6. a solution of phosphoric acid, h3po4, is found to contain 35.2 g of h3po4 per liter of solution. calculate the molarity and normality of the solution.

Answer:

2p is the correct representation

Explanation:

Answer:

Metals have high densities, high melting points, are malleable and ductile, and can conduct heat and electricity.

The average atomic mass of cadmium based on the given percent abundance is approximately 114.16 atomic mass units (amu).

Isotopes are atoms of the same element that have different numbers of neutrons in their nuclei, resulting in different atomic masses.

To calculate the average atomic mass of cadmium based on the given percent abundance, we need to first find the atomic masses of each isotope, and then use the following formula:

average atomic mass = (percent abundance of isotope 1/100 x atomic mass of isotope 1) + (percent abundance of isotope 2/100 x atomic mass of isotope 2) + ...

The atomic masses of the isotopes of cadmium are:

Cd-110: 109.903002

Cd-111: 110.904178

Cd-112: 111.902757

Cd-114: 113.903358

Cd-116: 115.904756

Using the formula, we can calculate the average atomic mass of cadmium as follows:

average atomic mass = (12.9/100 x 109.903002) + (13.3/100 x 110.904178) + (36/100 x 111.902757) + (30.3/100 x 113.903358) + (7.5/100 x 115.904756)

average atomic mass = 14.155350058

Therefore, the average atomic mass of cadmium based on the given percent abundance is approximately 114.16 atomic mass units (amu).

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The factor that describes why H2S is more nucleophilic than H2O is polarizability. This is because sulfur (in H2S) is larger than oxygen (in H2O) and has more electrons in its outer shell, making it more easily distorted by a positive charge and therefore more nucleophilic.

The factor that best describes why H2S is more nucleophilic than H2O is polarizability. H2S has larger sulfur atoms with more diffuse electron clouds, making it more easily distorted and more likely to form a bond with an electrophile compared to the smaller, less polarizable oxygen atom in H2O.

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Answer:

Explanation: A.0

Answer:

C

Explanation:

The percent composition of an atom in a molecule gives information regarding the relative amount of mass an atom contributes to a molecule.

The statement in which La Niña affect the climate of the Pacific Ocean is "The cold water sinks deeper into the ocean."

La Niña is a climate phenomenon that depicts the cooling of surface ocean waters along the coast of South America's tropical west coast.

The average weather in a certain place over a longer length of time is referred to as climate.

The jet stream moves northward and weakens across the eastern Pacific as a result of La Niña. The South experiences warmer and drier weather than usual during La Nia winters. The North and Canada are wetter and colder than the rest of the country. The seas off the Pacific coast are cooler and contain more nutrients than typical during La Niña.

Water in the eastern Pacific is colder than typical because to La Niña. El Niño might cause the water to be warmer than usual in the same place. During La Niña years, drought-stricken areas are drenched, while El Niño years are drenched.

Hence the correct option is 2.

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His blood volume will increase and its osmolarity will decrease after administering 5 liters of 300moS fluid.

Osmoles of solute per liter of solution serve as a quantitative unit for expressing the concentration of osmotically active particles in solution, or osmolarity. The term "osmolality" refers to the quantity of solute particles per liter of solution, and it is commonly stated in terms of osmoles per liter (Osm/L) or milliosmoles per liter (mOsm/L).

The direction of fluid transport within an organism can be determined by the plasma osmolality and oncotic pressure, therefore it's critical to have emergency care on hand in case it's required during labor and after delivery. Insufficient blood flow to bodily organs causes postpartum hemorrhage (PPH), which can result in shock and death.

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Answer:

a) melting point

Answer:

hex-

Explanation:

Prefix Prefix meaning Sample word

hex-           6                                  hexapod: having six legs, an insect, for      

                                                                   example.

Answer:

Hex-

Explanation:

Answer:

-pneumonoultramicroscopicsilicovolcanoconiosis.ogg

Answer: The Solvay process is an industrial process, also known as the ammonia-soda process

Explanation:

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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A gas phase may not be present in the phosphorus cycle, unlike the other major biogeochemical cycles; however, in some cases, small amounts of phosphoric acid (H3PO4) differ from nitrogen

That do reach the atmosphere can result in acid rain. At least one step of the processes for the elements sulfur, carbon, nitrogen, and water involves the gaseous state. phosphorus cycle and its various derivatives are not gases at Earth's natural temperatures and pressures, so there is an inadequate amount of phosphorus cycle circulating in the atmosphere. Sedimentary soil is the main source of phosphorus.

The movement of phosphorus through the lithosphere, hydrosphere, and nitrogen is referred to as the phosphorus cycle, a sedimentary nitrogen cycle.

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There could be several reasons why a student produced less magnesium oxide than expected. Here are two possibilities: Incomplete reaction,  Loss of product

Incomplete reaction: Magnesium oxide is produced when magnesium metal is heated in the presence of oxygen. However, if the reaction is incomplete, then less magnesium oxide will be produced. One reason for incomplete reaction could be that the temperature was not high enough to provide the necessary activation energy.

Loss of product: It is possible that some of the magnesium oxide that was produced was lost during the experiment. For example, if the magnesium oxide was not handled carefully after it was produced, it may have been spilled or blown away.

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Answer:

(the numbers are suppose small on the bottom right of the letter)

1. H2SO4 + K

2. H2SO4 + Mg

3. HCL + Na

The negatively charged atoms are known to show the electron affinity. Hydrogen is more reactive than oganesson based on electron affinity.

The amount of energy released when an electron is added to a neutral atom to create a negatively charged ion is known as electron affinity in chemistry.

Due to the difficulty in determining atoms' electron affinities, values are only known for a small number of chemical elements, primarily halogens.

Similar towards how chlorine can achieve the configuration of noble gases and become an electronegative ion, hydrogen has a high attraction for electrons, becoming the hydrogen anion and obtaining the stable configuration of helium.

The first synthetic element to belong to group 18 (the noble gases), oganesson has the potential to be substantially more reactive than the other members of that group.

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Answer:

magnesium oxide MgO      

Explanation:

i thinnnk

Mg⇒O2=MgO

Answer:

Yes

Explanation:

Answer:

THATS WHAT SHE SAID

Explanation:

Mid-Atlantic region generalized New York State landscape region is drained by the Susquehenna River and its tributaries

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Answer

0.1

Explanation

Given:

mass of HCl = 0.915g

volume of HCl = 250 mL

We know the molar mass of HCl = 36,458 g/mol

Solution

Step 1: covert the volume from mL to L

1 mL = 0.001 L

therefore 250 mL = 0.25 L

Step 2: Calculate the number of moles of HCl

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 0.915 g/36,458 g/mol

n = 0.025 mol

Step 3: Calculate the molarity

C = n/V where C is the molarity, n is the moles and V is the volume

C = 0.025 mol/0.25 L

C = 0.1

The standard Gibbs free energy change (ΔG∘rxn) for the reaction involving hypochlorous acid (HClO) at 296K is determined using  ΔG∘rxn =-RTln(K), where R is the gas constant, T is the temperature in K.

To calculate ΔG∘rxn, we use the equation ΔG∘rxn = -RTln(K), where R is the gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin. In this case, the equilibrium constant (K) is determined by the acid dissociation constant (Ka) for HClO. The equilibrium constant expression for the reaction is K = [HClO−][H3O+]/[HClO].

Given that Ka = 2.9 × 10^–8, we substitute this value into the K expression. Next, we calculate ΔG∘rxn using the given temperature of 296 K. By plugging in the values into the equation ΔG∘rxn = -(8.314 J/(mol·K))(296 K)ln(2.9 × 10^–8) and evaluating the expression, we can determine the value of ΔG∘rxn for the reaction involving HClO at 296 K.

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Answer:

Verdadero.

Explanation:

¡Hola!

En este caso, dado que las propiedades periódicas nos hablan de un comportamiento específico sobre los elementos en la tabla periódica, resulta primeramente necesario recordar que la electornegatividad nos dice que tan fuerte es un elemento para atraer electrones de valencia de otros elementos.

De este modo, inferimos que es verdadero, ya que de hecho la electronegatividad nos define el tipo de enlace, basado en la diferencia de electronegatividades de los elementos enlazados, de acuerdo con la imagen adjunta.

Saludos!

The depreciation expense for the year ended December 31, 2016, given the straight-line method, a 5-year useful life, and a salvage value of $600, is $1,320.

The depreciation expense for the year ended December 31, 2016, can be calculated using the straight-line method, which allocates the cost of an asset evenly over its useful life. In this case, the equipment was purchased for $7,200 on July 1, 2016, and has a useful life of 5 years with a salvage value of $600.

To calculate the annual depreciation expense, we need to determine the depreciable cost, which is the original cost minus the salvage value. In this case, the depreciable cost would be $7,200 - $600 = $6,600.

Next, we divide the depreciable cost by the useful life to determine the annual depreciation expense. In this case, the annual depreciation expense would be $6,600 / 5 = $1,320.

Therefore, the depreciation expense for the year ended December 31, 2016, given the straight-line method, a 5-year useful life, and a salvage value of $600, is $1,320.

The depreciation expense is calculated by subtracting the salvage value from the original cost to determine the depreciable cost. Then, the depreciable cost is divided by the useful life of the asset to determine the annual depreciation expense.

In this case, the firm purchased equipment for $7,200 on July 1, 2016, with a 5-year useful life and a salvage value of $600. Therefore, the annual depreciation expense for the year ended December 31, 2016, would be $1,320.

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Answer:

option d

Explanation:

isotope means atoms with different mass no. 17 and 18 written on the left represent mass number

this is because atoms can differ in mass no.

If Half- life of an isotope is 30 days and it was assumed that the person ate 100 Bq of isotope, there are 50 transformations in the stomach.

The radioactive decay of a sample of an isotope can be characterized by the half-life of that isotope. When a radioisotope undergoes decay, its nucleus becomes unstable, and it emits particles or energy to become more stable. The half-life of an isotope is the time it takes for half of the original sample to decay. The question states that the half-life of an isotope is 30 days, and the person ingested 100 Bq of isotope. It also says to calculate the number of transformations in the stomach using GI track model information .

Since the isotope has a half-life of 30 days, we can use the following formula to find the number of transformations in the stomach:` N = N₀ (1/2)^(t/T₁/₂)`where: N₀ = initial number of nuclei N = final number of nuclei (after time t)T₁/₂ = half-life of the isotope The isotope has a half-life of 30 days, so T₁/₂ = 30 days. The question doesn't specify how long the person has had the isotope in their stomach, so we'll assume it's been there for one half-life, or 30 days. Therefore, t = 30 days.

Substituting into the formula:` N = 100 (1/2)^(30/30)`Simplifying:` N = 100 (1/2)^1`Evaluating:`N = 50`So after 30 days in the stomach, the person would have 50 Bq of the isotope left. Therefore, the number of transformations in the stomach is the difference between the initial number of transformations (100 Bq) and the final number of transformations (50 Bq):`Number of transformations in stomach = 100 - 50 = 50 transformations. Therefore, there are 50 transformations in the stomach.

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The molarity of the solution is approximately 0.148 M.

To calculate the molarity of a solution, you need to know the moles of solute and the volume of the solution in liters.

First, let's determine the moles of solute (C₆H₁₂O₆) using its mass and molar mass. The molar mass of C₆H₁₂O₆ is calculated by adding the atomic masses of carbon, hydrogen, and oxygen:

C6H12O6:

6 carbon atoms (C) x atomic mass of carbon = 6 * 12.01 g/mol = 72.06 g/mol

12 hydrogen atoms (H) x atomic mass of hydrogen = 12 * 1.01 g/mol = 12.12 g/mol

6 oxygen atoms (O) x atomic mass of oxygen = 6 * 16.00 g/mol = 96.00 g/mol

Total molar mass of C₆H₁₂O₆ = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol

Next, we can calculate the moles of C₆H₁₂O₆: moles = mass / molar mass = 40.0 g / 180.18 g/mol ≈ 0.222 mol

Now, we need to convert the volume of the solution from milliliters to liters:

volume = 1500 ml = 1500 ml / 1000 ml/L = 1.5 L

Finally, we can calculate the molarity (M) of the solution using the formula:

Molarity = moles of solute / volume of solution in liters

Molarity = 0.222 mol / 1.5 L ≈ 0.148 M

Therefore, the molarity of the solution is approximately 0.148 M.

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Answer:

Increasing the temperature

Increasing particle size

Explanation:

Increasing the temperature allows for particles and molecules to move faster (because there is an increase in energy) and allows for more collisions.

∴ Increasing the temperature would be an answer.

Increasing the particle size allows for more surface area and a greater chance for particles to collide with each other.

∴ Increasing particle size would be an answer.

Topic: AP Chemistry

Unit: Kinetics

Answer:

10,765 g As

Explanation: