6. A car begins traveling at 15 m/s before it has engine trouble and has to stop.the force it takes the car to stop is 15,000 N what is the mass of the car?

Given:

The initial temperatures of the liquids 1,2 and 3 are

the final temperature of the first two liquids is

the final temperature of the second and third liquids is

Required:

final temperature of the first and third liquidd.

Explanation:

to solve this problem apply principal of calorimetry here,

for the first two liquids is

plugging all the values in the above relation we get

here k1 nad k2 are the specific heat of the two liquids

now similarly for, second and third liquids

here, k3 is specific heat of liquid three

from the equation (1) and (2) we can write

now for liquid first and third

Plugging all the values in the above relation we get

Thus, the final equilibrium temperature is

The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.

The J. J. Thomson Method

In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$

When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$

The Millikan Oil Drop Method

This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.

The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.

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The methods to determine the specific charge of an electron are :

In the J. J. Thomson Method, an  electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.

When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.

The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.

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The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Answer:

The amount of liters of fuel should have been added is  20093 L

Explanation:

Given that;

a mechanic used a dipstick to determine that 7682 L of fuel were left on the plane

i.e the volume of fuel left in the plane = 7682 L

Required fuel to make  a trip = 22,300 kg of fuel

Also from the question; we are being told that in order for the pilot to determine the volume ; he asked for the density of the fuel and the mechanic said 1.77.

This volume of fuel was added and the plane subsequently ran out of fuel, but landed safely by gliding into Gimli Airport near Winnipeg. The error arose because the factor 1.77 was in units of pounds per liter (lbs/L).

Now; we can understand that the density of the fuel was 1.77 pound /litre.

SO , let convert 1.77 pound /litre to kg/Litre;

we all know that

1 pound = 0.4536 kg

1.77 pound/litre  = x kg

If we cross multiply ; we will have:

1.77 pound/litre  × 0.4536 kg = 1 pound × x kg

x kg = (1.77 pound/litre  × 0.4536 kg) /1 pound

x = 0.802872 kg/litre

\(\mathbf{Density = \dfrac{mass}{volume}}\)

where ;

mass =  22,300 kg of fuel

volume = unknown ???

density = 0.802872 kg/litre

making volume the subject of the formula from above; we have:

\(\mathbf{volume = \dfrac{mass}{Density}}\)

\(\mathbf{volume = 22300 \ kg \ of \ fuel *\dfrac{1 \ litre }{0.802872 \ kg \ of \ fuel}}\)

volume = 27775.28672 litre

volume \(\approx\) 27775 L

Let not forget that we are being told as well that the volume of fuel left in the plane = 7682 L

Now;

The amount of liters of fuel should have been added is: =  27775 L - 7682 L

The amount of liters of fuel should have been added is  20093 L

Answer:50

Explanation:

The current flowing through the given circuit is 0.12 A.

The given parameters;

The current passing through the headlight is calculated by applying Ohms law as shown below;

V = IR

where;

Substitute the given parameters and solve the current flowing in the circuit;

\(V = IR\\\\I = \frac{V}{R} \\\\I = \frac{12}{10} \\\\I = 0.12 \ A\)

Thus, the current flowing through the given circuit is 0.12 A.

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Answer:

2 to 3 weeks

Explanation:

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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Answer:

233.33°F

Explanation:

(385K - 273.15) * 9/5 + 32 = 233.33°F

Answer:

126.01 rad/s^2

Explanation:

since it starts from rest, initial angular speed ω' = 0 rad/s

angular speed N = 477 rev/min

angular speed in rad/s ω = \(\frac{2\pi N}{60}\) =  \(\frac{2*3.142* 477}{60}\) = 49.95 rad/s

angular displacement ∅ = 1.5758 rev

angular displacement in rad/s = \(2\pi N\) = 2 x 3.142 x 1.5758 = 9.9 rad

angular acceleration \(\alpha\) = ?

using the equation of angular motion

ω^2 = ω'^2 + 2\(\alpha\)∅

imputing values, we have

\(49.95^{2} = 0^{2} + (2 *\alpha*9.9 )\)

2495 = 19.8\(\alpha\)

\(\alpha\) = 2495/19.8 = 126.01 rad/s^2

Answer:

58.56 J

Explanation:

Since the formula for gravitational potential energy is:

GE = m x g x h - where m = mass (kg), g = acceleration due to gravity (9.81 m/s²), h = height (m)

GE= 3 x 9.81 x 2

GE = 58.86 J

Hope this helps

Answer: (1) C, (2) B

Explanation: I took the test, but to solve question 1 use the inelastic collision formula m1v1+m2v2 = (m1+m2)v2 to get the answer. Question 2 is b because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.

The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.

The kinetic energy of the bouncy ball after it collides with floor is 30 J.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

According to the given in question,

a.) Using inelastic collision formula

\(m_1v_1+m_2v_2 = (m_1+m_2)v_2\)

\(v_2\) = 60/16 m/sec = 3.75 m/sec

b.) Because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.

The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.

The kinetic energy of the bouncy ball after it collides with floor is 30 J.

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Answer:

iv

Explanation:

to be honest the others make since but the last 1 and all of the others are actually used.

-NULL

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Answer:

Explanation:

To find the force acting on an object we use the formula

From the question

mass = 3.5 kg

acceleration = 0.80 m/s²

We have

Force = 3.5 × 0.8

We have the final answer as

Hope this helps you

Answer:

Velocity is a vector whose magnitude is called speed. Collision study needs to analyse the transfer of momentum, which is another vector quantity associated with the velocity vector of each object

Explanation:

The important concept to recall is that velocity is a vector quantity, which has direction apart from just magnitude (as speed is). So in the transfer of momentum (another vector quantity) that takes place in a collision, it is extremely important to know the direction of the velocity vector, since there is much larger transfer of momentum if the cars collide heads on, than if the cars collide from behind while going in the same direction.

The weight must be 288N placed on the end of the spring when it is 2m from the ground.

If an object is lifted, work is done against gravitational force. The object gains energy.

Given is a spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground. The final height of weight above the ground, h =2m

Using Hooke's law, expressed as

Force, F = k (x₂-x₁).

Put the values, we get

F = 48 (8-2)

F = 288 N

This force applied on the spring is equal to the weight placed on the spring.

Weight W= 288N.

Thus, the weight must be 288N.

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The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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Answer:

d. context

Explanation:

Answer:

See below

Explanation:

Average speed =  (0+ 10)/2 = 5 m/s

 then to cover 50 m     will take    50 m / 5 m/s  = 10 seconds

     change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2

The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

Substances Used to Fill It:

A mixture of "brown" and "green" organic materials such as leaves, grass clippings, fruit and vegetable scraps, coffee grounds, and shredded paper can be used to fill the bin.

Household Items That Can Go in It:

Most fruit and vegetable scraps, eggshells, tea bags, coffee grounds, yard waste such as grass clippings and leaves, and shredded paper can be added to the compost bin. Meat, dairy, and fatty foods should be avoided.

How Long It Takes Before It Is Ready:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

How You Use the Compost:

The finished compost can be used as a nutrient-rich soil amendment for planting and gardening.

Compost Bin Design:

To add household items to your compost bin, simply add any of the following organic materials to the bin: fruit and vegetable scraps, coffee grounds and filters, tea bags, eggshells, yard waste such as leaves and grass clippings, and shredded paper.

Compost is ready to use in this much time:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

Use your compost this way:

The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

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According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.

Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.

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Answer:

A. The nucleaus is filled with cytoplasm OR d. The nucleus is by a double layer membrane.

Explanation:

b. and c. are true and I'm certain they are true

a. I know the inside of a cell has cytoplasm but I'm not sure if the inside of a nucleus is filled with cytoplasm. And d. I'm not so sure, so it's either a or d. Hope this helps!

The electric field E at a point in space is defined as the gradient of the electric potential at that point, which is the negative of the rate of change of the potential with respect to position. In this case, the gradient of the electric potential V can be found by taking the derivative of V with respect to x: dV/dx = 6 - 8x

The magnitude of the electric field at the point (3,0) is then given by the magnitude of the gradient at that point:

E =|dV/dx| = |6 - 8x| = |6 - 8(3)| = |-18| = 18 Volts/meter. So the magnitude of the electric field at the point (3,0) is 18 Volts/meter.

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Answer:

b

Explanation:

sorry if i got it wrong

Answer:

85.12 μAmp

Explanation:

The battery power output = 17.15 Amp-hr

If the battery is to last 23 years, we have to calculate how many hours there are in 23 years

in one year there are 24 hours x 365 day = 8760 hrs

in 23 years there are 23 x 8760 = 201480 hours

maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = 85.12 μA

The velocity of the ball is 19.6 m/s and when the ball lands, it is moving at a speed of 77.134 m/s.

All objects with mass are subject to gravity, which is a fundamental force of nature. It is the force that pulls everything toward the core of a planet or other entity.

(a) The equation can be used to determine the velocity of a dropped ball.

v = v0 + a * t

where a is the acceleration caused by gravity (9.8 m/s2), v0 is the beginning velocity (0 in this case because the ball is dropped from rest), and t is the amount of time that has passed.

Therefore, if t = 2 seconds, the ball's velocity at that time would be:

v = 0 + 9.8 * 2 = 19.6 m/s

(b) The ball's final velocity is identical to its velocity when it lands. The following equation can be used to determine how long it takes the ball to touch the ground:

t = √(2h / a)

where a is the acceleration brought on by gravity (9.8 m/s2) and h is the height (in this case, 300 m) from which the ball is dropped.

Thus, the duration of time required for the ball to touch the ground is:

t = √(2 * 300 / 9.8) = √(600 / 9.8) = √(61.22) = 7.83 s

The formula: can be used to determine the ball's velocity when it lands.

v=v0 + a*t = 0 + 9.8 * 7.83 = 77.134 m/s

So, when the ball lands, it is moving at a speed of 77.134 m/s.

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Answer:

The ball will go as high as 8.46 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:

\(\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}\)

The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of \(g=9.8 m/s^2\), then:

\(\displaystyle h_m=\frac{24^2\cdot \sin^2 31^\circ}{2\cdot 9.8}\)

\(\displaystyle h_m=\frac{576\cdot 0.2653}{19.6}\)

\(h_m=7.80~m\)

The ball will go as high as 8.46 m

Answer:

Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.

Explanation:

Answer:

37500 N

Explanation:

F = ma

F = 7500 (5 m/s^2) = 37500 N

Answer: