7. Using the following figure I given below calculate the work done against gravity a) the net work done b) the normal force between the box and the surface. please help me!​

In words, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time.

The INTERSALT Study was designed to investigate the relationship between dietary sodium and blood pressure (hypertension) in populations worldwide.

The study included 10,079 men and women from 52 population samples in 32 countries. One of the goals of the study was to quantify the relationship between 24-hour urinary Na (y) and estimated 24-hour urinary Na (x) obtained from casual urine specimens at one point in time.

The investigators presented a simple linear regression of y on x, separately for men and women. The regression equation for men was: Y = 1.03x + 7.19, with R2 = 0.27, n = 1369.

The coefficient of determination, R2, is a statistical measure that represents the proportion of the variance for a dependent variable (y) that's explained by an independent variable (x) or variables in a regression model.

In this case, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time. The remaining 73% of the variability in y is due to other factors that are not included in the regression model.

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Take "to the right" to the be the positive horizontal direction. Then the net force on the box in the horizontal is

∑ F = 225 N - 100 N = 125 N

and by Newton's second law,

∑ F = ma   ↔   125 N = (250 kg) a

where a is the acceleration of the box. Solve for a :

a = (125 N) / (250 kg) = 0.5 m/s²

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question we have

\(density = \frac{4000}{2} = 2000 \\ \)

We have the final answer as

Hope this helps you

The sky on Earth is blue because blue light is scattered through the atmosphere as the other colors of light pass through undisturbed. Dark nebulae  have something similar going on.

Nebulae are interstellar dust and gas clouds that get backlighting from stars both inside and behind them. The clouds are illuminated by the photons from these stars that are dispersed throughout them. A nebula does not generate most of the light that appears to come from it; rather, it reflects and refracted light.

A dark nebula, also known as an absorption nebula, is a form of interstellar cloud, particularly a molecular cloud, that is so dense that it absorbs all of the light from objects behind it, including emission or reflection nebulae and background stars, at visible wavelengths.

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A planes average speed between two cities is 610 km/hr. If the trip takes 2. 25 hrs, then the distance covered by a plane is  1372.5 kilometers.

To calculate the distance the plane flies, we can use the formula:

Distance = Speed × Time

Given that the average speed of the plane is 610 km/hr and the trip takes 2.25 hours, we can substitute these values into the formula to find the distance.

Distance = 610 km/hr × 2.25 hrs

To multiply these values, we need to align the units correctly. By canceling out "hrs" in the numerator and denominator, we get:

Distance = 610 km × 2.25

Multiplying 610 km by 2.25 gives us:

Distance = 1372.5 km

Therefore, the plane flies a distance of 1372.5 kilometers.

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Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane The plane flies 1372.5 km

Let's find the solution to this problem .The formula for distance, speed and time isd

= s * there,

d = distance covered by the planes

= speed t

= time taken

Substituting the given values, we have610 × 2.25 = 1372.5 km

Hence, the plane flies 1372.5 km.

Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane

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To develop a sampling plan for LSI circuit chips, an electronics firm should consider the AQL (Acceptable Quality Level) of 0.15 specified by the LSI manufacturing department and the LTPD (Lot Tolerance Percent Defective) of 0.40 acceptable by the assembly department.

The sampling plan should involve selecting a representative sample of LSI circuit chips from the manufacturing department and conducting tests to determine their quality. The AQL of 0.15 means that the manufacturing department will tolerate no more than 15% defective chips in a given sample. Therefore, the sampling plan should ensure that the sample size is large enough to provide statistical confidence in determining the quality level of the chips.

The assembly department's LTPD of 0.40 indicates the maximum allowable defective rate for the chips after assembly. This implies that the sampling plan needs to consider the overall quality of the chips and their performance in the final analog devices.

To execute the sampling plan, one could follow these steps:

1. Determine the appropriate sample size based on statistical calculations, taking into account the desired confidence level and the acceptable quality levels specified by both departments.

2. Randomly select the required number of LSI circuit chips from the manufacturing department.

3. Perform thorough testing and inspection on the selected chips to identify any defects or anomalies.

4. Calculate the defect rate based on the number of defective chips found in the sample.

5. Compare the defect rate with the specified AQL and LTPD to assess if the chips meet the required quality standards.

6. Provide feedback to the manufacturing and assembly departments based on the results, taking necessary actions if the quality standards are not met.

By following this sampling plan, the electronics firm can ensure that the LSI circuit chips meet the required quality standards and are suitable for use in analog devices.

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The mass (in grams) Ricardo should measure out on the scale, given that he has 2500 mg is 2.5 g (Option B)

To obtain the mass that Ricardo should measure out on the scale, we shall convert 2500 milligrams (mg) to grams (g). This is illustrated below:

Conversion scale

1000 mg = 1 g

Therefore

2500 mg = (2500 mg × 1 g) / 1000 mg

2500 mg = 2.5 g

From the above, we can see that 2500 mg is equivalent to 2.5 g

Thus, we can conclude from the above illustration that the mass Ricardo should measure out on the scale is 2.5 g (Option B)

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Answer:

Your answers are Continental crust and Mountain range.

Explanation:

Continental crust is the first blank, and Mountain range the second.

I hope I helped, and I always appreciate Brainliest!!! :)

Answer:

First you take a hula hoop and hold it around your waist then you start moving your hips in a circle and let the hula  hoop go off your hands and you keep moving your hips. You keep moving your hips until you want to stop but it might fall. Just keep trying and you should get the hang of it in a few minutes.

Explanation:

Frequency: 4.38 × 10¹⁴ Hz

Wavelength: m

Type:

To calculate the wavelength, we can use the formula: λ = c / f, where λ represents the wavelength, c is the speed of light (approximately 3 × 10^8 m/s), and f is the frequency.

λ = c / f

λ = (3 × 10^8 m/s) / (4.38 × 10¹⁴ Hz)

λ ≈ 6.85 × 10^-7 m

The wavelength of the photons with a frequency of 4.38 × 10¹⁴ Hz is approximately 6.85 × 10^-7 meters.

Based on the calculated wavelength, this falls in the range of the visible light spectrum. The photons with this frequency would correspond to violet light.

Frequency: 4.14 × 10²⁰ Hz

Wavelength: m

Type:

Using the same formula, we can calculate the wavelength:

λ = c / f

λ = (3 × 10^8 m/s) / (4.14 × 10²⁰ Hz)

λ ≈ 7.25 × 10^-9 m

The wavelength of the photons with a frequency of 4.14 × 10²⁰ Hz is approximately 7.25 × 10^-9 meters.

This wavelength is in the range of X-rays. The photons with this frequency would correspond to X-ray radiation.

Frequency: 3.24 × 10¹² Hz

Wavelength: m

Type:

Using the same formula, we can calculate the wavelength:

λ = c / f

λ = (3 × 10^8 m/s) / (3.24 × 10¹² Hz)

λ ≈ 9.26 × 10^-4 m

The wavelength of the photons with a frequency of 3.24 × 10¹² Hz is approximately 9.26 × 10^-4 meters.

This wavelength falls in the microwave region. The photons with this frequency would correspond to microwave radiation.

In summary, the type of electromagnetic radiation for each combination is as follows:

1. Frequency: 4.38 × 10¹⁴ Hz, Wavelength: 6.85 × 10^-7 m, Type: Visible light (violet).

2. Frequency: 4.14 × 10²⁰ Hz, Wavelength: 7.25 × 10^-9 m, Type: X-rays.

3. Frequency: 3.24 × 10¹² Hz, Wavelength: 9.26 × 10^-4 m, Type: Microwave radiation.

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Answer:

natural is the answer

Friction is a natural force which exist

Answer:

Explanation:

It's not equal and opposite. You're thinking of Newton's 3rd Law. This is not that. This is gravitational attraction between 2 objects. We can figure out mathematically the pull that the earth has on a single person, by using the equation for gravitational force and the universal gravitational constant, G:

\(F_g=\frac{Gm_1m_2}{r^2}\) where G is the universal gravitational constant, m1 is the mass of one person, m2 is the mass of the earth, and r-squared is the addition of the radius of the earth plus the radius of you in relation to the surface of the earth.

Let's say a person weighs 150 pounds; in Newtons this is 667 N (rounded from 667.233); his mass then, in terms of the metric system (using 9.8 for gravity), is 68.2 kg. Let's also say that this person is 6 feet tall. 6 feet is the same as 1.83 m (rounded to 3 sig fig's) and the radius from that person's center to the surface of the earth would be about half that height at r = .915 meters. Filling in the formula:

\(F_g=\frac{(6.67*10^{-11})(68.2)(5.98*10^{24})}{(6.38*10^6)^2}\) it turns out that the person's radius adds nothing significantly to the radius of the earth, so it doesn't even count mathematically. It's way too small compared to the earth's radius (which is the denominator of that equation). We find that

\(F_g=668N\) That's the pull that the earth has on that person which, not coincidentally, is the weight in pounds we said that the person was. Isn't physics amazing!?

To create an electromagnetic field, a magnetic and electric field is involved.

Electromagnetic field consists of both electric and magnetic fields which are produced by human activities through the use of electricity.

With the above definition of electromagnetic field, it's production will involve:

These fields oscillate in perpendicular planes with respect to each other, and are in phase.

Therefore, to create an electromagnetic field, a magnetic and electric field is involved.

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Answer:

I need this as well

Explanation:

If the poster got the project, please let me know. I'm struggling on this unit and if you don't want to give out the project, help is appreciated too! thanks

As per the given variables, the frequency of the waves is b) 4 Hz

Total number of waves seen = 24

Total time = 6 seconds

Frequency is the rate at which something happens over a period of time or in a given sample. For the given question, wave frequency is the number of waves passing in one second. The SI unit of frequency is Hz. Further, frequency is the number of waves divided by time.

Calculating frequency -

Frequency = Number of waves / Time

Substituting the values -

= 24 waves / 6 seconds

= 4

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Answer:

\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)

Explanation:

We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:

The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:

\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).

The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:

\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).

The statements that are true about meiosis include:

Meiosis is a type of cell division that occurs in sexually reproducing organisms. It involves two rounds of cell division, resulting in the production of four haploid cells from one diploid cell.

This is accomplished through a series of stages including prophase I, metaphase I, anaphase I, telophase I, and cytokinesis, followed by prophase II, metaphase II, anaphase II, telophase II, and cytokinesis.

Meiosis results in the production of gametes, such as sperm and egg cells, each with half the number of chromosomes as compared to somatic cells.

This ensures that when two gametes combine during fertilization, the resulting zygote has the correct number of chromosomes.

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In corrosion fatigue is: "d) the surface remains bright after fracture."

Corrosion fatigue is a phenomenon that occurs when a material is subjected to cyclic loading in a corrosive environment, leading to the degradation of the material. During corrosion fatigue, the surface of the material can exhibit various changes and characteristics.

Option d) states that "the surface remains bright after fracture." This statement is incorrect. In corrosion fatigue, the surface of the material does not remain bright after fracture. Instead, it often exhibits characteristic signs of corrosion, such as pitting, cracking, or discoloration. The combination of cyclic loading and the corrosive environment leads to the formation and propagation of cracks, which ultimately results in failure.

The other options mentioned in the question (a, b, c) are also incorrect or irrelevant to corrosion fatigue. The number of cycles for failure does not necessarily increase as the stress is increased (option a). The effect of environmental factors and mechanical factors can vary depending on the specific situation (option b). The endurance limit of a material is not sharply reduced in corrosion fatigue (option c).

Therefore, the correct statement is option - d.

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9514 1404 393

Answer:

  27.85 m/s

Explanation:

If we take the direction of motion of the aircraft carrier as positive, The speed of the deck is 31.0 m/s. Bond is running in the opposite direction, so his speed relative to the deck is -3.15 m/s.

Bond's speed relative to the stationary reference (the sub or the water), is ...

  31.0 m/s - 3.15 m/s = 27.85 m/s

Answer:

\(density = \frac{mass}{volume} \\ \\ density = \frac{14.4}{2} \\ \\ { \boxed{ \boxed{density = 7.2 \: g {cm}^{ - 3} }}}\)

The work done is 1350. Option C is correct. The work-energy theorem is applied to a given problem.

From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.

\(\rm W_{net}=K_f-K_i \\\\ \rm W_{net}=\frac{1}{2}mv_f^2-\frac{1}{2} mv_i^2 \\\\ W_{net}=\frac{1}{2} m(v_f^2-v_i^2)}\)

Substitute the given value;

\(\rm W_{net}=\frac{1}{2} \times 60 \times (9.00^2-6.00^2)} \\\\ W_{net}=1350 \ J\)

The work done is 1350 J.

Hence option C is correct.

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Answer:

C on edge

Explanation:

1,350 J

First, let's calculate the electric force, using the formula below:

Now, let's use the second law of Newton to find the acceleration:

From the law of conservation of momentum, the first egg did not break because it forward momentum is transferred to the cloth while the second egg broke, the block exerts an opposite force equal to the momentum of the egg on the egg.

Momentum is the product of the mass of an object and its velocity of motion.

The law of conservation of momentum states that the momentum of an isolated system of colliding bodies is conserved.

When an egg is thrown on a large sheet of cloth suspended, the egg does not break because the momentum of the egg is transferred to the cloth as it is depressed.

However, a second egg, thrown with similar force at a suspended concrete block, did break on impact because the block does not move forward, instead it exerts an equal but opposite force on the egg resulting in the egg breaking.

Therefore, from the law of conservation of momentum, the first egg did not break because it forward momentum is transferred to the cloth while the second egg broke, the block exerts an opposite force equal to the momentum of the egg on the egg.

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A new pipe with a diameter of approximately 27.2 inches is required to triple the discharge capacity from 15 cfs to 45 cfs, assuming the same slope and roughness coefficient.

To determine the diameter of the new pipe required to triple the discharge capacity from 15 cfs to 45 cfs, we can use the Manning's equation. The equation relates the discharge capacity, cross-sectional area, hydraulic radius, slope, and roughness coefficient of the conduit to each other.

First, we can calculate the cross-sectional area and hydraulic radius of the existing 18-inch concrete conduit using the given values:

Cross-sectional area (A) = π/4 * d^2 = π/4 * (18/12)^2 = 1.767 ft^2

Hydraulic radius (R) = A/P = A/(2*(d/12)) = 1.767/(2*(18/12)) = 0.983 ft

where d is the diameter of the conduit.

Next, we can calculate the head loss due to friction, which is given by the formula:

hf = S * L

where S is the slope of the conduit and L is the length. In this case, S is given as 0.02 and L is unknown. We can use the Manning's equation to solve for L:

15 = (1.486/n) * (A * R^(2/3) * S^(1/2)) * (L^(1/2))

where n is the roughness coefficient, which is given as 0.013. Solving for L, we get:

L = (15/(1.486/0.013) * (1.767 * 0.983^(2/3) * 0.02^(1/2)))^2 = 431.3 ft

Now, we can use the continuity equation to calculate the cross-sectional area and hydraulic radius of the new pipe required to triple the discharge capacity. The continuity equation states that the flow rate (discharge capacity) remains constant between two sections of a conduit, so we have:

Q_old = Q_new

A_old * v_old = A_new * v_new

where v is the velocity of the flow.

Solving for A_new, we get:

A_new = A_old * (Q_new/Q_old) = 1.767 * (45/15) = 5.301 ft^2

Using the expression for hydraulic radius (R = A/P), we can solve for P_new, which is the wetted perimeter of the new pipe. For a circular pipe, P_new = π * d_new. Substituting this expression into the hydraulic radius equation, we get:

R_new = A_new/(π * d_new)

Substituting the values for A_new and R_new into the Manning's equation, we can solve for the new pipe's diameter (d_new):

Q_new = (1.486/n) * (A_new * R_new^(2/3) * S^(1/2))

45 = (1.486/0.013) * (5.301/(π * d_new) * R_new^(2/3) * 0.02^(1/2))

d_new = 27.2 inches

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The idea that objects (in the absence of an outside force) tend to continue doing what they are already doing is called the law of inertia.

The law of inertia states that an object at rest will remain at rest, and an object in motion will continue moving with a constant velocity in a straight line unless acted upon by an external force.

The law of inertia helps to understand the concept of momentum, which is the product of an object's mass and velocity. According to Newton's first law, an object with greater mass will require more force to change its state of motion compared to an object with lesser mass.

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Answer:

7.5 minutes (you mean hours)

t = 7.5 min (if it was actually not hours than put minutes just letting u know.)

Explanation:

The first thing you have to do is know the equation; it is t = d/s, which is time = distance divided by speed. Know fill in the equation, now it will be t = 750 km/100 km/ hr ( in this min). If you divide it, then the answer will be t = 7.5 min (which it has to be hours instead of min because hours makes more sense than minutes.)

The car will take 7.5 hours to cover a distance of 750km.

Speed ​​is defined as the rate over time at which an object is moving along a path, while velocity is defined as the rate and direction of motion of an object. Speed is a scalar quantity as it has only magnitude, no direction but Velocity is a vector quantity as it has both magnitude as well as direction.

Speed can be expressed as:

Speed= Distance travelled/ Time taken

Velocity can be expressed as:

Velocity= Displacement travelled/ Time taken

Both the quantities are expressed as meter per second (m/s).

If the two values are given , we can calculate the another value like in the above given information, speed of the car = 100km/hr and distance travelled by the car= 750 km.

So, Time taken= 750/100 = 7.5 hours

Thus, the car will take 7.5 hours to cover a distance of 750km.

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Answer:

The crust is the outer rigid layer of a planet

Answer:

The lithosphere

Explanation: