5xy8 • (4y4)2 = 5xy8 • 42• V4)2

Answers

Answer 1

Answer:

Yes they are equal. Hkama d d jans ans


Related Questions

Judy uses 7.5 pints of white paint and blue paint to paint her bedroom walls.
3/4 of this amount is white paint, and the rest is blue paint. How many pints of blue paint did she use to paint her bedroom walls?

Answers

Step-by-step explanation:

3/4*7.5

5.625

7.5-5.625

1.875

of blue pints

What are the solutions of this quadratic equation?
X^2 = 16x – 65

Answers

Answer:

x= 4.3125

Step-by-step explanation:

Answer:

x=4+7i and x=4-7i

Step-by-step explanation:

Rewrite the given quadratic equation by completing the square.

x^2-8x=-65

x^2-8x+16=-65+16

x^2-8x+16=-49

(x-4)^2=-49

Now, solve the equation by applying the square root property and isolating x.

(x-4)^2=-49

√(x-4)^2 = √-49

x-4=+7i

x=4+7i

So, the solutions to the given quadratic equation are x+4+7i and x=4-7i.

Help me exercise 1 and 2

Help me exercise 1 and 2

Answers

Answer:

it is so hard as I am studying in just grade 8

An isosceles triangle has a perimeter of 23 meters. The base of the triangle is 7 meters.
Write an equation to represent the other lengths, X, of the triangle.

Answers

An equation to represent the other lengths, X, of the triangle is 2X+7=23.

What is meant by an isosceles triangle?

An isosceles triangle is one that has two equal-length sides in geometry. The term "equilateral triangle" can refer to a shape with either exactly two sides that are the same length or at least two sides that are the same length, with the latter definition containing the equilateral triangle as an exception. The faces of bipyramids and a few Catalan solids are examples of isosceles triangles, as are the isosceles right triangle, the golden triangle, and others.

Isosceles triangles have been the subject of mathematical research since the time of the Babylonians and the Egyptians.

Given,

Perimeter of an isosceles triangle=23 meters

The base of a triangle=7 meters

P=2X+b

2X+7=23

Therefore, an equation to represent the other lengths, X, of the triangle is 2X+7=23.

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9. Look at some of the printed letters in a textbook. The small horizontal
and vertical segments attached to the ends of the letters are called
serifs. Most of the letters in a textbook are in a serif typeface. The
letters on this page do not have serifs, so these letters are in a sans-
serif typeface. (Sans means "without" in French.) The figure shows a
capital letter A with serifs. Use the given information to write a
paragraph proof that the serif, segment HI, is parallel to segment JK.
Given: 21 and 23 are supplementary.
Prove: HI || JK

Answers

By considering the given information that angles 21 and 23 are supplementary and analyzing the properties of supplementary angles and parallel lines, we have proven that segment HI is parallel to segment JK.

To prove that segment HI is parallel to segment JK based on the given information that angles 21 and 23 are supplementary, we can utilize the properties of supplementary angles and parallel lines.

First, let's examine the given figure and information.

We have a capital letter A with serifs, where segment HI represents one of the serifs, and segment JK represents a horizontal line within the letter A.

To begin the proof, we'll make use of the fact that angles 21 and 23 are supplementary.

Supplementary angles are defined as two angles whose measures sum up to 180 degrees.

We can observe that angle 21 is an interior angle of triangle AHI, and angle 23 is an interior angle of triangle AJK.

Since angles 21 and 23 are supplementary, their sum is equal to 180 degrees.

Now, let's assume that segments HI and JK are not parallel.

In this case, if we extend lines HA and JA, they will eventually intersect at point P.

Since the angles formed at the point of intersection are supplementary (angle 21 + angle 23 = 180 degrees), it would imply that angle 21 and angle PJK, as well as angle 23 and angle PHI, are also supplementary.

However, this leads to a contradiction. In the original figure, we can observe that angle 21 and angle PJK do not form a supplementary pair since angle PJK is a right angle (90 degrees) in the letter A.

Therefore, our assumption that segments HI and JK are not parallel must be incorrect.

Consequently, we can conclude that segment HI is indeed parallel to segment JK.

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James used 42% of the money on a gift card to purchase groceries. If he spent $67.20 on groceries, how much was on the gift card to begin with?

Answers

Answer:

160 dollars

Step-by-step explanation:

whats 5x5
5x5x5x5x5x5x5x5xc5

Answers

Answer

1953125

Step-by-step explanation:

Answer:

9765625

Step-by-step explanation:

in a shooting match, eight clay targets are arranged in two hanging columns of three targets each and one column of two targets. a marksman is to break all the targets according to the following rules: 1) the marksman first chooses a column from which a target is to be broken. 2) the marksman must then break the lowest remaining target in the chosen column. if the rules are followed, in how many dierent orders can the eight targets be broken?

Answers

Therefore, there are 72 different orders in which the eight targets can be broken according to the given rules.

To find the number of different orders in which the eight targets can be broken, we can consider the arrangement of the columns and the targets within each column. Since there are three targets in each of the first two columns and two targets in the third column, we can focus on the relative order of breaking the targets within each column. Let's represent the columns as follows:

Column 1: T T T

Column 2: T T T

Column 3: T T

To calculate the number of different orders, we can count the permutations of breaking the targets within each column and then multiply them together.

For Column 1, there are 3 targets, so there are 3! = 3 × 2 × 1 = 6 possible orders.

For Column 2, there are also 3 targets, so there are 3! = 6 possible orders.

For Column 3, there are 2 targets, so there are 2! = 2 possible orders.

To find the total number of different orders, we multiply the number of orders for each column:

Total number of orders = 6 × 6 × 2

= 72

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The diagonals of this rhombus are 4 inches and 10 inches.
10 in.
4 in.
What is the area of the rhombus?
square inches

Answers

i can send you a picture if you want me to do it or if not i’ll lol it looks really good and yea it was good but not too big ago but it’s like crazy lol how did you do it

Which of the following represents the factorization of the polynomial below?
2x2 +11x +5

Answers

Answer:

(2x + 1)(x + 5)

Step-by-step explanation:

2x² + 11x + 5 =

= 2x² + 10x + x + 5

= 2x(x + 5) + (x + 5)

= (2x + 1)(x + 5)

An experiment is conducted with a bag of marbles containing 5 red and 2 blue marbles. The results of a marble being drawn twice and replaced 100 times are shown in the table. Outcome Frequency Red, Red 19 Red, Blue 32 Blue, Blue 21 Blue, Red 28 Find P(no blue).

Answers

The probability of getting no blue is 19/100.

Given that an experiment is conducted with a bag of marbles containing 5 red and 2 blue marbles.

The results of a marble being drawn twice and replaced 100 times are shown in the table.

Outcome Frequency = Red, Red 19 Red, Blue 32 Blue, Blue 21 Blue, Red 28

We need to determine the probability of getting no blue.

So, in every event there is a blue marble except the first event =

(red, red) = 19.

So, the probability of not getting a blue marble = 19/100

Therefore, probability of getting no blue is 19/100.

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___ could be used to solve the problems caused by the electoral college.

Answers

One possible solution that could be used to address the problems caused by the Electoral College is "electoral reform."

Popular Vote: One approach is to replace the Electoral College with a system where the President is directly elected by a popular vote. This would eliminate the possibility of a candidate winning the presidency while losing the popular vote, as has happened in some elections.

Proportional Representation: Another option is to implement a proportional representation system, where the allocation of electors is based on the percentage of votes a candidate or party receives in each state. This would ensure a more proportional representation of voters' preferences and reduce the influence of winner-takes-all mechanisms.

National Popular Vote Interstate Compact: This reform proposal aims to work within the existing Electoral College framework. States that join the compact agree to allocate their electoral votes to the winner of the national popular vote, effectively ensuring that the candidate who receives the most votes nationwide becomes the President.

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an unbiased coin is tossed four times. what is the probability that coin lands heads up at least once? (round your answer to three decimal places.)

Answers

The probability of getting at least one head is 15/16.

What is probability?

The ratio of positive outcomes to all possible outcomes of an event is known as the probability.

Formula for probability = favourable outcomes/ total outcomes

Main body:

if 4 coins are tossed , total no. of outcomes = 2⁴ = 16

In a toss there are 2 outcomes T or H

so, Probability of getting Head = 1/2

The probability of getting at least 1 head = 1- probability of getting no heads

⇒1 - Probability of getting tail in 4 tosses

⇒ 1 - (1/2)⁴

⇒ 1 - 1/16

⇒ 15/16

So the probability of getting at least one head is 15/16.

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a circular pool is surrounded by a brick walkway 3 m wide. find the ra- dius of the pool if the area of the walk- way is 198 m*.

Answers

The radius of the pool is 9.01 m.

Given,

In the question:

A circular pool is surrounded by a brick walkway 3 m wide.

The area of the walk- way is 198 m^2.

To find the Radius of the pool.

Now, According to the question:

"Area of the circle bounded by the outside edge of the walkway" minus "area of the pool" = "area of the walkway".

Let R = Radius of the pool

Area of the circle bounded by the outside edge of the walkway is:

\(\pi\)(R +3)^2

Area of the pool is:

\(\pi R^2\)

Now, Our equation is:;

\(\pi\)(R +3)^2 - \(\pi R^2\) = 198

\(\pi\)((R+3)^2 - \(R^2\)) = 198

Open the inner bracket :

\(\pi\)(\(R^2+6R+9-R^2\)) = 198

\(\pi\)(6R +9) = 198

6R+9 = 198/\(\pi\)

6R = 198/\(\pi\) - 9

R = (198/\(\pi\) - 9)/6

R = (198/(3.14) - 9)/6

R = (63.057 - 9)/6

R = 54.057/6

R = 9.01 meters

Hence, The radius of the pool is 9.01 m.

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Solve for a and b in the picture.

Solve for a and b in the picture.

Answers

Answer:

a=13 b=10.5

Step-by-step explanation:

jshshdvshxhshxhdbshsgxghsgxghxhsgch

Solve for a and b in the picture.

PLEASE HELP ASAP DUE 11:59 TODAY PLEASE ANSWER 6 and 7.​

PLEASE HELP ASAP DUE 11:59 TODAY PLEASE ANSWER 6 and 7.

Answers

Number 1 is:

C and E

Number 2 is:

400

The temperature at 5:00 a.m. was -23 °F. By 3:00 p.m., the temperature had risen to a high of 38 °F. If the temperature at 8:00 p,m. decreased from the high by 2/5of the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.? Round your answer to the nearest tenths place.

Answers

Temp at 8pm = 38 degrees - (2/5)(change in temp from 5 to 3)

38 - (2/5)(61)
38-24.4 = 13.6 degrees

1.Find the period of the following functions. a) f(t) = (7 cos t)² b) f(t) = cos (2φt²/m)

Answers

Period of the functions: The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ). The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.

We know that cos (t) is periodic and has a period of 2π.∴ b = 2π∴ The period of the function f(t) =

(7 cos t)² = 2π/b = 2π/2π = 1.

The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ) Hence, the period of the function f(t) =

cos (2φt²/m) is √(4πm/φ).

The function f(t) = (7 cos t)² is a trigonometric function and it is periodic. The period of the function is given by 2π/b where b is the period of cos t. As cos (t) is periodic and has a period of 2π, the period of the function f(t) = (7 cos t)² is 2π/2π = 1. Hence, the period of the function f(t) = (7 cos t)² is 1.The function f(t) = cos (2φt²/m) is also a trigonometric function and is periodic. The period of this function is given by T = √(4πm/φ). Therefore, the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

The period of the function f(t) = (7 cos t)² is 1, and the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

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Which of the following is the necessary condition for creating confidence intervals for the population mean? A. Known population parameter B. Normality of the population C. Known standard deviation of the estimator D. Normality of the estimator (e.g., sample mean)

Answers

Answer:

D. Normality of the estimator (e.g., sample mean)

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The question was incomplete. Check below the complete question.

Which of the following is the necessary condition for creating confidence intervals for the population mean? A. Known population parameter B. Normality of the population C. Known standard deviation of the estimator D. Normality of the estimator (e.g., sample mean)

A cylindrical tank is one-fifth full of oil. The cylinder has a base radius of 80 cm. The height of the cylinder is 200 cm. 1 litre 1000 cm3 How many litres of oil are in the tank? Round your answer to the nearest litre

Answers

The number of litres (Volume) of oil that is present in the tank of given dimension is calculated to be 806 litres (approximately).

The volume of any cylinder can be calculated using the formula,

V = πr²h

(Here V is the volume, r is the radius of the base, and h is the height of the cylinder)

As, the cylinder is one-fifth full of oil, which means that it is four-fifths empty. Therefore, the volume of oil in the tank is:

Volume of oil = (1/5) x Total Volume

Substituting the given values, we have:

Total Volume =  π(80cm)²(200cm) = 4,031,240 cm³

Volume of oil = (1/5) x 4,031,240 cm³ = 806,248 cm³

Converting cm³ to litres, we have:

1 litre = 1000 cm³

Volume of oil = 806,248 cm³ ÷ 1000 = 806.248 litres

Therefore, after rounding of the final volume (806.248 litres) to the nearest litre, the final answer is found to be 806 litres of oil.

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A vendor sells fifteen sweatshirts for $15 each, thirty t-shirts for $10 each, and forty hats for $8 each. What is the average price of an item sold that day?

Answers

I think the answer is 3$ because if you divide each item by the price you get 1 3 and 5 3 is more likely to be the middle so that would be your average price the unit rate of each of the items is dividing the price by the number of items to get the price of one item or your unit rate.

A restaurant offered cooking classes on 20 of the 30 day in November.
What percent of the days in November did the restaurant offer cooking classes?

Answers

The percentage is 66.6%.

Step-by-step explanation:

Since the number of days for classes is 20 and the total days in November is 30

% = Number of days for classes

_____________________ *100

Total days in November

% = 20/30 *100

% = 66.7%(approximately)

(20 points, please help!) Using the diagram, what are the measures of angles 1, 2 and 3?

(20 points, please help!) Using the diagram, what are the measures of angles 1, 2 and 3?

Answers

Answer:

angle 1 = 50°

angle 2 = 70°

angle 3 = 50°

Step-by-step explanation:

We know the top triangle equals 180 degrees.

angle 1 + 60 + 70 = 180

angle 1 + 130 = 180

angle 1 = 50

Because of parallel lines, we know that opposite angles will be equal.

What I mean by this is that angle 1 = angle 3 and angle 2 = 70 degrees.

angle 1 = 50°

angle 2 = 70°

angle 3 = 50°

The Ridgeport school district collected data about about class size in the district. The table shows the class sizes for five randomly selected kindergarten and seventh-grade classes.

The Ridgeport school district collected data about about class size in the district. The table shows

Answers

The true statement is "Every seventh-grade class has 12 more students than a kindergarten class." (option d).

For the seventh-grade class, the mean is 32, which is larger than the mean for the kindergarten class. This means that, on average, seventh-grade classes have more students than kindergarten classes. The MAD for the seventh-grade class is 2, which is larger than the MAD for the kindergarten class.

This suggests that the deviation from the mean for each data point in the seventh-grade class is larger, on average 2 students, than for the kindergarten class. This means that the size of seventh-grade classes is more variable than kindergarten classes.

Option D is correct because while the difference between the means of the two classes is 12, this does not mean that every seventh-grade class has 12 more students than every kindergarten class.

Hence the c correct choice is option (d).

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An airplane has a bearing of 30°. Find the velocity of the airplane in component form if it is traveling at 625 mph.Select one:a.<625sin60°, 625cos60°>b.<625cos30°, 625sin30°>c.<625cos60°, 625sin60°>d.<625sin30°, 625cos30°>

Answers

SOLUTION:

From the diagram, we can see that velocity in component form is;

\(\langle625cos30,625sin30\rangle\)

An airplane has a bearing of 30. Find the velocity of the airplane in component form if it is traveling

Question 18 (5 points)
Determine the sum of the measures of the interior angles of a dodecagon (12-sided
polygon).
540°
1,800°
360°
2,160°

Answers

Answer:

its 540 bro

Step-by-step explanation:

plsssssss answer fast

plsssssss answer fast

Answers

B, x=12 because 140-80=60, 60/5=12

The food company is now designing soup cans. They currently make a large can of soup that holds 24oz of soup. They would like to make a single serve can that holds only 8oz of soup. The large can has a surface area of 100.48in². What will the new single serving surface area be? Explain or show your reasoning.​

Answers

The surface area of the new single-serving soup can, with a volume ratio of 24:8, will be approximately 11.164 square inches.

To determine the surface area of the new single-serving soup can, we can use the concept of ratios and proportions.

Let's assume the radius of the large can is represented by R and the radius of the single-serving can is represented by r.

The volume of a cylinder can be calculated using the formula V = πr^2h, where V is the volume, r is the radius, and h is the height.

We know that the large can has a volume of 24oz, so we have:

24 = πR^2h

Now, we need to find the height of the single-serving can. Since the large can and the single-serving can have the same height (we assume), we can set up a ratio of their volumes:

24/8 = πR^2h / πr^2h

Simplifying the equation, we have:

3 = (R^2h) / (r^2h)

Since the height cancels out, we can rewrite the equation as:

3 = R^2 / r^2

To find the ratio of the surface areas, we square both sides of the equation:

9 = (R^2 / r^2)^2

Now, we can find the surface area ratio:

100.48 / A = 9

Solving for A (the surface area of the single-serving can), we have:

A = 100.48 / 9

Calculating the value, we find that the new single-serving surface area will be approximately 11.164 in².

Therefore, the new single-serving soup can will have a surface area of approximately 11.164 square inches.

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I’ll mark you brainlist I’ll mark you brainlist show work

Ill mark you brainlist Ill mark you brainlist show work

Answers

Answer:

X=66

Step-by-step explanation:

114+x=180

X= 66

X= 66

Hope this is right



write an equation of the line that passes through the points:
(0,0), (4,-2)

Answers

Basically you want to plug it into the midpoint formula and the results from both sides will give you x and y make into a point (x, y) and your all set
write an equation of the line that passes through the points:(0,0), (4,-2)
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