Answers
Answer: Because anyone the ended up staying inside that build for too long, they started to show signs of menta deterioration in other words acting looney.
Explanation:
Related Questions
I NEED HELP PLEASE EXPLAIN ANSWER
Answers
Answer:
ask a pro
Explanation:
hope this was helpful
Write in Scientific Notation 1,060,000,000
Answers
How does the air temperature at the bottom of a mountain compare with the air temperature at the top of the mountain?
A. The air is colder at the bottom.
B. The air is warmer at the top.
C. The air temperature at the top is lower.
D. The air temperature is the same.
Answers
Explanation: C) the air temp. at the top is lower
3A 2B --> 5C If compound A has a molar mass of 159.7 g/mol and compound C has a molar mass of 57.6 g/mole, how many grams of compound C will be produced from 18.24 grams of compound A and excess compound B
Answers
Answer:
10.96 grams of compound C will be produced from 18.24 grams of compound A and excess compound B.
Explanation:
3A + 2B ⇒ 5C
By stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) the following amounts of reagent and products participate in the reaction:
A: 3 molesB: 2 molesC: 5 molesThe excess reagent will be that which is not completely depleted during the reaction.
The amount of product obtained from the reaction will always depend on the amount of limiting reagent in the reaction. Then, being B the excess reagent and therefore A the limiting reagent and knowing that compound A has a molar mass of 159.7 g/mole and compound C has a molar mass of 57.6 g/mole, by stoichiometry the following mass amounts of A and C participate in the reaction:
A: 3 moles* 159.7 g/mole= 479.1 gC: 5 moles* 57.6 g/mole= 288 gThen it is possible to apply the following rule of three: if by stoichiometry of the reaction 479.1 grams of A produce 288 grams of C, 18.24 grams of A, how much mass of C does it produce?
\(mass of C=\frac{18.24 grams of A*288 grams of C}{479.1 grams of A}\)
mass of C= 10.96 grams
10.96 grams of compound C will be produced from 18.24 grams of compound A and excess compound B.
When steam comes out of the tea kettle, what TWO types of energy are visible?
mechanical
chemical
electrical
thermal
light
Answers
thermal steam comes out of the tea kettle, what TWO types of energy are visible
What kind of energy does steam emit as it heats up?Latent heat has potential energy and sensible heat has kinetic energy in the case of steam. As water is heated, an invisible gas called steam is produced. It is liquid water that has been converted to gas. Saturated steam is steam that has come into direct touch with the water it is being produced from.
The majority of the energy contained in the hot, gaseous steam is released as it expands and cools as it passes by the rotating blades of the turbine. The blades are constantly being spun by this steam. Hence, the blades mostly transform the potential energy of the steam into kinetic energy.
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How many grams of HBr would there be in 355 mL of a 7.5% m/v HBr solution?
Answers
26.62 grams of HBr would be present in 355 mL of a 7.5% m/v HBr solution.
Concentration refers to the amount of a substance in a defined space. Another definition is that concentration is the ratio of solute in a solution to either solvent or total solution.
There are various methods of expressing the concentration of a solution.
Concentrations are usually expressed in terms of molarity, defined as the number of moles of solute in 1 L of solution.
Solutions of known concentration can be prepared either by dissolving a known mass of solute in a solvent and diluting to a desired final volume or by diluting the appropriate volume of a more concentrated solution (a stock solution) to the desired final volume.
Given,
HBr = 7.5% m/ v
This means 7.5g of HBr in 100 ml of the solution.
1 ml of the solution has 0.075g
355 ml of the solution will have = 0.075 × 355 = 26.62g of HBr
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What pressure will be produced when 2.0 moles of N2 gas is heated to 68oC in a container that holds 1.25 of gas?
Answers
The pressure of the nitrogen gas produced is determined as 44.77 atm.
What is the pressure of the Nitrogen gas?
The pressure of the nitrogen gas is determined from ideal gas equation, as shown below;
PV = nRT
P = nRT/V
where;
n is number of moles = 2 molesR is ideal gas constant = 0.08205 L.atm/mol.KT is temperature = 68⁰C = 68 + 273 = 341 KV is volume = 1.25 LP = (2 x 0.08205 x 341)/(1.25)
P = 44.77 atm.
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Question 19 of 30
Why does Hess's law allow you to determine the enthalpy change of a
reaction?
A. It states that the enthalpy of any reaction can be determined using
a bomb calorimeter.
B. It states that the change in enthalpy is independent of the pathway
the reaction takes to get to the products.
C. It states how the equilibrium constant is related to the enthalpy
change.
D. It states that the change in enthalpy depends on the reaction
pathway between the products and the reactants.
Answers
Answer:
B.) It states that the change in enthalpy is independent of the pathway
the reaction takes to get to the products.
Explanation:
Hess's Law states that the overall enthalpy change is the sum of the enthalpy changes of all preceding steps. It does not matter how many steps there are or the type, so long as the enthalpy change of each is combined at the end, the overall change can be determined. The sequence (aka pathway) is not important.
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. He has a 0.1838 M
0.1838
M
standard sodium hydroxide solution. He takes a 25.00 mL
25.00
mL
sample of the original acid solution and dilutes it to 250.0 mL.
250.0
mL
.
Then, he takes a 10.00 mL
10.00
mL
sample of the dilute acid solution and titrates it with the standard solution. The endpoint was reached after the addition of 10.81 mL
10.81
mL
of the standard solution. What is the concentration of the original sulfuric acid solution?
concentration:
Answers
Initial solution concentration of the original sulfuric acid solution is 1.66.
How to calculate concentration?We know that Na2SO4 + 2 H2O > H2SO4 + 2 NaOH.The concentration of NaOH has been reported at 0.1678.Volume of NaOH: 19.88 mL (or 0.01988 L)Here are the calculations for NaOH moles: NaOH concentration times volume equals 0.01988 x 0.1678 x 0.00333 moles.Half a mole of NaOH is equivalent to half a mole of in 25 mL of the original solution, which is equivalent to 0.00166 mol in 10 mL of the diluted solution. 250 mL of the diluted solution divided by 10 is equal to 0.0415 mol.Initial solution concentration = moles/volume = 0.0415/0.025 = 1.66For more information on concentration kindly visit to
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Consider this map of the world. Which region would you expect to find a very cold climate, with low temperatures most of the year. lots of snow and frozen ground?
Answers
Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.
Answers
Answer:
The given condition is proved.
Explanation:
Given that,
Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.
We need to construct the resonance structure for CSO
The structure shown in figure
According to question,
A formal charge of +2 on the central atom and +1 on the oxygen atom.
Then tha structure shown in figure
The central atom in the structure is sulphur.
We need to calculate the formal charge on sulphur
Using figure,
\(charge\ on\ S=+3-1\)
\(charge\ on\ S=+2\)
A formal charge of +2 on the central atom.
This is proved.
Hence, The given condition is proved.
Resonance structure is attached below in the image.
Given: We need to construct the resonance structure for CSO
Structure of CSO:A formal charge of +2 on the central atom and +1 on the oxygen atom. The central atom in the structure is sulphur. The formal charge on sulphur is +2 i.e. +3-1 = 2. Thus, a formal charge of +2 on the central atom.
The resonance structure is attached below:
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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
Answers
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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The electronic structure 1s22s22p63523p64523d8 refers to the ground state of
Kr.
Ni.
Pd.
Fe.
none of the above.
Previous
Answers
Answer:
Ni
Explanation:
Electronic configuration given by
\(\\ \sf\longmapsto 1s^22s^22p^63s^23p^64s^23d^8\)
No expectations so it's Z=28Element is nickel
Naturally occurring boron has an atomic mass of 10.810 amu consists of two isotopes. One of those isotopes is 10B with an isotopic mass of 10.0129 amu and an abundance of 19.9%. What is the isotopic mass of the other isotope?
Answers
Answer:
boron has an atomic mass of 10.810 amu consists of two isotopes.
Answer:
boron has an atomic mass of 10.810 amu consists of two isotopes.
Explanation:
SECTIONA Answer all the questions, use the answer grid provided. Which of the following branches of chemistry involves the study of chemical nature of living matter? 1 A Biochemistry B Inorganic chemistry C Organic chemistry D Physical chemistry 2. The diagram below shows the chromatogram for a dye. 30
Answers
The separation of the dye into its individual components is based on the principle of adsorption chromatography, where the stationary phase is a solid adsorbent that retains the components of the mixture based on their adsorption properties.
Answer all the questions, use the answer grid provided. The branch of chemistry that involves the study of chemical nature of living matter is Biochemistry. Biochemistry is a branch of science that deals with the study of chemical processes within and relating to living organisms. It is an interdisciplinary field that involves the application of chemistry, biology, physics, and mathematics to the study of biological systems. It focuses on the chemical and physical properties of living things and their interaction with the environment.Biochemistry can be divided into two main categories, which are structural biochemistry and functional biochemistry. Structural biochemistry deals with the study of the chemical structure of biological molecules such as proteins, carbohydrates, and lipids. It involves the analysis of the molecular structure and the physical properties of these molecules. Functional biochemistry, on the other hand, focuses on the study of the chemical reactions and processes that occur within living organisms. It involves the study of metabolic pathways, enzymology, and the regulation of cellular processes. 2. The diagram below shows the chromatogram for a dye.Chromatography is a technique used to separate mixtures into their individual components. It works on the principle that different compounds will move at different rates through a stationary phase under the influence of a mobile phase. In this case, the dye is separated into its individual components by passing it through a stationary phase of paper under the influence of a mobile phase of water.As can be seen from the chromatogram, the dye has been separated into three distinct components, which are represented by the three peaks on the graph. The first peak represents the component that moved through the paper at the fastest rate, while the third peak represents the component that moved through the paper at the slowest rate. The second peak represents the component that moved through the paper at an intermediate rate.
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Calculate the [OH−] and the pH of a solution with an [H+]=4.9×10−13 M at 25 °C .
[OH−]= M
pH=
Calculate the [H+] and the pH of a solution with an [OH−]=2.2×10−7 M at 25 °C .
[H+]= M
pH=
Calculate the [H+] and the [OH−] of a solution with a pH=8.66 at 25 °C .
[H+]= M
[OH−]= M
Answers
The [OH⁻] concentration is 1.9 × 10⁻² M and the [H⁺] concentration is 3.9 × 10⁻⁸ M
a) [ H⁺ ] = 4.9 × 10⁻¹³ M
pH = - log [ 4.9 × 10⁻¹³ ]
pH = 12.3
pH + pOH = 14
pOH = 14 - 12.3 = 1.7
pOH = -log [OH⁻]
[OH⁻] = 10^-1.7
= 1.9 × 10⁻² M
b) pOH = - log [ 2.2 × 10⁻⁷]
pOH = 6.6
pOH + pH = 14
pH = 7.4
pH = -log [H⁺]
[H⁺] = 10^-7.4
[H⁺] = 3.9 × 10⁻⁸ M
Thus, The [OH⁻] concentration is 1.9 × 10⁻² M and the [H⁺] concentration is 3.9 × 10⁻⁸ M
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You are writing a safety contract for your class. List 10 things you would include in the contract.
Answers
Writing a safety contract for your class. List 10 things you would include in the contract are
1) students should always listen to teachers.
2) In case you see fire in school you should tell to your teacher.
3) No eating in between class.
4) No student may work in laboratory without teachers.
5) wear eyeglasses when need in class.
6) Proceed with cautions in lab.
7) Student should always wear a proper safety material.
8) Tie your hair in tight ponytail or make braid.
9) Work with chemicals by takin precaution do not play with it.
10) Carry sharp instrument with tip down away.
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Why does burned toast taste so bad? Is it a chemical or physical change?
Answers
Because things that are burnt have been changed into something else like moldy bread thats cooked.
It is chemical change because you cannot unburn something.
Answer:
It's a chemical change because I'm really good at answers
Explanation:
WHATS THE LAST OPTION HELP ASAP I WILL MARK BRAINLIEST
Answers
Answer:
SI-28
Explanation:
A drop of water contains 2 x 104 bacteria. How many bacteria are in 100 gallons of water? [1 drop = 1 mL]
Answers
Answer:
7.57×10⁹ bacteria.
Explanation:
We'll begin by convert 100 gallons of water to millilitres (mL). This can be obtained as follow:
1 gallon = 3785.41 mL
Therefore,
100 gallons = 100 gallon × 3785.41 mL / 1 gallon
100 gallons = 378541 mL
Therefore, 100 gallons of water is equivalent to 378541 mL.
Next, we shall convert 378541 mL to drop of water. This can be obtained as follow:
1 mL = 1 drop
Therefore,
378541 mL = 378541 mL × 1 drop/ 1 mL
378541 mL = 378541 drop
Therefore, 378541 mL is equivalent to 378541 drops of water.
Finally, we shall determine the number of bacteria in 378541 drops of water as follow:
1 drop = 2×10⁴ bacteria
Therefore,
378541 drop = 378541 drop × 2×10⁴ bacteria / 1 drop
378541 drop = 7.57×10⁹ bacteria.
Therefore, there are 7.57×10⁹ bacteria in 100 gallons of water
Directions: Write the balanced equation for each of the following situations. \ In addition, list the reaction type. YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS GO TO COMPLETION. If only STOICHIOMETRY, tell how much of the excess reactant is used!!!! Reaction Type a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction 6. 8.924 g of copper(II) sulfate, pentahydrate is heated to drive off the water of hydration 6. Balanced Chemical Equation: At the completion of reactions: Grams of copper(II) sulfate pentahydrate: Grams of copper(II) sulfate: Grams of water:
Answers
The compound involved is copper(II) sulfate pentahydrate, that is, CuSO₄.5H₂O.
The heat will make the water separate, so the balanced equation is:
\(CuSO_4.5H_2O(s)\to CuSO_4(s)+5H_2O(g)\)Since we start with one compound and end with more than on, this is a decomposition reaction.
Since we started with 8.924 g of CuSO₄.5H₂O, we can calculate how many moles are there to make the stoichiometry of the products.
The equation we use for transforming mass to number of moles or the other way around is:
\(M=\frac{m}{n}_{}\)Where M is the molar weight of the compound.
The molar weight of CuSO₄.5H₂O is:
\(\begin{gathered} M_{CuSO_4.5H_2O}=1\cdot M_{Cu}+1\cdot M_S+9\cdot M_O+10\cdot M_H \\ M_{CuSO_4.5H_2O}=(1\cdot63.546+1\cdot32.065+9\cdot15.9994+10\cdot1.00794)g/mol \\ M_{CuSO_4.5H_2O}=(63.546+32.065+143.9946+10.0794)g/mol \\ M_{CuSO_4.5H_2O}=249.6850g/mol \end{gathered}\)Thus, the number of moles is:
\(\begin{gathered} M_{CuSO_{4}.5H_{2}O}=\frac{m_{CuSO_4.5H_2O}}{n_{CuSO_{4}.5H_{2}O}} \\ n_{CuSO_4.5H_2O}=\frac{m_{CuSO_4.5H_2O}}{M_{CuSO_{4}.5H_{2}O}}=\frac{8.924g}{249.6850g/mol}=0.035741\ldots mol \end{gathered}\)The reaction is 1 to 1 for CuSO₄ and 1 to 5 for H₂O, so this reaction will produce:
\(\begin{gathered} n_{CuSO_4}=\frac{1}{1}n_{CuSO_4.5H_2O}=0.035741\ldots mol \\ n_{H_2O}=\frac{5}{1}n_{CuSO_4.5H_2O}=5\cdot0.035741mol=_{}0.17870\ldots mol \end{gathered}\)Now, we just need to convert these to mass, but first we need the molar weight of CuSO₄ and H₂O:
\(\begin{gathered} M_{CuSO_4}=1\cdot M_{Cu}+1\cdot M_S+4\cdot M_O \\ M_{CuSO_4}=(1\cdot63.546+1\cdot32.065+4\cdot15.9994)g/mol \\ M_{CuSO_4}=(63.546+32.065+63.9976)g/mol \\ M_{CuSO_4}=159.6086g/mol \end{gathered}\)\(\begin{gathered} M_{H_2O}=2\cdot M_H+1\cdot M_O \\ M_{H_2O}=(2\cdot1.00794+1\cdot15.9994)g/mol \\ M_{H_2O}=(2.01588+15.9994)g/mol \\ M_{H_2O}=18.01528g/mol \end{gathered}\)So, we have:
\(\begin{gathered} M_{CuSO_4}=\frac{m_{CuSO_4}}{n_{CuSO_{4}}} \\ m_{CuSO_4}=n_{CuSO_4}\cdot M_{CuSO_4}=0.035741\ldots mol\cdot159.6086g/mol\approx5.705g \end{gathered}\)\(\begin{gathered} M_{H_{2}O}=\frac{m_{H_2O}}{n_{H_{2}O}} \\ m_{H_2O}=n_{H_2O}\cdot M_{H_2O}=0.17870\ldots mol\cdot18.01528g/mol\approx3.219g \end{gathered}\)So, in the end we will have 0 g of copper(II) sulfate pentahydrate, approximately 5.705 g of copper(II) sulfate and approximately 3.219 g of water.
if 20.2g of NO and 13.8g of O2 are used to form NO2, how many moles of excess reactant will be left over
Answers
Answer:
0.095 moles of O₂ are left over.
Explanation:
First of all, state the balanced reaction:
2NO + O₂ → 2NO₂
We determine moles of each reactant:
20.2 g . 1mol / 30g = 0.673 moles of NO
13.8g . 1mol / 32g = 0.431 moles of oxygen
Oxygen is the excess reactant. Let's see.
For 2 moles of NO I need 1 mol of O₂
Then, for 0.673 moles of NO I may use (0.673 .1) /2 = 0.336 moles
I have 0.431 moles of O₂ and I only need 0.336 mol. According to reaction, stoichiometry is 2:1.
In conclussion, the moles of excess reactant that will be left over:
0.431 - 0.336 = 0.095 moles
Mylanta a common antacid contains magnesium hydroxide Mg (OH)2.How many miles of magnesium hydroxide are in 75.0g of magnesium hydroxide?
Answers
To answer this question, we need to convert grams to moles and then use the Avogadro's number to convert moles to molecules.
The molar mass of Mg(OH)2 is 58.32 g/mol.
First, we need to find the number of moles of Mg(OH)2 in 75.0 g.
75.0 g / 58.32 g/mol = 1.287 mol
Next, we need to convert moles to molecules.
1.287 mol x 6.022 x 10^23 molecules/mol = 7.75 x 10^23 molecules
Finally, we can use the molecular formula of Mg(OH)2 to calculate the number of miles of Mg(OH)2.
1 molecule of Mg(OH)2 contains 3 atoms of oxygen (O) and 2 atoms of hydrogen (H).
So, the total number of miles of Mg(OH)2 is:
7.75 x 10^23 molecules x 2 miles/molecule = 1.55 x 10^24 miles
Therefore, there are 1.55 x 10^24 miles of magnesium hydroxide in 75.0 g of magnesium hydroxide.
what are physical properties of matter
Answers
Answer: The physical properties are mass, weight, volume, and density.
Explanation:
You make Kool- Aid. Unfortunately, you misread the directions and made 0.512 L at a concentration of 13.2 M. In order for it to taste good it needs to be only 2.00 M. How much water do you need to add to make taste good? Show your work.
Answers
To dilute the Kool-Aid solution to a concentration of 2.00 M, we need to calculate the volume of water (Vw) that needs to be added.
The initial concentration of Kool-Aid solution is 13.2 M, and the initial volume is 0.512 L. Let's assume that Vw is the volume of water we need to add to dilute the solution to a concentration of 2.00 M.
Since the total volume after dilution will be the sum of the initial volume of Kool-Aid solution and the volume of water added, we can set up the following equation based on the dilution formula:
C1V1 = C2V2
where
C1 = initial concentration of Kool-Aid solution = 13.2 M
V1 = initial volume of Kool-Aid solution = 0.512 L
C2 = final concentration of Kool-Aid solution = 2.00 M
V2 = final volume of Kool-Aid solution after adding water = 0.512 L + Vw
Substituting the given values into the equation, we get:
13.2 M x 0.512 L = 2.00 M x (0.512 L + Vw)
Simplifying the equation, we get:
6.7584 L·M = 1.024 L·M + 2.00 M·Vw
Subtracting 1.024 L·M from both sides, we get:
5.7344 L·M = 2.00 M·Vw
Dividing both sides by 2.00 M, we get:
Vw = 2.8672 L
Therefore, we need to add 2.8672 L of water to 0.512 L of 13.2 M Kool-Aid solution to dilute it to a concentration of 2.00 M.
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The gas in a 250.0 mL piston experiences a change in pressure from 1.25 atm to 2.00 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?
Answers
Answer:
The new volume of the gas is 156.25 mL.
Explanation:
According to Boyle's Law, at constant temperature and number of moles, the pressure and volume of a gas are inversely proportional.
So, we can use the following equation to solve for the new volume (V2):
P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.
Substituting the given values:
(1.25 atm) x (250.0 mL) = (2.00 atm) x V2
Solving for V2:
V2 = (1.25 atm x 250.0 mL) / (2.00 atm)
V2 = 156.25 mL
Therefore, the new volume of the gas is 156.25 mL.
Calculate the number of nitrogen atoms in a 80.0 g sample of dinitrogen tetroxide (N₂O4).
Be sure your answer has a unit symbol if necessary, and round it to 3 significant digits.
Answers
The number of atoms of nitrogen in an 80.0 g sample of dinitrogen tetroxide (N₂O4) is 1.047 * 10²⁴ atoms.
What is the number of nitrogen atoms in an 80.0 g sample of dinitrogen tetroxide (N₂O4)?The number of nitrogen atoms in an 80.0 g sample of dinitrogen tetroxide (N₂O4) is calculated as follows:
Molar mass of N₂O4 = 92 g/mol
Moles of N₂O4 in 80.0 g sample = 80/92
Moles of N₂O4 in 80.0 g sample =0.87 moles
Moles of nitrogen in the sample = 0.87 * 2
Moles of nitrogen in the sample = 1.74 moles
1 mole of nitrogen contains 6.0 * 10²³ atoms
Number of atoms of nitrogen = 1.74 * 6.0 * 10²³ atoms
Number of atoms of nitrogen = 1.047 * 10²⁴ atoms
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pls help with 1 question (15 ponts)
What happens in the circulatory system?
Answers
C6H12O6 + 602 → 6CO2 + 6H₂O
The most efficient ratio is
1 C6H12O6 6 02.
Which set of reactants will be the most
efficient (least wasteful of materials) for
the reaction?
A. 1.0 mol C6H12O6 and 3.0 mol O₂
B. 1.5 mol C6H₁2O6 and 3.0 mol O₂
C. 3.0 mol C6H₁2O6 and 6.0 mol O₂
D. 0.5 mol C6H₁2O6 and 3.0 mol O₂
Answers
Answer:
D
Explanation:
The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.
I NEED THIS RIGHT NOW!! Daria had some sand from the beach. The mass of the sand was 72 grams. She used the graduated cylinder below to measure the volume.
What is the volume of the sand found in the graduated cylinder? _____ mL
Answers
Daria had some beach sand with her. The sand has a 72 gramme mass. She calculated the volume using the graduated cylinder below. The graduated cylinder contains 15 mL of sand.
The volume of the sand is calculated using the graduated cylinder below. The sand's bulk is specified as 72 grammes.
We can use the water displacement method to calculate the volume of the sand. Following is a description of how to estimate the amount of sand using the water displacement method:
The graduated cylinder of water should first be measured for volume.
The graduated cylinder's water volume should then be measured after adding the sand to it. The volume of water increases by the same amount.
Let's use the provided problem to implement this approach.
In the beginning, there is 10 mL of water in the graduated cylinder. The graduated cylinder contains 25 mL of water once the sand has been added.
The amount of sand is therefore equal to the difference between the two volumes, which is: Sand volume equals final water volume minus initial water volume (25 - 10 = 15 mL).
As a result, there are 15 mL of sand in the graduated cylinder.
Answer : 15
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