7-34.Find the perimeter and area of each algebra tile shape below. Be sure tocombine like terms.

The graph of the function \(f(x) = (9/4)x^2\) is a symmetric upward-opening parabola.

Overall, the graph represents a quadratic function with a positive leading coefficient, resulting in an upward-opening parabolic curve. The graph has been attached.

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P=160-70*cos(2π*(1/12)*t)

• Pressure in mathematics or physics is defined as force per unit area. The pressure exerted by a solid object which is resting on top of a solid surface is the weight divided by the area of the object . SI unit of force is Newton (N).

First, we find the amplitude by taking the difference between the peak values and dividing by two:

Amplitude=(230+90)/2=70

We can find the center value by either adding 70 to the minimum or subtracting 70 from the maximum:

90+70=160

230-70=160

This tells us that the Center Value=160

The frequency that we are operating at is given as:

f = 5/hour

so in minutes

f=5*(1/60)/minute=5/60=1/12 per minute

So, combining everything we get

P=160-70*cos(2π*(1/12)*t)

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Answer:

n = 34/13

Step-by-step explanation:

13 x 4 = n x 26

=> 68 = 26n

=> n = 68/26

=> n = 34/13

Therefore, n = 34/13

Hoped this helped.

\(GeniusUser\)

Step-by-step explanation:

1)All rational numbers are also integers.

2)All integers are rational numbers.

3)All rational numbers can be written in the form.

Answer:

97

Step-by-step explanation:

Answer:

the number of branches required to use 25 wreaths is 75 branches

Step-by-step explanation:

Given that

The florist used 225 branches of winterberry for making 75 wreaths

First we have to compute the unit rate or the ratio

= 225 ÷ 75

= 3 : 1

Now the number of branches required to use 25 wreaths is

= 3 × 25

= 75 branches

Hence, the number of branches required to use 25 wreaths is 75 branches

Shape area of timber measured in millimeters is 10.8 m2.

Given:

Rectangle 1's length is 4000 mm, or 4 meters.

Rectangle 1's width is 1200 mm, or 1.2 meters.

Rectangle 2's length is [6200-1200] mm, or 5 meters.

Rectangle width 2 = 1200 mm = 1.2 m

Area of the form,

Shape's area is equal to the sum of its two rectangles.

Shape area equals [(4)(1.2)] plus [(5)(1.2)].

Shape's area equals 4.8 + 6.

Length area of the shape is 10.8 m2.

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\(\\ \rm\Rrightarrow log_2z+2log_2x+4log_9y+12log_9x-2log_2y\)

So

\(\\ \rm\Rrightarrow log_2z+log_2x^2-log_2y^2+log_9y^4+log_9x^{12}\)

\(\\ \rm\Rrightarrow log_2(zx^2)-log_2y^2+log_9(y^4x^{12})\)

\(\\ \rm\Rrightarrow log_2\left(\dfrac{zx^2}{y^2}\right)+log_9(y^4x^{12})\)

Answer:

\(\log_2\dfrac{x^2z}{y^2}+\log_9x^{12}y^4\)

Step-by-step explanation:

Log laws

\(\textsf{Product law}: \quad \log_axy=\log_ax + \log_ay\)

\(\textsf{Quotient law}: \quad \log_a\frac{x}{y}=\log_ax - \log_ay\)

\(\textsf{Power law}: \quad \log_ax^n=n\log_ax\)

Given expression:

\(\log_2z+2\log_2x+4\log_9y+12\log_9x-2\log_2y\)

Group terms with same log base:

\(\implies \log_2z+2\log_2x-2\log_2y+4\log_9y+12\log_9x\)

Apply the power law:

\(\implies \log_2z+\log_2x^2-\log_2y^2+\log_9y^4+\log_9x^{12}\)

Apply the product law:

\(\implies \log_2x^2z-\log_2y^2+\log_9x^{12}y^4\)

Apply the quotient law:

\(\implies \log_2\dfrac{x^2z}{y^2}+\log_9x^{12}y^4\)

Answer:

Slope - intercept form

    \(y = \frac{3}{5} x - \frac{26}{5}\)

Step-by-step explanation:

Step(i):-

Given that the point (2,-4) and slope \(m = \frac{3}{5}\)

Equation of the straight line passing through the point (x₁, y₁) and slope 'm'

     y - y₁ = m( x-x₁ )

    y - (-4) =  \(\frac{3}{5}\)( x-2)

⇒  5( y+4) = 3(x-2)

⇒  5 y +20 = 3x -6

⇒ 3x - 5 y -6-20 =0

⇒ 3 x -5y -26=0

Step(ii):-

Slope - intercept form

       5 y = 3x -26

         \(y = \frac{3}{5} x - \frac{26}{5}\)

Answer:

333234

Step-by-step explanation:

333234$ for the next 4 years and the ecvation is 69$+-2$

The factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

To determine the factors of the polynomial x^3 - 12x^2 - 2x + 24 by grouping, we can follow these steps:

Step 1: Group the terms in pairs. In this case, we can pair the first two terms and the last two terms:

(x^3 - 12x^2) + (-2x + 24)

Step 2: Factor out the greatest common factor from each pair. From the first pair, we can factor out x^2, and from the second pair, we can factor out -2:

x^2(x - 12) - 2(x - 12)

Step 3: Notice that we now have a common binomial factor of (x - 12) in both terms. Factor out this common binomial factor:

(x - 12)(x^2 - 2)

Therefore, the factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

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To find the common roots between two functions, we need to find the roots (or solutions) of each function individually and then identify the shared solutions.

For the function f(x) = x^2 + x - 6, we can find the roots by setting the function equal to zero and solving for x:

x^2 + x - 6 = 0

To factorize this quadratic equation, we need to find two numbers that multiply to -6 and add up to 1 (the coefficient of x). The numbers that satisfy these conditions are 3 and -2:

(x + 3)(x - 2) = 0

Setting each factor equal to zero:

x + 3 = 0 or x - 2 = 0

Solving for x in each equation:

x = -3 or x = 2

Therefore, the function f(x) = x^2 + x - 6 has two roots: x = -3 and x = 2.

To find the common roots between this function and another function, we would need to know the second function. If you provide the second function, I can help determine if there are any shared roots.

Answer:

The team for which number of spectators at one of the matches was 16000 to the nearest thousands is Manchester.

The number of spectators at different football matches is given.

We have to find out that for which team no. of spectators were 16000 nearest to thousands.

What is the nearest thousand of a number ?

The nearest thousand of a number meant we need to round off number in form of multiple of 1000 which is closest to the given number.

As per the question ;

The number of spectators at different football matches is given ;

Let's round off them all nearest to thousand.

No. of spectators for Newcastle =  16, 750

Rounding off to nearest thousands ;

As the number up to thousands place i.e., 750 is greater than 500 , so ; we need to change 750 to 000 and 1 will be added to 16 and that would be ;

= 17000

No of spectators for Manchester =  16, 213

Rounding off to nearest thousands ;

As the number up to thousands place i.e., 213 is less than 500 , so ; we need to change 213 to 000 ;

= 16000

So ; the Manchester is that team for which no. of spectators were 16000 nearest to thousands at one of the matches.

Thus , the team for which number of spectators at one of the matches was 16000 to the nearest thousands is Manchester.

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Answer:

3. f(3) = 16

4. h(3) = 4

Step-by-step explanation:

3.

f(x) = x² + 7

f(3) = 3² + 7

f(3) = 16

4.

h(x) = 12/x

h(3) = 12/3

h(3) = 4

Answer:

expression

Step-by-step explanation:

It's an expression. The expression happens to be a quadratic polynomial.

An equation must have an equal sign.

An equation is a statement that a number or expression equals a number or expression.

Here, there is no equal sign. There is only an expression.

Answer:

This is an expression

8x2+7x-15

The system of equation has a solution of x = 8 and y = 6.

In order to remove a variable from a system of equation, we must change the equations so that the variable is removed. In relation to this specific set of equations:

3x - 4y = 0 \s-3x + 9y = 30

By combining the two equations, we can take the variable x out of the equation. This is due to the fact that the x terms cancel out when the two equations are added:

3x - 4y + (-3x + 9y) = 0 + 30

When we simplify this equation, we obtain:

5y = 30

When we multiply both sides by 5, we get:

y = 6

After figuring out y, we can now put this answer back into one of the initial equations to figure out x:

3x - 4y = 0

3x - 4(6) = 0

3x - 24 = 0

3x = 24

x = 8

As a result, the system of equations has a solution of x = 8 and y = 6. By substituting the values of x and y into the two original equations and confirming that they are both true.

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Answer:

The mean is the average number of a data set gotten by adding all the numbers then dividing by two.

the median is the middle number in a sorted set of data,either sorted in ascending order or descending order.

I hope this helps

To calculate mean:

• add up all the numbers,

• then divide by how many numbers there are.

Example:

Data: 5, 6, 10, 1

Add these all together, which is 22, then divide by 4 (because that is how many numbers there are), so:

the mean is 5.5

To calculate median:

Arrange your numbers in order.

Cross off numbers until you get to the middle.

If there is an even number of data, then find the two in the middle and find the middle of that.

Example:

Data: 5, 6, 10, 1

Arrange: 1, 5, 6, 10

So, the middle 2 are 5 and 6. In between these would be 5.5, so that is the median.

If the data was: 1, 5, 6, 8, 10,

then the median would be 6.

To calculate Swornima's annual income and the amount of tax she should pay, let's break down the information provided:

Monthly basic salary: Rs 48,000

Social security tax rate: 1%

Income tax rate on income up to Rs 5,00,000: 0% (no tax)

Income tax rate on income from Rs 5,00,001 to Rs 7,00,000: 10%

Dashain allowance: 1 month's salary

Deposit in Citizen Investment Trust (CIT): 10%

Rebate on income tax: 10%

(i) Annual Income:

Swornima's monthly basic salary is Rs 48,000, so her annual basic salary would be:

Annual Basic Salary = Monthly Basic Salary x 12

= Rs 48,000 x 12

= Rs 5,76,000

Additionally, she receives 1 month's salary as the Dashain allowance, which we can add to her annual income:

Annual Income = Annual Basic Salary + Dashain Allowance

= Rs 5,76,000 + Rs 48,000

= Rs 6,24,000

Swornima's annual income is Rs 6,24,000.

(ii) Tax Rebate:

Swornima receives a 10% rebate on her income tax. To calculate the rebate, we need to determine her income tax first.

(iii) Annual Income Tax:

First, let's calculate the income tax for the range of income from Rs 5,00,001 to Rs 7,00,000. The tax rate for this range is 10%.

Taxable Income in this range = Rs 6,24,000 - Rs 5,00,000

= Rs 1,24,000

Income Tax in this range = Taxable Income x Tax Rate

= Rs 1,24,000 x 0.1

= Rs 12,400

Now, let's calculate the total annual income tax:

Total Annual Income Tax = Income Tax in the range Rs 5,00,001 to Rs 7,00,000

= Rs 12,400

Next, we calculate the rebate on income tax:

Tax Rebate = Total Annual Income Tax x Rebate Rate

= Rs 12,400 x 0.1

= Rs 1,240

Swornima's annual income tax is Rs 12,400, and she receives a tax rebate of Rs 1,240.

To summarize:

(i) Swornima's annual income is Rs 6,24,000.

(ii) Swornima's tax rebate is Rs 1,240.

(iii) Swornima should pay an annual income tax of R

Answer:

first one is left second one is right

Answer:

What is that on?

it is blury

Answer:

1 2 3 4 5

4 8 12 16 20

Step-by-step explanation:

the x is 4 therefore, count by 4.

Answer:

288π inch³

Step-by-step explanation:

V=4

/3πr³

by substituding in formulae

4/3*216π

=288π inch³

hope this helps

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Oliver's number is bigger than that of Chen.

It is a number equal to 10 times 10.

Given is that Oliver and Chen both write down a number. Oliver says, my number has 8 hundreds and Chen's number only has 3 hundreds, my number must be bigger.

Oliver number can be written as follows -

8 x 10 x 10

Chens number can be written as follows -

3 x 10 x 10

It can be concluded that Oliver's number is bigger than that of Chen.

Therefore, Oliver's number is bigger than that of Chen.

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Answer:

Simplifying

x + 16 = -19

Step-by-step explanation:

Reorder the terms:

16 + x = -19

Solving

16 + x = -19

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.

16 + -16 + x = -19 + -16

Combine like terms: 16 + -16 = 0

0 + x = -19 + -16

x = -19 + -16

Combine like terms: -19 + -16 = -35

x = -35

Simplifying

x = -35

Step-by-step explanation:

jjzjznzijxmxnjxndksnndjxnz z

Here are the completed tables for each sequence:

Sequence 1 Sequence 2 Ordered Pair

5                    15                   (5, 15)

6                        14               (6, 14)

7                        13             (7, 13)

8                    12                 (8, 12)

9                   11                (9, 11)

The corresponding terms in the two sequences are related by a linear function. The slope of the line is 1, which means that for every 1 increase in y, there is a 1 increase in x.

The corresponding terms in the two sequences are related by a linear function. The slope of the line is 1, which means that for every 1 increase in y, there is a 1 increase in x. This means that the two sequences are increasing at the same rate.

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Answer:

121

Step-by-step explanation:

firstly you arrange the numbers in ascending order the number in the middle is considered to be the median

As a result, the set of all [u, w] Rn Rn satisfying the previous equation is the tangent space to F at [v1, v2]  by using preimage theorem.

Let F be the Stiefel manifold of orthonormal 2-frames in Rn to apply the preimage theorem. The collection of all tangent vectors to curves passing through [v1, v2] in F is what is known as the tangent space T[F] at a location [v1, v2]. Let (t) be a straight line in F such that (v1, v2) is a smooth curve. The tangent vector to t at time t = 0 is then given by

γ′(0) = [u, w] ∈ T[F].

We must now determine the requirements that [u, w] must meet in order to be in T[F]. Assume that V is a matrix with columns named v1 and v2. If Q is an orthogonal matrix, then any orthonormal 2-frame [v1′, v2′] in Rn can be represented as VQ. The category to which [v1′, v2′] belong Q is a 2 by 2 matrix with determinant 1, and F is equivalent to Q. Given that Q(0) = I, let Q(t) be a smooth curve in SO(2). Then, there is

γ(t) = VQ(t) (t),

and

γ′(0) = VQ′(0) (0).

We have Q since Q(t) is orthogonal (t)

TQ(t) = I, indicating

Q′(0)T + Q′(0) = 0.

Let [u, w] T[F] now. Once this is the case, a smooth curve Q(t) in SO(2) exists with Q(0) = I and

[u, w] = VQ′(0) (0).

Applying the equation above, we obtain

v1uv2w plus v1wv2u equals 0.

As a result, the set of all [u, w] Rn Rn satisfying the previous equation is the tangent space to F at [v1, v2].

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