-5(x+2)+3x= Which expression can be written in the box on the other side of the equation

It would take 370 days to build the wall with the given conditions.

If 60 men can build a wall in 40 days, then the total man-days required to build the wall is:

60 men x 40 days = 2400 man-days

However, 55 men quit every ten days, which means that after 10 days, there are only 60 - 55 = 5 men left to work on the wall. After 20 days, there are only 5 - 55 = -50 men left, which means that the remaining 5 men cannot work any faster than they were already working. Therefore, we can assume that the remaining 5 men complete the wall on their own.

The number of man-days required for the first 10 days is:

60 men x 10 days = 600 man-days

The number of man-days required for the second 10 days is:

5 men x 10 days = 50 man-days

The total number of man-days required for the first 20 days is:

600 man-days + 50 man-days = 650 man-days

The remaining work can be completed by the 5 men in:

2400 man-days - 650 man-days = 1750 man-days

Therefore, the total time needed to build the wall is:

20 days + 1750 man-days / 5 men = 20 + 350 days = 370 days

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Max is going to have more money than Shawn at the end of the seven weeks from the calculations

We would first have to define x to be the point where the money that they have would be equal

This is the week that is referred to as x

Sean would have $20 + $2x

Max would have $5x

When both amounts are equal, we would have sean = max

= $20 + $2x = $5x

Take like terms

20 = 5x - 2x

20 = 3x

divide through by 3

x = 20 / 3

= 6.6667

Remember

In 7 weeks sean = 20 + 2x 7 = 34

max = 5 x 7 = 75

Hence we can say that Max would have more money than Sean

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Answer:

200+ 40h= c

Step-by-step explanation:

Answer:

the quotient is -4

Step-by-step explanation:

Starting from zero, zero divided by anything is 0. The main concept here is not to divide anything by 0 and just straight of add by 5 because there would be more than one answer for the quotient. I know that 2+3=5 but but I know that my quotient would be smaller than 0 but add up to 3 when I divide it in half and add 5. -4/2=-2 plus 5 is equal to 3. 5>-2 so my answer would be positive.

To find the mass of the lamina, we need to integrate the density function over region D. The density function is given by? (x, y) = 7ky, where k is a constant. The region D is bounded by y = \((1 ? x^2)\)  and y = 0, and the limits of integration are \(0 < = y < = (1 - x^2)\) .

So, the mass of the lamina is:

\(m = ∫∫?(x, y) dx dy = ∫∫ 7ky dx dy\\= 7k ∫∫ y dx dy = 7k * ∫ (1 - x^2) dy dx\\= 7k * ∫(0 to 1 - x^2) y dy\\= 7k * (1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/2 * [((1-x^2)^3/3] - 0))= 7k * (1/2 * (1/3 - x^6))\)

To find the center of mass (x bar, y bar) of the lamina, we need to find the x and y coordinates of the center of mass.

The x-coordinate is given by

\((x bar) = 1/m * ∫∫ x ?(x, y) dx dy = 1/m * ∫∫ x * 7ky dx dy \\= 7k * ∫ (x * y) dx dy\\= 7k * (x * 1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (x * 1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (x * (1/2 * (1/3 - x^6))\\The y-coordinate is given by\\(y bar) = 1/m * ∫∫ y ?(x, y) dx dy = 1/m * ∫∫ y * 7ky dx dy= 7k * ∫ (y^2) dx dy\\= 7k * (1/3 * ∫(0 to 1 - x^2) y^3 dy)\\= 7k * (1/3 * [y^4/4] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/3 * (1/4 - x^6/2))\)

It's worth noting that the mass and center of mass of the lamina depend on the constant k, which is not specified in the problem.

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Answer:

Step-by-step explanation:

so the whole question is as follows

The graph of the feasible region is attached

From the question, we have the following parameters that can be used in our computation:

\(\left\{ \begin{array}{lr} y + 7x \ge 10 \\ 8y + 2x \ge 20 \\ y + x \ge 4 \\ y + x\le 10 \\ x \ge 0 \\ y \ge 0\end{array}\)

To plot the graph of the feasible region, we plot each inequality in the domain x ≥ 0 and y ≥ 0

Using the above as a guide, the graph is attached

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a) The statement " The intersection of two events A and B can be larger than the union of the same two events A and B" is False.

b) The statement " The probability of a single event A must be smaller than or equal to the union of two events A and B" is False.

c) The statement " The condition probability of A given B must be smaller than the intersection of the same two events A and B"  is False.

(a) False. The intersection of two events A and B represents the set of outcomes that are common to both A and B, while the union of the same two events A and B represents the set of outcomes that belong to either A or B or both. Hence, it cannot be larger than the union of A and B.

(b) False. The probability of an event A must be between 0 and 1 (inclusive), while the union of two events A and B represents the set of outcomes that belong to either A or B or both. The probability of the union of A and B is the sum of the probabilities of A and B, which can be larger than the probability of A.

(c) False. The conditional probability of A given B, denoted as P(A|B), represents the probability of event A occurring given that event B has already occurred.  Since the intersection of A and B must be less than or equal to 1, the conditional probability of A given B must also be less than or equal to 1.

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The angle m∠JIX is 90 degrees.

IX is perpendicular to IJ. Therefore, angle m∠JIX is 90 degrees.

IG bisect CIJ. Hence,

m∠CIG ≅ m∠GIJ

Therefore,

m∠CIX = 150 degrees

Hence, let's find m∠JIX.

Therefore, m∠JIX is 90 degrees because IX is perpendicular to IJ. Perpendicular lines forms a right angle.

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The measure of angle m∠JIX is  estimated to be 90⁰.

You should understand that an angle is a figure formed by two straight lines or rays that meet at a common endpoint, called the vertex.

IX is perpendicular to IJ. Therefore, angle m∠JIX is 90⁰.

Frim the given parameters,

IG⊥CIJ.

But;  m∠CIG ≅ m∠GIJ

⇒ m∠CIX = 150⁰

Hence, let's find m∠JIX.

Therefore, m∠JIX is 90⁰ because IX is perpendicular to IJ. Perpendicular lines forms a right angle.

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Answer:

Step-by-step explanation:

85% of fasteners = conforming

10% of fasteners = downgraded

5% of fasteners = scrap

In a sample size of 500 fasteners

410 = conforming , 55 = downgraded,

The true percentage actually differ from 85%, 10%, and 5% as shown below

                               Observed Expected

conforming                 410                  500*0.85 = 425

Downgraded               55                  500*0.10 = 50

Scrap                            35                  500 * 0.05 = 25

Test statistic

determine the test statistic

= [ (410 - 425)2 / 425 + (55 -50)2 / 50 + (35 - 25)2 / 25 ]

chi-square statistic. = 5.0294

The percentage of women with weights that are within the limits is:

60.93%

Can be calculated using the normal distribution formula. First, we need to find the z-scores for both the lower and upper limits:

z-score for lower limit = (132.4 - 168.7) / 48.8 = -0.74

z-score for upper limit = (217 - 168.7) / 48.8 = 0.99

Next, we can use a z-table to find the corresponding probabilities for these z-scores:

Probability for lower limit = 0.2296

Probability for upper limit = 0.8389

Finally, we can subtract the lower probability from the upper probability to find the percentage of women with weights that are within those limits:
Percentage = 0.8389 - 0.2296 = 0.6093

Therefore, approximately 60.93% of women have weights that are within the limits of 132.4 lb and 217 lb.

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To find the distance above the ground at which the tack is, we need to calculate the vertical displacement of the front wheel when the tack was picked up.

First, let's determine the circumference of the front wheel. The circumference of a circle is given by the formula C = πd, where C is the circumference and d is the diameter. Given that the diameter is 26 inches, we can calculate the circumference:

C = π × 26

C ≈ 81.64 inches

This means that for every complete revolution of the wheel, Devon travels a distance of approximately 81.64 inches.

Next, we need to determine how many complete revolutions the front wheel made as Devon rolled another 100 feet (1200 inches). Since the circumference of the wheel is 81.64 inches, we can divide 1200 inches by 81.64 inches to find the number of revolutions:

1200 / 81.64 ≈ 14.68 revolutions

Now, we know that the tack was picked up after one full revolution. Therefore, out of the 14.68 revolutions, 13 complete revolutions have occurred. The tack is located at the point where the 14th revolution starts.

Since each revolution covers a distance equal to the circumference of the wheel, the vertical displacement of the tack is the height of the wheel, which is the radius of the wheel. The radius is half the diameter, so in this case, it is 26 / 2 = 13 inches.

Therefore, the tack is located 13 inches above the ground.

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Answer:

Correct choice is B

Step-by-step explanation:

y = -1/2 X + 1/4

comparing with y = mx+c

m = -1/2 and m is slop

henve slope = -1/2

Answer:

Starting with the equation:

(x + 1)^2 = 13/4

We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.

Taking the square root of both sides, we get:

x + 1 = ±√(13/4)

Simplifying under the radical:

x + 1 = ±(√13)/2

Now we can solve for x by subtracting 1 from both sides:

x = -1 ± (√13)/2

Therefore, the solutions to the equation are:

x = -1 + (√13)/2 or x = -1 - (√13)/2

Step-by-step explanation:

Answer:

2.8 years

Step-by-step explanation:

continuous compounding formula:

A = Pe^rt

3000 = 2500e^.065t

ln(6/5) ÷ .065 ≈ 2.8 years

The graph can be used to determine the median, quartiles, and other statistical measures.

(a). Class width = (maximum value - minimum value)/ number of classes = (109 - 45)/6 = 9

(b).

Class Limits  Class Boundaries Midpoints  Frequencies  Relative Frequencies  Cumulative Frequencies

45 - 54  44.5 - 54.5  49.5  2  0.0741  2

55 - 64  54.5 - 64.5  59.5  7  0.2593  9

65 - 74  64.5 - 74.5  69.5  17  0.6207  26

75 - 84  74.5 - 84.5  79.5  20  0.7407  46

85 - 94  84.5 - 94.5  89.5  14  0.5185  60

95 - 104  94.5 - 104.5  99.5  7  0.2593  67

(c). Histogram

(d). Relative-Frequency Histogram

(e). The basic distribution shape is right-skewed.

(f). Ogive

The ogive graph is a cumulative frequency plot that shows the number of data values that lie at or below each given value on the x-axis. It is constructed by plotting the cumulative frequencies of each data value on the y-axis against the corresponding data values on the x-axis. The points are then connected using closed line segments to form the ogive graph. The graph can be used to determine the median, quartiles, and other statistical measures.

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In order for the relationship zyx ~ wvu to be correct, the following conditions must be true:

Corresponding angles are congruent: The angles formed by matching vertices should have the same measures in both triangles. This ensures that the corresponding angles are equivalent.

Corresponding sides are proportional: The lengths of the sides that connect the corresponding vertices of the triangles should have a consistent ratio. This implies that the corresponding sides are proportional to each other.

These conditions are based on the definition of similarity between two triangles. If both the corresponding angles are congruent and the corresponding sides are proportional, then the triangles zyx and wvu are considered similar (denoted by ~).

Therefore, in order for zyx ~ wvu to be correct, the congruence of corresponding angles and the proportionality of corresponding sides must hold true.

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A parabola written in vertex form is

The coordinates (h, k) represents the vertex.

Since the vertex of our problem is (-1, 9), our parabola equation will have the form

We know that the point (-5, 4) belongs to this parabola. If we evaluate this point on our equation we can determinate the coefficient a.

Then, our equation is

This is a transformation of the parent square root function, and it can be written as:

f(x) = √(-x + 4) - 2

It is ratter easy to identify the shape of the general square root function:

f(x) = √x

The only difference is that now it opens to the left, and it starts at the point (4, -2)

Then:

The sign of the x must be negative.

And with the known vertex we can write the equation:

f(x) = √(-x + 4) - 2

That is the graphed function.

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Answer:

y=-4x=5

Step-by-step explanation:

i did it on a test

Note that the table of budget is attached accordingly, and steps 1-4 have been completed. See the table.

4) Since the emergency fund for that month was $200, it means that they are in the short for $105. They can only affod it if they take from their savings.

5) they had a balance of $800 for the month. This is miscellaneous funds. They can make use of this for the trip to NASA. This way, they won't have to touch the savings or entertainment.

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Full Question:
See attached image.

Reflect

4. Analyze Relationships One month, the family must make an

emergency car repair for $305. Are they able to pay for it out of the

fixed emergency fund for that month? If not, how can they afford it?

5. The family wants to make a trip to Houston to visit the NASA Space

Center. What are some ways they can save without using all of the

allotted $160 for entertainment

Answer:

Time taken by two painters would be 39.21 and 45.21 hours ( 39.21 + 6 hours)...

Step-by-step explanation:

U 2 can help me by marking as brainliest........

Answer:

c

Step-by-step explanation: because

Answer:

y = -3/4x + 6.75

Step-by-step explanation:

Slope intercept form is y = mx + b, where m is the slope and b is the y intercept.

Plug in the given point and slope into the equation, then solve for b:

y = mx + b

3 = -3/4(5) + b

3 = -3.75 + b

6.75 = b

Then, plug in the slope and y intercept into the equation:

y = -3/4x + 6.75 is the equation of the line in slope intercept form

It will take 3.5 hours for the two cars to be 280 miles apart.

To determine the time it takes for the two cars to be 280 miles apart, we can use the concept of relative velocity.

Since the cars are traveling in opposite directions, their velocities can be added together to find their relative velocity:

Relative velocity = Velocity of car traveling east + Velocity of car traveling west

Relative velocity = 60 mph + 20 mph

Relative velocity = 80 mph

The relative velocity of the cars is 80 mph, which means that they are moving away from each other at a combined speed of 80 mph.

To find the time it takes for them to be 280 miles apart, we can use the formula:

Time = Distance / Speed

Plugging in the values, we have:

Time = 280 miles / 80 mph

Time = 3.5 hours

Therefore, it will take 3.5 hours for the two cars to be 280 miles apart.

During this time, the car traveling east would have covered a distance of 60 mph × 3.5 hours = 210 miles, while the car traveling west would have covered a distance of 20 mph × 3.5 hours = 70 miles.

The sum of these distances is indeed 280 miles, confirming the result.

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Answer:

14

Step-by-step explanation:

Answer:

$14.40

Step-by-step explanation:

18 x .2 = 3.6

18 - 3.6 = 14.40

Answer will be 27.

Given,

3√81

Now, to solve the expression the squares of whole numbers and square roots for some numbers must be known.

For example, squares of

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

6² = 36

7² = 49

8² = 64

9² = 81
10² = 100

Square roots,

√100 = 10

√81 = 9

√64 = 8

√49 = 7

√36 = 6

√25 = 5

√16 = 4

√9 = 3

√4 = 2

√1 = 1

Now ,

3√81 = 3× 9

= 27.

Thus the value is 27.

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The linear function that describes the table is f(x) = -2x + 3

The linear function of an equation can be found as follows:

y = mx + b

where

Therefore, using the table

b = 3

using (1, 1)

1 = m + 3

m = -2

Therefore, the function that represent the table is as follows:

f(x) = -2x + 3

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Answer:  f(x) = -2x + 3

Step-by-step explanation: