are apart one hour before they meet is; 30 km

We are told that a Nonstop trains leave Toronto and Montreal at the same time each day going to the other city along the main line.

Speed of Train 1 = 120 km/h

Speed of Train 2 = 90 km/h

Time spent by train 1 = 1 hour

Time spent train 2 = 1 hour

Formula for distance is;

Distance = Speed * time

If they leave the same time each day, it means that;

Distance of train 1 = 120 * 1 = 120 km

Distance of train 2 = 90 * 1 = 90 km

Thus, distance at which they will be apart before meeting each other is;

Distance apart = 120 - 90

Distance apart = 30 km

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Answer:

y=-1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-(-1))/(-5-0)

m=(-1+1)/-5

m=0/-5

m=0

y-y1=m(x-x1)

y-(-1)=0(x-0)

y+1=0

y=0-1

y=-1

1:

cos (37)= 11/x

x(cos(37))= 11

x= 11/cos(37)

x= 14.4

2:

tan (0)= 4/13

0= tan^-1/ 4/13

0= 0.3

x= 0.3

Step-by-step explanation:

solution:

A.

relation between hypotenuse and base is given by cos angle

so

\( \cos(ø) \)=base/hypotenuse=11/x

cos37°=11/x

x=11/(cos37°)=13.77units

side indicated =x=13.77units

solution:

B.

relation between perpendicular and base is given by tan angle

so

\( \tan(ø) \)=perpendicular/base=4/13

ø=tan-¹ (4/13)=17.10°

angle indicated =ø=17.10°

The distance between the two parallel sides of the trapezium is 8 cm.

A trapezium is a convex quadrilateral with exactly one pair of opposite sides parallel to each other.

The area of a trapezium is expressed as:

Area = 1/2 × ( a + b ) × h

Where a and b are base a and base b, h is height.

Given that:

Area of the trapezium = 36 cm²

Base a = 3 cm

Base b = 6 cm

Height h =?

Plug the given values into the above formula and solve for height:

Area = 1/2 × ( a + b ) × h

36 = 1/2 × ( 3 + 6 ) × h

36 = 1/2 × ( 9 ) × h

36 = 4.5 × h

h = 36 / 4.5

h = 8 cm

Therefore, the height of the trapezium is 8 cm.

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Answer: No, the pythagorean Theorem can only be done on right triangles.

Step-by-step explanation:

The shift of the function y = log(x+4) -3 is 4 units left and 3 units down

From the question, we have the following parameters that can be used in our computation:

y = log(x + 4)

The above equation is a logarithmic equation

So, the parent function is

y = log(x)

When the parent function is compared to the given function, we have

3 units down and 4 units left

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Answer:

y= -1/4x + 3

Step-by-step explanation:

y-y1 = m(x-x1)

(-8 {x1}, -5 {y1}, -1/4 [m] )

We'll then replace the letters with the available figures.

y-[-5] = -1/4 (x-[-8])

We are made to know that minus + minus= plus

Minus + plus= Minus

Minus x minus = plus

minus x plus = minus

Therefore, the mathematical setting of this question becomes,

y+5 = -1/4 (x+8)

Multiply everything in the bracket with the outside value

-1/4 x X = -1/4x

-1/4 x 8 = -2

The mathematical setting then becomes,

y+5 = -1/4x + -2 (Note: plus + minus = minus)

so, it becomes

y+5 = -1/4x - 2

The equation is supposed to look like this, y= mx + b

Therefore we add +5 to both sides to cancel out

 y+5 = -1/4x - 2

   +5            +5

+5 cancels out +5 which makes the setting,

y= -1/4x - 2 +5 (-2+5 goes around to become 5-2= 3)

The expression now looks like this

y= -1/4x +3 which is the final answer!

\(y= -1/4x + 3\)

Replicate measurements of 14 and 33 are necessary to decrease the 95 and 99% confidence limits to +0.19ug Cu/mL respectively.

a) For a 95% confidence limit, N is about 14

b) For a 99% confidence limit, N is about 33

To determine the number of replicate measurements necessary to achieve a desired confidence limit, we can use the formula:

\(N = (z * Spooled / d)^2\)

where z is the Z-score associated with the desired confidence level (from the table provided), Spooled is the pooled standard deviation, and d is the desired decrease in the confidence limit.

\(N = (1.96 * 0.27 / 0.19)^2 = 14.22 = 14\) (rounded to the nearest integer)

\(N = (2.58 * 0.27 / 0.19)^2 = 33.06 = 33\) (rounded to the nearest integer)

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Complete Question:

An atomic absorption method for the determination of copper in fuel samples yielded a pooled standard deviation of Spooled = 0.27ug Cu/mL (s-->Sigma). How many replicate measurements are necessary to decrease the 95 and 99% confidence limits to +0.19ug Cu/mL?

Confidence Level%/z 95%/1.96 99%/2.58

a) For a 95% confidence limit, N is about __?

b) For a 99% confidence limit, N is about __?

Answer: 2cm

Step-by-step explanation:

Answer:

122

Step-by-step explanation:

64 + 58 = (l)

(l) = 122

Answer:

1.75 × 10⁶

Step-by-step explanation:

7,000,000 ÷ 4 = 1750000

Which is 1.75 × 10⁶ in standard form

Reason:

The 24 needs to be changed to a 10 for it to be in scientific notation.

The template for scientific notation is \(a * 10^b\) where \(0 \le |a| < 10\)

So for example, \(1.23 \times 10^4\) is in scientific notation.

The probability of both 1 and 6 being observed at least once when rolling a die n times is given by P(A ∪ B), which is equal to 1 - (11/6)^n + (2/3)^n.

To find the probability that numbers 1 and 6 are both observed at least once when rolling a die n times, we can use the principle of inclusion-exclusion.

Let A be the event that 1 is not observed in n rolls, and B be the event that 6 is not observed in n rolls.

Then, the probability of A and B not occurring is (5/6)^n and the probability of their union, denoted by A ∪ B, is 1 - (5/6)^n.

However, this includes cases where neither 1 nor 6 are observed at least once. To exclude these cases, we can use the same principle to count the number of ways in which neither 1 nor 6 are observed and subtract it from the total number of possible outcomes, which is \(6^n\).

Let C be the event that neither 1 nor 6 are observed in n rolls. Then, the probability of C occurring is (4/6)^n = (2/3)^n. By inclusion-exclusion, the probability of both 1 and 6 being observed at least once in n rolls is:

P(A ∪ B) = 1 - (5/6)^n - (5/6)^n + (2/3)^n

Simplifying this expression gives:

P(A ∪ B) = 1 - (11/6)^n + (2/3)^n

Therefore, there are 1 - (11/6)^n + (2/3)^n probability that numbers 1 and 6 are both observed at least once.

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The population of the town in 5 years will be approximately 28,982.

A data pattern known as exponential growth exhibits faster expansion over time. Compounding generates exponential profits in finance. Exponential growth is possible in savings accounts with a compounding interest rate. Compound returns in finance lead to exponential development. One of the most potent forces in finance is the power of compounding. With the help of this idea, investors may generate sizable sums with little start-up money. Compound interest savings accounts are typical instances of exponential development.

Given that, population of a town increases by 3% each year.

The population after 5 years is calculated by:

Population in 5 years = Initial population x (1 + rate) raised to time.

That is,

Population in 5 years = 25,000 x (1 + 0.03)⁵

Population in 5 years = 25,000 x 1.159274

Population in 5 years = 28,981.85

Hence, the population of the town in 5 years will be approximately 28,982.

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Answer:

18

Step-by-step explanation:

3 x 6=18

Answer:

install mo po yan na app,

Answer:

y+2=5(x+8)

Step-by-step explanation:

y-y1=m(x-x1)

plug the coordinate and slope in...

y+2=5(x+8)

DONE

Answer:

try y=5x-42

Step-by-step explanation:

Answer: 39,000 dollars

Step-by-step explanation: weekly salary multiplied by how many weeks are in a year(52)

The standard form of the tangent plane to the surface represented by the function f(x, y) = xcos(xy) at the point (1, α, 0) is (x - 1) + α(y - β) + (f(1, α) - 0) = 0.

To find the standard form of the tangent plane, we first need to calculate the partial derivatives of the function f(x, y) = xcos(xy) with respect to x and y.

∂f/∂x = cos(xy) - yxsin(xy)

∂f/∂y = -x^2sin(xy)

Next, we evaluate these partial derivatives at the given point (1, α, 0) to obtain their values.

∂f/∂x evaluated at (1, α, 0) = cos(0) - α(1)sin(0) = 1

∂f/∂y evaluated at (1, α, 0) = -(1)^2sin(0) = 0

Using the values of the partial derivatives and the given point, we can write the equation of the tangent plane in point-normal form:

(x - 1) + α(y - β) + (f(1, α) - 0) = 0

Here, α represents the y-coordinate of the given point (1, α, 0), β can be any constant, and f(1, α) is the value of the function at the point (1, α, 0).

Note that the values of ∂f/∂x and ∂f/∂y at the given point determine the coefficients of x and y in the equation of the tangent plane, respectively.

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Answer:

6z-30 :D

Step-by-step explanation:

Step-by-step explanation:

The perimeter of a square is just all the sides added up together. To do this we can make an equation.

2(z-5) + 2(2z - 10)

This represents two sides with different lengths two times. To solve, you first use the distributive property to multiply z-5 by 2.

2z - 10 + 2(2z - 10)

We then use the distributive property by multiplying 2z - 10 by 2.

2z − 10 + 4z − 20

We then combine 2z and 4z to get 6z.

6z − 10 − 20

Subtract 20 from 10 to get -30.

6z-30.

Answer:

9a³b³

Step-by-step explanation:

9a³b³(ab - 3) = 9a^4b^4 - 27a^3b^3

Answer:

9a^3 b^3

Step-by-step explanation:

GCF=Greatest common factor

\(( \frac{1}{4} x - 6)( \frac{4}{3} x - \frac{5}{4} )\)

\( \frac{1}{4} x( \frac{4}{3} x - \frac{5}{4} ) - 6( \frac{4}{3} x - \frac{5}{4} )\)

\( \frac{4}{12} {x}^{2} - \frac{5}{16} - \frac{24}{3} x - \frac{30}{4} \)

\(\frac{1}{3} {x}^{2} - \frac{5}{16} - 8x - \frac{30}{4} \)

\( \frac{1}{3x {}^{2} } - 8x - ( \frac{5}{16} + \frac{120}{16} )\)

\( \frac{1}{3x {}^{2} } - 8x - \frac{125}{16} \)

Answer:

\(p=\frac{1}{8}\)

Step-by-step explanation:

\(-3p+\frac{1}{8}=-\frac{1}{4}\)

Subtract \(\frac{1}{8}\) from both sides:

\(-3p=-\frac{1}{4}-\frac{1}{8}\)

Multiply \(\frac{1}{4}\) by \(\frac{2}{2}\) and simplify:

\(-3p=-\frac{3}{8}\)

Divide both sides by -3:

\(p=\frac{3}{24}\)

Simplify:

\(p=\frac{1}{8}\)

The radius of curvature (r) is -100 cm and Magnification (m) is 11.26. The mirror is a concave mirror.

Given Data: Object distance, u = -1.03 cm; Image distance, v = 11.6 cm

To find: The radius of curvature (r) and Magnification (m).

Formula used:

1/f = 1/v - 1/u;

Magnification, m = -v/u

Calculation:

Using the formula,

1/f = 1/v - 1/u

1/f = 1/11.6 - 1/-1.03 = -0.02

f = -50 cm

The radius of curvature,

r = 2f

r = 2 × (-50) = -100 cm

Since the radius of curvature is negative, the mirror is a concave mirror.

Magnification, m = -v/u= -11.6/-1.03= 11.26

Hence, the radius of curvature (r) is -100 cm and Magnification (m) is 11.26.

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