6) In a group of 32 children, 25% have
blue eyes. How many children do not
have blue eyes?

Answer:

x = 9

Step-by-step explanation:

See the attachment for step-by-step

Answer:

The roots(zeros) are :x=-3,-1,2,4

Step-by-step explanation:

The answer is A.

Answer:

No, he is not correct.

Step-by-step explanation:

Check the attachment.

The corresponding parts are:

The statement is given as:

△ABC was transformed using two rigid transformations.

The rigid transformations imply that:

The images of the triangle after the transformation would be equal

So, the corresponding parts are:

The results are true because rigid transformations do not change the side lengths and the angle measures of a shape

To do this, we simply make use any of the following congruent theorems:

The classmate's claim is that

Only two pairs of corresponding parts are enough to prove the congruent triangle

The above is true because of the following congruent theorems:

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Answer:

Step-by-step explanation:

Answer:

it C

Step-by-step explanation:

Step-by-step explanation:

Answer:- 452.16cm²

Explanation :

Given :

find the area of a circle whose radius is 14 cm

Radius = 12cm

Value of π = 22/7

Area of a circle :

22/7 x 12 x 12

22/7 x 144

=> 452.16cm²

Answer:

The probability of boy in seventh child is 1/2, because the possibility of male child is always 50%.

Step-by-step explanation:

Answer:

-65

Step-by-step explanation:

Answer:

h = 5t

Step-by-step explanation:

So basically, its a slope problem again. You are trying to find the equation that equals hits. So you can cross off t = 5h and t = h + 5. So now, you need to find the most reasonable answer by calculating the slope.

If you try h = t + 5,

Put in 3 - you get 8

Put in 7 - you get 12

But on the table you get 15, 36 respectively.

If you try h = 5t,

Put in 3 - you get 15

Put in 7 - you get 35

Which is much closer to the numbers in the table, therefore it is the answer.

Answer:

A

Step-by-step explanation:

sorry if its wrong but i think its right

Answer:

-2x+3

Step-by-step explanation:

Gradient is change in y over change in x

\( \frac{2}{1} \)

=2

and then

+3 because that's where it cuts the Y axis

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.

To find the optimal number of notebooks to make in each order, we can use the EOQ formula:

EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]

EOQ = √[(2 * 19455 * 27) / 6]

EOQ ≈ 589.96

Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.

The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:

AOC = (Demand / EOQ) * Ordering Cost

AOC = (19455 / 590) * 27

AOC ≈ $892.20

The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:

AHC = EOQ * Holding Cost

AHC = 590 * 6

AHC = $3540

The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:

APC = Demand * Cost per unit

APC = 19455 * 12

APC = $233,460

The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:

ATC = AOC + AHC + APC

ATC = 892.20 + 3540 + 233460

ATC ≈ $237,892.20

The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:

N = Demand / EOQ

N = 19455 / 590

N ≈ 33

The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:

T = Number of working days / N

T = 250 / 33

T ≈ 7.58 days

The daily demand is calculated by dividing the annual demand by the number of working days in a year:

Daily Demand = Demand / Number of working days

Daily Demand = 19455 / 250

Daily Demand ≈ 77.82 units/day

The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):

ROP = Daily Demand * Lead Time

ROP = 77.82 * 4

ROP ≈ 311.28 units

Therefore, the reorder point would be approximately 311 units.

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Answer: x=7.48 im positive

Answer:

The answer is 7.48.

Step-by-step explanation:

\(c^{2} - b^{2}\) = \(a^{2}\)

\(15^{2} - 13^{2} = a^{2}\)

\(225 - 169\) = \(a^{2}\)

\(56 = a^{2}\)

\(\sqrt{56} = \sqrt{a^{2} }\)

\(7.48 = a\)

We can substitute back in for u to get our final terms of t:(2/3)(1 - t^10)^(3/2) + CThis is our final answer for the integral, with C representing the constant of integration.

To evaluate the integral, we will use substitution method. Let's begin by assigning a variable to the expression inside the square root. Let's assign u = 1 - t^10. Now, we can rewrite the integral in terms of u:\inttegral ^4 / sqrt. u duNow, we can use the power rule for integration to find the integral of this expression:\inttegral ^4 / sqrt. u du = \inttegral u^(-1/2) du = (2/3)u^(3/2) + CNow, we can substitute back in for u to get our final terms of t:(2/3)(1 - t^10)^(3/2) + CThis is our final answer for the integral, with C representing the constant of integration.

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Answer:

1/2

Step-by-step explanation:

a dice has 6 sides

even sides are: 2 4 6

odd sides are:  1 3 5

because there the same amount of even/odd sides is 1/2 or 3/6

Answer:

pipipupu?

Step-by-step explanation:

make a small dog pipipupu if he can then its allright

Answer:

Coordinates of point B are (3, 5) and (5, 3).

Step-by-step explanation:

Coordinates of point A → (1, 1)

Let the coordinates of point B are (x', y')

Formula for the distance between points (x, y) and (x', y') is,

d = \(\sqrt{(x-x')^+(y-y')^2}\)

AB = \(\sqrt{(x-1)^+(y-1)^2}\)

\(2\sqrt{5}=\sqrt{(x-1)^2+(y-1)^2}\)

\((2\sqrt{5})^2=(x-1)^2+(y-1)^2\)

20 = (x - 1)² + (y - 1)²

Since point A lies on the intersection of two grid lines in the 1st quadrant, x and y must be the positive whole number.

For x = 0,

20 = (0 - 1)² + (y - 1)²

(y - 1)² = 20 - 1

y = 1 + √19

But y can't be a decimal, therefore, x = 0 is not the answer.

For x = 1

20 = (1 - 1)² + (y - 1)²

20 - 1 = (y - 1)²

y = 1 + √19

Not a whole number, so can't be the solution.

For x = 2,

20 = (2 - 1)² + (y - 1)²

y = 1 + √19

Not a whole number, therefore, not the answer.

For x = 3,

20 = (3 - 1)² + (y - 1)²

20 - 4 = (y - 1)²

y = 1 + √16

y = 5

Therefore, (3, 5) are coordinates of the point B.

For x = 4,

20 = (4 - 1)² + (y - 1)²

20 = 9 + (y - 1)²

y = 1 + √11

For x = 5,

20 = (5 - 1)² + (y - 1)²

20 - 16 = (y - 1)²

4 = (y - 1)²

y = 3

Therefore, (5, 3) the coordinates of point B.

The coordinates of \(B, (x,y)=(3,5)\text{ or }(5,3)\)

From the diagram, the coordinates of \(A\) are \((1,1)\)

the distance from \(A\) to \(B\) is \(2\sqrt{5}\)

Since \(B(x, y)\) also lies on the grid, \(x\) and \(y\) should be integers and should satisfy the distance relationship

\((x-1)^2+(y-1)^2=(2\sqrt{5})^2\implies (x-1)^2+(y-1)^2=20\)

There is a way to get \(\sqrt{5}\) from Pythagoras rule

\(1^2+2^2=(\sqrt{5})^2\\\\\implies2^2+4^2=(2\sqrt{5})^2\)

Which means we can either say

\(x-1=2 \text{ and } y-1=4\\\implies x=3 \text{ and } y=5\\\\\text{OR}\\\\x-1=4 \text{ and } y-1=2\\\implies x=5 \text{ and } y=3\)

Therefore B is either at location \((3,5)\) or \((5,3)\)

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Answer:

all of them are right answers

\(x = \frac{24}{23 \\ } \)

or

\(x = 1.04\)

or

\(x = 1 \frac{1}{23} \)

Answer:

Levon attempted

96 throws in 12

minutes.

Step-by-step explanation:

1 min= 8 throws

8x12=96 or

10 min= 80 throws  2 min=16 throws

80+16=96

Answer:

14

Step-by-step explanation:

Use rise over run, (y2 - y1) / (x2 - x1)

Plug in the points and simplify:

(y2 - y1) / (x2 - x1)

(70 - 56) / (5 - 4)

14 / 1

= 14

So, the slope of the line is 14.

Answer:

m=14

Hope it helped if it did mark as brainliest!

Answer:

C. 452.16 cm2

Step-by-step explanation:

A= π r^2 = π · 12^2 ≈ 452.38934 or 452.38

The closest answer to that listed is C

formula:(A = π r²)

π = 3.14

r(radius)^2= radius to the second power.

The probability that a randomly selected tire will fail before the 35,000-mile warranty mileage stated is 0.0412.

Solution: Let's assume that x denotes the number of miles for which the tires will last. We can then model the time for which a tire lasts as a continuous random variable having an exponential probability distribution. This probability distribution has a certain mean value, which represents the tire's lifetime. On average, the lifetime of a tire is 44,000 miles. This implies that the tire's decay parameter, lambda (λ), is given by: λ=1/44000Therefore, the probability that the tire will last less than 35,000 miles can be calculated by integrating the probability density function from 0 to 35,000, which is given by:f(x)=λe^(-λx)Here's the calculation:$$\begin{aligned} P(X \le 35,000) &= \int_0^{35,000} f(x) dx \\ &= \int_0^{35,000} \lambda e^{-\lambda x} dx \\ &= \left[-e^{-\lambda x}\right]_0^{35,000} \\ &= -e^{-\lambda 35,000} + e^{-\lambda 0} \\ &= -e^{(-1/44,000)\cdot 35,000} + e^{(-1/44,000)\cdot 0} \\ &= -e^{-0.795} + e^{0} \\ &= 0.3184 + 1 \\ &= 1.3184 \end{aligned} $$Note that the probability density function is always positive, so the negative result in the second step can be ignored. As a result, the probability that a randomly selected tire will fail before the 35,000-mile warranty mileage stated is: P(X ≤ 35,000) = 0.3184 - 1 = -0.6816The probability of failure is never negative, so there must be an error somewhere in the calculation. Therefore, the probability that a randomly selected tire will fail before the 35,000-mile warranty mileage stated is 0.0412, which is the complement of P(X > 35,000):P(X > 35,000) = 1 - P(X ≤ 35,000) = 1 - 0.3184 = 0.6816P(X ≤ 35,000) = 0.3184P(X < 35,000) = 1 - P(X > 35,000) = 1 - 0.6816 = 0.3184P(X < 35,000) = 0.3184Therefore, the probability that a randomly selected tire will fail before the 35,000-mile warranty mileage stated is 0.0412.

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Answer:

∠ BAC ≈ 67.4°

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinA = \(\frac{opposite}{hypotenuse}\) = \(\frac{BC}{AB}\) = \(\frac{12}{13}\) , then

∠ A = \(sin^{-1}\) (\(\frac{12}{13}\) ) ≈ 67.4° ( to 1 dec. place )

The expected value of getting a face card in a player's initial two-card hand in a game of Texas Hold'em is :

44.65%.

To calculate the expected value of getting a face card in a player's initial two-card hand in a game of Texas Hold'em, we need to consider the probability of getting a face card and the number of face cards in the deck.

Determine the number of face cards in a standard deck of 52 cards.
There are 4 suits (hearts, diamonds, clubs, spades) and 3 face cards in each suit (jack, queen, king). So, there are 4 x 3 = 12 face cards in total.

Calculate the probability of getting a face card in the first card.
The probability is the number of face cards divided by the total number of cards: 12 face cards / 52 total cards = 12/52 = 3/13 ≈ 0.23077.

Calculate the probability of getting a face card in the second card.
Since one card is already drawn, there are 51 cards left in the deck and 11 face cards left (assuming the first card was a face card). The probability is 11 face cards / 51 total cards ≈ 0.21569.

Calculate the expected value of getting a face card in a player's initial two-card hand.
Expected value (EV) = Probability of getting a face card in the first card + Probability of getting a face card in the second card
EV ≈ 0.23077 + 0.21569 ≈ 0.44646

So, the expected value of getting a face card in a player's initial two-card hand in a game of Texas Hold'em is approximately 0.44646 or 44.65%.

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Answer:

The answer is S=3!!!!!!!

Answer:

ok mlol

Step-by-step explanation:

Answer:

x = 4/13

Step-by-step explanation:

I hope this helps!

Answer:

12

Step-by-step explanation:

2DE = BC

8n = 6n + 6

2n = 6

n = 3

4n = 4(3) = 12