Answer: el pepe
Explanation:
Answer:
8125 N.
Explanation:
F = M A
M is mass
A is acceleration
F = 65 X 25
F = 8125 N.
Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?
We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.
The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.
The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.
The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.
The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.
The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.
The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.
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What is the answer can you explain it to me
Answer:
C) 300 Ohm.
Explanation:
In a series circuit, total resistance is just adding all the resistance together. So R (total) = 75 +75 +75+ 75 = 300 ohms
Parallel circuit are different because you add the inverses of resistance and you flip the final answer.
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Thomson effect is the combined effect of Seebeck effect
and Peltier effect. Justify your answer.plz help me
Answer:
its c
Explanation:
We have 3 gears meshed with the following teeth. A – 20; B – 50; C – 30. Another set of gears have the following teeth. X – 20; Y – 25; Z – 30. Assuming gears A and X are running at the same rpm. Which statement is correct?
gear C and Z will run at the same RPM
RPM is not a unit, according to the International System of Units (SI). The word "revolution" is a semantic annotation rather than a unit, which explains this. RPM formula sign must be f for (rotational) frequency and or for angular velocity due to the measured physical quantity. s−1 or Hz is the basic SI-derived unit that corresponds. The radians per the second unit are used to express angular speed.
As a result, a disc rotating at 60 RPM is considered to be rotating at either 2 rad/s or 1 Hz, where the former refers to angular velocity and the latter to the rate of revolutions per second.
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NASA is designing a Mars-lander that will enter the Martian atmosphere at high speed. To land safely it must slow to a constant vertical speed of 20 m/s after deploying a parachute with an area of 200 m^2. The drag coefficient of the parachute is 1.855. The acceleration due to gravity on Mars is 3.71 m/s2, and the density of the atmosphere near the surface is 0.01 kg/m^3.
a. Calculate the maximum mass of the Mars lander to ensure it can land safely?
b. The mission designers consider a larger lander with a mass of 480 kg. Show that the parachute required would be larger than 400 m².
c. To test the lander before launching it to Mars, it is tested on Earth where g = 9.8 m/s^2 and the atmospheric density is 1.0 kg m-3. How big should the parachute be for the terminal speed to be 20 m/s, if the mass of the lander is 480 kg?
Answer:
a) maximum mass of the Mars lander to ensure it can land safely is 200 kg
b) area of the parachute required is 480 m² which is larger than 400 m²
c) area of the parachute should be 12.68 m²
Explanation:
Given the data in the question;
V = 20 m/s
A = 200 m²
drag co-efficient CD = 1.855
g = 3.71 m/s²
density of the atmospheric pressure β = 0.01 kg/m³
a. Calculate the maximum mass of the Mars lander to ensure it can land safely?
Drag force FD = 1/2 × CD × β × A × V²
we substitute
FD = 1/2 × 1.855 × 0.01 kg/m × 200 m² × ( 20 m/s )²
FD = 742 N
we know that;
FD = Fg
Fg = gravity force
Fg = mg
so
FD = mg
m = FD/g
we substitute
m = 742 N / 3.71 m/s²
m = 200 kg
Therefore, the maximum mass of the Mars lander to ensure it can land safely is 200 kg
b. The mission designers consider a larger lander with a mass of 480 kg. Show that the parachute required would be larger than 400 m²;
Given that;
M = 480 kg
Show that the parachute required would be larger than 400 m²
we know that;
FD = Fg = Mg = 480 kg × 3.71 m/s²
FD = 1780.8 N
Now, FD = 1/2 × CD × β × A × V², we solve for A
A = FD / 0.5 × CD × β × V²
we substitute
A = 1780.8 / 0.5 × 1.855 × 0.1 × (20)²
A = 1780.8 / 3.71
A = 480 m²
Therefore, area of the parachute required 480 m² which is larger than 400 m²
c. To test the lander before launching it to Mars, it is tested on Earth where g = 9.8 m/s^2 and the atmospheric density is 1.0 kg m-3. How big should the parachute be for the terminal speed to be 20 m/s, if the mass of the lander is 480 kg?
Given that;
g = 9.8 m/s²,
β" = 1 kg/m³
v" = 20 m/s
M" = 480 kg
we know that;
FD = Fg = M"g
FD = 480 kg × 9.8 m/s² = 4704 N
from the expression; FD = 1/2 × CD × β × A × V²
A = FD / 0.5 × CD × β" × V"²
we substitute
A = 4704 / 0.5 × 1.855 × 1 × (20)²
A = 4704 / 371
A = 12.68 m²
Therefore area of the parachute should be 12.68 m²
A 600 kg rocket sled can be accelerated at a constant rate from rest to 1400 km/h in 2.1 s. What is the magnitude of the required net force
Answer:
7.2 × 10^5 N
Explanation:
The first step is to convert 1400 km/hr to m/s
= 1,400×1000/3600
= 1,400,000/3600
= 388.88 m/s
The acceleration can be calculated as follows
a= v-u/t
= 388.88/2.1
= 185.18
Therefore the required net force can be calculated as follow
= 388.88 × 185.18
= 7.2 × 10^5 N
A student pushes a 6.0-kg box to the right with a
constant force FSB. The box moves at a constant velocity. The box experiences a
friction force f from the floor.
a. What type of friction does the box experience? Explain your reasoning.
b. Identify the four forces acting on the box.
onsider laminar flow of a fluid through a square channel with smooth surfaces. now the average velocity of the fluid is doubled. determine the change in the head loss of the fluid. assume the flow regime remains unchanged
The head loss doubles when the average velocity is doubled.
The velocity formula: why?
The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).
How do velocity and speed differ?Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.
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The blade of a windshield wiper moves through an angle of 90.08 in 0.40 s. The tip of the blade moves on the arc of a circle that has a radius of 0.45 m. What is the magnitude of the centripetal acceleration of the tip of the blade
Answer:
The centripetal acceleration is 6.95 m/s²
Explanation:
Given;
angular displacement of the blade, θ = 90.08⁰
duration of motion of the blade, t = 0.4 s
radius of the circle moved by the blade, r = 0.45 m
The angular speed of the blade in radian is calculated as;
\(\omega = \frac{\theta}{t} \times \frac{\pi \ radian}{180^0} \\\\\omega = \frac{90.08 ^0}{0.4 \ s} \times \frac{\pi \ radian}{180^0} \\\\\omega = 3.93 \ rad/s\)
The centripetal acceleration is calculated as;
a = ω²r
a = (3.93)² x 0.45
a = 6.95 m/s²
A ball of mass 3 kg is released at the top of a track, as shown in the image below. The top of the ramp is 1 metre higher than
the lower, horizontal section of the track. This horizontal section is 5 metres long.
Assumptions:
• There is no loss of energy due to friction or air resistance.
• Gravitational acceleration is 9.8 m/s?
3 kg
1 m
5 m
(a) [1 MARK] What type of energy does the ball have when it is being held at the top of the track?
potential energy
(b) How much work must be done to hold the ball at the top of the track?
• [0.5 MARK] Write the amount of work done (number only) here: 0
[0.5 MARKI Write the unit for the work done here (symbol, not words):
.
(C) (1 MARK] What is the velocity (in m/s) of the ball when it is at the start of the horizontal section of the track? (Write the
number only to two decimal places. Do not include the unit.)
(d) [1 MARK] What is the velocity (in m/s) of the ball when it is at the end of the horizontal section of the track? (Write the
number only to two decimal places. Do not include the unit.)
Answer:
potential energy
Explanation:
A plane is landing at an airport. The plane has a massive amount of kinetic energy due to it's motion. When the plane lands, it activates its brakes, causing it to slow down and eventually stop. The kinetic energy that the plane had is now gone. In keeping with the Law of Conservation of Energy, which of the following is the most likely explanation of what happened to that energy?
A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes
B. The kinetic energy of the plane gets pushed into the air in front of it due to drag forces, causing the air to move, thus transferring the kinetic energy from the plane to the air
C. The brakes create friction, which transformed the kinetic energy to heat energy that was dissipated to the surroundings
D. The kinetic energy is being converted into sound energy by the loud engines of the plane
Answer:
A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes
Explanation:
Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.
The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.
As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.
The potential energy is the energy due to the position of a body.
What is the penetration depth β−-radiations in Aluminium in cm? Can you determine the
depth of this radiation in Lead, what is it? (ρlead = 11.4g/cm^3)
So the corresponding answer for beta particle penetration in aluminum is:
\(2.37 cm\)
Firstly, it is known that aluminum stops beta particles, which is why penetration occurs. Thus, to calculate the depth of beta radiation in aluminum, it is given by the formula:
\(P=\frac{m}{K}\)
Where P is the given coefficient, K is the distance in cm and M is the mass of aluminum in grams.
\(k=\frac{27}{11.4} \\k= 2.37 cm\)
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100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water. The water is stirred until the temperature of the water has fallen to 0 °C. 18 g of ice remains unmelted. The specific heat capacity of water is 4.2 J / g °C. Which value does this experiment give for the specific latent heat of fusion of ice?
The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.
To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:
Q1 = m1 * c * ΔT1
Where:
m1 = mass of water = 100 g
c = specific heat capacity of water = 4.2 J/g °C
ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C
Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J
Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:
Q2 = m2 * Lf
Where:
m2 = mass of ice = 18 g
Lf = specific latent heat of fusion of ice (to be determined)
Q2 = 18 g * Lf
Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):
-10,500 J = 18 g * Lf
Solving for Lf:
Lf = -10,500 J / 18 g = -583.33 J/g
The negative sign indicates that energy is being released during the process of freezing.
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How does our body control blood pressure?
Answer:
Short-term regulation of blood pressure is controlled by the autonomic nervous system (ANS). Changes in blood pressure are detected by baroreceptors. These are located in the arch of the aorta and the carotid sinus. Increased arterial pressure stretches the wall of the blood vessel, triggering the baroreceptors.
hope this helps and can i have brainliest please.
*★,°*:.☆( ̄▽ ̄)/$:*.°★* 。
How does methodology in natural science influence knowledge produced
answer pls urgent pls
Answer:
Brittleness
Explanation:
Lustrous means shiny
sonorous means capable of producing a deep or ringing sound
and iron isn't brittle or weak
Answer:
\(\huge\boxed{\sf brittleness}\)
Explanation:
Iron is a metal which have luster (shine) so it is lustrous (shiny).
Iron is sonorous. When it is hit with a hard object, it produces ringing sounds.
Iron is not brittle. It cannot be easily broken. So, Iron does not show brittleness (It cannot be easily broken)
\(\rule[225]{225}{2}\)
Hope this helped!
~AnonymousHelper1807A skydiver opens his parachute, and shortly thereafter, he is moving at constant velocity. (a) What forces are acting on him? (b) Which force is bigger?
a)
We have the next forces
Fd that is the air drag force that is acting upward
Fd gravitation force that is acting downward
in other words
his weight is the force that acts downward and the force of the air resistance with the parachute act upward
b)
In this case, because he is falling at a constant velocity it means
\(Fg=Fd\)So the net force on the skydiver is 0
therefore both forces are equal amount in other words the forces are equal in magnitude
A helicopter (mass = 5000 kg) lifts 1475 kg of stuff (two people and packages). Let’s say initially the helicopter is hovering (v = 0 m/s). What thrust (force) is necessary for the helicopter to hover?
While it's carrying the passengers and packages, its total mass is 5000 kg + 1475 kg = 6475 kg, so that its weight is
(6475 kg) g = 63,455 N
In order to hover, the helicopter's thrust should match this weight.
4.Label a compression region and a rarefaction region on the diagram below:
For a longitudinal wave, the compression region, is the one represented by the densely packed particles with high pressure and the region with loosely packed particles is called rarefaction. Hence, the first part is C he dense region and the second one with some space between the dots is labeled as R.
What are longitudinal waves ?Longitudinal waves are a type of mechanical waves passing through a medium. Unlike electromagnetic waves, they cannot be passed through vacuum.
In a longitudinal wave, the oscillation of particles is along the direction of wave propagation. The wave is composed of high pressure regions and low pressure regions called compressions and rarefactions respectively.
The regions where, particles are densely packed and shows the thick dote are labelled as compressions and the regions where, some space between particles are labeled as rarefactions.
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How has Physics improved
or affected our society?
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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which one of the following is not a typical consequence associated with open pit mines. apes
One of the things that are NOT a typical consequence that is associated with open pit mines is the release of high concentrations of ozone into the local environment, causing long-term respiratory harm to individuals and the environment.
The open-pit mine is a surface mining technique used to extract rocks or minerals from the earth using an open-air pit. This technique is used when ore or rock deposits are found near the surface, which makes digging a tunnel unnecessary.
The main consequence of open-pit mine that concerns most people is that it generates a large amount of dust that contains heavy metals to the environment, as well as creating deposits of toxic waste ponds. Ozone is not considered a heavy metal.
Attached below is an image of the Sunrise Dam Gold Mine open pit mine in Australia.
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in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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what is the only force that can act on an object in free fall? gravity friction air resistance speed; increasing which factor will cause the gravitational force between two objects to decrease?; what determines the strength of the gravitational force of an object in space; what are the units of mass and weight; which factors affect the gravitational force between two objects select all that apply; if siobhan hits a 0.25 kg volleyball with 0.5 n of force, what is the acceleration of the ball? m/s2; what is the weight, on earth, of a book with a mass of 1.5 kg? 1.5 n 6.5 n 11.3 n 14.7 n
In Newtonian physics, free fall refers to any motion of a body in which gravity is the only force acting on it.
What are the forces at work on a falling object?
In addition, gravity is pulling something down as it falls. The force of gravity is an unbalanced force at the beginning of the fall. As a result, the object accelerates or picks up speed. It runs into aerodynamic drag or air resistance as it accelerates.
What is the force responsible for an object falling to the ground?
All objects on Earth experience weight, or a gravitational pull that is proportional to their mass and is imposed by the planet's mass. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A helicopter flies 160 m horizontally and then moves downward to land 50 m below. What is the helicopter's resultant displacement?
Answer:
Displacement = 167.63 m
Explanation:
Distance refers to the total ground covered by an object while in motion while displacement refers to how far an object is from it's original position.
Now, we are told that the helicopter flies 160m horizontally and then flies 50m downwards.
This means that it's displacement will be the distance from its final position to the initial position.
This can be represented with a triangle attached.
From the triangle, the displacement d will be gotten from pythagoras theorem.
Thus;
d² = 160² + 50²
d² = 25600 + 2500
d² = 28100
d = √28100
d ≈ 167.63 m
The frequency of a wave is 200.0 Hz . Its velocity is 3.00 * 10 ^ 8 * m / s . What is the period of the wave?
In order to calculate the period of the wave, we can use the formula below:
\(T=\frac{1}{f}\)So, to calculate the period, let's use the given frequency of 200 Hz:
\(T=\frac{1}{200}=0.005=5\cdot10^{-3}\text{ s}\)Therefore the correct option is A.
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 6 cm and 4 cm.
52 cm4
72 cm4
32 cm4
24 cm4
2 cm4
Answer:
Minimum Area of rectangle = 24 centimeter²
Explanation:
Given:
Length of rectangle = 6 centimeter
Width of rectangle = 4 centimeter
Find:
Minimum Area of rectangle
Computation:
Minimum Area of rectangle = Length of rectangle x Width of rectangle
Minimum Area of rectangle = 6 x 4
Minimum Area of rectangle = 24 centimeter²
9
17. Mary is 14 years old, weighs 125 pounds and is 5ft 6in tall. What is her
Basal Metabolic Rate? (Use the formula found in the "Nutrition &
Metabolism" worksheet. Round to the nearest whole calorie)
1326
O 1436
O 1568
O 2436
The basal metabolic rate for the girl of 14 years weighing 125 pounds and height of 5ft.6 inch is 1573 Kcal/day.
What is basal metabolic rate ?The basal metabolic rate of a person is the number of calories that is burned inside the body through basic life -sustaining metabolic functions. It can be calculated using the below equations for men and women.
BMR for men = 88.362 + (13.397 x weight in kg) + (4.799 x height in cm) – (5.677 x age in years)
BMR for women = 447.593 + (9.247 x weight in kg) + (3.098 x height in cm) – (4.330 x age in years).
Given, the age = 14 years
weight = 125 pounds = 56.7 kg
1 feet = 30.48 cm
1 inch = 2.54 cm.
then 5ft.6inch = 167.64 cm.
Now BMR = 447.593 + (9.247 x 56.7) + (3.098 x 167.64 ) – (4.330 x 14)
= 1573 Kcal/day.
Therefore, the basal metabolic rate of the girl is 1573 Kcal/day.
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Please help it’s due in 40 minutes
Analyze the models to explain how you think an electromagnet produces a magnetic field that could attract magnetic metals. Be sure to explicitly cite features of the two models and consistencies between them to support your response
25. A 0.75 kg spike is hammered into a railroad tie.
The initial speed of the spike is equal to 3.0 m/s.
a. If the tie and spike together absorb 85 percent of the spike's initial kinetic energy as internal energy, calculate the increase in internal energy of the tie and spike.
b. What happens to the remaining energy?
If the tie and spike together absorb 85 percent of the spike's initial kinetic energy as internal energy, internal energy of them be 2.869 Joule.
What is energy?The capacity to do work is energy. Energy can only be changed from one form to another; it cannot be created or destroyed. Energy is measured in Joules, the same unit used to measure work. There are several sorts of energy since it is present in many different things.
Given parameters:
Mass of the spike = 0.75 kg
Speed of the spike = 3.0 m/s.
Kinetic energy of the spike = 1/2 × mass × speed²
= 1/2 × 0.75 × 3.0 × 3.0 joule
= 3.375 joule.
If the tie and spike together absorb 85 percent of the spike's initial kinetic energy as internal energy, If the internal energy of them, be = 3.375 × 85% joule
= 2.869 Joule.
The remaining energy will be transformed into sound energy and kinetic energy.
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