Here is a movement lesson that includes two gross motor activities for enhancing the learning of mathematics and two gross motor activities for enhancing language development are Hopscotch , Counting Hike , Follow the Leader ,Simon Says.
Mathematics Activities
1. Hopscotch: Create a hopscotch board on the ground with numbers ranging from 1 to 10. Invite children to hop through the squares as they recite the numbers in order. They can also be asked to skip certain numbers, add numbers together, or subtract numbers in order to work on addition and subtraction concepts.
2. Counting Hike: Take a walk with the children while counting everything in the surrounding environment, such as trees, cars, and rocks. This activity can help children learn to count forward and backward, as well as work on one-to-one correspondence.
Language Activities
1. Follow the Leader: Children can take turns being the leader and performing various actions, such as hopping, skipping, crawling, or clapping, while the other children follow and repeat the leader's words. This activity can help children learn new vocabulary words, practice listening skills, and develop their spatial awareness.
2. Simon Says: Play a game of Simon Says, but with a language twist. Instead of only giving physical commands, you can also give language commands, such as "Simon says say your name backward" or "Simon says spell the word cat backward." This activity can help children work on language skills, such as pronunciation, spelling, and grammar.
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What type of atomic radiation will most deeply penetrate matter?
Multiple Choice
Beta radiation
Gamma radiation
Alpha radiation
A right triangle has a leg that measures 17 measures 24 ft. What would the missing length be
The lenght of the missing side is 29.41 ft.
To calculate the missing length of the triangle, we use pythagoras theorem.
What is pythagoras theorem?
Pythagoras theorem states that in a right angle triangle, the square the hypotenus is equal to the sum of the square of the two other sides.
These can be expressed mathematically as
a² = b²+c²...............Equation 1From the question,
b = 17 ftc = 24 ftSubstitute these values into equation 1
a² = 17²+24²a² = 289+576a² = 865a = √865a = 29.41 ft.Hence, the lenght of the missing side is 29.41 ft.
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find the instantaneous velocity at t=5
The instantaneous velocity of the object is 36 m/s
The given displacement equation of motion;
\(d(t) = 3t(t+2 )\)
To find:
the instantaneous velocity after 5 s;
The instantaneous velocity is the change in displacement per change in time of motion at the given time.
\(v = \frac{d.d(t)}{dt} = 6t + 6\)
at t = 5 seconds, v = 6(5) + 6 = 36 m/s
Thus, the instantaneous velocity of the object is 36 m/s
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The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e-10 C what is the strength of the other charge ?
Answer:
\( \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}\)
Explanation:
Given:
Force between pair of charges= 900 newtons
The distance between the charges = 0.01 meters
Strength of Charge first q1 = 2e-10 Coulomb
To find:
Strength of Charge second q2 = ____ Coulomb?
Solution:
We know that,
Force between two charges separate by distance r is given by the equation,
\(|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb\)
\( \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}\)
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A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determine its resultant displacement vector by use of the diagram.
Answer:
Explanation is given
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5) The average speed of a sailing ship in the 1700's was about 15m/s. It would take a letter
about 3 months to travel from England to the American colonies. Based on this information,
what distance would the letter have traveled to reach America from England?
Answer:time in seconds spent for traveling=3×30×24×60×60
. = 7776000 seconds
distance= velocity× time.
. =15×7776000
. =116640000
. =116640km
Explanation:
1. It is important to make your own decisions. At the same time, it is good to ask for help. Identify a
situation where you absolutely need to be thinking for yourself and one in which turning to others
is best when it comes to making decisions about your health.
Answer:
Explanation:
Decision making is the process of making choices and it is important for a person to make their own decisions in life as it makes them accountable for the choices they made.
What is decision making?
Decision making is the process of making your own choices by identifying a decision, gathering the information, and assessing alternative resolutions for the decision.
Each person has the right to make their own decisions and have choices about how they live their life in their own way. Each person has different ideas about what is important and what makes them feel best in life. Making own choices about things in life is very important because it gives the life meaning.
Being responsible in making own decisions means being accountable, taking charge of the course of the actions and the consequences of choices, however it is also important to turn to others in cases of making decisions about health as this helps in making the best decision by understanding things from other perspectives.
Find the gravitational field on the surface of an alien planet that has an estimated mass of 8.5 x 10^26 kg and radius of 3.5 x 10^4 km. Show all work.
Answer:
Below
Explanation:
Fg = G m1 m2 / r^2 Gravitational constant = 6.6743 x10^-11 m^3 /(kg s^2)
PLug in the given numbers:
Fg = 6.6743 x 10^-11 (1 kg)(8.5x10^26 kg) / (3.5 x10^7 m)^2
= 46.3 m/s^2
Note on basic formula
Answer:
If this is Pre-Algebra or Algebra.
Arithmetic mean (average) = Sum of values/Number of values.
Explanation:
28g of copper pellets are removed from a 300∘C oven and immediately dropped into 90 mL of water at 25∘C in an insulated cup.
The final temperature of the water and copper pellets is 43.8°C.
We can use the equation:
\(mc\Delta T = mwCw\Delta T\)
Substituting the values given in the problem:
m c = 28 g
m w = 90 mL = 90 g
c = 0.385 J/g°C
Cw = 4.18 J/g°C
ΔT = T f - 25°C
where T f is the final temperature of the water and copper pellets.
Simplifying the equation:
28 g x 0.385 J/g°C x (T f - 300°C) = 90 g x 4.18 J/g°C x (T f - 25°C)
Solving for T f:
T f = (90 g x 4.18 J/g°C x 25°C + 28 g x 0.385 J/g°C x 300°C) / (90 g x 4.18 J/g°C + 28 g x 0.385 J/g°C)
T f = 43.8°C
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--The complete Question is, What are the final temperature of the water and the copper pellets after thermal equilibrium is reached, assuming no heat is lost to the surroundings? --
You are falling down a chasm at 9.80 m/s2. It's a deep chasm, and you've got a calculator with you. If you are currently hurtling toward your doom at 23.016 m/s, how many seconds will it take you to reach terminal ivelocity of 195 km/h? Your answer must have the appropriate number of significant figures.
3.2 seconds
Explanation
Step 1
convert all measures in m.s.k system
so
\(\begin{gathered} \text{aceleration}=a=9.8\text{ }\frac{m}{s^2} \\ \text{Inital sp}eed=v_0=23.016\text{ }\frac{m}{s} \\ \text{time}=\text{ t=unknown} \\ \text{ final sp}eed=v_f=195\text{ }\frac{\operatorname{km}}{h}\rightarrow it\text{ n}eeds\text{ to be converted, so} \\ 195\text{ }\frac{\operatorname{km}}{h}(\frac{1000\text{ m}}{1\text{ km}})(\frac{1\text{ hour}}{3600\text{ s}})=54.16\text{ }\frac{m}{s} \\ so,\text{ } \\ \text{ final sp}eed=v_f=54.16\text{ }\frac{m}{s} \end{gathered}\)Step 2
now, to figure out this we need to use the free fall formula:
\(v_f=v_o+at\)hence, replace
\(\begin{gathered} v_f=v_o+at \\ 54.16\frac{m}{s}=23.016\frac{m}{s}+9.8\frac{m}{s^2}\cdot t \\ 54.16=23.016+9.8t \end{gathered}\)Now, let's solve for t
\(\begin{gathered} 54.16=23.016+9.8t \\ \text{subtract 23.016 in both sides} \\ 54.16-23.016=23.016+9.8t-23.016 \\ 31.15=9.8t \\ \text{divide both sides by 9.8} \\ \frac{31.15}{9.8}=\frac{9.8t}{9.8} \\ 3.178=t \\ \text{rounded} \\ t=3.2\text{ seconds} \end{gathered}\)therefore, the answer is
3.2 seconds
I hope this helps you
An investigation of an automobile crash suggests that vehicle A was moving at 52
mph toward the south and vehicle B was moving at an unknown speed toward the
north, when the two cars collided, sticking together after the collision.
Vehicle A weighs 1350 lbs., and vehicle B weighs 1893 lbs. If the cars did not move
significantly after their collision, find the initial speed of vehicle B in mph.
mph (miles per hour)
Answer:
Here the total momentum of the vehicles is conserved during even after the collision. The two cars are not moving after, hence their final momentum is zero which means, the have equal and opposite momentum. Hence, the initial speed of B were, 37 mph.
What is momentum ?Momentum of an object is the product of the mass and velocity of the object. It is a vector quantity and having both direction and magnitude.
Given mass of A = 1350 lbs
v = 52 mph
then momentum = 1350 lbs × 52 mph = 70200 lbs mph
Mass of B = 1893 lbs
let its velocity be v .
then momentum = 1893 v.
According to conservation of momentum:
m1u1 + m1 u2 = (m1+ m2) v
The cars are not moving after the collision. Hence, the final speed is zero.
then, 70200 lbs mph + 1893 v = 0
70200 lbs mph = - 1893 v
v = 70200 lbs mph /1893 lbs
= 37 mph.
Therefore, the velocity of the car B is 37 miles per hour.
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Simple physics question, check the document. Should take about 3-5 minutes.
Answer:
The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N
Explanation:
Forces on block 4.3 kg are:
63N to the right and R21 (contact force from the 6.3 kg block) to the left
Net force on 4.3 kg block is: 63 N - R21
Forces on the 6.3 kg block are:
R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.
So net force on the 6.3 kg block is: R12 - 11 N
According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").
Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:
a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2
solve for R by cross multiplication
6.3 (63 - R) = 4.3 (R - 11)
396.9 - 6.3 R = 4.3 R - 47.3
369.9 + 47.3 = 10.6 R
444.2 = 10.6 R
R = 444.2 / 10.6
R = 41.90 N
A heat engine is used to convert heat into which of the following?
Answer:
work
Explanation:
experiment to show that light travels in a straight line
Electrons are accelerated through a voltage difference of 295 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons? 2.95×105 eV You are correct. Your receipt no. is 161-399 Help: Receipt Previous Tries What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)
To calculate the speed of the electrons in terms of the speed of light, we can use the relativistic kinetic energy equation:
KE = (γ - 1)mc^2
where KE is the kinetic energy of the electron, m is its rest mass, c is the speed of light, and γ is the Lorentz factor:
γ = 1/√(1 - v^2/c^2)
where v is the velocity of the electron.
To find v, we can use the relationship between kinetic energy and voltage:
KE = qV
where q is the charge of the electron and V is the voltage difference.
Substituting qV for KE, we get:
qV = (γ - 1)mc^2
Rearranging, we get:
γ = 1 + qV/mc^2
Substituting q = -1.6 x 10^-19 C (the charge of the electron), V = 295 kV, and m = 9.11 x 10^-31 kg (the rest mass of the electron), we get:
γ = 1 + (-1.6 x 10^-19 C)(295 x 10^3 V)/(9.11 x 10^-31 kg)(3 x 10^8 m/s)^2
γ = 1.344
Finally, we can calculate the speed of the electrons in terms of the speed of light:
γ = 1/√(1 - v^2/c^2)
1.344 = 1/√(1 - v^2/(3 x 10^8 m/s)^2)
Squaring both sides and solving for v, we get:
v = 0.9964c
Therefore, the speed of the electrons is 0.9964 times the speed of light
Give two examples of situations or application where electronic circuits are used
In 2012, NASA sent the 900kg Curiosity robot to Mars to study the planet. a) Recall the relationship between the weight P and the mass m. Specify the units. b) What is the weight of Curiosty on Mars? c) Compare the weight of Curiosity on Earth and on Mars. Why is it more important on Earth
(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
(b)The weight of Curiosity on Earth is approximately 8820 Newtons.
a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.
c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.
The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.
It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.
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Please tell me which on it is!
Answer
.0003
Explanation:
Does the moon have water?
Explanation:
after rereading: Yes, there is a term for water on the moon and it's called lunar water, pretty straightforward. you can check out moon.nasa.gov, or literally look this up in the magical (g-engine) and it'll gove you a few articles.
______________________
oh my, sorry, i thought the question asked if the moon moved water, in which case: I wouldn't say that the moon actually MOVES the water, but yes, its gravitational force is strong enough to affect tides on Earth. (i could've sworn that's what I saw but whatever, sorry!)
A physics student sits in a chair. The chair pushes up on the student's body. Identify the other force of the interaction force pair.
Answer:
gravity pulls down on student the chair pushes up on the student's body with the same force gravity is pulling down on the student
True or False: A rough rock will absorb more radiant energy than a smooth rock
a roller coaster start at a height of 40Meters and reached a height of 20meter. does mechanical energy change
Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
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2. Gerard is riding his bicycle directly east. His maximum
instantaneous velocity was 8 meters per second and his
minimum instantaneous velocity was 0 meters per second. He
covered 7.20 kilometers in 20.0 minutes. What is his average
velocity for the ride?
Gerard's average velocity for the ride is 6 meters per second.
To find Gerard's average velocity for the ride, we can use the formula:
Average velocity = Total displacement / Total time
First, we need to convert the distance traveled from kilometers to meters:
7.20 kilometers * 1000 = 7200 meters
Next, we convert the time from minutes to seconds:
20.0 minutes * 60 = 1200 seconds
Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:
Total displacement = 7200 meters
Finally, we substitute the values into the average velocity formula:
Average velocity = 7200 meters / 1200 seconds
Average velocity = 6 meters per second
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A girl runs up the down escalator in the mall. If the escalator is moving with a velocity of 27 m/min and the girl is running with a velocity of 28 m/min, how far up the escalator can she go in 2 minutes?
The girl can go up the escalator by 2 meters in 2 minutes if a girl runs up the down escalator in the mall and escalator is moving with a velocity of 27 m/min and the girl is running with a velocity of 28 m/min,
When the girl runs up the down escalator, her effective velocity is the difference between her velocity and the velocity of the escalator. In this case, the escalator is moving down with a velocity of 27 m/min, while the girl is running up with a velocity of 28 m/min. So, her effective velocity is:
Effective velocity = Girl's velocity - Escalator's velocity
= 28 - 27
= 1 m/min
Therefore, the girl is moving up the escalator at a speed of 1 m/min.
To calculate how far up the escalator she can go in 2 minutes, we need to use the formula:
Distance = Speed x Time
In this case, the speed is the effective velocity of the girl, which is 1 m/min, and the time is 2 minutes. So, the distance she can go up the escalator is:
Distance = Speed x Time
= 1 x 2
= 2 meters
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Is it possible that the physical velocity is constant but the magnitude of the velocity is variable?give an example
Answer:
yes it is possible
Explanation:
if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.
eg: a body in uniform circular motion has constant speed but its velocity changes at every point during the course of motion. Whenever, the direction changes, velcoity changes.
explain how a paradox work∞
Answer:
A paradox is a statement, proposition, or situation that seems illogical, absurd or self-contradictory, but which, upon further scrutiny, may be logical or true — or at least contain an element of truth. Paradoxes often express ironies and incongruities and attempt to reconcile seemingly opposing ideas.
Explanation:
hope this help :)
Which term is applied to an object through which light passes?
A. Absorbent
B. Opaque
C. Reflective
D. Transparent
Answer:
D
Explanation:
transparent_objects that allows light to pass through and can you see through them
A ball of mass 1.2 kg is suspended by two wires from a horizontal arm, which is attached to a vertical shaft, as shown in the figure. The rate of rotation of the shaft and ball is such that the tensions in the two wires are equal. What is the radial acceleration of the ball?
The radial acceleration of the ball of mass 1.2 kg that is suspended by two wires from a horizontal arm, which is attached to a vertical shaft is 4.9 m / s²
Since the wires form a right angled triangle with the horizontal arm,
tan θ = Opposite side / Adjacent side
tan θ = 0.6 / 0.8
θ = \(tan^{-1}\) ( 0.75 )
θ = 36.9°
m = 1.2 kg
W = m g
W = 1.2 * 9.8
W = 11.76 N
T1 = T2 = T
∑ \(F_{y}\) = 0
T1 + T2 sin θ - W = 0
T + T sin 36.9° - 11.76 = 0
T + 0.6 T = 11.76
T = 11.76 / 1.6
T = 7.35 N
\(F_{c}\) = m v² / r
\(F_{c}\) = Centripetal force
∑ \(F_{x}\) = m v² / r
T cos 36.9° = m * \(a_{r}\)
\(a_{r}\) = 7.35 * 0.8 / 1.2
\(a_{r}\) = 4.9 m / s²
Therefore, the radial acceleration of the ball = 4.9 m / s²
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An airplane flying upward at 39.6m/s and an angle of 30 degree relative to the horizontal releases a ball when it is 287m above the ground. Calculate the time it takes the ball to hit the ground? Calculate the maximum height of the ball? Calculate the horizontal distance the ball travels from the release point to the ground? Neglect any effects due to air resistance.
Answer:
Assuming the speed of the plane is 39.6 m/s
vy = 39.6 * sin 30 = 19.8 vertical speed
vx = 39.6 * cos 30 = 34.3 m/s
S = vy t - 1/2 a t^2 to calclulate vertical height
-287 = 19.8 t - 4.9 t^2
4.9 t^2 -19.8 t - 287 = 0
I get t = 9.93 for solving the quadratic for time for ball to hit ground
Horizontal distance = 34.3 m/s * 9.93 s = 341 m
With a vertical speed of 19.9 m/s it takes 19.8 / 9.8 = 2.02 s to reach max height
You can again solve a quadratic or use 19.8 / 2 * 2.02 for time to reach vertical height H = 287 + 20 = 307 m
As a check 307 = 1/2 g t^2 = 4.9 * (9/93 - 2/02)^2 = 307 m max height
After you know how long the ball is in the air there are several ways to calculate the other values.