An initial investment amount P, an annual interest rate r, and a time t are given. Find the future value of the investment
when interest is compounded (a) annually, (b) monthly, (c) daily, and (d) continuously. Then find (e) the doubling time T
for the given interest rate.
P= $1500, r = 3.95%, t = 5 yr
a) The future value of the investment when interest is compounded annually is $
(Type an integer or a decimal. Round to the nearest cent as needed.)
ANSWER ALL PARTS
A, B, C, D, E
The future value of the investment when interest is compounded continuously is; $3408.29
What is Compound interest?Compound interest is a method of calculating the interest charge. In other words, it is the addition of interest on interest.
Given Data
P= $1500, r = 3.95%, t = 5 yr
To Calculate the number of periods: in this case we have 5*12= 60 months.
- The monthly interest rate, we have to divide the annual nominal rate by 12 (the number of periods in the year).
Then, we can calculate the future value as:
A = P (1 + r/n)^nt
A = 1500(1 + 3.95/365)(365)^(5)
P = 1500/ (1 + 0.00010137)^(5)
P = $3408.29
The future value when compounded monthly is $3408.29.
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Given that p(x)=2(5−x)2+1 , what is the value of p(-4)? Responses
Answer:
37
Step-by-step explanation:
x=-4
=2(5-(-4)2+1
=2(5+4)2+1
=2(9)2+1
=18(2)+1
=36+1
=37
Alison and Tyrone each bought a slice of pizza in the shape of a right triangle as
shown. What is the area of each slice of pizza? Who has the larger slice?
Alison 5in-W. 6inL
Tyrone 3in L. 8 W
Alison's slice of pizza has an area of in.
Answer:
The area of Alison's pizza would be 30 in.
solve for x, 3(xt2)=2(2-x)
Answer:
x=-2/5
Step-by-step explanation:
3x+6=4-2x3x+2x=4-65x/5=-2/5x=-2/510. Higher Order Thinking Each of 5 friends has x action figures in
his or her collection. Each friend buys 11 more action figures. Now
the 5 friends have a total of 120 action figures.
a. Write an equation that models the problem.
b. Solve the equation to find the number of action figures, x, that
each friend had originally.
Each friend had originally 13 action figures before buying 11 more.
Given that there are 5 friends and each of them has x action figures in his or her collection. When they buy 11 more action figures, the total number of action figures they will have is 120.
a) We need to find an equation that models the problem. Let x be the original number of action figures that each friend had.
Therefore, the total number of action figures that each friend will have after purchasing 11 more is x + 11.
The total number of action figures will be 5(x + 11) = 5x + 55.
Now, according to the problem,5x + 55 = 120
This is our equation that models the problem.
b) We have to solve the equation 5x + 55 = 120 to find the original number of action figures, x, that each friend had before buying 11 more action figures.
5x + 55 = 120
5x = 120 - 55 (subtract 55 from both sides)
5x = 65x = 13
Therefore, each friend had originally 13 action figures before buying 11 more.
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The points L, M,N and O all lie on the same line segment, in that order , such that the ratio of LM: MN: NO is equal to 1 : 5 : 1. If LO=21, find MN
Answer: MN = 15
Step-by-step explanation:
1x+5x+1x=21
1x=3 (Length of the Segment with 1)
5*3=15
A line segment is also a line but a line with finite length and fixed endpoints. The length of line segment MN is 15 units.
What is a line?A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. A line segment is also a line but a line with finite length and fixed endpoints.
Given that the ratio of LM: MN: NO is equal to 1: 5: 1. Therefore, we can write,
LM : MN : NO = 1:5:1
If the ratio is multiplied by x, which is the factor that brings the ratio to its original value,
LM : MN : NO = 1x : 5x : 1x
Therefore, The length of the sides LM, MN, and NO are 1x, 5x, and 1x, respectively.
Now, since the length of LO is 21 units, it is made by joining LM, MN, and NO. Therefore, we can write,
LO = LM + MN + NO
21 = 1x + 5x + 1x
21 = 7x
x = 21 /7
x = 3
Further, the length of line segment MN is,
MN = 5x
= 5(3)
= 15 units
Hence, the length of line segment MN is 15 units.
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A 2-gallon container of disinfectant costs $20.48. What is the price per cup?
Answer:
$0.64 per cup
Step-by-step explanation:
There are 16 cups in 1 gallon, so the number of cups in 2 gallons is:
1 gallon: 16 cups
2 gallon = 2 x 1 gallon = 2 x 16 cups = 32 cups
So we need to find the price of each cup:
1 cup = ($20.48 / 32 cups) = $0.64 per cup.
The multiples of two form a sequence as follows:2,4,6,8,10,12,14,16 describe the sequence you see. What about the multiples of three?Four?Five?
Answer: The sequence firmed here is the arithmetic progression or sequence
Step-by-step explanation:
The sequence firmed here is the arithmetic progression. The numbers are given as 2,4,6,8,10,12,14,16. Here the first term is 2 and the common difference is (6-4) = 2.
Let's check to confirm. Let's find the 5th term. This will be:
= a + (n - 1)d
= 2 + (5 - 1)2
= 2 + (4 × 2).
= 2 + 8
= 10
The fifty term is 10.
This is correct as shown with the figures given.
The multiples of 3,4,5 would also make up and arithmetic progression.
14. 3/64 + 2/32 + 5/16 =
what is the answer
Answer:
27/64
Step-by-step explanation:
(7×16)+(5×64)64×16
=112+3201/024
=432/1024
Simplifying 432/1024, the answer is
=27/64
How are factors and products connected
A ball pit contains 190 balls.
50 are orange, 100 are purple and 40 are yellow.
What is the ratio of yellow to purple balls in its simplest form?
Step-by-step explanation:
40 :100 yellow to purple, divide both sides by 20
2:5
Answer:
the ratio of yellow to purple is 40:100 that is 2:5 in the simplest form.
Step-by-step explanation:
Hope it helps.
I need help please I can only find 2 of these solutions
Step 1: Isolate the Sin Operator
\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)
Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable
Note that since trig functions have 2 general solutions, this will give us one of our general solutions.
\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)
x₁= 0.48
Solving for x₂
Use the period identity for Sin Functions
\(sin(x)=sin(\pi -x)\)
X in this case is arcsin(0.25)
\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)
So our two general solutions are 0.48 and 5.52
Step 3: Period
Trig Functions have periodic behavior and this function period is
\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)
So our general solutions are
0.48±12k, where k is an integer
5.52±12k, where k is an integer
Let k=1, and we get our next set of solutions:
12.48 and 17.52
So our answer is 0.48,5.52,12.48,17.52
please help! thank uu!~
The intermediate step in the form (x+a)²=b as a result of completing the square for the given equations is (x+4)²=18.
The given quadratic equation is x²+4x-9=-4x-7.
Here, x²+4x-9+4x=-7
x²+8x=-7+9
x²+8x=2 ------(i)
Choose coefficient of x, that is 8.
Half of coefficient of x is 4.
Take square of 4, that is 4²=16
Add 16 to both the sides of the equation, we get
x²+8x+16=2+16
(x+4)²=18
Therefore, the intermediate step in the form (x+a)²=b as a result of completing the square for the given equations is (x+4)²=18.
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I need help I need an equivalent expression to this please
Consider the following dice game, as played at a certain gambling casino: players 1 and 2 roll a pair of dice in turn. the bank then rolls the dice to determine the outcome according to the following rule: player i,i=1,2, wins if his roll is strictly
Ii={1 if i wins, 0 otherwise}
and show that I1 and I2 are positively correlated. Explain why this result was to be expected.
Answer:
they are positively correlated.
Step-by-step explanation:
We can calculate the individal expectations first. FIrst player will win if that player's roll is greater than the bank's roll. There are (6 possible rolls of player 1 * 6 possible rolls of bank =) 36 total possible rolls, out of which player 1 will win in 15 cases.
\(\therefore E(I_i) = 1\cdot \frac{15}{36} + 0 \cdot \frac{21}{36} = \frac{5}{12} \approx 0.4167\)
For the joint expectation, there are (6 possible rolls of player 1 * 6 possible rolls of player 2 * 6 possible rolls of bank =) 216 total possible rolls.
Cases where both players win: Expectation = $2.
If bank rolls 1, both players will win in 5*5 = 25 cases. P1 is one of {2,3,4,5,6}, P2 is one of {2,3,4,5,6}
If bank rolls 2, both players will win in 4*4 = 16 cases.
If bank rolls 3, both players will win in 3*3 = 9 cases.
If bank rolls 4, both players will win in 2*2 = 4 cases.
If bank rolls 5, both players will win in 1*1 = 1 cases.
If bank rolls 6, both players will win in 0*0 = 0 cases.
Total cases = 25+16+9+4+1+0 = 55 cases.
Cases where player 1 wins $1 and player 2 loses: Expectation = $1.
If bank rolls 1, player 1 will win and player 2 will lose in 5*1 = 5 cases. P1 is one of {2,3,4,5,6}, P2 is {1}
If bank rolls 2, player 1 will win and player 2 will lose in 4*2 = 8 cases.
If bank rolls 3, player 1 will win and player 2 will lose in 3*3 = 9 cases.
If bank rolls 4, player 1 will win and player 2 will lose in 2*4 = 8 cases.
If bank rolls 5, player 1 will win and player 2 will lose in 1*5 = 5 cases.
If bank rolls 6, player 1 will win and player 2 will lose in 0*6 = 0 cases.
Total cases = 5+8+9+8+5+0 = 35
Cases where player 2 wins $1 and player 1 loses: Expectation = $1.
This is the same as above with player 1 and 2 exchanged.
Total cases = 35
Cases where both players lose: Expectation = $0.
If bank rolls 1, both players will lose in 1*1 = 1 cases. P1 is {1}, P2 is {1}
If bank rolls 2, both players will lose in 2*2 = 4 cases.
If bank rolls 3, both players will lose in 3*3 = 9 cases.
If bank rolls 4, both players will lose in 4*4 = 16 cases.
If bank rolls 5, both players will lose in 5*5 = 25 cases.
If bank rolls 6, both players will lose in 6*6 = 36 cases.
Total cases = 1+4+9+16+25+36 = 91 cases.
Total of all cases (we expect this to be 216 as mentioned above) = 55+35+35+91=216
So, joint expectation is:
\(E(I_1I_2) = \frac{2\cdot 55 +1\cdot 35+1\cdot 35+0\cdot 91}{216} = \frac{180}{216}= \frac{5}{6} \approx 0.8333\)
So, the covariance is given by:
\(\texttt{Cov}(I_1I_2) =E(I_1I_2) -E(I_1)\cdot E(I_2)= \frac{5}{6}-\frac{5}{12}\cdot\frac{5}{12}=\frac{95}{144} \approx 0.6597\)
As this is greater than 0 and closer to 1, they are positively correlated.
The reason why this result is expected is because the same bank roll is being used for both players. So, it is very likely that both players will win if the bank roll is 1 or even 2. Also, it is very likely that both players will lose if the bank roll is 6, 5, or even 4. This shows positive correlation between the events.
Find the cost for a family of four with two children ages 1 and 2 to fly to a destination
for which the adult fare is $288 and the child fare for children under 3 is two thirds of
the adult fare.
The total cost for the family of four is $944
What is cost?Cost denotes the amount of money that a company or a person spends on the creation or production or acquiring of goods or services.
Here the family needs the service if transportation.
The cost of adult is $280. Out of four members , two are under 3years. This means the total cost for adult is 2 × 280 = $560
The cost of under 3 is ⅔ of the cost of adult.
= ⅔ × 280= $192
The cost of the two under 3 = 2 × $192 = $384
therefore the total cost for the family is $560 +$384 = $944
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Estimate to compare. Write<,>, or=.
Sorry for the bad photos
Answer:
<
Step-by-step explanation:
Use the polling tool to respond to the question below.
Gina typed 2,700 words. She types 45 words per minute. How long did she type for?
HELP PLZZ
Answer:
She typed for 60 minutes (1 hour).
Step-by-step explanation:
Do 2,700 divided by 45 to get your answer.
2,700 ÷ 45 = 60
She typed for 60 minutes (1 hour).
In circle O, secants ADB and AEC are drawn from external point A
such that points D, B, E, and C are on circle O. If AD = 8, AE = 6,
and EC is 12 more than BD, the length of BD is
(1) 6
(2) 22
(3) 36
(4) 48
The length of BD is 22.
In the given scenario, let's consider the following information.
AD = 8
AE = 6
EC is 12 more than BD.
To find the length of BD, we can utilize the Intercepted Arcs Theorem, which states that when two secants intersect outside a circle, the measure of an intercepted arc formed by those secants is equal to half the difference of the measures of the intercepted angles.
From the given information, we know that AD = 8 and AE = 6.
Since these are the lengths of the secants, we can use them to calculate the intercepted arcs.
First, let's find the intercepted arc corresponding to AD:
Intercepted Arc ADB = 2 \(\times\) AD = 2 \(\times\) 8 = 16
Similarly, we can find the intercepted arc corresponding to AE:
Intercepted Arc AEC = 2 \(\times\) AE = 2 \(\times\) 6 = 12
Now, we know that EC is 12 more than BD.
Let's assume the length of BD as x.
BD + 12 = EC
Now, let's consider the intercepted arcs theorem:
Intercepted Arc ADB - Intercepted Arc AEC = Intercepted Angle B - Intercepted Angle C
16 - 12 = Angle B - Angle C
4 = Angle B - Angle C.
Since Angle B and Angle C are vertical angles, they are congruent:
Angle B = Angle C.
Therefore, we can say:
4 = Angle B - Angle B
4 = 0
However, we have reached an inconsistency here.
The equation does not hold true, indicating that the given information is not consistent or there may be an error in the problem statement.
As a result, we cannot determine the length of BD based on the given information.
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Suppose a poker hand contains seven cards rather than five. Compute the probabilities of the following poker hands: (a) a seven-card straight (b) four cards of one rank and three of a different rank (c) three cards of one rank and two cards of each of two different ranks (d) two cards of each of three different ranks, and a card of a fourth rank (e) three cards of one rank and four cards of each of four different ranks (f) seven cards each of different rank
Answer:
a) 0.00031
b) 0.0017
c) 0.31
d) 0.00018
Step-by-step explanation:
attached below is the detailed solution
Total number of 7-poker cards are 52P7 = 133784560
A) Determine the probabilities of Seven-card straight
probability of seven-card straight = 0.00031
B) Determine the probability of four cards of one rank and three of a different rank
P( four cards of one rank and three of different rank ) = 0.0017
C) Determine probability of three cards of one rank and two cards of each two different ranks
P( three cards one rank and two cards of two different ranks ) = 0.31
D) Determine probability of two cards of each of three different ranks and a card of a fourth rank
P ( two cards of each of three different ranks and a card of fourth rank ) = 0.00018
Please answer the attached question
The 5th term of the arithmetic series is 1179/ 19.
How to solve an arithmetic series?The 10th term of the arithmetic series , S is 66.
Using arithmetic formula,
aₙ = a + (n - 1)d
where
n = number of termsd = common differencea = first termTherefore,
66 = a + 9d
The sum of the first 20 terms of S is 1290.
Therefore,
Sₙ = n / 2 (2a + (n - 1)d)
1290 = 10(2a + 19d)
1290 = 20a + 190d
combine the equation
66 = a + 9d
1290 = 20a + 190d
Hence,
a = 66 - 9d
1290 = 20(66 - 9d) + 190d
1290 = 1320 - 180 + 190d
1290 - 1320 + 180 = 190d
190d = 150
d = 150 / 190
d = 15 / 19
Hence,
a = 66 - 9(15 /19)
a = 66 - 135 / 19
a = 1254 - 135/ 19
a = 1119 / 19
Hence, let's find the fifth term.
a₅ = a + 4d
a₅ = 1119 / 19 + 4(15 / 19)
a₅ = 1119 / 19 + 60 / 19
Therefore,
a₅ = 1179/ 19
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The following list shows how many brothers and sisters some students have:
1, 2, 1, 2, 1, 3, 4, 5, 4, 3, 1
State the mode.
Answer:
The mode is 1
Step-by-step explanation:
Mode is the number that occurs the most in the following numbers the statment gives you.
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
y2 = 2x, x = 2y;
about the y-axis
The volume V of the solid obtained by rotating the region bounded by the curves \(y^2=2x\) and \(x=2y\) about the y-axis is 107.168
Given,
The curves are \(y^2=2x...i\) and \(x=2y....ii\)
We need to determine the volume V of the solid obtained by rotating the region bounded by the given curves about y-axis.
Volume of the region can be obtained by using washer method.i.e.
\(V=\int \pi [(f(y)_{outer})^2-(f(y)_{inner})^2]dy\)
From figure, we can observe that the inner curve i.e. \(f(y)_{inner}\) is \(y^2=2x = > x=\frac{y^2}{2}\)
and outer curve i.e. \(f(y)_{outer}\) is \(x=2y\).
To determine the boundaries of the integral, substitute eq.ii in eq.i, we get
\(y^2=2(2y)\\\\y^2=4y\\\\y^2-4y=0\\\\y(y-4)=0\\\\\)
y=0 and y=4
These are the limits of the integral
Now, substituting the equations for volume V,
\(V = \int\limits^4_0 \pi [ (2y)^2 - (\frac{y^2}{2} )^2] dy\\\\ V = \int\limits^4_0 \pi [ 4y^2 - (\frac{y^4}{4} )] dy\\\\V = \pi [ \frac{4}{3} y^3 -\frac{1}{20} y^5 ]\limits^4_0\\\\V=\pi[\frac{4}{3}(4)^3-\frac{1}{20}(4)^5]\\\\V=\pi[\frac{256}{3} - \frac{1024}{20}]\\\\V=\pi[85.33-51.2]\\\\V=\pi [34.13]\\\\V=107.168\)
Hence, the volume of the region bounded by the curve after rotating is 107.168
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Nikola likes to play horseshoes, where players try to score a ringer by throwing a horseshoe so it lands around a post. A player gets 2 attempts each round. Let R represent the number of ringers that Nikola scores in a round. Here's the probability distribution of R along with summary statistics. R=# of ringers 0 1 2 P(R) 0.75 0.20 0.05 Mean: HR=0.3 Standard deviation: OR 0.56 Nikola gets 3 points for each ringer that he scores. Let X represent the number of points that Nikola gets from ringers in a round. What are the mean and standard deviation of X?
The mean and standard deviation of X are 0.9 and 1.68 points.
Since Nikola gets 3 points for each ringer which he scores, then total points he gets from ringers could be determined by multiplying the number of ringers by 3.
So, X = R * 3 = 3R
Where:
R = numbers of ringers
X = total points Nikola gets from ringers
Given:
Mean : μR = 0.3
Standard deviation : σR = 0.56
Thus, multiplying by 3 will effects the mean as follows:
μX = 3 (μR)
= 3 (0.3)
= 0.9
And, multiplying by 3 also will effects the standard deviation as follows:
σX = 3 (σR)
≈ 3 (0.56)
≈ 1.68
Hence, the mean of X is 0.9 and and the standard deviation of X is 1.68.
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what is the solution set for 1<_|x+3|<_4
The solution set for 1<|x+3|<4 is:
x ∈ (-2, 2)
To solve this inequality, we first need to isolate the absolute value. This gives us:
|x+3| - 1 < 4 - 1
We can then remove the absolute value signs by considering two cases:
* Case 1: x + 3 > 0
In this case, we have:
x + 3 < 5
Solving for x, we get:
x < 2
* Case 2: x + 3 < 0
In this case, we have:
-(x + 3) < 5
Multiplying both sides by -1, we get:
x + 3 > -5
Solving for x, we get:
x > -8
Combining the solutions from both cases, we get:
x ∈ (-2, 2)
you buy 1.68 pounds of ground beef, 2.8 pounds of chicken, and 1.02 pounds of ground turkey, how much meat did you buy in all?
Answer:
ya ya ya ya ya ya ya ya
Step-by-step explanation:
The total quantity of meat is 5.5 pounds.
What is total?A total is a whole or complete amount, and "to total" is to add numbers or to destroy something. In math, you total numbers by adding them: the result is the total.
Given that, quantity of ground beef = 1.68 pounds, quantity of chicken = 2.8 pounds and quantity of turkey = 1.02 pounds.
Here, total = The quantity of ground beef + The quantity of chicken + The quantity of turkey
Total = 1.68+2.8+1.02
= 5.5 pounds
Therefore, the total quantity of meat is 5.5 pounds.
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How many yards are in 108 inches?
Answer:
3 yards
Step-by-step explanation:
Divide inches by 36
\(108/36\\=3yards\)
Answer:
\(3 \: \: yards\)
Step-by-step explanation:
\(1 \: \: yard = 36\: \: inches \\ yard \: \: x = 108 \: \: inches\)
So,
\( 1 = 36 \\ x = 108 \\ \\ cross \: \: \: multiple \\ \\ 108 = 36x \\ \frac{108}{36} = \frac{36x}{36} \\ x = 3 \: \: yards\)
hope this helps
brainliest appreciated
good luck! have a nice day!
AHH!! PLEASE HELP ME IM STUCK :(
Answer:
x = 6
Step-by-step explanation:
Compare the given formula to the equations shown in the attachment. First of all, you see that all of the numbers are scaled by a factor of 4. Removing that gives ...
\(r=\dfrac{6.6}{1+1.1\cos{\theta}}=\dfrac{1.1\cdot6}{1+1.1\cos{\theta}}\)
This matches the formula for the hyperbola with e=1.1 and d=6, for a directrix of x = 6.
The triangle, ABC, shown on the coordinate plane below, is dilated from the origin by a scale factor of r = 1/3. What is the location of A'B'C'?
Answer:
Step-by-step explanation:
Coordinates of the vertices of the triangle ABC are A(3, 4), B(-7, 2) and C(2, 1).
Rule for the dilation of the coordinates of the ends of a segment is,
(x, y) → k(x, y)
→ (kx, ky)
Where k = scale factor by which the segment is dilated
If the given triangle ABC is dilated by a scale factor = \(\frac{1}{3}\)
Coordinates of the vertices of the image triangle will be,
A(3, 4) → A'(1, \(\frac{4}{3}\)) Or A'(1, 1.3)
B(-7, 2) → \(B'(\frac{7}{3},\frac{2}{3})\) Or B'(2.3, 0.7)
C(2, 1) → \(C'(\frac{2}{3},\frac{1}{3})\) Or C'(0.7, 0.3)
Now we can plot these points on the given graph
What were the rental rates?
answer/explanation:
d = daily rental chargem = the charge per mileJon rented a car from a company that charged a daily rental fee and a mileage charge. He rented the car for 6 days and drove 300 miles and was charged $285.6d + 300m = 285His friend Amanda later rented the same car for 7 days and drove 260 miles and was charged $310.7d + 260m = 310by solving the system of equations6d + 300m = 2857d + 260m = 310we findd = $35m = $0.25the daily rental charge is $35.the company charge per mile is $0.25.hope this helps